In each of the question, relationships between some elements are shown in the statements(s). These statements are followed by conclusions numbered I and II. Read the statements and give the answer.
Statements: A< B > N = M,B≤ V,M > R
Conclusions: I.B > R II. V > A
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Answer: (E) If both conclusions I and II follow.
Explanation
Combining B > N = M > R yields B > R, showing that conclusion I is true. Combining V ≥ B > A yields V > A, showing that conclusion II is true. Therefore, both conclusions follow.
2Reasoning
In each of the question, relationships between some elements are shown in the statements(s). These statements are followed by conclusions numbered I and II. Read the statements and give the answer.
Statements: D< E > F = G > H = I≤ J
Conclusions: I.F > I II. J≥ E
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Answer: (A) If only conclusion I follows.
Explanation
From the statement chain F = G > H = I, it directly follows that F > I, which validates conclusion I. For conclusion II, the relationship between E and J contains opposing inequality signs (E > F = G > H = I ≤ J), so no definitive order can be established between J and E.
3Reasoning
In each of the question, relationships between some elements are shown in the statements(s). These statements are followed by conclusions numbered I and II. Read the statements and give the answer.
Statements: M< N< O > P,N< E
Conclusions: I.E< M II. E > O
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Answer: (D) If neither conclusion I nor II follows.
Explanation
Combining M < N < E yields M < E, which means E > M, so conclusion I (E < M) is false. For conclusion II, both N < O and N < E are given, but no relation exists between E and O due to lack of direct connection. Thus, neither conclusion follows.
4Reasoning
In each of the question, relationships between some elements are shown in the statements(s). These statements are followed by conclusions numbered I and II. Read the statements and give the answer.
Statements: C≥ D< E = F≥ G,C< W
Conclusions: I.E = G II. G< E
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Answer: (C) If either conclusion I or II follows.
Explanation
From E = F ≥ G, the relation between E and G is E ≥ G. This implies that either E = G or E > G (which is G < E). Since these two outcomes are mutually exclusive and exhaustive for E ≥ G, either conclusion I or conclusion II must follow.
5Reasoning
In each of the question, relationships between some elements are shown in the statements(s). These statements are followed by conclusions numbered I and II. Read the statements and give the answer.
Statements: R< T< S< P > Q,R > X
Conclusions: I.S< Q II. X< S
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Answer: (B) If only conclusion II follows.
Explanation
Combining R > X with R < T < S gives X < R < T < S, which simplifies directly to X < S, making conclusion II true. For conclusion I, S < P > Q contains opposing inequality symbols, so no relationship between S and Q can be determined.
6Reasoning
Study the following information carefully and answer the question given below. Eight people viz. G, H, I, J, K, L, M and N lives in a Building on different floors from top to bottom (such as ground floor numbered as 1 and top is numbered as 8) but not necessarily in the same order.
There is a gap of three floors between J and L and both of them lives on odd number of floor. N lives just above H, who lives on even numbered floor. I lives on floor number 6. Only one person lives between L and M. J lives above I. Three persons live between K and H.
Who among the following lives on ground floor?
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Answer: (D) M
Explanation
Given I is on floor 6 and J lives above I on an odd floor, J must be on floor 7. With three floors between J and L, L is on floor 3. N lives directly above H on an even floor, placing H on floor 4 and N on floor 5. Since M is one person away from L, M is on floor 1. Three persons between K and H places K on floor 8, leaving G on floor 2. Thus, floor 1 (ground floor) is occupied by M.
7Reasoning
Study the following information carefully and answer the question given below. Eight people viz. G, H, I, J, K, L, M and N lives in a Building on different floors from top to bottom (such as ground floor numbered as 1 and top is numbered as 8) but not necessarily in the same order.
There is a gap of three floors between J and L and both of them lives on odd number of floor. N lives just above H, who lives on even numbered floor. I lives on floor number 6. Only one person lives between L and M. J lives above I. Three persons live between K and H.
Who among the following lives immediately below L?
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Answer: (C) G
Explanation
The floor positions from top to bottom are Floor 8: K, Floor 7: J, Floor 6: I, Floor 5: N, Floor 4: H, Floor 3: L, Floor 2: G, Floor 1: M. Since L is on floor 3, the person living on floor 2, directly below L, is G.
8Reasoning
Study the following information carefully and answer the question given below. Eight people viz. G, H, I, J, K, L, M and N lives in a Building on different floors from top to bottom (such as ground floor numbered as 1 and top is numbered as 8) but not necessarily in the same order.
There is a gap of three floors between J and L and both of them lives on odd number of floor. N lives just above H, who lives on even numbered floor. I lives on floor number 6. Only one person lives between L and M. J lives above I. Three persons live between K and H.
How many persons lives between I and H?
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Answer: (A) One
Explanation
I lives on floor 6 and H lives on floor 4. The only floor between floor 6 and floor 4 is floor 5, which is occupied by N. Therefore, exactly one person lives between I and H.
9Reasoning
Study the following information carefully and answer the question given below. Eight people viz. G, H, I, J, K, L, M and N lives in a Building on different floors from top to bottom (such as ground floor numbered as 1 and top is numbered as 8) but not necessarily in the same order.
There is a gap of three floors between J and L and both of them lives on odd number of floor. N lives just above H, who lives on even numbered floor. I lives on floor number 6. Only one person lives between L and M. J lives above I. Three persons live between K and H.
Who among the following lives on Top floor?
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Answer: (C) K
Explanation
Placing H on floor 4 requires K to be on floor 8 so that three persons (on floors 5, 6, and 7) reside between them. Thus, K lives on the 8th (top) floor.
10Reasoning
Study the following information carefully and answer the question given below. Eight people viz. G, H, I, J, K, L, M and N lives in a Building on different floors from top to bottom (such as ground floor numbered as 1 and top is numbered as 8) but not necessarily in the same order.
There is a gap of three floors between J and L and both of them lives on odd number of floor. N lives just above H, who lives on even numbered floor. I lives on floor number 6. Only one person lives between L and M. J lives above I. Three persons live between K and H.
Which of the following combination is false?
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Answer: (E) N-1
Explanation
The full floor distribution is K-8, J-7, I-6, N-5, H-4, L-3, G-2, and M-1. Since N lives on floor 5, pairing N with floor 1 is incorrect.
11Reasoning
In a row of children facing North, Rajan is twelfth from the right end and is fifth to the right of Satyarthi who is tenth from the left end. How many total number of children are there in the row?
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Answer: (C) 26
Explanation
Satyarthi is 10th from the left end, and Rajan is 5th to the right of Satyarthi, placing Rajan at 10 + 5 = 15th position from the left end. Since Rajan is also 12th from the right end, the total number of children in the row is calculated as 15 + 12 − 1 = 26.
12Reasoning
Raj leaves his home and goes straight 20 meters, then turns right and goes 10 meters. He turns left and goes 30 meters and finally turns right and starts walking. If he is now moving in the north direction, then in which direction did he start his walking?
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Answer: (B) West
Explanation
Tracing the movements backward from the final direction: Raj is moving North after taking a right turn, which means he was moving West before this turn. Before that, he took a left turn while moving West, meaning he was moving South prior to that turn. Before that, he took a right turn while moving South, which means he was originally moving West when he started walking from home.
13Reasoning
In each of the questions given below, a group of digits/letter is given followed by four combinations of symbols numbered (a), (b), (c) and (d). You have to find out which of the four combinations correctly represents the group of digits/letters based on the symbol codes and the conditions given below. If none of the four combinations represents the group of digits correctly, give (e) ie 'None of these' as the answer.
| Digit | Z | L | F | 1 | I | 5 | 7 | A | E | B | 2 | X | 6 | W |
|--------|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Symbol | @ | ! | $ | | µ | Δ | A | | | > | ≠ | < | ® | £ | ∞ |
Condition for coding the group elements:
(i) If the first letter is Vowel and the last digit is divisible by 2, then both are to be coded as ^+
(ii) If the first as well as the last digit is odd, then both are to be coded by the code of the first digit.
(iii) If the first letter is consonant and the last digit is odd number, then the code of first and last elements are to be interchanged.
WX6ZF1
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Answer: (C) ^®£@$∞
Explanation
In the group WX6ZF1, the first element W is a consonant and the last element 1 is an odd number. This satisfies condition (iii), which requires interchanging the codes of the first and last elements.
The standard symbol codes are W = ∞, X = ®, 6 = £, Z = @, F = , and 1 = ^.
Interchanging the codes of the first element (W) and the last element (1) places at the beginning and ∞ at the end. The middle elements X, 6, Z, and F keep their standard codes ®, £, @, and.
Combining these gives the coded representation ^®£@∞.
14Reasoning
In each of the questions given below, a group of digits/letter is given followed by four combinations of symbols numbered (a), (b), (c) and (d). You have to find out which of the four combinations correctly represents the group of digits/letters based on the symbol codes and the conditions given below. If none of the four combinations represents the group of digits correctly, give (e) ie 'None of these' as the answer.
| Digit | Z | L | F | 1 | I | 5 | 7 | A | E | B | 2 | X | 6 | W |
|--------|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Symbol | @ | ! | $ | | µ | Δ | A | | | > | ≠ | < | ® | £ | ∞ |
Condition for coding the group elements:
(i) If the first letter is Vowel and the last digit is divisible by 2, then both are to be coded as ^+
(ii) If the first as well as the last digit is odd, then both are to be coded by the code of the first digit.
(iii) If the first letter is consonant and the last digit is odd number, then the code of first and last elements are to be interchanged.
FE1XI6
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Answer: (C) $>^®µ£
Explanation
First element F is a consonant and the last element 6 is an even digit, so none of the three special conditions apply to the group FE1XI6. Coding each element directly using the provided table gives: F = , E = >, 1 = ^, X = ®, I = µ, and 6 = £. Combining these in order yields>^®µ£.
15Reasoning
In each of the questions given below, a group of digits/letter is given followed by four combinations of symbols numbered (a), (b), (c) and (d). You have to find out which of the four combinations correctly represents the group of digits/letters based on the symbol codes and the conditions given below. If none of the four combinations represents the group of digits correctly, give (e) ie 'None of these' as the answer.
| Digit | Z | L | F | 1 | I | 5 | 7 | A | E | B | 2 | X | 6 | W |
|--------|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Symbol | @ | ! | $ | | µ | Δ | A | | | > | ≠ | < | ® | £ | ∞ |
Condition for coding the group elements:
(i) If the first letter is Vowel and the last digit is divisible by 2, then both are to be coded as ^+
(ii) If the first as well as the last digit is odd, then both are to be coded by the code of the first digit.
(iii) If the first letter is consonant and the last digit is odd number, then the code of first and last elements are to be interchanged.
5L2IA1
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Answer: (A) ∆!<µ | ∆
Explanation
In the given group 5L2IA1, both the first element (5) and the last element (1) are odd digits, so condition (ii) applies. According to condition (ii), both the first and last elements are coded using the symbol for the first digit, which is Δ. The middle elements are coded directly using their respective table symbols: L = !, 2 = <, I = µ, and A = | . Combining these in order yields Δ!<µ | Δ.
16Reasoning
In each of the questions given below, a group of digits/letter is given followed by four combinations of symbols numbered (a), (b), (c) and (d). You have to find out which of the four combinations correctly represents the group of digits/letters based on the symbol codes and the conditions given below. If none of the four combinations represents the group of digits correctly, give (e) ie 'None of these' as the answer.
| Digit | Z | L | F | 1 | I | 5 | 7 | A | E | B | 2 | X | 6 | W |
|--------|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Symbol | @ | ! | $ | | µ | Δ | A | | | > | ≠ | < | ® | £ | ∞ |
Condition for coding the group elements:
(i) If the first letter is Vowel and the last digit is divisible by 2, then both are to be coded as ^+
(ii) If the first as well as the last digit is odd, then both are to be coded by the code of the first digit.
(iii) If the first letter is consonant and the last digit is odd number, then the code of first and last elements are to be interchanged.
E2ZA6
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Answer: (D) +<@ | +
Explanation
The input sequence is E2ZA6. The first element is a vowel (E) and the last element is divisible by 2 (6). This satisfies condition (i), which specifies that both the first and last elements must be coded as +.
The remaining middle elements are coded directly according to the given symbol table:
2 is coded as <
Z is coded as @
A is coded as | Combining the modified codes for the outer elements with the direct codes for the inner elements yields the final sequence +<@ | +.
17Reasoning
In each of the questions given below, a group of digits/letter is given followed by four combinations of symbols numbered (a), (b), (c) and (d). You have to find out which of the four combinations correctly represents the group of digits/letters based on the symbol codes and the conditions given below. If none of the four combinations represents the group of digits correctly, give (e) ie 'None of these' as the answer.
| Digit | Z | L | F | 1 | I | 5 | 7 | A | E | B | 2 | X | 6 | W |
|--------|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Symbol | @ | ! | $ | | µ | Δ | A | | | > | ≠ | < | ® | £ | ∞ |
Condition for coding the group elements:
(i) If the first letter is Vowel and the last digit is divisible by 2, then both are to be coded as ^+
(ii) If the first as well as the last digit is odd, then both are to be coded by the code of the first digit.
(iii) If the first letter is consonant and the last digit is odd number, then the code of first and last elements are to be interchanged.
IZ2W2
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Answer: (B) +@<∞+
Explanation
The group to be coded is IZ2W2.
Here, the first element 'I' is a vowel and the last element '2' is a digit divisible by 2. This satisfies condition (i), which states that if the first letter is a vowel and the last digit is divisible by 2, both the first and last elements must be coded as '+'.
The remaining middle elements are coded directly using their respective symbol codes from the table:
Z = @
2 = <
W = ∞
Replacing the first and last elements with '+' and coding the middle elements from the table gives the code sequence +@<∞+.
18Reasoning
Read the following information carefully and answer the questions given below.
A,B,C,D,E,F,G and H are eight members standing in a row (not necessarily in the same order) facing north.
C and B have as many members between them as G and C have between them. D, who is 4ᵗʰ from the extreme left end, is 2ⁿᵈ to the left of E. G is 3ʳᵈ place away from one of the extreme end. Neither B nor C sits any extreme end. F sits immediate right of A.
How many persons sit between G and B?
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Answer: (B) Three
Explanation
Arranging members according to all given constraints yields the unique left-to-right order: A, F, G, D, C, E, B, H. The position of G is 3rd from the left end and the position of B is 7th from the left end. The persons sitting between G and B are D, C, and E, which equals three persons.
19Reasoning
Read the following information carefully and answer the questions given below.
A,B,C,D,E,F,G and H are eight members standing in a row (not necessarily in the same order) facing north.
C and B have as many members between them as G and C have between them. D, who is 4ᵗʰ from the extreme left end, is 2ⁿᵈ to the left of E. G is 3ʳᵈ place away from one of the extreme end. Neither B nor C sits any extreme end. F sits immediate right of A.
Who among the following persons sits at extreme ends?
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Answer: (D) H, A
Explanation
From the conditions provided, the unique left-to-right order of the eight members facing north is A, F, G, D, C, E, B, H. The person standing at the extreme left end is A (position 1) and the person standing at the extreme right end is H (position 8).
20Reasoning
Read the following information carefully and answer the questions given below.
A,B,C,D,E,F,G and H are eight members standing in a row (not necessarily in the same order) facing north.
C and B have as many members between them as G and C have between them. D, who is 4ᵗʰ from the extreme left end, is 2ⁿᵈ to the left of E. G is 3ʳᵈ place away from one of the extreme end. Neither B nor C sits any extreme end. F sits immediate right of A.
Who sits second to the right of E?
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Answer: (B) H
Explanation
The arrangement facing north from left to right is A, F, G, D, C, E, B, H. Member E occupies the 6th position from the left end. Counting two places to the right from E leads to the 8th position, which is occupied by H.
21Reasoning
Read the following information carefully and answer the questions given below.
A,B,C,D,E,F,G and H are eight members standing in a row (not necessarily in the same order) facing north.
C and B have as many members between them as G and C have between them. D, who is 4ᵗʰ from the extreme left end, is 2ⁿᵈ to the left of E. G is 3ʳᵈ place away from one of the extreme end. Neither B nor C sits any extreme end. F sits immediate right of A.
Who sits third to the left of G?
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Answer: (B) None
Explanation
In the order A, F, G, D, C, E, B, H, member G is at the 3rd position from the left end. There are only two persons, A and F, to the left of G, so no person sits third to the left of G.
22Reasoning
Read the following information carefully and answer the questions given below.
A,B,C,D,E,F,G and H are eight members standing in a row (not necessarily in the same order) facing north.
C and B have as many members between them as G and C have between them. D, who is 4ᵗʰ from the extreme left end, is 2ⁿᵈ to the left of E. G is 3ʳᵈ place away from one of the extreme end. Neither B nor C sits any extreme end. F sits immediate right of A.
Who sits immediate left of C?
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Answer: (D) D
Explanation
In the linear arrangement A, F, G, D, C, E, B, H facing north, member C is located at position 5. The person at position 4, directly adjacent to C on the left, is D.
23Reasoning
Find the odd one out?
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Answer: (E) MNO
Explanation
The groups ACB, DFE, GIH, and JLK follow the rule of moving two steps forward from the first letter to get the second letter, and then one step backward to get the third letter (+2, −1). In contrast, MNO consists of consecutive letters (+1, +1), making it the odd one out.
24Reasoning
Study the following number sequence and answer the questions following it.
9 3 2 4 5 7 9 5 8 1 5 0 6 4 2 9 8 2 6 3 5 9 8 2 1 5 4 3 2 1
How many odd numbers are there in the numeric series which are immediately preceded by a number, which is a whole square?
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Answer: (D) More than three
Explanation
The single-digit whole squares present in the series are 1, 4, and 9. Checking pairs of adjacent digits where a square number is followed by an odd number yields six such occurrences: 9 followed by 3, 4 followed by 5, 9 followed by 5, 1 followed by 5, 1 followed by 5, and 4 followed by 3. Since six is greater than three, the correct count is more than three.
25Reasoning
Study the following number sequence and answer the questions following it.
9 3 2 4 5 7 9 5 8 1 5 0 6 4 2 9 8 2 6 3 5 9 8 2 1 5 4 3 2 1
If all the odd numbers are dropped from the series, which number will be eighth to the left of eleventh number from the left end?
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Answer: (B) 8
Explanation
Finding the 8th number to the left of the 11th number from the left end corresponds to finding the 11 − 8 = 3rd number from the left end. Removing all odd numbers from the original sequence leaves the remaining digits in order: 2, 4, 8, 0, 6, 4, 2, 8, 2, 6, 8. The 3rd digit in this reduced sequence is 8.
26Reasoning
Study the following number sequence and answer the questions following it.
9 3 2 4 5 7 9 5 8 1 5 0 6 4 2 9 8 2 6 3 5 9 8 2 1 5 4 3 2 1
If 1 is subtracted from all odd numbers and 2 is subtracted from all even numbers in the given number series, then which number will be sixteenth from the right end?
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Answer: (A) 0
Explanation
The given sequence contains 30 numbers. The 16th number from the right end corresponds to position 30 - 16 + 1 = 15 from the left end. The 15th number from the left end in the sequence is 2. Since 2 is an even number, subtracting 2 from it yields 2 - 2 = 0.
27Reasoning
Study the following number sequence and answer the questions following it.
9 3 2 4 5 7 9 5 8 1 5 0 6 4 2 9 8 2 6 3 5 9 8 2 1 5 4 3 2 1
If the position of the 1ˢᵗ and the 16ᵗʰ numbers, the 2ⁿᵈ and the 17ᵗʰ numbers, and so on up to the 15ᵗʰ and the 30ᵗʰ numbers, are interchanged, which number will be 7ᵗʰ to the right of 19ᵗʰ number from the right end?
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Answer: (D) 4
Explanation
The target position, 7th to the right of the 19th number from the right end, is position 19 - 7 = 12 from the right end. In a 30-number sequence, position 12 from the right end corresponds to position 30 - 12 + 1 = 19 from the left end. When the first 15 numbers are interchanged with the last 15 numbers, position 19 receives the number from original position 19 - 15 = 4. The 4th number in the original sequence is 4.
28Reasoning
Study the following number sequence and answer the questions following it.
9 3 2 4 5 7 9 5 8 1 5 0 6 4 2 9 8 2 6 3 5 9 8 2 1 5 4 3 2 1
How many total even numbers which is immediately preceded by a 'whole cube' or 'immediately preceded by a whole square' in the above sequence?
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Answer: (B) Five
Explanation
The single-digit whole squares and whole cubes in the sequence are 1, 4, 8, and 9. Scanning the sequence for even numbers preceded by any of these numbers yields: the digit 2 at position 15 preceded by 4 (square of 2); the digit 8 at position 17 preceded by 9 (square of 3); the digit 2 at position 18 preceded by 8 (cube of 2); the digit 8 at position 23 preceded by 9 (square of 3); and the digit 2 at position 24 preceded by 8 (cube of 2). This gives a total of five such even numbers.
29Reasoning
In each question below are given some statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows/follow from the given statements, disregarding commonly known facts. Give answer
Statements: All shirts are skirts. No skirt is top. All tops are kurta.
Conclusions: I. All shirts are kurta II. Some kurta are skirts.
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Answer: (D) If neither conclusion I nor II follows.
Explanation
From the statements All shirts are skirts and No skirt is top, shirts and tops are mutually exclusive sets. The statement All tops are kurta places tops inside kurta, but this does not require shirts or skirts to overlap with kurta outside of the top set. Therefore, neither All shirts are kurta nor Some kurta are skirts logically follows.
30Reasoning
In each question below are given some statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows/follow from the given statements, disregarding commonly known facts. Give answer
Statements: Some chocolate are chips. Some chips are jelly. All jelly are whoppers.
Conclusions: I. Some jelly are chips. II. All chocolate being whoppers is a possibility
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Answer: (E) If both conclusions I and II follow.
Explanation
Since Some chips are jelly, its simple conversion Some jelly are chips is directly true, so Conclusion I logically follows. Furthermore, there is no negative restriction connecting chocolate and whoppers in any statement, making the statement All chocolate being whoppers is a possibility logically valid. Hence, both conclusions follow.
31Reasoning
In each question below are given some statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows/follow from the given statements, disregarding commonly known facts. Give answer
Statements: Some frooti are Maaza. No Maaza is slice. All slice are fanta.
Conclusions: I. Some frooti are definitely not slice. II. Some fanta are definitely not Maaza.
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Answer: (E) If both conclusions I and II follow.
Explanation
Since Some frooti are Maaza and No Maaza is slice, the specific portion of frooti that overlaps with Maaza cannot be slice, which makes Some frooti are definitely not slice true. Additionally, since All slice are fanta and No Maaza is slice, the portion of fanta that comprises slice can never be Maaza, making Some fanta are definitely not Maaza true. Thus, both conclusions follow.
32Reasoning
In each question below are given some statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows/follow from the given statements, disregarding commonly known facts. Give answer
Statements: All carbon are oxygen. All Nitrogen are carbon. Some oxygen are Sulphur.
Conclusions I. All Nitrogen being Sulphur is a possibility. II. All Nitrogen are not oxygen.
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Answer: (A) If only conclusion I follows.
Explanation
The premises All Nitrogen are carbon and All carbon are oxygen mean that Nitrogen is a sub-category of Oxygen. Since Some oxygen are Sulphur, it is possible for Sulphur to encompass all of Nitrogen without contradicting any premise. Conclusion II states All Nitrogen are not oxygen, which directly contradicts Nitrogen being a subset of Oxygen. Thus, only conclusion I follows.
33Reasoning
In each question below are given some statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows/follow from the given statements, disregarding commonly known facts. Give answer
Statements: All September are October. No October is November. No November is December.
Conclusions: I. Some September are not Novembers II. No October is December.
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Answer: (A) If only conclusion I follows.
Explanation
Because All September are October and No October is November, it logically follows that No September is November. The universal negative statement No September is November implies the particular negative statement Some September are not Novembers. The relationship between October and December is undetermined, so No October is December does not follow definitely. Thus, only conclusion I follows.
34Reasoning
Following questions are based on the five words given below, Study the following words and answer the following questions.
NOW SAD WAF RAT CAT
(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)
If the given words are arranged in the order as they appear in a dictionary from left to right, which of the following will be the fourth from the left end?
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Answer: (C) SAD
Explanation
Arranging the five words CAT, NOW, RAT, SAD, and WAF in standard alphabetical dictionary order gives CAT first, NOW second, RAT third, SAD fourth, and WAF fifth. The word in the fourth position from the left end is SAD.
35Reasoning
Following questions are based on the five words given below, Study the following words and answer the following questions.
NOW SAD WAF RAT CAT
(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)
How many letters are there in the English alphabetical series between the second letter of the word which is second from the right end and the third letter of the word which is second from the left end?
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Answer: (A) Two
Explanation
In the given list of words NOW, SAD, WAF, RAT, CAT, the word second from the right end is RAT and the word second from the left end is SAD. The second letter of RAT is A, and the third letter of SAD is D. In the English alphabetical series, the letters strictly between A and D are B and C, which equals two letters.
36Reasoning
Following questions are based on the five words given below, Study the following words and answer the following questions.
NOW SAD WAF RAT CAT
(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)
If the third alphabet in each of the words is changed to the previous alphabet in the English alphabetical order, how many words thus formed will be without any vowels?
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Answer: (A) None
Explanation
In all five given words (NOW, SAD, WAF, RAT, CAT), the middle letter is already a vowel (O, A, A, A, A). Changing only the third letter to its previous alphabetical letter leaves the middle vowel unchanged in every word. Consequently, all five newly formed words contain at least one vowel, resulting in zero words without any vowels.
37Reasoning
Following questions are based on the five words given below, Study the following words and answer the following questions.
NOW SAD WAF RAT CAT
(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)
If the position of the first and the third alphabet of each of the words are interchanged, which of the following will form a meaningful word in the new arrangement?
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Answer: (E) Both (a) and (c)
Explanation
Interchanging the first and third letters of each word yields: NOW becomes WON, SAD becomes DAS, WAF becomes FAW, RAT becomes TAR, and CAT becomes TAC. Among these, WON and TAR are standard meaningful English words.
38Reasoning
Following questions are based on the five words given below, Study the following words and answer the following questions.
NOW SAD WAF RAT CAT
(The new words formed after performing the mentioned operations may not necessarily be a meaningful English word.)
If in each of the given words, each of the consonants is changed to its previous letter and each vowel is changed to its next letter in the English alphabetical series, then how many words thus formed will at least one vowel appear?
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Answer: (B) One
Explanation
Transforming each letter according to the rule gives: NOW becomes MPV, SAD becomes RBC, WAF becomes VBE (since F becomes E, which is a vowel), RAT becomes QBS, and CAT becomes BBS. Only VBE contains a vowel.
39Reasoning
If in the number 9737132710, positions of the first and the second digits are interchanged, positions of the third and fourth digits are interchanged and so on till the positions of 9ᵗʰ and 10ᵗʰ digits are interchanged, then which digit will be 6th from the left end?
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Answer: (B) 1
Explanation
Interchanging adjacent pairs of digits in the string 9737132710 swaps positions 1 and 2, 3 and 4, 5 and 6, 7 and 8, and 9 and 10. The digit at the 6th position in the new string will be the digit originally at the 5th position, which is 1.
40Reasoning
How many pairs of letters are there in the word" WORSHIP" which have as many letters between them in the word as in alphabetical series?
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Answer: (D) Three
Explanation
In the word WORSHIP, comparing letter positions with their alphabetical order yields three matching pairs:
R (18) and S (19) are adjacent in both the word and the alphabet with a positional difference of 1.
H (8) and I (9) are adjacent in both the word and the alphabet with a positional difference of 1.
S (19) and P (16) have a positional difference of 3 in both the word and the alphabet.
41Numerical Ability
The retail price of a water geyser is Rs. 1265. If the manufacturer gains 10% , the wholesale dealer gains 15% and the retailer gains 25% , then the cost of the product is:
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Answer: (A) Rs. 800
Explanation
Let C be the original cost price.
C × (1 + 10/100) × (1 + 15/100) × (1 + 25/100) = 1265
C × (11/10) × (23/20) × (5/4) = 1265
C × (1265 / 800) = 1265
C = 800
42Numerical Ability
A pipe can fill a cistern in 6 hrs. Due to a leak in its bottom, it is filled in 7 hrs. When the cistern is full, in how much time will it be emptied by the leak?
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Answer: (A) 42 hrs
Explanation
Filling rate of the pipe = 1/6 per hour.
Combined filling rate with the leak = 1/7 per hour.
Emptying rate of the leak = 1/6 - 1/7 = 1/42 per hour.
Time taken by the leak to empty the full cistern = 1 / (1/42) = 42 hours.
43Numerical Ability
Ram travels a certain distance at 3km / h and reaches 15 minutes late. If he travels at 4km / h , he reaches 15 minutes earlier. The distance he has to travel is:
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Answer: (B) 6km
Explanation
Distance D = (s₁ × s₂ / |s₁ - s₂|) × Δt
Given speeds s₁ = 3 km/h, s₂ = 4 km/h, and total time difference Δt = 15 min late + 15 min early = 30 min = ½ hour.
D = (3 × 4 / |3 - 4|) × ½ = 12 × ½ = 6 km.
44Numerical Ability
In a mixture of 45 litres, the ratio of milk and water is 3:2 . How much water must be added to make the ratio 9:11 ?
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Answer: (B) 15 litres
Explanation
Initial volume = 45 litres with Milk:Water ratio 3:2.
Milk = (3/5) × 45 = 27 litres and Water = (2/5) × 45 = 18 litres.
Let x be the volume of water added.
27 / (18 + x) = 9/11
27 × 11 = 9 × (18 + x)
33 = 18 + x
x = 15 litres.
45Numerical Ability
A person can row with the stream at 8km per hour and against the stream at 6km an hour. The speed of the current is:
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Answer: (A) 1km / h
Explanation
Speed of current = ½ × (Downstream speed - Upstream speed)
Speed of current = ½ × (8 - 6) = 1 km/h.
46Numerical Ability
A father's age is three times the sum of the ages of his two children, but 20 years hence his age will be equal to the sum of their ages. Then, the father's age is:
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Answer: (A) 30 years
Explanation
Let F be the father's current age and S be the current sum of the ages of his two children. According to the problem, F = 3S. In 20 years, the father's age becomes F + 20 and the sum of the ages of the two children becomes S + 40. Equating the two gives F + 20 = S + 40, which simplifies to F - S = 20. Substituting F = 3S into this equation gives 3S - S = 20, resulting in S = 10. Thus, the father's age F = 3 × 10 = 30 years.
47Numerical Ability
A sum was put at simple interest at a certain rate for 3 years. Had it been put at 1% higher rate, it would have fetched Rs. 5100 more. The sum is:
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Answer: (A) Rs. 170000
Explanation
Using the simple interest formula SI = (P × R × T) / 100, the extra interest fetched by a rate increase ΔR is given by ΔSI = (P × ΔR × T) / 100. Substituting ΔSI = 5100, ΔR = 1, and T = 3 gives 5100 = (P × 1 × 3) / 100. Solving for P yields 3P = 510000, so P = 170000.
48Numerical Ability
From among 36 teachers in a school, one principal and one vice-principal are to be appointed. In how many ways can this be done?
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Answer: (A) 1260
Explanation
The principal can be chosen from any of the 36 teachers in 36 ways. Once the principal is selected, the vice-principal can be chosen from the remaining 35 teachers in 35 ways. By the multiplication principle, the total number of ways to appoint both is 36 × 35 = 1260.
49Numerical Ability
A card is drawn at random from a well-shuffled pack of 52 cards. What is the probability of getting a two of hearts or a two diamonds?
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Answer: (C) ¹⁄₂₆
Explanation
Using the probability formula P(E) = Number of favorable outcomes / Total outcomes, the total number of outcomes for drawing a card from a standard deck is 52. The favorable outcomes consist of the 2 of hearts (1 card) and the 2 of diamonds (1 card), giving 2 favorable cards. Therefore, the probability is 2 / 52 = 1 / 26.
50Numerical Ability
A sum is invested for 3 years at compound interest at 5% , 10% and 20% respectively. In three years, if the sum amounts to Rs. 16,632, then find the sum.
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Answer: (B) Rs. 12000
Explanation
Using the formula for amount under successive compound interest rates, A = P × (1 + r₁/100) × (1 + r₂/100) × (1 + r₃/100). Substituting A = 16632, r₁ = 5, r₂ = 10, and r₃ = 20 gives 16632 = P × (105/100) × (110/100) × (120/100) = P × (21/20) × (11/10) × (6/5) = P × (1386 / 1000). Solving for P yields P = (16632 × 1000) / 1386 = 12000.
51Numerical Ability
Table shows the mobile phones sold on different days by different sellers. Read the table carefully and answer the questions.
Days→ Monday Tuesday Wednesday Thursday Friday Saturday Sunday
MobilesPhonesSellers
P 40 45 48 28 50 24 20
Q 90 92 27 12 16 98 26
R 80 36 30 13 28 62 47
S 60 46 12 64 52 34 76
T 48 18 58 69 70 10 15
Find the difference of mobile phones sold by P and R together on Monday to the mobile phones sold by S and T on Wednesday?
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Answer: (B) 50
Explanation
Mobile phones sold by P and R on Monday are 40 and 80 respectively, making a total of 40 + 80 = 120. Mobile phones sold by S and T on Wednesday are 12 and 58 respectively, making a total of 12 + 58 = 70. The difference between these two sums is 120 - 70 = 50.
52Numerical Ability
Table shows the mobile phones sold on different days by different sellers. Read the table carefully and answer the questions.
| Mobile Phone Seller | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday |
|---------------------|-------:|--------:|----------:|---------:|-------:|---------:|-------:|
| P | 40 | 45 | 48 | 28 | 50 | 24 | 20 |
| Q | 90 | 92 | 27 | 12 | 16 | 98 | 26 |
| R | 80 | 36 | 30 | 13 | 28 | 62 | 47 |
| S | 60 | 46 | 12 | 64 | 52 | 34 | 76 |
| T | 48 | 18 | 58 | 69 | 70 | 10 | 15 |
Find the ratio of mobile phone sold by Q on Tuesday and Saturday together to the mobile phone sold by R on Thursday and Sunday together?
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Answer: (C) 19:6
Explanation
Mobile phones sold by Q on Tuesday (92) and Saturday (98) total 92 + 98 = 190. Mobile phones sold by R on Thursday (13) and Sunday (47) total 13 + 47 = 60. The ratio of these two totals is 190 : 60, which simplifies to 19 : 6.
53Numerical Ability
Table shows the mobile phones sold on different days by different sellers. Read the table carefully and answer the questions.
| Mobile Phone Seller | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday |
|---------------------|-------:|--------:|----------:|---------:|-------:|---------:|-------:|
| P | 40 | 45 | 48 | 28 | 50 | 24 | 20 |
| Q | 90 | 92 | 27 | 12 | 16 | 98 | 26 |
| R | 80 | 36 | 30 | 13 | 28 | 62 | 47 |
| S | 60 | 46 | 12 | 64 | 52 | 34 | 76 |
| T | 48 | 18 | 58 | 69 | 70 | 10 | 15 |
Mobile phones sold by P and S together on Wednesday is what percent of mobile phone sold by T on Sunday?
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Answer: (A) 400%
Explanation
Mobile phones sold by P and S on Wednesday are 48 and 12 respectively, giving a total of 48 + 12 = 60. Mobile phones sold by T on Sunday equal 15. Using the percentage formula (Part / Whole) × 100, the required percentage is (60 / 15) × 100% = 400%.
54Numerical Ability
Table shows the mobile phones sold on different days by different sellers. Read the table carefully and answer the questions.
Days→ Monday Tuesday Wednesday Thursday Friday Saturday Sunday
MobilesPhonesSellers
P 40 45 48 28 50 24 20
Q 90 92 27 12 16 98 26
R 80 36 30 13 28 62 47
S 60 46 12 64 52 34 76
T 48 18 58 69 70 10 15
What is the average of mobile phone sold by Q on Wednesday, T on Sunday and S on Monday?
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Answer: (E) None of these
Explanation
Mobile phones sold by Q on Wednesday = 27, by T on Sunday = 15, and by S on Monday = 60. The sum of these sales is 27 + 15 + 60 = 102. The average is calculated as 102 / 3 = 34.
55Numerical Ability
Table shows the mobile phones sold on different days by different sellers. Read the table carefully and answer the questions.
| Mobile Phone Seller | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday |
|---------------------|-------:|--------:|----------:|---------:|-------:|---------:|-------:|
| P | 40 | 45 | 48 | 28 | 50 | 24 | 20 |
| Q | 90 | 92 | 27 | 12 | 16 | 98 | 26 |
| R | 80 | 36 | 30 | 13 | 28 | 62 | 47 |
| S | 60 | 46 | 12 | 64 | 52 | 34 | 76 |
| T | 48 | 18 | 58 | 69 | 70 | 10 | 15 |
The mobiles sold by P on Thursday are of two types i.e. Windows phone and Android phone in ratio 3:4 Find the number of Windows phones sold by P on Thursday?
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Answer: (D) 12
Explanation
P sold 28 mobile phones on Thursday. The ratio of Windows phones to Android phones is 3 : 4, making the total number of ratio parts 3 + 4 = 7. The number of Windows phones sold is 28 × (3 / 7) = 12.
56Numerical Ability
What should come in place of question mark (?) in following simplification problems?
45% of 600 + ?% of 480 = 390
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Answer: (B) 25
Explanation
Evaluating 45% of 600 gives 0.45 × 600 = 270. Substituting this into the given equation yields 270 + (x / 100) × 480 = 390. Subtracting 270 from both sides gives (x / 100) × 480 = 120, which simplifies to 4.8x = 120. Dividing 120 by 4.8 results in x = 25.
57Numerical Ability
What should come in place of question mark (?) in following simplification problems?
4⅔ +7⅙ -5²⁄₉ = ?
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Answer: (C) 6¹¹⁄₁₈
Explanation
Separate the expression into integer and fractional components: (4 + 7 - 5) + (2/3 + 1/6 - 2/9). The integer part equals 6. Finding a common denominator of 18 for the fractions gives 12/18 + 3/18 - 4/18 = 11/18. Combining the integer and fractional parts yields 6 11/18.
58Numerical Ability
What should come in place of question mark (?) in following simplification problems?
65% of 240 + ?% of 150 = 210
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Answer: (D) 36
Explanation
Evaluating 65% of 240 gives 0.65 × 240 = 156. Substituting this into the equation yields 156 + (x / 100) × 150 = 210. Subtracting 156 gives 1.5x = 54. Dividing 54 by 1.5 yields x = 36.
59Numerical Ability
What should come in place of question mark (?) in following simplification problems?
⅔ of 1⅔ of 75% of 540 = ?
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Answer: (E) None of these
Explanation
Convert the mixed fraction 1 2/3 to 5/3 and 75% to 3/4. The expression becomes (2/3) × (5/3) × (3/4) × 540. Multiplying the fractions gives (2 × 5 × 3) / (3 × 3 × 4) = 30/36 = 5/6. Calculating (5/6) × 540 gives 5 × 90 = 450.
60Numerical Ability
What should come in place of question mark (?) in following simplification problems?
555.05 + 55.50 + 5.55 + 5 + 0.55 = ?
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Answer: (A) 621.65
Explanation
Align the decimal points and add the numbers step by step: 555.05 + 55.50 = 610.55; 610.55 + 5.55 = 616.10; 616.10 + 5 = 621.10; 621.10 + 0.55 = 621.65.
61Numerical Ability
What should come in place of question mark (?) in following simplification problems?
1425 + 8560 + 1680 ÷ 200 = ?
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Answer: (E) None of these
Explanation
Following order of operations rules, perform division before addition. Dividing 1680 by 200 gives 8.4. Adding this to the remaining terms yields 1425 + 8560 + 8.4 = 9993.4.
62Numerical Ability
What should come in place of question mark (?) in following simplification problems?
? % of 800 = 293 - 22% of 750
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Answer: (D) 16
Explanation
First evaluate 22% of 750, which equals 0.22 × 750 = 165. The right side of the equation becomes 293 - 165 = 128. Setting up the equation (x / 100) × 800 = 128 simplifies to 8x = 128, which yields x = 16.
63Numerical Ability
What should come in place of question mark (?) in following simplification problems?
25.6% of 250 + √? = 119
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Answer: (B) 3025
Explanation
Evaluating 25.6% of 250 gives 0.256 × 250 = 64. Substituting into the equation gives 64 + √x = 119. Subtracting 64 yields √x = 55. Squaring both sides gives x = 55² = 3025.
64Numerical Ability
What should come in place of question mark (?) in following simplification problems?
4⅚ -5⁵⁄₉ = ? -2⅓ +¹¹⁄₁₈
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Answer: (E) None of these
Explanation
Convert mixed fractions to improper fractions: 4 5/6 = 29/6, 5 5/9 = 50/9, and 2 1/3 = 7/3. The left side simplifies to 29/6 - 50/9 = 87/18 - 100/18 = -13/18. The right side is x - 7/3 + 11/18 = x - 42/18 + 11/18 = x - 31/18. Equating both sides gives -13/18 = x - 31/18, which solves to x = (31 - 13) / 18 = 18/18 = 1.
65Numerical Ability
What should come in place of question mark (?) in following simplification problems?
[30% of {(80% of 850) ÷ 34} ] = ?
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Answer: (C) 6
Explanation
Evaluate the innermost operation first: 80% of 850 = 0.8 × 850 = 680. Next, divide by 34: 680 ÷ 34 = 20. Finally, calculate 30% of 20: 0.3 × 20 = 6.
66Numerical Ability
The sides of a triangle are in the ratio of ½:⅓:¼ If the perimeter is 52 cm , then the length of the smallest side is:
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Answer: (D) 12 cm
Explanation
To convert the ratio ½ : ⅓ : ¼ to whole numbers, multiply each term by the LCM of denominators (12), obtaining the ratio 6 : 4 : 3.
Sum of ratio terms = 6 + 4 + 3 = 13 parts.
Given total perimeter = 52 cm.
Length of the smallest side = (3 / 13) × 52 = 12 cm.
67Numerical Ability
If A's salary is 25% higher than B's salary, then how much per cent is B's salary lower than A's?
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Answer: (B) 20%
Explanation
When A's salary is r% higher than B's, B's salary is lower than A's by [r / (100 + r)] × 100%.
Substituting r = 25:
Percentage lower = [25 / (100 + 25)] × 100% = (25 / 125) × 100% = 20%.
68Numerical Ability
Ravi sells an article at a gain of 12½% . If he had sold it at Rs. 22.50 more, he would have gained 25% The cost price of the article is:
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Answer: (D) Rs. 180
Explanation
Difference in gain percentage = 25% - 12½% = 12.5%.
This 12.5% increase in gain equals ₹22.50.
Cost Price = 22.50 / 0.125 = ₹180.
69Numerical Ability
A certain job was assigned to a group of men to do it in 20 days. But 12 men did not turn up for the job and the remaining men did the job in 32 days. The original number of men in the group was:
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Answer: (A) 32
Explanation
Let the original number of men be M.
Total work in man-days is constant:
M × 20 = (M - 12) × 32
20M = 32M - 384
12M = 384
M = 32.
70Numerical Ability
A vessel contains liquid P and Q in the ratio 5:3 . If 16 litres of the mixture are removed and the same quantity of liquid Q is added, the ratio become 3:5 . What quantity does the vessel hold?
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Answer: (C) 40 litres
Explanation
Let the capacity of the vessel be V litres.
When 16 litres of mixture are removed, the remaining volume is V - 16 with liquids P and Q in the ratio 5:3.
Quantity of P remaining = (5/8) × (V - 16)
Quantity of Q after adding 16 litres = (3/8) × (V - 16) + 16
Since the new ratio P : Q is 3 : 5:
[(5/8)(V - 16)] / [(3/8)(V - 16) + 16] = 3 / 5
25(V - 16) = 9(V - 16) + 384
16(V - 16) = 384
V - 16 = 24
V = 40 litres.
71Numerical Ability
What should come in place of question mark (?) in following simplification problems?
50% of 250 + √? = 165
The differences between these difference values are 1, 2, and 3. Continuing this pattern, the next difference of differences is 4, which makes the next term difference 9 + 4 = 13. Adding 13 to 27 yields 27 + 13 = 40.
77Numerical Ability
What should come in place of question mark (?) in following number series ?
2,10,30,68,130,?
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Answer: (C) 222
Explanation
The series follows the formula T_n = n³ + n for integer values of n starting from 1:
1³ + 1 = 2
2³ + 2 = 10
3³ + 3 = 30
4³ + 4 = 68
5³ + 5 = 130
For the sixth term, setting n = 6 gives 6³ + 6 = 216 + 6 = 222.
78Numerical Ability
What should come in place of question mark (?) in following number series ?
142,133,115,88,?
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Answer: (E) 52
Explanation
The pattern subtracts consecutive multiples of 9 from each term to get the next:
142 - 9 = 133
133 - 18 = 115
115 - 27 = 88
The next value to subtract is 36 (9 × 4). Thus, the missing term is 88 - 36 = 52.
79Numerical Ability
What should come in place of question mark (?) in following number series ?
3,8,18,38,78,?
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Answer: (A) 158
Explanation
The pattern follows the recurrence relation T_n = 2 × T_(n-1) + 2:
3 × 2 + 2 = 8
8 × 2 + 2 = 18
18 × 2 + 2 = 38
38 × 2 + 2 = 78
Applying this rule to the last given term gives 78 × 2 + 2 = 158.
80Numerical Ability
What should come in place of question mark (?) in following number series ?
6,3,3,6,24,?
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Answer: (E) 192
Explanation
Each term is generated by multiplying the preceding term by an increasing power of 2, starting from 0.5:
6 × 0.5 = 3
3 × 1 = 3
3 × 2 = 6
6 × 4 = 24
Following this geometric progression of multipliers, the next factor is 8. Multiplying 24 by 8 gives 24 × 8 = 192.
