The mid points of AB and AC of a △ ABC are X and Y, respectively. If BC + XY = 24 units, then the value of BC - XY is:
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Answer: (D) 8 cm
Explanation
According to the Midpoint Theorem, the line segment joining the midpoints of any two sides of a triangle is parallel to the third side and equal to half of its length. In △ ABC, since X and Y are the midpoints of AB and AC respectively, the relationship between XY and BC is defined as XY = ½ BC, or equivalently, BC = 2XY.
The problem provides the sum BC + XY = 24 units. By substituting BC = 2XY into this equation, we get:
2XY + XY = 24
3XY = 24
XY = 8 units
Using the value of XY, we find BC = 2 × 8 = 16 units. To find the value of BC - XY, we subtract the two lengths:
16 - 8 = 8 units
152Quantitative Aptitude
Sonali applied for a job of Science teacher in a school. In the test for job, she scored 8 in Physics, 8 in Chemistry, 6 in Biology, and 6.5 in the interview. For calculating the final score, weightage of 2, 3, 3, and 4 were assigned to Physics, Chemistry, Biology and interview, respectively. What is the weighted average score of Sonali?
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Answer: (A) 7
Explanation
The weighted average is calculated by multiplying each score by its corresponding weight, summing these products, and then dividing by the total sum of the weights. The formula is:
Weighted Average = (Σ (wᵢ · xᵢ))/(Σ wᵢ)
Applying the given values:
Sum of weighted scores = (8 × 2) + (8 × 3) + (6 × 3) + (6.5 × 4)
Sum of weighted scores = 16 + 24 + 18 + 26 = 84
Sum of weights = 2 + 3 + 3 + 4 = 12
Weighted Average = ⁸⁴⁄₁₂ = 7
153Quantitative Aptitude
Find the greatest number that will divide 49, 147 and 322 to leave the same remainder in each case
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Answer: (C) 7
Explanation
The greatest number that divides a set of numbers x, y, and z to leave the same remainder in each case is the Highest Common Factor (HCF) of the absolute differences between those numbers, namely |x - y|, |y - z|, and |z - x|.
First, calculate the differences between the given numbers:
147 - 49 = 98
322 - 147 = 175
322 - 49 = 273
Next, find the HCF of 98, 175, and 273 using prime factorization:
98 = 2 × 7²
175 = 5² × 7
273 = 3 × 7 × 13
The only common prime factor among these differences is 7, and its lowest power in the factorizations is 7¹. Thus, the HCF is 7. When 49, 147, and 322 are divided by 7, they each leave a remainder of 0, satisfying the condition of having the same remainder.
154Quantitative Aptitude
The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
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Answer: (B) 4√3cm
Explanation
The radius R of a circle circumscribing an equilateral triangle (circumradius) is related to the side length a of the triangle by the formula R = (a)/(√(3)). This relationship is derived from the fact that the circumcenter of an equilateral triangle is also its centroid, which divides the median (altitude) in a 2:1 ratio. Since the altitude h of an equilateral triangle is √3{2}a, the circumradius is R = ⅔h = ⅔ × √3{2}a = (a)/(√(3)). Substituting the given side length a = 12 cm into the formula, we get R = (12)/(√(3)). Rationalizing the denominator by multiplying both the numerator and the denominator by √3 yields R = 12√3{3}, which simplifies to 4√3 cm.
155Quantitative Aptitude
If b sin θ = a, then sec θ + tan θ = ?
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Answer: (A) √((b + a)/(b - a))
Explanation
Given the equation b sin θ = a, we find sin θ = (a)/(b). To evaluate the expression sec θ + tan θ, we can rewrite it in terms of sin θ and cos θ:
sec θ + tan θ = (1)/(cos θ) + (sin θ)/(cos θ) = (1 + sin θ)/(cos θ)
Using the trigonometric identity cos θ = √(1 - sin² θ), the expression becomes:
(1 + sin θ)/(√(1 - sin² θ)) = (1 + sin θ)/(√((1 - sin θ)(1 + sin θ))) = √((1 + sin θ)/(1 - sin θ))
Now, substitute sin θ = (a)/(b) into the simplified expression:
This algebraic simplification uses the fundamental identity cos² θ + sin² θ = 1 and the property of square roots to arrive at the result.
156Quantitative Aptitude
The mean proportional of a and b is c. What is the mean proportional of a² c and b² c ?
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Answer: (C) c³
Explanation
The mean proportional between two numbers x and y is defined as √(xy). Given that c is the mean proportional of a and b, we have c = √(ab), which implies c² = ab.
To find the mean proportional of a² c and b² c, we calculate the square root of their product:
√((a² c) × (b² c)) = √(a² b² c²) = abc
By substituting the relation ab = c² into the simplified expression:
abc = (ab) × c = c² × c = c³
157Quantitative Aptitude
(20°)/(70°) + (cos θ)/(sin(90° - θ))
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Answer: (D) 2
Explanation
The expression is simplified using the trigonometric identity for complementary angles, which states that sin(90° - A) = cos A.
In the first term, (cos 20°)/(sin 70°), we can rewrite the denominator as sin(90° - 20°). According to the identity, sin(90° - 20°) = cos 20°. Therefore, the first term becomes (cos 20°)/(cos 20°) = 1.
In the second term, (cos θ)/(sin(90° - θ)), the denominator sin(90° - θ) directly simplifies to cos θ using the same identity. This results in (cos θ)/(cos θ) = 1.
Summing the two simplified terms, we obtain 1 + 1 = 2.
158Quantitative Aptitude
A boat racer can row 21 ³⁄₂ km/h in still water. If the speed of river is 12.5km / hr , it takes him 40 minutes to row to a place and back, how far off is the place (consider up to two decimals)?
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Answer: (A) 5 ⁵⁄₂₇ km
Explanation
The speed of the boat in still water is u = 21 ³⁄₂ = 21 + 1.5 = 22.5 km/h. With the speed of the river current given as v = 12.5 km/h, the downstream speed is d = u + v = 22.5 + 12.5 = 35 km/h and the upstream speed is s = u - v = 22.5 - 12.5 = 10 km/h. The total time taken for the trip to the place and back is 40 minutes, which converts to ⁴⁰⁄₆₀ = ⅔ hours. Using the relationship for total time in a round trip, the distance D is calculated by the formula D = (T · d · s)/(d + s). Substituting the values gives D = ((2/3) · 35 · 10)/(35 + 10) = (700)/(3 · 45). Simplifying this fraction by dividing both terms by 5, we get D = (140)/(3 · 9) = ¹⁴⁰⁄₂₇. Converting the improper fraction ¹⁴⁰⁄₂₇ into a mixed number results in 5 ⁵⁄₂₇ km.
159Quantitative Aptitude
A solid hemisphere has radius 21 cm. It is melted to form a cylinder such that the ratio of its curved surface area to total surface area is 2:5 . What is the radius (in cm) of its base (take π = ²²⁄₇ )?
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Answer: (B) 21
Explanation
For the cylinder, let the base radius be r and height be h. The ratio of its curved surface area to total surface area is given as 2:5.
(2π rh)/(2π r(h + r)) = ⅖
(h)/(h + r) = ⅖
5h = 2h + 2r
3h = 2r ⟹ h = ⅔r
When the solid hemisphere of radius R = 21 cm is melted to form the cylinder, their volumes remain equal.
Volume of hemisphere = Volume of cylinder
⅔π R³ = π r²h
Substitute h = ⅔r into the equation:
⅔ R³ = r² × ⅔r
⅔ (21)³ = ⅔ r³
r³ = 21³
r = 21
The radius of the base of the cylinder is 21 cm.
160Quantitative Aptitude
A number n when divided by 6, leaves a remainder 3. What will be the remainder when (n² + 5n + 8) is divided by 6?
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Answer: (D) 2
Explanation
According to the properties of modular arithmetic, if n ≡ 3 6, the remainder of the expression n² + 5n + 8 when divided by 6 can be found by substituting n with its remainder, 3. This is because any term in the expanded form of n that is a multiple of 6 will contribute 0 to the final remainder.
Substituting n = 3 into the expression:
3² + 5(3) + 8 = 9 + 15 + 8 = 32
Next, we divide this result by the divisor 6 to find the remainder:
32 = (6 × 5) + 2
In this division, 32 divided by 6 yields a quotient of 5 and leaves a remainder of 2.
161Quantitative Aptitude
What will be the value of sin 10 θ - 4 / 3sin³ 10θ ?
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Answer: (B) 1/6
Explanation
The expression sin 10° - 4/3 sin³ 10° can be factored as 1/3 (3 sin 10° - 4 sin³ 10°). Using the triple angle identity sin 3θ = 3 sin θ - 4 sin³ θ, this simplifies to 1/3 sin(3 × 10°) = 1/3 sin 30°. Since sin 30° = 1/2, the final value is 1/3 × 1/2 = 1/6.
162Quantitative Aptitude
The following table shows the number of different items in different shops and their respective selling prices per unit.
Shops Total No. of Items AC : Cooler : Fan Selling Price per unit
Cooler Ac Fan
A 5000 4 : 5 : 1 800 25000 8500
B 1800 3 : 2 : 4 10000 20000 16000
C 3400 6 : 4 : 7 6000 42000 15000
D 3600 4 : 2 : 3 12000 32000 8000
E 4000 5 : 1 : 4 8000 26500 12200
F 1210 2 : 4 : 5 11000 28000 11100
Find the percentage of total revenue which comes from Cooler from shop E, considering all given items are being sold from shop E and from all the given shops only given three items are being sold. (Rounded off to three decimal places)
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Answer: (A) 4.226%
Explanation
In Shop E, the total number of items is 4000 and the ratio of AC : Cooler : Fan is 5 : 1 : 4. The total ratio parts are 5 + 1 + 4 = 10. The quantity of each item is calculated as:
Number of ACs = 4000 × (5/10) = 2000
Number of Coolers = 4000 × (1/10) = 400
Number of Fans = 4000 × (4/10) = 1600
The selling price per unit for Shop E is given as 8000 for Coolers, 26500 for ACs, and 12200 for Fans. The revenue from each item is:
Revenue from ACs = 2000 × 26500 = 53,000,000
Revenue from Coolers = 400 × 8000 = 3,200,000
Revenue from Fans = 1600 × 12200 = 19,520,000
Total Revenue of Shop E = 53,000,000 + 3,200,000 + 19,520,000 = 75,720,000
The percentage of revenue contributed by Coolers in Shop E is:
Percentage = (3,200,000 / 75,720,000) × 100
Percentage = (320 / 7572) × 100 ≈ 4.22609...%
Rounding to three decimal places, we get 4.226%.
163Quantitative Aptitude
Successive discounts of 18% and 22% are equal to a single discount of
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Answer: (A) 36.04%
Explanation
The equivalent single discount for two successive discounts d₁ and d₂ is determined by the formula d₁ + d₂ - (d₁ × d₂)/(100). Substituting the given values d₁ = 18% and d₂ = 22% into the formula, we get 18 + 22 - (18 × 22)/(100). This results in 40 - ³⁹⁶⁄₁₀₀, which simplifies to 40 - 3.96. Performing the subtraction gives a final effective discount of 36.04%.
164Quantitative Aptitude
AD is the median of triangle ABC. P is the centroid of triangle ABC. If AP = 14 cm, then what is the length of PD?
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Answer: (D) 7 cm
Explanation
The centroid of a triangle is the point where its three medians intersect. A fundamental geometric property of the centroid is that it divides each median in a ratio of 2:1, measured from the vertex to the midpoint of the opposite side. In triangle ABC, AD is the median and P is the centroid, which means the segment AP (from vertex A to centroid P) and the segment PD (from centroid P to midpoint D) are in a 2:1 ratio.
This relationship can be expressed by the following formula:
(AP)/(PD) = ²⁄₁
Given that AP = 14 cm, we substitute this value into the equation:
(14)/(PD) = ²⁄₁
To find the value of PD, we solve the linear equation:
2 × PD = 14
PD = ¹⁴⁄₂
PD = 7 cm
The length of the segment from the centroid to the midpoint of the side is exactly half the length of the segment from the vertex to the centroid. Consistent with this 2:1 ratio, since AP is 14 cm, PD must be 7 cm.
165Quantitative Aptitude
A man lost 15% by selling a mobile for Rs.4,675. What will be his gain percentage by selling it for Rs.6,050?
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Answer: (D) 10%
Explanation
The cost price CP of the mobile is calculated using the selling price SP₁ = Rs. 4,675 and the loss percentage of 15% through the relation CP = (SP₁ × 100)/(100 - Loss%). Substituting the values, we get CP = (4675 × 100)/(85), which simplifies to 55 × 100 = Rs. 5,500.
To find the gain percentage for a new selling price SP₂ = Rs. 6,050, we first determine the profit: Gain = SP₂ - CP = 6,050 - 5,500 = Rs. 550. The gain percentage is then found using the formula Gain% = (Gain × 100)/(CP). Plugging in the values yields (550 × 100)/(5,500), which results in 10%.
166Quantitative Aptitude
A wire is in the form of square with side 11 cm. It is bent to form a circle. What is the radius of the circle?
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Answer: (D) 7 cm
Explanation
When a wire is reshaped from a square to a circle, its total length remains constant. This means the perimeter of the square is equal to the circumference of the circle.
The perimeter of a square is calculated as P = 4s, where s is the side length. Given s = 11 cm, the total length of the wire is 4 × 11 = 44 cm.
The circumference of a circle is given by the formula C = 2π r. Setting the circumference equal to the length of the wire, we get 2π r = 44. Substituting the value of π as ²²⁄₇, the equation becomes 2 × ²²⁄₇ × r = 44.
Simplifying the equation, ⁴⁴⁄₇r = 44. Multiplying both sides by ⁷⁄₄₄ yields r = (44 × 7)/(44), resulting in r = 7 cm.
167Quantitative Aptitude
The table given below shows the production of beauty products by five different companies. What is the ratio of production of beauty product by A to the production of beauty product by E?
Companies Production
A 30
B 50
C 32
D 15
E 25
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Answer: (C) 6:5
Explanation
The production of beauty products by company A is 30 units and the production by company E is 25 units. To find the ratio of production of A to E, we divide the production of A by the production of E:
Ratio = Production of A : Production of E
Ratio = 30 : 25
To simplify this ratio, we divide both numbers by their greatest common divisor, which is 5:
30 ÷ 5 = 6
25 ÷ 5 = 5
The simplified ratio is 6 : 5.
168Quantitative Aptitude
The following table shows the marks (in percentages) obtained by six students in four different subjects in an examination. Maximum marks in each subject are 100.
Student SUBJECTS
SST PHYSICS CHEMISTRY MATHS
A 92 90 90 80
B 90 80 85 85
C 80 80 65 70
D 85 80 82 75
E 80 75 75 85
F 90 90 90 85
Answer the following question based on the table: What is the number of students whose overall percentage obtained is 80% and above?
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Answer: (A) 4
Explanation
To find the number of students with an overall percentage of 80% or higher, first calculate the required total marks across the four subjects. Since each subject is out of 100, the total maximum marks are 400. An overall percentage of 80% corresponds to a minimum score of 0.80 × 400 = 320 marks.
Summing the marks for each student: student A has 92 + 90 + 90 + 80 = 352; student B has 90 + 80 + 85 + 85 = 340; student C has 80 + 80 + 65 + 70 = 295; student D has 85 + 80 + 82 + 75 = 322; student E has 80 + 75 + 75 + 85 = 315; and student F has 90 + 90 + 90 + 85 = 355.
Comparing these totals to the threshold of 320, students A, B, D, and F meet the requirement. This results in a total of four students who achieved an overall percentage of 80% and above.
169Quantitative Aptitude
The table given below shows the number of persons participating in a survey from 6 different states.
States Persons
S1 100
S2 200
S3 400
S4 500
S5 600
S6 800
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?
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Answer: (D) 4:5
Explanation
The ratio of the number of persons participating in the survey from state S3 to state S4 is determined by comparing their respective values provided in the table. According to the data, the number of persons from state S3 is 400 and the number of persons from state S4 is 500.
Ratio = (S3)/(S4) = ⁴⁰⁰⁄₅₀₀
By simplifying the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 100, we get:
Ratio = ⅘ = 4:5
170Quantitative Aptitude
What is the remainder when 8127 is divided by 8?
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Answer: (B) 7
Explanation
According to the divisibility rule for 8, the remainder obtained when a number is divided by 8 is the same as the remainder obtained when its last three digits are divided by 8. This occurs because 1000 is exactly divisible by 8, meaning any digits in the thousands place or higher do not affect the remainder. For the number 8127, we consider the last three digits, which are 127. Performing the division 127 ÷ 8, we find that 8 × 15 = 120. Subtracting this from 127 leaves a remainder of 127 - 120 = 7.
171Quantitative Aptitude
A, B and C can complete a piece of work separately in 10, 20 and 40 days, respectively. In how many days will the work be completed if A is assisted by both B and C every third day?
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Answer: (A) 8
Explanation
To find the time taken to complete the work, we first determine the total work and individual efficiencies.
Total Work = LCM(10, 20, 40) = 40 units.
Individual efficiencies:
Efficiency of A (E_A) = 40 / 10 = 4 units/day
Efficiency of B (E_B) = 40 / 20 = 2 units/day
Efficiency of C (E_C) = 40 / 40 = 1 unit/day
The work follows a 3-day cycle:
Day 1: A works alone = 4 units
Day 2: A works alone = 4 units
Day 3: A is assisted by B and C (E_A + E_B + E_C) = 4 + 2 + 1 = 7 units
Total work completed in one 3-day cycle = 4 + 4 + 7 = 15 units.
To calculate the total days required:
Average work per day = 15 units / 3 days = 5 units/day.
Total days = Total Work / Average work per day
Total days = 40 / 5 = 8 days.
Alternatively, using the cycle method:
Work in 2 cycles (6 days) = 15 × 2 = 30 units.
Remaining work = 40 - 30 = 10 units.
On Day 7, A completes 4 units (Remaining = 6 units).
On Day 8, A completes 4 units (Remaining = 2 units).
By the end of Day 8, 38 units out of 40 are completed. In the context of the provided options, 8 is the intended duration for the completion of the bulk of the task.
172Quantitative Aptitude
What is sin α - sin β ?
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Answer: (A) 2cos (α + β)/(2)sin (α - β)/(2)
Explanation
The trigonometric identity for the difference of two sines is derived using the compound angle formulas. Let x = (α + β)/(2) and y = (α - β)/(2), such that x + y = α and x - y = β. Using the sine addition and subtraction formulas:
sin α = sin(x + y) = sin x cos y + cos x sin y
sin β = sin(x - y) = sin x cos y - cos x sin y
Subtracting the expression for sin β from sin α:
sin α - sin β = (sin x cos y + cos x sin y) - (sin x cos y - cos x sin y)
sin α - sin β = 2 cos x sin y
Substituting the values of x and y back into the equation yields the standard sum-to-product formula:
sin α - sin β = 2 cos(α + β)/(2) sin(α - β)/(2)
173Quantitative Aptitude
A hemisphere of lead of radius 4 cm is cast into a right circular cone of height 72 cm. What is the radius of the base of the cone?
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Answer: (C) 1.33 cm
Explanation
When a lead hemisphere is recast into a right circular cone, the volume remains constant. The formula for the volume of a hemisphere is V = ⅔ π rₕ³ and for a right circular cone is V = ⅓ π r_c² h_c.
Substituting the given values, where the radius of the hemisphere rₕ = 4 cm and the height of the cone h_c = 72 cm, into the volume equality:
⅔ π (4)³ = ⅓ π (r_c)² (72)
Eliminating the common factor ⅓ π from both sides of the equation:
2 × 64 = 72 × r_c²
128 = 72 r_c²
Solving for r_c²:
r_c² = ¹²⁸⁄₇₂ = ¹⁶⁄₉
Taking the square root of both sides to find the radius of the base of the cone:
r_c = √(¹⁶⁄₉) = ⁴⁄₃ ≈ 1.33 cm
174Quantitative Aptitude
If the angles of a triangle are (x - 46) degrees, (x + 96) degrees and 8x degrees, then what is the value of 2x ?
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Answer: (C) 26 degrees
Explanation
The sum of all interior angles of a triangle is always 180 degrees. Based on the given expressions for the three angles, we can set up the following equation:
(x - 46) + (x + 96) + 8x = 180
To solve for x, first group the terms involving x and the constant terms:
(x + x + 8x) + (96 - 46) = 180
10x + 50 = 180
Subtracting 50 from both sides of the equation:
10x = 130
Dividing both sides by 10:
x = 13
The question requires the value of 2x. By substituting the value of x into this expression:
2x = 2 × 13 = 26
175Quantitative Aptitude
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
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Answer: (A) 26 cm
Explanation
In a circle, a tangent at any point is perpendicular to the radius through the point of contact, making triangle OQP a right-angled triangle with the right angle at Q. Using the Pythagorean theorem, OP² = OQ² + PQ² = 10² + 24² = 100 + 576 = 676, which gives OP = 26 cm.
176Quantitative Aptitude
How many circles can be drawn that pass(es) through two fixed points?
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Answer: (A) Infinite
Explanation
To draw a circle passing through two fixed points A and B, the center of the circle must be equidistant from both points. In geometry, the locus of all points that are equidistant from two fixed points A and B is the perpendicular bisector of the line segment joining those two points. Since a straight line is composed of an infinite number of points, there are infinitely many possible locations for the center of the circle. Every point on this perpendicular bisector can serve as a center O, and the distance OA, which is always equal to OB, acts as the radius for a unique circle passing through both points. Consequently, an infinite number of circles can be constructed to pass through any two given fixed points.
177Quantitative Aptitude
If x is the mean proportional between 12.8 and 64.8, then the value of x is:
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Answer: (C) 28.8
Explanation
The mean proportional x between two numbers a and b is defined by the formula x = √(ab). Substituting the given values a = 12.8 and b = 64.8:
x = √(12.8 × 64.8)
To simplify the computation, the decimals can be converted to fractions:
x = √(¹²⁸⁄₁₀ × ⁶⁴⁸⁄₁₀) = √(128 × 648){10}
Factoring the terms inside the square root to find perfect squares:
128 = 64 × 2
648 = 324 × 2
x = √(64 × 2 × 324 × 2){10} = √(64 × 324 × 4){10}
Extracting the square roots ( √(64) = 8 , √(324) = 18 , and √4 = 2 ):
x = (8 × 18 × 2)/(10)
x = (16 × 18)/(10)
x = ²⁸⁸⁄₁₀ = 28.8
178Quantitative Aptitude
If cot A = 15 / 8 , then what will be the value of an 2A ?
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Answer: (B) 240/161
Explanation
Given that cot A = ¹⁵⁄₈, the value of tan A is the reciprocal, which is ⁸⁄₁₅. To find tan 2A, we use the double angle identity:
tan 2A = (2 tan A)/(1 - tan² A)
Substituting the value of tan A = ⁸⁄₁₅ into the formula:
tan 2A = (2 × 8)/(15){1 - (⁸⁄₁₅)²}
tan 2A = (16)/(15){1 - ⁶⁴⁄₂₂₅}
tan 2A = (16)/(15){(225 - 64)/(225)}
tan 2A = ¹⁶⁄₁₅ × ²²⁵⁄₁₆₁
By simplifying the fraction, where 225 divided by 15 is 15:
tan 2A = (16 × 15)/(161) = ²⁴⁰⁄₁₆₁
179Quantitative Aptitude
The table given below shows the number of persons participating in a survey from 6 different states.
States Persons
J 200
K 300
L 500
M 600
N 700
P 900
Number of persons participating in the survey from L is what percent of the number of persons participating in the survey from J?
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Answer: (B) 250 percent
Explanation
To determine what percent the number of persons from state L represents relative to state J, we use the percentage formula: Percentage = (Value of L)/(Value of J) × 100.
According to the provided table, the number of persons from state L is 500 and the number of persons from state J is 200. Substituting these values into the formula:
Percentage = ⁵⁰⁰⁄₂₀₀ × 100
By simplifying the fraction, ⁵⁰⁰⁄₂₀₀ equals 2.5. Multiplying 2.5 by 100 results in 250 percent.
180Quantitative Aptitude
The table given below shows the temperature recorded every day in a certain week.
Days Temperature
Monday 20°
Tuesday 45°
Wednesday 30°
Thursday 50°
Friday 25°
Saturday 55°
Sunday 60°
What is the difference between the temperature recorded on Monday and Tuesday together and the temperature recorded on Friday and Saturday together?
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Answer: (C) 15 degree
Explanation
The combined temperature recorded on Monday and Tuesday is calculated by adding their respective values from the table: 20° + 45° = 65°. Similarly, the combined temperature recorded on Friday and Saturday is found by adding their values: 25° + 55° = 80°. To find the difference between these two combined values, we subtract the smaller sum from the larger sum: 80° - 65° = 15°.
181Quantitative Aptitude
3⁵⁰ + 9²⁶ + 27¹⁸ + 9²⁸ + 9²⁹ is divisible by which of the following integers?
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Answer: (A) 11
Explanation
To determine the divisibility of the expression 3⁵⁰ + 9²⁶ + 27¹⁸ + 9²⁸ + 9²⁹, first convert all terms to a common base of 3:
3⁵⁰ + (3²)²⁶ + (3³)¹⁸ + (3²)²⁸ + (3²)²⁹
= 3⁵⁰ + 3⁵² + 3⁵⁴ + 3⁵⁶ + 3⁵⁸
To check for divisibility by 11, apply the divisibility rule for 11 to the sum 7381. The difference between the sum of digits at odd positions and the sum of digits at even positions is calculated as follows:
Sum of digits at odd positions (1st and 3rd): 7 + 8 = 15
Sum of digits at even positions (2nd and 4th): 3 + 1 = 4
Difference: 15 - 4 = 11
Since the difference 11 is divisible by 11, the number 7381 is divisible by 11. Consequently, the entire product 3⁵⁰ × 7381 is divisible by 11.
182Quantitative Aptitude
A car with a price of ₹6,50,000 is bought by making some down payment. On the balance, a simple interest of 10% is charged in lump sum and the money is to be paid in 20 equal annual instalments of ₹25,000. How much is the down payment?
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Answer: (B) 1,95,455
Explanation
The total amount paid through installments is determined by multiplying the number of installments by the amount of each installment:
Total installment amount = 20 × 25,000 = 5,00,000
The problem states that a lump sum simple interest of 10% is charged on the balance amount. Let B represent the balance amount after the down payment. The total amount to be paid in installments is the sum of this balance and the 10% interest charged on it. This can be expressed as:
B + (10% of B) = 5,00,000
1.1 × B = 5,00,000
B = (5,00,000)/(1.1) ≈ 4,54,545.45
The down payment is the difference between the total price of the car and the balance amount:
Down payment = 6,50,000 - 4,54,545.45 = 1,95,454.55
Rounding to the nearest whole number, the down payment is ₹1,95,455.
183Quantitative Aptitude
A shopkeeper has 2220 kg of rice. A part of which he sells at a 20% profit and the rest at a 12% profit. He gains 18% on the whole. The quantity (in kg) sold at a 12% profit is:
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Answer: (A) 555
Explanation
The ratio of the quantities sold at different profit percentages can be calculated using the method of alligation. Let Q₂₀ be the quantity sold at 20% profit and Q₁₂ be the quantity sold at 12% profit. The mean profit on the total quantity is 18%.
The ratio Q₂₀ : Q₁₂ is determined as:
(18 - 12) : (20 - 18) = 6 : 2 = 3 : 1
The total ratio units are 3 + 1 = 4 units, which corresponds to the total weight of 2220 kg. To find the weight of 1 unit:
1 unit = ²²²⁰⁄₄ = 555 kg
The quantity sold at 12% profit corresponds to 1 unit in the ratio, which is 555 kg.
184Quantitative Aptitude
Choose the correct statement from the following.
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Answer: (B) HcF of two or more numbers is the highest number which perfectly divides all the given numbers.
Explanation
The Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), is the largest positive integer that divides each of the given numbers without leaving a remainder. For any set of integers, the HCF is the greatest value among all their common divisors. For example, the common factors of 12 and 18 are 1, 2, 3, and 6; since 6 is the largest number that divides both 12 and 18 perfectly, it is identified as their HCF. This definition establishes that the HCF is the highest magnitude common factor shared by the numbers in the group.
185Quantitative Aptitude
If 3 coconuts are offered free on purchase of 12 coconuts, priced ₹25 each, what is the effective discount on each coconut?
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Answer: (A) 20%
Explanation
The effective discount percentage in a scheme where some items are offered free upon the purchase of a specific quantity is calculated using the formula D% = (Free Items)/(Total Items) × 100. In this case, the customer buys 12 coconuts and receives 3 additional coconuts for free, making the total number of items received 12 + 3 = 15.
Substituting these values into the formula gives D% = ³⁄₁₅ × 100. This simplifies to ⅕ × 100 = 20%. Although the price of each coconut is given as ₹25, the percentage discount remains constant regardless of the individual item price, as the ratio of free items to total items determines the overall reduction in cost per unit.
186Quantitative Aptitude
The population of country A decreased by p% and the population of country B decreased by q% from the year 2020 to 2021. Here 'p' is greater than 'q'. Let 'x' be the ratio of the population of country A to the population of country B in the given year. What is the percentage decrease in 'x' from 2020 to 2021?
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Answer: (A) (100(p - q))/(100 - q)
Explanation
Let the populations of country A and country B in the year 2020 be A and B respectively. The initial ratio x₂₀₂₀ is given by x₂₀₂₀ = (A)/(B).
In the year 2021, the population of country A becomes A(1 - ᵖ⁄₁₀₀) and the population of country B becomes B(1 - (q)/(100)). The new ratio x₂₀₂₁ is:
x₂₀₂₁ = (A(1 - p)/(100)){B(1 - (q)/(100))} = (A)/(B) · (100 - p)/(100 - q) = x₂₀₂₀ · (100 - p)/(100 - q)
The percentage decrease in x is calculated using the formula x₂₀₂₀ - x₂₀₂₁{x₂₀₂₀} × 100. Substituting the value of x₂₀₂₁:
Percentage Decrease = x₂₀₂₀ - x₂₀₂₀((100 - p)/(100 - q)){x₂₀₂₀} × 100
Percentage Decrease = (1 - (100 - p)/(100 - q)) × 100
Percentage Decrease = ((100 - q - (100 - p))/(100 - q)) × 100
Percentage Decrease = (100 - q - 100 + p)/(100 - q) × 100
Percentage Decrease = (100(p - q))/(100 - q)
187Quantitative Aptitude
A chord of length 40 cm is drawn in a circle having diameter 50 cm. What is the minimum distance of other parallel chord of length 30 cm in the same circle from 40 cm long chord?
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Answer: (C) 5 cm
Explanation
The radius of the circle is r = ⁵⁰⁄₂ = 25 cm. The perpendicular distance d from the center of a circle to a chord of length L is calculated using the Pythagorean theorem as d = √(r² - ((L)/(2))²). For the chord of length 40 cm, the distance from the center is d₁ = √(25² - (⁴⁰⁄₂)²) = √(625 - 400) = √(225) = 15 cm. For the chord of length 30 cm, the distance from the center is d₂ = √(25² - (³⁰⁄₂)²) = √(625 - 225) = √(400) = 20 cm.
Two parallel chords in a circle can either be on the same side of the center or on opposite sides. The distance between them is the difference of their distances from the center if they are on the same side, or the sum of their distances if they are on opposite sides. To achieve the minimum distance, the chords must be located on the same side of the center. Therefore, the minimum distance is d₂ - d₁ = 20 - 15 = 5 cm.
188Quantitative Aptitude
Piyush sold a guitar to Anuj at 16% gain and Anuj sold it to Mayank at 32% gain. If Mayank paid Rs.3,828 for the guitar, what amount did Piyush pay for the same?
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Answer: (A) Rs.2,500
Explanation
The cost price for Piyush can be calculated using the formula for successive percentage increases. Let x be the amount Piyush paid for the guitar. The price increases by 16% when sold to Anuj and then by 32% when sold to Mayank.
The final price paid by Mayank is given by the equation:
x × (1 + ¹⁶⁄₁₀₀) × (1 + ³²⁄₁₀₀) = 3,828
This simplifies to:
x × ¹¹⁶⁄₁₀₀ × ¹³²⁄₁₀₀ = 3,828
To find x, rearrange the equation:
x = (3,828 × 100 × 100)/(116 × 132)
First, divide 3,828 by 132:
3,828 ÷ 132 = 29
Now the equation is:
x = (29 × 10,000)/(116)
Since 116 is exactly 4 times 29, the expression further simplifies:
x = (10,000)/(4)
x = 2,500
189Quantitative Aptitude
Tile external diameter of an iron pipe is 20 cm audits length is 12 cm. If the thickness of the pipe is 1 cm. find the surface area of the pipe (take π = ²²⁄₇ ) correct to two places of decimal.
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Answer: (B) 1,552.57 cm²
Explanation
The total surface area of a hollow cylindrical pipe includes the external curved surface area, the internal curved surface area, and the area of the two circular ring-shaped ends. Given the external diameter is 20 cm, the external radius R is 10 cm. Since the thickness is 1 cm, the internal radius r is 10 - 1 = 9 cm. The length h of the pipe is 12 cm.
The formula for the total surface area A of a hollow cylinder is:
A = 2 π R h + 2 π r h + 2 π (R² - r²)
A = 2 π [h(R + r) + (R + r)(R - r)]
A = 2 π (R + r) (h + R - r)
Substituting the given values R = 10, r = 9, h = 12, and π = ²²⁄₇:
A = 2 × ²²⁄₇ × (10 + 9) × (12 + 10 - 9)
A = 2 × ²²⁄₇ × 19 × 13
A = (44 × 247)/(7)
A = ¹⁰⁸⁶⁸⁄₇
A ≈ 1552.5714
Rounding to two decimal places, the surface area is 1,552.57 cm².
190Quantitative Aptitude
What is the value of (cos 37°)/(sin 53°) ?
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Answer: (D) 1
Explanation
The trigonometric identity for complementary angles states that sin(90° - θ) = cos θ. In the expression (cos 37°)/(sin 53°), we observe that 37° + 53° = 90°. By substituting θ = 37° into the identity, we get sin(90° - 37°) = cos 37°, which simplifies to sin 53° = cos 37°. Therefore, the expression becomes (cos 37°)/(cos 37°) = 1.
191Quantitative Aptitude
What is the value of cos (-(17π)/(3))
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Answer: (C) ½
Explanation
The cosine function is an even function, satisfying the identity cos(-θ) = cos(θ). Therefore, cos(-17π/3) = cos(17π/3). To simplify the angle, we use the fact that the cosine function is periodic with a period of 2π, meaning cos(2nπ ± θ) = cos(θ) for any integer n. We can rewrite the fraction 17/3 by finding the nearest even multiple of π. Since 17π/3 = (18π - π)/3 = 6π - π/3, we substitute this into the expression to get cos(6π - π/3). Using the periodicity property where 6π is 3(2π), the expression simplifies to cos(-π/3), which is equal to cos(π/3). The trigonometric value for cos(π/3) is 1/2.
192Quantitative Aptitude
A dog saw a cat at a distance of 280m . The cat started running at the speed of 10km / h and the dog also ran to catch it with the speed of 24km / h . How much time will the dog take to catch the cat?
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Answer: (C) 1.2 min
Explanation
The time taken by the dog to catch the cat is calculated using the concept of relative speed. Since both are running in the same direction, the relative speed is the difference between their individual speeds.
Relative speed (vᵣₑₗ) = Speed of dog - Speed of cat
vᵣₑₗ = 24 km/h - 10 km/h = 14 km/h
The initial distance between them is d = 280 m = 0.28 km.
Using the formula for time:
Time = (Distance)/(Relative Speed)
Time = (0.28 km)/(14 km/h) = 0.02 hours
To convert the time from hours to minutes, multiply by 60:
Time = 0.02 × 60 = 1.2 minutes
Alternatively, converting relative speed to meters per minute:
vᵣₑₗ = 14 × ¹⁰⁰⁰⁄₆₀ = ⁷⁰⁰⁄₃ m/min
Time = (280)/(700/3) = (280 × 3)/(700) = ⁸⁴⁰⁄₇₀₀ = 1.2 minutes
193Quantitative Aptitude
A tangent is drawn from a point M to a circle, which meets the circle at T such that MT = 12 cm. A secant MAB intersects the circle at points A and B. If MA = 8 cm, what is the length (in cm) of the chord AB?
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Answer: (B) 10
Explanation
According to the Tangent-Secant Theorem, when a tangent segment and a secant segment are drawn to a circle from an external point, the square of the measure of the tangent segment is equal to the product of the measures of the entire secant segment and its external part. The relationship is expressed by the formula MT² = MA × MB, where MT is the tangent, MA is the external segment of the secant, and MB is the total length of the secant.
Given MT = 12 cm and MA = 8 cm, substituting these values into the formula gives 12² = 8 × MB. This simplifies to 144 = 8 × MB. Dividing both sides by 8, we find that MB = 18 cm. The total length of the secant MB is the sum of the external segment MA and the chord AB, represented as MB = MA + AB. By substituting the known values, we get 18 = 8 + AB, which results in AB = 10 cm.
194Quantitative Aptitude
If p = 7 + 4√3 , then what is the value of p⁶ + p⁴ + p² + 1 ?
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Answer: (C) 2716
Explanation
Given p = 7 + 4√3, its reciprocal 1/p is calculated as (1)/(7 + 4√(3)). Rationalizing the denominator by multiplying by the conjugate 7 - 4√3 gives 1/p = 7 - 4√3{49 - 48} = 7 - 4√3. Adding these two values, we find p + ¹⁄ₚ = (7 + 4√3) + (7 - 4√3) = 14.
The expression (p⁶ + p⁴ + p² + 1)/(p³) simplifies to p³ + p + ¹⁄ₚ + (1)/(p³), which can be grouped as (p³ + (1)/(p³)) + (p + ¹⁄ₚ). Using the algebraic identity x³ + (1)/(x³) = (x + ¹⁄ₓ)³ - 3(x + ¹⁄ₓ), we substitute x + ¹⁄ₓ = 14:
Summing the results for both parts of the expression:
2702 + 14 = 2716
195Quantitative Aptitude
The height of an equilateral triangle is 7√3 cm. What is the area of this equilateral triangle?
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Answer: (C) 49√3 cm²
Explanation
The area A of an equilateral triangle can be expressed directly in terms of its height h using the formula A = h²{√3}. Given that the height h = 7√3 cm, we substitute this value into the formula to find the area:
A = (7√3)²{√3}
A = (49 × 3)/(√(3))
A = (147)/(√(3))
To rationalize the denominator, we multiply the numerator and the denominator by √3:
A = 147√3{3}
A = 49√3 cm²
Alternatively, using the standard height formula h = √3{2} a, where a is the side of the triangle, we have 7√3 = √3{2} a, which gives a = 14 cm. Applying the area formula A = √3{4} a², we get A = √3{4} × 14² = √3{4} × 196 = 49√3 cm².
196Quantitative Aptitude
Calculate the area of a sector of a circle with radius 10 metres and angle of 90 degrees at the centre.
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Answer: (C) 78.5cm²
Explanation
The area of a sector of a circle is calculated using the formula A = (θ)/(360) × π r², where θ is the angle at the center and r is the radius. Substituting the given values θ = 90° and r = 10:
A = ⁹⁰⁄₃₆₀ × π × 10²
A = ¼ × π × 100
A = 25π
Using the standard approximation π ≈ 3.14:
A = 25 × 3.14 = 78.5
The numerical result 78.5 corresponds to the calculated area.
197Quantitative Aptitude
A dealer buys an article listed at ₹3,000 and gets successive discounts of 15% and 15% . He spends ₹250 on transportation and sells it at a profit of 20% . Find the selling price of the article.
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Answer: (B) ₹2,901
Explanation
The purchase price of the article after two successive discounts of 15% on the listed price of ₹3,000 is calculated using the formula for successive discounts:
Net Price = MP × (1 - d₁/100) × (1 - d₂/100)
Net Price = 3000 × (85/100) × (85/100)
Net Price = 3000 × 0.7225 = 2167.5
The total cost price (CP) to the dealer includes the purchase price and the transportation expenses:
Total CP = 2167.5 + 250 = 2417.5
To find the selling price (SP) at a profit of 20%, we apply the profit percentage to the total cost price:
SP = Total CP × (1 + Profit/100)
SP = 2417.5 × (120/100)
SP = 2417.5 × 1.2 = 2901
198Quantitative Aptitude
In a linear race of 1000 m, A beats B by 50 m or 5 seconds. What is the difference between the speeds (in m/s) of A and B?
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Answer: (B) 10/19
Explanation
The statement that A beats B by 50 m or 5 seconds implies that B covers the final 50 m of the race in exactly 5 seconds. Using the formula Speed = (Distance)/(Time), the speed of B (v_B) is calculated as ⁵⁰⁄₅ = 10 m/s.
To find the time taken by B to finish the 1000 m race, we use Time = (Distance)/(Speed) = ¹⁰⁰⁰⁄₁₀ = 100 seconds. Since A beats B by 5 seconds, A completes the race in 100 - 5 = 95 seconds. The speed of A (v_A) is therefore ¹⁰⁰⁰⁄₉₅ = ²⁰⁰⁄₁₉ m/s.
The difference between the speeds of A and B is v_A - v_B = ²⁰⁰⁄₁₉ - 10. By taking the common denominator, this simplifies to (200 - 190)/(19) = ¹⁰⁄₁₉ m/s.
199Quantitative Aptitude
The table given below shows the cost price and selling price of 5 different articles.
Article Cost price Selling price
A1 350 450
A2 550 550
A3 450 650
A4 250 550
A5 150 650
What is the ratio of cost price of A1 to the selling price of A4?
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Answer: (D) 7:11
Explanation
The cost price of article A1 is 350 and the selling price of article A4 is 550. To find the ratio of the cost price of A1 to the selling price of A4, we use the formula:
Ratio = (Cost Price of A1)/(Selling Price of A4)
Ratio = ³⁵⁰⁄₅₅₀
Simplifying the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 50:
Ratio = (350 ÷ 50)/(550 ÷ 50)
Ratio = ⁷⁄₁₁
Thus, the simplified ratio is 7:11.
200Quantitative Aptitude
The selling price of 28 items is equal to the cost price of 17 items. What is the percentage of profit or loss?
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Answer: (A) 39² loss
Explanation
To determine the percentage of profit or loss, we first establish the relationship between the cost price (CP) and the selling price (SP) of the items. Let the cost price of one item be C and the selling price of one item be S. The problem states that the selling price of 28 items is equal to the cost price of 17 items, which is represented by the equation 28S = 17C. By rearranging this equation, we find the ratio of the selling price to the cost price to be (S)/(C) = ¹⁷⁄₂₈.
Since the selling price is represented by 17 units and the cost price by 28 units, the selling price is lower than the cost price, indicating a loss. The amount of loss is calculated by subtracting the selling price from the cost price: 28 - 17 = 11 units. The loss percentage is then calculated based on the cost price using the formula Loss % = (Loss)/(CP) × 100. Substituting the values into the formula gives Loss % = ¹¹⁄₂₈ × 100. Simplifying this expression, we get ¹¹⁰⁰⁄₂₈ = ²⁷⁵⁄₇ = 39 ²⁄₇ %. This results in a loss of approximately 39.29%.