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Answer: (C) 35
Explanation
Let the present ages of the father and the son be F and S, respectively.
According to the first condition, ten years later, the father's age will be double the son's age: F + 10 = 2(S + 10) F - 2S = 10
According to the second condition, ten years ago, the father's age was six times the son's age: F - 10 = 6(S - 10) F - 6S = -50
Subtracting the second equation from the first equation gives: 4S = 60 S = 15
Substituting S = 15 into the first equation: F - 2(15) = 10 F = 40
So, the present age of the father is 40 years and that of the son is 15 years.
Let t be the number of years from now when the ratio of their ages will be 3 : 2: (40 + t) / (15 + t) = 3 / 2 2(40 + t) = 3(15 + t) 80 + 2t = 45 + 3t t = 35