GEO stands for Geostationary Earth Orbit, which is a circular orbit positioned approximately 35,786 kilometers above Earth's equator. Satellites placed in this orbit revolve around the Earth with an orbital period equal to Earth's rotational period of 23 hours, 56 minutes, and 4 seconds. Consequently, the satellite moves in the same direction and at the same rate as Earth rotates, making it appear stationary relative to a fixed position on the Earth's surface. This makes it ideal for telecommunications, weather monitoring, and satellite broadcasting.
1203Mathematics
The maximum length of a stick that can be kept in a rectangular box of dimensions 15cm× 8cm× 6cm is:
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Answer: (B) 5√(13)cm
Explanation
The maximum length of a stick that can fit inside a rectangular box (cuboid) is given by the length of its space diagonal:
Diagonal = √(l² + b² + h²)
Given dimensions l = 15 cm, b = 8 cm, and h = 6 cm:
The sides of a triangle are in the ratio of ⅖:⅓:⅗ and its perimeter is 110~cm . The length of the shortest side is:
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Answer: (A) 27.5 cm
Explanation
To convert the given fractional ratio 2/5 : 1/3 : 3/5 into integers, multiply each term by the LCM of the denominators, which is 15:
(2/5 × 15) : (1/3 × 15) : (3/5 × 15) = 6 : 5 : 9
The total number of ratio parts = 6 + 5 + 9 = 20 parts.
Since 5 is the smallest ratio term, the length of the shortest side = (5 / 20) × 110 = 27.5 cm.
1205Mathematics
The ratio of two numbers is 5 : 6 and their HCF is 6. Their LCM is:
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Answer: (C) 180
Explanation
For two numbers in the ratio a : b where a and b are co-prime, the relationship between HCF and LCM is given by the formula:
LCM = HCF × a × b
Given the ratio a : b = 5 : 6 and HCF = 6:
LCM = 6 × 5 × 6 = 180
1206Mathematics
The least perfect square number completely divisible by 4, 5, 9 and 12 is:
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Answer: (A) 900
Explanation
To find the least perfect square completely divisible by 4, 5, 9, and 12, first find the LCM of the numbers by prime factorization:
4 = 2²
5 = 5¹
9 = 3²
12 = 2² × 3¹
LCM(4, 5, 9, 12) = 2² × 3² × 5¹ = 180
For a number to be a perfect square, all prime factors must have even exponents. In 180, the prime factor 5 appears with an odd power (5¹). Multiplying 180 by 5 yields:
2² × 3² × 5² = 900
1207Mathematics
Atulit has 100 apples. He gave 10% of the apples to Amar, 15% of the apples to Kenhav and ⅖ th of the apples to Rinku. How many apples are left with Atulit after distribution?
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Answer: (D) 35
Explanation
Initial number of apples = 100
Apples given to Amar = 10% of 100 = 10
Apples given to Kenhav = 15% of 100 = 15
Apples given to Rinku = (2/5) × 100 = 40
Total apples distributed = 10 + 15 + 40 = 65
Apples left with Atulit = 100 - 65 = 35
1208Mathematics
A rectangular carpet has an area of 168 m² and a perimeter of 62 m . The length of its diagonal is:
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Answer: (B) 25 m
Explanation
For a rectangle with length l and width w:
Perimeter = 2(l + w) = 62 m, which gives l + w = 31 m.
Area = l × w = 168 m².
The diagonal d is given by the formula d = √(l² + w²).
Substituting this into the diagonal formula:
d = √625 = 25 m.
1209Mathematics
Solve the following.
If x - ¹⁄ₓ = 3 , then x³ - (1)/(x³) = ?
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Answer: (B) 36
Explanation
Using the algebraic identity (x - 1/x)³ = x³ - 1/x³ - 3(x - 1/x), we can express x³ - 1/x³ as:
x³ - 1/x³ = (x - 1/x)³ + 3(x - 1/x)
Substituting the given value x - 1/x = 3 into the formula:
x³ - 1/x³ = 3³ + 3(3) = 27 + 9 = 36
1210Mathematics
Four different mobile devices make a beep sound after every 30 min, 45 min, 1 h and 1½h respectively. All the mobiles beeped together at 10.45 a.m. They will again beep together at:
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Answer: (C) 1.45 p.m.
Explanation
Convert all time intervals into minutes: 30 min, 45 min, 1 h = 60 min, and 1½ h = 90 min.
To find when all four devices will beep together again, calculate the Least Common Multiple (LCM) of the four time intervals:
LCM(30, 45, 60, 90) = 180 minutes
When 1.25 is written in simplest fraction form, the difference between the numerator and the denominator is:
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Answer: (C) 1
Explanation
The decimal 1.25 can be written as the fraction 125/100. Dividing both the numerator and denominator by their greatest common divisor, 25, gives the simplest fraction form:
1.25 = 125/100 = 5/4
Here, the numerator is 5 and the denominator is 4. The difference between the numerator and denominator is:
5 - 4 = 1
1214Mathematics
Simplify.
5 + 2 × 3 ÷ (3 × 2) × 3
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Answer: (A) 8
Explanation
Using the BODMAS rule (Brackets, Division/Multiplication from left to right, Addition):
First, evaluate the expression inside the brackets:
(3 × 2) = 6
This simplifies the expression to:
5 + 2 × 3 ÷ 6 × 3
Next, execute the multiplication and division sequentially from left to right:
2 × 3 = 6
6 ÷ 6 = 1
1 × 3 = 3
Finally, perform the addition:
5 + 3 = 8
1215Mathematics
If tan θ = 1 ( θ an acute angle) then the value of 2 sin θ cos θ - cos e c² θ is:
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Answer: (A) -1
Explanation
Given tan θ = 1 for an acute angle θ, θ = 45°.
Substituting θ = 45° into the expression:
2 sin 45° cos 45° - cosec² 45° = sin 90° - cosec² 45°
= 1 - (√2)²
= 1 - 2
= -1
1216Mathematics
An amount doubles itself on simple interest in 4 years. What is the per cent per annum rate of interest?
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Answer: (B) 25%
Explanation
When an amount doubles itself under simple interest, the interest earned (SI) is equal to the principal (P).
Using the simple interest formula SI = (P × R × T) / 100:
P = (P × R × 4) / 100
1 = (R × 4) / 100
R = 100 / 4 = 25% per annum
1217Mathematics
Two cars cover a certain distance by moving at speeds of 45km / h and 50km / h respectively.Find the distance travelled when one car takes 32 minutes more than the other to cover the distance.
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Answer: (D) 240km
Explanation
When a fixed distance is covered at two different speeds S₁ and S₂, the distance D is given by the formula:
D = (S₁ × S₂ / |S₁ - S₂|) × Δt
Given S₁ = 45 km/h, S₂ = 50 km/h, and time difference Δt = 32 minutes = 32/60 hours = 8/15 hours.
Substituting these values into the formula:
D = (45 × 50 / 5) × (8 / 15)
D = 450 × (8 / 15)
D = 240 km
1218Mathematics
A can complete a piece of work in 24 days. He worked for 21 days and then B finished the remaining work in 5 days. In how many days can A and B together finish the work?
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Answer: (C) 15 days
Explanation
A's 1-day work = 1/24.
Work done by A in 21 days = 21/24 = 7/8.
Remaining work = 1 - 7/8 = 1/8.
B finishes the remaining 1/8 work in 5 days, so B's 1-day work = (1/8) ÷ 5 = 1/40.
Combined 1-day work of A and B = 1/24 + 1/40 = (5 + 3)/120 = 8/120 = 1/15.
Time taken by A and B together to complete the work = 1 ÷ (1/15) = 15 days.
1219Mathematics
If (4y - 1) and (y + 4) both are factors of py² + 15y - q then:
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Answer: (B) p = q
Explanation
Multiplying the given factors:
(4y - 1)(y + 4) = 4y² + 16y - y - 4 = 4y² + 15y - 4
Comparing the coefficients of 4y² + 15y - 4 with py² + 15y - q:
p = 4
-q = -4 ⇒ q = 4
Since p = 4 and q = 4, it follows that p = q.
1220Mathematics
Simplify.
4√(0.000081)
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Answer: (D) 0.036
Explanation
√(0.000081) = 0.009, since 0.009 × 0.009 = 0.000081.
Multiplying this value by 4 gives:
4 × 0.009 = 0.036
1221Mathematics
If circumference and area of a circle are numerically equal then radius of the circle is:
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Answer: (B) 2 units
Explanation
Circumference of a circle is 2πr and area is πr², where r is the radius. Equating the numerical values of both gives:
2πr = πr²
Dividing both sides by πr yields r = 2 units.
1222Mathematics
Two numbers are in the ratio 3:2. If 8 and 6 are subtracted from the first and the second number respectively, the ratio becomes 8:5. The numbers are:
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Answer: (B) 24,16
Explanation
Let the two numbers be 3x and 2x.
According to the given condition:
(3x - 8) / (2x - 6) = 8 / 5
Six years from now, Kirti's age will be twice the age of her brother Kunal, but 4 years ago she was four times as old as Kunal was then. Find the present age of Kunal.
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Answer: (A) 9 years
Explanation
Let the present ages of Kunal and Kirti be x and y years, respectively.
According to the given conditions:
y + 6 = 2(x + 6) ⇒ y = 2x + 6
y - 4 = 4(x - 4) ⇒ y = 4x - 12
Equating the two expressions for y:
2x + 6 = 4x - 12
2x = 18
x = 9
1225Mathematics
What is the difference between ⅗ of 200 and ½ of 300?
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Answer: (D) 30
Explanation
First value = (3/5) × 200 = 120
Second value = (1/2) × 300 = 150
Difference = 150 - 120 = 30
1226Mathematics
By which number should 2⅕ be multiplied to get 5⅖ ?
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Answer: (A) 2⁵⁄₁₁
Explanation
Convert the given mixed fractions into improper fractions:
2(1/5) = 11/5
5(2/5) = 27/5
Let x be the required multiplier.
(11/5) × x = 27/5
x = (27/5) ÷ (11/5)
x = 27/11 = 2(5/11)
1227Mathematics
In triangle ABC, the angles are in the ratio of 2:3:4. The measure of the biggest angle in degrees is:
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Answer: (C) 80°
Explanation
Sum of the interior angles of a triangle is always 180°. Given the ratio of the angles as 2 : 3 : 4, the total number of ratio parts is 2 + 3 + 4 = 9.
Value of 1 ratio part = 180° / 9 = 20°.
The largest angle corresponds to the largest ratio part, 4, so its measure is 4 × 20° = 80°.
1228Mathematics
Find the least multiple of 7 which when divided by 6, 8 and 12 leaves 1 as remainder.
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Answer: (B) 49
Explanation
The least common multiple (LCM) of 6, 8, and 12 is 24.
Any number that leaves a remainder of 1 when divided by 6, 8, and 12 is of the form 24k + 1, where k is a positive integer.
For k = 1: 24(1) + 1 = 25, which is not a multiple of 7.
For k = 2: 24(2) + 1 = 49, which is divisible by 7 (49 = 7 × 7).
1229Mathematics
A sells an article to B at a profit of 20% and B sells it to C at a profit of 20%. If C pays ₹360 for it, what was the cost price for A?
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Answer: (C) ₹250
Explanation
Cost Price for A = Final Price / ((1 + Profit₁%)(1 + Profit₂%))
Cost Price for A = 360 / (1.20 × 1.20) = 360 / 1.44 = ₹250.
1230Mathematics
A bag contains cards numbered between 33 and 92. If one card is drawn from the bag, the probability that the number on the drawn card is a perfect square is:
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Answer: (C) 1/15
Explanation
Total outcomes = (92 - 33) + 1 = 60 cards.
The perfect squares in the range 33 to 92 are 36 (6²), 49 (7²), 64 (8²), and 81 (9²).
Number of favorable outcomes = 4.
Probability = Favorable outcomes / Total outcomes = 4 / 60 = 1 / 15.
1231Mathematics
LCM of 30, 40 and 45 is:
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Answer: (D) 360
Explanation
Prime factorization of the given numbers:
30 = 2 × 3 × 5
40 = 2³ × 5
45 = 3² × 5
The LCM is the product of the highest power of each prime factor involved:
LCM(30, 40, 45) = 2³ × 3² × 5 = 8 × 9 × 5 = 360
1232Mathematics
In what time will ₹3,200 invested at 10% per annum compounded quarterly become ₹3,362?
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Answer: (B) 1/2 year
Explanation
The formula for compound amount with quarterly compounding is A = P × (1 + R/400)⁽4t), where P is the principal, A is the final amount, R is the annual interest rate, and t is the time in years.
Substituting P = 3200, A = 3362, and R = 10 into the formula:
3362 = 3200 × (1 + 10/400)⁽4t)
3362 / 3200 = (41/40)⁽4t)
1681 / 1600 = (41/40)⁽4t)
(41/40)² = (41/40)⁽4t)
Equating exponents:
4t = 2
t = ½ year
1233Mathematics
A, B and C together can do a piece of work in 14 days, whereas C alone can do the same work in 42 days. How long will A and B together take to finish it?
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Answer: (C) 21 days
Explanation
Work done by A, B, and C together in 1 day = 1/14
Work done by C alone in 1 day = 1/42
Work done by A and B together in 1 day = 1/14 - 1/42 = (3 - 1)/42 = 2/42 = 1/21
Alternatively, using the combined work formula:
Time taken = (14 × 42) / (42 - 14) = 588 / 28 = 21 days
1234Mathematics
For a = - 5 and b = 5 , value of a² - b² is:
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Answer: (B) 0
Explanation
Using direct substitution into the expression:
a² - b² = (-5)² - (5)²
Since (-5)² = 25 and 5² = 25, substituting these values gives:
a² - b² = 25 - 25 = 0
Alternatively, using the algebraic identity a² - b² = (a + b)(a - b):
a² - b² = (-5 + 5)(-5 - 5) = 0 × (-10) = 0
1235Mathematics
What is the value of 8x³ + 18xy + y³ - 27 when 2x + y - 3 = 0 .
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Answer: (C) 0
Explanation
Using the algebraic identity, if a + b + c = 0, then a³ + b³ + c³ - 3abc = 0.
Let a = 2x, b = y, and c = -3.
Given that a + b + c = 2x + y - 3 = 0, we substitute these into the identity:
Two friends received a bonus of ₹2,000 each in their bank accounts. They already have ₹47,000 and ₹54,000 in their respective bank accounts. Ratio of the amounts in their respective accounts will be:
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Answer: (A) 7 : 8
Explanation
New amount in the first friend's account = ₹47,000 + ₹2,000 = ₹49,000
New amount in the second friend's account = ₹54,000 + ₹2,000 = ₹56,000
Ratio = 49,000 : 56,000 = 49 : 56
Dividing both terms by their greatest common divisor (7):
49 ÷ 7 = 7 and 56 ÷ 7 = 8, giving the simplified ratio 7 : 8.
1237Mathematics
Kings and Queens of black colour are taken out from a deck of 52 playing cards. A card is drawn from the remaining well- shuffled cards. Probability of getting a spade card is:
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Answer: (C) 11/48
Explanation
Total cards in a standard deck = 52.
Number of black Kings and Queens removed = 2 Kings (Spades, Clubs) + 2 Queens (Spades, Clubs) = 4 cards.
Remaining total cards = 52 - 4 = 48.
Original number of spade cards = 13.
Since the King of Spades and Queen of Spades were removed, remaining spade cards = 13 - 2 = 11.
Probability of drawing a spade card = Favorable outcomes / Total outcomes = 11/48.
1238Mathematics
Select the option that gives decimal numbers 0.25, 1.24, 0.0882 and 2.67 arranged in ascending order.
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Answer: (A) 0.0882, 0.25, 1.24, 2.67
Explanation
Ascending order means arranging numbers from the smallest value to the largest value. Comparing the whole number parts and decimal place values: 0.0882 is the smallest since its whole number part is 0 and tenths digit is 0, followed by 0.25 which has a tenths digit of 2, then 1.24 which has a whole number part of 1, and finally 2.67 which has the largest whole number part of 2. The sequence from smallest to largest is 0.0882 < 0.25 < 1.24 < 2.67.
1239Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows.
Marks (out of 50)
Name of Students | Physics | Chemistry | Maths | English | Sanskrit
A | 48 | 47 | 49 | 46 | 44
B | 29 | 33 | 22 | 15 | 30
C | 35 | 36 | 42 | 40 | 29
D | 46 | 49 | 48 | 48 | 40
E | 32 | 30 | 25 | 21 | 22
Which student got the lowest overall percentage of marks?
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Answer: (B) B
Explanation
Total maximum marks for 5 subjects = 5 × 50 = 250.
Since the maximum possible marks are equal for all students, the student with the lowest total marks will have the lowest overall percentage.
Total marks obtained by B = 29 + 33 + 22 + 15 + 30 = 129
Overall percentage for B = (129 / 250) × 100 = 51.6%
With a total of 129 marks out of 250, student B secures the lowest total marks and consequently the lowest overall percentage of 51.6%.
1240Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows.
Marks (out of 50)
Name of Students | Physics | Chemistry | Maths | English | Sanskrit
A | 48 | 47 | 49 | 46 | 44
B | 29 | 33 | 22 | 15 | 30
C | 35 | 36 | 42 | 40 | 29
D | 46 | 49 | 48 | 48 | 40
E | 32 | 30 | 25 | 21 | 22
What is the maximum overall percentage (average of percentages obtained in all subjects by any student) of marks obtained by any student among A, B, C, D and E?
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Answer: (B) 93.60%
Explanation
Total maximum marks for the 5 subjects = 5 × 50 = 250.
Calculating the total marks for student A gives 48 + 47 + 49 + 46 + 44 = 234, which is the highest total score among all students.
The given table shows the marks of various students in a class. Study the table and answer the question that follows.
Marks (out of 50)
Name of Students | Physics | Chemistry | Maths | English
A | 48 | 47 | 49 | 46
B | 29 | 33 | 22 | 15
C | 35 | 36 | 42 | 40
D | 46 | 49 | 48 | 48
E | 32 | 30 | 25 | 21
Which two students have the least difference of marks between them?
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Answer: (B) A and D
Explanation
To find the two students with the least difference in marks, calculate the total marks obtained by each student across all subjects:
Total marks of A = 48 + 47 + 49 + 46 = 190
Total marks of B = 29 + 33 + 22 + 15 = 99
Total marks of C = 35 + 36 + 42 + 40 = 153
Total marks of D = 46 + 49 + 48 + 48 = 191
Total marks of E = 32 + 30 + 25 + 21 = 108
The difference in total marks between A and D is 191 - 190 = 1, which is the smallest possible difference between any pair of students.
1242Mathematics
The given table shows the marks of various students in a class. Study the table and answer the question that follows.
Marks (out of 50)
Name of Students | Physics | Chemistry | Maths | English
A | 48 | 47 | 49 | 46
B | 29 | 33 | 22 | 15
C | 35 | 36 | 42 | 40
D | 46 | 49 | 48 | 48
E | 32 | 30 | 25 | 21
If we rank students on the basis of all five subjects and then we rank them only on the basis of physics, chemistry and maths then what will happen to the arrangement of ranks in both cases?
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Answer: (C) Only the top two ranks will be different.
Explanation
Calculating total marks in all listed subjects for each student:
D: 46 + 49 + 48 + 48 = 191
A: 48 + 47 + 49 + 46 = 190
C: 35 + 36 + 42 + 40 = 153
E: 32 + 30 + 25 + 21 = 108
B: 29 + 33 + 22 + 15 = 99
Rank order in all subjects: 1st D, 2nd A, 3rd C, 4th E, 5th B.
Rank order in PCM: 1st A, 2nd D, 3rd C, 4th E, 5th B.
Comparing both rankings, the 1st and 2nd positions swap between A and D, while the 3rd, 4th, and 5th positions (C, E, B) remain unchanged. Thus, only the top two ranks are different.
1243Mathematics
How will you write 4.14 hours in hours, minutes and seconds?
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Answer: (C) 4 hours, 8 minutes, 24 seconds
Explanation
To convert 4.14 hours into hours, minutes, and seconds:
Whole hours = 4 hours.
Convert the decimal part to minutes: 0.14 × 60 = 8.4 minutes, which gives 8 whole minutes.
Convert the remaining decimal part of the minute to seconds: 0.4 × 60 = 24 seconds.
Combining these gives 4 hours, 8 minutes, 24 seconds.
1244Mathematics
Two articles are sold by a trader. One of them is sold for 20% profit. Its selling price equals the cost price of the other article which is sold for 20% loss. Find the effective profit/loss percentage approximately.
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Answer: (A) 1.8% loss
Explanation
Let the cost price of the first article be CP1 = 100.
Since it is sold at a 20% profit, its selling price is SP1 = 100 × 1.20 = 120.
The cost price of the second article equals SP1, so CP2 = 120.
The second article is sold at a 20% loss, so its selling price is SP2 = 120 × 0.80 = 96.
Total Loss = 220 - 216 = 4.
Loss percentage = (4 ÷ 220) × 100 = 20/11 % ≈ 1.818% ≈ 1.8% loss.
1245Mathematics
If each side of square is increased by 20% then find the percentage change in its area.
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Answer: (B) 44%
Explanation
Percentage change in area when two successive dimensions increase by x% and y% is given by the formula:
Net percentage change = x + y + (x × y) / 100
Since area of a square is side × side, both dimensions increase by 20%, so x = 20 and y = 20.
Substituting these values into the formula:
Net percentage change = 20 + 20 + (20 × 20) / 100
= 40 + 400 / 100
= 40 + 4
= 44%
Alternatively, assuming initial side length as 10 units, initial area is 10 × 10 = 100 square units. With a 20% increase, the new side length becomes 12 units, making the new area 12 × 12 = 144 square units. The percentage increase is ((144 - 100) / 100) × 100 = 44%.
1246Mathematics
The largest number of four digits which, when divided by 6, 12 and 18 leaves the same remainder 5 in each case is:
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Answer: (C) 9977
Explanation
The LCM of 6, 12, and 18 is 36.
The largest four-digit number is 9999. Dividing 9999 by 36 yields a quotient of 277 and a remainder of 27 (9999 = 36 × 277 + 27).
Subtracting the remainder gives the largest four-digit number divisible by 36:
9999 - 27 = 9972
To find the number that leaves a remainder of 5 in each case, add 5 to this multiple:
9972 + 5 = 9977
1247Mathematics
The ratio of two numbers is 7:5 . Their HCF is 3, their LCM is ______.
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Answer: (C) 105
Explanation
For two numbers in the ratio a : b (where a and b are co-prime) and having a Highest Common Factor (HCF) of h, the Least Common Multiple (LCM) is given by the formula:
LCM = HCF × a × b
Substituting the given values into the formula:
LCM = 3 × 7 × 5 = 105
1248Mathematics
If (7 + 2√5)/(11 + 3√5) = a + b√5 , then:
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Answer: (D) a = ⁴⁷⁄₇₆; b = ¹⁄₇₆
Explanation
To rationalize the denominator of (7 + 2√5) / (11 + 3√5), multiply the numerator and denominator by the conjugate of the denominator, (11 - 3√5):
Thus, the fraction simplifies to:
(47 + √5) / 76 = (47 / 76) + (1 / 76)√5
Comparing this with a + b√5 yields:
a = 47/76 and b = 1/76
1249Mathematics
A hemispherical bowl of internal radius of 12 cm contains a liquid. This liquid is to be filled into conical shaped small bottles of base diameter 3 cm and height 4 cm. How many same type of bottles will be needed to empty the bowl?
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Answer: (B) 384
Explanation
The volume of a hemisphere is (2/3)πR³ and the volume of a cone is (1/3)πr²h.
Number of bottles required = Volume of hemisphere / Volume of one conical bottle
= [(2/3)πR³] / [(1/3)πr²h]
= (2R³) / (r²h)
Given:
Radius of hemisphere (R) = 12 cm
Radius of cone (r) = 3/2 = 1.5 cm
Height of cone (h) = 4 cm
The price of a car is 6,25,000. It was insured to 80% of its price. The car was damaged completely, and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received?
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Answer: (D) ₹1,75,000
Explanation
Amount received as a percentage of the original car price = 80% × 90% = 72%
Percentage difference between car price and amount received = 100% - 72% = 28%