Which number is wrong in the following number series.
5,8,17,24,39,48,65
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Answer: (E) 39
Explanation
The terms in the series follow the alternate square offset rule starting from n = 2:
2² + 1 = 5
3² - 1 = 8
4² + 1 = 17
5² - 1 = 24
6² + 1 = 37
7² - 1 = 48
8² + 1 = 65
Using 37 gives the correct value for 6² + 1.
102Numerical Ability
Which number is wrong in the following number series.
32,64,16,96,12,120,8
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Answer: (C) 8
Explanation
The numbers are obtained by alternating multiplication and division operations using successive even numbers starting with 2:
32 × 2 = 64
64 ÷ 4 = 16
16 × 6 = 96
96 ÷ 8 = 12
12 × 10 = 120
120 ÷ 12 = 10
Applying 120 ÷ 12 yields 10 as the final term.
103Numerical Ability
Which number is wrong in the following number series.
17,21,26,33,44,57,74
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Answer: (A) 17
Explanation
Calculating the differences between successive terms reveals a sequence of consecutive prime numbers starting from 3:
21 - 18 = 3
26 - 21 = 5
33 - 26 = 7
44 - 33 = 11
57 - 44 = 13
74 - 57 = 17
Starting the sequence with 18 produces the prime differences 3, 5, 7, 11, 13, and 17 throughout the series.
104Numerical Ability
The table given below shows total number of Mouse sold by five different shopkeepers. Study the data carefully and answer the following questions.
Total Mouse Sold Wired Mouse: Wireless Mouse
A 840 9:5
B 650 7:6
C 750 2:3
D 480 3:5
E 550 7:4
Total number of Wireless mouse sold by D are what percent of total number of Wired mouse sold by C?
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Answer: (D) 100%
Explanation
Wireless mice sold by shopkeeper D = (5 / 8) × 480 = 300.
Wired mice sold by shopkeeper C = (2 / 5) × 750 = 300.
Percentage = (Wireless mice sold by D / Wired mice sold by C) × 100 = (300 / 300) × 100 = 100%.
105Numerical Ability
The table given below shows total number of Mouse sold by five different shopkeepers. Study the data carefully and answer the following questions.
Total Mouse Sold Wired Mouse: Wireless Mouse
A 840 9:5
B 650 7:6
C 750 2:3
D 480 3:5
E 550 7:4
What is the difference between the average number of wired mouse sold by A and B and total number of mouse sold by D?
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Answer: (C) 35
Explanation
Wired mice sold by shopkeeper A = (9 / 14) × 840 = 540.
Wired mice sold by shopkeeper B = (7 / 13) × 650 = 350.
Average number of wired mice sold by A and B = (540 + 350) / 2 = 890 / 2 = 445.
Total mice sold by shopkeeper D = 480.
Difference = |480 - 445| = 35.
106Numerical Ability
The table given below shows total number of Mouse sold by five different shopkeepers. Study the data carefully and answer the following questions.
Total Mouse Sold Wired Mouse: Wireless Mouse
A 840 9:5
B 650 7:6
C 750 2:3
D 480 3:5
E 550 7:4
What is the ratio between the wireless mouse sold by shopkeeper B and wired mouse sold by shopkeeper E?
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Answer: (D) 6:7
Explanation
Wireless mice sold by shopkeeper B = (6 / 13) × 650 = 300.
Wired mice sold by shopkeeper E = (7 / 11) × 550 = 350.
Ratio = Wireless mice sold by B : Wired mice sold by E = 300 : 350 = 6 : 7.
107Numerical Ability
The table given below shows total number of Mouse sold by five different shopkeepers. Study the data carefully and answer the following questions.
Total Mouse Sold Wired Mouse: Wireless Mouse
A 840 9:5
B 650 7:6
C 750 2:3
D 480 3:5
E 550 7:4
Total number of mouse sold by B and E together is what percentage more or less than total number of mouse sold by C.
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Answer: (A) 60%
Explanation
Total mice sold by shopkeeper B and E together = 650 + 550 = 1200.
Total mice sold by shopkeeper C = 750.
Percentage difference = [(1200 - 750) / 750] × 100 = (450 / 750) × 100 = 60%.
108Numerical Ability
The table given below shows total number of Mouse sold by five different shopkeepers. Study the data carefully and answer the following questions.
Total Mouse Sold Wired Mouse: Wireless Mouse
A 840 9:5
B 650 7:6
C 750 2:3
D 480 3:5
E 550 7:4
A shopkeeper - X sold Wired mouse and wireless mouse in the ratio of 23: 29 and total mouse sold by him is 20% more than that by shopkeeper B. Find the difference between the wired mouse and wireless mouse sold by him.
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Answer: (B) 90
Explanation
Total mice sold by shopkeeper B = 650.
Total mice sold by shopkeeper X = 650 × 1.20 = 780.
Ratio of wired to wireless mice sold by X = 23 : 29.
Total parts = 23 + 29 = 52 parts.
Difference in ratio parts = 29 - 23 = 6 parts.
Difference in quantity = (6 / 52) × 780 = 90.
109Numerical Ability
A container contains 160-liter mixture in which water to milk is in ratio of 3:7. If 10 liter of mixture is taken out and 20 liter of water is added in the container, the find the final ratio of water to milk in container?
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Answer: (B) 13: 21
Explanation
Initial volume of mixture = 160 L with water to milk ratio 3 : 7.
Initial water = (3 / 10) × 160 = 48 L.
Initial milk = (7 / 10) × 160 = 112 L.
When 10 L of mixture is removed:
Water removed = (3 / 10) × 10 = 3 L.
Milk removed = (7 / 10) × 10 = 7 L.
Remaining water = 48 - 3 = 45 L.
Remaining milk = 112 - 7 = 105 L.
After adding 20 L of water, final water = 45 + 20 = 65 L.
Final ratio of water to milk = 65 : 105 = 13 : 21.
110Numerical Ability
Rahul and Ayush can complete a piece a work alone in 12 days and 20 days respectively, while Deepak takes 2.5 days more than time taken by Rahul | Ayush together to complete the same work. Find the time taken by Deepak to complete the work alone?
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Answer: (B) 10 days
Explanation
Time taken by Rahul and Ayush together T = (12 × 20) / (12 + 20) = 240 / 32 = 7.5 days.
Deepak takes 2.5 days more than their combined time.
Time taken by Deepak = 7.5 + 2.5 = 10 days.
111Numerical Ability
What is the radius of circle which area is 124.74 cm² ?
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Answer: (B) 6.3 cm
Explanation
Area of a circle formula: A = πr².
Given area A = 124.74 cm².
(22 / 7) × r² = 124.74
r² = (124.74 × 7) / 22 = 39.69
r = √39.69 = 6.3 cm.
112Numerical Ability
There were two candidates in an election and 15% of the total voters didn't cast their vote. If 20% of the total cast votes declared invalid and the winning candidate got 50% of the total votes | he win by 3200 votes, then find total number of voters?
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Answer: (A) 10000
Explanation
Let total voters be 100x.
Voters who cast their vote = 85x.
Invalid votes = 20% of 85x = 17x.
Valid votes = 85x - 17x = 68x.
Winning candidate gets 50% of total voters = 50x.
Losing candidate gets = 68x - 50x = 18x.
Margin of victory = 50x - 18x = 32x.
Given margin = 3200 votes.
32x = 3200 → x = 100.
Total voters = 100 × 100 = 10000.
113Numerical Ability
A shopkeeper sold article A and article B each at Rs. 1050. On article A, he incurred a loss of 6.25% , while on article B, profit gained by him is 16 ⅔% . Find the sum of cost price (in Rs.) of article A and B?
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Answer: (C) 2020
Explanation
Selling price of article A = ₹1050 at a loss of 6.25% (fraction 1/16).
Cost price of article A = 1050 / (1 - 1/16) = 1050 × (16 / 15) = ₹1120.
Selling price of article B = ₹1050 at a profit of 16.67% (fraction 1/6).
Cost price of article B = 1050 / (1 + 1/6) = 1050 × (6 / 7) = ₹900.
Sum of cost prices = 1120 + 900 = ₹2020.
114Numerical Ability
Five years ago, the ratio of ages of Pankaj to Pradeep was 4:7. If after two years the ratio of ages of Pankaj to Pradeep becomes 5:8 respectively, then find the present age of Pradeep?
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Answer: (E) 54 years
Explanation
Let the ages of Pankaj and Pradeep 5 years ago be 4x and 7x.
Their present ages are 4x + 5 and 7x + 5.
After 2 years, their ages become 4x + 7 and 7x + 7.
According to the problem:
(4x + 7) / (7x + 7) = 5 / 8
Cross-multiplying gives:
8(4x + 7) = 5(7x + 7)
32x + 56 = 35x + 35
3x = 21
x = 7
Pradeep's present age = 7x + 5 = 7(7) + 5 = 54 years.
115Numerical Ability
Harsh and Veer started a business with the investment of Rs. 2500 and Rs. 4000 respectively. If the ratio of time period of investment of Harsh and Veer is 7: 5 respectively and the profit share of Harsh is Rs. 350, then find the profit share of Veer?
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Answer: (A) Rs 400
Explanation
Profit share ratio = Investment of Harsh × Time of Harsh : Investment of Veer × Time of Veer
Profit ratio = (2500 × 7) : (4000 × 5) = 17500 : 20000 = 7 : 8.
Given Harsh's profit share corresponding to 7 parts is Rs. 350.
Value per part = 350 / 7 = Rs. 50.
Veer's profit share corresponding to 8 parts = 8 × 50 = Rs. 400.
116Numerical Ability
Jagdish invested Rs X at 12.5% per annum for four years on simple interest in scheme A and he invested same amount in scheme B at 16% per annum on simple interest for three years. If the difference between interest earned from both schemes is Rs. 122, then find the value of X?
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Answer: (D) 6100
Explanation
Simple Interest formula: SI = (P × R × T) / 100.
Interest from Scheme A = (X × 12.5 × 4) / 100 = 0.50X.
Interest from Scheme B = (X × 16 × 3) / 100 = 0.48X.
Difference between interests = 0.50X - 0.48X = 0.02X.
Given 0.02X = 122.
X = 122 / 0.02 = 6100.
117Numerical Ability
In an examination, the average marks scored by 15 girls of a class is 54 and the average marks scored by 25 boys from the same class is 42. Find the average marks scored by the class?
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Answer: (A) 46.5
Explanation
Weighted average = (Sum of marks of girls + Sum of marks of boys) / Total number of students.
Total marks of girls = 15 × 54 = 810.
Total marks of boys = 25 × 42 = 1050.
Total class marks = 810 + 1050 = 1860.
Total number of students = 15 + 25 = 40.
Average marks of class = 1860 / 40 = 46.5.
118Numerical Ability
Manoj goes office from platform with speed of 12km / hr and comes back with 10km / hr . If he takes 5½ hours in all, then find distance between office and platform?
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Answer: (C) 30km
Explanation
Let the distance between office and platform be D km.
Total time taken = D / 12 + D / 10 = 5.5 hours.
(5D + 6D) / 60 = 11 / 2
11D / 60 = 11 / 2
D / 60 = 1 / 2
D = 30 km.
119Numerical Ability
What will come in the place of question (?) mark in following number series.
41,30,52,19,63,?
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Answer: (E) 8
Explanation
The difference pattern between consecutive terms is:
41 - 11 = 30
30 + 22 = 52
52 - 33 = 19
19 + 44 = 63
63 - 55 = 8
Hence, the missing number replacing the question mark is 8.
120Numerical Ability
What will come in the place of question (?) mark in following number series.
16,47,80,115,152,?
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Answer: (C) 191
Explanation
The difference between consecutive terms increases by 2 each step:
47 - 16 = 31
80 - 47 = 33
115 - 80 = 35
152 - 115 = 37
The next difference is 37 + 2 = 39.
Missing term = 152 + 39 = 191.
121Numerical Ability
What will come in the place of question (?) mark in following number series.
?,10,20,60,240,1200
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Answer: (B) 10
Explanation
The pattern moving left to right multiplying by consecutive numbers is:
? × 1 = 10 ⇒ ? = 10
10 × 2 = 20
20 × 3 = 60
60 × 4 = 240
240 × 5 = 1200
Thus, the value of ? is 10.
122Numerical Ability
What will come in the place of question (?) mark in following number series.
8,21,47,86,138,203,?
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Answer: (B) 281
Explanation
The differences between successive terms are multiples of 13:
21 - 8 = 13 (13 × 1)
47 - 21 = 26 (13 × 2)
86 - 47 = 39 (13 × 3)
138 - 86 = 52 (13 × 4)
203 - 138 = 65 (13 × 5)
The next difference is 13 × 6 = 78.
Missing term = 203 + 78 = 281.
123Numerical Ability
What will come in the place of question (?) mark in following number series.
11,12,16,43,59,?
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Answer: (D) 184
Explanation
The difference pattern between consecutive terms is:
12 - 11 = 1 = 1³
16 - 12 = 4 = 2²
43 - 16 = 27 = 3³
59 - 43 = 16 = 4²
The next difference is 5³ = 125.
Missing term = 59 + 125 = 184.
124Numerical Ability
What should come in the place of question (?) mark in the following questions.
42 × ²²⁄₇ + 20% of 530 - 26 =?
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Answer: (D) 212
Explanation
To simplify the expression 42 × (22/7) + 20% of 530 - 26, apply the standard order of operations.
First, simplify the multiplication with fraction: 42 × (22/7) = (42 ÷ 7) × 22 = 6 × 22 = 132.
Second, calculate the percentage term: 20% of 530 = (20/100) × 530 = 0.2 × 530 = 106.
Third, substitute these computed values back into the equation: 132 + 106 - 26.
Finally, perform addition and subtraction from left to right: 132 + 106 = 238, and 238 - 26 = 212.
125Numerical Ability
What should come in the place of question (?) mark in the following questions.
(23 × 23) + 21 × 7 = ?²
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Answer: (C) 26
Explanation
To find the unknown value in (23 × 23) + 21 × 7 = ?², simplify the left side using basic arithmetic operations.
First, compute the square of 23: 23 × 23 = 529.
Second, calculate the product of 21 and 7: 21 × 7 = 147.
Next, sum these two results: 529 + 147 = 676.
Now the equation becomes ?² = 676.
Taking the square root on both sides gives ? = √676 = 26.
126Numerical Ability
What should come in the place of question (?) mark in the following questions.
√(1444) ÷ 19 + 3.5 × √(16) = (?)
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Answer: (A) 16
Explanation
To solve √1444 ÷ 19 + 3.5 × √16 = ?, evaluate the square roots first.
The square root of 1444 is 38 because 38 × 38 = 1444.
The square root of 16 is 4 because 4 × 4 = 16.
Substitute these values back into the given expression:
38 ÷ 19 + 3.5 × 4.
Perform division and multiplication from left to right:
38 ÷ 19 = 2
3.5 × 4 = 14
Finally, add the results together: 2 + 14 = 16.
127Numerical Ability
What should come in the place of question (?) mark in the following questions.
780 ÷ 48 × 16 = ?
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Answer: (E) 260
Explanation
To evaluate 780 ÷ 48 × 16 = ?, apply the standard order of operations or simplify the expression using fractional form.
Write the expression as (780 × 16) / 48.
Simplify the fraction by dividing the numerator and denominator by 16:
48 ÷ 16 = 3.
The expression simplifies to 780 / 3.
Performing the division gives 780 ÷ 3 = 260.
128Numerical Ability
What should come in the place of question (?) mark in the following questions.
1486 + 212 - 1704 = ? - (11)²
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Answer: (B) 115
Explanation
To solve 1486 + 212 - 1704 = ? - (11)², simplify both sides step by step.
First, calculate the left side of the equation:
1486 + 212 = 1698
1698 - 1704 = -6
Next, evaluate the exponent on the right side: (11)² = 121.
Substitute these values into the equation:
-6 = ? - 121
Isolate ? by adding 121 to both sides:
? = 121 - 6 = 115.
129Numerical Ability
What should come in the place of question (?) mark in the following questions.
? × (8² + 26) = 60²
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Answer: (D) 40
Explanation
To solve ? × (8² + 26) = 60², simplify the expressions inside the parentheses and the exponent first.
Calculate 8² = 64, so 8² + 26 = 64 + 26 = 90.
Calculate 60² = 3600.
Substitute these values back into the equation:
? × 90 = 3600
Isolate ? by dividing 3600 by 90:
? = 3600 ÷ 90 = 40.
130Numerical Ability
What should come in the place of question (?) mark in the following questions.
? % of 800 + 8³ = 1024
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Answer: (B) 64
Explanation
To find the value of ? in ?% of 800 + 8³ = 1024, simplify the exponent first.
Calculate 8³ = 8 × 8 × 8 = 512.
Substitute this into the equation:
?% of 800 + 512 = 1024
Subtract 512 from both sides to isolate the percentage term:
?% of 800 = 1024 - 512 = 512
Express ?% as (? / 100):
(? / 100) × 800 = 512
8 × ? = 512
Divide both sides by 8:
? = 512 ÷ 8 = 64.
131Numerical Ability
What should come in the place of question (?) mark in the following questions.
281 + ? = 32% of 1700
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Answer: (D) 263
Explanation
To solve 281 + ? = 32% of 1700, calculate the percentage on the right side first.
32% of 1700 = (32 / 100) × 1700 = 32 × 17.
Calculate 32 × 17 = 544.
Substitute this back into the original equation:
281 + ? = 544
Subtract 281 from both sides to isolate ?:
? = 544 - 281 = 263.
132Numerical Ability
What should come in the place of question (?) mark in the following questions.
2⅓ +3⅙ = ? - 1½
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Answer: (C) 7
Explanation
To evaluate 2⅓ + 3⅙ = ? - 1½, isolate ? by moving -1½ to the left side of the equation:
? = 2⅓ + 3⅙ + 1½.
Separate the whole numbers and the fractions:
Whole numbers: 2 + 3 + 1 = 6.
Fractions: ⅓ + ⅙ + ½.
Find a common denominator, which is 6:
⅓ = 2/6, ⅙ = 1/6, ½ = 3/6.
Sum of fractions = 2/6 + 1/6 + 3/6 = 6/6 = 1.
Combine the whole numbers and fractional sum:
? = 6 + 1 = 7.
133Numerical Ability
What should come in the place of question (?) mark in the following questions.
20% of (? + 96) = 30 × 1.6
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Answer: (D) 144
Explanation
To find ? in 20% of (? + 96) = 30 × 1.6, simplify the right side of the equation first.
Calculate 30 × 1.6 = 48.
Express 20% as a fraction: 20% = 20/100 = 1/5.
Substitute these into the equation:
(1/5) × (? + 96) = 48
Multiply both sides by 5:
? + 96 = 48 × 5 = 240
Subtract 96 from both sides to solve for ?:
? = 240 - 96 = 144.
134Numerical Ability
What should come in the place of question (?) mark in the following questions.
24% of ? + 48% of 250 = 240
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Answer: (C) 500
Explanation
Calculate 48% of 250 using the identity 48% of 250 = 24% of 500 = 120.
Substitute this value back into the given percentage expression: 24% of ? + 120 = 240.
Subtracting 120 from both sides gives 24% of ? = 120.
Expressing 24% as 24/100, the equation becomes (24/100) × ? = 120.
Solving for the unknown yields ? = (120 × 100) / 24 = 5 × 100 = 500.
135Numerical Ability
What should come in the place of question (?) mark in the following questions.
²⁸⁸⁄? +12² = 40% of 420
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Answer: (A) 12
Explanation
Calculate the right-hand side of the equation: 40% of 420 = 0.40 × 420 = 168.
Evaluate the square term on the left-hand side: 12² = 144.
Set up the simplified equation with the unknown divisor x in place of the expression: (288 / x) + 144 = 168.
Subtract 144 from both sides to isolate the fraction term: 288 / x = 168 - 144 = 24.
Solve for x by dividing 288 by 24: x = 288 / 24 = 12.
136Numerical Ability
What should come in the place of question (?) mark in the following questions.
17.5 × 8 + ? = 20² + 100
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Answer: (A) 360
Explanation
Evaluate the multiplication term on the left side: 17.5 × 8 = (35 / 2) × 8 = 140.
Evaluate the numerical terms on the right side: 20² + 100 = 400 + 100 = 500.
Substitute these simplified values back into the original equation: 140 + ? = 500.
Subtract 140 from both sides to determine the unknown value: ? = 500 - 140 = 360.
137Numerical Ability
What should come in the place of question (?) mark in the following questions.
25% of 960 + 24 × 15 = ?
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Answer: (D) 600
Explanation
Calculate 25% of 960 by dividing 960 by 4, which yields 960 / 4 = 240.
Calculate the product of the second term: 24 × 15 = 24 × (10 + 5) = 240 + 120 = 360.
Substitute both evaluated values into the expression to solve for the missing question mark: ? = 240 + 360 = 600.
138Numerical Ability
What should come in the place of question (?) mark in the following questions.
∛? +24² = 29.2 × 20
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Answer: (A) 512
Explanation
Evaluate the term on the right-hand side of the equation: 29.2 × 20 = 584.
Evaluate the square term on the left-hand side: 24² = 576.
The expression simplifies to ³√? + 576 = 584.
Subtract 576 from both sides to isolate the cube root of the unknown number: ³√? = 584 - 576 = 8.
Cube both sides of the equation to find the value of the unknown: ? = 8³ = 512.
139Numerical Ability
A contractor employed 20 men to finish a work in 22 days. After 10 days he employed X men more, due to which work completed by them in 6 days less than projected. Find the value of X.
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Answer: (A) 20
Explanation
Total work = 20 × 22 = 440 man-days.
Work completed in the first 10 days = 20 × 10 = 200 man-days.
Remaining work = 440 - 200 = 240 man-days.
The total time taken is 6 days less than projected, which is 22 - 6 = 16 days.
Thus, the remaining time available is 16 - 10 = 6 days.
Let the new team size be (20 + X).
(20 + X) × 6 = 240
20 + X = 40
X = 20.
140Numerical Ability
A 440 ml mixture of water and milk contain 40% of water. If 54 ml of water and 66 ml of milk is added into the mixture, then find the ratio of milk and water in the mixture.
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Answer: (C) 33:23
Explanation
In the 440 ml mixture:
Water = 40% of 440 = 176 ml.
Milk = 440 - 176 = 264 ml.
After adding 54 ml of water and 66 ml of milk:
New water quantity = 176 + 54 = 230 ml.
New milk quantity = 264 + 66 = 330 ml.
Ratio of milk to water = 330 : 230 = 33 : 23.
141Numerical Ability
A bag contains 5 red, 7 white and some yellow ball. If the probability of choosing yellow ball is 2/5, the find the total balls.
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Answer: (C) 20
Explanation
Let the number of yellow balls be Y.
Total balls = 5 + 7 + Y = 12 + Y.
Given probability of choosing a yellow ball = Y / (12 + Y) = 2/5.
5Y = 2(12 + Y)
5Y = 24 + 2Y
3Y = 24
Y = 8.
Total balls = 12 + 8 = 20.
142Numerical Ability
The speed of downstream is 66 ⅔ % more than speed of upstream. If the boat covers a distance of 120 km in upstream in 10 hours. Find the speed of stream.
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Answer: (D) 4 kmph
Explanation
Upstream speed = 120 km / 10 hours = 12 km/h.
Downstream speed = 12 × (1 + 66.67%) = 12 × (1 + 2/3) = 20 km/h.
Speed of stream = (Downstream speed - Upstream speed) / 2 = (20 - 12) / 2 = 4 km/h.
143Numerical Ability
Pipe A and pipe B can fill a tank in 15 hours and 18 hours respectively. Both the pipes were opened together, after 5 hours pipe A was closed. Find the total time taken to fill the tank.
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Answer: (A) 12 hours
Explanation
Let total tank capacity = LCM(15, 18) = 90 units.
Efficiency of pipe A = 90 / 15 = 6 units/hour.
Efficiency of pipe B = 90 / 18 = 5 units/hour.
Work completed in the first 5 hours by both pipes = (6 + 5) × 5 = 55 units.
Remaining work = 90 - 55 = 35 units.
Time taken by pipe B alone to finish the remaining work = 35 / 5 = 7 hours.
Total time taken = 5 + 7 = 12 hours.
144Numerical Ability
690 toffees are distributed among Jyoti, Shalu and Sagar in the ratio of 7: 11: 5. Find the difference between no. of toffees of Jyoti and Sagar.
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Answer: (E) 60
Explanation
Total ratio parts = 7 + 11 + 5 = 23 parts.
Value of 1 part = 690 / 23 = 30 toffees.
Difference between Jyoti's and Sagar's share = 7 - 5 = 2 parts.
Difference in toffees = 2 × 30 = 60.
145Numerical Ability
The area of square is 100 m² more than the area of a rectangle of length 12 m . If the perimeter of the square is 56 m , then find the ratio of length and breadth of the rectangle.
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Answer: (B) 3:2
Explanation
Side of the square = 56 / 4 = 14 m.
Area of the square = 14² = 196 m².
Area of the rectangle = 196 - 100 = 96 m².
Breadth of the rectangle = 96 / 12 = 8 m.
Ratio of length to breadth = 12 : 8 = 3 : 2.
146Numerical Ability
Average weight of three person is 51. If weight of second person is 14 kg less than first person and 5 kg more than third person, then find the age of first person.
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Answer: (B) 62 kg
Explanation
Sum of weights of the three persons = 51 × 3 = 153 kg.
Let the weight of the second person be W.
Weight of the first person = W + 14.
Weight of the third person = W - 5.
(W + 14) + W + (W - 5) = 153
3W + 9 = 153
3W = 144
W = 48 kg.
Weight of the first person = 48 + 14 = 62 kg.
147Numerical Ability
Mukesh invested a certain sum of money on compound interest at rate of 20% p.a. for 1.5 years at semiannually. If interest obtained by him is Rs. 1986, then find the sum.
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Answer: (D) Rs. 6000
Explanation
Rate of interest per half-year r = 20% / 2 = 10%.
Number of half-year periods n = 1.5 × 2 = 3.
Effective compound interest rate = (1 + 0.10)³ - 1 = 1.331 - 1 = 0.331 or 33.1%.
Principal = Interest / Effective rate = 1986 / 0.331 = Rs. 6000.
148Numerical Ability
Ayush spent 25% of his monthly income on rent, 30% on food and 20% of income he saves. If the difference between his savings and expenditure on food is Rs. 1800, then find his expenditure of Rent.
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Answer: (A) Rs. 4500
Explanation
Let the total monthly income be 100%.
Expenditure on food = 30%.
Savings = 20%.
Difference between food expenditure and savings = 30% - 20% = 10%.
Given 10% of income = Rs. 1800.
Expenditure on rent = 25% of income = (1800 / 10) × 25 = Rs. 4500.
149Numerical Ability
Which number is wrong in the following number series.
64,384,48,288,36,216,28
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Answer: (C) 28
Explanation
To identify the wrong term in the given number series, observe the mathematical pattern relating consecutive numbers. The series follows an alternating sequence of two operations: multiplying by 6 and dividing by 8.
64 × 6 = 384
384 ÷ 8 = 48
48 × 6 = 288
288 ÷ 8 = 36
36 × 6 = 216
216 ÷ 8 = 27
Following this consistent pattern, the final term should be 27 instead of 28. Therefore, 28 is the wrong number in the given series.
150Numerical Ability
Which number is wrong in the following number series.
16,15,32,99,400,2005.12036
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Answer: (A) 16
Explanation
To find the wrong number in the series, analyze the pattern relating each term to the next. The sequence follows a rule where each term is multiplied by consecutive integers starting from 1, and the same integer is added to the product: T(n+1) = T(n) × n + n.
Starting with 14 as the first term:
14 × 1 + 1 = 15
15 × 2 + 2 = 32
32 × 3 + 3 = 99
99 × 4 + 4 = 400
400 × 5 + 5 = 2005
2005 × 6 + 6 = 12036
Every term after the first matches the pattern perfectly when starting from 14. Therefore, 16 is the wrong term in the given series.