RRB NTPC2021MathematicsPage 29 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1401–1450 of 1,785, each with the correct answer and a step-by-step explanation.

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1401Mathematics
A number lies between the cubes of 11 and 12. If the number is divisible by twice of 80 and 6 both, what will be the number?
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Answer: (B) 1440

Explanation

The cube of 11 is 11³ = 1331 and the cube of 12 is 12³ = 1728. Thus, the required number lies strictly between 1331 and 1728.

Twice of 80 is 2 × 80 = 160. Since the number is divisible by both 160 and 6, it must be a multiple of their Least Common Multiple (LCM).

LCM(160, 6) = 480

The multiples of 480 are 480, 960, 1440, 1920, and so on.

The only multiple of 480 that lies between 1331 and 1728 is 480 × 3 = 1440.

1402Mathematics
Manu sold a dozen watches for Rs. 1454.64 per watch and made a profit of 16% . Find the cost price of the watches?
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Answer: (C) 15048.00

Explanation

Cost Price of 1 watch = Selling Price / (1 + Profit%) = 1454.64 / 1.16 = 1254

Total Cost Price of a dozen (12) watches = 12 × 1254 = 15048.00

1403Mathematics
Manju takes 16 days to complete a work. If she works with her friend Jenny they complete it in 12 days. How many days will it take for Jenny to complete the work alone?
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Answer: (A) 48

Explanation

Using the work-rate formula, Jenny's daily work rate is obtained by subtracting Manju's daily work rate from their combined daily work rate:

Jenny's rate = 1/12 - 1/16 = (4 - 3) / 48 = 1/48

Since Jenny completes 1/48 of the work in one day, she will take 48 days to complete the entire work alone.

1404Mathematics
Solve: 10⁹ × 10² ÷ 10³
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Answer: (A) 10⁸

Explanation

Using the laws of exponents, aᵐ × aⁿ = aᵐ⁺ⁿ and aᵐ ÷ aⁿ = aᵐ⁻ⁿ.

Applying these rules to the expression: 10⁹ × 10² ÷ 10³ = 10⁹⁺²⁻³ = 10¹¹⁻³ = 10⁸

1405Mathematics
If the circumference of a circle is 22 cm, find the area of the semicircle.
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Answer: (B) 19.25 sq.cm

Explanation

Circumference of a circle = 2πr = 22 cm.

2 × (22/7) × r = 22 r = 7/2 = 3.5 cm

Area of the semicircle = ½πr² = ½ × (22/7) × (7/2)² = ½ × (22/7) × (49/4) = 77/4 = 19.25 sq.cm

1406Mathematics
Find the interest on Rs. 25000 at 12% p.a compounded annually for 3 years.
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Answer: (C) 10,123.20

Explanation

The compound interest is given by the formula CI = P[(1 + r/100)ⁿ - 1], where P is the principal, r is the annual rate of interest, and n is the time in years.

Given: P = ₹25000, r = 12%, and n = 3 years.

CI = 25000 × [(1 + 12/100)³ - 1] CI = 25000 × [(1.12)³ - 1] CI = 25000 × [1.404928 - 1] CI = 25000 × 0.404928 CI = 10123.20

1407Mathematics
The LCM and HCF of 2 numbers are 168 and 6 respectively. If one of the numbers is 24, find the other.
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Answer: (D) 42

Explanation

For any two positive integers, the product of the two numbers is equal to the product of their LCM and HCF:

Number 1 × Number 2 = LCM × HCF

Substituting the given values into the formula: 24 × Number 2 = 168 × 6 Number 2 = (168 × 6) / 24 Number 2 = 168 / 4 Number 2 = 42

1408Mathematics
78 books, 114 crayons and 141 notebooks were distributed to school children equally. It was found that 6 were left undistributed in each. What was the total number of children?
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Answer: (A) 9

Explanation

The number of items actually distributed among the children is obtained by subtracting the remainder 6 from each category:

Books distributed = 78 - 6 = 72 Crayons distributed = 114 - 6 = 108 Notebooks distributed = 141 - 6 = 135

The number of children is the Highest Common Factor (HCF) of 72, 108, and 135.

72 = 9 × 8 108 = 9 × 12 135 = 9 × 15

HCF(72, 108, 135) = 9

Thus, the total number of children is 9.

1409Mathematics
If Aˣ⁺ʸ = a⁶ and x > y by 2 find x.
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Answer: (D) 4

Explanation

From the given equation a⁽x+y) = a⁶, equating exponents of the same base gives: x + y = 6

It is given that x is greater than y by 2, which gives: x - y = 2

Adding both equations together: (x + y) + (x - y) = 6 + 2 2x = 8 x = 4

1410Mathematics
Solve: ¹²⁄₁₃ × ²⁸⁵⁄₉₆ ÷ ¹⁷¹⁄₁₆₉ = ?
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Answer: (B) ⁶⁵⁄₂₄

Explanation

To solve the given expression: (12/13) × (285/96) ÷ (171/169)

Convert division into multiplication by taking the reciprocal of the fraction: = (12/13) × (285/96) × (169/171)

Simplify by dividing common terms in the numerators and denominators: 169 ÷ 13 = 13 12 ÷ 96 = 1/8 285 ÷ 171 = 5/3 (dividing both by 57)

Combine the simplified values: = (1 × 5 × 13) / (1 × 8 × 3) = 65/24

1411Mathematics
I take a book from a library containing 378 pages to be returned in a week's time. If I can red 14 pages an hour for three hours daily, for how long should it be renewed so that the book can be fully read?
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Answer: (D) 2 days

Explanation

Reading rate per day = 14 pages/hour × 3 hours/day = 42 pages/day.

Total time required to read the entire book = 378 ÷ 42 = 9 days.

Since the initial borrowing period is 1 week (7 days), the required renewal duration is 9 − 7 = 2 days.

1412Mathematics
Eggs sold by a shopkeeper over a week is given in the table below. Eggs sold in dozens Day Sales in dozen Sunday 12 Monday 8 Tuesday 11 Wednesday 5 Thursday 9 Friday 10 Saturday 10 If the price of one egg was Rs. 2.50, how much more did he earn on Friday than on Monday?
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Answer: (B) 60 rupees

Explanation

Difference in earnings = (Friday sales in dozen - Monday sales in dozen) × 12 × Price per egg

Substituting the values from the table: Difference in earnings = (10 - 8) × 12 × 2.50 = 2 × 12 × 2.50 = 24 × 2.50 = 60 rupees.

1413Mathematics
The man of the marks scored by 12 students of a class is 67.4. If the mean of another class consisting of 15 students is 72.3, find their combined mean?
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Answer: (A) 70.12

Explanation

Combined Mean = (n₁x̄₁ + n₂x̄₂) / (n₁ + n₂)

Total marks for the first class = 12 × 67.4 = 808.8 Total marks for the second class = 15 × 72.3 = 1084.5

Sum of all marks = 808.8 + 1084.5 = 1893.3 Total number of students = 12 + 15 = 27

Combined mean = 1893.3 / 27 = 70.12

1414Mathematics
The cost of a pair of roller skates was 450. The sales tax charged was 5 % Find the bill amount.
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Answer: (D) 472.50

Explanation

Bill Amount = Cost Price × (1 + Tax Rate %)

Substituting the given values: Sales Tax Amount = 5% of 450 = (5 ÷ 100) × 450 = 22.50

Total Bill Amount = Cost Price + Sales Tax Amount = 450 + 22.50 = 472.50

1415Mathematics
A man walks at a certain speed and reaches his destination which is 6 km in 1 hr 40 minutes. If he runs the same distance in 1 hour 20 minutes what is the difference in speed?
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Answer: (B) 0.9 km/hr

Explanation

Speed = Distance / Time.

Walking time = 1 hr 40 min = 5/3 hours. Walking speed = 6 / (5/3) = 18/5 = 3.6 km/hr.

Running time = 1 hr 20 min = 4/3 hours. Running speed = 6 / (4/3) = 18/4 = 4.5 km/hr.

Difference in speed = 4.5 - 3.6 = 0.9 km/hr.

1416Mathematics
Find sin (90° - θ)
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Answer: (D) cos θ

Explanation

By the trigonometric complementary angle identity, the sine of an angle's complement equals the cosine of the angle:

sin(90° - θ) = cos θ

In a right-angled triangle with acute angle θ, the other acute angle is 90° - θ. The side opposite to 90° - θ is the side adjacent to θ, making the sine ratio for 90° - θ identical to the cosine ratio for θ.

1417Mathematics
Find (x + y)² - (x - y)²
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Answer: (B) 4xy

Explanation

Using the algebraic identity (a + b)² - (a - b)² = 4ab, expanding both terms gives:

(x + y)² - (x - y)² = (x² + 2xy + y²) - (x² - 2xy + y²) = 4xy

1418Mathematics
The area of a rectangle is 42 sq. cm and its length is 7 cm . Find its perimeter.
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Answer: (C) 26 cm

Explanation

Area of a rectangle = length × breadth 42 = 7 × breadth breadth = 6 cm

Perimeter of a rectangle = 2 × (length + breadth) Perimeter = 2 × (7 + 6) = 2 × 13 = 26 cm

1419Mathematics
If by selling 20 cycles Vinay incurs a loss equal to the selling price of 2 cycles, find his loss percentage.
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Answer: (D) 9¹⁄₁₁%

Explanation

Let the selling price (SP) of 1 cycle be 1 unit.

Total SP of 20 cycles = 20 units Loss = SP of 2 cycles = 2 units

Cost Price (CP) = Total SP + Loss CP = 20 + 2 = 22 units

Loss % = (Loss / CP) × 100 Loss % = (2 / 22) × 100 = 100/11 % = 9 1/11 %

1420Mathematics
A politician distributed 285 kg of sugar among the people of a village counting 1487. Find out how much sugar does each person get.
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Answer: (C) 0.191 kg

Explanation

Amount of sugar received by each person = Total sugar ÷ Total population

Substituting the given values: Amount per person = 285 kg ÷ 1487 = 0.19166... kg ≈ 0.191 kg

1421Mathematics
A sum borrowed at 6% p.a earns an interest which is 1 / 3ʳᵈ of its principal in x years. Find x.
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Answer: (A) 5⁵⁄₉

Explanation

Simple interest formula is SI = (P × R × x) / 100.

Given that SI = P / 3 and R = 6%: P / 3 = (P × 6 × x) / 100 1 / 3 = 6x / 100 x = 100 / 18 = 50 / 9 = 5 5/9 years.

1422Mathematics
Yash sells vegetables at 40 per kg and incurs a loss of 10% . If the total loss incurred is 144, what is the weight of vegetables sold? (Rounded off)
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Answer: (B) 32.40kg

Explanation

Selling price (SP) is 90% of the cost price (CP) due to a 10% loss. CP per kg = 40 / 0.9 = 400/9 per kg.

Loss per kg = CP - SP = (400/9) - 40 = 40/9 per kg.

Weight of vegetables sold = Total loss / Loss per kg = 144 / (40/9) = (144 × 9) / 40 = 32.40 kg.

1423Mathematics
08 tonne = ? kg
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Answer: (C) 1080

Explanation

1 metric tonne is equal to 1000 kg.

Converting 1.08 tonnes into kilograms using this standard relation: 1.08 × 1000 = 1080 kg

1424Mathematics
Solve: 1 + tan²θ = ?
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Answer: (B) sec²θ

Explanation

By the standard Pythagorean trigonometric identity, 1 + tan²θ = sec²θ. This can also be derived by dividing the fundamental identity sin²θ + cos²θ = 1 by cos²θ, giving (sin²θ / cos²θ) + (cos²θ / cos²θ) = 1 / cos²θ, which simplifies to tan²θ + 1 = sec²θ.

1425Mathematics
If x is an even number, what is the consecutive odd number?
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Answer: (B) x+1

Explanation

Consecutive integers on the number line alternate between even and odd with a common difference of 1. Therefore, for any given even number x, the immediate next consecutive odd number is obtained by adding 1, which gives x + 1.

1426Mathematics
How many litres of water can be stored in a tank of 1m length, ½m breadth, and ½m tall?
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Answer: (B) 250

Explanation

Volume of a rectangular tank = length × breadth × height V = 1 m × ½ m × ½ m = ¼ m³ = 0.25 m³

Since 1 m³ = 1,000 litres: Capacity in litres = 0.25 × 1,000 = 250 litres

1427Mathematics
Jane won a lottery and gets 1 / 3ʳᵈ of the winning amount and donates Rs. 6000 which is 1 / 6ᵗʰ , find how much the lottery was worth.
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Answer: (D) 108000

Explanation

Let L be the total worth of the lottery.

Jane receives a share equal to L / 3. She donates 1/6 of her received share, which is given as Rs. 6000:

(1/6) × (L / 3) = 6000 L / 18 = 6000 L = 6000 × 18 = 108,000

1428Mathematics
Find the difference between the place value and face value of the digit 9 in the number 229301?
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Answer: (B) 8991

Explanation

In the number 229301, the digit 9 is at the thousands place.

Place value of 9 = 9 × 1000 = 9000 Face value of 9 = 9

Difference = Place value - Face value = 9000 - 9 = 8991

1429Mathematics
The sum of two numbers is 437 and their product is 21982. Find the numbers.
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Answer: (C) 58 and 379

Explanation

Let the two numbers be x and y. Any two numbers with a known sum S and product P are the roots of the quadratic equation t² - St + P = 0.

t² - 437t + 21982 = 0

Applying the quadratic formula: t = (437 ± √(437² - 4 × 21982)) / 2 t = (437 ± √(190969 - 87928)) / 2 t = (437 ± √103041) / 2 t = (437 ± 321) / 2

Solving for both roots: t₁ = (437 + 321) / 2 = 379 t₂ = (437 - 321) / 2 = 58

1430Mathematics
A bank agrees to lend a loan to Arvind of Rs. 2,38,75,697 which falls short by 17% for starting his business. How much more loan would he need?
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Answer: (A) 4890203

Explanation

Let the total amount required to start the business be T. Since the approved loan of ₹2,38,75,697 falls short by 17%, it represents 83% of the total required amount.

83% of T = ₹2,38,75,697

1% of T = 2,38,75,697 / 83 = ₹2,87,659

The additional loan amount needed by Arvind is the remaining 17% of T: 17% of T = 2,87,659 × 17 = ₹48,90,203

1431Mathematics
A piece of wire is bent to form a circle with a radius of 70~cm . If the same piece of wire is bent to form a square, the length of the side of the square will be ²²⁄₇ . [Use π = ²²⁄₇ ]
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Answer: (B) 110cm

Explanation

The total length of the wire remains constant whether it forms a circle or a square.

Length of wire = Circumference of circle = 2 × π × r = 2 × (22/7) × 70 = 440 cm

Since the perimeter of the square equals the length of the wire: 4 × side = 440 cm side = 440 / 4 = 110 cm

1432Mathematics
If the selling price of an article is ⁵⁄₄ of its cost price, then the profit obtained in the transaction is:
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Answer: (D) 25%

Explanation

Profit percentage is given by the formula: Profit % = [(SP - CP) / CP] × 100

Given SP = (5/4) CP, the ratio of selling price to cost price is: SP / CP = 5 / 4

Substituting these values into the formula: Profit % = [(5 - 4) / 4] × 100 = (1 / 4) × 100 = 25%

1433Mathematics
In an examination, 90% of the students passed and 600 students failed. How many students appeared for the examination?
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Answer: (C) 6000

Explanation

Since 90% of the students passed, the percentage of students who failed is 100% - 90% = 10%.

Let T be the total number of students who appeared for the examination.

10% of T = 600 (10 / 100) × T = 600 T = (600 × 100) / 10 = 6000

1434Mathematics
A gold ring is sold for ₹17,500 at a loss of 30% . What is the cost price of the gold ring?
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Answer: (B) ₹25,000

Explanation

Cost Price = Selling Price × 100 / (100 - Loss%)

Given, Selling Price = ₹17,500 and Loss = 30%.

Cost Price = 17,500 × 100 / (100 - 30) = 17,500 × 100 / 70 = 250 × 100 = ₹25,000

1435Mathematics
Which of the following fractions does NOT lie between ⁷⁄₁₈ and ⅗ ?
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Answer: (D) ⅓

Explanation

Converting the boundary fractions to decimal form: 7/18 ≈ 0.389 3/5 = 0.600

For a fraction to lie between 7/18 and 3/5, its decimal value must be greater than 0.389 and less than 0.600.

Converting 1/3 to decimal form gives 1/3 ≈ 0.333. Since 0.333 < 0.389, 1/3 is less than 7/18 and lies outside the given range.

1436Mathematics
Which of the following is closest to zero?
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Answer: (D) (0.09)²

Explanation

Evaluating the expression gives (0.09)² = 0.0081. Since 0.0081 is less than 0.009, 0.8281, and 0.9919, its distance from zero is the smallest.

1437Mathematics
The angles of depression of two houses of the same height from the top of a building are 45° and 30° towards the east. If the two houses are 50~m apart, what will be the height of the building in metres?
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Answer: (C) 25(√3 +1)

Explanation

Let h be the height of the building relative to the top of the houses, and d be the distance of the nearer house from the building.

For the nearer house with angle of depression 45°: tan 45° = h / d 1 = h / d d = h

For the farther house with angle of depression 30°: tan 30° = h / (d + 50) 1 / √3 = h / (h + 50)

Solving for h: h + 50 = h√3 h(√3 - 1) = 50 h = 50 / (√3 - 1)

Rationalizing the denominator: h = 50(√3 + 1) / ((√3 - 1)(√3 + 1)) h = 50(√3 + 1) / 2 h = 25(√3 + 1) m

1438Mathematics
44% of a number is 798.6. What is 63% of that number?
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Answer: (D) 1143.45

Explanation

Using the direct proportion method:

Required value = (798.6 / 44) × 63

798.6 ÷ 44 = 18.15

18.15 × 63 = 1143.45

1439Mathematics
In an isosceles Δ ABC , if the measure of ∠ A is twice that of the base ∠ B , then the measure of ∠ C will be:
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Answer: (A) 45°

Explanation

In an isosceles triangle, the two base angles are equal, so ∠C = ∠B. Given that the measure of ∠A is twice that of the base angle ∠B, we have ∠A = 2∠B.

Using the angle sum property of a triangle: ∠A + ∠B + ∠C = 180° 2∠B + ∠B + ∠B = 180° 4∠B = 180° ∠B = 45°

Since ∠C = ∠B, the measure of ∠C is 45°.

1440Mathematics
The perimeter of a rectangle is 120m . If its length is twice its breadth, then its area is:
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Answer: (D) 800m2

Explanation

Let the breadth of the rectangle be b. Since the length l is twice its breadth, l = 2b.

The perimeter of a rectangle is given by the formula P = 2(l + b).

Substituting the given values: 2(2b + b) = 120 6b = 120 b = 20 m

Thus, length l = 2 × 20 = 40 m.

Area of the rectangle = l × b = 40 × 20 = 800 m².

1441Mathematics
Find the least number that when divided by 9, 8, 10 and 12 leaves a remainder of 3 in each case.
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Answer: (C) 363

Explanation

The required least number is given by LCM(9, 8, 10, 12) + 3.

Prime factorization of the given divisors: 9 = 3² 8 = 2³ 10 = 2 × 5 12 = 2² × 3

LCM(9, 8, 10, 12) = 2³ × 3² × 5 = 8 × 9 × 5 = 360.

Required number = 360 + 3 = 363.

1442Mathematics
How many cubes of side 3cm can be formed by melting a cuboid of length 9cm breadth 6cm and height 6cm
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Answer: (B) 12

Explanation

Number of cubes = Volume of cuboid / Volume of a cube

Volume of cuboid = length × breadth × height = 9 × 6 × 6 = 324 cm³ Volume of a cube = side³ = 3³ = 27 cm³

Number of cubes = 324 / 27 = 12

1443Mathematics
The sum of the consecutive angles of a parallelogram is equal to:
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Answer: (D) 180°

Explanation

In a parallelogram, opposite sides are parallel. When two parallel lines are cut by a transversal, the interior angles on the same side of the transversal (consecutive angles) are supplementary. Therefore, the sum of any two consecutive angles of a parallelogram is equal to 180°.

1444Mathematics
The sum and difference of the LCM and HCF of two numbers are 682 and 638 respectively. If the sum of the two numbers is 286, find the numbers.
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Answer: (B) 220 and 66

Explanation

Let L and H be the LCM and HCF of the two numbers.

L + H = 682 L - H = 638

Solving these equations: 2L = 1320 ⇒ L = 660 2H = 44 ⇒ H = 22

Let the two numbers be 22a and 22b, where a and b are co-prime integers. Given sum = 22(a + b) = 286 ⇒ a + b = 13. Product of co-prime factors a × b = LCM / HCF = 660 / 22 = 30.

The pair of co-prime integers satisfying a + b = 13 and a × b = 30 is 10 and 3. The two numbers are 22 × 10 = 220 and 22 × 3 = 66.

1445Mathematics
Ram bought five bananas for 20 and sold them at the rate of three for 15. Find his gain percentage.
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Answer: (A) 25%

Explanation

Cost Price (CP) of 1 banana = ₹20 / 5 = ₹4 Selling Price (SP) of 1 banana = ₹15 / 3 = ₹5

Gain Percentage = [(SP - CP) / CP] × 100 = [(5 - 4) / 4] × 100 = (1 / 4) × 100 = 25%

1446Mathematics
A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the ground. Find the length of the ladder.
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Answer: (A) 6.5m

Explanation

By the Pythagorean theorem, for a right-angled triangle formed by the wall, the ground, and the ladder:

Length of ladder² = (Distance from wall)² + (Height of window)²

Length of ladder² = (2.5)² + 6² Length of ladder² = 6.25 + 36 = 42.25 Length of ladder = √42.25 = 6.5 m

1447Mathematics
If X's income is 40% less than that of Y, then Y's income is approximately what percentage more than that of X?
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Answer: (D) 66.67%

Explanation

Percentage increase = [r / (100 - r)] × 100%

Substituting r = 40: Percentage increase = [40 / (100 - 40)] × 100 = (40 / 60) × 100 = 200/3 % ≈ 66.67%

Alternatively, assuming Y's income is 100, X's income becomes 60. Y's income is 40 more than X's income, making it (40 / 60) × 100 = 66.67% more than X's income.

1448Mathematics
What is the median of the following data? 78,56,22,34,45,54,39,68,54,84
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Answer: (C) 54

Explanation

To find the median, arrange the given dataset of 10 numbers in ascending order:

22, 34, 39, 45, 54, 54, 56, 68, 78, 84

Since the number of observations n = 10 is even, the median is the average of the 5th and 6th terms:

Median = (5th term + 6th term) / 2 = (54 + 54) / 2 = 54

1449Mathematics
If p is the length of a rectangle and its width is one-third of its length, then the area of the rectangle will be:
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Answer: (A) (p²)/(3)

Explanation

Length of the rectangle = p Width of the rectangle = p/3

Area of a rectangle = Length × Width = p × (p/3) = p²/3

1450Mathematics
Find the mean of x + 77 x + 7 x + 5 x + 3 and x - 2
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Answer: (D) x + 18

Explanation

Mean = (Sum of observations) ÷ (Total number of observations)

Sum of the 5 observations = (x + 77) + (x + 7) + (x + 5) + (x + 3) + (x - 2) = 5x + 90

Mean = (5x + 90) ÷ 5 = x + 18

Answer key

Tap a number to jump to that question.

  1. 1401B
  2. 1402C
  3. 1403A
  4. 1404A
  5. 1405B
  6. 1406C
  7. 1407D
  8. 1408A
  9. 1409D
  10. 1410B
  11. 1411D
  12. 1412B
  13. 1413A
  14. 1414D
  15. 1415B
  16. 1416D
  17. 1417B
  18. 1418C
  19. 1419D
  20. 1420C
  21. 1421A
  22. 1422B
  23. 1423C
  24. 1424B
  25. 1425B
  26. 1426B
  27. 1427D
  28. 1428B
  29. 1429C
  30. 1430A
  31. 1431B
  32. 1432D
  33. 1433C
  34. 1434B
  35. 1435D
  36. 1436D
  37. 1437C
  38. 1438D
  39. 1439A
  40. 1440D
  41. 1441C
  42. 1442B
  43. 1443D
  44. 1444B
  45. 1445A
  46. 1446A
  47. 1447D
  48. 1448C
  49. 1449A
  50. 1450D

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