Simple interest on a certain sum at 12% p.a. for five years is Rs 1560. Find the difference between the simple interest and the principal amount.
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Answer: (B) Rs 1040
Explanation
Simple interest SI = P × R × T / 100.
1560 = P × 12 × 5 / 100
1560 = 0.6 × P
P = 2600
Difference between principal and simple interest = P - SI = 2600 - 1560 = 1040.
52Numerical Ability
The average of X, Y, and Z is 9, and the difference between Z and X is 5, which is half of Y. If Z is greater than X, then find the value of Z.
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Answer: (D) 11
Explanation
From the average of X, Y, and Z, X + Y + Z = 27.
Since half of Y is 5, Y = 10.
Substituting Y = 10 into the sum gives X + Z = 17.
Given Z - X = 5, adding the two equations yields 2Z = 22, which gives Z = 11.
53Numerical Ability
The present age of Jerry is 16 years more than that of Tom, while four years hence the ratio of Jerry to Tom will be 11:7, respectively. Find the present age of Jerry.
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Answer: (A) 40 years
Explanation
Let Jerry's present age be J and Tom's present age be T.
J = T + 16
Four years hence, (J + 4) / (T + 4) = 11 / 7.
Substituting J = T + 16 gives (T + 20) / (T + 4) = 11 / 7.
7(T + 20) = 11(T + 4)
7T + 140 = 11T + 44
4T = 96
T = 24
Jerry's present age J = 24 + 16 = 40 years.
54Numerical Ability
A can complete a work in 15 days, while A and B together can complete 3/5th of the work in 4 days. In how many days B alone can complete the whole work?
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Answer: (B) 12
Explanation
A's 1-day work = 1/15.
A and B together complete 3/5th of work in 4 days, so they complete the whole work in 4 × 5/3 = 20/3 days.
Their combined 1-day work = 3/20.
B's 1-day work = 3/20 - 1/15 = (9 - 4) / 60 = 5/60 = 1/12.
Therefore, B alone can complete the whole work in 12 days.
55Numerical Ability
B has 78% more chocolates than that of A. If the total number of chocolates B has is 89, then find the total number of chocolates A has.
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Answer: (E) 50
Explanation
Since B has 78% more chocolates than A, B = 1.78 × A.
Given B = 89, substituting into the equation gives 1.78 × A = 89.
A = 89 / 1.78 = 50.
56Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
8, 27, 125, 343, 121, 2197, 4913
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Answer: (B) 121
Explanation
The pattern in the series is cubes of consecutive prime numbers:
2³ = 8
3³ = 27
5³ = 125
7³ = 343
11³ = 1331
13³ = 2197
17³ = 4913
The number 121 is given instead of 1331, making it the wrong number in the series.
57Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
3264, 1632, 816, 408, 206, 102, 51
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Answer: (A) 206
Explanation
The pattern in the series is dividing each successive number by 2:
3264 ÷ 2 = 1632
1632 ÷ 2 = 816
816 ÷ 2 = 408
408 ÷ 2 = 204
204 ÷ 2 = 102
102 ÷ 2 = 51
The term 206 should be 204, making 206 the wrong number in the series.
58Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
20, 41, 83, 167, 335, 670, 1343
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Answer: (E) 670
Explanation
The pattern in the series is multiplying by 2 and adding 1:
20 × 2 + 1 = 41
41 × 2 + 1 = 83
83 × 2 + 1 = 167
167 × 2 + 1 = 335
335 × 2 + 1 = 671
671 × 2 + 1 = 1343
The number 670 is given instead of 671, making it the wrong number in the series.
59Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
203, 186, 169, 152, 135, 118, 104
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Answer: (D) 104
Explanation
The pattern in the series is subtracting 17 from each preceding term:
203 - 17 = 186
186 - 17 = 169
169 - 17 = 152
152 - 17 = 135
135 - 17 = 118
118 - 17 = 101
The number 104 is given instead of 101, making it the wrong number in the series.
60Numerical Ability
In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.
27, 54, 108, 214, 432, 864, 1728
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Answer: (B) 214
Explanation
The pattern in the series is multiplying each successive number by 2:
27 × 2 = 54
54 × 2 = 108
108 × 2 = 216
216 × 2 = 432
432 × 2 = 864
864 × 2 = 1728
The term 214 is given instead of 216, making 214 the wrong number in the series.
61Numerical Ability
What will come in the place of question (?) mark in following the question:
(?+3)⁄₅ + ⁵⁄₁₅ = ²⁴⁄₁₅
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Answer: (C) 10/3
Explanation
Start with (?+3)/5 + 5/15 = 24/15. Simplify 5/15 to 1/3, and rewrite (?+3)/5 with denominator 15, giving 3(?+3)/15 + 5/15 = 24/15. Multiplying through by 15 gives 3(?+3) + 5 = 24, so 3(?+3) = 19. Dividing by 3 gives ?+3 = 19/3, so ? = 19/3 - 9/3 = 10/3.
62Numerical Ability
What will come in the place of question (?) mark in following the question:
⁵⁄₄ + ⁹⁄₃ - ⁶⁄₆ + ⁴⁄₂ = ?
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Answer: (A) ¹²⁄₁₂ ¹¹⁄₁₂
Explanation
Simplifying each term gives 5/4 + 3 - 1 + 2 = 5/4 + 4 = 21/4, which equals 5.25.
63Numerical Ability
What will come in the place of question (?) mark in following the question:
⅚ of ⁸⁄₇ of ²¹⁄₂₄ of 2526 = ?
What will come in the place of question (?) mark in following the question:
¹¹⁴⁄₃₃₃ × ²⁵²⁄₁₂₁ × ²²⁄₉ = ²⁸⁄₃₇ × ¹⁹⁄?
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Answer: (E) 8.25
Explanation
Simplify the left side first: 252/121 × 22/9 reduces because 121 = 11 × 11 and 22 = 2 × 11, giving 252 × 2/(11 × 9) = 56/11. Multiplying by 114/333, and noting 114/333 reduces to 38/111, gives (38/111) × (56/11) = 2128/1221. On the right side, 28/37 × 19/x = 532/(37x). Setting 2128/1221 equal to 532/(37x) and cross-multiplying gives 2128 × 37x = 532 × 1221, and since 1221 = 33 × 37, this simplifies to 2128x = 532 × 33, so x = 17556/2128 = 8.25.
66Numerical Ability
What will come in the place of question (?) mark in following the question:
(19)² - 23 × 12 = ?² + 256 ÷ 4³
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Answer: (A) 9
Explanation
19² - 23 × 12 = 361 - 276 = 85. The right side simplifies to ?² + 256 ÷ 64 = ?² + 4. Solving 85 = ?² + 4 gives ?² = 81, so ? = 9.
67Numerical Ability
What will come in the place of question (?) mark in following the question:
√((587 + 638) ÷ 25 + ?) = 2828 ÷ 7
What will come in the place of question (?) mark in following the question:
42% of 800 + (725)/(?) = (19)²
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Answer: (E) 29
Explanation
42% of 800 = 336 and 19² = 361. The equation becomes 336 + 725/? = 361. Subtracting 336 from 361 gives 725/? = 25, so ? = 725 / 25 = 29.
69Numerical Ability
What will come in the place of question (?) mark in following the question:
(?)/(2) = ¹³⁄₂₆₀ + ⁸⁰⁄₄₈₀
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Answer: (A) 13/30
Explanation
Simplify the right-hand side: 13/260 reduces to 1/20 and 80/480 reduces to 1/6. Taking a common denominator of 60 gives 3/60 + 10/60 = 13/60. The equation is therefore ?/2 = 13/60, so ? = 2 x 13/60 = 26/60. Reducing gives ? = 13/30.
70Numerical Ability
What will come in the place of question (?) mark in following the question:
18² + (40% of 200)/(5) = (17)/(?)
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Answer: (B) 1/20
Explanation
18² = 324 and (40% of 200) / 5 = 80 / 5 = 16. The left-hand side sums to 324 + 16 = 340. Setting 340 = 17/? gives ? = 17 / 340 = 1/20.
71Numerical Ability
What will come in the place of question (?) mark in following the question:
(3)/(³√(3375)) ÷ (80)/(5²) = ?
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Answer: (E) 1/8
Explanation
To evaluate the given mathematical expression, simplify the individual components using power and root properties:
∛3375 = 15
5² = 25
Now substitute these values back into the simplified fraction form:
3 / 15 = 1 / 5
80 / 25 = 16 / 5
Next, perform the division of the two fractions by multiplying the first fraction by the reciprocal of the second:
(1 / 5) ÷ (16 / 5) = (1 / 5) × (5 / 16) = 1 / 16
72Numerical Ability
What will come in the place of question (?) mark in following the question:
⁵⁄₉ of 180 + 8² = ? - 24
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Answer: (C) 188
Explanation
To find the unknown value, simplify each component on the left-hand side of the equation using the order of operations:
Add these terms together to find the value of the left-hand side:
100 + 64 = 164
Set up the linear equation for the unknown value:
164 = ? - 24
? = 164 + 24 = 188
73Numerical Ability
What will come in the place of question (?) mark in following the question:
318+980-224-540=?
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Answer: (E) 534
Explanation
To evaluate the arithmetic expression, combine the positive and negative terms step by step following standard order of operations:
First, add the positive terms:
318 + 980 = 1298
Next, subtract the first negative term:
1298 - 224 = 1074
Finally, subtract the second negative term:
1074 - 540 = 534
Alternatively, group the additions and subtractions:
(318 + 980) - (224 + 540) = 1298 - 764 = 534
74Numerical Ability
What will come in the place of question (?) mark in following the question:
²²⁴⁄₄₉ × ⁷⁄₁₆ = 5 × ?
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Answer: (A) 2/5
Explanation
To solve for the unknown variable, first simplify the left-hand side by cancelling common factors:
(224 / 49) × (7 / 16)
Cancel 7 in the numerator and 49 in the denominator:
(224 / 7) × (1 / 16) = 32 × (1 / 16) = 32 / 16 = 2
Now set the simplified left-hand side equal to the right-hand side:
2 = 5 × ?
Isolate the question mark by dividing both sides by 5:
? = 2 / 5
75Numerical Ability
What will come in the place of question (?) mark in following the question:
12³ - 728 = ? + 33.33% of 69
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Answer: (B) 977
Explanation
To find the unknown value, evaluate both sides of the equation using percentage and exponent identities:
First, calculate the cube:
12³ = 1728
Subtract 728 to find the value of the left-hand side:
1728 - 728 = 1000
Next, convert 33.33% to its equivalent fraction 1/3:
33.33% of 69 = (1 / 3) × 69 = 23
Set up the simplified equation:
1000 = ? + 23
Isolate the unknown value by subtracting 23 from 1000:
? = 1000 - 23 = 977
76Numerical Ability
The average marks obtained by a student in five subjects is 105. If we exclude marks of three subjects which average is 72 excluding highest and lowest mark obtained by the student, then find the sum of highest and lowest mark obtained by the student?
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Answer: (C) 309
Explanation
Total marks obtained in 5 subjects = 5 × 105 = 525.
The average of the 3 subjects excluding highest and lowest is 72, so their sum = 3 × 72 = 216.
Sum of highest and lowest marks = Total marks - Sum of remaining 3 subjects = 525 - 216 = 309.
77Numerical Ability
6 bulls can have plugged a field in 9 days, while 12 ox's can plugged the field in 6 days. Find in how many days 5 bulls and 4 ox's can plugged the same field?
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Answer: (A) 6
Explanation
Work done by 1 bull in 1 day = 1 / (6 × 9) = 1/54.
Work done by 1 ox in 1 day = 1 / (12 × 6) = 1/72.
Combined daily work rate of 5 bulls and 4 oxen = 5 × (1/54) + 4 × (1/72) = 5/54 + 1/18 = (5 + 3)/54 = 8/54 = 4/27.
Number of days required to complete the field = 1 / (4/27) = 27/4 = 6.75 days (or 6 ¾ days).
78Numerical Ability
The length of a rectangle is 3 cm more than its breadth. If the perimeter of the rectangle is 66 cm, then find the area of the rectangle (in cm square)?
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Answer: (B) 270
Explanation
Let the breadth of the rectangle be B cm. Then length L = B + 3 cm.
Perimeter = 2(L + B) = 66
2(B + 3 + B) = 66
2B + 3 = 33
2B = 30 ⇒ B = 15 cm
Length L = 15 + 3 = 18 cm.
Area of rectangle = L × B = 18 × 15 = 270 cm².
79Numerical Ability
A vessel contains mixture of milk and water in the ratio of 11 : 8. When 8 liters of milk and 24 liters of water added in the mixture, then the ratio of milk to water in resultant mixture becomes 7 : 6. Find the quantity of water in the initial mixture?
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Answer: (D) 96 liters
Explanation
Let the initial quantities of milk and water be 11x and 8x liters respectively.
After adding 8 liters of milk and 24 liters of water:
(11x + 8) / (8x + 24) = 7 / 6
Cross-multiplying:
6(11x + 8) = 7(8x + 24)
66x + 48 = 56x + 168
10x = 120 ⇒ x = 12
Initial quantity of water = 8x = 8 × 12 = 96 liters.
80Numerical Ability
There are two numbers and smaller number is 13 more than half off the bigger number. If difference between bigger and smaller number is 78, then find the smaller number?
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Answer: (D) 104
Explanation
Let the bigger number be B and smaller number be S.
Given, S = ½ B + 13 ⇒ B = 2S - 26.
Also, B - S = 78.
Substituting B into the difference equation:
(2S - 26) - S = 78
S - 26 = 78 ⇒ S = 104.
81Numerical Ability
X is 24 more than Y and 3/5th of X is 16 less than Y. Find the value of 'Y'?
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Answer: (C) 76
Explanation
Given X = Y + 24, so Y = X - 24.
Also, ⅗ X = Y - 16.
Substituting Y = X - 24:
⅗ X = (X - 24) - 16
⅗ X = X - 40
X - ⅗ X = 40
⅖ X = 40 ⇒ X = 100.
Therefore, Y = 100 - 24 = 76.
82Numerical Ability
Three years ago, the age of A was 21 years. Four years hence, the ratio of age of A to that of B will be 7 : 5. Find the present age of B (in years)?
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Answer: (D) 16
Explanation
Present age of A = 21 + 3 = 24 years.
Age of A after 4 years = 24 + 4 = 28 years.
Ratio of ages of A to B after 4 years = 7 : 5.
Let age of B after 4 years be B₄.
28 / B₄ = 7 / 5 ⇒ B₄ = 20 years.
Present age of B = 20 - 4 = 16 years.
83Numerical Ability
P started business with Rs 2500 and after 4 months, Q joined him with Rs X. At the end of one year, the ratio of profit share of P and Q is 5 : 4. Find the value of X (in Rs.)?
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Answer: (E) 3000
Explanation
Profit ratio of P and Q = (Investment of P × Time) : (Investment of Q × Time)
(2500 × 12) / (X × 8) = 5 / 4
30000 / 8X = 5 / 4
3750 / X = 5 / 4
5X = 15000 ⇒ X = 3000.
84Numerical Ability
A man invested Rs P on simple interest at rate of 12% p.a. for five years and he received Rs 2700 as interest. Find the value of P (in Rs.)?
A man travelled a certain distance by car for 2 hours at 60 km/hr, by Bus for 5 hours at 80 km/hr and the remaining distance by bicycle at 10 km/hr for 5 hours. Find the average speed of man in the whole journey?
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Answer: (C) 47.5 km/hr
Explanation
Distance covered by car = 2 × 60 = 120 km.
Distance covered by bus = 5 × 80 = 400 km.
Distance covered by bicycle = 5 × 10 = 50 km.
Total distance = 120 + 400 + 50 = 570 km.
Total time = 2 + 5 + 5 = 12 hours.
Average speed = Total distance / Total time = 570 / 12 = 47.5 km/hr.
86Numerical Ability
What will come in the place of question mark (?) in the following number series.
22, 24.5, 29.5, 37, 47, ?
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Answer: (D) 59.5
Explanation
The pattern in the series is based on adding increments that increase by 2.5 at each step:
24.5 - 22 = 2.5
29.5 - 24.5 = 5.0
37 - 29.5 = 7.5
47 - 37 = 10.0
The next difference is 10.0 + 2.5 = 12.5.
Adding this to the last term yields 47 + 12.5 = 59.5.
87Numerical Ability
What will come in the place of question mark (?) in the following number series.
413, 244, 123, 74, ?, 40
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Answer: (D) 49
Explanation
The differences between successive terms are squares of descending prime numbers:
413 - 244 = 169 = 13²
244 - 123 = 121 = 11²
123 - 74 = 49 = 7²
The next prime in descending order is 5, so the required subtraction is 5² = 25.
74 - 25 = 49.
Subtracting the next prime square 3² = 9 confirms 49 - 9 = 40.
88Numerical Ability
What will come in the place of question mark (?) in the following number series.
64, 68, 80, 116, 224, ?
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Answer: (D) 548
Explanation
The difference between terms follows a geometric progression with a common ratio of 3:
68 - 64 = 4
80 - 68 = 12 = 4 × 3
116 - 80 = 36 = 12 × 3
224 - 116 = 108 = 36 × 3
The next difference is 108 × 3 = 324.
Adding this difference to 224 gives 224 + 324 = 548.
89Numerical Ability
What will come in the place of question mark (?) in the following number series.
17, 22, 37, 62, ?, 142
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Answer: (E) 97
Explanation
The differences between adjacent terms increase by 10 at each step:
22 - 17 = 5
37 - 22 = 15
62 - 37 = 25
The next difference in the sequence is 25 + 10 = 35.
Adding this to 62 gives 62 + 35 = 97.
Continuing the pattern with 35 + 10 = 45 gives 97 + 45 = 142, confirming the calculation.
90Numerical Ability
What will come in the place of question mark (?) in the following number series.
48, ?, 123, 223, 423, 823
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Answer: (A) 73
Explanation
Examining the differences between adjacent terms from the right end of the series shows:
823 - 423 = 400
423 - 223 = 200
223 - 123 = 100
Halving the difference for each preceding step gives 50 and 25.
The missing term is 123 - 50 = 73.
Checking the first step gives 73 - 48 = 25, which confirms the pattern.
91Numerical Ability
The table given below shows number of students in three classes A, B and C in four different months March, April, May and June. Read the data carefully and answer the questions given below.
| Months | Class A | Class B | Class C |
|--------|--------:|--------:|--------:|
| March | 96 | 87 | 91 |
| April | 64 | 72 | 60 |
| May | 90 | 80 | 68 |
| June | 75 | 63 | 56 |
Find the difference between total number of students in class B | C together in May and total number of students in class A | C together in March?
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Answer: (D) 39
Explanation
Total students in class B and C together in May = 80 + 68 = 148.
Total students in class A and C together in March = 96 + 91 = 187.
Required difference = 187 - 148 = 39.
92Numerical Ability
The table given below shows number of students in three classes A, B and C in four different months March, April, May and June. Read the data carefully and answer the questions given below.
| Months | Class A | Class B | Class C |
|--------|--------:|--------:|--------:|
| March | 96 | 87 | 91 |
| April | 64 | 72 | 60 |
| May | 90 | 80 | 68 |
| June | 75 | 63 | 56 |
The average number of students in March, April | May in class C is what percent of total number of students in A in the month of June (approx.)?
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Answer: (A) 97%
Explanation
Total students in class C for March, April, and May = 91 + 60 + 68 = 219.
Average number of students in class C for these months = 219 / 3 = 73.
Total students in class A in June = 75.
Percentage = (73 / 75) × 100 = 97.33%, which rounds to approximately 97%.
93Numerical Ability
The table given below shows number of students in three classes A, B and C in four different months March, April, May and June. Read the data carefully and answer the questions given below.
| Months | Class A | Class B | Class C |
|--------|--------:|--------:|--------:|
| March | 96 | 87 | 91 |
| April | 64 | 72 | 60 |
| May | 90 | 80 | 68 |
| June | 75 | 63 | 56 |
If total number of students in class D in month of April are half of the total student in class A and B in the same month, then find the sum of total students in class D in month of April and students in class B in month of March?
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Answer: (B) 155
Explanation
Total students in class A and B in April = 64 + 72 = 136.
Students in class D in April = 136 / 2 = 68.
Students in class B in March = 87.
Required sum = 68 + 87 = 155.
94Numerical Ability
The table given below shows number of students in three classes A, B and C in four different months March, April, May and June. Read the data carefully and answer the questions given below.
| Months | Class A | Class B | Class C |
|--------|--------:|--------:|--------:|
| March | 96 | 87 | 91 |
| April | 64 | 72 | 60 |
| May | 90 | 80 | 68 |
| June | 75 | 63 | 56 |
Find the ratio of total students in class A in month of May to sum of total students in class B in month of May and total students in class C in month of April?
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Answer: (D) 9 : 14
Explanation
Students in class A in May = 90.
Sum of students in class B in May and class C in April = 80 + 60 = 140.
Required ratio = 90 : 140 = 9 : 14.
95Numerical Ability
The table given below shows number of students in three classes A, B and C in four different months March, April, May and June. Read the data carefully and answer the questions given below.
| Months | Class A | Class B | Class C |
|--------|--------:|--------:|--------:|
| March | 96 | 87 | 91 |
| April | 64 | 72 | 60 |
| May | 90 | 80 | 68 |
| June | 75 | 63 | 56 |
Total students in class A in month of March is what percent more than total students in class B in month of June?
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Answer: (E) 52%
Explanation
Students in class A in March = 96.
Students in class B in June = 63.
Difference = 96 - 63 = 33.
Percentage more = (33 / 63) × 100 = (11 / 21) × 100 = 52.38%, which rounds to 52%.
96Numerical Ability
What value should come in place of (?) in the following questions. ²⁰⁹⁄₃₉₉× 21² -(11)² =?
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Answer: (A) 110
Explanation
Simplifying the fraction 209/399 by dividing numerator and denominator by 19 yields 11/21.
Substituting this back into the expression:
(11/21) × 21² - 11² = 11 × 21 - 121 = 231 - 121 = 110.
97Numerical Ability
What value should come in place of (?) in the following questions. 343 + 243 + 512 = 20% of?
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Answer: (B) 5490
Explanation
First, add the numbers on the left-hand side:
343 + 243 + 512 = 1098.
Let the required value be x.
20% of x = (20/100) × x = x / 5 = 1098.
x = 1098 × 5 = 5490.
98Numerical Ability
What value should come in place of (?) in the following questions. ³√(1728) + √(784) + √(1296) =? + ³√(512)
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Answer: (B) 68
Explanation
Evaluating each root individually:
∛1728 = 12, √784 = 28, √1296 = 36, and ∛512 = 8.
Substitute these values into the equation:
12 + 28 + 36 = ? + 8
76 = ? + 8
? = 76 - 8 = 68.
99Numerical Ability
What value should come in place of (?) in the following questions. √(256× 49) +(16)² - ³√(343) = (?)²