IBPS RRB Clerk2022Numerical AbilityPage 4 of 7

IBPS RRB Clerk Prelims 2022 Numerical Ability Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 151–200 of 308, each with the correct answer and a step-by-step explanation.

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151Numerical Ability
Which number is wrong in the following number series. 5,10,26,50,82,124,170
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Answer: (C) 124

Explanation

To find the wrong number in the series, evaluate the differences between consecutive terms: 10 - 5 = 5 26 - 10 = 16 50 - 26 = 24 82 - 50 = 32

Examining the second differences, the difference increases by 8 at each step starting from 16 (16, 24, 32). Continuing this constant addition of 8 to find the next differences: Next difference = 32 + 8 = 40 82 + 40 = 122

Subsequent difference = 40 + 8 = 48 122 + 48 = 170

Since 122 correctly completes the sequence up to 170, the number 124 is incorrect.

152Numerical Ability
Which number is wrong in the following number series. 160,154,142,126,106,82,54
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Answer: (B) 160

Explanation

To identify the wrong number, calculate the differences between adjacent terms from right to left: 82 - 54 = 28 106 - 82 = 24 126 - 106 = 20 142 - 126 = 16 154 - 142 = 12

The differences form an arithmetic progression decreasing by 4 at each step: 28, 24, 20, 16, 12. Following this arithmetic sequence, the difference between the first two terms must be: 12 - 4 = 8

Adding 8 to the second term gives: 154 + 8 = 162

Thus, the correct first term is 162, making 160 the wrong number in the series.

153Numerical Ability
Which number is wrong in the following number series. 65,50,80,35,95,20,105
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Answer: (E) 105

Explanation

To determine the wrong number in the series, calculate the difference between consecutive terms: 50 - 65 = -15 80 - 50 = +30 35 - 80 = -45 95 - 35 = +60 20 - 95 = -75

The pattern involves alternating subtraction and addition of increasing multiples of 15: -15, +30, -45, +60, -75, +90. Applying the next step in the pattern to the term 20: 20 + 90 = 110

The sequence requires the last number to be 110 instead of 105, which makes 105 the incorrect value.

154Numerical Ability
The given table shows the data related to five students and the total number of movies watched by them during a period of ten years. Read the data carefully and answer the questions. Note: Total number of movies watched by any student = Number of Hollywood movies + Number of Bollywood movies. Students Total number of movies watched Ratio of Hollywood to Bollywood movies A 350 4:3 B 400 11:9 C 250 3:7 D 200 13:12 E 375 16:9 What is average number of Bollywood movies watched by students A, B and D together?
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Answer: (C) 142

Explanation

To calculate the average number of Bollywood movies watched by students A, B, and D, first calculate the individual counts using the total movies and the ratio of Hollywood to Bollywood movies:

Student A: Total = 350, Ratio = 4:3. Bollywood movies = 350 × (3 ÷ 7) = 150

Student B: Total = 400, Ratio = 11:9. Bollywood movies = 400 × (9 ÷ 20) = 180

Student D: Total = 200, Ratio = 13:12. Bollywood movies = 200 × (12 ÷ 25) = 96

Sum of Bollywood movies for A, B, and D = 150 + 180 + 96 = 426 Average = 426 ÷ 3 = 142

155Numerical Ability
The given table shows the data related to five students and the total number of movies watched by them during a period of ten years. Read the data carefully and answer the questions. Note: Total number of movies watched by any student = Number of Hollywood movies + Number of Bollywood movies. Students Total number of movies watched Ratio of Hollywood to Bollywood movies A 350 4:3 B 400 11:9 C 250 3:7 D 200 13:12 E 375 16:9 Find the ratio of total number of movies watched by student C | D together to the number of Bollywood movies watched by B, C and E together?
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Answer: (B) 45:49

Explanation

To find the required ratio, calculate both quantities separately using the given dataset:

Total number of movies watched by student C and student D together: Total = 250 + 200 = 450

Number of Bollywood movies watched by student B, student C, and student E: For student B: 400 × (9 ÷ 20) = 180 For student C: 250 × (7 ÷ 10) = 175 For student E: 375 × (9 ÷ 25) = 135 Sum of Bollywood movies = 180 + 175 + 135 = 490

Ratio of total movies (C | D) to Bollywood movies (B, C | E) = 450 : 490 = 45 : 49

156Numerical Ability
The given table shows the data related to five students and the total number of movies watched by them during a period of ten years. Read the data carefully and answer the questions. Note: Total number of movies watched by any student = Number of Hollywood movies + Number of Bollywood movies. Students Total number of movies watched Ratio of Hollywood to Bollywood movies A 350 4:3 B 400 11:9 C 250 3:7 D 200 13:12 E 375 16:9 The average of total number of movies watched by B and D is what percent of the average of total number of movies watched by A and C.
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Answer: (E) 100%

Explanation

To determine the percentage, first find the average total movies watched for both pairs of students:

Average total movies watched by students B and D: (400 + 200) ÷ 2 = 600 ÷ 2 = 300

Average total movies watched by students A and C: (350 + 250) ÷ 2 = 600 ÷ 2 = 300

Calculate the percentage: Percentage = (300 ÷ 300) × 100% = 100%

157Numerical Ability
What will come in the place of question (?) mark in following questions. {(400% of? + 15× 12) - 140} = 60
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Answer: (A) 5

Explanation

To find the value of the unknown variable x in the equation, simplify the mathematical operations step by step:

Equation: {(400% of x + 15 × 12) - 140} = 60

Step 1: Simplify the percentage and multiplication terms inside the brackets. 400% of x = (400 ÷ 100) × x = 4x 15 × 12 = 180

Step 2: Substitute these values into the original expression. {(4x + 180) - 140} = 60 4x + 40 = 60

Step 3: Solve for x. 4x = 60 - 40 4x = 20 x = 5

158Numerical Ability
What will come in the place of question (?) mark in following questions. ? = 30% of 1200 - 122 + 7²
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Answer: (B) 287

Explanation

To solve for the question mark in the given expression, calculate each term using standard order of operations:

Expression: ? = 30% of 1200 - 122 + 7²

Step 1: Evaluate the percentage of the number. 30% of 1200 = (30 ÷ 100) × 1200 = 360

Step 2: Calculate the square term. 7² = 49

Step 3: Substitute the calculated values into the expression and solve. ? = 360 - 122 + 49 ? = 238 + 49 ? = 287

159Numerical Ability
What will come in the place of question (?) mark in following questions. ? = 22²⁄₉% of 72 + √(1444)
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Answer: (D) 54

Explanation

22(2/9)% can be converted to the simple fraction 2/9. 2/9 × 72 = 16 √1444 = 38 ? = 16 + 38 = 54

160Numerical Ability
What will come in the place of question (?) mark in following questions. 840 = 25% of 2560 + 12.5% of?
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Answer: (A) 1600

Explanation

25% of 2560 = 2560 / 4 = 640 840 = 640 + 12.5% of ? 200 = 12.5% of ? Since 12.5% = 1/8: ? = 200 × 8 = 1600

161Numerical Ability
What will come in the place of question (?) mark in following questions. 4! + 20% of 45% of 200 = ?
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Answer: (C) 42

Explanation

4! = 4 × 3 × 2 × 1 = 24 20% of 45% of 200 = 0.20 × 0.45 × 200 = 18 ? = 24 + 18 = 42

162Numerical Ability
What will come in the place of question (?) mark in following questions. ⁸²⁰⁄₅₁₀ × ¹⁷⁰⁰⁄₄₁₀ = (?)/(3)
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Answer: (B) 20

Explanation

(820 / 510) × (1700 / 410) = ? / 3 (820 / 410) × (1700 / 510) = ? / 3 2 × (10 / 3) = ? / 3 20 / 3 = ? / 3 ? = 20

163Numerical Ability
What will come in the place of question (?) mark in following questions. 8¹⁶× 64³⁵÷ 512¹² = 64^?
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Answer: (A) 25

Explanation

Express all terms in base 8: 8¹⁶ × (8²)³⁵ ÷ (8³)¹² = (8²)^? 8¹⁶ × 8⁷⁰ ÷ 8³⁶ = 8⁽2?) 8⁽16 + 70 - 36) = 8⁽2?) 8⁵⁰ = 8⁽2?) 2? = 50 ? = 25

164Numerical Ability
What will come in the place of question (?) mark in following questions. 55× 44 + 17.5% of1600 = ?
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Answer: (C) 2700

Explanation

55 × 44 = 2420 17.5% of 1600 = (35 / 2)% × 1600 = 35 × 8 = 280 ? = 2420 + 280 = 2700

165Numerical Ability
What will come in the place of question (?) mark in following questions. 3½× 7⅔÷ 9⁶⁄₇ = (?²)⁄₂
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Answer: (E) 7/3

Explanation

3½ = 7/2 5¼ = 21/4 1⁴/₉ = 14/9 Setting up the equation: (7/2) × ? ÷ (21/4) = 14/9 (7/2) × ? × (4/21) = 14/9 (2/3) × ? = 14/9 ? = (14/9) × (3/2) = 7/3

166Numerical Ability
What will come in the place of question (?) mark in following questions. 29² + 13× 3 = ?× 10
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Answer: (C) 88

Explanation

29² = 841 13 × 3 = 39 29² + 13 × 3 = 841 + 39 = 880 880 = ? × 10 ? = 880 / 10 = 88

167Numerical Ability
What will come in the place of question (?) mark in following questions. 18² - 11² + 7³ = ?
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Answer: (D) 546

Explanation

18² = 324 11² = 121 7³ = 343 ? = 324 - 121 + 343 = 203 + 343 = 546

168Numerical Ability
What will come in the place of question (?) mark in following questions. 65% of180 + 15× √(841) = ?
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Answer: (A) 552

Explanation

65% of 180 = (65 / 100) × 180 = 117 √841 = 29 15 × √841 = 15 × 29 = 435 ? = 117 + 435 = 552

169Numerical Ability
What will come in the place of question (?) mark in following questions. ?² + 12² = 23² - ⁴⁄₇ of168
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Answer: (C) 17

Explanation

23² = 529 and (4/7) × 168 = 96. Substituting these values into the right-hand side gives 529 - 96 = 433. The equation becomes ?² + 12² = 433, which simplifies to ?² + 144 = 433. Subtracting 144 from 433 gives ?² = 289. Taking the square root gives ? = 17.

170Numerical Ability
What will come in the place of question (?) mark in following questions. ⁴⁵⁄₂₇₀ × ¹⁶²⁄₉ = ? ÷ 15
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Answer: (B) 45

Explanation

Simplifying the left-hand side: (45/270) × (162/9) = (1/6) × 18 = 3. Setting up the full equation: 3 = ? + 15. Subtracting 15 from both sides yields ? = -12.

171Numerical Ability
Neeraj started a business with an investment of Rs. 7500. Prashant joined him after four months by investing Rs. 1000 more than Neeraj. At the end of a year, the profit share of Neeraj is Rs. 900. Find the total profit?
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Answer: (C) Rs. 1580

Explanation

Neeraj invested Rs. 7500 for 12 months, while Prashant invested Rs. 8500 (7500 + 1000) for 8 months (12 - 4). The ratio of their profit shares is (7500 × 12) : (8500 × 8) = 90000 : 68000 = 45 : 34. Since Neeraj's share of 45 units equals Rs. 900, 1 unit equals Rs. 20. The total profit corresponds to (45 + 34) = 79 units. Total profit = 79 × 20 = Rs. 1580.

172Numerical Ability
In village T, only three types of networks are used i.e., Airtel, Jio and Vodafone. If number of users of Vodafone are 30% of the total users, then find the number of users of Vodafone.
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Answer: (C) 600

Explanation

The problem states that Vodafone users comprise 30% of the total network users in village T, but no numerical value or relationship is provided to determine the total number of users. Without the total number of users or user counts for Airtel and Jio, it is mathematically impossible to calculate the exact number of Vodafone users.

173Numerical Ability
Shopkeeper allows 25% discount on a table and sell it at Rs. 450. If cost price of table is Rs 320, then find marked price of table is what percent more than its cost price?
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Answer: (D) 87.5%

Explanation

Marked Price = Selling Price ÷ (1 - Discount%) = 450 ÷ 0.75 = Rs 600. Percentage by which Marked Price exceeds Cost Price = [(Marked Price - Cost Price) ÷ Cost Price] × 100. Substituting the values: [(600 - 320) ÷ 320] × 100 = (280 ÷ 320) × 100 = 87.5%.

174Numerical Ability
Sum of two digits of a two-digit number is 11. When digits of the number are reversed then number formed is 45 more than the original number. Find the original number?
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Answer: (E) 38

Explanation

Let the original number be 10x + y, where x is the tens digit and y is the units digit. Given x + y = 11 and (10y + x) - (10x + y) = 45, which simplifies to 9(y - x) = 45, giving y - x = 5. Solving the two linear equations x + y = 11 and y - x = 5 yields y = 8 and x = 3. The original number is 10(3) + 8 = 38.

175Numerical Ability
Pipe A alone fill a tank for 6 hours and then it replaces with pipe B, which alone fill the remaining tank in 12 hours. If ratio of time taken by pipe A alone to B alone to fill the tank completely is 3:2 , then find time taken by pipe B alone to fill the tank?
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Answer: (B) 16 hours

Explanation

Let the total time taken by Pipe A and Pipe B alone be 3t and 2t hours respectively. The work equation for filling the tank completely is 6 ÷ (3t) + 12 ÷ (2t) = 1, which simplifies to 2/t + 6/t = 1. Solving 8/t = 1 gives t = 8. The time taken by Pipe B alone to fill the tank completely is 2t = 2 × 8 = 16 hours.

176Numerical Ability
Sum of present age of P and R is 58 years and R is eight years younger than Q. If the ratio of present age of P to that of Q is 6:5, then the age of Q six years hence will be?
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Answer: (D) 36 years

Explanation

Let the present ages of P and Q be 6x and 5x respectively. Since R is 8 years younger than Q, R = 5x - 8. Using P + R = 58 gives 6x + (5x - 8) = 58, which simplifies to 11x = 66, so x = 6. The present age of Q is 5 × 6 = 30 years, so six years hence Q's age will be 30 + 6 = 36 years.

177Numerical Ability
A boat covers 25% less distance in downstream than upstream and the time taken by boat to cover given distance in downstream and upstream is 2 hours and 4 hours respectively. If speed of boat in still water is 15 Km / hr , then find the speed of stream?
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Answer: (C) 3km / hr

Explanation

Let the speed of the stream be v km/hr. Downstream distance is 2 × (15 + v) and upstream distance is 4 × (15 - v). Since downstream distance is 25% less than upstream distance, 2 × (15 + v) = 0.75 × 4 × (15 - v). Simplifying yields 30 + 2v = 45 - 3v, which reduces to 5v = 15, giving v = 3 km/hr.

178Numerical Ability
In what time will Rs 10500 at rate of 3% per annum on simple interest will produce the same interest as Rs 6000 does in two years at rate of 10% p.a. on compound interest?
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Answer: (D) 4 years

Explanation

Compound interest earned on Rs 6000 at 10% p.a. for 2 years = 6000 × [(1 + 0.10)² - 1] = 6000 × 0.21 = Rs 1260. Simple interest SI = (P × R × T) ÷ 100. Equating simple interest to 1260 gives 1260 = (10500 × 3 × T) ÷ 100 = 315 × T. Solving for T gives T = 1260 ÷ 315 = 4 years.

179Numerical Ability
A and B enter into a business by investing their sum in the ratio of 7 : 9 respectively. After seven months, B leaves the business and after four more months they get a total profit of Rs. 6150. Find the profit share of B (in Rs.)?
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Answer: (A) 2767.5

Explanation

Investment ratio of A to B is 7:9. A invests for 11 months (7 + 4 months) and B invests for 7 months. Profit ratio A : B = (7 × 11) : (9 × 7) = 77 : 63 = 11 : 9. B's share of the total profit = [9 ÷ (11 + 9)] × 6150 = (9 ÷ 20) × 6150 = Rs 2767.5.

180Numerical Ability
Two trains A and B cross the same platform in 18 and 24 seconds respectively. The respective length of train A and B is 240 meters and 210 meters and the ratio of their speeds is 3:2. Find the length of platform (in meters)?
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Answer: (C) 30

Explanation

Let the length of the platform be L meters. Speed of train A is (240 + L) ÷ 18 m/s and speed of train B is (210 + L) ÷ 24 m/s. Using the speed ratio 3:2 gives [(240 + L) ÷ 18] ÷ [(210 + L) ÷ 24] = 3 ÷ 2. Simplifying yields 4(240 + L) ÷ [3(210 + L)] = 3 ÷ 2, which cross-multiplies to 8(240 + L) = 9(210 + L). Solving 1920 + 8L = 1890 + 9L gives L = 30 meters.

181Numerical Ability
A vessel contains 42 liters pure milk. Seven liters of milk is taken out and replaced with water and again 7 liter of mixture is taken out and replaced with water. Find the quantity of milk in final mixture (in liters)?
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Answer: (B) (29 ⅙)/(6)

Explanation

The remaining quantity of pure milk after repeated replacements is given by Final Milk = V × (1 - x ÷ V)ⁿ. Substituting initial volume V = 42 liters, replaced volume x = 7 liters, and n = 2 operations: Final Milk = 42 × (1 - 7 ÷ 42)² = 42 × (5 ÷ 6)² = 42 × (25 ÷ 36) = 175 ÷ 6 = 29 ⅙ liters.

182Numerical Ability
The circumference of two circles is 88 m and 132 m respectively. What is difference between the area of larger circle and smaller circle? (in m²)
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Answer: (D) 770

Explanation

The radius of a circle with circumference C is given by r = C / (2π). For the circle with circumference 88 m: r₁ = (88 × 7) / (2 × 22) = 14 m. For the circle with circumference 132 m: r₂ = (132 × 7) / (2 × 22) = 21 m. The difference between the areas of the two circles is: ΔA = π × (r₂² - r₁²) ΔA = (22 / 7) × (21² - 14²) = (22 / 7) × (441 - 196) = (22 / 7) × 245 = 22 × 35 = 770 m².

183Numerical Ability
Read the given data carefully and answer the following questions. The data given below shows the no. of watches (Analog and Digital) sold by five shopkeepers. Shopkeeper Total watches sold Ratio of Analog watches to digital watches sold A 1200 9 : 7 B 1440 5 : 7 C 1650 6 : 5 D 1540 3 : 4 E 1360 7 : 13 Which shopkeeper sold maximum number of digital watches.
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Answer: (B) E

Explanation

To find the number of digital watches sold by each shopkeeper, multiply the total watches sold by the fraction representing digital watches in the given ratio: For shopkeeper A: 1200 × (7 / 16) = 525 For shopkeeper B: 1440 × (7 / 12) = 840 For shopkeeper C: 1650 × (5 / 11) = 750 For shopkeeper D: 1540 × (4 / 7) = 880 For shopkeeper E: 1360 × (13 / 20) = 884 Comparing the totals, shopkeeper E sold the maximum number of digital watches.

184Numerical Ability
Read the given data carefully and answer the following questions. The data given below shows the no. of watches (Analog and Digital) sold by five shopkeepers. Shopkeeper Total watches sold Ratio of Analog watches to digital watches sold A 1200 9 : 7 B 1440 5 : 7 C 1650 6 : 5 D 1540 3 : 4 E 1360 7 : 13 Total analog watches sold by shopkeeper D are what percentage more or less than total digital watches sold by shopkeeper C.
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Answer: (E) 12%

Explanation

Analog watches sold by shopkeeper D = 1540 × (3 / 7) = 660. Digital watches sold by shopkeeper C = 1650 × (5 / 11) = 750. The required percentage difference is: Percentage = ((750 - 660) / 750) × 100 = (90 / 750) × 100 = 12%.

185Numerical Ability
Read the given data carefully and answer the following questions. The data given below shows the no. of watches (Analog and Digital) sold by five shopkeepers. Shopkeeper Total watches sold Ratio of Analog watches to digital watches sold A 1200 9 : 7 B 1440 5 : 7 C 1650 6 : 5 D 1540 3 : 4 E 1360 7 : 13 Find the difference between total analog watches and digital watches sold by all given shopkeepers.
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Answer: (E) 568

Explanation

Total analog watches sold = 1200 × (9 / 16) + 1440 × (5 / 12) + 1650 × (6 / 11) + 1540 × (3 / 7) + 1360 × (7 / 20) Total analog watches = 675 + 600 + 900 + 660 + 476 = 3311. Total digital watches sold = 1200 × (7 / 16) + 1440 × (7 / 12) + 1650 × (5 / 11) + 1540 × (4 / 7) + 1360 × (13 / 20) Total digital watches = 525 + 840 + 750 + 880 + 884 = 3879. Difference between total digital and total analog watches sold = 3879 - 3311 = 568.

186Numerical Ability
What will come in place of question mark (?) in the following series questions. 24 30 23 31 22 ?
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Answer: (A) 32

Explanation

The given series alternates between adding and subtracting consecutive integers: 24 + 6 = 30 30 - 7 = 23 23 + 8 = 31 31 - 9 = 22 22 + 10 = 32

187Numerical Ability
What will come in place of question mark (?) in the following series questions. 6, 7, 16, 51, 208, ?
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Answer: (E) 1045

Explanation

The pattern in the series follows the rule xₙ₊₁ = xₙ × n + n for n starting from 1: 6 × 1 + 1 = 7 7 × 2 + 2 = 16 16 × 3 + 3 = 51 51 × 4 + 4 = 208 208 × 5 + 5 = 1045

188Numerical Ability
What will come in place of question mark (?) in the following series questions. 39600, 6600, ?, 330, 110, 55
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Answer: (A) 1320

Explanation

The pattern involves successive division by consecutive decreasing integers starting from 6: 39600 ÷ 6 = 6600 6600 ÷ 5 = 1320 1320 ÷ 4 = 330 330 ÷ 3 = 110 110 ÷ 2 = 55 The missing number in the sequence is 1320.

189Numerical Ability
What will come in place of question mark (?) in the following series questions. 9, 10, 18, 27, 91, ?
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Answer: (E) 116

Explanation

The pattern adds alternating perfect squares and cubes of consecutive natural numbers: 9 + 1² = 10 10 + 2³ = 18 18 + 3² = 27 27 + 4³ = 91 91 + 5² = 116

190Numerical Ability
What will come in place of question mark (?) in the following series questions. 999, ?, 778, 669, 561, 454
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Answer: (A) 888

Explanation

The differences between consecutive terms decrease by 1 moving forward in the sequence: 454 + 107 = 561 561 + 108 = 669 669 + 109 = 778 778 + 110 = 888 888 + 111 = 999 The missing number is 888.

191Numerical Ability
Monthly income of Ankush is 77⁷⁄₉ % of monthly income of Aman. If Ankush's total monthly expenditure is Rs 28000 and he saves 40% of his salary. Find monthly income of Aman.
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Answer: (B) Rs 60000

Explanation

Ankush saves 40% of his salary, which means he spends 60% of his monthly income. 60% of Ankush's income = Rs 28000 Ankush's income = (28000 × 100) / 60 = Rs 140000 / 3 Ankush's income is 77(7/9)% of Aman's income. Expressing 77(7/9)% as a fraction yields 7/9: (7 / 9) × Aman's income = 140000 / 3 Aman's income = (140000 / 3) × (9 / 7) = Rs 60000

192Numerical Ability
The ratio of present age of A and B is 3 : 2 and the ratio of A's age five years ago to B's age ten years hence is 1 : 2. Find sum of their present age?
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Answer: (B) 25 years

Explanation

Let the present ages of A and B be 3x and 2x respectively. According to the given ratio: (3x - 5) / (2x + 10) = 1 / 2 2 × (3x - 5) = 2x + 10 6x - 10 = 2x + 10 4x = 20 x = 5

Sum of present ages of A and B = 3x + 2x = 5x = 5 × 5 = 25 years.

193Numerical Ability
What will come in the place of question (?) mark in following questions. ²⁷⁄₄₀ ÷ ⅕ × ⁸⁄₉ ÷ ³⁄₁₀₀ = ?
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Answer: (C) 100

Explanation

Convert division operations into multiplication by multiplying by the reciprocal: (27 / 40) ÷ (1 / 5) × (8 / 9) ÷ (3 / 100) = (27 / 40) × (5 / 1) × (8 / 9) × (100 / 3)

Simplifying step-by-step: (27 / 40) × 5 = 27 / 8 (27 / 8) × (8 / 9) = 3 3 × (100 / 3) = 100

194Numerical Ability
What will come in the place of question (?) mark in following questions. 51% of ¹²⁰⁰⁄₁₇ + 18² = ? × 24
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Answer: (A) 15

Explanation

Evaluate the expression step-by-step using order of operations: 51% of (1200 / 17) = (51 / 100) × (1200 / 17) = (51 / 17) × (1200 / 100) = 3 × 12 = 36 18² = 324

Adding these terms: 36 + 324 = 360

Now solve for the unknown: 360 = ? × 24 ? = 360 / 24 = 15

195Numerical Ability
What will come in the place of question (?) mark in following questions. 102² ÷ 17 of 25% of 4 ÷ 36 = ?
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Answer: (E) 17

Explanation

Evaluate the 'of' expressions first according to BODMAS rules: 25% of 4 = (25 / 100) × 4 = 1 17 of 1 = 17

Substitute back into the expression and solve from left to right: 102² ÷ 17 ÷ 36 = 10404 ÷ 17 ÷ 36 = 612 ÷ 36 = 17

196Numerical Ability
What will come in the place of question (?) mark in following questions. 35% of 30% of 50% of 6000 = ?
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Answer: (B) 315

Explanation

Calculate successive percentages of the given number: 35% of 30% of 50% of 6000 = (35 / 100) × (30 / 100) × (50 / 100) × 6000 = 0.35 × 0.30 × 0.50 × 6000 = 0.35 × 0.30 × 3000 = 0.35 × 900 = 315

197Numerical Ability
What will come in the place of question (?) mark in following questions. 5 × 12 ÷ 8 × 4 = ?
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Answer: (C) 30

Explanation

Applying BODMAS rules, perform operations of equal precedence from left to right: 5 × 12 ÷ 8 × 4 = (5 × 12) ÷ 8 × 4 = 60 ÷ 8 × 4 = 7.5 × 4 = 30

198Numerical Ability
What will come in the place of question (?) mark in following questions. √(144) +⁴√(256) +? = ³√(324)
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Answer: (A) 2

Explanation

Evaluate the radical terms: √144 = 12 ∜256 = 4 √324 = 18

Substitute these values into the equation: 12 + 4 + ? = 18 16 + ? = 18 ? = 18 - 16 = 2

199Numerical Ability
What will come in the place of question (?) mark in following questions. 17 + 24÷ 6 = ? + √(169)
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Answer: (D) 8

Explanation

Apply BODMAS to evaluate division and square root: 24 ÷ 6 = 4 √169 = 13

Substitute these into the equation: 17 + 4 = ? + 13 21 = ? + 13 ? = 21 - 13 = 8

200Numerical Ability
What will come in the place of question (?) mark in following questions. ((16)² +(10)²) + ⅔ = ?× 6
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Answer: (A) 89

Explanation

Evaluate the squares inside the parentheses: 16² = 256 10² = 100 16² + 10² = 256 + 100 = 356

Apply division by 2/3 and solve for the unknown: 356 ÷ (2 / 3) = 356 × (3 / 2) = 534 534 = ? × 6 ? = 534 / 6 = 89

Answer key

Tap a number to jump to that question.

  1. 151C
  2. 152B
  3. 153E
  4. 154C
  5. 155B
  6. 156E
  7. 157A
  8. 158B
  9. 159D
  10. 160A
  11. 161C
  12. 162B
  13. 163A
  14. 164C
  15. 165E
  16. 166C
  17. 167D
  18. 168A
  19. 169C
  20. 170B
  21. 171C
  22. 172C
  23. 173D
  24. 174E
  25. 175B
  26. 176D
  27. 177C
  28. 178D
  29. 179A
  30. 180C
  31. 181B
  32. 182D
  33. 183B
  34. 184E
  35. 185E
  36. 186A
  37. 187E
  38. 188A
  39. 189E
  40. 190A
  41. 191B
  42. 192B
  43. 193C
  44. 194A
  45. 195E
  46. 196B
  47. 197C
  48. 198A
  49. 199D
  50. 200A

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