Total Cost Price of a dozen (12) watches = 12 × 1254 = 15048.00
1403Mathematics
Manju takes 16 days to complete a work. If she works with her friend Jenny they complete it in 12 days. How many days will it take for Jenny to complete the work alone?
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Answer: (A) 48
Explanation
Using the work-rate formula, Jenny's daily work rate is obtained by subtracting Manju's daily work rate from their combined daily work rate:
Jenny's rate = 1/12 - 1/16 = (4 - 3) / 48 = 1/48
Since Jenny completes 1/48 of the work in one day, she will take 48 days to complete the entire work alone.
1404Mathematics
Solve: 10⁹ × 10² ÷ 10³
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Answer: (A) 10⁸
Explanation
Using the laws of exponents, aᵐ × aⁿ = aᵐ⁺ⁿ and aᵐ ÷ aⁿ = aᵐ⁻ⁿ.
Applying these rules to the expression:
10⁹ × 10² ÷ 10³ = 10⁹⁺²⁻³ = 10¹¹⁻³ = 10⁸
1405Mathematics
If the circumference of a circle is 22 cm, find the area of the semicircle.
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Answer: (B) 19.25 sq.cm
Explanation
Circumference of a circle = 2πr = 22 cm.
2 × (22/7) × r = 22
r = 7/2 = 3.5 cm
Area of the semicircle = ½πr²
= ½ × (22/7) × (7/2)²
= ½ × (22/7) × (49/4)
= 77/4 = 19.25 sq.cm
1406Mathematics
Find the interest on Rs. 25000 at 12% p.a compounded annually for 3 years.
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Answer: (C) 10,123.20
Explanation
The compound interest is given by the formula CI = P[(1 + r/100)ⁿ - 1], where P is the principal, r is the annual rate of interest, and n is the time in years.
Given: P = ₹25000, r = 12%, and n = 3 years.
CI = 25000 × [(1 + 12/100)³ - 1]
CI = 25000 × [(1.12)³ - 1]
CI = 25000 × [1.404928 - 1]
CI = 25000 × 0.404928
CI = 10123.20
1407Mathematics
The LCM and HCF of 2 numbers are 168 and 6 respectively. If one of the numbers is 24, find the other.
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Answer: (D) 42
Explanation
For any two positive integers, the product of the two numbers is equal to the product of their LCM and HCF:
Number 1 × Number 2 = LCM × HCF
Substituting the given values into the formula:
24 × Number 2 = 168 × 6
Number 2 = (168 × 6) / 24
Number 2 = 168 / 4
Number 2 = 42
1408Mathematics
78 books, 114 crayons and 141 notebooks were distributed to school children equally. It was found that 6 were left undistributed in each. What was the total number of children?
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Answer: (A) 9
Explanation
The number of items actually distributed among the children is obtained by subtracting the remainder 6 from each category:
I take a book from a library containing 378 pages to be returned in a week's time. If I can red 14 pages an hour for three hours daily, for how long should it be renewed so that the book can be fully read?
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Answer: (D) 2 days
Explanation
Reading rate per day = 14 pages/hour × 3 hours/day = 42 pages/day.
Total time required to read the entire book = 378 ÷ 42 = 9 days.
Since the initial borrowing period is 1 week (7 days), the required renewal duration is 9 − 7 = 2 days.
1412Mathematics
Eggs sold by a shopkeeper over a week is given in the table below. Eggs sold in dozens
Day Sales in dozen
Sunday 12
Monday 8
Tuesday 11
Wednesday 5
Thursday 9
Friday 10
Saturday 10
If the price of one egg was Rs. 2.50, how much more did he earn on Friday than on Monday?
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Answer: (B) 60 rupees
Explanation
Difference in earnings = (Friday sales in dozen - Monday sales in dozen) × 12 × Price per egg
Substituting the values from the table:
Difference in earnings = (10 - 8) × 12 × 2.50 = 2 × 12 × 2.50 = 24 × 2.50 = 60 rupees.
1413Mathematics
The man of the marks scored by 12 students of a class is 67.4. If the mean of another class consisting of 15 students is 72.3, find their combined mean?
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Answer: (A) 70.12
Explanation
Combined Mean = (n₁x̄₁ + n₂x̄₂) / (n₁ + n₂)
Total marks for the first class = 12 × 67.4 = 808.8
Total marks for the second class = 15 × 72.3 = 1084.5
Sum of all marks = 808.8 + 1084.5 = 1893.3
Total number of students = 12 + 15 = 27
Combined mean = 1893.3 / 27 = 70.12
1414Mathematics
The cost of a pair of roller skates was 450. The sales tax charged was 5 % Find the bill amount.
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Answer: (D) 472.50
Explanation
Bill Amount = Cost Price × (1 + Tax Rate %)
Substituting the given values:
Sales Tax Amount = 5% of 450 = (5 ÷ 100) × 450 = 22.50
Total Bill Amount = Cost Price + Sales Tax Amount = 450 + 22.50 = 472.50
1415Mathematics
A man walks at a certain speed and reaches his destination which is 6 km in 1 hr 40 minutes. If he runs the same distance in 1 hour 20 minutes what is the difference in speed?
By the trigonometric complementary angle identity, the sine of an angle's complement equals the cosine of the angle:
sin(90° - θ) = cos θ
In a right-angled triangle with acute angle θ, the other acute angle is 90° - θ. The side opposite to 90° - θ is the side adjacent to θ, making the sine ratio for 90° - θ identical to the cosine ratio for θ.
1417Mathematics
Find (x + y)² - (x - y)²
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Answer: (B) 4xy
Explanation
Using the algebraic identity (a + b)² - (a - b)² = 4ab, expanding both terms gives:
A politician distributed 285 kg of sugar among the people of a village counting 1487. Find out how much sugar does each person get.
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Answer: (C) 0.191 kg
Explanation
Amount of sugar received by each person = Total sugar ÷ Total population
Substituting the given values:
Amount per person = 285 kg ÷ 1487 = 0.19166... kg ≈ 0.191 kg
1421Mathematics
A sum borrowed at 6% p.a earns an interest which is 1 / 3ʳᵈ of its principal in x years. Find x.
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Answer: (A) 5⁵⁄₉
Explanation
Simple interest formula is SI = (P × R × x) / 100.
Given that SI = P / 3 and R = 6%:
P / 3 = (P × 6 × x) / 100
1 / 3 = 6x / 100
x = 100 / 18 = 50 / 9 = 5 5/9 years.
1422Mathematics
Yash sells vegetables at 40 per kg and incurs a loss of 10% . If the total loss incurred is 144, what is the weight of vegetables sold? (Rounded off)
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Answer: (B) 32.40kg
Explanation
Selling price (SP) is 90% of the cost price (CP) due to a 10% loss.
CP per kg = 40 / 0.9 = 400/9 per kg.
Loss per kg = CP - SP = (400/9) - 40 = 40/9 per kg.
Weight of vegetables sold = Total loss / Loss per kg = 144 / (40/9) = (144 × 9) / 40 = 32.40 kg.
1423Mathematics
08 tonne = ? kg
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Answer: (C) 1080
Explanation
1 metric tonne is equal to 1000 kg.
Converting 1.08 tonnes into kilograms using this standard relation:
1.08 × 1000 = 1080 kg
1424Mathematics
Solve: 1 + tan²θ = ?
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Answer: (B) sec²θ
Explanation
By the standard Pythagorean trigonometric identity, 1 + tan²θ = sec²θ. This can also be derived by dividing the fundamental identity sin²θ + cos²θ = 1 by cos²θ, giving (sin²θ / cos²θ) + (cos²θ / cos²θ) = 1 / cos²θ, which simplifies to tan²θ + 1 = sec²θ.
1425Mathematics
If x is an even number, what is the consecutive odd number?
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Answer: (B) x+1
Explanation
Consecutive integers on the number line alternate between even and odd with a common difference of 1. Therefore, for any given even number x, the immediate next consecutive odd number is obtained by adding 1, which gives x + 1.
1426Mathematics
How many litres of water can be stored in a tank of 1m length, ½m breadth, and ½m tall?
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Answer: (B) 250
Explanation
Volume of a rectangular tank = length × breadth × height
V = 1 m × ½ m × ½ m = ¼ m³ = 0.25 m³
Since 1 m³ = 1,000 litres:
Capacity in litres = 0.25 × 1,000 = 250 litres
1427Mathematics
Jane won a lottery and gets 1 / 3ʳᵈ of the winning amount and donates Rs. 6000 which is 1 / 6ᵗʰ , find how much the lottery was worth.
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Answer: (D) 108000
Explanation
Let L be the total worth of the lottery.
Jane receives a share equal to L / 3.
She donates 1/6 of her received share, which is given as Rs. 6000:
(1/6) × (L / 3) = 6000
L / 18 = 6000
L = 6000 × 18 = 108,000
1428Mathematics
Find the difference between the place value and face value of the digit 9 in the number 229301?
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Answer: (B) 8991
Explanation
In the number 229301, the digit 9 is at the thousands place.
Place value of 9 = 9 × 1000 = 9000
Face value of 9 = 9
Difference = Place value - Face value = 9000 - 9 = 8991
1429Mathematics
The sum of two numbers is 437 and their product is 21982. Find the numbers.
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Answer: (C) 58 and 379
Explanation
Let the two numbers be x and y. Any two numbers with a known sum S and product P are the roots of the quadratic equation t² - St + P = 0.
t² - 437t + 21982 = 0
Applying the quadratic formula:
t = (437 ± √(437² - 4 × 21982)) / 2
t = (437 ± √(190969 - 87928)) / 2
t = (437 ± √103041) / 2
t = (437 ± 321) / 2
A bank agrees to lend a loan to Arvind of Rs. 2,38,75,697 which falls short by 17% for starting his business. How much more loan would he need?
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Answer: (A) 4890203
Explanation
Let the total amount required to start the business be T. Since the approved loan of ₹2,38,75,697 falls short by 17%, it represents 83% of the total required amount.
83% of T = ₹2,38,75,697
1% of T = 2,38,75,697 / 83 = ₹2,87,659
The additional loan amount needed by Arvind is the remaining 17% of T:
17% of T = 2,87,659 × 17 = ₹48,90,203
1431Mathematics
A piece of wire is bent to form a circle with a radius of 70~cm . If the same piece of wire is bent to form a square, the length of the side of the square will be ²²⁄₇ . [Use π = ²²⁄₇ ]
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Answer: (B) 110cm
Explanation
The total length of the wire remains constant whether it forms a circle or a square.
Length of wire = Circumference of circle = 2 × π × r = 2 × (22/7) × 70 = 440 cm
Since the perimeter of the square equals the length of the wire:
4 × side = 440 cm
side = 440 / 4 = 110 cm
1432Mathematics
If the selling price of an article is ⁵⁄₄ of its cost price, then the profit obtained in the transaction is:
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Answer: (D) 25%
Explanation
Profit percentage is given by the formula:
Profit % = [(SP - CP) / CP] × 100
Given SP = (5/4) CP, the ratio of selling price to cost price is:
SP / CP = 5 / 4
Substituting these values into the formula:
Profit % = [(5 - 4) / 4] × 100 = (1 / 4) × 100 = 25%
1433Mathematics
In an examination, 90% of the students passed and 600 students failed. How many students appeared for the examination?
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Answer: (C) 6000
Explanation
Since 90% of the students passed, the percentage of students who failed is 100% - 90% = 10%.
Let T be the total number of students who appeared for the examination.
10% of T = 600
(10 / 100) × T = 600
T = (600 × 100) / 10 = 6000
1434Mathematics
A gold ring is sold for ₹17,500 at a loss of 30% . What is the cost price of the gold ring?
Which of the following fractions does NOT lie between ⁷⁄₁₈ and ⅗ ?
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Answer: (D) ⅓
Explanation
Converting the boundary fractions to decimal form:
7/18 ≈ 0.389
3/5 = 0.600
For a fraction to lie between 7/18 and 3/5, its decimal value must be greater than 0.389 and less than 0.600.
Converting 1/3 to decimal form gives 1/3 ≈ 0.333. Since 0.333 < 0.389, 1/3 is less than 7/18 and lies outside the given range.
1436Mathematics
Which of the following is closest to zero?
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Answer: (D) (0.09)²
Explanation
Evaluating the expression gives (0.09)² = 0.0081. Since 0.0081 is less than 0.009, 0.8281, and 0.9919, its distance from zero is the smallest.
1437Mathematics
The angles of depression of two houses of the same height from the top of a building are 45° and 30° towards the east. If the two houses are 50~m apart, what will be the height of the building in metres?
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Answer: (C) 25(√3 +1)
Explanation
Let h be the height of the building relative to the top of the houses, and d be the distance of the nearer house from the building.
For the nearer house with angle of depression 45°:
tan 45° = h / d
1 = h / d
d = h
For the farther house with angle of depression 30°:
tan 30° = h / (d + 50)
1 / √3 = h / (h + 50)
Solving for h:
h + 50 = h√3
h(√3 - 1) = 50
h = 50 / (√3 - 1)
Rationalizing the denominator:
h = 50(√3 + 1) / ((√3 - 1)(√3 + 1))
h = 50(√3 + 1) / 2
h = 25(√3 + 1) m
1438Mathematics
44% of a number is 798.6. What is 63% of that number?
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Answer: (D) 1143.45
Explanation
Using the direct proportion method:
Required value = (798.6 / 44) × 63
798.6 ÷ 44 = 18.15
18.15 × 63 = 1143.45
1439Mathematics
In an isosceles Δ ABC , if the measure of ∠ A is twice that of the base ∠ B , then the measure of ∠ C will be:
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Answer: (A) 45°
Explanation
In an isosceles triangle, the two base angles are equal, so ∠C = ∠B. Given that the measure of ∠A is twice that of the base angle ∠B, we have ∠A = 2∠B.
Using the angle sum property of a triangle:
∠A + ∠B + ∠C = 180°
2∠B + ∠B + ∠B = 180°
4∠B = 180°
∠B = 45°
Since ∠C = ∠B, the measure of ∠C is 45°.
1440Mathematics
The perimeter of a rectangle is 120m . If its length is twice its breadth, then its area is:
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Answer: (D) 800m2
Explanation
Let the breadth of the rectangle be b.
Since the length l is twice its breadth, l = 2b.
The perimeter of a rectangle is given by the formula P = 2(l + b).
Substituting the given values:
2(2b + b) = 120
6b = 120
b = 20 m
Thus, length l = 2 × 20 = 40 m.
Area of the rectangle = l × b = 40 × 20 = 800 m².
1441Mathematics
Find the least number that when divided by 9, 8, 10 and 12 leaves a remainder of 3 in each case.
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Answer: (C) 363
Explanation
The required least number is given by LCM(9, 8, 10, 12) + 3.
Prime factorization of the given divisors:
9 = 3²
8 = 2³
10 = 2 × 5
12 = 2² × 3
How many cubes of side 3cm can be formed by melting a cuboid of length 9cm breadth 6cm and height 6cm
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Answer: (B) 12
Explanation
Number of cubes = Volume of cuboid / Volume of a cube
Volume of cuboid = length × breadth × height = 9 × 6 × 6 = 324 cm³
Volume of a cube = side³ = 3³ = 27 cm³
Number of cubes = 324 / 27 = 12
1443Mathematics
The sum of the consecutive angles of a parallelogram is equal to:
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Answer: (D) 180°
Explanation
In a parallelogram, opposite sides are parallel. When two parallel lines are cut by a transversal, the interior angles on the same side of the transversal (consecutive angles) are supplementary. Therefore, the sum of any two consecutive angles of a parallelogram is equal to 180°.
1444Mathematics
The sum and difference of the LCM and HCF of two numbers are 682 and 638 respectively. If the sum of the two numbers is 286, find the numbers.
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Answer: (B) 220 and 66
Explanation
Let L and H be the LCM and HCF of the two numbers.
L + H = 682
L - H = 638
Solving these equations:
2L = 1320 ⇒ L = 660
2H = 44 ⇒ H = 22
Let the two numbers be 22a and 22b, where a and b are co-prime integers.
Given sum = 22(a + b) = 286 ⇒ a + b = 13.
Product of co-prime factors a × b = LCM / HCF = 660 / 22 = 30.
The pair of co-prime integers satisfying a + b = 13 and a × b = 30 is 10 and 3.
The two numbers are 22 × 10 = 220 and 22 × 3 = 66.
1445Mathematics
Ram bought five bananas for 20 and sold them at the rate of three for 15. Find his gain percentage.
A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the ground. Find the length of the ladder.
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Answer: (A) 6.5m
Explanation
By the Pythagorean theorem, for a right-angled triangle formed by the wall, the ground, and the ladder:
Length of ladder² = (Distance from wall)² + (Height of window)²
Length of ladder² = (2.5)² + 6²
Length of ladder² = 6.25 + 36 = 42.25
Length of ladder = √42.25 = 6.5 m
1447Mathematics
If X's income is 40% less than that of Y, then Y's income is approximately what percentage more than that of X?
Alternatively, assuming Y's income is 100, X's income becomes 60. Y's income is 40 more than X's income, making it (40 / 60) × 100 = 66.67% more than X's income.
1448Mathematics
What is the median of the following data?
78,56,22,34,45,54,39,68,54,84
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Answer: (C) 54
Explanation
To find the median, arrange the given dataset of 10 numbers in ascending order:
22, 34, 39, 45, 54, 54, 56, 68, 78, 84
Since the number of observations n = 10 is even, the median is the average of the 5th and 6th terms:
Median = (5th term + 6th term) / 2 = (54 + 54) / 2 = 54
1449Mathematics
If p is the length of a rectangle and its width is one-third of its length, then the area of the rectangle will be:
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Answer: (A) (p²)/(3)
Explanation
Length of the rectangle = p
Width of the rectangle = p/3
Area of a rectangle = Length × Width = p × (p/3) = p²/3
1450Mathematics
Find the mean of x + 77 x + 7 x + 5 x + 3 and x - 2
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Answer: (D) x + 18
Explanation
Mean = (Sum of observations) ÷ (Total number of observations)
Sum of the 5 observations = (x + 77) + (x + 7) + (x + 5) + (x + 3) + (x - 2) = 5x + 90