SSC CHSL Tier 1 2024 General Intelligence & Reasoning Questions with Solutions

Explanation

The given sequence follows an alternating pattern of subtraction and addition.

First term: 138 Second term: 138 - 1 = 137 Third term: 137 + 3 = 140 Fourth term: 140 - 1 = 139 Fifth term: 139 + 3 = 142

Following this alternating pattern of subtracting 1 and adding 3, the next operation is to subtract 1:

Sixth term: 142 - 1 = 141

Explanation

To find the number of letters that remain unchanged, we compare the original positions of the letters in the word PRAISE with their positions when arranged in alphabetical order.

Original word: 1: P 2: R 3: A 4: I 5: S 6: E

Alphabetical order: 1: A 2: E 3: I 4: P 5: R 6: S

Comparing the letters at each position: At position 1, P is replaced by A. At position 2, R is replaced by E. At position 3, A is replaced by I. At position 4, I is replaced by P. At position 5, S is replaced by R. At position 6, E is replaced by S.

Comparing the two sequences shows that no letter occupies the same position in both arrangements. Thus, the position of zero letters remains unchanged.

Explanation

By interchanging 75 and 30, the equation becomes:

79 - 43 + (23 + 30) × 3 - (75 ÷ 15) × 4 = 175

Applying the BODMAS rule, simplify the terms inside the parentheses first:

23 + 30 = 53 75 ÷ 15 = 5

Substitute these simplified values back into the equation:

79 - 43 + 53 × 3 - 5 × 4 = 175

Next, perform the multiplication operations:

53 × 3 = 159 5 × 4 = 20

Now, perform the remaining addition and subtraction operations from left to right:

79 - 43 + 159 - 20 = 36 + 159 - 20 = 195 - 20 = 175

This balances the equation perfectly with LHS equal to RHS.

Explanation

Interchanging '+' with '-' and '×' with '÷' in the equation 14 + 6 × 3 + 7 - 3 gives:

14 - 6 ÷ 3 - 7 + 3

According to the BODMAS rule, division is performed first:

6 ÷ 3 = 2

Substituting this back into the equation:

14 - 2 - 7 + 3

Now, performing the addition and subtraction from left to right:

14 - 2 = 12

12 - 7 = 5

5 + 3 = 8

Explanation

By interchanging the numbers 43 and 2, the equation becomes: (86 ÷ 2) + (66 ÷ 33) × 43 + 72 - 6 × 4 = 177

Applying the BODMAS rule, solve the divisions inside the parentheses first: 86 ÷ 2 = 43 66 ÷ 33 = 2

Substitute these values back into the equation: 43 + 2 × 43 + 72 - 6 × 4 = 177

Next, perform the multiplications: 2 × 43 = 86 6 × 4 = 24

This simplifies the expression to: 43 + 86 + 72 - 24 = 177

Perform the addition operations from left to right: 43 + 86 + 72 = 201

Finally, perform the subtraction: 201 - 24 = 177

The left-hand side equals the right-hand side, making the equation correct.

Explanation

The coding scheme follows a pattern where the letters of the word are shifted by +2, +3, -2, and -1 respectively.

Applying this pattern to the word LDWR: L (+2) = N D (+3) = G W (-2) = U R (-1) = Q

Applying the same pattern to the word YTGX: Y (+2) = A (wrapping around from Z to A) T (+3) = W G (-2) = E X (-1) = W

This yields the code AWEW.

Explanation

By comparing the two coded words, we can find the common letters and their corresponding digits:

The letters in DEAL are D, E, A, L, and its code digits are 0, 3, 6, 8. The letters in DEAF are D, E, A, F, and its code digits are 2, 6, 3, 0.

The common letters in both words are D, E, and A. The common digits in both codes are 0, 3, and 6. This means the letters D, E, and A correspond to the digits 0, 3, and 6 in some order.

The remaining letter in DEAF is F, and the remaining digit in its code is 2. Therefore, the code for F is 2.

Explanation

The numbers in the given sets follow a specific mathematical pattern. For any set of three numbers (A, B, C):

B = C × 3 A = B × 4

Let us verify this with the given sets:

First set (60, 15, 5): 15 = 5 × 3 60 = 15 × 4

Second set (96, 24, 8): 24 = 8 × 3 96 = 24 × 4

Applying the same logic to the set (156, 39, 13): 39 = 13 × 3 156 = 39 × 4

Explanation

The relationship between the words is established by shifting each letter forward by 4 positions in the English alphabetical order.

For STAUNCH to WXEYRGL: S (19) + 4 = W (23) T (20) + 4 = X (24) A (1) + 4 = E (5) U (21) + 4 = Y (25) N (14) + 4 = R (18) C (3) + 4 = G (7) H (8) + 4 = L (12)

For BLISS to FPMWW: B (2) + 4 = F (6) L (12) + 4 = P (16) I (9) + 4 = M (13) S (19) + 4 = W (23) S (19) + 4 = W (23)

Applying the same logic to COWARD: C (3) + 4 = G (7) O (15) + 4 = S (19) W (23) + 4 = A (27, which wraps around to 1) A (1) + 4 = E (5) R (18) + 4 = V (22) D (4) + 4 = H (8)

This results in the coded word GSAEVH.

Explanation

According to the given condition of interchanging the mathematical signs: The sign × is replaced by + The first + is replaced by × The second + is replaced by - The sign - is replaced by ÷

Substituting these signs into the given equation: 46 + 17 × 4 - 98 ÷ 7

Applying the BODMAS rule: First, division: 98 ÷ 7 = 14

Next, multiplication: 17 × 4 = 68

Now, substitute these values back into the expression: 46 + 68 - 14

Finally, addition and subtraction: 114 - 14 = 100

Explanation

Each letter in the second term of the given pairs is obtained by shifting the corresponding letter of the first term forward by three positions in alphabetical order.

For the pair CJM : FMP: C (3) + 3 = F (6) J (10) + 3 = M (13) M (13) + 3 = P (16)

For the pair AHL : DKO: A (1) + 3 = D (4) H (8) + 3 = K (11) L (12) + 3 = O (15)

Applying this same +3 pattern to NRS: N (14) + 3 = Q (17) R (18) + 3 = U (21) S (19) + 3 = V (22)

This produces the pair NRS : QUV.

Explanation

By comparing the letter codes of CERTAIN and UNCERTAIN:

The word CERTAIN has 7 letters and is coded as 9643821, which gives the letter-to-digit mapping: C = 9 E = 6 R = 4 T = 3 A = 8 I = 2 N = 1

The word UNCERTAIN has 9 letters and is coded as 964382117. This code contains all the digits of CERTAIN (9, 6, 4, 3, 8, 2, 1) along with two additional digits, 1 and 7.

The additional letters in UNCERTAIN compared to CERTAIN are U and N. Since the letter N is already coded as 1, the remaining digit 7 must represent the letter U.

Explanation

By decoding the expression P + Q + R × S - T from right to left:

S - T means S is the brother of T. This indicates that S and T are siblings.

R × S means R is the father of S. Since S and T are siblings, R is the father of T.

Q + R means Q is the sister of R.

P + Q means P is the sister of Q.

Since P is the sister of Q, and Q is the sister of R, P is also the sister of R.

R is the father of T, so R's sister P is the father's sister of T.

Explanation

The given series follows a distinct pattern for each letter in the triplets based on their positions in the English alphabetical order.

For the first letter of each term: L, G, B, W, ? The alphabetical positions are 12, 7, 2, 23. The pattern is a constant decrease of 5 positions: 12 - 5 = 7 (G) 7 - 5 = 2 (B) 2 - 5 = -3, which wraps around to 23 (W) 23 - 5 = 18 (R)

For the second letter of each term: D, H, L, P, ? The alphabetical positions are 4, 8, 12, 16. The pattern is a constant increase of 4 positions: 4 + 4 = 8 (H) 8 + 4 = 12 (L) 12 + 4 = 16 (P) 16 + 4 = 20 (T)

For the third letter of each term: P, O, N, M, ? The alphabetical positions are 16, 15, 14, 13. The pattern is a constant decrease of 1 position: 16 - 1 = 15 (O) 15 - 1 = 14 (N) 14 - 1 = 13 (M) 13 - 1 = 12 (L)

Combining these letters yields RTL.

Explanation

To find how many letters remain unchanged, arrange the letters of the word ENGLISH in alphabetical order and compare them with the original word.

Original word: E N G L I S H

Alphabetical arrangement: E G H I L N S

Comparing the positions: E remains at the 1st position. N changes to G at the 2nd position. G changes to H at the 3rd position. L changes to I at the 4th position. I changes to L at the 5th position. S changes to N at the 6th position. H changes to S at the 7th position.

Only the letter E retains its original position, meaning the position of only one letter remains unchanged.

Explanation

By interchanging the signs as specified (where + and - are interchanged, and × and ÷ are interchanged), the given equation:

20 - 80 × 16 ÷ 5 + 15 = ?

becomes:

20 + 80 ÷ 16 × 5 - 15 = ?

Using the BODMAS rule, first perform the division:

80 ÷ 16 = 5

Next, perform the multiplication:

5 × 5 = 25

Finally, perform the addition and subtraction:

20 + 25 - 15 = 30

Explanation

For Conclusion I, we are given that some charts are notebooks and some notebooks are files. While both categories overlap with notebooks, there is no direct relationship established between charts and files. Therefore, the definite conclusion that some charts are files cannot be established.

For Conclusion II, since all statements are positive and there are no negative relations or exclusions between any of the categories, a possibility where the entire circle of papers is placed inside the circle of notebooks is completely valid. This scenario does not violate any of the given statements, which means that all papers being notebooks is a distinct possibility.

Explanation

The series follows a pattern where the difference between consecutive terms increases by a constant value of 8.

Calculating the differences between the consecutive terms of the series: 49 - 41 = 8 65 - 49 = 16 89 - 65 = 24 121 - 89 = 32 161 - 121 = 40

The differences form an arithmetic progression of multiples of 8: 8, 16, 24, 32, 40. The next difference in this sequence is 48.

To find the missing term, add 48 to the last term of the series: 161 + 48 = 209

Explanation

The relationship between the numbers in the set follows the pattern where the third number is the square of the product of the first two numbers.

Formula: (First number × Second number)² = Third number

Applying this formula to the set (3, 5, 225): (3 × 5)² = 15² = 225

Explanation

The given series follows a pattern where the differences between consecutive terms are the squares of consecutive odd numbers starting from 3.

The differences are calculated as follows: 78 - 69 = 9 = 3² 103 - 78 = 25 = 5² 152 - 103 = 49 = 7²

Following this pattern, the next difference must be the square of the next odd number, which is 9² = 81.

Adding 81 to the last term: 152 + 81 = 233

Explanation

Comparing the words BILLION and MILLION, they differ by only one letter: BILLION contains the letter B, while MILLION contains the letter M. The other letters (I, L, L, I, O, N) are identical in both words.

Similarly, comparing their respective codes 3264581 and 3249581, they differ by only one digit: the code for BILLION contains the digit 6, which is replaced by the digit 9 in the code for MILLION. All other digits (1, 2, 3, 4, 5, 8) are common to both codes.

By comparing these differences, the letter M corresponds to the digit 9, while the letter B corresponds to the digit 6.

Explanation

The logic followed in the given pairs is that the first number is divided by 7 to obtain the second number.

First pair: 105 ÷ 7 = 15 Second pair: 154 ÷ 7 = 22

Following the same logic for the third number: 189 ÷ 7 = 27

Explanation

The relationship between the letter groups is based on subtracting consecutive integers from the alphabetical positions of each letter. Specifically, the first letter is shifted backward by 1 position, the second by 2 positions, the third by 3 positions, and the fourth by 4 positions.

Applying this pattern to JNLO: J (10) - 1 = I (9) N (14) - 2 = L (12) L (12) - 3 = I (9) O (15) - 4 = K (11)

Applying this pattern to NRPS: N (14) - 1 = M (13) R (18) - 2 = P (16) P (16) - 3 = M (13) S (19) - 4 = O (15)

Applying the same logic to LPNQ: L (12) - 1 = K (11) P (16) - 2 = N (14) N (14) - 3 = K (11) Q (17) - 4 = M (13)

This yields the letter combination KNKM.

Explanation

The given series consists of 16 letters, which can be divided into four groups of four letters each. By sequentially placing the letters D, C, E, and E into the blanks, the series is divided as follows:

First group (letters 1 to 4): A B C D. In this group, the letters progress forward by 1 step (+1, +1, +1).

Second group (letters 5 to 8): C C C C. In this group, the letters remain constant with a step of 0.

Third group (letters 9 to 12): E D C B. In this group, the letters progress backward by 1 step (-1, -1, -1).

Fourth group (letters 13 to 16): G E C A. In this group, the letters progress backward by 2 steps (-2, -2, -2).

This systematic pattern of step sizes (+1, 0, -1, -2) completes the series with the letter combination D, C, E, E.

Explanation

Correct Answer: B

By mapping the letters to their respective arithmetic operators, we have: N stands for × (multiplication) G stands for - (subtraction) Y stands for ÷ (division) M stands for + (addition)

Substituting these operators into the given expression: 100 × 80 - 40 ÷ 20 + 10

Applying the BODMAS rule (Division, Multiplication, Addition, Subtraction):

First, perform the division: 40 ÷ 20 = 2

Next, perform the multiplication: 100 × 80 = 8000

Now, perform the addition and subtraction: 8000 - 2 + 10 = 7998 + 10 = 8008

Explanation

To find the day of the week on 2 March 2019 starting from 19 February 2004, we calculate the total number of odd days between the two dates.

First, calculate the odd days for the years from 19 February 2004 to 19 February 2019: Number of years = 2019 - 2004 = 15 years. Since 19 February 2004 is before 29 February, the leap day of 2004 is included. The leap years in this period are 2004, 2008, 2012, and 2016, which gives 4 leap years. The remaining 11 years are ordinary years. Odd days from years = (4 × 2) + (11 × 1) = 19 odd days.

Next, calculate the remaining days from 19 February 2019 to 2 March 2019: Remaining days in February 2019 (non-leap year) = 28 - 19 = 9 days. Days in March = 2 days. Total remaining days = 9 + 2 = 11 days.

Total odd days = 19 + 11 = 30 days. Dividing 30 by 7 gives a remainder of 2 odd days (30 = 4 × 7 + 2).

Adding 2 odd days to Thursday results in Saturday.

Explanation

The relationship in the given pair Engage : Involve is that of synonyms, as both words share a similar meaning of attracting, occupying, or including. Similarly, Diverse and Varied are synonyms, as both words describe things that are different from one another or show a great deal of variety.

Explanation

The position values of the letters in the alphabetical series are converted to numbers where A = 1, B = 2, and so on.

For the letter-clusters LIK, EBD, and PMO, the difference between the letters follows a consistent pattern of minus 3 followed by plus 2. Specifically: L (12) minus 3 is I (9), and I (9) plus 2 is K (11). E (5) minus 3 is B (2), and B (2) plus 2 is D (4). P (16) minus 3 is M (13), and M (13) plus 2 is O (15).

For the letter-cluster ROS, the pattern is minus 3 followed by plus 4. Specifically: R (18) minus 3 is O (15), and O (15) plus 4 is S (19).

This difference makes ROS the odd letter-cluster as it does not follow the minus 3, plus 2 pattern.

Explanation

The relationship between the numbers in each pair follows the pattern where the first number is x² + 1 and the second number is x³ - 1.

For the first pair, 10 and 26, we use x = 3: 3² + 1 = 10 3³ - 1 = 26

Applying the same pattern to the second pair, where the third number is 50, we find x = 7: 7² + 1 = 50 7³ - 1 = 343 - 1 = 342

Explanation

The given word-pair Modest : Humble consists of synonyms, as both words share the same meaning of having a modest or low estimate of one's own importance. Similarly, the words Obvious and Evident are synonyms, both meaning easily perceived or understood, clear, self-evident, or apparent. Thus, they represent the exact same relationship.

Explanation

The given sequence is an arithmetic progression where each term increases by a constant difference, d.

Calculating the difference between consecutive terms: 40 - 24 = 16 56 - 40 = 16 72 - 56 = 16

Using the common difference of 16, the fifth term is: 72 + 16 = 88

To verify, adding 16 to this term gives the final term of the sequence: 88 + 16 = 104

Explanation

There is a typographical error in the question text; it should ask how P is related to R (not T). Based on the expression, P is the wife of Q, and Q is the brother of R, making P the brother's wife of R, which corresponds to Option C.

Explanation

Since some handles are bars and all bars are rods, the common portion of handles and bars must also be rods. This confirms that some handles are indeed rods, making conclusion I valid.

Furthermore, because all bars are entirely contained within rods, and no rod has any overlap with sticks, it is impossible for any bar to be a stick. This makes conclusion II valid.

Both conclusions logically follow from the given statements.

Explanation

The given letters are C, K, I, and K. By rearranging these letters, the only meaningful English word that can be formed is KICK. Since no other valid English word can be formed using each of these letters exactly once, the total number of meaningful words is 1.

Explanation

To find the day of the week on 2 November 2007, we calculate the total number of odd days from 25 October 2004 to 2 November 2007.

First, calculate the odd days from 25 October 2004 to 25 October 2007. Since 2004 is a leap year but its February has already passed, the years 2005, 2006, and 2007 are all ordinary years of 365 days each. An ordinary year has 1 odd day (365 mod 7 = 1). Odd days for 3 years = 3 × 1 = 3 odd days.

Next, calculate the remaining days from 25 October 2007 to 2 November 2007. Days remaining in October = 31 - 25 = 6 days. Days in November = 2 days. Total days = 6 + 2 = 8 days. Odd days in 8 days = 8 mod 7 = 1 odd day.

Total odd days = 3 + 1 = 4 odd days.

Adding 4 days to Monday (Monday + 4 days) results in Friday.

Explanation

The alphabetical positions of the letters in ILO are I = 9, L = 12, and O = 15. The step differences between successive letters are +3 and +3. This constant +3, +3 difference pattern makes it the odd one out, as the other letter-clusters in the group follow a +3, +4 difference pattern between their consecutive letters.

Explanation

By decoding the letter symbols to their respective mathematical operators: A represents - (subtraction) B represents × (multiplication) C represents + (addition) D represents ÷ (division)

We can substitute these operators into the expression given in option A: 113 × 4 - 62 ÷ 2 + 7

Applying the BODMAS rule: First, perform the division: 62 ÷ 2 = 31

Next, perform the multiplication: 113 × 4 = 452

Then, perform the addition and subtraction operations from left to right: 452 - 31 + 7 = 421 + 7 = 428

Explanation

To find the day of the week on 20 February 2015, we calculate the number of odd days from 29 July 2001 to 20 February 2015.

First, count the odd days from 29 July 2001 to 29 July 2014: Number of years = 13 years Leap years in this period are 2004, 2008, and 2012 (3 leap years). Odd days = 13 ordinary years + 3 leap years = 16 odd days. 16 odd days = 2 weeks and 2 odd days.

Next, count the odd days from 29 July 2014 to 20 February 2015: Remaining days in July 2014 = 2 days August = 3 days (31 days) September = 2 days (30 days) October = 3 days (31 days) November = 2 days (30 days) December = 3 days (31 days) January 2015 = 3 days (31 days) February 2015 (up to 20th) = 6 days (20 days)

Total odd days in this period = 2 + 3 + 2 + 3 + 2 + 3 + 3 + 6 = 24 odd days. 24 odd days = 3 weeks and 3 odd days.

Total odd days from 29 July 2001 to 20 February 2015 = 2 + 3 = 5 odd days.

Adding 5 odd days to Sunday gives Friday.

Explanation

By interchanging the mathematical signs − with ÷ and × with +, the given equation is decoded.

Original equation: 98 - 14 × 11 + 6 ÷ 23

Applying the interchanges (replace - with ÷, × with +, + with ×, and ÷ with -): 98 ÷ 14 + 11 × 6 - 23

Applying BODMAS rule: First, perform division: 98 ÷ 14 = 7

Next, perform multiplication: 11 × 6 = 66

Now, substitute these values back into the equation: 7 + 66 - 23

Perform addition and subtraction: 73 - 23 = 50

Explanation

In each given set (A, B, C), the numbers follow the relationship where the first number is four times the second number, and the third number is two times the second number. This can be expressed as:

A = 4 × B C = 2 × B

For the first set (180, 45, 90): 180 = 4 × 45 90 = 2 × 45

For the second set (128, 32, 64): 128 = 4 × 32 64 = 2 × 32

Applying this relation to the correct option (224, 56, 112): 224 = 4 × 56 112 = 2 × 56

Explanation

In the expression G + J + H × I - K, we decode the relationships starting from K:

I - K means I is the brother of K.

H × I means H is the wife of I, making H the brother's wife of K.

J + H means J is the father of H, making J the brother's wife's father of K.

G + J means G is the mother of J, making G the brother's wife's father's mother of K.

Explanation

The series follows an alternating pattern of adding an increasing integer and multiplying by 3:

7 + 6 = 13 13 × 3 = 39 39 + 7 = 46 46 × 3 = 138 138 + 8 = 146 146 × 3 = 438 438 + 9 = 447

Following this pattern, the next operation is to multiply the last term by 3:

447 × 3 = 1341

Explanation

We can analyze the logical validity of the conclusions using set relationships.

Let the sets of dresses, clouds, tables, and stones be represented by D, C, T, and S respectively.

The statement All dresses are clouds means D is a subset of C. The statement Some clouds are tables means the intersection of C and T is non-empty. The statement Some tables are stones means the intersection of T and S is non-empty.

To test Conclusion (I), All stones are dresses (S is a subset of D): There is no direct relationship specified between S and D. We can construct a scenario where the set S is completely disjoint from the set D. Thus, this conclusion is not definitely true in all possible cases.

To test Conclusion (II), Some dresses are tables (the intersection of D and T is non-empty): Although D is a subset of C, and C intersects with T, the intersecting region of C and T does not have to overlap with D. We can draw a Venn diagram where D and T have no elements in common within the larger set C. Thus, this conclusion is also not definitely true.

Explanation

The letter-cluster series is determined by analyzing the pattern of each letter position.

For the first letter of each cluster: U, O, I, E are consecutive English vowels in reverse order. Following this pattern, the next letter is A.

For the second letter of each cluster: M, P, S, V. The positions of these letters in the English alphabet are 13, 16, 19, and 22 respectively, showing a constant increase of 3. Following this pattern, the next letter position is 22 + 3 = 25, which corresponds to Y.

For the third letter of each cluster: E, G, J, N. The positions of these letters in the English alphabet are 5, 7, 10, and 14 respectively. The differences between consecutive letters are +2, +3, and +4. Following this increasing difference pattern, the next letter position is 14 + 5 = 19, which corresponds to S.

Combining these three letters yields the cluster AYS.

Explanation

The series is formed by adding 5 to the alphabetical position of each corresponding letter in the previous term.

For the first letter of each term, the positions are A (1), F (6), K (11), and P (16). Adding 5 to the position of P (16 + 5) gives 21, which corresponds to U.

For the second letter of each term, the positions are C (3), H (8), M (13), and R (18). Adding 5 to the position of R (18 + 5) gives 23, which corresponds to W.

For the third letter of each term, the positions are W (23), B (2), G (7), and L (12). Since the alphabet wraps around after Z, adding 5 to W (23 + 5) gives 28, which corresponds to B (28 - 26 = 2). Similarly, adding 5 to the position of L (12 + 5) gives 17, which corresponds to Q.

Combining these letters yields UWQ.

Explanation

The relationship between the given words is based on opposite letters in the English alphabetical order, where the sum of the positions of the original letter and its coded letter is 27.

For STEM to HGVN: S (19) corresponds to H (8), because 19 + 8 = 27. T (20) corresponds to G (7), because 20 + 7 = 27. E (5) corresponds to V (22), because 5 + 22 = 27. M (13) corresponds to N (14), because 13 + 14 = 27.

Similarly, for QUIT to JFRG: Q (17) corresponds to J (10). U (21) corresponds to F (6). I (9) corresponds to R (18). T (20) corresponds to G (7).

Applying this logic to ACCOUNTABLE: A (1) corresponds to Z (26). C (3) corresponds to X (24). C (3) corresponds to X (24). O (15) corresponds to L (12). U (21) corresponds to F (6). N (14) corresponds to M (13). T (20) corresponds to G (7). A (1) corresponds to Z (26). B (2) corresponds to Y (25). L (12) corresponds to O (15). E (5) corresponds to V (22).

Thus, ACCOUNTABLE is coded as ZXXLFMGZYOV.

Explanation

Correct Answer: D

The given series follows a pattern where each term can be expressed as n² + 9, starting from n = 7.

7² + 9 = 49 + 9 = 58 8² + 9 = 64 + 9 = 73 9² + 9 = 81 + 9 = 90 10² + 9 = 100 + 9 = 109

Following this sequence, the next term is: 11² + 9 = 121 + 9 = 130

Alternatively, the difference between consecutive terms increases by 2 each time: 73 - 58 = 15 90 - 73 = 17 109 - 90 = 19

The next difference must be 21. 109 + 21 = 130

Explanation

The relationship in the given pair is that the first word is an action of cutting, shaping, or grooming a growing entity, which is the second word, to maintain its neatness and form. Similarly, to prune is to cut back or trim a hedge to maintain its shape, promote healthy growth, and keep it neat.

Explanation

To find the code for the word 'get', we compare the two given statements and their corresponding codes:

In the first statement, 'get enough sleep' is coded as 'ab de jf'. In the second statement, 'go get it' is coded as 'jk ab gh'.

The only word common to both statements is 'get', and the only code common to both code sets is 'ab'. Therefore, the code for 'get' must be 'ab'.

Explanation

To find the day of the week on 16 January 2010, we calculate the total number of odd days between 22 March 2000 and 16 January 2010.

First, calculate the remaining days in the year 2000 from 22 March to 31 December: March: 9 days (31 - 22) April: 30 days May: 31 days June: 30 days July: 31 days August: 31 days September: 30 days October: 31 days November: 30 days December: 31 days Total days in 2000 = 284 days. Dividing 284 by 7 gives a remainder of 4 odd days.

Next, calculate the odd days for the complete years from 2001 to 2009: Total years = 9 years Leap years = 2 (2004 and 2008) Ordinary years = 7 (2001, 2002, 2003, 2005, 2006, 2007, 2009) Total odd days from these years = (2 × 2) + (7 × 1) = 11 odd days. Dividing 11 by 7 gives a remainder of 4 odd days.

Finally, calculate the days in 2010 from 1 January to 16 January: Total days = 16 days. Dividing 16 by 7 gives a remainder of 2 odd days.

Total odd days = 4 + 4 + 2 = 10 odd days. Dividing 10 by 7 gives a final remainder of 3 odd days.

Adding 3 days to Wednesday (Thursday, Friday, Saturday) gives Saturday.