IBPS RRB Clerk Prelims 2022 Reasoning Questions with Solutions

Explanation

The 8th element from the left end of the alphanumeric series is W. To find the 4th element to its right, add 4 positions to its rank, giving the 12th element from the left end (8 + 4 = 12). Counting 12 elements from left: S (1), J (2), 2 (3), L (4), D (5), U (6), A (7), W (8), 8 (9), X (10), Q (11), and C (12). Thus, C is the required element.

Explanation

Scanning the series from left to right for letters that are immediately followed by a digit gives seven instances: J followed by 2, W followed by 8, C followed by 7, M followed by 4, Z followed by 9, E followed by 5, and T followed by 3. Because seven total letters satisfy this condition, the count exceeds six.

Explanation

The vowels present in the series are U, A, and E. Checking the surrounding characters for each vowel: U is preceded by D and followed by A (D U A, both letters); A is preceded by U and followed by W (U A W, both letters); E is preceded by N but followed by 5, which is a number. Therefore, exactly two vowels (U and A) are both preceded and followed by a letter.

Explanation

Checking each number in the series to see if it is preceded by a vowel and followed by a consonant: 2 is preceded by J; 8 is preceded by W; 7 is preceded by C; 6 is preceded by 7; 4 is preceded by M; 9 is preceded by Z; 1 is preceded by 9; 3 is preceded by T. Only the number 5 is preceded by the vowel E and followed by the consonant T, satisfying the Vowel-Number-Consonant sequence E 5 T. Thus, only one such number exists.

Explanation

Analyzing the relative position jumps between elements in each term: in 2DA, 2 to D is +2 and D to A is +2; in 8Q7, 8 to Q is +2 and Q to 7 is +2; in R9N, R to 9 is +2 and 9 to N is +2; in 53Z, 5 to 3 is +2 and 3 to Z is +2. In 64H, 6 to 4 moves 2 places forward (+2), but 4 to H moves only 1 place forward (+1). Thus, 64H does not share the same pattern.

Explanation

Writing the alphabetical positions for H I E R A R C H Y gives H(8), I(9), E(5), R(18), A(1), R(18), C(3), H(8), Y(25). Comparing letter gaps: H and I are adjacent in both the word and the alphabet (1 letter distance). A and C have one letter between them in the word (R) as well as in the alphabet (B), making a distance of 2 positions. No other forward or backward letter pairs match their alphabetical distance, yielding two valid pairs.

Explanation

Since P attends on an even date and three persons attend between P and K, P must attend on 14th December and K on 14th April (placing P on 14th April would put K on 14th December, forcing N to be last, which violates the clue). L attends immediately after J in a different month, placing J on 23rd April and L on 14th July. N attends after K but not last, so N attends on 23rd July and M attends on 23rd December. Hence, L attends on 14th July.

Explanation

From the scheduling puzzle, the sequential order of attendees across the six seminar dates is: 14th April is K, 23rd April is J, 14th July is L, 23rd July is N, 14th December is P, and 23rd December is M. The persons scheduled between K on 14th April and M on 23rd December are J, L, N, and P, which totals four persons.

Explanation

From the scheduling analysis, the date-wise attendance list is: 14th April (K), 23rd April (J), 14th July (L), 23rd July (N), 14th December (P), and 23rd December (M). Looking at the seminar slot immediately preceding N (23rd July), L attends on 14th July.

Explanation

Checking each given pair against the established schedule: K attends on 14th April, P on 14th December, N on 23rd July, and M on 23rd December. Since L attends the seminar on 14th July while J attends on 23rd April, the combination L-23rd April is not true.

Explanation

The chronological order of seminar dates from top to bottom is: 14th April: K 23rd April: J 14th July: L 23rd July: N 14th December: P 23rd December: M

Arranging these persons alphabetically from top to bottom yields J, K, L, M, N, P. Comparing the two sequences: Position 1: K vs J Position 2: J vs K Position 3: L vs L (Unchanged) Position 4: N vs M Position 5: P vs N Position 6: M vs P

Only L remains in the same position.

Explanation

The original number is 7256291543. Arranging all digits in descending order from left to right gives: 9, 7, 6, 5, 5, 4, 3, 2, 2, 1

Interchanging adjacent pairs (1st with 2nd, 3rd with 4th, 5th with 6th, 7th with 8th, 9th with 10th) yields: 7, 9, 5, 6, 4, 5, 2, 3, 1, 2

The 3rd digit from the left end is 5. The 5th digit from the right end (6th digit from the left) is 5. The sum of these two digits is 5 + 5 = 10.

Explanation

The floor and flat distribution of all ten persons is: Floor 5: Flat I = S, Flat II = T Floor 4: Flat I = M, Flat II = U Floor 3: Flat I = Q, Flat II = P Floor 2: Flat I = C, Flat II = G Floor 1: Flat I = F, Flat II = D

U lives in Flat II on Floor 4. Directly below U's flat is Flat II on Floor 3, where P lives.

Explanation

The floor and flat distribution of all ten persons is: Floor 5: Flat I = S, Flat II = T Floor 4: Flat I = M, Flat II = U Floor 3: Flat I = Q, Flat II = P Floor 2: Flat I = C, Flat II = G Floor 1: Flat I = F, Flat II = D

The 3rd floor is occupied by Q in Flat I and P in Flat II.

Explanation

The floor and flat distribution of all ten persons is: Floor 5: Flat I = S, Flat II = T Floor 4: Flat I = M, Flat II = U Floor 3: Flat I = Q, Flat II = P Floor 2: Flat I = C, Flat II = G Floor 1: Flat I = F, Flat II = D

M, Q, C, and S all reside in Flat I, whereas D resides in Flat II. Thus, D does not belong to the group.

Explanation

The floor and flat distribution of all ten persons is: Floor 5: Flat I = S, Flat II = T Floor 4: Flat I = M, Flat II = U Floor 3: Flat I = Q, Flat II = P Floor 2: Flat I = C, Flat II = G Floor 1: Flat I = F, Flat II = D

Q lives in Flat I on Floor 3. Living south of Q means living in the same flat column below Floor 3. C lives in Flat I on Floor 2 and F lives in Flat I on Floor 1.

Explanation

The floor and flat distribution of all ten persons is: Floor 5: Flat I = S, Flat II = T Floor 4: Flat I = M, Flat II = U Floor 3: Flat I = Q, Flat II = P Floor 2: Flat I = C, Flat II = G Floor 1: Flat I = F, Flat II = D

D lives in Flat II on the 1st floor.

Explanation

The original sequence of numbers is: 264 945 748 457 523

Reversing the order of the numbers in the series yields: 523 457 748 945 264

Counting from the right end: 1st from right end: 264 2nd from right end: 945

Explanation

Arranging the given numbers in ascending order gives: 264 (1st lowest) 457 (2nd lowest) 523 (3rd lowest) 748 (4th lowest) 945 (5th lowest)

The 3rd lowest number is 523. Sum of its digits = 5 + 2 + 3 = 10.

Explanation

Interchanging the 1st and 3rd digit of each number gives: 264 becomes 462 945 becomes 549 748 becomes 847 457 becomes 754 523 becomes 325

The highest number among the new values is 847, which corresponds to the original number 748.

Explanation

From the statement F > R ≥ T = E > W ≤ Q, combining the terms from F to E yields F > E, which means E < F. Therefore, conclusion I is true. For conclusion II, moving from T to Q gives T = E > W ≤ Q, where the opposing inequality signs > and ≤ prevent any single relationship from being established between Q and T. Hence, conclusion II is false.

Explanation

From the statement W = G ≥ T = C ≤ V ≤ B, the relation between W and C is W ≥ C, and the relation between W and T is W ≥ T. Since T = C, the condition W ≥ C means that either W > C or W = C must hold true. Because conclusion II states W = T (which is equivalent to W = C), either conclusion I or conclusion II must be correct.

Explanation

From the statement K > I ≥ G > F ≤ T < R, assessing conclusion I (K > R) involves the path from K to R, which contains both > and < signs across F, so no relationship can be determined. Similarly, assessing conclusion II (R > G) involves the path G > F ≤ T < R, which also contains opposing inequality signs > and ≤ across F, making it impossible to determine a definite relation between R and G.

Explanation

From the statement Q > O ≥ P = K < U ≤ Z, tracking from K to Z gives K < U ≤ Z, which simplifies to K < Z, meaning Z > K. Thus, conclusion I is true. For conclusion II, tracking from Q to U gives Q > O ≥ P = K < U, where the presence of both > and < signs means no relation between Q and U can be concluded.

Explanation

From the statement K < G ≤ D < C > R ≤ Y, evaluating conclusion I involves the segment G ≤ D < C, which simplifies directly to G < C or C > G, making conclusion I true. Evaluating conclusion II involves the segment K < G ≤ D, which simplifies directly to K < D, making conclusion II true.

Explanation

To find the element that is 6th to the left of the 8th element from the right end, add the positions since the directions are opposite: 8 + 6 = 14th element from the right end. Counting 14 elements from the right end of the series B @ 9 # C 1 ε 2 8 D μ 7 K 5 L ε % U | F ε M G 4 ! 3 Z ? 6 X # P 5 A @ 6 gives 6, @, A, 5, P, #, X, 6, ?, Z, 3, !, 4, G. The 14th element from the right end is G.

Explanation

To find the required letters, we look for the pattern: Symbol → Letter → Number.

Scanning all the English alphabet letters in the given sequence: C 1 — The letter C is immediately preceded by the symbol # and immediately followed by the number 1. P 5 — The letter P is immediately preceded by the symbol # and immediately followed by the number 5.

Checking every other letter in the sequence shows that none of them fulfill both conditions at the same time. Therefore, there are exactly two such letters in the given series.

Explanation

Removing all letters from the series leaves only numbers and symbols: @ 9 # 1 ε 2 8 μ 7 5 ε % | ε 4 ! 3 ? 6 # 5 @ 6. Counting from the right end: 1st is 6, 2nd is @, 3rd is 5, 4th is #, 5th is 6, 6th is ?, 7th is 3, 8th is !, 9th is 4, 10th is ε, and 11th is | .

Explanation

To locate the element that is 4th to the right of the 9th element from the left end, combine the movements from the left end: 9 + 4 = 13th element from the left end. Counting from the left in the sequence B @ 9 # C 1 ε 2 8 D μ 7 K 5 L ε % U | F ε M G 4 ! 3 Z ? 6 X # P 5 A @ 6, the 9th element is 8, and moving 4 steps further right gives D (10th), μ (11th), 7 (12th), and K (13th).

Explanation

We search for the combination Vowel - Symbol - Number. The vowels present in the given sequence are U and A. Checking around U gives % U | , which is Symbol - Vowel - Symbol. Checking around A gives 5 A @ 6, where A is a vowel, @ is a symbol, and 6 is a number, matching the required pattern. Therefore, there is 1 such symbol.

Explanation

Arranging the six persons chronologically based on the given conditions gives: 11 September (B), 22 September (Q), 11 October (R), 22 October (D), 11 November (F), and 22 November (T). Since R was born on 11 October, three persons (D, F, and T) were born after R.

Explanation

Arranging the six persons chronologically gives B on 11 Sep, Q on 22 Sep, R on 11 Oct, D on 22 Oct, F on 11 Nov, and T on 22 Nov. Thus, F was born on 11th November.

Explanation

The chronological order of births is 11 Sep (B), 22 Sep (Q), 11 Oct (R), 22 Oct (D), 11 Nov (F), and 22 Nov (T). Analyzing the given statements: statement I is false since no one was born after T; statement II is true as two persons (Q and R) were born between B and D; and statement III is true as T was born after F. Therefore, both statements II and III are true.

Explanation

The birth order of the six persons is B on 11 Sep, Q on 22 Sep, R on 11 Oct, D on 22 Oct, F on 11 Nov, and T on 22 Nov. Hence, both R and D were born in the month of October.

Explanation

The chronological order of births is 11 Sep (B), 22 Sep (Q), 11 Oct (R), 22 Oct (D), 11 Nov (F), and 22 Nov (T). Since D was born on 22 October, two persons (F and T) were born after D.

Explanation

In the three-generation family, B and C are a married couple in the first generation with D as their daughter. D is married to A in the second generation, and together they have children J and K in the third generation. Since B is the father-in-law of A and C is the mother of D, S must be the mother of A, making her the paternal grandmother of K. Therefore, S is the mother-in-law of D.

Explanation

C is the mother of D, and D is the mother of J and K. Thus, C is the maternal grandmother of K.

Explanation

The family consists of B (male), C (female), S (female), A (male), D (female), J (male), and K. While C, S, and D are female and B, A, and J are male, the gender of K is not specified. Consequently, the exact number of female members in the family cannot be determined.

Explanation

In the number 95273524, counting digits both forward and backward yields three pairs: Position 2 (digit 5) and Position 4 (digit 7): 5-6-7 (1 digit between them in both number and series). Position 3 (digit 2) and Position 6 (digit 5): 2-3-4-5 (2 digits between them in both number and series). Position 6 (digit 5) and Position 4 (digit 7) counted backward: 5-6-7 (1 digit between them in both number and series). Thus, there are 3 pairs.

Explanation

Arranging the seven people facing the center in clockwise order starting from K yields: Position 1 = K, Position 2 = D, Position 3 = L, Position 4 = N, Position 5 = O, Position 6 = M, Position 7 = G. Counting four positions to the left (clockwise) from D at Position 2 leads to Position 6, which is occupied by M.

Explanation

Arranging the seven persons facing the center around the circle in clockwise order yields K at position 1, D at position 2, L at position 3, N at position 4, O at position 5, M at position 6, and G at position 7. Starting from N at position 4 and moving clockwise (left), the positions are 5 (O), 6 (M), and 7 (G). Therefore, G is 3rd to the left of N.

Explanation

In the circular sequence clockwise from M at position 6, the persons seated to the left of M are G (position 7), K (position 1), D (position 2), L (position 3), and N (position 4) before reaching O at position 5. Counting these individuals yields 5 persons, which is greater than four.

Explanation

With the persons seated in clockwise order as K (1), D (2), L (3), N (4), O (5), M (6), and G (7), moving to the right of K means moving counter-clockwise. The 1st person to the right of K is G (position 7) and the 2nd person to the right of K is M (position 6).

Explanation

In the clockwise arrangement K (1), D (2), L (3), N (4), O (5), M (6), and G (7), N and O occupy adjacent positions 4 and 5, making them immediate neighbors, so statement I is true. Position 2nd to the left of O (position 5) is G (position 7), not D, making statement II false. Between L (position 3) and G (position 7), there are two persons on one side (D, K) and three on the other (N, O, M), so statement III is false.

Explanation

The 2nd, 4th, 5th, and 8th letters of ACHIEVED are C, I, E, and D respectively. Using all four letters, at least two standard meaningful English words can be formed: DICE and ICED. As specified in the instructions, when more than one meaningful word can be formed, the code Y is given.

Explanation

Swapping the 1st and 3rd letters of each given word produces BAL (from LAB), XOF (from FOX), PIS (from SIP), TEB (from BET), and TEW (from WET). None of these five transformed strings form standard meaningful English words.

Explanation

A consonant changes to a vowel only if it is B, F, J, P, or V, because subtracting one position yields A, E, I, O, or U respectively. Vowels change to consonants (A to B, E to F, I to J, O to P, U to V). Checking the given words for B, F, J, P, or V: LAB contains B (becomes KBA, containing A), FOX contains F (becomes EPW, containing E), SIP contains P (becomes RJO, containing O), and BET contains B (becomes AFS, containing A). WET becomes VFS, containing no vowel. Thus, 4 words contain at least one vowel.

Explanation

Arranging the words in alphabetical order from left to right yields BET, FOX, LAB, SIP, WET. Counting from the right end: 1st from right is WET, 2nd from right is SIP, and 3rd from right is LAB.

Explanation

Rearranging the letters inside each word in alphabetical order yields ABL (from LAB), FOX (from FOX), IPS (from SIP), BET (from BET), and ETW (from WET). Out of these five, FOX and BET are valid meaningful English words, giving a total of two words.

Explanation

The given sequence of words is LAB, FOX, SIP, BET, WET. The 3rd word from the right end is SIP, whose 1st letter is S. The 2nd word from the left end is FOX, whose 2nd letter is O. In the English alphabet between O (15th letter) and S (19th letter), the letters are P, Q, and R, which amounts to exactly 3 letters.