IBPS RRB Clerk Prelims 2022 Reasoning Questions with Solutions

Explanation

Corner persons face outside and middle persons face inside. Placing U at the North-middle position facing inside, C sits 3rd to the right at the South-West corner facing outside. T sits 2nd to the left of C at the South-East corner. V sits at the North-East corner to maintain one person between V and T. Y and Q occupy West-middle and North-West corner respectively, sitting immediate left of each other. B sits at South-middle and R sits at East-middle so that R is 2nd to the right of B and does not face Q. Q is at the North-West corner facing outside, so counting three positions clockwise to its left brings us to B at South-middle.

Explanation

In the square table seating arrangement, T sits at the South-East corner, C sits at the South-West corner, Q sits at the North-West corner, and V sits at the North-East corner. Y sits at the West-middle position. Four of the persons sit at corners facing outside, whereas Y sits at a side-middle position facing inside.

Explanation

Based on the seating arrangement, Q sits at the North-West corner of the table facing opposite to the centre. The diagonally opposite position to the North-West corner across the center is the South-East corner, where T is seated.

Explanation

R sits at the East-middle position facing West toward the centre, so the person sitting directly opposite and facing R is Y at the West-middle position. Since Y faces East toward the centre, its left direction moves counter-clockwise along the table. Counting three positions to the left of Y leads to the North-East corner, which is occupied by V.

Explanation

V sits at the North-East corner while Y sits at the West-middle position, so they are not immediate neighbours, which makes statement 1 true. B sits at the South-middle position and faces towards the centre, so statement 2 is false. U sits at the North-middle position, which is to the immediate right of Q, making statement 3 false.

Explanation

The given series is @ V 1 X A D % G H J R 6 Y # I L 9 7 8 %. To satisfy the condition of being immediately preceded and immediately followed by an alphabet, a number must match the sequence Alphabet-Number-Alphabet. Checking each number: 1 is preceded by V and followed by X; 6 is preceded by R and followed by Y. The numbers 9, 7, and 8 do not meet this condition. Thus, there are two such numbers.

Explanation

The vowels present in the series are A and I. Removing them yields the sequence following 1 as: X, D, %, G, , , H, J, R, 6, Y, #, L, 9,, 7, 8, %. Counting 5 elements to the right from 1 gives X (1st), D (2nd), % (3rd), G (4th), and (5th).

Explanation

Scanning the alphanumeric series @ V 1 X A D % G H J R 6 Y # I L 9 7 8 % for the pattern Symbol-Letter gives four valid pairs: @ V, % G, H, and # I. Therefore, four letters are immediately preceded by a symbol.

Explanation

Using the position formula for same-direction operations, the position from the left end is calculated as 15 - 9 = 6th element from the left. Counting to the 6th element from the left in the series @ V 1 X A D % G H J R 6 Y # I L 9 7 8 % yields D.

Explanation

Eliminating all alphabets (V, X, A, D, G, H, J, R, Y, I, L) leaves the remaining sequence of non-alphabet elements: @, 1, %, , , 6, #, 9,, 7, 8, %. In this sequence, 8 is at position 11. Counting 9 positions to the left (11 - 9 = 2) brings us to the 2nd element, which is 1.

Explanation

Arranging the schedule from Monday to Sunday gives: Monday (S), Tuesday (U), Wednesday (R), Thursday (T), Friday (Y), Saturday (H), and Sunday (K). Since H goes to market on Saturday, only one person goes to market after H, which is K on Sunday.

Explanation

Arranging the schedule from Monday to Sunday gives: Monday (S), Tuesday (U), Wednesday (R), Thursday (T), Friday (Y), Saturday (H), and Sunday (K). Since U goes to market on Tuesday, three days after Tuesday corresponds to Friday, which is when Y goes to market.

Explanation

Arranging the schedule from Monday to Sunday gives: Monday (S), Tuesday (U), Wednesday (R), Thursday (T), Friday (Y), Saturday (H), and Sunday (K). The number of persons going to market between S (Monday) and U (Tuesday) is zero. Similarly, zero persons go to market before S.

Explanation

Arranging the schedule from Monday to Sunday gives: Monday (S), Tuesday (U), Wednesday (R), Thursday (T), Friday (Y), Saturday (H), and Sunday (K). Statement I is true as R goes on Wednesday, which is before Thursday. Statement II is true because H goes on Saturday, which is after Thursday. Statement III claims that more than three persons go between Y (Friday) and S (Monday), but there are exactly three persons (U, R, T) between them, making statement III false.

Explanation

Arranging the schedule from Monday to Sunday gives: Monday (S), Tuesday (U), Wednesday (R), Thursday (T), Friday (Y), Saturday (H), and Sunday (K). Since R goes to market on Wednesday and K goes on Sunday, there are exactly three persons (T on Thursday, Y on Friday, and H on Saturday) between K and R.

Explanation

Since all shine are cloud and a few cloud are nine, shine can be entirely contained within nine without violating any condition, so conclusion I follows as a possibility. Similarly, bright only has a negative relation with shine and no restriction with nine, so all bright can sit inside nine without intersecting shine, meaning conclusion II also follows as a possibility.

Explanation

Since all music is play and no play is right, no music can ever be right, making conclusion I definitely true. For conclusion II, a few guitar are music, and since no music can be right, that overlapping portion of guitar can never be right, which makes it impossible for all guitar to be right.

Explanation

No direct relation is established between home and window in the given statements. Therefore, either some home are window or no window is home must hold true, forming a standard complementary pair where exactly one of the two conclusions must be true.

Explanation

The statement that only flowers are petals means petals belong exclusively to flowers and cannot be leaves. Additionally, some stems are flowers and no leaves are stems, so those portions of flowers can never be leaves, making conclusion I definitely true. Conclusion II expresses the possibility that no leaves are flowers, which is valid because leaves can be drawn entirely disjoint from flowers without violating any statements.

Explanation

There is no negative relation between photo and light, so it is possible for some photo to be light, making conclusion I follow. For conclusion II, no light is play, but play can sit entirely inside the portion of camera that does not overlap with light, making it possible for all play to be camera.

Explanation

The 1st, 4th, 6th, and 8th letters of EDITORIAL are E, T, R, and A respectively. Using these letters, more than one meaningful four-letter word can be formed, such as RATE, TEAR, and TARE. Following the given instruction, when more than one meaningful word can be formed, the answer is represented by Z.

Explanation

Taking point T as the origin (0, 0), point R is 4m south at (0, -4). Point S is 5m east of R, placing it at (5, -4). The shortest distance between T and S is given by √((5 - 0)² + (-4 - 0)²) = √(25 + 16) = √41m.

Explanation

Point K is located at (5, -11). Point I is 10m east of K at (15, -11). Point J lies directly east of T (0, 0) and north of I, giving it coordinates (15, 0). The path distance from K to J going through I is the horizontal distance KI plus the vertical distance IJ, which equals 10m + 11m = 21m.

Explanation

With respect to T at (0, 0), point P is located 3m west of R, placing it at (-3, -4). Point I is located at (15, -11). Comparing the coordinates, point I is 18m to the east and 7m to the south of point P. Therefore, point I is in the South-East direction relative to point P.

Explanation

In the number 463527139, pair (5, 7) has 1 digit between them ('2'), matching the single number 6 between 5 and 7 in the number series. Pair (3, 9) at positions 3 and 9 has 5 digits between them, matching the 5 numbers (4, 5, 6, 7, 8) between 3 and 9. Counting backward, pair (6, 1) at positions 2 and 7 has 4 digits between them, matching the 4 numbers (2, 3, 4, 5) between 1 and 6. Hence, there are 3 such pairs.

Explanation

A is born on an even date in a 31-day month, so A is on 28th January. C is born before A, placing C on 5th January. For the remaining slots, E is on 5th June, B is on 28th June, D is on 5th September, and F is on 28th September, satisfying two persons between E and F and B born immediately before D. Thus, C was born on 5th January.

Explanation

The complete order of birth dates is C (Jan 5), A (Jan 28), E (Jun 5), B (Jun 28), D (Sep 5), and F (Sep 28). The person born just after D is F, who is the last person in the sequence. Therefore, exactly 5 persons were born before F.

Explanation

E and B were born in June, and D and F were born in September, all of which are months having 30 days. A was born on 28th January, which is a month having 31 days. Therefore, A does not belong to the group formed by the other four.

Explanation

Based on the puzzle arrangement, the six persons in chronological order of birth are C (5th January), A (28th January), E (5th June), B (28th June), D (5th September), and F (28th September). Thus, F was born on 28th September.

Explanation

A was born on 28th January and B was born on 28th June. Since both were born on the same date number (28th), the assertion that A and B were born on different numbered dates is incorrect.

Explanation

An integer is odd if its unit digit is odd. When the first and third digits of each three-digit number in the series 923, 983, 628, 476, and 458 are interchanged, the original first digit becomes the new unit digit. The original first digits are 9, 9, 6, 4, and 4. Since 9 is odd, the numbers formed from 923 and 983 become 329 and 389, which are odd. The remaining numbers end in even digits 6 and 4, forming 826, 674, and 854. Therefore, exactly two odd numbers are formed.

Explanation

Arranging the digits of each number in descending order from left to right transforms the series 923, 983, 628, 476, and 458 into 932, 983, 862, 764, and 854. Ordering these newly formed numbers from lowest to highest gives 764, 854, 862, 932, and 983. The highest number formed is 983 and the second lowest number formed is 854. Adding these two values together gives 983 + 854 = 1837.

Explanation

Adding 1 to even numbers and subtracting 2 from odd numbers transforms the given set 923, 983, 628, 476, and 458 as follows: 923 becomes 921, 983 becomes 981, 628 becomes 629, 476 becomes 477, and 458 becomes 459. Arranging the modified numbers in descending order gives 981, 921, 629, 477, and 459. The third highest number in this transformed sequence is 629, which was derived from the original number 628.

Explanation

Arranging numbers in ascending order from right to left means the smallest number is placed at the extreme right end and numbers increase towards the left end. The ascending order of the given set 923, 983, 628, 476, and 458 is 458, 476, 628, 923, and 983. Positioning them from right to left produces the left-to-right sequence 983, 923, 628, 476, and 458. Counting from the left end, the first is 983, the second is 923, the third is 628, and the fourth number from the left end is 476.

Explanation

A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Evaluating the set 923, 983, 628, 476, and 458: 923 and 983 are odd numbers and cannot be divisible by 4; for 628, the last two digits 28 are divisible by 4 (28 ÷ 4 = 7); for 476, the last two digits 76 are divisible by 4 (76 ÷ 4 = 19); for 458, the last two digits 58 are not divisible by 4 (58 ÷ 4 = 14.5). Thus, exactly two numbers are divisible by 4.

Explanation

In the inequality statement P > T ≥ U < M = H ≥ W > L ≤ J, comparing T and W involves the path T ≥ U < M = H ≥ W. The presence of opposing relational symbols ≥ and < between T and M breaks the chain, so no definite relationship exists between T and W. Similarly, comparing H and T involves H = M > U ≤ T, where opposing symbols > and ≤ break the connection between H and T. Neither conclusion I nor conclusion II holds true.

Explanation

Examining the statement 7 > 9 ≤ 6 = 1 ≥ 4 > 3 = 2, to evaluate conclusion I (9 < 4), the path between 9 and 4 is 9 ≤ 6 = 1 ≥ 4. Opposing relational symbols ≤ and ≥ mean no definite relation can be established between 9 and 4. To evaluate conclusion II (2 < 6), follow the relation from 6 to 2: 6 = 1 ≥ 4 > 3 = 2. Since 6 equals 1, and 1 is greater than or equal to 4, which is strictly greater than 3, which equals 2, it directly follows that 6 > 2. Reversing this inequality gives 2 < 6, making conclusion II definitely true.

Explanation

The given statement splits into two independent relational groups: A ≤ D ≤ S = T and Y ≥ M < F. There is no common element or defined relationship linking the variables A, D, S, T to Y, M, F. For conclusion I (D < Y), no comparative path exists between D and Y. For conclusion II (S ≥ F), no comparative path exists between S and F. Because no definitive relationship can be deduced for either pair, neither conclusion follows.

Explanation

Analyzing the statement P > T ≥ U < M = H ≥ W > L ≤ J, for conclusion I (U < H), the direct inequality chain from U to H is U < M = H, which immediately simplifies to U < H. Thus, conclusion I is definitely true. For conclusion II (W ≤ T), tracing from T to W gives T ≥ U < M = H ≥ W. The opposing symbols ≥ and < between T and M prevent establishing any definite order between T and W. Therefore, only conclusion I is true.

Explanation

Applying the given transformation rule to each letter of the word POPULISM: P is a consonant and becomes Q. O is a vowel and becomes N. P is a consonant and becomes Q. U is a vowel and becomes T. L is a consonant and becomes M. I is a vowel and becomes H. S is a consonant and becomes T. M is a consonant and becomes N.

The resulting set of letters is Q, N, Q, T, M, H, T, N. Counting the frequency of each letter in this transformed sequence shows that Q appears twice, N appears twice, T appears twice, while M and H each appear once. Therefore, exactly three letters appear twice.

Explanation

Interchanging the first two letters of each word gives CTB, UYQ, FIL, NBD, NDU, and CAT. Among these transformed words, only CAT forms a valid English word. Thus, exactly one meaningful word is formed.

Explanation

Changing consonants to their previous letter (-1) and vowels to their next letter (+1) transforms the given words as follows: TCB becomes SBA (contains vowel A) YUQ becomes XVP (no vowel) IFL becomes JEK (contains vowel E) BND becomes AMC (contains vowel A) DNU becomes CMV (no vowel) ACT becomes BBS (no vowel)

Thus, three words contain at least one vowel.

Explanation

Arranging the given six words alphabetically from left to right yields: ACT BND DNU IFL TCB YUQ

Counting from the right end, YUQ is first, TCB is second, and IFL is third.

Explanation

Sorting the letters of each word alphabetically yields BCT, QUY, FIL, BDN, DNU, and ACT. Interchanging the first and second letters of each transformed word gives CBT, UQY, IFL, DBN, NDU, and CAT. Only CAT is a meaningful English word, so exactly one meaningful word is formed.

Explanation

Changing the last letter of each word to its next alphabetical letter gives: TCB becomes TCC (0 vowels) YUQ becomes YUR (1 vowel: U) IFL becomes IFM (1 vowel: I) BND becomes BNE (1 vowel: E) DNU becomes DNV (0 vowels) ACT becomes ACU (2 vowels: A, U)

Only ACU contains more than one vowel, so exactly one word meets the criterion.

Explanation

Evaluating the positional constraints from top (1) to bottom (6): Since at most two boxes are above Covishield and two boxes lie between Covishield and Covaxin, with Pfizer below Covaxin, Covishield must be at position 2 and Covaxin at position 5, placing Pfizer at position 6. Sputnik is 3 places above Moderna, so Sputnik is at position 1 and Moderna is at position 4. The remaining position 3 is occupied by AstraZeneca.

The complete top-to-bottom order is: Sputnik Covishield AstraZeneca Moderna Covaxin Pfizer

Covishield is placed directly above AstraZeneca.

Explanation

The arrangement of vaccine boxes from top (1) to bottom (6) is: Sputnik Covishield AstraZeneca Moderna Covaxin Pfizer

Because Sputnik occupies position 1 and Covishield occupies position 2, they are adjacent, meaning zero boxes lie between them.

Explanation

The original top-to-bottom arrangement is: Sputnik Covishield AstraZeneca Moderna Covaxin Pfizer

Interchanging Moderna (position 4) and Pfizer (position 6) places Pfizer at position 4. The box directly above position 4 is AstraZeneca at position 3.

Explanation

In the top-to-bottom order (1-Sputnik, 2-Covishield, 3-AstraZeneca, 4-Moderna, 5-Covaxin, 6-Pfizer): Between Covishield (position 2) and Pfizer (position 6), there are 3 boxes (AstraZeneca, Moderna, Covaxin). Between Sputnik (position 1) and Covaxin (position 5), there are also 3 boxes (Covishield, AstraZeneca, Moderna). Therefore, both statement pairs satisfy the condition.

Explanation

The vaccine boxes in order from top (1) to bottom (6) are: Sputnik Covishield AstraZeneca Moderna Covaxin Pfizer

Position 3 is occupied by AstraZeneca, which is located directly below Covishield at position 2.