IBPS RRB Clerk2025Numerical AbilityPage 3 of 3

IBPS RRB Clerk Prelims 2025 Numerical Ability Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 101–140 of 140, each with the correct answer and a step-by-step explanation.

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Answers + explanations
101Numerical Ability
√? × √(3025) = 2695
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Answer: (A) 2401

Explanation

To find the unknown value represented by the question mark, simplify the square root of 3025. Since 50² = 2500 and 60² = 3600, 3025 ends in 25, which gives √3025 = 55. Substituting 55 into the original equation: √x × 55 = 2695 Isolate √x by dividing both sides of the equation by 55: √x = 2695 ÷ 55 2695 ÷ 55 = 49 To obtain x, square both sides: x = 49² = (50 - 1)² = 2500 - 100 + 1 = 2401.

102Numerical Ability
(98)² + (?) = (150)² - (80)² - 737
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Answer: (B) 5759

Explanation

To find the unknown value in the given algebraic expression, simplify each part step by step using basic arithmetic rules and identities. First, compute the right-hand side of the equation: (150)² - (80)² - 737 Using the difference of squares identity, a² - b² = (a - b)(a + b): (150)² - (80)² = (150 - 80) × (150 + 80) = 70 × 230 = 16100 Now, subtract 737 from 16100: 16100 - 737 = 15363 Next, compute the square term on the left-hand side: (98)² = (100 - 2)² = 10000 - 400 + 4 = 9604 Substitute these simplified values back into the equation: 9604 + x = 15363 Isolate x by subtracting 9604 from 15363: x = 15363 - 9604 = 5759.

103Numerical Ability
48 + 8 × 0.75 - 5 = ?
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Answer: (C) 49

Explanation

To solve this arithmetic problem, apply the BODMAS rule, which dictates the correct order of operations: Brackets, Orders, Division/Multiplication, and Addition/Subtraction. First, execute the multiplication operation before performing addition or subtraction: 8 × 0.75 = 8 × (3 ÷ 4) = 6 Now, substitute this result back into the original expression: 48 + 6 - 5 Perform the addition and subtraction sequentially from left to right: 48 + 6 = 54 54 - 5 = 49.

104Numerical Ability
657 - 7.549 - 4.111 - 1.630 = ?
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Answer: (D) 5.367

Explanation

To evaluate the given decimal expression, combine the numbers being subtracted before taking them away from the initial decimal value. First, calculate the sum of all negative terms: 7.549 + 4.111 + 1.630 Adding these step by step: 7.549 + 4.111 = 11.660 11.660 + 1.630 = 13.290 Now, subtract this total sum from the starting positive decimal value: 18.657 - 13.290 = 5.367.

105Numerical Ability
2950 ÷ 12.5 + 160 = ?
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Answer: (C) 396

Explanation

To determine the unknown value, follow the standard BODMAS rule for order of mathematical operations, which prioritizes division over addition. First, evaluate the division term: 2950 ÷ 12.5 To simplify division by a decimal, rewrite 12.5 as 25 ÷ 2: 2950 ÷ (25 ÷ 2) = (2950 × 2) ÷ 25 = 5900 ÷ 25 = 236 Next, add 160 to this calculated value: 236 + 160 = 396.

106Numerical Ability
The table given below shows the items sold by A,B and C sold on Monday, Tuesday and Wednesday. Sellers | Monday | Tuesday | Wednesday A | 98 | 78 | 45 B | 100 | 55 | 60 C | 22 | 90 | 82 Find the average number of items sold by A on Monday and Tuesday.
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Answer: (E) 88

Explanation

Items sold by seller A on Monday = 98 Items sold by seller A on Tuesday = 78

Average = (98 + 78) / 2 = 176 / 2 = 88

107Numerical Ability
The table given below shows the items sold by A,B and C sold on Monday, Tuesday and Wednesday. Sellers | Monday | Tuesday | Wednesday A | 98 | 78 | 45 B | 100 | 55 | 60 C | 22 | 90 | 82 Find the difference between items sold by B and C on Wednesday.
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Answer: (E) 22

Explanation

Items sold by B on Wednesday = 60 Items sold by C on Wednesday = 82

Difference = 82 - 60 = 22

108Numerical Ability
The table given below shows the items sold by A,B and C sold on Monday, Tuesday and Wednesday. Sellers | Monday | Tuesday | Wednesday A | 98 | 78 | 45 B | 100 | 55 | 60 C | 22 | 90 | 82 Items sold by C on Tuesday is what percentage of sum of items sold by B on Tuesday and A on Wednesday.
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Answer: (A) 90

Explanation

Items sold by C on Tuesday = 90 Sum of items sold by B on Tuesday and A on Wednesday = 55 + 45 = 100

Required percentage = (90 / 100) × 100 = 90%

109Numerical Ability
The table given below shows the items sold by A,B and C sold on Monday, Tuesday and Wednesday. Sellers | Monday | Tuesday | Wednesday A | 98 | 78 | 45 B | 100 | 55 | 60 C | 22 | 90 | 82 If the ratio of defective to non- defective items sold by B on Wednesday is 1:5, then find the difference between defective and non- defective items sold by B.
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Answer: (A) 40

Explanation

Total items sold by B on Wednesday = 60 Ratio of defective to non-defective items = 1 : 5 (Total 6 ratio units)

Defective items = (1 / 6) × 60 = 10 Non-defective items = (5 / 6) × 60 = 50

Difference = 50 - 10 = 40

110Numerical Ability
The table given below shows the items sold by A,B and C sold on Monday, Tuesday and Wednesday. Sellers | Monday | Tuesday | Wednesday A | 98 | 78 | 45 B | 100 | 55 | 60 C | 22 | 90 | 82 Find the difference between total items sold on Tuesday and Wednesday by all the sellers.
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Answer: (B) 36

Explanation

Total items sold on Tuesday = 78 + 55 + 90 = 223 Total items sold on Wednesday = 45 + 60 + 82 = 187

Difference = 223 - 187 = 36

111Numerical Ability
A man invested equal amounts in Scheme X and Scheme Y. Scheme X offers simple interest at 10% per annum for 3 years, while Scheme Y offers simple interest at 6% per annum for 3 years. The total simple interest earned from both schemes together is Rs 4,800. Find the amount invested in Scheme X (in Rs).
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Answer: (B) 10000

Explanation

Let the amount invested in each scheme be P. Simple interest formula: SI = (P × R × T) / 100

Interest from Scheme X = (P × 10 × 3) / 100 = 0.30P Interest from Scheme Y = (P × 6 × 3) / 100 = 0.18P

Total interest = 0.30P + 0.18P = 0.48P = 4800 P = 4800 / 0.48 = 10000

112Numerical Ability
Riya and Meena started a business together with a total investment of Rs 6,000. After 6 months, Meena withdrew her capital. At the end of the year, their profit- sharing ratio was equal. Find the initial investment of Riya (in Rs).
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Answer: (B) 2000

Explanation

Let Riya's investment be R and Meena's investment be M. Total investment: R + M = 6000

Riya invested for 12 months, and Meena invested for 6 months. Profit ratio = (R × 12) : (M × 6) = 2R : M

Since the profit ratio is equal (1 : 1): 2R = M

Substitute M = 2R into the total investment equation: R + 2R = 6000 3R = 6000 R = 2000

113Numerical Ability
A train crosses a platform in 24 seconds while running at a speed of 90 km / h . The length of the platform is 80 meters more than the length of the train. Find the length of the train (in meters).
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Answer: (A) 260

Explanation

Speed of train in m/s = 90 × (5 / 18) = 25 m/s

Total distance covered in 24 seconds = 25 × 24 = 600 m Total distance = Length of train (L) + Length of platform (P)

Given P = L + 80: L + (L + 80) = 600 2L + 80 = 600 2L = 520 L = 260 m

114Numerical Ability
The monthly incomes of Rohit and Amit are in the ratio of 4 : 5 respectively. Rohit spends 25% of his income on rent, 20% of the remaining amount on groceries, and 15% of the remaining amount on transport. He saves the rest of his income. If Rohit's savings amount to Rs 9,180, find the monthly income (in Rs) of Amit.
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Answer: (C) 22500

Explanation

Percentage of income saved by Rohit = (1 - 0.25) × (1 - 0.20) × (1 - 0.15) = 0.75 × 0.80 × 0.85 = 0.51 = 51%

Rohit's monthly income = 9180 / 0.51 = 18000

Since the ratio of Rohit's income to Amit's income is 4 : 5: Amit's monthly income = (18000 / 4) × 5 = 22500

115Numerical Ability
The present ages of two friends, Arjun and Karan, together are equal to the present age of their mentor. Four years ago, Arjun's age was half of the Montu age at that time. If the present age of Karan is 25 years, find the age (in years) of the Montu after 1 year from now.
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Answer: (E) 55

Explanation

Let the present ages of Arjun, Karan, and the mentor be A, K, and M respectively. Given K = 25 and A + K = M: A + 25 = M M - A = 25 --- (Equation 1)

Four years ago, Arjun's age was half of the mentor's age: A - 4 = 0.5 × (M - 4) 2A - 8 = M - 4 2A - M = 4 --- (Equation 2)

Adding Equation 1 and Equation 2: (M - A) + (2A - M) = 25 + 4 A = 29

Present age of mentor M = 29 + 25 = 54 Age of mentor after 1 year = 54 + 1 = 55

116Numerical Ability
P can complete a piece of work in 18 days, and Q can complete the same work in 27 days. Working together, P, Q, and R can finish the work in 9 days. Find the number of days R alone would take to complete the work.
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Answer: (A) 54

Explanation

Combined 1-day work rate of P, Q, and R is 1/9. 1-day work rate of P is 1/18 and that of Q is 1/27. 1-day work rate of R = 1/9 - (1/18 + 1/27) = 1/9 - 5/54 = 1/54. Therefore, R alone takes 54 days to complete the work.

117Numerical Ability
A shopkeeper marks the price of a watch 40% above its cost price and then allows a 25% discount on the marked price. If the profit earned is Rs 60, find the discount allowed (in Rs).
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Answer: (C) 420

Explanation

Let the cost price be CP. Marked price = 1.40 × CP. Discount = 25% of Marked price = 0.25 × 1.40 × CP = 0.35 × CP. Selling price = Marked price - Discount = 1.40 × CP - 0.35 × CP = 1.05 × CP. Profit = Selling price - CP = 0.05 × CP = 60. CP = 60 / 0.05 = 1200. Discount allowed = 0.35 × 1200 = 420.

118Numerical Ability
A mixture contains milk and water in the ratio 3:2 . The total quantity of the mixture is 40 liters. If x liters of water are added to the mixture, the ratio of milk to water becomes 3:5 . Find the value of x .
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Answer: (E) 24

Explanation

In 40 liters of total mixture with milk to water ratio 3:2: Milk = (3/5) × 40 = 24 liters. Water = (2/5) × 40 = 16 liters. After adding x liters of water, the new milk to water ratio is 3:5. 24 / (16 + x) = 3/5 24 × 5 = 3 × (16 + x) 120 = 48 + 3x 3x = 72 x = 24.

119Numerical Ability
The downstream speed of a boat is 20 km/h, and the speed of the stream is 4km / h . Find the time taken (in hours) by the boat to cover a distance of 24km upstream.
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Answer: (A) 2

Explanation

Downstream speed = Boat speed + Stream speed = 20 km/h. Given Stream speed = 4 km/h. Boat speed in still water = 20 - 4 = 16 km/h. Upstream speed = Boat speed - Stream speed = 16 - 4 = 12 km/h. Time taken upstream = Distance / Upstream speed = 24 / 12 = 2 hours.

120Numerical Ability
The breadth of a rectangle is half of its length. If the perimeter is 60cm , find the area (in sq. cm).
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Answer: (B) 200

Explanation

Let length be L and breadth be b = L/2, so L = 2b. Perimeter = 2 × (L + b) = 2 × (2b + b) = 6b = 60 cm. b = 10 cm. L = 2 × 10 = 20 cm. Area = L × b = 20 × 10 = 200 sq. cm.

121Numerical Ability
What will come in the place of question (?) mark in the following number series. ?, 46, 71, 87, 96, 100
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Answer: (D) 10

Explanation

The differences between consecutive terms in reverse order are consecutive perfect squares: 100 - 96 = 4 = 2² 96 - 87 = 9 = 3² 87 - 71 = 16 = 4² 71 - 46 = 25 = 5² 46 - ? = 36 = 6² Therefore, ? = 46 - 36 = 10.

122Numerical Ability
What will come in the place of question (?) mark in the following number series. 218, 231, 253, 293, 369, ?
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Answer: (B) 517

Explanation

First-order differences between consecutive terms: 231 - 218 = 13 253 - 231 = 22 293 - 253 = 40 369 - 293 = 76

Second-order differences: 22 - 13 = 9 40 - 22 = 18 76 - 40 = 36

The second-order differences double at each step (9, 18, 36, 72). Next first-order difference = 76 + 72 = 148. Missing term = 369 + 148 = 517.

123Numerical Ability
What will come in the place of question (?) mark in the following number series. 1308, ?, 324, 160, 78, 37
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Answer: (A) 652

Explanation

The recurrence relation for consecutive terms is xₙ₊₁ = xₙ / 2 - 2: 1308 / 2 - 2 = 652 652 / 2 - 2 = 324 324 / 2 - 2 = 160 160 / 2 - 2 = 78 78 / 2 - 2 = 37

Therefore, the missing number is 652.

124Numerical Ability
What will come in the place of question (?) mark in the following number series. 64, 71, 81, 96, ?, 149
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Answer: (C) 118

Explanation

First-order differences between terms: 71 - 64 = 7 81 - 71 = 10 96 - 81 = 15

Second-order differences: 10 - 7 = 3 15 - 10 = 5

The second-order differences increase by 2 each step (3, 5, 7, 9). Next first-order difference = 15 + 7 = 22. Missing term = 96 + 22 = 118. Verification: 118 + (22 + 9) = 118 + 31 = 149.

125Numerical Ability
What will come in the place of question (?) mark in the following number series. 18, 57, 174, 525, 1578, ?
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Answer: (A) 4737

Explanation

The recurrence relation for the series is xₙ₊₁ = 3 × xₙ + 3: 18 × 3 + 3 = 57 57 × 3 + 3 = 174 174 × 3 + 3 = 525 525 × 3 + 3 = 1578 1578 × 3 + 3 = 4737

Therefore, the missing term is 4737.

126Numerical Ability
What will come in the place of question (?) marks: 12² + 16² + 7.5 × 12 = ?² + ³√(216)
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Answer: (A) 22

Explanation

Evaluating the terms on the left-hand side gives 12² = 144, 16² = 256, and 7.5 × 12 = 90. Adding these together yields 144 + 256 + 90 = 490. On the right-hand side, the cube root of 216 is 6. Substituting this into the equation gives 490 = ?² + 6, which simplifies to ?² = 484. Taking the square root of 484 gives ? = 22.

127Numerical Ability
What will come in the place of question (?) marks: 3⅐ + 5¹⁄₁₄ - ? = 2⅐
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Answer: (B) 6¹⁄₁₄

Explanation

Rearranging the equation to solve for ? gives ? = 3 1/7 + 5 1/14 - 2 1/7. Subtracting 2 1/7 from 3 1/7 leaves 1. Adding 1 to 5 1/14 yields 6 1/14.

128Numerical Ability
What will come in the place of question (?) marks: ? % of 37.5 + 12.5 × 14 = 25% of 760
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Answer: (E) 40

Explanation

First, calculate the known terms: 12.5 × 14 = 175, and 25% of 760 = 760 / 4 = 190. Substituting these values into the expression gives ? % of 37.5 + 175 = 190. Subtracting 175 from 190 gives ? % of 37.5 = 15. Writing ? % as ? / 100 gives (? / 100) × 37.5 = 15, which simplifies to ? = 1500 / 37.5 = 40.

129Numerical Ability
What will come in the place of question (?) marks: 1246 + 1567 - ? = 22² + ³√(1000)
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Answer: (C) 2319

Explanation

Simplify the left-hand side sum: 1246 + 1567 = 2813. Evaluate the terms on the right-hand side: 22² = 484 and the cube root of 1000 is 10, giving a total of 484 + 10 = 494. Substituting these into the equation gives 2813 - ? = 494. Solving for ? yields ? = 2813 - 494 = 2319.

130Numerical Ability
What will come in the place of question (?) marks: (783)/(?) + 175.75 - 175.5 ÷ 6 = 190
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Answer: (A) 18

Explanation

First, calculate 175.5 ÷ 6 = 29.25. Next, subtract 29.25 from 175.75 to get 146.5. The equation becomes (783 / ?) + 146.5 = 190. Subtracting 146.5 from both sides gives 783 / ? = 43.5. Dividing 783 by 43.5 gives ? = 18.

131Numerical Ability
What will come in the place of question (?) marks: 56 % of 55 + ? % of 132.8 = 8²
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Answer: (C) 25

Explanation

Calculate 56% of 55 = 0.56 × 55 = 30.8, and 8² = 64. Substituting these into the equation gives 30.8 + ? % of 132.8 = 64. Subtracting 30.8 from 64 gives ? % of 132.8 = 33.2. Solving for ? gives ? = (33.2 × 100) / 132.8 = 3320 / 132.8 = 25.

132Numerical Ability
What will come in the place of question (?) marks: 17.5 × 16 + ? = 28² - ³√(576)
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Answer: (D) 480

Explanation

Evaluating the terms gives 17.5 × 16 = 280, 28² = 784, and √576 = 24. Substituting these into the equation gives 280 + ? = 784 - 24, which simplifies to 280 + ? = 760. Subtracting 280 from 760 yields ? = 480.

133Numerical Ability
What will come in the place of question (?) marks: (?)/(32.5) + 32² + 80 % of 317.5 = 36²
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Answer: (D) 585

Explanation

Calculate each part: 32² = 1024, 80% of 317.5 = 254, and 36² = 1296. Substituting these into the equation gives (? / 32.5) + 1024 + 254 = 1296. Combining the constants on the left gives (? / 32.5) + 1278 = 1296. Subtracting 1278 from 1296 gives ? / 32.5 = 18. Multiplying 18 by 32.5 yields ? = 585.

134Numerical Ability
What will come in the place of question (?) marks: 5.25 × 18 + 12.25 × 8 + ? = 14²
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Answer: (A) 3.5

Explanation

Calculate 5.25 × 18 = 94.5 and 12.25 × 8 = 98. Also, 14² = 196. Substituting these values into the equation gives 94.5 + 98 + ? = 196. Combining the numbers on the left yields 192.5 + ? = 196. Subtracting 192.5 from 196 gives ? = 3.5.

135Numerical Ability
What will come in the place of question (?) marks: 41 % of 2560 + 32 % of 388.75 = 34² + ?
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Answer: (B) 18

Explanation

First, calculate 41% of 2560 = 0.41 × 2560 = 1049.6, and 32% of 388.75 = 0.32 × 388.75 = 124.4. The left-hand side sum is 1049.6 + 124.4 = 1174. On the right-hand side, 34² = 1156. The equation becomes 1174 = 1156 + ?. Subtracting 1156 from 1174 gives ? = 18.

136Numerical Ability
43 % of 800 + 36 % of 750 = ? % of 400
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Answer: (C) 153.5

Explanation

Calculating the individual percentage values on the left side: 43% of 800 = (43 ÷ 100) × 800 = 344 36% of 750 = (36 ÷ 100) × 750 = 270

Adding these two values gives the left-hand sum: 344 + 270 = 614

Let the required percentage be x. Setting up the equation: (x ÷ 100) × 400 = 614 4x = 614 x = 614 ÷ 4 = 153.5

137Numerical Ability
7777 ÷ 700 + 7777 ÷ 1100 - 5555 ÷ 500 = ?
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Answer: (C) 7.07

Explanation

Simplifying each term individually: 7777 ÷ 700 = 77.77 ÷ 7 = 11.11 7777 ÷ 1100 = 77.77 ÷ 11 = 7.07 5555 ÷ 500 = 55.55 ÷ 5 = 11.11

Substituting these calculated quotient values back into the main expression gives: 11.11 + 7.07 − 11.11

The first and last terms cancel each other out, leaving: 7.07

138Numerical Ability
4345 + 5625 + 7125 - 3345 = ?
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Answer: (B) 13,750

Explanation

Grouping the numbers to make computation simpler: (4345 − 3345) + (5625 + 7125)

First, subtract 3345 from 4345: 4345 − 3345 = 1000

Next, add 5625 and 7125: 5625 + 7125 = 12,750

Finally, sum the two intermediate results together: 1000 + 12,750 = 13,750

139Numerical Ability
√(80 ÷ 5 × 8 + (17 × 5) − 17) ÷ ∛343 = ⁴√?
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Answer: (D) 16

Explanation

Evaluating the terms inside the square root following the order of operations: 80 ÷ 5 × 8 = 16 × 8 = 128 17 × 5 = 85 128 + 85 − 17 = 196 √(196) = 14

Evaluating the cube root term: ∛343 = 7

Dividing the two results: 14 ÷ 7 = 2

Let the missing value be x. Setting up the equation: 2 = ⁴√x x = 2⁴ = 16

140Numerical Ability
⅘ of ⅔ of ⁷⁄₉ of 16,200 = ⅙ of ?
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Answer: (A) 40,320

Explanation

Evaluating the left-hand side of the given equation: (4 ÷ 5) × (2 ÷ 3) × (7 ÷ 9) × 16,200

Simplifying by cancelling factors with 16,200: 16,200 ÷ (5 × 3 × 9) = 16,200 ÷ 135 = 120

Multiplying the numerators with the quotient: 4 × 2 × 7 × 120 = 56 × 120 = 6720

Setting up the equality with the unknown value x: 6720 = (1 ÷ 6) × x x = 6720 × 6 = 40,320

Answer key

Tap a number to jump to that question.

  1. 101A
  2. 102B
  3. 103C
  4. 104D
  5. 105C
  6. 106E
  7. 107E
  8. 108A
  9. 109A
  10. 110B
  11. 111B
  12. 112B
  13. 113A
  14. 114C
  15. 115E
  16. 116A
  17. 117C
  18. 118E
  19. 119A
  20. 120B
  21. 121D
  22. 122B
  23. 123A
  24. 124C
  25. 125A
  26. 126A
  27. 127B
  28. 128E
  29. 129C
  30. 130A
  31. 131C
  32. 132D
  33. 133D
  34. 134A
  35. 135B
  36. 136C
  37. 137C
  38. 138B
  39. 139D
  40. 140A

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