What will come in the place of question mark (?) in the following questions.
2, 4, 12, ?, 240, 1440
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Answer: (B) 48
Explanation
The pattern of the series is formed by multiplying terms by consecutive integers:
2 × 2 = 4
4 × 3 = 12
12 × 4 = 48
48 × 5 = 240
240 × 6 = 1440
The missing value is 48.
52Numerical Ability
What will come in the place of question mark (?) in the following questions.
1200, 300, 150, 112.5, ?, 140.625
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Answer: (B) 112.5
Explanation
The pattern of multiplication factors between terms increases by 0.25 at each step:
1200 × 0.25 = 300
300 × 0.50 = 150
150 × 0.75 = 112.5
112.5 × 1.00 = 112.5
112.5 × 1.25 = 140.625
The missing value is 112.5.
53Numerical Ability
What will come in the place of question mark (?) in the following questions.
1600, 1088, 1039, 823, 798, ?
What will come in the place of question mark (?) in the following questions.
147, ?, 111, 88, 59, 28
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Answer: (A) 130
Explanation
The differences between successive terms are consecutive prime numbers in increasing order from right to left:
59 - 28 = 31
88 - 59 = 29
111 - 88 = 23
130 - 111 = 19
147 - 130 = 17
The missing value is 130.
55Numerical Ability
What will come in the place of question mark (?) in the following questions.
148, ?, 203, 243, 294, 358, 437
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Answer: (A) 172
Explanation
The primary differences between consecutive terms are 24, 31, 40, 51, 64, and 79.
The differences of these differences (second differences) form a pattern decreasing by 2:
31 - 24 = 7
40 - 31 = 9
51 - 40 = 11
64 - 51 = 13
79 - 64 = 15
Adding 24 to 148 gives 172, and adding 31 to 172 gives 203.
The missing value is 172.
56Numerical Ability
What will come in the place of question (?) mark in the following questions?
50- 45+145=2.5x?
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Answer: (B) 60
Explanation
Simplifying the expression on the left-hand side by following the standard order of operations:
First, perform addition and subtraction from left to right:
50 - 45 + 145 = 5 + 145 = 150
Now, set up the equation with the right-hand side expression:
150 = 2.5 × ?
To isolate the unknown quantity ?, divide 150 by 2.5:
? = 150 / 2.5 = 1500 / 25 = 60
57Numerical Ability
What will come in the place of question (?) mark in the following questions?
√(225) ÷ √(25) × 6 = ?% of 200
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Answer: (B) 9
Explanation
Evaluating the square roots on the left-hand side of the given equation:
√225 = 15 and √25 = 5
Substituting these values into the left-hand side expression and applying division followed by multiplication:
(15 ÷ 5) × 6 = 3 × 6 = 18
Now evaluating the right-hand side expression:
?% of 200 = (? / 100) × 200 = 2 × ?
Equating the left-hand side and right-hand side expressions:
18 = 2 × ?
? = 18 / 2 = 9
58Numerical Ability
What will come in the place of question (?) mark in the following questions?
16 × 25 + 280 - (25)² = 25% of?
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Answer: (C) 220
Explanation
Simplifying each term on the left-hand side of the given equation:
16 × 25 = 400
(25)² = 625
Combining all terms on the left-hand side:
400 + 280 - 625 = 680 - 625 = 55
The right-hand side represents 25% of the unknown number ?, which simplifies to:
25% of ? = (25 / 100) × ? = ? / 4
Setting the left-hand side equal to the right-hand side:
55 = ? / 4
? = 55 × 4 = 220
59Numerical Ability
What will come in the place of question (?) mark in the following questions?
√(49) × √(196) + 430 = (?)² - 48
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Answer: (E) 24
Explanation
Evaluating the square root terms on the left-hand side:
√49 = 7
√196 = 14
Multiplying these square roots together:
7 × 14 = 98
Adding 430 gives the complete value for the left-hand side:
98 + 430 = 528
Now set up the complete equation with the right-hand side:
(?)² - 48 = 528
Adding 48 to both sides to isolate (?)²:
(?)² = 528 + 48 = 576
Taking the square root of 576:
? = √576 = 24
60Numerical Ability
What will come in the place of question (?) mark in the following questions?
118 + √(484) + ⁶⁄₁₃ × 260 + ? = (17)²
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Answer: (A) 29
Explanation
Evaluating each known term in the given equation step-by-step:
√484 = 22
(6 / 13) × 260 = 6 × 20 = 120
(17)² = 289
Adding all known numbers on the left-hand side together:
118 + 22 + 120 = 260
Substituting these simplified values back into the main equation:
260 + ? = 289
Subtracting 260 from both sides to determine the missing value ?:
? = 289 - 260 = 29
61Numerical Ability
What will come in the place of question (?) mark in the following questions?
108 ÷ 3 × 5 - 225 ÷ 9 × 4 = 400% of ?
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Answer: (D) 20
Explanation
Applying the standard order of operations to the left-hand side expression:
First term: 108 ÷ 3 × 5 = 36 × 5 = 180
Second term: 225 ÷ 9 × 4 = 25 × 4 = 100
Subtracting the second term from the first term:
180 - 100 = 80
The right-hand side of the equation is 400% of ?, which simplifies to:
(400 / 100) × ? = 4 × ?
Equating the two sides:
80 = 4 × ?
? = 80 / 4 = 20
62Numerical Ability
What will come in the place of question (?) mark in the following questions?
40% of 825 = 16 ⅔ % of 1260 + ?
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Answer: (A) 120
Explanation
Calculating 40% of 825 on the left-hand side:
40% of 825 = (40 / 100) × 825 = 0.40 × 825 = 330
Converting the percentage on the right-hand side to a fraction:
16 ⅔% = (50 / 3)% = 50 / 300 = 1 / 6
Calculating 1/6 of 1260:
(1 / 6) × 1260 = 210
Substituting these evaluated values back into the original equation:
330 = 210 + ?
Subtracting 210 from 330 to isolate ?:
? = 330 - 210 = 120
63Numerical Ability
What will come in the place of question (?) mark in the following questions?
18 ÷ 1.5 + 153 ÷ 17 + √(256) = ⁶²⁹⁄?
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Answer: (E) 17
Explanation
Evaluating each term on the left-hand side of the equation:
18 ÷ 1.5 = 12
153 ÷ 17 = 9
√256 = 16
Adding all three terms on the left-hand side together:
12 + 9 + 16 = 37
Setting the sum equal to the right-hand side expression 629 / ?:
37 = 629 / ?
Multiplying both sides by ? and dividing by 37 to isolate ?:
? = 629 / 37 = 17
64Numerical Ability
What will come in the place of question (?) mark in the following questions?
(110 + 70 - √(6400)) ÷ 25 + ? = (4)²
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Answer: (C) 12
Explanation
Evaluating the terms inside the parenthesis on the left-hand side first:
√6400 = 80
110 + 70 - 80 = 180 - 80 = 100
Dividing this result by 25 according to the equation:
100 ÷ 25 = 4
Evaluating the right-hand side term:
(4)² = 16
Substituting these simplified values into the overall equation:
4 + ? = 16
Subtracting 4 from both sides to find the unknown value ?:
? = 16 - 4 = 12
65Numerical Ability
What will come in the place of question (?) mark in the following questions?
(25% of 680) / (50% of 340) = ?
The table shows the number of workshops (science, economics, social science) attended by four students. Read the table to answer the following questions.
| Student | Science | Economics | Social Science |
|---------|--------:|----------:|---------------:|
| A | 136 | 188 | 100 |
| B | 134 | 122 | 105 |
| C | 150 | 120 | 132 |
| D | 125 | 80 | 120 |
Find the ratio of science workshops attended by A to Economics workshop attended by C.
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Answer: (A) 17:15
Explanation
From the given data table, student A attended 136 science workshops, while student C attended 120 economics workshops. To calculate the ratio of science workshops attended by student A to economics workshops attended by student C, we set up the ratio 136 : 120. Dividing both the numerator and denominator by their greatest common divisor of 8 gives 136 / 8 = 17 and 120 / 8 = 15. Hence, the simplified ratio is 17 : 15.
72Numerical Ability
The table shows the number of workshops (science, economics, social science) attended by four students. Read the table to answer the following questions.
| Student | Science | Economics | Social Science |
|---------|--------:|----------:|---------------:|
| A | 136 | 188 | 100 |
| B | 134 | 122 | 105 |
| C | 150 | 120 | 132 |
| D | 125 | 80 | 120 |
Find the average number of science workshops attended by A, B and C.
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Answer: (D) 140
Explanation
From the table, the science workshops attended by students A, B, and C are 136, 134, and 150 respectively. The total sum of science workshops attended by these three students is calculated as 136 + 134 + 150 = 420. The average number of science workshops is obtained by dividing the total sum by the number of students, which yields 420 / 3 = 140.
73Numerical Ability
The table shows the number of workshops (science, economics, social science) attended by four students. Read the table to answer the following questions.
| Student | Science | Economics | Social Science |
|---------|--------:|----------:|---------------:|
| A | 136 | 188 | 100 |
| B | 134 | 122 | 105 |
| C | 150 | 120 | 132 |
| D | 125 | 80 | 120 |
Find the economics workshops attended by C and D together is what percentage more than the social science workshop attended by A.
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Answer: (A) 100
Explanation
From the given data, student C attended 120 economics workshops and student D attended 80 economics workshops, giving a combined total of 120 + 80 = 200 economics workshops. Student A attended 100 social science workshops. The percentage by which the combined economics workshops exceed A's social science workshops is calculated using the percentage increase formula: [(200 - 100) / 100] × 100 = 100%.
74Numerical Ability
The table shows the number of workshops (science, economics, social science) attended by four students. Read the table to answer the following questions.
| Student | Science | Economics | Social Science |
|---------|--------:|----------:|---------------:|
| A | 136 | 188 | 100 |
| B | 134 | 122 | 105 |
| C | 150 | 120 | 132 |
| D | 125 | 80 | 120 |
If E attended 25% more economic workshop than that of A. find the difference between economics workshops attended by E and social science workshop attended by B.
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Answer: (C) 130
Explanation
Student A attended 188 economics workshops. Since student E attended 25% more economics workshops than student A, the number of economics workshops attended by E is 188 × (1 + 0.25) = 188 × 1.25 = 235. Student B attended 105 social science workshops. The required difference between the economics workshops attended by E and the social science workshops attended by B is 235 - 105 = 130.
75Numerical Ability
The table shows the number of workshops (science, economics, social science) attended by four students.
| Student | Science | Economics | Social Science |
|---------|--------:|----------:|---------------:|
| A | 136 | 188 | 100 |
| B | 134 | 122 | 105 |
| C | 150 | 120 | 132 |
| D | 125 | 80 | 120 |
The ratio of science to mathematics workshops attended by C is 3:1, then find the mathematic workshop attended by C is what percentage of social science workshops attended by D.
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Answer: (A) 41.67
Explanation
Student C attended 150 science workshops. Given that the ratio of science workshops to mathematics workshops attended by C is 3 : 1, the number of mathematics workshops attended by C is calculated as 150 / 3 = 50. Student D attended 120 social science workshops. The percentage of C's mathematics workshops relative to D's social science workshops is (50 / 120) × 100 = 500 / 12 = 41.67%.
76Numerical Ability
A train crosses a vertical pole in 25 seconds while moving at a speed of 72 km/h. If the speed of the train is increased by 18 km/h, find how much less time (in seconds) it will take to cross the same pole.
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Answer: (B) 5
Explanation
When a train crosses a pole, the distance covered equals the length of the train. Since the distance remains constant, time taken is inversely proportional to speed. The ratio of initial speed to new speed is 72 : (72 + 18) = 72 : 90 = 4 : 5. Consequently, the ratio of initial time to new time is 5 : 4. Since 5 units correspond to the initial time of 25 seconds, 1 unit equals 5 seconds. Therefore, the reduction in time is 1 unit, which equals 5 seconds.
77Numerical Ability
A shopkeeper marks an article 40% above its cost price and allows a 20% discount on the marked price. Find the profit percentage earned by the shopkeeper.
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Answer: (A) 12%
Explanation
To find the net profit percentage, apply the formula for successive percentage changes when an article is marked up and then discounted: Net % = m - d - (m × d) / 100, where m is the markup percentage (40%) and d is the discount percentage (20%). Substituting these values into the formula yields Net % = 40 - 20 - (40 × 20) / 100 = 20 - 8 = 12%.
78Numerical Ability
The ratio of the present ages of Dimp and Kajal is 2 : 3. The sum of Dimp's age three years ago and Kajal's age five years hence is 52 years. Find the present age (in years) of Dimp.
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Answer: (D) 20
Explanation
Let the present ages of Dimp and Kajal be 2x and 3x respectively. Dimp's age three years ago was 2x - 3 and Kajal's age five years hence will be 3x + 5. According to the given condition, the sum of these ages equals 52 years, yielding the linear equation (2x - 3) + (3x + 5) = 52. Simplifying gives 5x + 2 = 52, which reduces to 5x = 50, so x = 10. The present age of Dimp is 2x = 2 × 10 = 20.
79Numerical Ability
Tanmay and Ajay started a business with investments of Rs. 5600 and Rs. 4200 respectively. At the end of the year, Tanmay's share of the profit is Rs. 8400. Find the total profit (in Rs) earned by the business.
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Answer: (E) 14700
Explanation
The ratio of profit sharing in a partnership is directly proportional to the ratio of investments made by the partners over equal time periods. Ratio of investments of Tanmay to Ajay = 5600 : 4200 = 4 : 3. Therefore, Tanmay's fraction of the total profit is 4 / (4 + 3) = 4/7. Given that Tanmay's share of the profit is Rs. 8400, the total profit earned by the business is 8400 × (7 / 4) = 14700.
80Numerical Ability
The weight of A is 200 kg. The weight of B is 25% more than that of C, and the weight of C is 20% more than that of A. Find the sum of the weights (in kg) of A, B, and C.
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Answer: (C) 740
Explanation
The weight of student A is given as 200 kg. Since the weight of C is 20% more than that of A, weight of C = 200 × (1 + 0.20) = 200 × 1.20 = 240 kg. The weight of B is 25% more than that of C, so weight of B = 240 × (1 + 0.25) = 240 × 1.25 = 300 kg. The total sum of the weights of A, B, and C is 200 + 300 + 240 = 740 kg.
81Numerical Ability
The ratio of milk to water in a vessel is 9 : 5 respectively. If 10 liters of water are added, the ratio of milk to water in the new mixture becomes 3 : 5 respectively. Find the initial quantity (in liters) of milk in the vessel.
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Answer: (C) 9
Explanation
Let the initial quantities of milk and water be 9x and 5x liters, respectively. When 10 liters of water are added, the new mixture has 9x liters of milk and 5x + 10 liters of water. Setting up the proportion 9x / (5x + 10) = 3 / 5 gives 45x = 15x + 30, which yields 30x = 30 and x = 1. Therefore, the initial quantity of milk is 9 × 1 = 9 liters.
82Numerical Ability
The length of a rectangle is 8 cm more than its breadth. If the perimeter of the rectangle is 40 cm, find the area of the rectangle (in cm² ).
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Answer: (A) 84
Explanation
Let the breadth of the rectangle be b cm, so its length is b + 8 cm. The perimeter is given by 2(length + breadth) = 2(2b + 8) = 40. Solving 4b + 16 = 40 gives b = 6 cm. Consequently, the length is 14 cm, and the area of the rectangle is 14 × 6 = 84 cm².
83Numerical Ability
A man invested Rs P at 20% per annum simple interest for 6 years and earned an interest of Rs 2880. Find the value of P - 200.
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Answer: (E) 2200
Explanation
Simple interest is calculated using SI = (P × R × T) / 100. Substituting the given values gives 2880 = (P × 20 × 6) / 100, which simplifies to 2880 = 1.2P. Solving for P yields P = 2400. Thus, the value of P - 200 is 2400 - 200 = 2200.
84Numerical Ability
A number is increased by 40% , and the same number is then decreased by 80% . If the difference between the two results is 360, find the original number.
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Answer: (D) 300
Explanation
Let the original number be N. Increasing N by 40% gives 1.4N, and decreasing N by 80% gives 0.2N. The difference between the two results is 1.4N - 0.2N = 1.2N = 360. Dividing 360 by 1.2 gives N = 300.
85Numerical Ability
A boat can travel 24 km downstream in 3 hours and the same distance upstream in 6 hours. Find the speed of the boat in still water (in km/hr).
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Answer: (B) 6
Explanation
The downstream speed is 24 / 3 = 8 km/hr, and the upstream speed is 24 / 6 = 4 km/hr. The speed of the boat in still water is half the sum of the downstream and upstream speeds: (8 + 4) / 2 = 6 km/hr.
86Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
7, 14, 28, 52, 112, 224
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Answer: (B) 52
Explanation
Each term in the series is multiplied by 2 to obtain the next term. Starting with 7: 7 × 2 = 14, 14 × 2 = 28, 28 × 2 = 56, 56 × 2 = 112, and 112 × 2 = 224. Therefore, 52 is incorrect and should be replaced by 56.
87Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
141, 129, 112, 105, 93, 81, 69
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Answer: (B) 112
Explanation
Subtracting 12 from each term gives the successive term in the series: 141 - 12 = 129, 129 - 12 = 117, 117 - 12 = 105, 105 - 12 = 93, 93 - 12 = 81, and 81 - 12 = 69. Thus, 112 is wrong and should be 117.
88Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
50, 51, 57, 70, 94, 131, 186
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Answer: (D) 186
Explanation
The differences between consecutive terms are 1, 6, 13, 24, 37, and 54, which correspond to second differences of prime numbers: 5, 7, 11, 13, and 17. Adding 17 to 37 gives a final difference of 54, so the last term should be 131 + 54 = 185. Therefore, 186 is incorrect.
89Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
212, 228, 253, 289, 338, 400, 483
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Answer: (A) 400
Explanation
The differences between consecutive terms are consecutive square numbers starting from 4²: 212 + 4² = 228, 228 + 5² = 253, 253 + 6² = 289, 289 + 7² = 338, 338 + 8² = 402, and 402 + 9² = 483. Thus, 400 is wrong and should be replaced by 402.
90Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
2, 3, 6, 22, 89, 446, 2677
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Answer: (B) 6
Explanation
The series follows the pattern where each term after the first is obtained by multiplying the previous term by an increasing integer and adding 1. Starting from 2: 2 × 1 + 1 = 3, 3 × 2 + 1 = 7, 7 × 3 + 1 = 22, 22 × 4 + 1 = 89, 89 × 5 + 1 = 446, and 446 × 6 + 1 = 2677. Therefore, 6 is wrong and should be replaced by 7.
91Numerical Ability
What should come in place of question mark (?) in the following questions?
³√(729) +37½% of5⅓ = ? + 2