RRB NTPC2021MathematicsPage 27 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1301–1350 of 1,785, each with the correct answer and a step-by-step explanation.

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1301Mathematics
The value of (cosecθ + cotθ) × (1 − cosθ) is:
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Answer: (C) sinθ

Explanation

Using the trigonometric identities cosecθ = 1/sinθ and cotθ = cosθ/sinθ:

(cosecθ + cotθ) = (1 + cosθ) / sinθ

Multiplying this by (1 − cosθ):

(cosecθ + cotθ) × (1 − cosθ) = [(1 + cosθ) / sinθ] × (1 − cosθ) = (1 − cos²θ) / sinθ

Using the Pythagorean identity 1 − cos²θ = sin²θ:

= sin²θ / sinθ = sinθ

1302Mathematics
A raw data is in ascending order i.e. 3,4,8,x,x + 1,12,14,15 . If the median of this data is 9.5, then the value of x is:
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Answer: (B) 9

Explanation

For an even number of observations n = 8, the median is the arithmetic mean of the (n/2)th and (n/2 + 1)th terms, which are the 4th and 5th terms.

Median = (4th term + 5th term) / 2

Substituting the 4th term (x), 5th term (x + 1), and median (9.5):

(x + x + 1) / 2 = 9.5 2x + 1 = 19 2x = 18 x = 9

1303Mathematics
If ¹⁄ₓ +⅔ = ¹⁄₂ₓ +¾ , then the value of x is:
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Answer: (C) 6

Explanation

Rearranging the given equation to group terms containing x on one side and constant terms on the other:

1/x - 1/(2x) = 3/4 - 2/3

Simplifying both sides:

(2 - 1)/(2x) = (9 - 8)/12

1/(2x) = 1/12

Equating the denominators yields:

2x = 12 x = 6

1304Mathematics
What is the speed of a man, in km/h, who takes 10 min to run a distance of 1000 m?
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Answer: (A) 6 km/h

Explanation

Speed = Distance / Time.

Distance = 1000 m = 1 km Time = 10 min = 10/60 h = 1/6 h

Speed = 1 / (1/6) = 6 km/h.

1305Mathematics
How will you write 2.47 hours in hours, minutes and seconds?
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Answer: (A) 2 hours, 28 minutes, 12 seconds

Explanation

To convert 2.47 hours into hours, minutes, and seconds:

The whole number part gives 2 hours.

Multiply the remaining decimal portion by 60 to convert it into minutes: 0.47 × 60 = 28.2 minutes

The whole number part gives 28 minutes.

Multiply the remaining decimal portion of the minutes by 60 to convert it into seconds: 0.2 × 60 = 12 seconds

Combining these components yields 2 hours, 28 minutes, and 12 seconds.

1306Mathematics
If a cube of side 20 cm is divided into smaller cubes of side 4 cm, then what is the total number of smaller cubes?
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Answer: (B) 125

Explanation

The total number of smaller cubes formed by dividing a larger cube is given by the formula N = (L / l)³, where L is the side length of the larger cube and l is the side length of each smaller cube.

Substituting L = 20 cm and l = 4 cm:

N = (20 / 4)³ = 5³ = 125

1307Mathematics
In a right circular cylinder, the ratio of the curved surface area to the total surface area is 2 : 5. Find the ratio of the height to the radius of the cylinder.
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Answer: (D) 2 : 3

Explanation

The curved surface area of a right circular cylinder is 2πrh and its total surface area is 2πr(h + r), where h is the height and r is the radius.

Using the given ratio of curved surface area to total surface area: (2πrh) / [2πr(h + r)] = 2 / 5

Canceling the common terms 2πr: h / (h + r) = 2 / 5

Cross-multiplying to solve for the relation between h and r: 5h = 2(h + r) 5h = 2h + 2r 3h = 2r h / r = 2 / 3

The ratio of the height to the radius is h : r = 2 : 3.

1308Mathematics
For a frequency distribution, mean, median and mode are connected by the relation:
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Answer: (A) mean = (3 median - mode)/2

Explanation

The empirical relationship between the measures of central tendency for a moderately skewed frequency distribution is:

Mode = 3 Median - 2 Mean

Rearranging this equation to solve for Mean:

2 Mean = 3 Median - Mode Mean = (3 Median - Mode) / 2

1309Mathematics
If a:b = 2:5,b:c = 5:8,c:d = 8:11 ,then a:dis:
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Answer: (C) 2:11

Explanation

To find the ratio a:d, multiply the successive ratios:

a/d = (a/b) × (b/c) × (c/d)

Substituting the given values:

a/d = (2/5) × (5/8) × (8/11)

Canceling out common terms in the numerator and denominator gives:

a/d = 2/11

1310Mathematics
The product of two positive numbers is 972 and their quotient is ⁴⁄₃ . The numbers are:
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Answer: (B) 36 and 27

Explanation

Let the two positive numbers be x and y.

From the given quotient, x ÷ y = 4/3, which gives x = (4/3)y.

Substituting x into the product equation x × y = 972: (4/3)y × y = 972 y² = 972 × (3/4) y² = 729 y = √729 = 27

Substituting y = 27 into x = (4/3)y gives: x = (4/3) × 27 = 36

1311Mathematics
If the selling price of 10 pens is equal to the cost price of 15 pens, then the gain per cent is:
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Answer: (D) 50%

Explanation

When the selling price of x items equals the cost price of y items, the gain percentage is given by the formula:

Gain % = [(y - x) / x] × 100

Here, x = 10 and y = 15.

Substituting the given values: Gain % = [(15 - 10) / 10] × 100 = (5 / 10) × 100 = 50%

1312Mathematics
The length of a rectangular solar panel is 5% more than its breadth. If the area of the solar panel is 210 m² , find its breadth.
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Answer: (C) 10√2 m

Explanation

Let the breadth of the rectangular solar panel be b metres.

Length l = b + 5% of b = 1.05b = (21/20)b

Area = length × breadth 210 = (21/20)b × b 210 = (21/20)b² b² = (210 × 20) / 21 b² = 200 b = √200 = 10√2 m

1313Mathematics
The negative of a non-zero rational number is:
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Answer: (C) a rational number

Explanation

A rational number is any number that can be expressed in the form p/q, where p and q are integers and q ≠ 0. For any non-zero rational number p/q, its negative is -(p/q) = (-p)/q. Since integers are closed under negation, -p is also an integer. Therefore, (-p)/q is a ratio of two integers with a non-zero denominator, which satisfies the definition of a rational number.

1314Mathematics
The third proportional of 10 and 20 is:
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Answer: (A) 40

Explanation

The third proportional c of two numbers a and b is given by the formula c = b² / a.

Substituting a = 10 and b = 20: c = (20 × 20) / 10 = 400 / 10 = 40.

1315Mathematics
Which one of the following triplets can be measures of the sides of a triangle?
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Answer: (D) 5, 7, 4

Explanation

By the Triangle Inequality Theorem, three lengths can form a triangle if and only if the sum of the lengths of the two shorter sides is strictly greater than the length of the longest side (a + b > c).

For the side lengths 4, 5, and 7, the two shorter sides are 4 and 5, and the longest side is 7. Since 4 + 5 = 9 > 7, the triangle inequality condition is satisfied.

1316Mathematics
A train, 100 m long, is running at a speed of 64 km/h. Find the time taken by it to pass a man who is running at 8 km/h in the direction opposite to that of the train.
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Answer: (D) 5 sec

Explanation

When two objects move in opposite directions, their relative speed is the sum of their individual speeds: Relative speed = 64 + 8 = 72 km/h

Converting relative speed to m/s: 72 × (5/18) = 20 m/s

Time taken = Length of train / Relative speed = 100 / 20 = 5 sec.

1317Mathematics
Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is:
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Answer: (B) 1:1

Explanation

Area of a parallelogram = base × perpendicular height

Since both parallelograms have equal bases (b) and lie between the same pair of parallel lines, they share the same perpendicular distance/height (h) between those parallels.

Ratio of areas = (b × h) / (b × h) = 1 / 1 = 1:1

1318Mathematics
If the radius of a sphere is tripled, then its surface area is increased by:
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Answer: (A) 800%

Explanation

The surface area of a sphere of radius r is given by A = 4πr². When the radius is tripled (r' = 3r), the new surface area becomes A' = 4π(3r)² = 36πr² = 9A.

The increase in surface area is A' - A = 9A - A = 8A.

Percentage increase = (Increase / Original Area) × 100 = (8A / A) × 100 = 800%.

1319Mathematics
The largest four-digit number which is exactly divisible by 77 is:
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Answer: (B) 9933

Explanation

The largest four-digit number is 9999.

Dividing 9999 by 77 gives a quotient of 129 and a remainder of 66 (9999 = 77 × 129 + 66).

Subtracting the remainder from 9999 yields 9999 - 66 = 9933, which is the largest four-digit number exactly divisible by 77.

1320Mathematics
36 men can do a task in 25 days. If the task is to be finished in 60 days, then the number of men required are:
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Answer: (B) 15

Explanation

The total work required to complete the task remains constant, following the inverse variation formula:

M₁ × D₁ = M₂ × D₂

Substituting the given values: 36 × 25 = M₂ × 60 900 = 60 × M₂ M₂ = 900 / 60 = 15 men

1321Mathematics
If x% of y is 2000 and y% of z is 4000, then the relation between x and z is:
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Answer: (A) z = 2x

Explanation

Given that x% of y is 2000: (x / 100) × y = 2000 ⇒ x × y = 200000

Given that y% of z is 4000: (y / 100) × z = 4000 ⇒ y × z = 400000

Dividing the second equation by the first equation gives: (y × z) / (x × y) = 400000 / 200000 z / x = 2 z = 2x

1322Mathematics
The value of 9.377 - [3 + 0.5 × (3.1 - 2.3 × 1.02)] is:
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Answer: (C) 6

Explanation

Following the BODMAS rule, evaluate the innermost bracket first: 2.3 × 1.02 = 2.346 3.1 - 2.346 = 0.754 0.5 × 0.754 = 0.377

Next, evaluate the square bracket: 3 + 0.377 = 3.377

Finally, subtract this result from 9.377: 9.377 - 3.377 = 6

1323Mathematics
A steamer goes downstream and covers the distance between two ports in 6 h. It covers the same distance upstream in 8 h. If the speed of the stream is 3km / h , then the speed of the stream in still water is:
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Answer: (B) 21km / h

Explanation

Let the speed of the steamer in still water be v km/h. The speed of the stream is given as u = 3 km/h.

Downstream speed = v + 3 Upstream speed = v - 3

Since Distance = Speed × Time and the distance covered both downstream and upstream is the same:

6 × (v + 3) = 8 × (v - 3) 6v + 18 = 8v - 24 2v = 42 v = 21 km/h

1324Mathematics
The ratio of the HCF to the LCM of the numbers √(64) and 16 is:
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Answer: (A) 1:2

Explanation

First, evaluate the given radical expression: √64 = 8

Thus, the two numbers are 8 and 16.

For any two positive integers where one number completely divides the other, the smaller number is their Highest Common Factor (HCF) and the larger number is their Least Common Multiple (LCM).

Since 8 divides 16 completely: HCF(8, 16) = 8 LCM(8, 16) = 16

The required ratio of HCF to LCM is: HCF : LCM = 8 : 16 = 1 : 2

1325Mathematics
If (√7 - 1)/(√7 + 1) - (√7 + 1)/(√7 - 1) = a + b√7 , then the values of a and b are:
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Answer: (A) a = 0 and b = ⁽⁻²⁾⁄₃

Explanation

Using the algebraic identity (x - y)/(x + y) - (x + y)/(x - y) = -4xy / (x² - y²):

Substituting x = √7 and y = 1 gives: [(√7 - 1)/(√7 + 1)] - [(√7 + 1)/(√7 - 1)] = -4(√7)(1) / ((√7)² - 1²)

Simplifying the expression: -4√7 / (7 - 1) = -4√7 / 6 = -2√7 / 3

Equating this result to a + b√7: 0 + (-2/3)√7 = a + b√7

Comparing corresponding rational and irrational terms gives a = 0 and b = -2/3.

1326Mathematics
When 30% of a number is added to another number, the second number becomes 140% of itself. The ratio of the first number to the second number is:
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Answer: (D) 4 : 3

Explanation

Let the first number be x and the second number be y.

According to the given condition: y + (30/100)x = (140/100)y

Subtracting y from both sides: (30/100)x = (140/100)y - y (30/100)x = (40/100)y 30x = 40y 3x = 4y

Rearranging to find the ratio of the first number to the second number: x / y = 4 / 3 = 4 : 3

1327Mathematics
If x⁴ + (1)/(x⁴) = 6239 , and x > 0 , then the value of x + ¹⁄ₓ is:
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Answer: (A) 9

Explanation

Using the algebraic identity: (x² + 1/x²)² = x⁴ + 1/x⁴ + 2

Substituting x⁴ + 1/x⁴ = 6239: (x² + 1/x²)² = 6239 + 2 = 6241 x² + 1/x² = √6241 = 79

Next, applying the identity for (x + 1/x): (x + 1/x)² = x² + 1/x² + 2 (x + 1/x)² = 79 + 2 = 81

Since x > 0, taking the positive square root gives: x + 1/x = √81 = 9

1328Mathematics
If one- ninth of one- eighth of one- seventh of one- fifth of one- fourth of one- third of one- half of a number is 32, then the number is:
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Answer: (C) 1935360

Explanation

Let the required number be x.

According to the given condition: (1/9) × (1/8) × (1/7) × (1/5) × (1/4) × (1/3) × (1/2) × x = 32

Multiplying the denominators: 9 × 8 × 7 × 5 × 4 × 3 × 2 = 60,480

So, x / 60,480 = 32

x = 32 × 60,480 = 1,935,360

1329Mathematics
On what sum will the compound interest, at the rate of 12½% per annum for 2 years compounded annually, be ₹6,800?
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Answer: (B) (25,600)/(2)

Explanation

Rate of interest = 12½% = ⅛ per annum Time = 2 years

Ratio of Principal to Amount for 1 year = 8 : 9 Ratio of Principal to Amount for 2 years = 8² : 9² = 64 : 81

Compound Interest = 81 - 64 = 17 units

Given that 17 units = ₹6,800 1 unit = 6,800 ÷ 17 = ₹400

Principal = 64 units = 64 × 400 = ₹25,600

1330Mathematics
If a - b = 5 and a³ -b³ = 5 , then what will be the value of ab ?
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Answer: (C) -8

Explanation

Using the algebraic identity: a³ - b³ = (a - b)³ + 3ab(a - b)

Substituting the given values a - b = 5 and a³ - b³ = 5 into the identity: 5 = 5³ + 3ab(5) 5 = 125 + 15ab

Rearranging the equation to solve for ab: 15ab = 5 - 125 15ab = -120 ab = -120 / 15 ab = -8

1331Mathematics
A and B together can finish a task in 24 days. They worked at it for 18 days and then C finished the remaining work in 10 days. In how many days can A, B and C together finish the task?
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Answer: (B) 15 days

Explanation

Work done by A and B in 1 day = 1/24 Work done by A and B in 18 days = 18/24 = 3/4

Remaining work = 1 - 3/4 = 1/4

Since C finishes 1/4 of the work in 10 days: Work done by C in 1 day = (1/4) ÷ 10 = 1/40

Combined 1-day work of A, B, and C = 1/24 + 1/40 = (5 + 3)/120 = 8/120 = 1/15

Time taken by A, B, and C working together = 1 ÷ (1/15) = 15 days.

1332Mathematics
A bag contains balls numbered 1, 2, 3, ......... 30. One ball is drawn from the bag at random. What is the probability that the number on the ball drawn is divisible by 4 or 6?
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Answer: (D) 1/3

Explanation

Total outcomes n(S) = 30.

By the Principle of Inclusion-Exclusion, the number of favorable outcomes divisible by 4 or 6 is given by: n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

The count of numbers divisible by 4 is n(A) = ⌊30/4⌋ = 7. The count of numbers divisible by 6 is n(B) = ⌊30/6⌋ = 5. The count of numbers divisible by both 4 and 6 (multiples of LCM(4, 6) = 12) is n(A ∩ B) = ⌊30/12⌋ = 2.

Favorable outcomes = 7 + 5 - 2 = 10.

Probability = Favorable outcomes / Total outcomes = 10 / 30 = 1/3.

1333Mathematics
A father is twice as old as his son. Twenty years ago, the age of the father was 12 times his son's age at that time. Difference in the present ages (in years) of the father and son is:
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Answer: (D) 22

Explanation

Let the present age of the son be x years. Then, the present age of the father is 2x years.

Twenty years ago, their ages were (x - 20) and (2x - 20) respectively.

According to the given condition: 2x - 20 = 12 × (x - 20) 2x - 20 = 12x - 240 10x = 220 x = 22

The present age of the son is 22 years, and the present age of the father is 2 × 22 = 44 years.

The difference in their present ages is 44 - 22 = 22 years.

1334Mathematics
A man sells a washing machine for ₹21,600 gaining thereby 8% . At what price should he sell it to gain 20% ?
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Answer: (A) ₹24,000

Explanation

Selling Price₂ = Selling Price₁ × (100 + Gain₂%) / (100 + Gain₁%)

Substituting the given values: Selling Price₂ = 21,600 × 120 / 108 = 200 × 120 = ₹24,000

1335Mathematics
Solve the following. 2 - [(-5) × (-4) - (3 - 5)] = ?
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Answer: (A) -20

Explanation

Evaluating the given mathematical expression using the order of operations (BODMAS):

Step 1: Evaluate the terms inside the innermost parentheses: (-5) × (-4) = 20 (3 - 5) = -2

Step 2: Solve the expression inside the square brackets: [20 - (-2)] = 20 + 2 = 22

Step 3: Subtract this result from the main expression: 2 - 22 = -20

1336Mathematics
The number of prime numbers less than 20 is:
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Answer: (D) 8

Explanation

A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. The prime numbers less than 20 are 2, 3, 5, 7, 11, 13, 17, and 19. Counting these numbers gives a total of 8 prime numbers.

1337Mathematics
The least multiple of 14 which when divided by 6, 8, 12 leaves remainder 4, 6 and 10 respectively, is:
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Answer: (A) 70

Explanation

The difference between each divisor and its corresponding remainder is constant: 6 - 4 = 2 8 - 6 = 2 12 - 10 = 2

LCM(6, 8, 12) = 24.

The required number must be of the form N = 24k - 2, where k is a positive integer.

Testing integer values for k: For k = 1: N = 24(1) - 2 = 22 (not a multiple of 14) For k = 2: N = 24(2) - 2 = 46 (not a multiple of 14) For k = 3: N = 24(3) - 2 = 70, which is a multiple of 14 (14 × 5 = 70).

1338Mathematics
Ages of Keshav and Vipul are in the ratio 9 : 10. Twelve years hence their ages will be in the ratio 13 : 14. Keshav's present age is:
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Answer: (D) 27 years

Explanation

The change in age over 12 years corresponds to an increase of (13 - 9) = 4 ratio units for Keshav and (14 - 10) = 4 ratio units for Vipul.

4 ratio units = 12 years 1 ratio unit = 3 years

Keshav's present age = 9 × 3 = 27 years.

1339Mathematics
For a given fraction, how many equivalent fractions can be formed?
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Answer: (A) Infinite

Explanation

An equivalent fraction is obtained by multiplying or dividing both the numerator and the denominator of a fraction by the same non-zero integer. Since there are infinitely many non-zero integers (such as 1, 2, 3, 4, ...), multiplying the numerator and denominator by each distinct non-zero integer generates a unique equivalent fraction each time. Therefore, infinitely many equivalent fractions can be formed for any given fraction.

1340Mathematics
The HCF of 15,25 and 42 is:
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Answer: (A) 1

Explanation

To find the Highest Common Factor (HCF) of 15, 25, and 42, find the prime factorizations of each number: 15 = 3 × 5 25 = 5² 42 = 2 × 3 × 7

Since no prime factor is common to all three numbers, the only common factor is 1. Thus, the HCF is 1.

1341Mathematics
A can finish a task in 18 days and B can finish the same task in 15 days. They started working together but B left 7 days before the task finished. For how many days did A and B work together?
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Answer: (D) 5

Explanation

Let total work be LCM(18, 15) = 90 units. Efficiency of A = 90 / 18 = 5 units/day Efficiency of B = 90 / 15 = 6 units/day

Since B left 7 days before completion, A worked alone for the final 7 days. Work done by A in the last 7 days = 7 × 5 = 35 units. Remaining work done by A and B together = 90 - 35 = 55 units.

Number of days A and B worked together = 55 / (5 + 6) = 55 / 11 = 5 days.

1342Mathematics
If the sum of the squares of roots of the polynomial x² +8x + 15k is 34, then what will be the value of k
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Answer: (A) 1

Explanation

For a quadratic polynomial x² + bx + c with roots α and β, the sum of roots is α + β = -b and the product of roots is αβ = c.

Here, α + β = -8 and αβ = 15k.

Using the identity α² + β² = (α + β)² - 2αβ: 34 = (-8)² - 2(15k) 34 = 64 - 30k 30k = 30 k = 1

1343Mathematics
One third of one fourth of two seventh of 12 is:
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Answer: (A) 2 7

Explanation

Using the direct mathematical translation of "of" as multiplication:

Value = ⅓ × ¼ × ²⁄₇ × 12

Simplifying the expression: Value = (1 × 1 × 2 × 12) / (3 × 4 × 7) = 24 / 84 = ²⁄₇

1344Mathematics
A bag contains balls numbered 1, 2, 3, .......... 20. One ball is drawn from the bag at random. What is the probability that the number on the ball drawn is divisible by 3 or 5?
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Answer: (C) ⁹⁄₂₀

Explanation

The total number of outcomes is 20.

Using the Inclusion-Exclusion Principle, the number of balls divisible by 3 or 5 is given by: n(3 or 5) = ⌊20/3⌋ + ⌊20/5⌋ - ⌊20/15⌋ = 6 + 4 - 1 = 9

Probability = Favorable outcomes / Total outcomes = 9/20

1345Mathematics
Solve the following. 17.6 + 1.76 + 0.176 + 0.0176 + 0.00176 = ?
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Answer: (D) 19.55536

Explanation

Summing the given numbers by aligning their decimal places:

17.60000

  • 1.76000 = 19.36000
  • 0.17600 = 19.53600
  • 0.01760 = 19.55360
  • 0.00176 = 19.55536
1346Mathematics
A train travelling at a speed of 84 km/h passes a post in 9 seconds and a platform in 30 seconds. What is the length of the platform?
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Answer: (D) 490 m

Explanation

Speed of train in m/s = 84 × (5/18) = 70/3 m/s

The train takes 9 seconds to pass a post, which corresponds to covering its own length. To cross the platform, it takes 30 seconds.

Time taken to cover the length of the platform alone = 30 - 9 = 21 seconds

Length of the platform = Speed × Time = (70/3) × 21 = 490 m

1347Mathematics
A fruit seller sells 16 oranges for ₹42 thereby gaining 25%. How many oranges did he buy for ₹42?
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Answer: (A) 20

Explanation

Since total money remains constant at ₹42, quantity is inversely proportional to price. A gain of 25% means CP : SP = 100 : 125 = 4 : 5.

Therefore, Quantity Bought : Quantity Sold = 5 : 4.

Given Quantity Sold = 16, Quantity Bought = (5 / 4) × 16 = 20 oranges.

1348Mathematics
65% of the first number is 130 and 40% of the second number is 100. The ratio of the first number to the second number is:
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Answer: (B) 4:5

Explanation

Let the first number be x and the second number be y.

Given: 65% of x = 130 (65/100) × x = 130 x = (130 × 100) / 65 = 200

40% of y = 100 (40/100) × y = 100 y = (100 × 100) / 40 = 250

The ratio of the first number to the second number is x : y = 200 : 250 = 4 : 5.

1349Mathematics
What is the LCM of ⅙,¼ and ½ ?
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Answer: (A) ½

Explanation

LCM of fractions = (LCM of numerators) ÷ (HCF of denominators)

For the fractions 1/6, 1/4, and 1/2: LCM of numerators (1, 1, 1) = 1 HCF of denominators (6, 4, 2) = 2

LCM = 1/2

1350Mathematics
Abdul earned ₹12,600 as simple interest on ₹70,000 at the rate of 12% per annum in a certain period. Find the period.
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Answer: (C) ³⁄₂ years

Explanation

Using the formula for Simple Interest, SI = (P × R × T) / 100:

12,600 = (70,000 × 12 × T) / 100 12,600 = 8,400 × T T = 12,600 / 8,400 = 3/2 years

Answer key

Tap a number to jump to that question.

  1. 1301C
  2. 1302B
  3. 1303C
  4. 1304A
  5. 1305A
  6. 1306B
  7. 1307D
  8. 1308A
  9. 1309C
  10. 1310B
  11. 1311D
  12. 1312C
  13. 1313C
  14. 1314A
  15. 1315D
  16. 1316D
  17. 1317B
  18. 1318A
  19. 1319B
  20. 1320B
  21. 1321A
  22. 1322C
  23. 1323B
  24. 1324A
  25. 1325A
  26. 1326D
  27. 1327A
  28. 1328C
  29. 1329B
  30. 1330C
  31. 1331B
  32. 1332D
  33. 1333D
  34. 1334A
  35. 1335A
  36. 1336D
  37. 1337A
  38. 1338D
  39. 1339A
  40. 1340A
  41. 1341D
  42. 1342A
  43. 1343A
  44. 1344C
  45. 1345D
  46. 1346D
  47. 1347A
  48. 1348B
  49. 1349A
  50. 1350C

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