The upstream speed and downstream speed of a boat is 20 kmph and 28 kmph respectively and boat travelled for X hours | 6 hours in upstream and downstream respectively. If the distance travelled in downstream is 88 km more than upstream, then find the value of 'X'
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Answer: (A) 4
Explanation
Distance travelled downstream is 28 × 6 = 168 km, and distance travelled upstream is 20 × X km. Given that downstream distance exceeds upstream distance by 88 km, the equation is 168 - 20X = 88. Subtracting 88 from 168 gives 20X = 80, which yields X = 4.
52Numerical Ability
The ratio of cost price to marked price of an article is 2 : 3 and shopkeeper allows Rs 50 discount on marked price. If shopkeeper still made a profit of Rs. 50, then find the selling price of the article (in Rs.)?
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Answer: (C) 250 Rs.
Explanation
Let the cost price be 2x and the marked price be 3x. The selling price can be written as MP - Discount = 3x - 50, and also as CP + Profit = 2x + 50. Equating the two expressions gives 3x - 50 = 2x + 50, which simplifies to x = 100. Therefore, the selling price is 2(100) + 50 = Rs. 250.
53Numerical Ability
A invested Rs. Y and B invested Rs. 800 more than A for same period of time in a partnership. If A gets Rs. 3200 as profit share out of total profit of Rs. 6800, then find 'Y'?
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Answer: (E) 6400
Explanation
Since both investments are for the same period of time, the profit share ratio is equal to the ratio of their investments. B's profit share is 6800 - 3200 = Rs. 3600. The profit ratio of A to B is 3200 / 3600 = 8 / 9. Setting the investment ratio Y / (Y + 800) = 8 / 9 yields 9Y = 8Y + 6400, giving Y = Rs. 6400.
54Numerical Ability
A vessel contains 30 liters of milk and 6 liters of water. X liter of water is added in it. In final mixture water is 30% of the milk. Find the value of 'X'.
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Answer: (A) 3 liters
Explanation
The volume of milk remains constant at 30 liters. In the final mixture, water is 30% of milk, so the required water volume is 0.30 × 30 = 9 liters. Since the initial water volume is 6 liters, the added water X = 9 - 6 = 3 liters.
55Numerical Ability
Area of rectangle is 144 cm² and the length of rectangle is 10 cm more than its breadth. Find the perimeter of the rectangle.
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Answer: (D) 52 cm
Explanation
Let the breadth of the rectangle be b cm, so its length is b + 10 cm. The area equation is b(b + 10) = 144, which expands to b² + 10b - 144 = 0. Factoring gives (b + 18)(b - 8) = 0, yielding b = 8 cm since dimensions must be positive. Thus, length = 18 cm, and the perimeter is 2 × (18 + 8) = 52 cm.
56Numerical Ability
What will come in the place of question (?) mark in following questions.
256 ÷ 16 × 4 ÷ ? = 8
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Answer: (D) 8
Explanation
Evaluating the left-hand side step by step using BODMAS:
256 ÷ 16 = 16
16 × 4 = 64
64 ÷ ? = 8
? = 64 ÷ 8 = 8
57Numerical Ability
What will come in the place of question (?) mark in following questions.
√(40% of (? + 10)) = ²⁰⁰⁄₃% of 6
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Answer: (C) 30
Explanation
First, simplify the right-hand side:
(200/3)% of 6 = (200 / 300) × 6 = 4
Next, set up the left-hand side equation:
√(40% of (? + 10)) = 4
Read the following data carefully and answer the following question.
There are 210 students in a class and all of them like three different players(Dhoni, Rohit and virat). 40 students like only Dhoni, 30 students like all three players, there are total 130 students who like Dhoni and 100 students like Rohit. 40 students like both Dhoni and Rohit only and 10 students like both Virat and Rohit only.
Students like both Virat and Dhoni only are what percent of students like Dhoni only?
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Answer: (A) 50%
Explanation
Total Dhoni liking students = Only Dhoni + Dhoni | Rohit only + Dhoni | Virat only + All three.
Substituting the given values into the formula yields 130 = 40 + 40 + Dhoni | Virat only + 30, which gives Dhoni | Virat only = 20.
The required percentage is (20 / 40) × 100 = 50%.
67Numerical Ability
Read the following data carefully and answer the following question.
There are 210 students in a class and all of them like three different players(Dhoni, Rohit and virat). 40 students like only Dhoni, 30 students like all three players, there are total 130 students who like Dhoni and 100 students like Rohit. 40 students like both Dhoni and Rohit only and 10 students like both Virat and Rohit only.
Number of students like Rohit only is how much less than the students like all three players?
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Answer: (D) 10
Explanation
Total Rohit liking students = Only Rohit + Dhoni | Rohit only + Virat | Rohit only + All three.
Substituting the given values yields 100 = Only Rohit + 40 + 10 + 30, which gives Only Rohit = 20.
The required difference between students who like all three players and those who like only Rohit is 30 - 20 = 10.
68Numerical Ability
Read the following data carefully and answer the following question.
There are 210 students in a class and all of them like three different players(Dhoni, Rohit and virat). 40 students like only Dhoni, 30 students like all three players, there are total 130 students who like Dhoni and 100 students like Rohit. 40 students like both Dhoni and Rohit only and 10 students like both Virat and Rohit only.
Students like Virat are what percent of students like Rohit?
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Answer: (C) 110%
Explanation
Using the Venn diagram values, Dhoni | Virat only = 20 and Only Rohit = 20.
Only Virat = Total students - (Only Dhoni + Only Rohit + Dhoni | Rohit only + Dhoni | Virat only + Virat | Rohit only + All three) = 210 - (40 + 20 + 40 + 20 + 10 + 30) = 50.
Total Virat liking students = Only Virat + Dhoni | Virat only + Virat | Rohit only + All three = 50 + 20 + 10 + 30 = 110.
The required percentage is (110 / 100) × 100 = 110%.
69Numerical Ability
Read the following data carefully and answer the following question.
There are 210 students in a class and all of them like three different players(Dhoni, Rohit and virat). 40 students like only Dhoni, 30 students like all three players, there are total 130 students who like Dhoni and 100 students like Rohit. 40 students like both Dhoni and Rohit only and 10 students like both Virat and Rohit only.
What is the ratio of students like only Virat and only Dhoni together to the students like only Rohit?
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Answer: (B) 9:2
Explanation
Students who like only Virat = 50 and students who like only Dhoni = 40.
Combined count of students who like only Virat and only Dhoni = 50 + 40 = 90.
Students who like only Rohit = 20.
The required ratio is 90 : 20 = 9 : 2.
70Numerical Ability
If a sum of Rs. X invested at the rate of 20% p.a. on compound interest annually and it becomes Rs. 3456 after two years, then find the value of X.
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Answer: (A) 2400 Rs.
Explanation
The compound interest amount formula is A = P(1 + r/100)ⁿ.
Given A = 3456, r = 20, and n = 2:
3456 = X(1 + 20/100)²
3456 = X(1.2)²
3456 = 1.44 X
X = 3456 / 1.44 = 2400
Thus, the initial sum invested is Rs. 2400.
71Numerical Ability
The speed of stream is 40% of speed of boat in still water. If the boat covers 140 km in ten hours in downstream, then find the time taken by boat to cover 60 km in upstream?
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Answer: (D) 10 hr
Explanation
Let the speed of the boat in still water be B km/h.
Speed of the stream S = 0.40 B.
Downstream speed = B + S = B + 0.40 B = 1.40 B.
Given downstream distance is 140 km in 10 hours:
1.40 B = 140 / 10 = 14
B = 10 km/h
S = 0.40 × 10 = 4 km/h
Upstream speed = B - S = 10 - 4 = 6 km/h.
Time taken to cover 60 km upstream = Distance / Upstream speed = 60 / 6 = 10 hours.
72Numerical Ability
A work can be completed by 48 men in 80 days, in how many days 16 men can complete the 200% of the same work?
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Answer: (B) 480 days
Explanation
Total work = Men × Days = 48 × 80 = 3840 man-days.
200% of the work = 2 × 3840 = 7680 man-days.
Number of days required by 16 men = (200% of work) / 16 = 7680 / 16 = 480 days.
73Numerical Ability
The present age of father is 200% more than his son. If after five years the ratio of age of father to son will become 7:3, then find the father's age three years hence will be?
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Answer: (D) 33 years
Explanation
Let the present age of the son be S years.
The father's present age F is 200% more than the son, so F = S + 2 S = 3 S.
After 5 years:
(F + 5) / (S + 5) = 7 / 3
(3 S + 5) / (S + 5) = 7 / 3
3(3 S + 5) = 7(S + 5)
9 S + 15 = 7 S + 35
2 S = 20
S = 10
Father's present age F = 3 × 10 = 30 years.
Father's age three years hence = 30 + 3 = 33 years.
74Numerical Ability
Two person P and Q entered in a business with investments of Rs. 11000 and Rs. 13200 respectively. If Q left the business after 'X' months and at the end of the year P | Q got equal profit share, then find X?
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Answer: (A) 10
Explanation
Profit ratio is directly proportional to the product of investment and time period.
P's investment = Rs. 11000 for 12 months.
Q's investment = Rs. 13200 for X months.
Since P and Q share equal profit:
11000 × 12 = 13200 × X
132000 = 13200 X
X = 10 months
75Numerical Ability
The table chart given below shows the number of males and females in six (P, Q, R, S, T, and U) different companies. Study the data carefully and answer the question given below.
Companies | Number of males | Number of females
P | 120 | 170
Q | 150 | 140
R | 80 | 90
S | 100 | 70
T | 60 | 110
U | 160 | 180
Total number of females in U is what percent more than total number of males in P?
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Answer: (B) 50%
Explanation
Number of females in U = 180
Number of males in P = 120
Percentage more = [(Females in U - Males in P) / Males in P] × 100
Percentage more = [(180 - 120) / 120] × 100 = (60 / 120) × 100 = 50%
76Numerical Ability
The table chart given below shows the number of males and females in six (P, Q, R, S, T, and U) different companies. Study the data carefully and answer the question given below.
Companies | Number of males | Number of females
P | 120 | 170
Q | 150 | 140
R | 80 | 90
S | 100 | 70
T | 60 | 110
U | 160 | 180
Find the average number of males in R, S, and T together?
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Answer: (C) 80
Explanation
Number of males in company R = 80
Number of males in company S = 100
Number of males in company T = 60
Sum = 80 + 100 + 60 = 240
Average = 240 / 3 = 80
77Numerical Ability
The table chart given below shows the number of males and females in six (P, Q, R, S, T, and U) different companies. Study the data carefully and answer the question given below.
Companies | Number of males | Number of females
P | 120 | 170
Q | 150 | 140
R | 80 | 90
S | 100 | 70
T | 60 | 110
U | 160 | 180
Find the ratio between total numbers of females in Q to total number of males in U?
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Answer: (A) 7:8
Explanation
Number of females in Q = 140
Number of males in U = 160
Ratio = 140 : 160 = 7 : 8
78Numerical Ability
The table chart given below shows the number of males and females in six (P, Q, R, S, T, and U) different companies. Study the data carefully and answer the question given below.
Companies | Number of males | Number of females
P | 120 | 170
Q | 150 | 140
R | 80 | 90
S | 100 | 70
T | 60 | 110
U | 160 | 180
Total number of females in S is what percent of total number of males in same class?
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Answer: (B) 70%
Explanation
Number of females in S = 70
Number of males in S = 100
Percentage = (Females in S / Males in S) × 100 = (70 / 100) × 100 = 70%
79Numerical Ability
Gaurav bought a bike for Rs. 26600 and spent Rs. 1400 on its repairing. If he sold it for Rs. 30800, then find the profit percentage of Gaurav?
There are four consecutives even numbers. If sum of first three numbers is 108, then calculate the product of smallest and largest number?
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Answer: (D) 1360
Explanation
Let the four consecutive even numbers be x, x + 2, x + 4, and x + 6.
Sum of the first three numbers is x + (x + 2) + (x + 4) = 3x + 6 = 108.
Solving for x gives 3x = 102, so x = 34.
The four consecutive even numbers are 34, 36, 38, and 40.
The smallest number is 34 and the largest number is 40.
Product of smallest and largest number = 34 × 40 = 1360.
81Numerical Ability
What is the ratio between area of a circle with radius 7cm and perimeter of a circle with diameter 7 cm?
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Answer: (E) 7:1
Explanation
For a circle with radius r = 7 cm, the area is calculated using the formula Area = π × r² = (22/7) × 7² = 154 cm².
For a circle with diameter d = 7 cm, the perimeter (circumference) is given by Circumference = π × d = (22/7) × 7 = 22 cm.
The required ratio of area to perimeter is 154 : 22, which simplifies to 7 : 1.
82Numerical Ability
A train crosses a man, who is running in the same direction of train at the speed of 2m / sec. in 10 seconds. The same train crosses a tunnel in 54 seconds. If speed of train is 72km / h then what is the length of tunnel?
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Answer: (C) 900m
Explanation
Speed of train in m/s = 72 × (5/18) = 20 m/s.
When crossing a man running in the same direction at 2 m/s, relative speed = 20 - 2 = 18 m/s.
Length of train = relative speed × time = 18 × 10 = 180 m.
When crossing a tunnel in 54 seconds, total distance covered = train length + tunnel length = speed of train × time = 20 × 54 = 1080 m.
Tunnel length = 1080 - 180 = 900 m.
83Numerical Ability
70% ofa number is equal to 30% ofanother number. If average of both numbers is 48, then find the larger number?
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Answer: (C) 67.2
Explanation
Given that 70% of first number (A) equals 30% of second number (B):
0.7 × A = 0.3 × B, which gives A/B = 3/7.
The average of the two numbers is (A + B) / 2 = 48, so A + B = 96.
Let A = 3k and B = 7k.
3k + 7k = 10k = 96, which yields k = 9.6.
The larger number is B = 7 × 9.6 = 67.2.
84Numerical Ability
What will come in the place of question (?) mark in following questions.
80% 170 + 75% of216 - 10 = ? × 6
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Answer: (E) 48
Explanation
Evaluate each percentage term in the expression:
80% of 170 = (80 / 100) × 170 = 136.
75% of 216 = (3 / 4) × 216 = 162.
Substituting these calculated values into the expression gives 136 + 162 - 10 = 288.
Set the equation as 288 = ? × 6.
Dividing both sides by 6 yields ? = 288 / 6 = 48.
85Numerical Ability
What will come in the place of question (?) mark in following questions.
37½% of 600 + 14²⁄₇% of 210 = ?
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Answer: (C) 255
Explanation
Convert the given percentage values into their standard fractional equivalents:
37½% is equal to 3/8.
14²⁄₇% is equal to 1/7.
Substitute these fractions back into the given expression:
(3/8) × 600 + (1/7) × 210
Calculate each term separately:
(3/8) × 600 = 225
(1/7) × 210 = 30
Summing the results yields 225 + 30 = 255.
86Numerical Ability
What will come in the place of question (?) mark in following questions.
48 + 8 × 0.75 - 5 = ?
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Answer: (C) 49
Explanation
According to the standard order of operations (BODMAS/PEMDAS), multiplication must be carried out prior to addition and subtraction.
First, multiply 8 by 0.75:
8 × 0.75 = 6.
Now substitute this back into the given expression:
48 + 6 - 5.
Add and subtract in order from left to right:
48 + 6 = 54, then 54 - 5 = 49.
87Numerical Ability
What will come in the place of question (?) mark in following questions.
2950 ÷ 12.5 + 160 = ?
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Answer: (C) 396
Explanation
Following the standard order of operations, perform the division operation before addition.
To divide 2950 by 12.5 easily, express 12.5 as the fraction 25/2.
The calculation is 2950 ÷ (25/2) = (2950 × 2) / 25 = 5900 / 25 = 236.
Next, add 160 to this calculated quotient:
236 + 160 = 396.
88Numerical Ability
What will come in the place of question (?) mark in following questions.
25% of 124 + 35% of 60 = ?
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Answer: (A) 52
Explanation
Calculate each percentage term individually before performing addition.
25% of 124 is equivalent to one-fourth of 124:
(1/4) × 124 = 31.
35% of 60 is calculated as:
(35 / 100) × 60 = 0.35 × 60 = 21.
Summing these two values gives the required result:
31 + 21 = 52.
89Numerical Ability
What will come in the place of question (?) mark in following questions.
√(√(225) ÷ 3 + √(576) ÷ 6) = ?
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Answer: (A) 3
Explanation
First, simplify the square roots inside the main radical sign:
√225 = 15, and 15 ÷ 3 = 5.
√576 = 24, and 24 ÷ 6 = 4.
Adding these two intermediate values gives the expression inside the outer square root:
5 + 4 = 9.
Taking the square root of 9 yields √9 = 3.
90Numerical Ability
What will come in the place of question (?) mark in following questions.
(12)³ × (6)⁴ ÷ 432 = ?
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Answer: (A) 5184
Explanation
Simplifying the expression by power decomposition gives 432 = 12 × 36 = 12 × 6². Substituting this into the original expression:
(12³ × 6⁴) ÷ 432 = (12³ × 6⁴) ÷ (12 × 6²)
Applying exponent subtraction laws for division:
(12³ ÷ 12¹) × (6⁴ ÷ 6²) = 12² × 6²
Using the product rule for exponents:
(12 × 6)² = 72² = 5184.
91Numerical Ability
What will come in the place of question (?) mark in following questions.
45 + 20% of ? = 460 ÷ 4
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Answer: (D) 350
Explanation
Evaluating the right-hand side first yields 460 ÷ 4 = 115. Let the unknown value be x. Rewriting the percentage statement as a decimal gives 20% of x = 0.20 × x. Set up the equation:
45 + 0.20 × x = 115
Subtracting 45 from both sides gives:
0.20 × x = 115 - 45 = 70
Dividing both sides by 0.20 yields:
x = 70 ÷ 0.20 = 350.
92Numerical Ability
What will come in the place of question (?) mark in following questions.
(11)² +(23)² +? = 800
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Answer: (C) 150
Explanation
Calculate the squares of the known integers first:
11² = 121
23² = 529
Summing these two values gives:
121 + 529 = 650
Let the missing number in the equation be represented by x. Substituting the sum into the given equation yields:
650 + x = 800
Solving for x by subtracting 650 from 800 gives:
x = 800 - 650 = 150.
93Numerical Ability
What will come in the place of question (?) mark in following questions.
? + 432 - 206 = 550
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Answer: (E) 324
Explanation
Simplify the equation by evaluating the constant arithmetic operations on the left-hand side first:
432 - 206 = 226
Let x represent the unknown quantity replacing the question mark. The simplified equation is:
x + 226 = 550
Isolating x by subtracting 226 from both sides of the equation gives:
x = 550 - 226 = 324.
Hence, performing basic subtraction yields the correct missing term of 324.
94Numerical Ability
What will come in the place of question (?) mark in following questions.
2⁵ + 2¹⁰ = ? × 12
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Answer: (D) 88
Explanation
First evaluate the exponential terms on the left-hand side of the equation:
2⁵ = 32
2¹⁰ = 1024
Adding these two calculated values gives the left-hand side sum:
32 + 1024 = 1056
Let x represent the missing number replacing the question mark. Set up the algebraic equation:
1056 = x × 12
Isolating x by dividing both sides of the equation by 12 yields:
x = 1056 ÷ 12 = 88.
95Numerical Ability
Study the given data carefully and answer the following questions.
In a college, 7000 students participated in three sports games i.e. (Tennis, Hockey and Kabaddi). The ratio between boys and girls who participated in games is 9:5.30% of the total boys participated in Tennis, which is 125% of the girls who participated in Hockey. Total 2530 students participated in Hockey. number of girls participated in Tennis are 20 more than that of Kabaddi.
Note- A student participated in only in a particular sport.
Find the total number of students participated in Tennis?
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Answer: (A) 2070
Explanation
Total students = 7000, with ratio of boys to girls being 9 : 5.
Total boys = (9 ÷ 14) × 7000 = 4500
Total girls = (5 ÷ 14) × 7000 = 2500
Boys in Tennis = 30% of 4500 = 1350.
Since this is 125% of girls in Hockey, Girls in Hockey = 1350 ÷ 1.25 = 1080.
Total girls = Girls in Tennis + Girls in Hockey + Girls in Kabaddi = 2500.
Given Girls in Tennis = Girls in Kabaddi + 20, let Girls in Kabaddi = G.
(G + 20) + 1080 + G = 2500 ⇒ 2G = 1400 ⇒ G = 700.
Girls in Tennis = 700 + 20 = 720.
Total students in Tennis = 1350 + 720 = 2070.
96Numerical Ability
Study the given data carefully and answer the following questions.
In a college, 7000 students participated in three sports games i.e. (Tennis, Hockey and Kabaddi). The ratio between boys and girls who participated in games is 9:5.30% of the total boys participated in Tennis, which is 125% of the girls who participated in Hockey. Total 2530 students participated in Hockey. number of girls participated in Tennis are 20 more than that of Kabaddi.
Note- A student participated in only in a particular sport.
Boys participated in Kabaddi is what percentage more/less than that of girls participated in the same sport?
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Answer: (D) 142⁶⁄₇%
Explanation
From the overall distribution, total boys = 4500 and total girls = 2500.
Girls in Hockey = 1080.
Boys in Hockey = Total Hockey - Girls in Hockey = 2530 - 1080 = 1450.
Boys in Tennis = 1350.
Boys in Kabaddi = Total Boys - (Boys in Tennis + Boys in Hockey) = 4500 - (1350 + 1450) = 1700.
Girls in Kabaddi = 700.
Percentage excess = [(Boys in Kabaddi - Girls in Kabaddi) ÷ Girls in Kabaddi] × 100%
Percentage excess = [(1700 - 700) ÷ 700] × 100% = (1000 ÷ 700) × 100% = 142 6/7 %.
97Numerical Ability
Study the given data carefully and answer the following questions.
In a college, 7000 students participated in three sports games i.e. (Tennis, Hockey and Kabaddi). The ratio between boys and girls who participated in games is 9:5.30% of the total boys participated in Tennis, which is 125% of the girls who participated in Hockey. Total 2530 students participated in Hockey. number of girls participated in Tennis are 20 more than that of Kabaddi.
Note- A student participated in only in a particular sport.
Find the ratio between number of boys participated in Hockey to the number of girls participated in Kabaddi.
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Answer: (C) 29:14
Explanation
From the main distribution of 7000 students, total boys are 4500 and total girls are 2500.
Boys in Tennis = 1350 and Girls in Hockey = 1080.
Boys in Hockey = Total Hockey students - Girls in Hockey = 2530 - 1080 = 1450.
Girls in Kabaddi = Total Girls - Girls in Hockey - Girls in Tennis = 2500 - 1080 - 720 = 700.
Ratio of Boys in Hockey to Girls in Kabaddi = 1450 : 700 = 29 : 14.
98Numerical Ability
Study the given data carefully and answer the following questions.
In a college, 7000 students participated in three sports games i.e. (Tennis, Hockey and Kabaddi). The ratio between boys and girls who participated in games is 9:5.30% of the total boys participated in Tennis, which is 125% of the girls who participated in Hockey. Total 2530 students participated in Hockey. number of girls participated in Tennis are 20 more than that of Kabaddi.
Note- A student participated in only in a particular sport.
Girls participated in Tennis is what percentage of girls participated in Hockey?
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Answer: (D) 66⅔%
Explanation
From the given data distribution, total girls in Hockey are 1080.
Using the condition that Tennis girls are 20 more than Kabaddi girls:
Girls in Tennis = 720.
To find what percentage the girls in Tennis are of the girls in Hockey:
Percentage = (Girls in Tennis ÷ Girls in Hockey) × 100% = (720 ÷ 1080) × 100% = (2 ÷ 3) × 100% = 66 ⅔ %.
99Numerical Ability
Which number is wrong in the following number series.
9,14,29,54,89,134,179
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Answer: (C) 179
Explanation
Calculate the difference between consecutive terms in the series:
14 - 9 = 5
29 - 14 = 15
54 - 29 = 25
89 - 54 = 35
134 - 89 = 45
The sequence of differences increases uniformly by 10 (5, 15, 25, 35, 45, 55...).
Adding the next difference of 55 to 134 gives 134 + 55 = 189.
Therefore, the final term in the series should be 189 instead of 179.
100Numerical Ability
Which number is wrong in the following number series.
1,3,7,22,89,446,2677
● Correct
● Not quite — the correct answer is highlighted
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Answer: (D) 1
Explanation
The sequence follows the pattern where term Tₙ is generated from Tₙ₋₁ using the formula Tₙ = Tₙ₋₁ × n + 1 for n = 1, 2, 3, ...:
2 × 1 + 1 = 3
3 × 2 + 1 = 7
7 × 3 + 1 = 22
22 × 4 + 1 = 89
89 × 5 + 1 = 446
446 × 6 + 1 = 2677
Replacing 1 with 2 satisfies the rule consistently across all terms.
