How will you write 5.37 hours in hours, minutes and seconds?
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Answer: (C) 5 hours, 22 minutes, 12 seconds
Explanation
To convert 5.37 hours into hours, minutes, and seconds, keep the whole number part as 5 hours. Convert the fractional part 0.37 hours into minutes by multiplying by 60, which yields 0.37 × 60 = 22.2 minutes. The whole number part gives 22 minutes. Finally, convert the remaining 0.2 minutes into seconds by multiplying by 60, giving 0.2 × 60 = 12 seconds. Combining these results gives 5 hours, 22 minutes, 12 seconds.
1152Mathematics
The average age of a cricket team of 11 players is 18 years. If 4 players join that team, the average age of the team will be increased by 2 years. What is the average age (in years) of the new members of the team?
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Answer: (D) 25.5
Explanation
Total age of the initial 11 players = 11 × 18 = 198 years.
After 4 new players join, the team size increases to 11 + 4 = 15 players, and the new average age becomes 18 + 2 = 20 years.
Total age of all 15 players = 15 × 20 = 300 years.
Sum of the ages of the 4 new members = 300 - 198 = 102 years.
Average age of the new members = 102 / 4 = 25.5 years.
1153Mathematics
The difference between the greatest and the smallest number of six digits is:
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Answer: (D) 899999
Explanation
The greatest six-digit number is 999999 and the smallest six-digit number is 100000.
Difference = 999999 − 100000 = 899999.
1154Mathematics
The curved surface area of a cylindrical pillar is 66 m² and its volume is 231 m³. Find the measure of its radius.
(Take π = ²²⁄₇)
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Answer: (B) 7 m
Explanation
The volume of a cylinder is V = πr²h and its curved surface area is CSA = 2πrh.
Dividing the volume by the curved surface area gives:
V / CSA = (πr²h) / (2πrh) = r / 2
Substituting the given values:
231 / 66 = r / 2
7 / 2 = r / 2
r = 7 m
1155Mathematics
If P is a prime number and P divides Q² , then P will NOT necessarily divide:
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Answer: (B) Q + 1
Explanation
By Euclid's Lemma, if a prime number P divides Q², then P must divide Q.
Since P is a prime, P ≥ 2. Two consecutive integers Q and Q + 1 are always coprime, meaning gcd(Q, Q + 1) = 1. Since P divides Q, it cannot divide Q + 1, as no prime factor can be shared between consecutive integers. Therefore, P will never divide Q + 1.
1156Mathematics
What is the sum of the measures of the interior angles of a hexagon?
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Answer: (A) 720°
Explanation
The sum of the interior angles of an n-sided polygon is given by the formula (n - 2) × 180°. For a hexagon, n = 6. Substituting this into the formula gives (6 - 2) × 180° = 4 × 180° = 720°.
1157Mathematics
What is the value of the following?
(a + 1)(1 - a)(1 - a + a²)(1 + a + a²)(1 + a⁶)
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Answer: (D) 1 - a¹²
Explanation
Using the sum and difference of cubes formulas, (1 + a)(1 - a + a²) = 1 + a³ and (1 - a)(1 + a + a²) = 1 - a³.
Substituting these into the expression:
(a + 1)(1 - a)(1 - a + a²)(1 + a + a²)(1 + a⁶)
= (1 + a³)(1 - a³)(1 + a⁶)
Using the difference of squares formula, (1 + a³)(1 - a³) = 1 - a⁶.
A tree is broken by the wind at a height from the foot. The broken upper part of 10m length touches the ground at a distance of 6m from the foot of the tree. Find the height of the tree.
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Answer: (D) 18 m
Explanation
By Pythagoras theorem, the height at which the tree breaks forms the perpendicular side of a right-angled triangle, where the broken upper part is the hypotenuse (10 m) and the distance from the foot to the top is the base (6 m).
Total height of the tree = Height of standing part + Length of broken upper part = 8 m + 10 m = 18 m
1159Mathematics
A fort has provisions for 150 men for 45 days. After 10 days 25 men left the fort. How long will the provisions last at the same rate for the remaining men?
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Answer: (C) 42 days
Explanation
Remaining provisions after 10 days are sufficient for 150 men for (45 - 10) = 35 days.
Total remaining man-days = 150 × 35 = 5250 man-days.
Number of remaining men = 150 - 25 = 125 men.
Number of days the remaining provisions will last = 5250 / 125 = 42 days.
1160Mathematics
If X = √((1 + (√3)/(2))) +√((1 - (√3)/(2))) then the simplified value of X will be:
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Answer: (A) √3
Explanation
Squaring both sides of X = √(1 + √3/2) + √(1 - √3/2):
Since X is the sum of two positive real square roots, taking the positive square root gives X = √3.
1161Mathematics
Which of the following satellites of ISRO is an experimental satellite?
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Answer: (A) YOUTHSAT
Explanation
YOUTHSAT, launched on April 20, 2011 via PSLV-C16, is an experimental satellite developed jointly by ISRO and Roscosmos with participation from university students. Weighing 92 kg, it belongs to ISRO's Indian Mini Satellite (IMS) series and was designed to conduct aeronomy experiments studying solar variability and its effects on the Earth's upper atmosphere, thermosphere, and ionosphere.
1162Mathematics
What is the least number which is a perfect square and contains 3675 as its factor?
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Answer: (A) 11025
Explanation
Prime factorization of 3675 gives 3¹ × 5² × 7².
For a number to be a perfect square, every prime factor in its prime factorization must have an even exponent. Here, the exponent of 3 is 1 (odd), while the exponents of 5 and 7 are already even.
To get the least perfect square containing 3675 as a factor, 3675 must be multiplied by 3:
The incomes of A and B are in the ratio 3 : 2 and their expenditures are in the ratio 5 : 3. If each saves ₹2,000, what will be the difference between their incomes?
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Answer: (A) 4,000
Explanation
Let the incomes of A and B be 3x and 2x respectively. Since each saves ₹2,000, their expenditures are (3x - 2000) and (2x - 2000).
Given the expenditure ratio is 5 : 3:
(3x - 2000) / (2x - 2000) = 5 / 3
The difference between their incomes is 3x - 2x = x = 4,000.
Alternatively, multiplying the income ratio 3 : 2 by 2 gives 6 : 4, making the difference between income and expenditure equal for both (6 - 5 = 1 unit, and 4 - 3 = 1 unit). Since 1 unit = ₹2,000, the income difference of 2 units (6 - 4) is 2 × 2,000 = 4,000.
The highest common factor of 1650, 45, and 1500 is 3 × 5 = 15.
Dividing by 100 to adjust for the decimal shift gives HCF = 15 / 100 = 0.15.
1166Mathematics
A person lent a certain sum of money at the rate of 4% simple interest per annum. In 8 years, the interest amounted to ₹340 less than the sum lent. Find the sum lent.
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Answer: (C) ₹500
Explanation
Simple Interest SI = (P × R × T) / 100
Given rate R = 4% per annum and time T = 8 years, the simple interest is:
SI = (P × 4 × 8) / 100 = 0.32P
The simple interest is ₹340 less than the sum lent (P):
P - SI = 340
P - 0.32P = 340
0.68P = 340
P = 340 / 0.68 = ₹500
1167Mathematics
A vehicle before overhauling requires ⅚ h service time every 90 days, while after overhauling it requires ⅚ h service time every 120 days. What fraction of the pre- overhauling services time is saved in the latter case?
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Answer: (B) 4
Explanation
Since the required service time per interval is identical (5/6 h), the daily service time required is inversely proportional to the servicing interval.
Fraction of service time saved = [ (1/90) - (1/120) ] / (1/90) = 1 - (90 / 120) = 1 - 3/4 = 1/4.
1168Mathematics
If tan α = ¹⁄ₓ , then find the value of sin α + cos α .
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Answer: (A) (1 + x)/(√(1 + x²))
Explanation
Given tan α = 1/x, consider a right-angled triangle with perpendicular = 1 and base = x.
By the Pythagorean theorem, hypotenuse = √(1² + x²) = √(1 + x²).
Using the basic trigonometric ratios:
sin α = Perpendicular / Hypotenuse = 1 / √(1 + x²)
cos α = Base / Hypotenuse = x / √(1 + x²)
Adding both terms yields:
sin α + cos α = 1 / √(1 + x²) + x / √(1 + x²) = (1 + x) / √(1 + x²)
1169Mathematics
A can complete in 2 days as much of a task as B can complete in 3 days and B can complete in 4 days as much of the task as C can complete in 5 days. In what time will A, B and C together complete the task if A alone can complete it in 22 days?
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Answer: (C) 10 days
Explanation
Ratio of work efficiency of A and B is given by 2A = 3B, which means A : B = 3 : 2 = 15 : 10.
Ratio of efficiency of B and C is given by 4B = 5C, which means B : C = 5 : 4 = 10 : 8.
Combining these gives the efficiency ratio A : B : C = 15 : 10 : 8.
Let daily efficiencies of A, B, and C be 15, 10, and 8 units respectively.
Total work = A's efficiency × Time taken by A = 15 × 22 = 330 units.
Combined daily efficiency of A, B, and C = 15 + 10 + 8 = 33 units/day.
Time taken working together = Total work / Combined efficiency = 330 / 33 = 10 days.
1170Mathematics
Find the median of the given data.
25,18,20,16,8,10,15,20,13,30
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Answer: (B) 17
Explanation
To find the median, arrange the 10 observations in ascending order: 8, 10, 13, 15, 16, 18, 20, 20, 25, 30.
Since the number of observations n = 10 is even, the median is the average of the (n/2)th term and the (n/2 + 1)th term, which correspond to the 5th and 6th terms in the ordered list.
A man lent a part of 30,000 at the rate of 10% per annum and the remaining at the rate of 8% per annum simple interest. The total interest he received after 3 years is 8,280. Find the amount he lent at 10% per annum.
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Answer: (D) 18,000
Explanation
Total simple interest received in 1 year = 8,280 ÷ 3 = ₹2,760.
If the entire sum of ₹30,000 was lent at 8% per annum, the interest for 1 year would be:
8% of 30,000 = ₹2,400.
The excess interest obtained is 2,760 - 2,400 = ₹360.
This difference of ₹360 is due to the additional 2% (10% - 8%) interest rate applied on the sum lent at 10%.
2% of Amount at 10% = ₹360
Amount at 10% = 360 × 100 ÷ 2 = ₹18,000
1172Mathematics
Supposing that the telegraph poles on a railroad are 50m apart, how many poles will be passed by a train in 4 h if the speed of the train is 45km / h
(Include both the poles at the starting point as well as the one at the end of the journey in your count)
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Answer: (D) 3601
Explanation
Total distance covered = Speed × Time = 45 km/h × 4 h = 180 km = 180,000 m.
Number of intervals between adjacent poles = Total distance / Distance between two poles = 180,000 m / 50 m = 3600.
Including both the starting pole and the final pole, the total number of poles passed is Number of intervals + 1 = 3600 + 1 = 3601.
1173Mathematics
The height of a house is h and 5.2m long ladder is just sufficient to go at the top of the house when its inclination with the horizontal ground is 45° Find the height of the house.
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Answer: (C) (13√2)/(5) m
Explanation
In the right-angled triangle formed by the house wall, ground, and ladder, the height h of the house is related to the ladder length L and angle of inclination θ by the formula:
h = L × sin θ
Substituting L = 5.2 m and θ = 45°:
h = 5.2 × sin 45°
h = (26/5) × (1 / √2)
h = 26 / (5√2)
Rationalizing the denominator by multiplying the numerator and denominator by √2:
h = (26√2) / (5 × 2)
h = (13√2)/5 m
1174Mathematics
A car travels a distance of 300km at a uniform speed. If the speed of the car is 5km / h more, it takes 2 h less to cover the same distance. Find the original speed of the car.
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Answer: (B) 25 km/h
Explanation
Using the relation between distance D, original speed v, increase in speed Δv, and time difference Δt:
D = [v(v + Δv) × Δt] / Δv
Substituting D = 300 km, Δv = 5 km/h, and Δt = 2 h:
Let a = 0.4 and b = 0.3. The expression simplifies to:
(a³ + b³) / (a² - ab + b²) = [(a + b)(a² - ab + b²)] / (a² - ab + b²) = a + b
Substituting the values gives:
0.4 + 0.3 = 0.7
1178Mathematics
If the radius of a cylinder is doubled and the height is halved, what will be the ratio of the new volume to the previous volume?
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Answer: (A) 2:1
Explanation
Volume of a cylinder is given by V = π r² h.
Let the initial volume be V₁ = π r² h.
When the radius is doubled (r' = 2r) and the height is halved (h' = h/2), the new volume becomes:
V₂ = π (2r)² (h/2) = π (4r²) (h/2) = 2 π r² h = 2 V₁
The ratio of the new volume to the previous volume is V₂ / V₁ = (2 V₁) / V₁ = 2 / 1, which gives 2:1.
1179Mathematics
If x² = y + z,y² = z + x,z² = x + y , then the value of (1)/(x + 1) +(1)/(y + 1) +(1)/(z + 1) will be:
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Answer: (A) 1
Explanation
Multiply numerator and denominator of 1/(x + 1) by x:
1/(x + 1) = x / (x² + x)
Substitute x² = y + z into the denominator:
x / (x² + x) = x / (x + y + z)
By symmetry, the other two terms become:
1/(y + 1) = y / (x + y + z)
1/(z + 1) = z / (x + y + z)
Adding all three expressions:
1/(x + 1) + 1/(y + 1) + 1/(z + 1) = (x + y + z) / (x + y + z) = 1
1180Mathematics
Solve the following.
5 + 5× 5÷ (5× 5)× 5 = ?
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Answer: (B) 10
Explanation
According to the BODMAS rule, operations inside brackets are evaluated first, followed by division and multiplication from left to right, and finally addition.
Evaluating the bracket first:
(5 × 5) = 25
Substituting this back into the expression:
5 + 5 × 5 ÷ 25 × 5
Executing multiplication and division from left to right:
5 + 25 ÷ 25 × 5
= 5 + 1 × 5
= 5 + 5
Performing final addition:
5 + 5 = 10
1181Mathematics
Find the fraction form of 0.666....
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Answer: (C) 2/3
Explanation
Let x = 0.666...
Multiplying both sides by 10 gives 10x = 6.666...
Subtracting x from 10x:
10x - x = 6.666... - 0.666...
9x = 6
x = 6/9 = 2/3
1182Mathematics
The Lucknow Shatabdi Express leaves Delhi at 1:30 p.m. and reaches Lucknow at 10:30 p.m. The average speed of the train is 90 km/h. What is the distance covered by the train from Delhi to Lucknow?
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Answer: (C) 810 km
Explanation
Distance = Speed × Time
Time taken by the train = 10:30 p.m. - 1:30 p.m. = 9 hours
Average speed = 90 km/h
Distance = 90 km/h × 9 h = 810 km
1183Mathematics
A reduction of 10% in the price of mangoes enables a person to buy 10 mangoes more for ₹2250. What is the price per dozen after reduction?
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Answer: (D) 270
Explanation
Amount saved due to the 10% reduction = 10% of ₹2250 = ₹225.
This saved amount allows the person to buy 10 additional mangoes at the reduced price.
Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively.
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Answer: (B) 138
Explanation
To find the greatest number that leaves remainders 9 and 7 when dividing 285 and 1249 respectively, subtract the remainders from the given numbers and calculate their Highest Common Factor (HCF).
First number = 285 - 9 = 276
Second number = 1249 - 7 = 1242
Given that 2 parts correspond to 32 rubber bands:
1 part = 32 × ½ = 16 rubber bands
1186Mathematics
⅓ of a commodity is sold at the rate of 15% profit, ¼ is sold at the rate of 20% profit and the rest is sold at the rate of 24% profit. If a total profit of 62 is earned, then find the cost price of the commodity.
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Answer: (A) ₹310
Explanation
Let the total cost price of the commodity be CP.
Profit from 1/3 part = (1/3) × 15% = 5% of CP
Profit from 1/4 part = (1/4) × 20% = 5% of CP
Remaining part = 1 - (1/3 + 1/4) = 1 - (7/12) = 5/12
Profit from 5/12 part = (5/12) × 24% = 10% of CP
Total profit percentage = 5% + 5% + 10% = 20% of CP
Given total profit = ₹62:
20% of CP = ₹62
CP = (62 × 100) / 20 = ₹310
1187Mathematics
The following table shows the number of candidates at different score intervals for an entrance examination in which 10000 candidates appeared.
Subject No. of candidates at Different Score Intervals
0-40 41-80 81-120 121-160 161-200
GK 2219 2025 3652 1248 856
LR 1022 2237 2954 3569 218
English 1120 1689 3562 2412 1217
Computer 645 2759 3841 2564 191
According to the given table, what percentage of candidates scored less than 20% marks in GK?
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Answer: (D) 22.19%
Explanation
The maximum score in the examination is 200 marks.
20% of 200 = 40 marks.
The candidates scoring less than 20% marks fall in the 0–40 score interval, which contains 2219 candidates in GK out of a total of 10000 candidates.
The following table shows the number of candidates at different score intervals for an entrance examination in which 10000 candidates appeared.
Subject No. of candidates at Different Score Intervals
0-40 41-80 81-120 121-160 161-200
GK 2219 2025 3652 1248 856
LR 1022 2237 2954 3569 218
English 1120 1689 3562 2412 1217
Computer 645 2759 3841 2564 191
A candidate should score more than the cut- off marks for English to be evaluated for LR. If the cut- off marks for English is 40% , then how many answer sheets will be evaluated for LR?
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Answer: (B) 7191
Explanation
The maximum possible score in English is 200.
Cut-off marks for English = 40% of 200 = 80 marks.
To be evaluated for LR, a candidate must score more than 80 marks in English, which corresponds to the candidates in the score intervals 81-120, 121-160, and 161-200.
Total candidates = 3562 + 2412 + 1217 = 7191.
1189Mathematics
The following table shows the number of candidates at different score intervals for an entrance examination in which 10000 candidates appeared.
Subject No. of candidates at Different Score Intervals
0-40 41-80 81-120 121-160 161-200
GK 2219 2025 3652 1248 856
LR 1022 2237 2954 3569 218
English 1120 1689 3562 2412 1217
Computer 645 2759 3841 2564 191
What is the count of candidate scores above 80% across all the given subjects?
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Answer: (C) 2482
Explanation
Maximum score in each subject is 200.
80% of 200 = 160 marks.
Scores above 80% correspond to marks strictly greater than 160, which falls into the 161-200 score interval.
Sum of candidates scoring in the 161-200 interval across all subjects:
GK = 856
LR = 218
English = 1217
Computer = 191
Total = 856 + 218 + 1217 + 191 = 2482
1190Mathematics
The following table shows the number of candidates at different score intervals for an entrance examination in which 10000 candidates appeared.
Subject No. of candidates at Different Score Intervals
0-40 41-80 81-120 121-160 161-200
GK 2219 2025 3652 1248 856
LR 1022 2237 2954 3569 218
English 1120 1689 3562 2412 1217
Computer 645 2759 3841 2564 191
If for each subject, the cut- off marks is 40% , then how many candidates have scored more than the cut- off marks in all the subjects?
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Answer: (A) Cannot be determined from given data
Explanation
The maximum score in each subject is 200, making the 40% cut-off equal to 80 marks. The provided table shows subject-wise score distributions independently, but does not provide candidate-level cross-tabulation to track individual performance across multiple subjects. Without knowing the overlap of candidates scoring above 80 marks across all four subjects, the exact number of candidates who cleared the cut-off in all subjects simultaneously cannot be calculated.
1191Mathematics
What is the mean deviation of eight observations?
6, 7, 10, 12, 13, 4, 8, 12
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Answer: (A) 2.75
Explanation
Mean Deviation = Σ|x - x̅| / n
First, find the mean (x̅) of the eight observations:
x̅ = (6 + 7 + 10 + 12 + 13 + 4 + 8 + 12) / 8 = 72 / 8 = 9
The way the brain interprets the frequency of an emitted sound is called the
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Answer: (C) pitch
Explanation
Pitch is the perceptual attribute of sound that allows the human brain to categorize sound as high or low based on the frequency of the sound wave. High-frequency sound waves produce a high-pitched sound, whereas low-frequency sound waves result in a low-pitched sound.
1193Mathematics
Which of the following portal has been launched in Feb 2021 to provide municipal services to the citizens of Cantonment boards across India?
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Answer: (C) e- Chhawani
Explanation
In February 2021, Defence Minister Rajnath Singh launched the e-Chhawani portal to provide online municipal services to over 20 lakh residents residing across 62 Cantonment Boards in India. Developed jointly by the Directorate General Defence Estates, Bharat Electronics Limited, eGov Foundation, and National Informatics Centre, the portal enables citizens to easily access services such as property tax payment, trade license issuance, water and sewerage connections, and grievance redressal without visiting board offices.
The two sides of a triangle measure 10cm and 8cm respectively. The area of the triangle is equal to 16√6 cm² . Find the length of the third side, given that it is a rational number.
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Answer: (C) 14cm
Explanation
Area = ½ × a × b × sin C
16√6 = ½ × 10 × 8 × sin C
16√6 = 40 sin C
sin C = (2√6)/5
Using cos C = ±√(1 - sin² C):
cos C = ±√(1 - 24/25) = ±1/5
By the Law of Cosines, c² = a² + b² - 2ab cos C:
c² = 10² + 8² - 2(10)(8) cos C = 164 - 160 cos C
For cos C = 1/5:
c² = 164 - 32 = 132 ⇒ c = 2√33 (irrational)
For cos C = -1/5:
c² = 164 + 32 = 196 ⇒ c = √196 = 14 cm (rational)
1196Mathematics
The mean of the ages of three friends is 22. If the mean of the ages of four friends is 24, then find the age of the fourth friend.
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Answer: (B) 30
Explanation
Sum of ages = Mean × Number of friends
Sum of the ages of 3 friends = 3 × 22 = 66
Sum of the ages of 4 friends = 4 × 24 = 96
Age of the fourth friend = (Sum of ages of 4 friends) - (Sum of ages of 3 friends) = 96 - 66 = 30 years.
1197Mathematics
A person can complete a journey in 12 h. He travels the first half of the journey at a speed of 18 km/h and the second half at a speed of 30 km/h. Find the total journey in km.
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Answer: (B) 270
Explanation
When a journey is divided into two equal distances, the average speed is given by the formula:
Average Speed = (2 × s₁ × s₂) / (s₁ + s₂)
Substituting the given speeds s₁ = 18 km/h and s₂ = 30 km/h:
Average Speed = (2 × 18 × 30) / (18 + 30) = 1080 / 48 = 22.5 km/h
Total Distance = Average Speed × Total Time
Total Distance = 22.5 km/h × 12 h = 270 km
1198Mathematics
A sum of 12,400 amounts to 14,632 in 3 years at a rate of simple interest. What is the rate of interest per annum?
Using the formula SI = (P × R × T) / 100:
2,232 = (12,400 × R × 3) / 100
2,232 = 372 × R
R = 2,232 / 372 = 6%
1199Mathematics
A number, when 42 is subtracted from it, reduces to its 70% . What is two- fifth of that number?
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Answer: (C) 56
Explanation
Let the number be x. Subtracting 42 reduces the number to 70% of its original value, which means 42 corresponds to the remaining 30% (100% - 70%) of the number.
30% of x = 42
(30/100) × x = 42
x = (42 × 100) / 30 = 140
Two-fifths of the number is:
(2/5) × 140 = 56
1200Mathematics
If 12% of a = 25% of b then a : b is equal to:
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Answer: (C) 25:12
Explanation
Using the given percentage equality:
12% × a = 25% × b
Canceling the percentage sign from both sides:
12 × a = 25 × b
a / b = 25 / 12