IBPS RRB Clerk Prelims 2025 Reasoning Questions with Solutions

Explanation

B is a male who has a daughter A and an only son G. G is married to C, who is the daughter of F and D. Since C is the wife of B's son G, C is the daughter-in-law of B.

Explanation

D is married to F, and together they have daughters C and H. G is married to C, making G the son-in-law of D.

Explanation

H is the unmarried sister of C. C's husband G is therefore the brother-in-law of H. Since E is the son of C and G, E is the son of G.

Explanation

Analyzing the alphabetical positions of the letters in each set shows that K(11)-M(13)-O(15), G(7)-I(9)-K(11), B(2)-D(4)-F(6), and E(5)-G(7)-I(9) all follow a consistent pattern of skipping one letter (+2, +2). In contrast, U(21)-X(24)-Z(26) skips two letters (+3) and then one letter (+2).

Explanation

Comparing 'Mat on brown table' (uy ir ps ks) and 'Metal on glasses' (ps ko re) identifies 'on' as 'ps'. Comparing 'Mat on brown table' and 'Glasses kept brown' (ko gt uy) identifies 'brown' as 'uy'. Comparing 'Mat on brown table' and 'Under metal mat box' (ym ef re ks) identifies 'mat' as 'ks'. The remaining word in the first statement is 'table', which corresponds to 'ir'. Comparing 'Glasses kept brown' with 'Metal on glasses' gives 'glasses' as 'ko', leaving 'kept' as 'gt'. Combining these gives 'gt ps ir'.

Explanation

From the given statements, 'uy' uniquely decodes to 'brown'. However, comparing the third statement 'Under metal mat box' (ym ef re ks) with the other statements leaves the codes 'ym' and 'ef' distributed between the words 'under' and 'box'. Because 'ef' could refer to either 'under' or 'box', the pair 'uy ef' could translate to either 'brown under' or 'brown box'.

Explanation

Comparing 'Mat on brown table' (uy ir ps ks) with 'Under metal mat box' (ym ef re ks) reveals that 'mat' is coded as 'ks'. Comparing 'Metal on glasses' (ps ko re) with 'Glasses kept brown' (ko gt uy) reveals that 'glasses' is coded as 'ko'. Thus, 'Mat Glasses' corresponds to 'ks ko'.

Explanation

In 'Metal on glasses' (ps ko re), 'on' is coded as 'ps' and 'glasses' is coded as 'ko'. This leaves 'metal' mapped directly to 're'.

Explanation

Comparing 'Mat on brown table' (uy ir ps ks) and 'Glasses kept brown' (ko gt uy), the only common word is 'brown' and the only common code is 'uy'. Therefore, 'uy' stands for 'brown'.

Explanation

The six birth dates in chronological order are 7th March, 24th March, 7th April, 24th April, 7th May, and 24th May. Placing C on 7th April (slot 3) and F two positions after (slot 6, 24th May) leaves open slots. Placing A on 24th April (slot 4) allows B to be born immediately after on 7th May (slot 5), which leaves one person (C) between E on 24th March (slot 2) and A. Finally, D occupies 7th March (slot 1). Thus, B was born on 7th May.

Explanation

The six birth slots in chronological order are 7th March, 24th March, 7th April, 24th April, 7th May, and 24th May. C is born on 7th April (slot 3). Since two persons are born between C and F, F must be born on 24th May (slot 6). B is born immediately after A, forming an (A, B) pair. Since one person is born between A and E, placing A on 24th April (slot 4) and B on 7th May (slot 5) allows E to be on 24th March (slot 2). The remaining person D occupies 7th March (slot 1).

Explanation

In the chronological birth order (7th March: D, 24th March: E, 7th April: C, 24th April: A, 7th May: B, 24th May: F), E is born on 24th March, which is the second slot. The four persons born after E are C, A, B, and F.

Explanation

In the birth order D (1st slot), E (2nd slot), C (3rd slot), A (4th slot), B (5th slot), and F (6th slot), D is related to C by moving two slots forward. Similarly, C is related to B by moving two slots forward. Following the same pattern, moving two slots forward from A (4th slot) yields F (6th slot), so A is related to F.

Explanation

D and E are born in March, while B and F are born in May, both of which are months with 31 days. C is born in April, which has 30 days.

Explanation

Applying the given rules to PREVAIL: P (consonant) becomes O R (consonant) becomes Q E (vowel) becomes F V (consonant) becomes U A (vowel) becomes B I (vowel) becomes J L (consonant) becomes K The new arrangement of letters is O, Q, F, U, B, J, K. Among these letters, O and U are vowels, giving a total of two vowels.

Explanation

Placing the eight persons around the square table (Corners facing IN: A at Pos 1, H at Pos 3, C at Pos 5, B at Pos 7; Middles facing OUT: D at Pos 2, G at Pos 4, F at Pos 6, E at Pos 8), A and C, B and H, F and D, and G and E sit directly opposite to each other with three persons between them. In contrast, E and C sit adjacent to each other.

Explanation

E sits at the middle of a side facing outward. Facing outward means right corresponds to the clockwise direction around the table. Moving five positions clockwise from E (Pos 8) passes B (Pos 7), F (Pos 6), C (Pos 5), and G (Pos 4), arriving at H (Pos 3).

Explanation

C sits at a corner facing inward, so left corresponds to the clockwise direction around the table. Moving clockwise from C (Pos 5) towards D (Pos 2), the persons sitting in between are G (Pos 4) and H (Pos 3), making a total of two persons.

Explanation

B sits at a corner facing inward, so left corresponds to the clockwise direction. Moving three positions clockwise from B (Pos 7) passes F (Pos 6) and C (Pos 5), reaching G at the third position (Pos 4).

Explanation

Persons at the corners (A, H, C, B) face inside, while persons at the middle of the sides (D, G, F, E) face outside. Since E is positioned at the middle of a side, E faces outside, making Statement II incorrect. Statement I is correct because G (Pos 4) and C (Pos 5) sit adjacent to each other. Statement III is correct because B (Pos 7) and H (Pos 3) sit opposite each other with three persons between them.

Explanation

Counting the positions of letters in the word 'TROUBLE' (T=20, R=18, O=15, U=21, B=2, L=12, E=5), the pair L and O has 2 letters between them in the word (B and U in reverse order) and 2 letters between them in the English alphabet (M and N). No other pair in forward or backward directions satisfies this condition.

Explanation

From the statement R > T ≤ W < K = P > H ≥ J: For conclusion I, combining W < K = P > H gives opposite inequality signs between W and H, so no definite relation can be established. For conclusion II, combining K = P > H ≥ J yields K > J, which means J < K strictly, making J ≤ K false.

Explanation

From the statement Q ≥ M < R = T > K ≥ S > V: For conclusion I, since R = T > K, it directly follows that R > K. For conclusion II, the path between M and V contains opposite inequality signs (M < R and T > V), so no definite relation exists between V and M.

Explanation

From the statement L > X ≥ D ≥ P = Y < H ≤ C: For conclusion I, since X ≥ D ≥ P = Y, it follows directly that X ≥ Y. For conclusion II, since P = Y < H ≤ C, it follows directly that P < C, which is equivalent to C > P.

Explanation

The statement 'Only a few cars are blue' means some cars are blue and some cars are not blue. The statement 'Some blue are fast' indicates an overlap between blue and fast. Since there is no negative restriction between cars and fast, it is possible that some cars are fast, making conclusion I true. Conclusion II is not necessarily true because all fast items could potentially be blue.

Explanation

From the statements, all red are fresh, and only a few fresh are dry. Red and dry can potentially overlap as there is no statement restricting red from being dry, so conclusion I is not definitely true. Since there is no relation preventing roses and dry from being completely separate, it is possible that no roses are dry, making conclusion II true.

Explanation

Since all rivers are valleys and some valleys are hills, rivers may or may not overlap with hills, so the possibility that no rivers are hills is true. Furthermore, since some valleys are hills and no hills are mountains, the portion of valleys that are hills can never be mountains, making it definitely true that some valleys are not mountains.

Explanation

Combining the clues gives the height order B > D > F > E > (A/C). Since B is taller than D, and D is taller than F, E, A, and C, B is the tallest person among all six. Therefore, all five other persons are shorter than B.

Explanation

The height order established is B > D > F > E > (A/C). Given that D is the second tallest at 181 cm and E is the third shortest (fourth tallest in a group of six) at 174 cm, the height of F must be strictly between 174 cm and 181 cm. 178 cm is the only value within this range.

Explanation

The height hierarchy from tallest to shortest is B (1st), D (2nd, 181 cm), F (3rd), E (4th, 174 cm), followed by A and C in the remaining two positions (5th and 6th). Since no clue specifies whether A is taller than C or C is taller than A, either C or A occupies the 5th position, which corresponds to the second shortest person.

Explanation

When the given words are arranged alphabetically from left to right, the series becomes ANT, DOG, EAT, JAM, SUN. Counting from the right end, the first word is SUN, the second is JAM, and the third is EAT.

Explanation

Changing the middle letter of each word to its next alphabet produces SVN, EBT, DPG, AOT, and JBM. None of these five formed letter combinations is a meaningful English word.

Explanation

The second word from the left end is EAT, whose first letter is E. The third word from the right end is DOG, whose third letter is G. In the English alphabet, only the letter F lies between E and G, giving a count of one letter.

Explanation

Arranging the letters of each word in dictionary order gives NSU, AET, DGO, ANT, and AJM. The third letters of these words are U, T, O, T, and M respectively. Among these, U and O are vowels, so exactly two words have a vowel as their third letter.

Explanation

Counting from the left end, the fourth word in the given series is ANT. The third letter from the left in ANT is T.

Explanation

The designations in decreasing order of seniority are CEO (1), COO (2), AM (3), GM (4), AGM (5), Manager (6), and Executive (7). Since A is four designations junior to G and D is immediately junior to A, G is CEO (1), A is AGM (5), and D is Manager (6). F is two designations senior to C, and two persons sit between B and C, which fixes C as GM (4), F as COO (2), B as Executive (7), and E as AM (3).

Explanation

From the final order of seniority—CEO: G, COO: F, AM: E, GM: C, AGM: A, Manager: D, Executive: B—C holds the 4th rank (GM). The persons junior to C are A (AGM), D (Manager), and B (Executive), making a total of three persons.

Explanation

The seniority order from highest to lowest is G (1), F (2), E (3), C (4), A (5), D (6), and B (7). Here, G is related to F because F is immediately junior to G, and C is related to A because A is immediately junior to C. Following the same pattern, D is immediately senior to B, so D is related to B.

Explanation

Arranging the seven persons from highest rank to lowest rank gives CEO: G, COO: F, AM: E, GM: C, AGM: A, Manager: D, and Executive: B. Therefore, the designation of B is Executive.

Explanation

The seniority hierarchy from rank 1 to rank 7 is CEO: G, COO: F, AM: E, GM: C, AGM: A, Manager: D, and Executive: B. D is at rank 6 (Manager). Moving two designations senior leads to rank 4, which is C (GM).

Explanation

The third letter from the left end of the series is V, located at position 5. Moving to the right of V, the symbols encountered in order are # at position 8, % at position 11, ! at position 14, @ at position 16, and ? at position 20. Therefore, the fifth symbol to the right of the third letter is ?.

Explanation

Removing all symbols ( , *, #, %, !, @, ?, +, ^, ) and vowels (A, U) leaves only the consonants: P, K, V, Z, L, W, S, R, M, X, F, Y, Q, C, T, Z. Counting six positions from the right end gives Z (1st), T (2nd), C (3rd), Q (4th), Y (5th), and F (6th).

Explanation

Counting symbols from the right end gives (1st), (2nd), + (3rd), ? (4th), @ (5th), ! (6th), and % (7th), which is at position 11. Moving four elements to the right of position 11 lands on position 15, which contains the letter M.

Explanation

A letter must be sandwiched between two symbols in the pattern Symbol-Letter-Symbol. Scanning the series gives four such letters: K in | K *, M in ! M @, Q in ? Q +, and C in + C ^.

Explanation

The vowels present in the series are A and U. Checking each vowel, A is followed by the symbol %, while U is followed by the letter T. Thus, only U meets the condition of being a vowel immediately followed by a letter.

Explanation

Numbering the row positions from 1 to 21 from left to right puts E at position 2 and K at position 3. H is third to the right of K, placing H at position 6. D is five persons away from H at position 12, leaving 9 persons between E and D and 9 persons to the right of D for a total of 21 persons. J sits at position 15, and A sits two places to the right of J at position 17. Subtracting 11 from position 17 gives position 6, where H sits.

Explanation

In the linear arrangement of 21 persons, the element at position 15 is separated from the rightmost position (21) by calculating 21 - 15 + 1 = 7. Hence, its position is seventh from the right end.

Explanation

E sits second from the left end at position 2. K is at position 3 and H is at position 6. With five persons between H and D, D is at position 12. Since there are 9 persons between E (position 2) and D (position 12), there must also be 9 persons to the right of D, making the rightmost position 12 + 9 = 21. Thus, the total number of persons in the row is 21.

Explanation

From the statement chain K ≤ F < R = G > U < V = W: For conclusion I (R > W), the symbols between R and W are = G > U < V =, which contains opposing inequalities (> and <), so no definite relationship can be formed. For conclusion II (K < G), combining K ≤ F < R and R = G directly gives K < G. Therefore, only conclusion II is true.

Explanation

From the given statement M > B ≤ C ≤ A = E ≤ O ≥ F > G = P: For conclusion I (P < O), following the path from O to P gives O ≥ F > G = P, which simplifies to O > P or P < O. For conclusion II (O ≥ B), following the path from B to O gives B ≤ C ≤ A = E ≤ O, which simplifies to B ≤ O or O ≥ B. Therefore, both conclusions I and II are true.