IBPS PO Prelims 2022 Reasoning Ability Questions with Solutions

Explanation

Comparing the statements: 'Meeting Check Circle Star' = 'slk dgv cni bnm' 'Circle Yellow Coffee Star' = 'slk poz trf bnm' 'Meeting Coffee Line Star' = 'dgv poz kda bnm' 'Board Star Yellow' = 'bnm trf lfh'

The word 'Star' appears in all four statements, so its code is 'bnm'. Comparing the first and second statements, the remaining common word is 'Circle', and the common code shared between them is 'slk'. Therefore, 'slk' stands for 'Circle'.

Explanation

Comparing the given statements: The word 'Star' appears in all statements and is coded as 'bnm'. In statements 2 and 4, 'Yellow' is the common word coded as 'trf'. In statement 4 ('Board Star Yellow' = 'bnm trf lfh'), the remaining word 'Board' is coded as 'lfh'. In statements 1 and 3, 'Meeting' is the common word (besides 'Star') and is coded as 'dgv'. Combining these, the code for 'Board Meeting' is 'lfh dgv'.

Explanation

In the first statement ('Meeting Check Circle Star' = 'slk dgv cni bnm'), 'Star' is 'bnm', 'Circle' is 'slk', and 'Meeting' is 'dgv', leaving 'Check' coded as 'cni'. In statements 2 and 3, 'Coffee' is the common word (besides 'Star') and is coded as 'poz'. Thus, the codes 'cni' and 'poz' represent the words 'Check' and 'Coffee', respectively.

Explanation

The given series is: H F 3 A L 2 3 I B 6 R E 8 2 R 3 T M 6 B I C 9 4 D U 3 4 T 7 4. The vowels present in the series are A, I, E, I, and U. Checking each vowel to see if it is immediately followed by a number: A is followed by L (letter) The first I is followed by B (letter) E is followed by 8 (number) The second I is followed by C (letter) U is followed by 3 (number)

There are two vowels, E and U, that satisfy the condition.

Explanation

In the series H F 3 A L 2 3 I B 6 R E 8 2 R 3 T M 6 B I C 9 4 D U 3 4 T 7 4, we search for the pattern Letter-Number-Letter.

Analyzing each number: 3 in F 3 A is preceded by F and followed by A. 6 in B 6 R is preceded by B and followed by R. 3 in R 3 T is preceded by R and followed by T. 6 in M 6 B is preceded by M and followed by B.

All other numbers are either preceded or followed by another number or sit at the end of the series. Thus, there are 4 such numbers in total.

Explanation

Since all articles are headlines, if all headlines could be reports, then all articles would necessarily be reports. However, the statement specifies that only a few articles are reports, meaning some articles are definitely not reports. Thus, all headlines can never be reports, making Conclusion I logically sound. Conclusion II does not follow because the overlap between news and articles does not mandate that any of those news items fall outside the report category.

Explanation

Subject and air have no direct negative relation, so subject can overlap with the portion of air that does not overlap with relation, making Conclusion I a valid possibility. For Conclusion II, since some relations are air and no air is game, the specific portion of relation that overlaps with air can never be game. Thus, it is definitely true that some relation is not game.

Explanation

The statement only bake is chips means that all chips are bake, and chips cannot belong to any set other than bake. Consequently, chips cannot overlap with rice under any condition. Therefore, chips can neither definitely be rice nor potentially be rice, rendering both conclusions false.

Explanation

Evaluating the clues places eight persons from left to right at positions 1 to 8: P (1, North), Y (2, South), W (3, South), U (4, North), Q (5, South), E (6, North), R (7, South), and I (8, North). Since W faces south at position 3, his immediate right direction points toward position 2, occupied by Y.

Explanation

From the arrangement P (1, North), Y (2, South), W (3, South), U (4, North), Q (5, South), E (6, North), R (7, South), and I (8, North), E is located at position 6 and P is located at position 1. The four persons sitting between them are Y, W, U, and Q.

Explanation

In the arrangement, four persons face south (Y, W, Q, R) and four persons face north (P, U, E, I). Among the given options, I is the only person who faces north, whereas the other four persons face south.

Explanation

I is positioned at position 8 facing north. Looking north, the left side corresponds to decreasing position numbers. Q is located at position 5, which is three places to the left of I.

Explanation

Y is situated at position 2 facing south. Facing south means his left direction points toward positions 3 through 8. Therefore, six persons (W, U, Q, E, R, I) sit to the left of Y.

Explanation

Setting light house T at coordinates (0, 0), S is at (-600, 0), R is at (-1200, 0), Q is at (-1200, 600), P is at (-600, 600), U is at (0, 1200), and V is at (600, 1200). Relative to P (-600, 600), light house V (600, 1200) lies +1200 m to the east and +600 m to the north, which corresponds to the north-east direction.

Explanation

With T at (0, 0), light house V is at (600, 1200) and light house W (600m south of V) is at (600, 600). Light house X, being 600m west of W, has coordinates (0, 600). The straight-line distance between X (0, 600) and T (0, 0) along the y-axis is 600m.

Explanation

Following the direct sequence of given positions from lighthouse Q to lighthouse V gives the path Q → R (600 m) → S (600 m) → T (600 m) → U (1200 m) → V (600 m). Adding these individual distances together yields 600 + 600 + 600 + 1200 + 600 = 3600 meters, which equals 3.6 kilometers.

Explanation

In the given statement C > T = R < W ≤ S = A < E ≥ B, the relationship between C and S contains opposing inequality signs (> and <), making conclusion I false. Similarly, the relationship between W and B contains opposing inequality signs (< and ≥), making conclusion II false. Therefore, neither conclusion I nor II is true.

Explanation

From the statement M ≥ O ≥ L ≥ E ≤ T < G ≤ K = F, combining T < G ≤ K = F yields T < F, which means F > T, making conclusion I true. Combining M ≥ O ≥ L ≥ E directly yields M ≥ E, making conclusion II true.

Explanation

Combining X = O ≥ Y and Y ≥ Q = F gives X ≥ F, so conclusion I is true. Combining Y ≤ N ≤ D and Y ≥ Q gives D ≥ Q, which does not guarantee D = Q, so conclusion II is false.

Explanation

From S ≥ Y ≥ E = F, F can be equal to S, so F < S is not definitely true. From E = F ≥ R > P = L, the presence of the strict inequality > ensures that E > L, making conclusion II true.

Explanation

Arranging the six persons chronologically gives P (4th June, Red), M (13th June, Pink), G (4th August, Blue), J (13th August, Black), K (4th November, Green), and D (13th November, Yellow). J is born on 13th August and likes the black color.

Explanation

M was born on 13th June, the second earliest date. The persons born after M are G (4th August), J (13th August), K (4th November), and D (13th November). Since four persons are younger than M, the count is more than three.

Explanation

From the completed puzzle schedule, M is born on 13th June and likes pink.

Explanation

P was born on 4th June, which is the first slot, and likes red.

Explanation

D was born on 13th November, two persons (P and M) were born before G (4th August), the one who likes green (K) was born in November and is younger than P (born in June), and J does not like green. Thus, all statements are true.

Explanation

Extracting the 1st, 4th, 6th, and 8th letters from the word NUTRITION gives N, R, T, and O respectively. Rearranging these letters forms the standard English word TORN. The third letter in TORN is R.

Explanation

We search the series for the pattern Number-Symbol-Letter. Examining the given sequence A^SF79K5#XK8J*FIR31@V95%ML gives three such instances: 5#X, 1@V, and 5%M.

Explanation

In a sequence, the element 6th to the right of the 18th element from the right end corresponds to the (18 - 6) = 12th element from the right end. Counting 12 positions from the right end of A^SF79K5#XK8J*FIR31@V95%ML yields the letter F.

Explanation

In the series A^SF79K5#XK8J*FIR31@V95%ML, counting from the left end shows the 10th element is 5. Counting 14 elements from the right end gives J. The elements located strictly between 5 and J are #, X, K, and 8, which totals 4 elements.

Explanation

Scanning the series for adjacent pairs of numbers gives 79, 31, and 95. The numbers immediately followed by another number are 7 (followed by 9), 3 (followed by 1), and 9 (followed by 5), giving a total count of 3.

Explanation

Arranging five boxes in increasing order from right to left places the heaviest box on the far left. Box L is lighter than only one box, so L is 2nd heaviest. Box Q is heavier than X and Z but is not the heaviest, which forces Q to be 3rd, X to be 4th, and Z to be 5th heaviest. Box P occupies the 1st position as the heaviest box, meaning zero boxes are heavier than P.

Explanation

The seating order around the triangular table in clockwise direction starting from corner 1 is D (corner, facing outside), A (side, facing inside), N (side, facing inside), M (corner, facing outside), F (side, facing inside), E (side, facing inside), C (corner, facing outside), B (side, facing inside), and L (side, facing inside). B is seated between C and L. When A interchanges position with B, A sits between C and L, making both L and C his immediate neighbours.

Explanation

Following the clockwise seating sequence D-A-N-M-F-E-C-B-L, counting in the anticlockwise direction from A to E goes backwards through D, L, B, and C before reaching E. Exactly four persons sit between A and E in this direction.

Explanation

From the solved seating arrangement, the three corners of the triangular table facing outside are occupied by D at corner 1, M at corner 2, and C at corner 3. Thus, C, D, and M sit at the corners.

Explanation

The original clockwise sequence starting from A is A, N, M, F, E, C, B, L, D. Arranging the persons in alphabetical order (A, B, C, D, E, F, L, M, N) clockwise starting from A gives A, B, C, D, E, F, L, M, N. Comparing position by position shows that only E remains in the 5th position from A in both arrangements.

Explanation

Nine positions around the triangular table consist of three corner positions facing outside and six side positions facing inside. Placing D at corner position 1, E sits at side position 6 to satisfy having three persons between D and E. M sits 2nd to the right of E at corner position 4. To make the number of persons between M and D equal to that between M and C, C is placed at corner position 7. B cannot be adjacent to M or D, leaving side position 8 for B. F cannot sit near D, placing F at side position 5. Since A sits to the immediate right of N with both facing inside, N is placed at position 3 and A at position 2. L sits at the remaining side position 9. In this unique arrangement, F sits 6th to the right of A, L and B are adjacent neighbours, E sits to the immediate left of C, and B faces inside.

Explanation

Comparing the first statement "Every Day score good" (ev ba cr do) and the second statement "Day hard work good" (ba hd rk do), the common words are "Day" and "good" corresponding to codes "ba" and "do". Comparing these with the third statement "Work always day practice" (rk wl ba pc), the word "day" appears with code "ba". Subtracting "ba" for "day" leaves "do" as the unique code for "good".

Explanation

From the statements, "Day" is the common word across the first three sentences corresponding to code "ba". Comparing the first statement "Every Day score good" (ev ba cr do) and the fourth statement "Always practice score good" (pc wl cr do), the common codes are "do" and "cr". Since "do" stands for "good", "cr" uniquely represents "score". Therefore, "ba cr" decodes to "Day score".

Explanation

In the third statement "Work always day practice" (rk wl ba pc) and the fourth statement "Always practice score good" (pc wl cr do), both "always" and "practice" are present. After eliminating known codes ("rk" for "work", "ba" for "day", "cr" for "score", and "do" for "good"), the remaining codes in both sentences are "wl" and "pc". Since no other sentence distinguishes between "always" and "practice", the code for "practice" is either "wl" or "pc".

Explanation

The word "Every" appears only in the first statement "Every Day score good" (ev ba cr do). With "Day" coded as "ba", "score" coded as "cr", and "good" coded as "do", "Every" is uniquely coded as "ev". Thus, pairing "Every" with "do" is incorrect.

Explanation

Placing A facing inside at position 1, E sits second to the right of A at position 3, and O sits third to the right of A at position 4. To satisfy the non-adjacency and opposite constraints, C sits at position 6 facing outside, K sits at position 2 facing inside, G sits at position 8 facing outside, M sits at position 5 facing inside, and I sits at position 7 facing outside. Since E is at position 3 and I is at position 7 directly across the 8-person circular table, I sits opposite to E.

Explanation

In the circular arrangement, K is positioned at position 2 facing towards the center. Moving clockwise from K to count positions to the right, position 3 is occupied by E (first to the right), position 4 by O (second to the right), and position 5 by M. Therefore, M is seated third to the right of K.

Explanation

Based on the given conditions, we can deduce the step-by-step circular seating arrangement of the eight persons:

Assume A faces inside (towards the center). E sits second to the right of A, and O sits third to the right of A. Since O sits second to the right of K and E faces the same direction as K, K must face inside and sit between A and E. C is not adjacent to A or E, nor opposite to A or E. This places C three seats away from A, facing outside (away from the center). M faces inside and sits directly opposite A. Since G sits third to the right of M, G sits between A and the remaining vacant spot, facing outside. This satisfies the condition that A faces opposite to one of its immediate neighbors (G faces outside while A faces inside). The remaining spot between C and G is occupied by I, who faces outside, while C, I, and G all face outside to satisfy the condition that three persons face outside.

The order of persons sitting around the circle is A, K, E, O, M, C, I, G.

Counting from A to C in the anti-clockwise direction passes through K, E, O, and M. Therefore, four persons sit between C and A.

Explanation

In the solved circular arrangement, A, K, E, O, and M face towards the center, while C, I, and G face outside the center. Both A and O face inside, both M and K face inside, both G and I face outside, and both A and M face inside. However, E faces inside while C faces outside, making E and C the pair with opposite facing directions.

Explanation

K is at position 2 facing towards the center, so the person sitting at his immediate right in the clockwise direction is E at position 3. Since E faces towards the center, counting three positions to the left of E in the counter-clockwise direction leads to position 2 (first left), position 1 (second left), and position 8, which is occupied by G.

Explanation

Comparing the first two statements, "party" is common and corresponds to the code "five". Comparing the first and third statements, "grand" corresponds to "two". In the first statement, "village" and "here" remain with codes "three" and "seven". Thus, "village" can be coded as "three" or "seven", making "three five" a possible code for "Village Party".

Explanation

From the statement "Grand village party here" coded as "three two seven five", identifying "party" as "five" and "grand" as "two" leaves the words "village" and "here" associated with "three" and "seven". Since no further statement isolates "here", its code can be either "three" or "seven".

Explanation

The word "fun" appears in both "School party fun" coded as "five four ten" and "Township fun grand" coded as "one ten two". Since "party" is coded as "five" and "grand" is coded as "two", the common code "ten" corresponds directly to the word "fun".

Explanation

In the statement "Township fun grand" coded as "one ten two", the code for "fun" is "ten" and the code for "grand" is "two". Eliminating these leaves the word "township" uniquely coded as "one".

Explanation

Since T is the only neighbour of P, P sits at the extreme left end (position 1) and T at position 2. Four persons sit between P and H, placing H at position 6. A sits second to the right of H at position 8. Placing I fourth to the left of K puts I at position 3 and K at position 7. To avoid placing Y next to H or T, Y sits at position 4 and C sits at position 5, which satisfies C sitting to the left of H. Thus, A sits at the extreme right end of the row.