SSC CHSL2024Quantitative AptitudePage 4 of 13

SSC CHSL Tier 1 2024 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 151–200 of 648, each with the correct answer and a step-by-step explanation.

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151Quantitative Aptitude
A and B can do a piece of work in eight days and B alone can do it in 16 days. In how many days, can A do it alone?
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Answer: (A) 16 days

Explanation

Using the work formula, the rate of work is given by: 1/A + 1/B = 1/Total

Here, the combined time of A and B is 8 days, and B's individual time is 16 days. Substituting these values into the formula: 1/A + 1/16 = 1/8

Subtracting 1/16 from both sides: 1/A = 1/8 - 1/16 1/A = (2 - 1)/16 1/A = 1/16

Thus, A alone can complete the piece of work in 16 days.

152Quantitative Aptitude
The given table shows the marks obtained by 100 students out of 50 marks in Mathematics and Physics in an examination. Marks / Subjects | 40 or above | 30 or above | 20 or above | 10 or above | 0 or above --- | --- | --- | --- | --- | --- Mathematics | 9 | 32 | 80 | 92 | 100 Physics | 4 | 21 | 66 | 81 | 100 Average | 7 | 27 | 73 | 87 | 100 If at least 60% marks in Physics are required for pursuing higher studies in Physics, how many students will be eligible to pursue higher studies in Physics?
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Answer: (B) 21

Explanation

The total marks for the examination are 50. To be eligible for higher studies in Physics, a student must obtain at least 60% of the total marks.

Required minimum marks = 60% of 50 = (60 / 100) × 50 = 30 marks

From the given table, the row for Physics shows the cumulative number of students who scored marks within different ranges. The number of students who scored 30 or above in Physics is 21. Thus, there are 21 students eligible to pursue higher studies in Physics.

153Quantitative Aptitude
The sum of two- digit number and the number obtained by interchanging the digit is 77. If the difference of digits is 1, then the number is:
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Answer: (B) 34

Explanation

Let the two-digit number be 10x + y, where x is the tens digit and y is the units digit. The number obtained by interchanging the digits is 10y + x.

According to the question, the sum of the two numbers is 77: (10x + y) + (10y + x) = 77 11x + 11y = 77 x + y = 7

The difference between the digits is 1: |x - y| = 1

Solving these two equations: If x - y = 1: Adding x + y = 7 and x - y = 1 gives 2x = 8, which means x = 4 and y = 3. This gives the number 43.

If y - x = 1: Adding x + y = 7 and y - x = 1 gives 2y = 8, which means y = 4 and x = 3. This gives the number 34.

Checking the given choices, the number 34 satisfies all the conditions.

154Quantitative Aptitude
An equal sum of money was lent to P and Q at 8.6% per annum for a period of 7 years and 8 years, respectively. If the difference in interest paid by them was ₹172, then the sum lent to each was:
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Answer: (A) 2,000

Explanation

The difference in simple interest for the same principal sum at a constant rate of interest is directly proportional to the difference in time periods.

Using the simple interest formula, Simple Interest = Principal × Rate × Time / 100.

The difference in interest paid by P and Q is: Difference in Interest = (Principal × Rate × (T₂ - T₁)) / 100

Substituting the given values: 172 = (Principal × 8.6 × (8 - 7)) / 100 172 = Principal × 8.6 / 100 172 = Principal × 0.086 Principal = 172 / 0.086 Principal = 2000

Thus, the sum lent to each was ₹2,000.

155Quantitative Aptitude
A solid copper sphere of radius 9 cm is drawn into a wire of radius 4 mm. Find the length of the wire.
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Answer: (B) 60.75 m

Explanation

The volume of the copper remains constant when it is drawn from a sphere into a cylindrical wire.

Volume of sphere = Volume of cylindrical wire 4/3 π R³ = π r² h

The radius of the sphere R is 9 cm, and the radius of the wire r is 4 mm, which is equal to 0.4 cm. Substituting these values into the formula:

4/3 × 9³ = 0.4² × h 4/3 × 729 = 0.16 × h 4 × 243 = 0.16 × h 972 = 0.16 × h h = 972 / 0.16 h = 6075 cm

To convert the length from centimeters to meters, divide by 100: h = 60.75 m

156Quantitative Aptitude
A chord of length 12 units in a circle of radius 10 units is ______ units away from its centre.
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Answer: (A) 8

Explanation

The perpendicular drawn from the centre of a circle to a chord bisects the chord.

For a chord of length 12 units, the perpendicular divides it into two segments of 6 units each. This perpendicular distance d, the half-chord length of 6 units, and the radius of 10 units form a right-angled triangle.

Applying Pythagoras' theorem: d² + 6² = 10² d² + 36 = 100 d² = 64 d = 8

The distance of the chord from the centre is 8 units.

157Quantitative Aptitude
The average age of 24 workers and their supervisor is 41 years. If the supervisor's age is excluded, the average reduces by 0.75 years. The age of the supervisor is:
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Answer: (A) 59 years

Explanation

Using the deviation method, when the supervisor is excluded, the average age of the remaining 24 workers decreases by 0.75 years. This indicates that the supervisor's age is greater than the initial average of 41 by the total sum of the decrease distributed across the remaining 24 workers.

Supervisor's age = Original average + (Decrease in average × Remaining number of workers)

Substituting the given values: Supervisor's age = 41 + (0.75 × 24) Supervisor's age = 41 + 18 Supervisor's age = 59 years

Alternatively, using the total sum method: Total age of 25 people = 25 × 41 = 1025 years New average age of 24 workers = 41 - 0.75 = 40.25 years Total age of 24 workers = 24 × 40.25 = 966 years Supervisor's age = 1025 - 966 = 59 years

158Quantitative Aptitude
PQ is a chord of a circle. The tangent XR at point X on the circle intersects the extension of PQ at point R. Given that XR = 12 cm , PQ = x cm , and QR = (x - 2) cm , find the value of x.
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Answer: (A) 10 cm

Explanation

According to the tangent-secant theorem, when a tangent segment and a secant segment are drawn to a circle from an exterior point, the square of the length of the tangent segment is equal to the product of the lengths of the external secant segment and the entire secant segment.

Applying this theorem to the given circle: XR² = QR × PR

The total length of the secant segment PR is the sum of PQ and QR: PR = PQ + QR = x + (x - 2) = 2x - 2

Substituting the given values into the relation: 12² = (x - 2)(2x - 2) 144 = 2(x - 2)(x - 1) 72 = (x - 2)(x - 1) 72 = x² - 3x + 2 x² - 3x - 70 = 0 (x - 10)(x + 7) = 0

Solving for x gives x = 10 or x = -7. Since the length of a segment must be positive, we discard the negative value. Thus, the value of x is 10 cm.

159Quantitative Aptitude
If (1)/(M):(1)/(N):(1)/(O) = 3:4:5 , then M : N : O is equal to:
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Answer: (B) 20 : 15 : 12

Explanation

To find the ratio M : N : O from the given ratio of their reciprocals, we take the reciprocal of each term:

M : N : O = 1/3 : 1/4 : 1/5

To convert this fractional ratio into integers, we multiply each term by the Least Common Multiple (LCM) of the denominators 3, 4, and 5. The LCM of 3, 4, and 5 is 60.

Multiplying each part of the ratio by 60:

M : N : O = (1/3 × 60) : (1/4 × 60) : (1/5 × 60)

M : N : O = 20 : 15 : 12

160Quantitative Aptitude
If sin θ = (2xy)/(x² + y²) , then the value of tan θ is:
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Answer: (A) (2xy)/(x² - y²)

Explanation

In a right-angled triangle, sin θ is the ratio of the perpendicular to the hypotenuse.

sin θ = perpendicular / hypotenuse = 2xy / (x² + y²)

By setting perpendicular P = 2xy and hypotenuse H = x² + y², the base B is calculated using the Pythagorean theorem:

B = √(H² - P²) B = √((x² + y²)² - (2xy)²) B = √(x⁴ + 2x²y² + y⁴ - 4x²y²) B = √(x⁴ - 2x²y² + y⁴) B = √((x² - y²)²) B = x² - y²

The trigonometric ratio for tan θ is the ratio of the perpendicular to the base:

tan θ = P / B = 2xy / (x² - y²)

161Quantitative Aptitude
In an election between two candidates, one candidate gets 72% of the total votes cast. If the total votes are 1000, by how many votes does the winner win the election?
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Answer: (D) 440

Explanation

The total percentage of votes cast in the election is 100%. The winning candidate gets 72% of the total votes, which means the losing candidate gets the remaining portion of the votes: 100% - 72% = 28%

The margin of victory is the difference in the percentage of votes received by the two candidates: 72% - 28% = 44%

Given that the total number of votes cast is 1000, the margin of victory in terms of votes is: 44% of 1000 = 0.44 × 1000 = 440

162Quantitative Aptitude
Write the smallest digit in the blank space of a number 7_7624, so that the number formed is divisible by 3.
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Answer: (B) 1

Explanation

According to the divisibility rule for 3, a number is divisible by 3 if the sum of its digits is divisible by 3.

Let the digit in the blank space be x. The sum of the digits of the number 7x7624 is: 7 + x + 7 + 6 + 2 + 4 = 26 + x

For the number to be divisible by 3, the sum (26 + x) must be a multiple of 3. The smallest multiple of 3 that is greater than or equal to 26 is 27.

Setting the sum equal to 27 gives: 26 + x = 27 x = 1

Thus, the smallest digit that can be placed in the blank space to make the number divisible by 3 is 1.

163Quantitative Aptitude
A number is first increased by 44% and then decreased by 30% . The net percentage change (rounded off to the nearest integer) in the original number is:
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Answer: (A) increase by 1%

Explanation

The successive percentage change formula for an increase of a% followed by a decrease of b% is:

Net percentage change = a - b - (a × b)/100

Substituting a = 44 and b = 30 into the formula:

Net percentage change = 44 - 30 - (44 × 30)/100 Net percentage change = 14 - 13.2 = 0.8%

Rounding 0.8% to the nearest integer gives 1%. Since the value is positive, it represents an increase.

164Quantitative Aptitude
The given table shows the number of pizzas sold by four different bakeries in 5 different months. Bakery / Month | October | November | December | January | February --- | --- | --- | --- | --- | --- X | 102 | 120 | 105 | 130 | 140 Y | 98 | 104 | 115 | 120 | 136 Z | 89 | 106 | 112 | 118 | 126 W | 96 | 105 | 97 | 110 | 122 What is the respective ratio of the total number of pizzas sold by bakeries Y and Z together in November to the total number of pizzas sold by bakeries X and W together in the same month?
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Answer: (D) 42:45

Explanation

Total pizzas sold by bakeries Y and Z together in November: 104 + 106 = 210

Total pizzas sold by bakeries X and W together in November: 120 + 105 = 225

The required ratio of Y and Z together to X and W together in November: 210 : 225

Dividing both terms by their common factor of 5: 210 ÷ 5 = 42 225 ÷ 5 = 45

This simplifies to the ratio of 42 : 45.

165Quantitative Aptitude
Find the height of the triangle whose base is two- thirds of its height and whose area is 363~cm²
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Answer: (A) 33 cm

Explanation

The area of a triangle is given by the formula: Area = ½ × base × height

Let the height of the triangle be h cm. The base is given as two-thirds of its height, which is ⅔h.

Substituting these values into the area formula: 363 = ½ × ⅔h × h 363 = ⅓h²

Multiplying both sides by 3 to solve for h²: h² = 363 × 3 h² = 1089

Taking the square root of both sides: h = √1089 h = 33 cm

166Quantitative Aptitude
To reach at a destination, D takes 45 minutes if he drives at a speed of 60~km / h Due to some urgency, he is to reach the destination in 30 minutes. What should be his speed in km / h ?
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Answer: (A) 90

Explanation

For a constant distance, speed and time are inversely proportional. This relationship is represented by the formula:

s₁ × t₁ = s₂ × t₂

Here, the initial speed s₁ is 60 km/h and the initial time t₁ is 45 minutes. The required time t₂ is 30 minutes. Let the required speed be s₂.

Substituting these values into the formula:

60 × 45 = s₂ × 30

s₂ = (60 × 45) / 30

s₂ = 90 km/h

167Quantitative Aptitude
A shopkeeper marks up his goods 32% above the cost price and gives a discount of 21% on the marked price. Find his gain percentage on the goods.
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Answer: (C) 4.28%

Explanation

Correct Answer: C

To find the net gain percentage, use the successive percentage formula:

Net Gain = m - d - (m × d) / 100

where m is the markup percentage and d is the discount percentage.

Substituting the given values, m = 32 and d = 21:

Net Gain = 32 - 21 - (32 × 21) / 100 Net Gain = 11 - 672 / 100 Net Gain = 11 - 6.72 Net Gain = 4.28%

168Quantitative Aptitude
Ramendra purchased some watermelons for ₹1,500. He sold one-fourth of them at a loss of 12% . At what gain percentage should the remaining watermelons be sold so as to gain 25% on the whole transaction (correct to two decimal places)?
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Answer: (D) 37.33%

Explanation

Using the weighted average method for profit and loss, let the total quantity of watermelons be 4 units.

One-fourth of the quantity is 1 unit, which is sold at a loss of 12% (represented as -12%). The remaining quantity is 3 units, sold at a gain of x%. The overall gain on the entire 4 units is 25%.

The weighted average relation is: Total Gain = (Quantity 1 × Profit 1) + (Quantity 2 × Profit 2) 4 × 25 = 1 × (-12) + 3 × x 100 = -12 + 3x 3x = 112 x = 112 / 3 ≈ 37.33%

The remaining watermelons must be sold at a gain of 37.33% to achieve the desired overall profit.

169Quantitative Aptitude
Shobhita can complete a painting work in 20 hours while Saroj can complete the same work in 15 hours. In how much time (in hours) can the entire work of painting be completed, if both Shobhita and Saroj work simultaneously?
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Answer: (C) 8 4/7

Explanation

The time taken by two individuals working together to complete a task is given by the formula:

T = (a × b) / (a + b)

where a and b are the times taken by each individual to complete the task alone.

Here, Shobhita's time a = 20 hours and Saroj's time b = 15 hours.

Substituting these values into the formula:

T = (20 × 15) / (20 + 15) T = 300 / 35 T = 60 / 7 T = 8 4/7 hours

170Quantitative Aptitude
Δ ABC and Δ DEF are similar and their areas are respectively 0.64 ~m² and 0.0121 ~m² . If EF = 0.154 ~m , then BC is:
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Answer: (B) 1.12 m

Explanation

For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides:

Area(ΔABC) / Area(ΔDEF) = (BC / EF)²

Substituting the given values into the formula:

0.64 / 0.0121 = (BC / 0.154)²

Taking the square root on both sides:

0.8 / 0.11 = BC / 0.154

Solving for BC:

BC = (0.8 × 0.154) / 0.11 BC = 0.8 × 1.4 BC = 1.12 m

171Quantitative Aptitude
The diameter of the base of a cylindrical tank is 28 ~cm and its height is 42 ~cm . Find its curved surface area.
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Answer: (C) 3696 cm²

Explanation

The curved surface area (CSA) of a cylinder is given by the formula:

CSA = 2πrh

The radius (r) is half of the diameter:

r = 28 / 2 = 14 cm

The height (h) of the cylinder is 42 cm. Using π = 22/7, substitute these values into the formula:

CSA = 2 × (22/7) × 14 × 42 CSA = 2 × 22 × 2 × 42 CSA = 3696 cm²

172Quantitative Aptitude
The radii of two concentric circles are 35 ~cm and 21 ~cm . If the chord of the greater circle is a tangent to the smaller circle, then the length of that chord is:
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Answer: (D) 56 cm

Explanation

Let the two concentric circles have center O. The radius of the larger circle is R = 35 cm, and the radius of the smaller circle is r = 21 cm.

Let AB be the chord of the larger circle that is tangent to the smaller circle at point P. The radius OP is perpendicular to the tangent chord AB at the point of contact P. This forms a right-angled triangle OPA, where OA is the hypotenuse.

Using Pythagoras' theorem in triangle OPA: AP² = OA² - OP² AP² = 35² - 21² AP² = 1225 - 441 AP² = 784 AP = √784 = 28 cm

Since the perpendicular from the center of a circle to a chord bisects the chord, P is the midpoint of AB.

Therefore, the length of the chord AB is: AB = 2 × AP = 2 × 28 = 56 cm

173Quantitative Aptitude
If sin (X - Y) = sin X cos Y - cos X sin Y , then the value of (sin(A - B))/(cos A cos B) + (sin(B - C))/(cos B cos C) is:
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Answer: (D) sin(A-C)/(cosAcosC)

Explanation

Expanding the terms in the numerator using the given identity:

sin(A - B) / (cos A cos B) = (sin A cos B - cos A sin B) / (cos A cos B) = tan A - tan B

Similarly, the second term simplifies as:

sin(B - C) / (cos B cos C) = (sin B cos C - cos B sin C) / (cos B cos C) = tan B - tan C

Adding these two simplified expressions gives:

(tan A - tan B) + (tan B - tan C) = tan A - tan C

Converting tan A - tan C back to sine and cosine forms:

tan A - tan C = (sin A / cos A) - (sin C / cos C) = (sin A cos C - cos A sin C) / (cos A cos C) = sin(A - C) / (cos A cos C)

174Quantitative Aptitude
If θ be acute angle and cos θ = ²⁴⁄₂₅ , then the value of cot (90 - θ) is equal to:
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Answer: (B) ⁷⁄₂₄

Explanation

By trigonometric co-function identity, cot(90 - θ) = tan θ.

Given cos θ = 24/25 for an acute angle θ. In a right-angled triangle, the cosine of an angle is the ratio of the base to the hypotenuse.

Applying the Pythagorean theorem to find the perpendicular: Perpendicular = √(Hypotenuse² - Base²) = √(25² - 24²) = √(625 - 576) = √49 = 7

Using the definition of tangent: tan θ = Perpendicular / Base = 7/24

Therefore, cot(90 - θ) = 7/24.

175Quantitative Aptitude
R gives ⅔ of the toffees he has with him to S. If now R has k% of the toffees with S, then find the value of k.
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Answer: (A) 500/3

Explanation

Let the initial number of toffees with R and S be equal to T.

Since R gives 2/3 of his toffees to S: Toffees given to S = 2/3 T

Toffees remaining with R = T - 2/3 T = 1/3 T

New number of toffees with S = T + 2/3 T = 5/3 T

The number of toffees now with S is k% of the toffees originally with R: 5/3 T = (k/100) × T

Solving for k: k/100 = 5/3 k = 500/3

176Quantitative Aptitude
In an assembly election, a candidate got 60% of the total valid votes. 3% of the total votes were declared invalid. If the total number of voters is 2,40,000, then find the number of valid votes polled in favour of the candidate.
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Answer: (C) 139680

Explanation

To find the number of valid votes polled in favour of the candidate, we calculate the percentage step-by-step from the total number of voters.

Total number of voters = 2,40,000

Since 3% of the total votes were invalid, the percentage of valid votes is: 100% - 3% = 97%

The total number of valid votes is: 2,40,000 × 97/100 = 2,32,800

The candidate received 60% of these valid votes. Therefore, the number of valid votes polled in favour of the candidate is: 2,32,800 × 60/100 = 1,39,680

177Quantitative Aptitude
The mean proportion of 0.14 and 2.24 is:
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Answer: (A) 0.56

Explanation

The mean proportion of two numbers a and b is given by the formula √(a × b).

Given the numbers 0.14 and 2.24, we substitute them into the formula:

Mean Proportion = √(0.14 × 2.24)

By converting the decimals into fractions:

Mean Proportion = √((14/100) × (224/100)) Mean Proportion = √((14 × 14 × 16) / 10000) Mean Proportion = √((14² × 4²) / 100²) Mean Proportion = (14 × 4) / 100 Mean Proportion = 56/100 = 0.56

178Quantitative Aptitude
A quantity ⅘ is changed to ⅚ . How much percentage change is given to the quantity?
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Answer: (A) 4.17%

Explanation

To find the percentage change, the formula is: Percentage Change = ((Final Value - Initial Value) / Initial Value) × 100

Substituting the given values: Initial Value = 4/5 Final Value = 5/6

The absolute change in the quantity is: 5/6 - 4/5 = (25 - 24) / 30 = 1/30

Now, calculate the percentage change: Percentage Change = ((1/30) / (4/5)) × 100 = (1/30 × 5/4) × 100 = 5/120 × 100 = 1/24 × 100 = 25/6% ≈ 4.17%

179Quantitative Aptitude
A retailer gets a discount of 40% on the printed price of an article. If the retailer sells it at the printed price, then his gain percentage is:
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Answer: (D) 66 2/3 %

Explanation

Let the printed price of the article be ₹100.

The retailer gets a 40% discount, making the cost price for the retailer: CP = 100 - 40 = ₹60

The retailer sells the article at the printed price: SP = ₹100

Profit made by the retailer: Profit = SP - CP = 100 - 60 = ₹40

Profit percentage = (Profit / CP) × 100% Profit percentage = (40 / 60) × 100% = ⅔ × 100% = 200/3% = 66 ⅔%

180Quantitative Aptitude
Two parallel chords are drawn in a circle of radius 25cm . The distance between the two chords is 27cm . If the length of one chord is 48cm , then length of the other chord is equal to:
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Answer: (C) 30 cm

Explanation

For a circle with radius R = 25 cm, a perpendicular drawn from the center O to a chord bisects the chord.

For the first chord of length 48 cm, the half-length is 24 cm. Using the Pythagorean theorem, the perpendicular distance OM from the center to this chord is: OM = √(25² - 24²) = √(625 - 576) = √49 = 7 cm

The distance between the two parallel chords is 27 cm. Since this distance is greater than OM, the second chord must lie on the opposite side of the center.

The perpendicular distance ON of the second chord from the center is: ON = 27 - OM = 27 - 7 = 20 cm

Using the Pythagorean theorem for the second chord with distance ON = 20 cm and radius R = 25 cm, the half-length of the second chord CN is: CN = √(25² - 20²) = √(625 - 400) = √225 = 15 cm

The total length of the second chord is: 2 × CN = 2 × 15 = 30 cm

181Quantitative Aptitude
In a triangle ABC, BD is perpendicular to AC. E is a point on BC such that angle BEA = x° . If angle EAC = 38° and angle EBD = 40° , then the value of x is:
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Answer: (A) 88

Explanation

In the right-angled triangle BDC, the angle BDC is 90° because BD is perpendicular to AC. Since E is a point on BC, the angle EBD is the same as angle CBD, which is given as 40°.

In triangle BDC, the sum of angles is 180°: angle BCD = 180° - 90° - 40° = 50°

This means the angle ECA (or angle C) of triangle AEC is 50°.

Since E lies on the line segment BC, the angle BEA is an exterior angle of triangle AEC at vertex E. By the exterior angle theorem, the exterior angle of a triangle is equal to the sum of its two opposite interior angles: angle BEA = angle EAC + angle ECA x = 38 + 50 = 88

182Quantitative Aptitude
The perpendicular length from the origin to the line 6x + 8y - 48 = 0 is:
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Answer: (A) 4.8 unit

Explanation

The perpendicular distance d from the origin (0, 0) to a line of the form Ax + By + C = 0 is given by the formula:

d = |C| / √(A² + B²)

For the given line equation 6x + 8y - 48 = 0, the coefficients are A = 6, B = 8, and C = -48. Substituting these values into the formula:

d = |-48| / √(6² + 8²) d = 48 / √(36 + 64) d = 48 / √100 d = 48 / 10 d = 4.8 units

183Quantitative Aptitude
Evaluate the given expression. [7 + 9 - 2{(3÷ ⅓) - 3} +27÷ 3 + (27÷ 9 + 3) - 6] + 2
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Answer: (A) 15

Explanation

Solving using BODMAS, first the bracket: 3 ÷ (1/3) = 9, so 9 - 3 = 6, and 2 × 6 = 12. Next, 27 ÷ 3 = 9, and 27 ÷ 9 + 3 = 3 + 3 = 6. Substituting these values gives [7 + 9 - 12 + 9 + 6 - 6] + 2 = 13 + 2 = 15.

184Quantitative Aptitude
The following table represents the number of computers (in thousands) manufactured by four companies during the period from 2010 to 2014: Years | A | B | C | D 2010 | 240 | 120 | 270 | 280 2011 | 300 | 530 | 490 | 650 2012 | 1250 | 650 | 430 | 710 2013 | 470 | 320 | 1180 | 890 2014 | 320 | 1070 | 550 | 480 What is the difference (in thousands) between the number of computers manufactured by company A and C during the period from 2010 to 2014?
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Answer: (A) 340

Explanation

To find the difference between the total number of computers manufactured by Company A and Company C during the period from 2010 to 2014, we calculate the total production for each company.

Total computers manufactured by Company A: 240 + 300 + 1250 + 470 + 320 = 2580 thousand

Total computers manufactured by Company C: 270 + 490 + 430 + 1180 + 550 = 2920 thousand

The difference between the two totals: 2920 - 2580 = 340 thousand

185Quantitative Aptitude
If the angle of the sector with radius 7cm is 120° then find the length of the sector (in cm). (Use π = ²²⁄₇)
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Answer: (D) 44/3

Explanation

The arc length of a sector (L) with radius r and central angle θ is given by the formula:

L = (θ / 360°) × 2πr

Substituting the given values, θ = 120°, r = 7 cm, and π = 22/7:

L = (120 / 360) × 2 × (22/7) × 7

L = (1/3) × 2 × 22

L = 44/3 cm

186Quantitative Aptitude
A motorcyclist rides his motorcycle at a speed of 90km / hr in the first one hour and the next two hours at a speed of 120km / hr . Find the average speed of the rider.
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Answer: (D) 110 km/hr

Explanation

The average speed is calculated using the formula: Average Speed = Total Distance / Total Time

The distance covered in the first hour is: d₁ = 90 km/hr × 1 hr = 90 km

The distance covered in the next two hours is: d₂ = 120 km/hr × 2 hr = 240 km

Total distance covered is: Total Distance = 90 km + 240 km = 330 km

Total time taken is: Total Time = 1 hr + 2 hr = 3 hr

Substituting these values into the formula: Average Speed = 330 km / 3 hr = 110 km/hr

187Quantitative Aptitude
If the ratio of principal and simple interest for 5 years is 10 : 7, then the rate of interest per annum is:
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Answer: (D) 14%

Explanation

The relationship between Simple Interest (SI), Principal (P), Rate (R), and Time (T) is given by the formula:

SI = (P × R × T) / 100

From the given ratio of principal to simple interest, let the principal P be 10 and the simple interest SI be 7. The time period T is 5 years.

Substituting these values into the formula:

7 = (10 × R × 5) / 100

7 = 50 × R / 100

7 = R / 2

R = 14%

188Quantitative Aptitude
Find the percentage increase in surface area of a cube by triple each side.
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Answer: (B) 800%

Explanation

Correct Answer: B

The surface area of a cube with side length s is given by the formula A = 6s². When each side of the cube is tripled, the new side length becomes 3s.

The new surface area is: A_new = 6(3s)² = 54s²

The increase in the surface area is: 54s² - 6s² = 48s²

The percentage increase in the surface area is calculated by dividing the increase by the original surface area and multiplying by 100: (48s² / 6s²) × 100% = 8 × 100% = 800%

This can also be determined directly using scaling: scaling the linear dimensions of a shape by a factor of k scales its surface area by k². Tripling the sides (k = 3) scales the area by 3² = 9. This represents an increase of 9 - 1 = 8 times the original area, which corresponds to an 800% increase.

189Quantitative Aptitude
Study the given table and answer that question that follows. The given table shows the loan disbursed by five banks (in crores) over four years. Banks 2016 2017 2018 2019 A 15 20 10 12 B 15 20 15 20 C 20 25 15 20 D 15 20 35 10 E 10 20 25 30 Which two banks have disbursed the same sum of loan over all four years?
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Answer: (B) C and D

Explanation

To find which two banks disbursed the same sum of loan over all four years, calculate the total loan disbursed by each bank:

Total loan disbursed by Bank C = 20 + 25 + 15 + 20 = 80 crores

Total loan disbursed by Bank D = 15 + 20 + 35 + 10 = 80 crores

Both Bank C and Bank D have disbursed an equal sum of 80 crores over the four-year period.

190Quantitative Aptitude
If three spheres of radius 75cm , 60cm and 45cm are melted into one big sphere, then the radius of the big sphere is:
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Answer: (D) 90cm

Explanation

The volume of a sphere of radius r is given by the formula V = 4/3 πr³.

When three spheres of radii r₁, r₂, and r₃ are melted to form a single big sphere of radius R, the volume of the big sphere is equal to the sum of the volumes of the three smaller spheres:

4/3 πR³ = 4/3 πr₁³ + 4/3 πr₂³ + 4/3 πr₃³

Dividing both sides by 4/3 π gives:

R³ = r₁³ + r₂³ + r₃³

Substituting the given values r₁ = 75 cm, r₂ = 60 cm, and r₃ = 45 cm:

R³ = 75³ + 60³ + 45³

To simplify the calculation, factor out the greatest common divisor of 75, 60, and 45, which is 15:

R³ = (15 × 5)³ + (15 × 4)³ + (15 × 3)³ R³ = 15³ × (5³ + 4³ + 3³) R³ = 15³ × (125 + 64 + 27) R³ = 15³ × 216

Since 216 = 6³:

R³ = 15³ × 6³ R³ = (15 × 6)³ R³ = 90³

Taking the cube root of both sides gives:

R = 90 cm

191Quantitative Aptitude
Find the fourth proportion to 1.25, 5.75 and 3.5.
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Answer: (B) 16.1

Explanation

The fourth proportion d to three numbers a, b, and c is given by the formula d = (b × c) / a.

Substituting the given values a = 1.25, b = 5.75, and c = 3.5 into the formula:

d = (5.75 × 3.5) / 1.25

To simplify, first divide 5.75 by 1.25:

5.75 / 1.25 = 575 / 125 = 23 / 5 = 4.6

Now, multiply this result by 3.5:

d = 4.6 × 3.5 = 16.1

192Quantitative Aptitude
The difference (in ξ ) between a discount of 37% on ξ2,635 and two successive discounts of 23% and 7% on the same amount is (rounded off to 2 decimal places):
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Answer: (A) 226.87

Explanation

The single equivalent discount for two successive discounts of x% and y% is given by the formula: Equivalent discount = x + y - (x × y)/100

Substituting x = 23 and y = 7: Equivalent discount = 23 + 7 - (23 × 7)/100 = 30 - 1.61 = 28.39%

The first discount is 37%. The difference between the two discount percentages is: 37% - 28.39% = 8.61%

The difference in money value on the amount of ₹2,635 is: 8.61% of 2,635 = (8.61 / 100) × 2,635 = 0.0861 × 2,635 = 226.8735

Rounding to two decimal places, the difference is 226.87.

193Quantitative Aptitude
Two similar triangles have area 490 sq. cm. and 640 sq. cm. If the length of the one side of the first triangle is 21 cm, then what is the length of the corresponding side of the second triangle?
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Answer: (C) 24 cm

Explanation

For any two similar triangles, the ratio of their areas is equal to the ratio of the squares of their corresponding sides. This relation is given by the formula:

Area₁ / Area₂ = (side₁ / side₂)²

Substituting the given values into the formula:

490 / 640 = (21 / side₂)²

Simplifying the fraction on the left side:

49 / 64 = (21 / side₂)²

Taking the square root on both sides:

7 / 8 = 21 / side₂

Solving for side₂:

side₂ = 21 × 8 / 7

side₂ = 24 cm

194Quantitative Aptitude
The diameter of a roller is 35 cm and its length is 100 cm. It takes 200 complete revolutions to level a playground. Find the area of the playground in m²
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Answer: (A) 220

Explanation

The area of the playground leveled by the roller is equal to the curved surface area of the cylindrical roller multiplied by the total number of revolutions.

First, convert the dimensions of the roller from centimeters to meters: Diameter, d = 35 cm = 0.35 m Length (height), h = 100 cm = 1 m

The curved surface area (CSA) of a cylinder is given by the formula: CSA = π × d × h

Substituting the values: CSA = (22/7) × 0.35 × 1 = 22 × 0.05 = 1.1 m²

The total area leveled in 200 revolutions is: Total Area = CSA × Number of revolutions Total Area = 1.1 × 200 = 220 m²

195Quantitative Aptitude
Find the amount to be paid at the end if 4,500 is invested for a period of 4 years at the rate of 8% simple interest per annum.
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Answer: (B) 5,940

Explanation

The total amount to be paid at the end of the investment period is calculated using the formula for simple interest and total amount.

Simple Interest (SI) = (P × R × T) / 100

Substituting the given values: Principal (P) = 4500 Rate of interest (R) = 8% per annum Time (T) = 4 years

SI = (4500 × 8 × 4) / 100 = 45 × 32 = 1440

The total amount (A) to be paid is the sum of the principal and the simple interest:

Amount (A) = Principal + SI Amount (A) = 4500 + 1440 = 5940

196Quantitative Aptitude
The altitude of an equilateral triangle is 3√3 cm. Find its area.
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Answer: (B) 9√3 cm²

Explanation

The altitude of an equilateral triangle is given by the formula h = (√3/2) * a, where a is the side length. Substituting h = 3√3 cm gives the side length a = 6 cm, which yields an area of (1/2) * base * height = (1/2) * 6 * 3√3 = 9√3 square centimeters.

197Quantitative Aptitude
Let ABC be a right- angled triangle such that ∠ C = 90° . Let D be a point on AB such that CD is perpendicular to AB. If AC = 5 cm and BC = 12 cm, find the length of CD (in cm).
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Answer: (A) 4⁸⁄₁₃

Explanation

By Pythagoras' theorem in right-angled triangle ABC: AB = √(AC² + BC²) AB = √(5² + 12²) = √169 = 13 cm

The area of triangle ABC can be calculated in two ways: Area = ½ × AC × BC = ½ × AB × CD

This simplifies to: CD = (AC × BC) / AB

Substituting the given values: CD = (5 × 12) / 13 = 60/13 = 4 8/13 cm

198Quantitative Aptitude
A shopkeeper cheats 25% in weight while buying rice and cheats 25% while selling it. If he sells the rice at 12½% profit, then find his net profit percentage.
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Answer: (A) 87.5%

Explanation

The net profit percentage can be calculated using the successive multiplier method:

When the shopkeeper cheats 25% while buying, he gets 125 units of rice for the price of 100 units. This gives a weight multiplier of 125/100 = 5/4.

When he cheats 25% while selling, he delivers only 75 units of rice while charging the customer for 100 units. This gives a weight multiplier of 100/75 = 4/3.

He sells the rice at a nominal profit of 12½%, which is equal to 1/8. This gives a price multiplier of 1 + 1/8 = 9/8.

The net ratio of Selling Price to Cost Price is the product of these individual multipliers: Net Ratio = (5/4) × (4/3) × (9/8) = 15/8

Net Profit Percentage = (15/8 - 1) × 100% = (7/8) × 100% = 87.5%

199Quantitative Aptitude
X and Y can do a job in 18 days; Y and Z can do the same in 24 days. If all the three can finish the job in 12 days, in how many days can X and Z can complete the job?
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Answer: (A) 14 2/5 days

Explanation

To find the time taken by X and Z together, we can determine their work rates. Taking the total work as 72 units, the combined rate of X, Y, and Z is 6 units/day, X and Y is 4 units/day, and Y and Z is 3 units/day. This gives individual rates of 3 units/day for X and 2 units/day for Z, meaning X and Z together work at 5 units/day and will complete the job in 72/5 days, which is 14 2/5 days.

200Quantitative Aptitude
A person divides his total route of journey into three equal parts and decides to travel the three parts at the speeds of 80km / h , 60km / h and 30km / h , respectively. What is the average speed during the journey?
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Answer: (A) 48 km/h

Explanation

When a journey is divided into three equal parts travelled at speeds x, y, and z, the average speed of the entire journey is given by the formula:

Average Speed = 3 / (1/x + 1/y + 1/z)

Substituting the given values x = 80 km/h, y = 60 km/h, and z = 30 km/h:

Average Speed = 3 / (1/80 + 1/60 + 1/30)

Taking the least common multiple of the denominators 80, 60, and 30, which is 240:

1/80 + 1/60 + 1/30 = 3/240 + 4/240 + 8/240 = 15/240 = 1/16

Using this sum in the average speed formula:

Average Speed = 3 / (1/16) = 3 × 16 = 48 km/h

Answer key

Tap a number to jump to that question.

  1. 151A
  2. 152B
  3. 153B
  4. 154A
  5. 155B
  6. 156A
  7. 157A
  8. 158A
  9. 159B
  10. 160A
  11. 161D
  12. 162B
  13. 163A
  14. 164D
  15. 165A
  16. 166A
  17. 167C
  18. 168D
  19. 169C
  20. 170B
  21. 171C
  22. 172D
  23. 173D
  24. 174B
  25. 175A
  26. 176C
  27. 177A
  28. 178A
  29. 179D
  30. 180C
  31. 181A
  32. 182A
  33. 183A
  34. 184A
  35. 185D
  36. 186D
  37. 187D
  38. 188B
  39. 189B
  40. 190D
  41. 191B
  42. 192A
  43. 193C
  44. 194A
  45. 195B
  46. 196B
  47. 197A
  48. 198A
  49. 199A
  50. 200A

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