RRB NTPC2021MathematicsPage 25 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1201–1250 of 1,785, each with the correct answer and a step-by-step explanation.

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1201Mathematics
If 25³^.⁸× 5⁴^.²÷ 5⁶^.⁴ = 25ˣ, then the value of x is:
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Answer: (A) 2.7

Explanation

Convert all terms to base 5 using the exponent rules (aᵐ)ⁿ = aᵐⁿ and aᵐ × aⁿ ÷ aᵖ = aᵐ⁺ⁿ⁻ᵖ:

Left side: 25³.⁸ × 5⁴.² ÷ 5⁶.⁴ = (5²)³.⁸ × 5⁴.² ÷ 5⁶.⁴ = 5⁷.⁶ × 5⁴.² ÷ 5⁶.⁴ = 5⁷.⁶ ⁺ ⁴.² ⁻ ⁶.⁴ = 5⁵.⁴

Right side: 25ˣ = (5²)ˣ = 5²ˣ

Equating the powers of 5: 2x = 5.4 x = 2.7

1202Mathematics
What is the full form of GEO?
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Answer: (C) Geostationary Earth Orbit

Explanation

GEO stands for Geostationary Earth Orbit, which is a circular orbit positioned approximately 35,786 kilometers above Earth's equator. Satellites placed in this orbit revolve around the Earth with an orbital period equal to Earth's rotational period of 23 hours, 56 minutes, and 4 seconds. Consequently, the satellite moves in the same direction and at the same rate as Earth rotates, making it appear stationary relative to a fixed position on the Earth's surface. This makes it ideal for telecommunications, weather monitoring, and satellite broadcasting.

1203Mathematics
The maximum length of a stick that can be kept in a rectangular box of dimensions 15cm× 8cm× 6cm is:
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Answer: (B) 5√(13)cm

Explanation

The maximum length of a stick that can fit inside a rectangular box (cuboid) is given by the length of its space diagonal:

Diagonal = √(l² + b² + h²)

Given dimensions l = 15 cm, b = 8 cm, and h = 6 cm:

Diagonal = √(15² + 8² + 6²) Diagonal = √(225 + 64 + 36) Diagonal = √325 Diagonal = √(25 × 13) = 5√13 cm

1204Mathematics
The sides of a triangle are in the ratio of ⅖:⅓:⅗ and its perimeter is 110~cm . The length of the shortest side is:
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Answer: (A) 27.5 cm

Explanation

To convert the given fractional ratio 2/5 : 1/3 : 3/5 into integers, multiply each term by the LCM of the denominators, which is 15: (2/5 × 15) : (1/3 × 15) : (3/5 × 15) = 6 : 5 : 9

The total number of ratio parts = 6 + 5 + 9 = 20 parts.

Since 5 is the smallest ratio term, the length of the shortest side = (5 / 20) × 110 = 27.5 cm.

1205Mathematics
The ratio of two numbers is 5 : 6 and their HCF is 6. Their LCM is:
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Answer: (C) 180

Explanation

For two numbers in the ratio a : b where a and b are co-prime, the relationship between HCF and LCM is given by the formula:

LCM = HCF × a × b

Given the ratio a : b = 5 : 6 and HCF = 6:

LCM = 6 × 5 × 6 = 180

1206Mathematics
The least perfect square number completely divisible by 4, 5, 9 and 12 is:
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Answer: (A) 900

Explanation

To find the least perfect square completely divisible by 4, 5, 9, and 12, first find the LCM of the numbers by prime factorization:

4 = 2² 5 = 5¹ 9 = 3² 12 = 2² × 3¹

LCM(4, 5, 9, 12) = 2² × 3² × 5¹ = 180

For a number to be a perfect square, all prime factors must have even exponents. In 180, the prime factor 5 appears with an odd power (5¹). Multiplying 180 by 5 yields:

2² × 3² × 5² = 900

1207Mathematics
Atulit has 100 apples. He gave 10% of the apples to Amar, 15% of the apples to Kenhav and ⅖ th of the apples to Rinku. How many apples are left with Atulit after distribution?
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Answer: (D) 35

Explanation

Initial number of apples = 100

Apples given to Amar = 10% of 100 = 10 Apples given to Kenhav = 15% of 100 = 15 Apples given to Rinku = (2/5) × 100 = 40

Total apples distributed = 10 + 15 + 40 = 65

Apples left with Atulit = 100 - 65 = 35

1208Mathematics
A rectangular carpet has an area of 168 m² and a perimeter of 62 m . The length of its diagonal is:
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Answer: (B) 25 m

Explanation

For a rectangle with length l and width w: Perimeter = 2(l + w) = 62 m, which gives l + w = 31 m. Area = l × w = 168 m².

The diagonal d is given by the formula d = √(l² + w²).

Using the algebraic identity (l + w)² = l² + w² + 2lw: l² + w² = (l + w)² - 2lw l² + w² = 31² - 2 × 168 = 961 - 336 = 625

Substituting this into the diagonal formula: d = √625 = 25 m.

1209Mathematics
Solve the following. If x - ¹⁄ₓ = 3 , then x³ - (1)/(x³) = ?
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Answer: (B) 36

Explanation

Using the algebraic identity (x - 1/x)³ = x³ - 1/x³ - 3(x - 1/x), we can express x³ - 1/x³ as:

x³ - 1/x³ = (x - 1/x)³ + 3(x - 1/x)

Substituting the given value x - 1/x = 3 into the formula:

x³ - 1/x³ = 3³ + 3(3) = 27 + 9 = 36

1210Mathematics
Four different mobile devices make a beep sound after every 30 min, 45 min, 1 h and 1½h respectively. All the mobiles beeped together at 10.45 a.m. They will again beep together at:
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Answer: (C) 1.45 p.m.

Explanation

Convert all time intervals into minutes: 30 min, 45 min, 1 h = 60 min, and 1½ h = 90 min.

To find when all four devices will beep together again, calculate the Least Common Multiple (LCM) of the four time intervals: LCM(30, 45, 60, 90) = 180 minutes

Converting 180 minutes into hours: 180 / 60 = 3 hours

Adding 3 hours to the initial time of 10.45 a.m.: 10.45 a.m. + 3 hours = 1.45 p.m.

1211Mathematics
The value of a car depreciates at the rate of 12% per annum. Its present value is 7,74,400. What was the value of the car 2 years ago?
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Answer: (D) 10,00,000

Explanation

Using the depreciation formula: Present Value = P × (1 - r/100)ⁿ

where P is the value of the car 2 years ago, r = 12%, and n = 2 years.

7,74,400 = P × (1 - 12/100)² 7,74,400 = P × (88/100)² 7,74,400 = P × (22/25)² 7,74,400 = P × (484/625)

P = (7,74,400 × 625) / 484 P = 1600 × 625 = 10,00,000

1212Mathematics
If √(40) = 6.3245, then what will be the value of √(⁸⁄₅) ?
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Answer: (A) 1.2649

Explanation

To find the value of √(8/5), multiply the numerator and denominator under the square root by 5 to introduce 40 into the expression:

√(8/5) = √((8 × 5) / (5 × 5)) = √(40/25) = √(40) / 5

Substituting the given value of √(40) = 6.3245:

√(8/5) = 6.3245 / 5 = 1.2649

1213Mathematics
When 1.25 is written in simplest fraction form, the difference between the numerator and the denominator is:
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Answer: (C) 1

Explanation

The decimal 1.25 can be written as the fraction 125/100. Dividing both the numerator and denominator by their greatest common divisor, 25, gives the simplest fraction form:

1.25 = 125/100 = 5/4

Here, the numerator is 5 and the denominator is 4. The difference between the numerator and denominator is:

5 - 4 = 1

1214Mathematics
Simplify. 5 + 2 × 3 ÷ (3 × 2) × 3
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Answer: (A) 8

Explanation

Using the BODMAS rule (Brackets, Division/Multiplication from left to right, Addition):

First, evaluate the expression inside the brackets: (3 × 2) = 6

This simplifies the expression to: 5 + 2 × 3 ÷ 6 × 3

Next, execute the multiplication and division sequentially from left to right: 2 × 3 = 6 6 ÷ 6 = 1 1 × 3 = 3

Finally, perform the addition: 5 + 3 = 8

1215Mathematics
If tan θ = 1 ( θ an acute angle) then the value of 2 sin θ cos θ - cos e c² θ is:
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Answer: (A) -1

Explanation

Given tan θ = 1 for an acute angle θ, θ = 45°.

Substituting θ = 45° into the expression: 2 sin 45° cos 45° - cosec² 45° = sin 90° - cosec² 45° = 1 - (√2)² = 1 - 2 = -1

1216Mathematics
An amount doubles itself on simple interest in 4 years. What is the per cent per annum rate of interest?
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Answer: (B) 25%

Explanation

When an amount doubles itself under simple interest, the interest earned (SI) is equal to the principal (P).

Using the simple interest formula SI = (P × R × T) / 100: P = (P × R × 4) / 100 1 = (R × 4) / 100 R = 100 / 4 = 25% per annum

1217Mathematics
Two cars cover a certain distance by moving at speeds of 45km / h and 50km / h respectively.Find the distance travelled when one car takes 32 minutes more than the other to cover the distance.
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Answer: (D) 240km

Explanation

When a fixed distance is covered at two different speeds S₁ and S₂, the distance D is given by the formula:

D = (S₁ × S₂ / |S₁ - S₂|) × Δt

Given S₁ = 45 km/h, S₂ = 50 km/h, and time difference Δt = 32 minutes = 32/60 hours = 8/15 hours.

Substituting these values into the formula:

D = (45 × 50 / 5) × (8 / 15) D = 450 × (8 / 15) D = 240 km

1218Mathematics
A can complete a piece of work in 24 days. He worked for 21 days and then B finished the remaining work in 5 days. In how many days can A and B together finish the work?
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Answer: (C) 15 days

Explanation

A's 1-day work = 1/24.

Work done by A in 21 days = 21/24 = 7/8. Remaining work = 1 - 7/8 = 1/8.

B finishes the remaining 1/8 work in 5 days, so B's 1-day work = (1/8) ÷ 5 = 1/40.

Combined 1-day work of A and B = 1/24 + 1/40 = (5 + 3)/120 = 8/120 = 1/15.

Time taken by A and B together to complete the work = 1 ÷ (1/15) = 15 days.

1219Mathematics
If (4y - 1) and (y + 4) both are factors of py² + 15y - q then:
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Answer: (B) p = q

Explanation

Multiplying the given factors: (4y - 1)(y + 4) = 4y² + 16y - y - 4 = 4y² + 15y - 4

Comparing the coefficients of 4y² + 15y - 4 with py² + 15y - q: p = 4 -q = -4 ⇒ q = 4

Since p = 4 and q = 4, it follows that p = q.

1220Mathematics
Simplify. 4√(0.000081)
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Answer: (D) 0.036

Explanation

√(0.000081) = 0.009, since 0.009 × 0.009 = 0.000081.

Multiplying this value by 4 gives: 4 × 0.009 = 0.036

1221Mathematics
If circumference and area of a circle are numerically equal then radius of the circle is:
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Answer: (B) 2 units

Explanation

Circumference of a circle is 2πr and area is πr², where r is the radius. Equating the numerical values of both gives:

2πr = πr²

Dividing both sides by πr yields r = 2 units.

1222Mathematics
Two numbers are in the ratio 3:2. If 8 and 6 are subtracted from the first and the second number respectively, the ratio becomes 8:5. The numbers are:
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Answer: (B) 24,16

Explanation

Let the two numbers be 3x and 2x.

According to the given condition: (3x - 8) / (2x - 6) = 8 / 5

Cross-multiplying gives: 5(3x - 8) = 8(2x - 6) 15x - 40 = 16x - 48 x = 8

Therefore, the numbers are: First number = 3 × 8 = 24 Second number = 2 × 8 = 16

1223Mathematics
Find the value of x if, 20% of 75 = 225 - x% of 420.
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Answer: (A) 50

Explanation

20% of 75 = (20 / 100) × 75 = 15

Substituting this into the given equation: 15 = 225 - (x / 100) × 420

Rearranging the terms: (x / 100) × 420 = 225 - 15 4.2x = 210 x = 210 / 4.2 = 50

1224Mathematics
Six years from now, Kirti's age will be twice the age of her brother Kunal, but 4 years ago she was four times as old as Kunal was then. Find the present age of Kunal.
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Answer: (A) 9 years

Explanation

Let the present ages of Kunal and Kirti be x and y years, respectively.

According to the given conditions: y + 6 = 2(x + 6) ⇒ y = 2x + 6 y - 4 = 4(x - 4) ⇒ y = 4x - 12

Equating the two expressions for y: 2x + 6 = 4x - 12 2x = 18 x = 9

1225Mathematics
What is the difference between ⅗ of 200 and ½ of 300?
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Answer: (D) 30

Explanation

First value = (3/5) × 200 = 120 Second value = (1/2) × 300 = 150

Difference = 150 - 120 = 30

1226Mathematics
By which number should 2⅕ be multiplied to get 5⅖ ?
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Answer: (A) 2⁵⁄₁₁

Explanation

Convert the given mixed fractions into improper fractions: 2(1/5) = 11/5 5(2/5) = 27/5

Let x be the required multiplier. (11/5) × x = 27/5 x = (27/5) ÷ (11/5) x = 27/11 = 2(5/11)

1227Mathematics
In triangle ABC, the angles are in the ratio of 2:3:4. The measure of the biggest angle in degrees is:
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Answer: (C) 80°

Explanation

Sum of the interior angles of a triangle is always 180°. Given the ratio of the angles as 2 : 3 : 4, the total number of ratio parts is 2 + 3 + 4 = 9.

Value of 1 ratio part = 180° / 9 = 20°.

The largest angle corresponds to the largest ratio part, 4, so its measure is 4 × 20° = 80°.

1228Mathematics
Find the least multiple of 7 which when divided by 6, 8 and 12 leaves 1 as remainder.
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Answer: (B) 49

Explanation

The least common multiple (LCM) of 6, 8, and 12 is 24.

Any number that leaves a remainder of 1 when divided by 6, 8, and 12 is of the form 24k + 1, where k is a positive integer.

For k = 1: 24(1) + 1 = 25, which is not a multiple of 7. For k = 2: 24(2) + 1 = 49, which is divisible by 7 (49 = 7 × 7).

1229Mathematics
A sells an article to B at a profit of 20% and B sells it to C at a profit of 20%. If C pays ₹360 for it, what was the cost price for A?
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Answer: (C) ₹250

Explanation

Cost Price for A = Final Price / ((1 + Profit₁%)(1 + Profit₂%))

Cost Price for A = 360 / (1.20 × 1.20) = 360 / 1.44 = ₹250.

1230Mathematics
A bag contains cards numbered between 33 and 92. If one card is drawn from the bag, the probability that the number on the drawn card is a perfect square is:
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Answer: (C) 1/15

Explanation

Total outcomes = (92 - 33) + 1 = 60 cards.

The perfect squares in the range 33 to 92 are 36 (6²), 49 (7²), 64 (8²), and 81 (9²). Number of favorable outcomes = 4.

Probability = Favorable outcomes / Total outcomes = 4 / 60 = 1 / 15.

1231Mathematics
LCM of 30, 40 and 45 is:
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Answer: (D) 360

Explanation

Prime factorization of the given numbers: 30 = 2 × 3 × 5 40 = 2³ × 5 45 = 3² × 5

The LCM is the product of the highest power of each prime factor involved: LCM(30, 40, 45) = 2³ × 3² × 5 = 8 × 9 × 5 = 360

1232Mathematics
In what time will ₹3,200 invested at 10% per annum compounded quarterly become ₹3,362?
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Answer: (B) 1/2 year

Explanation

The formula for compound amount with quarterly compounding is A = P × (1 + R/400)⁽4t), where P is the principal, A is the final amount, R is the annual interest rate, and t is the time in years.

Substituting P = 3200, A = 3362, and R = 10 into the formula: 3362 = 3200 × (1 + 10/400)⁽4t) 3362 / 3200 = (41/40)⁽4t) 1681 / 1600 = (41/40)⁽4t) (41/40)² = (41/40)⁽4t)

Equating exponents: 4t = 2 t = ½ year

1233Mathematics
A, B and C together can do a piece of work in 14 days, whereas C alone can do the same work in 42 days. How long will A and B together take to finish it?
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Answer: (C) 21 days

Explanation

Work done by A, B, and C together in 1 day = 1/14 Work done by C alone in 1 day = 1/42

Work done by A and B together in 1 day = 1/14 - 1/42 = (3 - 1)/42 = 2/42 = 1/21

Alternatively, using the combined work formula: Time taken = (14 × 42) / (42 - 14) = 588 / 28 = 21 days

1234Mathematics
For a = - 5 and b = 5 , value of a² - b² is:
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Answer: (B) 0

Explanation

Using direct substitution into the expression:

a² - b² = (-5)² - (5)²

Since (-5)² = 25 and 5² = 25, substituting these values gives:

a² - b² = 25 - 25 = 0

Alternatively, using the algebraic identity a² - b² = (a + b)(a - b):

a² - b² = (-5 + 5)(-5 - 5) = 0 × (-10) = 0

1235Mathematics
What is the value of 8x³ + 18xy + y³ - 27 when 2x + y - 3 = 0 .
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Answer: (C) 0

Explanation

Using the algebraic identity, if a + b + c = 0, then a³ + b³ + c³ - 3abc = 0.

Let a = 2x, b = y, and c = -3.

Given that a + b + c = 2x + y - 3 = 0, we substitute these into the identity:

a³ + b³ + c³ - 3abc = (2x)³ + y³ + (-3)³ - 3(2x)(y)(-3) = 8x³ + y³ - 27 + 18xy = 8x³ + 18xy + y³ - 27 = 0

1236Mathematics
Two friends received a bonus of ₹2,000 each in their bank accounts. They already have ₹47,000 and ₹54,000 in their respective bank accounts. Ratio of the amounts in their respective accounts will be:
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Answer: (A) 7 : 8

Explanation

New amount in the first friend's account = ₹47,000 + ₹2,000 = ₹49,000 New amount in the second friend's account = ₹54,000 + ₹2,000 = ₹56,000

Ratio = 49,000 : 56,000 = 49 : 56

Dividing both terms by their greatest common divisor (7): 49 ÷ 7 = 7 and 56 ÷ 7 = 8, giving the simplified ratio 7 : 8.

1237Mathematics
Kings and Queens of black colour are taken out from a deck of 52 playing cards. A card is drawn from the remaining well- shuffled cards. Probability of getting a spade card is:
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Answer: (C) 11/48

Explanation

Total cards in a standard deck = 52. Number of black Kings and Queens removed = 2 Kings (Spades, Clubs) + 2 Queens (Spades, Clubs) = 4 cards. Remaining total cards = 52 - 4 = 48.

Original number of spade cards = 13. Since the King of Spades and Queen of Spades were removed, remaining spade cards = 13 - 2 = 11.

Probability of drawing a spade card = Favorable outcomes / Total outcomes = 11/48.

1238Mathematics
Select the option that gives decimal numbers 0.25, 1.24, 0.0882 and 2.67 arranged in ascending order.
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Answer: (A) 0.0882, 0.25, 1.24, 2.67

Explanation

Ascending order means arranging numbers from the smallest value to the largest value. Comparing the whole number parts and decimal place values: 0.0882 is the smallest since its whole number part is 0 and tenths digit is 0, followed by 0.25 which has a tenths digit of 2, then 1.24 which has a whole number part of 1, and finally 2.67 which has the largest whole number part of 2. The sequence from smallest to largest is 0.0882 < 0.25 < 1.24 < 2.67.

1239Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows. Marks (out of 50) Name of Students | Physics | Chemistry | Maths | English | Sanskrit A | 48 | 47 | 49 | 46 | 44 B | 29 | 33 | 22 | 15 | 30 C | 35 | 36 | 42 | 40 | 29 D | 46 | 49 | 48 | 48 | 40 E | 32 | 30 | 25 | 21 | 22 Which student got the lowest overall percentage of marks?
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Answer: (B) B

Explanation

Total maximum marks for 5 subjects = 5 × 50 = 250. Since the maximum possible marks are equal for all students, the student with the lowest total marks will have the lowest overall percentage.

Total marks obtained by B = 29 + 33 + 22 + 15 + 30 = 129 Overall percentage for B = (129 / 250) × 100 = 51.6%

With a total of 129 marks out of 250, student B secures the lowest total marks and consequently the lowest overall percentage of 51.6%.

1240Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows. Marks (out of 50) Name of Students | Physics | Chemistry | Maths | English | Sanskrit A | 48 | 47 | 49 | 46 | 44 B | 29 | 33 | 22 | 15 | 30 C | 35 | 36 | 42 | 40 | 29 D | 46 | 49 | 48 | 48 | 40 E | 32 | 30 | 25 | 21 | 22 What is the maximum overall percentage (average of percentages obtained in all subjects by any student) of marks obtained by any student among A, B, C, D and E?
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Answer: (B) 93.60%

Explanation

Total maximum marks for the 5 subjects = 5 × 50 = 250.

Calculating the total marks for student A gives 48 + 47 + 49 + 46 + 44 = 234, which is the highest total score among all students.

Maximum overall percentage = (234 / 250) × 100 = 93.60%.

1241Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows. Marks (out of 50) Name of Students | Physics | Chemistry | Maths | English A | 48 | 47 | 49 | 46 B | 29 | 33 | 22 | 15 C | 35 | 36 | 42 | 40 D | 46 | 49 | 48 | 48 E | 32 | 30 | 25 | 21 Which two students have the least difference of marks between them?
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Answer: (B) A and D

Explanation

To find the two students with the least difference in marks, calculate the total marks obtained by each student across all subjects:

Total marks of A = 48 + 47 + 49 + 46 = 190 Total marks of B = 29 + 33 + 22 + 15 = 99 Total marks of C = 35 + 36 + 42 + 40 = 153 Total marks of D = 46 + 49 + 48 + 48 = 191 Total marks of E = 32 + 30 + 25 + 21 = 108

The difference in total marks between A and D is 191 - 190 = 1, which is the smallest possible difference between any pair of students.

1242Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows. Marks (out of 50) Name of Students | Physics | Chemistry | Maths | English A | 48 | 47 | 49 | 46 B | 29 | 33 | 22 | 15 C | 35 | 36 | 42 | 40 D | 46 | 49 | 48 | 48 E | 32 | 30 | 25 | 21 If we rank students on the basis of all five subjects and then we rank them only on the basis of physics, chemistry and maths then what will happen to the arrangement of ranks in both cases?
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Answer: (C) Only the top two ranks will be different.

Explanation

Calculating total marks in all listed subjects for each student: D: 46 + 49 + 48 + 48 = 191 A: 48 + 47 + 49 + 46 = 190 C: 35 + 36 + 42 + 40 = 153 E: 32 + 30 + 25 + 21 = 108 B: 29 + 33 + 22 + 15 = 99

Rank order in all subjects: 1st D, 2nd A, 3rd C, 4th E, 5th B.

Calculating marks in Physics, Chemistry, and Maths only: A: 48 + 47 + 49 = 144 D: 46 + 49 + 48 = 143 C: 35 + 36 + 42 = 113 E: 32 + 30 + 25 = 87 B: 29 + 33 + 22 = 84

Rank order in PCM: 1st A, 2nd D, 3rd C, 4th E, 5th B.

Comparing both rankings, the 1st and 2nd positions swap between A and D, while the 3rd, 4th, and 5th positions (C, E, B) remain unchanged. Thus, only the top two ranks are different.

1243Mathematics
How will you write 4.14 hours in hours, minutes and seconds?
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Answer: (C) 4 hours, 8 minutes, 24 seconds

Explanation

To convert 4.14 hours into hours, minutes, and seconds:

Whole hours = 4 hours.

Convert the decimal part to minutes: 0.14 × 60 = 8.4 minutes, which gives 8 whole minutes.

Convert the remaining decimal part of the minute to seconds: 0.4 × 60 = 24 seconds.

Combining these gives 4 hours, 8 minutes, 24 seconds.

1244Mathematics
Two articles are sold by a trader. One of them is sold for 20% profit. Its selling price equals the cost price of the other article which is sold for 20% loss. Find the effective profit/loss percentage approximately.
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Answer: (A) 1.8% loss

Explanation

Let the cost price of the first article be CP1 = 100. Since it is sold at a 20% profit, its selling price is SP1 = 100 × 1.20 = 120.

The cost price of the second article equals SP1, so CP2 = 120. The second article is sold at a 20% loss, so its selling price is SP2 = 120 × 0.80 = 96.

Total Cost Price = CP1 + CP2 = 100 + 120 = 220. Total Selling Price = SP1 + SP2 = 120 + 96 = 216.

Total Loss = 220 - 216 = 4. Loss percentage = (4 ÷ 220) × 100 = 20/11 % ≈ 1.818% ≈ 1.8% loss.

1245Mathematics
If each side of square is increased by 20% then find the percentage change in its area.
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Answer: (B) 44%

Explanation

Percentage change in area when two successive dimensions increase by x% and y% is given by the formula: Net percentage change = x + y + (x × y) / 100

Since area of a square is side × side, both dimensions increase by 20%, so x = 20 and y = 20.

Substituting these values into the formula: Net percentage change = 20 + 20 + (20 × 20) / 100 = 40 + 400 / 100 = 40 + 4 = 44%

Alternatively, assuming initial side length as 10 units, initial area is 10 × 10 = 100 square units. With a 20% increase, the new side length becomes 12 units, making the new area 12 × 12 = 144 square units. The percentage increase is ((144 - 100) / 100) × 100 = 44%.

1246Mathematics
The largest number of four digits which, when divided by 6, 12 and 18 leaves the same remainder 5 in each case is:
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Answer: (C) 9977

Explanation

The LCM of 6, 12, and 18 is 36.

The largest four-digit number is 9999. Dividing 9999 by 36 yields a quotient of 277 and a remainder of 27 (9999 = 36 × 277 + 27).

Subtracting the remainder gives the largest four-digit number divisible by 36: 9999 - 27 = 9972

To find the number that leaves a remainder of 5 in each case, add 5 to this multiple: 9972 + 5 = 9977

1247Mathematics
The ratio of two numbers is 7:5 . Their HCF is 3, their LCM is ______.
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Answer: (C) 105

Explanation

For two numbers in the ratio a : b (where a and b are co-prime) and having a Highest Common Factor (HCF) of h, the Least Common Multiple (LCM) is given by the formula:

LCM = HCF × a × b

Substituting the given values into the formula:

LCM = 3 × 7 × 5 = 105

1248Mathematics
If (7 + 2√5)/(11 + 3√5) = a + b√5 , then:
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Answer: (D) a = ⁴⁷⁄₇₆; b = ¹⁄₇₆

Explanation

To rationalize the denominator of (7 + 2√5) / (11 + 3√5), multiply the numerator and denominator by the conjugate of the denominator, (11 - 3√5):

Numerator = (7 + 2√5)(11 - 3√5) = 77 - 21√5 + 22√5 - 30 = 47 + √5

Denominator = (11 + 3√5)(11 - 3√5) = 11² - (3√5)² = 121 - 45 = 76

Thus, the fraction simplifies to: (47 + √5) / 76 = (47 / 76) + (1 / 76)√5

Comparing this with a + b√5 yields: a = 47/76 and b = 1/76

1249Mathematics
A hemispherical bowl of internal radius of 12 cm contains a liquid. This liquid is to be filled into conical shaped small bottles of base diameter 3 cm and height 4 cm. How many same type of bottles will be needed to empty the bowl?
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Answer: (B) 384

Explanation

The volume of a hemisphere is (2/3)πR³ and the volume of a cone is (1/3)πr²h.

Number of bottles required = Volume of hemisphere / Volume of one conical bottle = [(2/3)πR³] / [(1/3)πr²h] = (2R³) / (r²h)

Given: Radius of hemisphere (R) = 12 cm Radius of cone (r) = 3/2 = 1.5 cm Height of cone (h) = 4 cm

Number of bottles = (2 × 12 × 12 × 12) / (1.5 × 1.5 × 4) = 3456 / 9 = 384

1250Mathematics
The price of a car is 6,25,000. It was insured to 80% of its price. The car was damaged completely, and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received?
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Answer: (D) ₹1,75,000

Explanation

Amount received as a percentage of the original car price = 80% × 90% = 72%

Percentage difference between car price and amount received = 100% - 72% = 28%

Difference in amount = 28% × ₹6,25,000 = 0.28 × 6,25,000 = ₹1,75,000

Answer key

Tap a number to jump to that question.

  1. 1201A
  2. 1202C
  3. 1203B
  4. 1204A
  5. 1205C
  6. 1206A
  7. 1207D
  8. 1208B
  9. 1209B
  10. 1210C
  11. 1211D
  12. 1212A
  13. 1213C
  14. 1214A
  15. 1215A
  16. 1216B
  17. 1217D
  18. 1218C
  19. 1219B
  20. 1220D
  21. 1221B
  22. 1222B
  23. 1223A
  24. 1224A
  25. 1225D
  26. 1226A
  27. 1227C
  28. 1228B
  29. 1229C
  30. 1230C
  31. 1231D
  32. 1232B
  33. 1233C
  34. 1234B
  35. 1235C
  36. 1236A
  37. 1237C
  38. 1238A
  39. 1239B
  40. 1240B
  41. 1241B
  42. 1242C
  43. 1243C
  44. 1244A
  45. 1245B
  46. 1246C
  47. 1247C
  48. 1248D
  49. 1249B
  50. 1250D

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