IBPS RRB Clerk2022Numerical AbilityPage 1 of 7

IBPS RRB Clerk Prelims 2022 Numerical Ability Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1–50 of 308, each with the correct answer and a step-by-step explanation.

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1Numerical Ability
Table give below shows total numbers of fours and sixes hit by three different players. Read the data carefully and answer the questions. Players | Number of fours hit | Number of sixes hit A | 62 | 40 B | 31 | 25 C | 44 | 20 Find the difference between total run scored by C from fours and total run scored by A from sixes?
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Answer: (B) 64

Explanation

Total runs scored by C from fours = 44 × 4 = 176. Total runs scored by A from sixes = 40 × 6 = 240. Difference = 240 - 176 = 64.

2Numerical Ability
Table give below shows total numbers of fours and sixes hit by three different players. Read the data carefully and answer the questions. Players | Number of fours hit | Number of sixes hit A | 62 | 40 B | 31 | 25 C | 44 | 20 Find the ratio of total run scored by B from sixes to total run scored by C from sixes?
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Answer: (D) 5 : 4

Explanation

Total runs scored by B from sixes = 25 × 6 = 150. Total runs scored by C from sixes = 20 × 6 = 120. Required ratio = 150 : 120 = 5 : 4.

3Numerical Ability
Table give below shows total numbers of fours and sixes hit by three different players. Read the data carefully and answer the questions. Players | Number of fours hit | Number of sixes hit A | 62 | 40 B | 31 | 25 C | 44 | 20 If total fours hit by X is 9 1/11% more than that of by C and total sixes hit by X is 25% more than total sixes hit by A, then find total run scored by X from fours | sixes?
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Answer: (E) 492

Explanation

Number of fours hit by X = 44 × (1 + 1/11) = 48. Number of sixes hit by X = 40 × (1 + 1/4) = 50. Total runs scored by X from fours and sixes = (48 × 4) + (50 × 6) = 192 + 300 = 492.

4Numerical Ability
Table give below shows total numbers of fours and sixes hit by three different players. Read the data carefully and answer the questions. Players | Number of fours hit | Number of sixes hit A | 62 | 40 B | 31 | 25 C | 44 | 20 Find the average of run scored by A and C from fours?
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Answer: (D) 212

Explanation

Average number of fours hit by A and C = (62 + 44) / 2 = 53. Average runs scored from fours = 53 × 4 = 212.

5Numerical Ability
Table give below shows total numbers of fours and sixes hit by three different players. Read the data carefully and answer the questions. Players | Number of fours hit | Number of sixes hit A | 62 | 40 B | 31 | 25 C | 44 | 20 Total runs scored by A from fours is what percent (approx..) more than total run scored by B from sixes?
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Answer: (C) 65%

Explanation

Total runs scored by A from fours = 62 × 4 = 248. Total runs scored by B from sixes = 25 × 6 = 150. Percentage excess = [(248 - 150) / 150] × 100 = (98 / 150) × 100 = 65.33% ≈ 65%.

6Numerical Ability
Find out the missing number in the given number series. 1, 2, 5, 10, 17, ?
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Answer: (C) 26

Explanation

The pattern in the series follows adding consecutive odd numbers: 1 + 1 = 2 2 + 3 = 5 5 + 5 = 10 10 + 7 = 17 17 + 9 = 26

7Numerical Ability
Find out the missing number in the given number series. 8, 12, 20, 36, 68, ?
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Answer: (A) 132

Explanation

The differences between successive terms are powers of 2: 12 - 8 = 4 20 - 12 = 8 36 - 20 = 16 68 - 36 = 32 Next difference = 32 × 2 = 64 Missing term = 68 + 64 = 132.

8Numerical Ability
Find out the missing number in the given number series. 2, ?, 30, 74, 154, 282
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Answer: (D) 10

Explanation

Analyzing the second-order differences of the series: 282 - 154 = 128 154 - 74 = 80 74 - 30 = 44 Differences of differences are 128 - 80 = 48 and 80 - 44 = 36, forming a sequence decreasing by 12. Previous second-order differences = 36 - 12 = 24 and 24 - 12 = 12. Previous first-order differences: 44 - 24 = 20 20 - 12 = 8 Therefore, the missing number = 2 + 8 = 10.

9Numerical Ability
Find out the missing number in the given number series. 5, 6, 10, 19, 35, ?
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Answer: (B) 60

Explanation

The sequence of differences consists of squares of consecutive integers: 6 - 5 = 1² = 1 10 - 6 = 2² = 4 19 - 10 = 3² = 9 35 - 19 = 4² = 16 Next difference = 5² = 25 Missing term = 35 + 25 = 60.

10Numerical Ability
Find out the missing number in the given number series. 1, 6, 16, 31, 51, ?
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Answer: (D) 76

Explanation

The pattern in the series adds increasing multiples of 5 to each term: 1 + 5 = 6 6 + 10 = 16 16 + 15 = 31 31 + 20 = 51 51 + 25 = 76

11Numerical Ability
A man invested Rs. P at the rate of 10% p.a. on simple interest for four years and gets a total interest of Rs. 1000. If he invested Rs. (P + 500) at 20% p.a. on simple interest for two years, then find the interest received by man?
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Answer: (E) Rs. 1200

Explanation

Using the simple interest formula SI = (P × R × T) / 100, the initial interest gives 1000 = (P × 10 × 4) / 100, which simplifies to 0.4 × P = 1000, so P = 2500. The new principal invested is P + 500 = 2500 + 500 = 3000. Applying the formula for the second investment with P = 3000, R = 20%, and T = 2 years gives SI = (3000 × 20 × 2) / 100 = 1200.

12Numerical Ability
Average age of nine member of a family is 31 years and four months. If the age of youngest members of the family is 18 years, then find the average age (in years) of remaining eight members of the family six years ago?
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Answer: (D) 27

Explanation

The average age of 9 members is 31 years 4 months, which equals 31 + 4/12 = 94/3 years. The total age of all 9 members is 9 × (94/3) = 282 years. Subtracting the youngest member's age of 18 years gives the sum of the ages of the remaining 8 members as 282 − 18 = 264 years. Their current average age is 264 / 8 = 33 years. Subtracting 6 years from their current average gives their average age six years ago as 33 − 6 = 27 years.

13Numerical Ability
The population a city after three years will be 21,600. If rate of increase of population per year be 20% then find the present population of the city?
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Answer: (A) 12,500

Explanation

Let P be the present population. With an annual increase rate of 20%, the population increases by a factor of 1 + 20/100 = 6/5 each year. The population after 3 years is given by P × (6/5)³ = P × (216 / 125). Setting this equal to 21,600 gives 21600 = P × 216 / 125, which simplifies to P = (21600 × 125) / 216 = 12,500.

14Numerical Ability
A shopkeeper marks up the price of an article by 40% above cost price. He allows 25% discount on mark price and earns Rs 420 as profit. If he allows discount of 20% at the place of 25%, then find his profit?
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Answer: (D) Rs 1008

Explanation

Let the cost price be 100x. The marked price at 40% markup is 140x. With a 25% discount, the selling price is 140x × 0.75 = 105x, yielding a profit of 105x − 100x = 5x. Given 5x = 420, we find x = 84. If the discount is 20%, the new selling price becomes 140x × 0.80 = 112x. The new profit is 112x − 100x = 12x = 12 × 84 = 1008.

15Numerical Ability
The circumference of two circles is 132 m and 176 m respectively. Find the difference between the area (in m²) of larger circle and smaller circle?
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Answer: (D) 1078

Explanation

From the circumference formula C = 2 × π × r, the radius of the smaller circle is r₁ = 132 / (2 × 22/7) = 21 m, and the radius of the larger circle is r₂ = 176 / (2 × 22/7) = 28 m. The difference between the areas is π × (r₂² − r₁²) = (22/7) × (28² − 21²) = (22/7) × (28 + 21) × (28 − 21) = (22/7) × 49 × 7 = 22 × 49 = 1078 m².

16Numerical Ability
A takes three times as long as B | C together take to do a work. If all the three working together can complete the work in 24 days, then find in how many days A will complete the work alone?
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Answer: (B) 96

Explanation

Let the time taken by B and C together to complete the work be t days. Then A takes 3t days to finish the work alone. The daily work rate of A is 1/(3t) and that of B and C together is 1/t. The combined work rate of all three is 1/(3t) + 1/t = 4/(3t). Since all three complete the work together in 24 days, 4/(3t) = 1/24, which gives 3t = 96. Thus, A alone takes 96 days.

17Numerical Ability
The speed of boat in upstream is 3/5th of the speed of boat in downstream. If the speed of boat in still water is 6 km/hr more than the speed of stream, then find the total time taken by boat to cover 35 km in downstream and 15 km in upstream?
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Answer: (D) 6 hours

Explanation

Let boat speed in still water be u and stream speed be v. Upstream speed is u − v = 6 km/hr. Since upstream speed is 3/5 of downstream speed, downstream speed is 6 × (5/3) = 10 km/hr. Time taken to travel 35 km downstream is 35 / 10 = 3.5 hours. Time taken to travel 15 km upstream is 15 / 6 = 2.5 hours. Total time required is 3.5 + 2.5 = 6 hours.

18Numerical Ability
A invested Rs.9000 in a business. After four months, B joined the business with Rs. 'X'. If at the end of the year, the profit share of B is Rs.800 out of the total profit of Rs.1700, then find X?
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Answer: (A) 12000

Explanation

A invests Rs. 9000 for 12 months, giving an investment-time product of 9000 × 12 = 108,000. B invests Rs. X for 12 − 4 = 8 months, giving a product of 8X. Total profit is Rs. 1700 and B's share is Rs. 800, so A's share is 1700 − 800 = 900. The profit ratio equals the investment-time product ratio, so 900 / 800 = 108000 / (8X), which simplifies to 9 / 8 = 13500 / X, giving X = (13500 × 8) / 9 = 12000.

19Numerical Ability
A container contains mixture of milk and water in which milk is 50% more than that of water. If four liter of milk is added in the vessel, then now milk becomes 100% more than water. Find the initial quantity of mixture?
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Answer: (A) 20 liters

Explanation

Let the initial quantity of water be W liters. Since milk is 50% more than water, initial milk is 1.5W liters, making the total initial mixture 2.5W liters. Adding 4 liters of milk makes milk 100% more than water, so 1.5W + 4 = 2W. Solving this gives 0.5W = 4, so W = 8 liters. The total initial mixture is 2.5 × 8 = 20 liters.

20Numerical Ability
A train having length of 110 meter is running at a speed of 72 kmph. If length of a platform is 4.5 times to the length of the train, then find how much time train will take to cross the platform?
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Answer: (D) 30.25 Second

Explanation

The length of the train is 110 meters, and the length of the platform is 4.5 × 110 = 495 meters. The total distance the train must cover to cross the platform is 110 + 495 = 605 meters. The speed of the train in meters per second is 72 × (5/18) = 20 m/s. The time taken to cross the platform is total distance divided by speed, which gives 605 / 20 = 30.25 seconds.

21Numerical Ability
What will come in place of question mark(?) in the given questions. 6080 ÷ 19 = ?% of 256
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Answer: (D) 125

Explanation

Evaluating the left-hand side gives 6080 ÷ 19 = 320. Setting up the percentage equation: 320 = (? / 100) × 256. Solving for ?: ? = (320 × 100) / 256 ? = 32000 / 256 = 125.

22Numerical Ability
What will come in place of question mark(?) in the given questions. (48% of 625) + 0.75 = ?
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Answer: (E) 400

Explanation

First, calculate 48% of 625: (48 / 100) × 625 = 12 × 25 = 300. Next, divide 300 by 0.75: 300 ÷ 0.75 = 300 ÷ (3 / 4) = 300 × (4 / 3) = 400.

23Numerical Ability
What will come in place of question mark(?) in the given questions. √(225) + 150 × 30 + 6 - 11 × 20 = ?
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Answer: (C) 545

Explanation

Applying standard order of operations: √225 = 15 150 × 30 ÷ 6 = 4500 ÷ 6 = 750 11 × 20 = 220 Combining these terms gives 15 + 750 - 220 = 545.

24Numerical Ability
What will come in place of question mark(?) in the given questions. 345 + 727 - 628 = ?
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Answer: (B) 444

Explanation

Following basic arithmetic operations from left to right: 345 + 727 = 1072 1072 - 628 = 444.

25Numerical Ability
What will come in place of question mark(?) in the given questions. ? - 16² = 428 - 298
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Answer: (A) 386

Explanation

Evaluate the numerical terms: 16² = 256 428 - 298 = 130 Rearranging the equation to solve for ?: ? = 130 + 256 = 386.

26Numerical Ability
What will come in place of question mark(?) in the given questions. 4⅝ + ³⁄₂ - 2⅔ = ?
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Answer: (B) 3¹¹⁄₂₄

Explanation

Convert 3/2 to 1 + 1/2. Separating the whole numbers and fractions: Whole number part = 4 + 1 - 2 = 3 Fractional part = 5/8 + 1/2 - 2/3 Taking the LCM of denominators 8, 2, and 3 as 24: (15 + 12 - 16) / 24 = 11/24 Combining the whole and fractional parts gives 3 11/24.

27Numerical Ability
What will come in place of question mark(?) in the given questions. 360 - 80% of 1200 = ? - 840
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Answer: (B) 240

Explanation

Calculate 80% of 1200: (80 / 100) × 1200 = 960 Left-hand side of the equation: 360 - 960 = -600 Solving for ?: -600 = ? - 840 ? = 840 - 600 = 240.

28Numerical Ability
What will come in place of question mark(?) in the given questions. √? = 28² - 1180 + 20²
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Answer: (C) 16

Explanation

Evaluate the right-hand side of the equation: 28² = 784 20² = 400 784 - 1180 + 400 = 1184 - 1180 = 4 Setting up the equation for ?: √? = 4 Squaring both sides gives ? = 4² = 16.

29Numerical Ability
What will come in place of question mark(?) in the given questions. (?)² + 25 × 12 = 4800 + 12
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Answer: (A) 10

Explanation

Applying order of operations: 25 × 12 = 300 4800 ÷ 12 = 400 Substitute these into the equation: (?)² + 300 = 400 (?)² = 100 ? = √100 = 10.

30Numerical Ability
What will come in place of question mark(?) in the given questions. (36 × 8) - (440 ÷ 8) = ?
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Answer: (C) 233

Explanation

Evaluate each term within the brackets: 36 × 8 = 288 440 ÷ 8 = 55 Subtracting the second term from the first: 288 - 55 = 233.

31Numerical Ability
What will come in place of question mark(?) in the given questions. 2 ⅓ + 3 ⅙ = ? - 1 ½
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Answer: (C) 7

Explanation

Adding the mixed fractions on the left side gives 7/3 + 19/6 = 14/6 + 19/6 = 33/6 = 11/2. Expressing 1 ½ as 3/2 on the right side gives ? − 3/2 = 11/2, so ? = 11/2 + 3/2 = 14/2 = 7.

32Numerical Ability
What will come in place of question mark(?) in the given questions. 20% of (? + 96) = 30 × 1.6
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Answer: (D) 144

Explanation

Evaluating the right side gives 30 × 1.6 = 48. Substituting this into 20% × (? + 96) = 48 yields 0.2 × (? + 96) = 48. Dividing both sides by 0.2 gives ? + 96 = 240, so ? = 240 − 96 = 144.

33Numerical Ability
Two companies A | B manufacturing three different items Balloons, Balls and Toys. Total balloons manufactured by B is 25% more than that of by A and the ratio of total balloons to total balls manufactured by A is 2: 3. The difference between total balloons manufactured by B and total balls manufactured by A is 5 and total balls manufactured by B is six more than that of by A. The ratio of total toys manufactured by A to that of by B is 5: 6 and the difference between total toys manufactured by A and B is 8. Find the difference between total balls manufactured by A | B together and total toys manufactured by A | B together?
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Answer: (E) 22

Explanation

Let balloons by A be x. Then balloons by B = 1.25x and balls by A = 1.5x. The difference between balls by A and balloons by B is 1.5x − 1.25x = 0.25x = 5, giving x = 20. Thus, A manufactures 20 balloons and 30 balls, while B manufactures 25 balloons and 30 + 6 = 36 balls. Total balls by A and B combined = 30 + 36 = 66. For toys, the ratio is 5:6 with a difference of 8, so 6y − 5y = 8, giving y = 8. Company A manufactures 40 toys and B manufactures 48 toys. Total toys by A and B combined = 40 + 48 = 88. The difference between total toys and total balls is 88 − 66 = 22.

34Numerical Ability
Two companies A | B manufacturing three different items Balloons, Balls and Toys. Total balloons manufactured by B is 25% more than that of by A and the ratio of total balloons to total balls manufactured by A is 2: 3. The difference between total balloons manufactured by B and total balls manufactured by A is 5 and total balls manufactured by B is six more than that of by A. The ratio of total toys manufactured by A to that of by B is 5: 6 and the difference between total toys manufactured by A and B is 8. Total balloons manufactured by A is what percent less than total balloons manufactured by B?
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Answer: (E) 20%

Explanation

Let balloons manufactured by A be x, so balloons by B = 1.25x and balls by A = 1.5x. Given 1.5x − 1.25x = 5, we get 0.25x = 5, which gives x = 20. Thus, A manufactures 20 balloons and B manufactures 25 balloons. The percentage by which A is less than B is ((25 − 20) / 25) × 100% = (5 / 25) × 100% = 20%.

35Numerical Ability
Two companies A | B manufacturing three different items Balloons, Balls and Toys. Total balloons manufactured by B is 25% more than that of by A and the ratio of total balloons to total balls manufactured by A is 2: 3. The difference between total balloons manufactured by B and total balls manufactured by A is 5 and total balls manufactured by B is six more than that of by A. The ratio of total toys manufactured by A to that of by B is 5: 6 and the difference between total toys manufactured by A and B is 8. Find average number of all three items manufactured by A?
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Answer: (B) 30

Explanation

Let balloons by A be x, so balloons by B = 1.25x and balls by A = 1.5x. Since 1.5x − 1.25x = 5, x = 20. Thus, company A manufactures 20 balloons and 30 balls. For toys, since the ratio of A to B is 5:6 and the difference is 8, company A manufactures 5 × 8 = 40 toys. Total items manufactured by A = 20 + 30 + 40 = 90. The average number of items manufactured by A is 90 / 3 = 30.

36Numerical Ability
The table given below shows number of orders received by three (A, B | C) companies of their three (Pen, Pencil | Eraser) items. Read the data carefully and answer the questions. Companies | Pen | Pencil | Eraser A | 160 | 120 | 100 B | 80 | 140 | 180 C | 160 | 200 | 60 Total orders of item Pen | Pencil received by C is how much more than total orders of item Pencil | Eraser received by B?
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Answer: (C) 40

Explanation

Total orders of Pen and Pencil received by company C = 160 + 200 = 360. Total orders of Pencil and Eraser received by company B = 140 + 180 = 320. The required difference is 360 - 320 = 40.

37Numerical Ability
The table given below shows number of orders received by three (A, B | C) companies of their three (Pen, Pencil | Eraser) items. Read the data carefully and answer the questions. Companies | Pen | Pencil | Eraser A | 160 | 120 | 100 B | 80 | 140 | 180 C | 160 | 200 | 60 Find total orders (all three items) received by C is what percent more than that of total orders (all three items) received by B?
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Answer: (A) 5%

Explanation

Total orders received by company C across all items = 160 + 200 + 60 = 420. Total orders received by company B across all items = 80 + 140 + 180 = 400. Percentage excess = [(420 - 400) / 400] × 100 = (20 / 400) × 100 = 5%.

38Numerical Ability
The table given below shows number of orders received by three (A, B | C) companies of their three (Pen, Pencil | Eraser) items. Read the data carefully and answer the questions. Companies | Pen | Pencil | Eraser A | 160 | 120 | 100 B | 80 | 140 | 180 C | 160 | 200 | 60 Find ratio of total orders of item Pen | Pencil received by A to total orders of item Pencil | Eraser received by B?
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Answer: (E) 7:8

Explanation

Total orders of Pen and Pencil received by company A = 160 + 120 = 280. Total orders of Pencil and Eraser received by company B = 140 + 180 = 320. The required ratio is 280 : 320 = 7 : 8.

39Numerical Ability
The table given below shows number of orders received by three (A, B | C) companies of their three (Pen, Pencil | Eraser) items. Read the data carefully and answer the questions. Companies | Pen | Pencil | Eraser A | 160 | 120 | 100 B | 80 | 140 | 180 C | 160 | 200 | 60 Find average number of orders of Pencil received by B | C is what percent of total orders of Pen received by A?
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Answer: (B) 106.25%

Explanation

Average Pencil orders received by B and C = (140 + 200) / 2 = 170. Total Pen orders received by company A = 160. Required percentage = (170 / 160) × 100 = 106.25%.

40Numerical Ability
The table given below shows number of orders received by three (A, B | C) companies of their three (Pen, Pencil | Eraser) items. Read the data carefully and answer the questions. Companies | Pen | Pencil | Eraser A | 160 | 120 | 100 B | 80 | 140 | 180 C | 160 | 200 | 60 Find total orders of item Pen, Pencil | Eraser received by A?
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Answer: (C) 380

Explanation

Total orders of Pen, Pencil, and Eraser received by company A = 160 + 120 + 100 = 380.

41Numerical Ability
What will come in the place of question (?) mark in following number series: 24, 24, 48, 144, ?, 2880
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Answer: (B) 576

Explanation

The pattern in the series is multiplication by consecutive natural numbers: 24 × 1 = 24, 24 × 2 = 48, 48 × 3 = 144, 144 × 4 = 576, and 576 × 5 = 2880.

42Numerical Ability
What will come in the place of question (?) mark in following number series: 32, 33.8, 37.4, 44.6, 59, ?
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Answer: (E) 87.8

Explanation

The differences between consecutive terms double with each step: 33.8 - 32 = 1.8, 37.4 - 33.8 = 3.6, 44.6 - 37.4 = 7.2, and 59 - 44.6 = 14.4. The next difference is 14.4 × 2 = 28.8, so the missing value is 59 + 28.8 = 87.8.

43Numerical Ability
What will come in the place of question (?) mark in following number series: 12, 7, 8, 13, ?, 68.5
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Answer: (B) 27

Explanation

The term transition rule is x × n + 1, where n increases by 0.5 each step: 12 × 0.5 + 1 = 7, 7 × 1 + 1 = 8, 8 × 1.5 + 1 = 13, 13 × 2 + 1 = 27, and 27 × 2.5 + 1 = 68.5.

44Numerical Ability
What will come in the place of question (?) mark in following number series: 72, 81, 63, 99, ?, 171
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Answer: (D) 27

Explanation

The pattern alternates addition and subtraction of powers of 2 multiplied by 9: 72 + 9 = 81, 81 - 18 = 63, 63 + 36 = 99, 99 - 72 = 27, and 27 + 144 = 171.

45Numerical Ability
What will come in the place of question (?) mark in following number series: 8, 9, 19, 58, 233, ?
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Answer: (B) 1166

Explanation

The series follows the rule x × n + 1, where n increases by 1 each step: 8 × 1 + 1 = 9, 9 × 2 + 1 = 19, 19 × 3 + 1 = 58, 58 × 4 + 1 = 233, and 233 × 5 + 1 = 1166.

46Numerical Ability
If the difference between the present age of A and B is three years and age of A will be is 25% more than that of B after two years, then find the age of A after two years (in years)?
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Answer: (A) 15

Explanation

The age difference between two individuals remains constant over time, so the difference between A and B after 2 years is still 3 years. Given that A's age after 2 years is 25% more than B's age, let B's age after 2 years be B₂. Then A₂ = 1.25 × B₂, which gives A₂ - B₂ = 0.25 × B₂ = 3 years. Solving for B₂ gives B₂ = 12 years, making A's age after 2 years equal to 12 + 3 = 15 years.

47Numerical Ability
Aman and Bhanu both spend 30% of their income together which is equal to Rs. 13200. If ratio of income of Aman to that of Bhanu 6 : 5, then find the income of Bhanu (in Rs.)?
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Answer: (C) 20000

Explanation

Since 30% of their combined income equals Rs. 13200, the total combined income of Aman and Bhanu is 13200 / 0.30 = Rs. 44000. With the income ratio of Aman to Bhanu being 6 : 5, the total ratio parts equal 11. Thus, Bhanu's income is (5 / 11) × 44000 = Rs. 20000.

48Numerical Ability
Gita invests equal sum on two different schemes at the same rate of interest on simple interest for X years and X+4 years and the respective ratio of interest gets by Gita is 1:2 respectively, then find 'X'?
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Answer: (E) 4

Explanation

Simple interest is given by SI = (P × R × T) / 100. Because equal sums are invested at the same rate of interest, the interest ratio equals the time ratio T₁ / T₂ = X / (X + 4). Setting this ratio equal to 1 / 2 gives X / (X + 4) = 1 / 2, which yields 2X = X + 4, hence X = 4.

49Numerical Ability
Six men can complete a work in 128 days, then find how many men will be required to complete 66 % of the same work in 32 days?
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Answer: (D) 16

Explanation

Using the work equivalence relation (M₁ × D₁) / W₁ = (M₂ × D₂) / W₂, where 66% of the work corresponds to 2/3 of the total work: (6 × 128) / 1 = (M₂ × 32) / (2/3). Multiplying gives 768 = 48 × M₂, which yields M₂ = 768 / 48 = 16 men.

50Numerical Ability
A train running at the speed of 144 kmph crosses a pole in 15 seconds. Find the time taken by the same train to cross the pole with the speed of 108 kmph (in seconds)?
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Answer: (E) 20

Explanation

When a train crosses a pole, the distance covered equals its own length, which remains constant. Using S₁ × T₁ = S₂ × T₂, substituting the given values yields 144 × 15 = 108 × T₂. Solving for T₂ gives T₂ = (144 × 15) / 108 = 20 seconds.

Answer key

Tap a number to jump to that question.

  1. 1B
  2. 2D
  3. 3E
  4. 4D
  5. 5C
  6. 6C
  7. 7A
  8. 8D
  9. 9B
  10. 10D
  11. 11E
  12. 12D
  13. 13A
  14. 14D
  15. 15D
  16. 16B
  17. 17D
  18. 18A
  19. 19A
  20. 20D
  21. 21D
  22. 22E
  23. 23C
  24. 24B
  25. 25A
  26. 26B
  27. 27B
  28. 28C
  29. 29A
  30. 30C
  31. 31C
  32. 32D
  33. 33E
  34. 34E
  35. 35B
  36. 36C
  37. 37A
  38. 38E
  39. 39B
  40. 40C
  41. 41B
  42. 42E
  43. 43B
  44. 44D
  45. 45B
  46. 46A
  47. 47C
  48. 48E
  49. 49D
  50. 50E

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