Ramu and Somu together can complete a task in 10 days. Somu and Dhamu together can complete it in 12 days. Dhamu and Ramu together can complete it in 15 days. If Ramu, Somu and Dhamu work together, in how many days will they complete the task?
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Answer: (D) 8
Explanation
Let the total work be 60 units (LCM of 10, 12, and 15).
Combined daily work of Ramu and Somu = 60 / 10 = 6 units
Combined daily work of Somu and Dhamu = 60 / 12 = 5 units
Combined daily work of Dhamu and Ramu = 60 / 15 = 4 units
Adding these gives 2 × (Ramu + Somu + Dhamu) = 6 + 5 + 4 = 15 units per day.
Daily work of Ramu, Somu, and Dhamu together = 15 / 2 = 7.5 units.
Time taken to complete the task together = 60 / 7.5 = 8 days.
553Mathematics
If x = (√5 + 1)/(√5 - 1) and y = (√5 - 1)/(√5 + 1) , then find the value of x² + y² - 4 .
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Answer: (A) 3
Explanation
First, note that y is the reciprocal of x, so xy = 1.
Sum of x and y:
x + y = [(√5 + 1)² + (√5 - 1)²] / [(√5 - 1)(√5 + 1)]
x + y = [2((√5)² + 1²)] / [5 - 1]
x + y = 2(5 + 1) / 4 = 12 / 4 = 3
Substitute this into the given expression:
x² + y² - 4 = 7 - 4 = 3
554Mathematics
The sum of the angles of a quadrilateral is ______.
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Answer: (C) 360°
Explanation
The sum of the interior angles of a polygon with n sides is given by the formula (n - 2) × 180°. For a quadrilateral, n = 4:
Angle sum = (4 - 2) × 180° = 2 × 180° = 360°
Alternatively, drawing a diagonal divides any quadrilateral into two triangles. Since the sum of angles in a triangle is 180°, the total angle sum of the quadrilateral is 2 × 180° = 360°.
555Mathematics
If sin θ = ⅘ and θ is NOT in the first quadrant, then find the value of cos θ .
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Answer: (A) -⅗
Explanation
Using the trigonometric identity cos² θ = 1 - sin² θ, substituting sin θ = 4/5 yields:
Since sin θ is positive and θ does not lie in the first quadrant, θ must lie in the second quadrant where sine is positive and cosine is negative. Therefore, cos θ = -3/5.
556Mathematics
Suhas can cover the distance between point A and point B in 7 hours, if he travels at an average speed of 104 km / h . He travelled for the first four hours at an average speed of 118 km / h . What should be his average speed for the rest of the journey if he wants to reach his destination in a total time of 8 hours from the start of the journey?
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Answer: (C) 64 km / h
Explanation
Total distance between point A and point B = Speed × Time = 104 × 7 = 728 km.
Distance covered in the first 4 hours = 118 × 4 = 472 km.
Remaining distance = 728 - 472 = 256 km.
Since the total target time is 8 hours and 4 hours have already passed, the remaining time available is 8 - 4 = 4 hours.
Required average speed for the rest of the journey = 256 / 4 = 64 km/h.
557Mathematics
What percentage of a day is 3 h?
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Answer: (B) 12 ½ %
Explanation
Percentage = (Given Time / Total Time in a Day) × 100%
Since 1 day = 24 hours:
Percentage = (3 / 24) × 100% = (1 / 8) × 100% = 12.5% = 12 ½ %
558Mathematics
HCF of ½, ⅔, ¾, ⅘ is:
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Answer: (A) ¹⁄₆₀
Explanation
HCF of fractions = (HCF of numerators) / (LCM of denominators)
For the fractions 1/2, 2/3, 3/4, and 4/5:
HCF of numerators (1, 2, 3, 4) = 1
LCM of denominators (2, 3, 4, 5) = 60
HCF = 1/60
559Mathematics
If the cost price of 12 pens is equal to the selling price of 8 pens, the percentage gain is:
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Answer: (B) 50%
Explanation
Let the cost price of 1 pen be C and the selling price of 1 pen be S.
Given: 12 × C = 8 × S
S / C = 12 / 8 = 3 / 2 = 1.5
Gain percentage = [(S - C) / C] × 100
Gain percentage = (1.5 - 1) × 100 = 50%
560Mathematics
If 10% of x = 15% of y, then what will be the value of x:y?
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Answer: (C) 3:2
Explanation
10% of x = 15% of y
(10/100) × x = (15/100) × y
10 × x = 15 × y
x / y = 15 / 10 = 3 / 2
x : y = 3 : 2
561Mathematics
If the angle of a sector in a pie diagram is 135° , then it is equivalent to of the pie diagram.
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Answer: (A) 3 8
Explanation
Fraction of a pie diagram = Sector Angle / Total Angle
Substituting the given values:
Fraction = 135° / 360° = 3/8
562Mathematics
What is the domain of sine function?
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Answer: (B) R
Explanation
The domain of a function is the set of all possible input values for which the function is defined. The sine function sin(x) is defined for every real angle x, whether positive, negative, or zero, because a angle of any magnitude can be represented on the unit circle. Consequently, the set of all real numbers, denoted by R, constitutes the domain of the sine function.
563Mathematics
Find the value of the following.
4.6×13.5+5.4×13.5
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Answer: (A) 135
Explanation
By applying the distributive property of multiplication over addition, a × c + b × c = (a + b) × c:
Now, rewrite the given expression following BODMAS rules:
(16/3) ÷ (13/4) × (117/16) + (7/8) × 16
Change division to multiplication by taking the reciprocal:
= (16/3) × (4/13) × (117/16) + (7/8) × 16
Simplify the first term:
= (16/16) × (117/39) × 4
= 1 × 3 × 4 = 12
Simplify the second term:
= (7/8) × 16 = 14
Sum the results:
= 12 + 14 = 26
567Mathematics
ABCD is a parallelogram in which ∠ A = x + 20° and ∠ C = 3x - 10° . The value of x is ______
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Answer: (A) 15°
Explanation
In a parallelogram, opposite angles are equal. Since A and C are opposite angles in parallelogram ABCD, ∠A = ∠C.
x + 20° = 3x - 10°
3x - x = 20° + 10°
2x = 30°
x = 15°
568Mathematics
Given that a = √4 , find the value of the following.
√9 +25a + √(64)
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Answer: (D) 61
Explanation
Given a = √4 = 2.
Evaluating each term of the expression:
√9 = 3
25a = 25 × 2 = 50
√64 = 8
Substituting these values into the expression:
√9 + 25a + √64 = 3 + 50 + 8 = 61
569Mathematics
The following table shows the number of students appeared in an examination and the number of the students selected from different schools for admission in a well ranked university. Study the table carefully and answer the question that follows.
School Appeared Selected
ABC 1000 800
EFG 1200 1050
IJK 1500 1350
MNO 1100 900
QRS 900 750
In which of the following schools has there been the maximum percentage of selection in university?
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Answer: (A) IJK
Explanation
To find the school with the maximum percentage of selection, calculate the selection percentage for each school using the formula:
Selection Percentage = (Number of Selected Students / Number of Appeared Students) × 100%
School IJK achieves the highest selection percentage at 90%.
570Mathematics
An observer 1.5 m tall is standing 28.5 m away at the same level as the foot of a tower. If angle of elevation of the observer watching the top of the tower is 45 degrees then what is the height of the tower?
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Answer: (C) 30 m
Explanation
Height of tower = Height of observer + (Distance × tan θ)
Given:
Height of observer = 1.5 m
Distance from tower = 28.5 m
Angle of elevation θ = 45°
Height of tower above eye level = 28.5 × tan(45°) = 28.5 × 1 = 28.5 m
Total height of tower = 28.5 m + 1.5 m = 30 m
571Mathematics
Study the following table carefully and answer the question that follows.
Items of expenditure Years
2012 2013 2014 2015
Salary 200 215 250 255
Transport 48 60 71 82
Interest on loans 25 18 14 13
Taxes 2.5 3 4 5.5
Expenditure of a company (in lakh) per year over the years
What is the ratio of the expenditure on transport in the year 2013 to the total expenditure on transport for all the years taken together?
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Answer: (A) 20:87
Explanation
Expenditure on transport in the year 2013 = 60 lakh
Total expenditure on transport for all four years (2012 to 2015) = 48 + 60 + 71 + 82 = 261 lakh
Required ratio = 60 : 261 = 20 : 87
572Mathematics
The ratio of two numbers is 3 : 4 and their L.C.M is 180. What is the larger of the two numbers?
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Answer: (C) 60
Explanation
Let the common multiplier be x, so the two numbers are 3x and 4x. Since 3 and 4 are co-prime, their Least Common Multiple (LCM) is 3 × 4 × x = 12x.
Given 12x = 180, solving for x yields x = 180 / 12 = 15.
The larger number is 4x = 4 × 15 = 60.
573Mathematics
What is the compound interest on 2,800 for 1½ years at 10% per annum compounded half-yearly?
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Answer: (B) 441.35
Explanation
For interest compounded half-yearly, the annual rate is halved and the time period in half-years is doubled:
Rate per half-year, r = 10% / 2 = 5%
Number of half-years, n = 1.5 × 2 = 3
Amount (A) = P × (1 + r/100)ⁿ
A = 2800 × (1 + 5/100)³
A = 2800 × (21/20)³
A = 2800 × 9261 / 8000 = 3241.35
If each element of a matrix is zero, then the matrix is:
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Answer: (D) null
Explanation
A null matrix, also known as a zero matrix, is defined as a matrix in which every single element is zero. It can be of any dimension m × n, where every entry aᵢⱼ = 0 for all i and j.
575Mathematics
If x = (√9 + 1)/(√9 - 1) and y = (√(16) + 1)/(√(16) - 1) , then the value of (x² - y²) is:
If a cube of 15 cm side is divided into smaller cubes of 3 cm side, then how many smaller cubes will be formed?
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Answer: (B) 125
Explanation
Number of smaller cubes along each edge (n) = Side of larger cube / Side of smaller cube = 15 / 3 = 5.
Total number of smaller cubes = n³ = 5³ = 125.
578Mathematics
2 chairs and 1 table cost 880, while 1 chair and 2 tables cost 980. Find the cost of each.
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Answer: (C) 260 and 360
Explanation
Let the cost of a chair be C and the cost of a table be T.
From the given information:
2C + T = 880
C + 2T = 980
Adding the two equations:
3C + 3T = 1860
C + T = 620
Subtracting the first equation from the second:
T - C = 100
Adding these two equations:
2T = 720
T = 360
Substituting T = 360 into C + T = 620:
C = 620 - 360 = 260
The cost of each chair is 260 and each table is 360.
579Mathematics
The H.C.F of three numbers is 15. If they are in the ratio 1:2:3 , then find the numbers.
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Answer: (C) 15,30,45
Explanation
When numbers are expressed in a simplified ratio a : b : c where the terms are co-prime, each actual number is obtained by multiplying its ratio term by the H.C.F.
Since 1, 2, and 3 are co-prime, the common multiplier is the H.C.F. itself, which is 15.
Multiplying each term of the ratio 1 : 2 : 3 by 15 gives:
1 × 15 = 15
2 × 15 = 30
3 × 15 = 45
580Mathematics
After deducting a commission of 10% on the marked price, a T.V. set costs 9,090. What is its marked price?
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Answer: (D) 10,100.00
Explanation
Marked Price = Cost / (1 - Commission Rate)
Substituting the given values:
Marked Price = 9090 / (1 - 0.10) = 9090 / 0.90 = 10,100.00
581Mathematics
Find the greatest ratio in the following.
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Answer: (D) 19:27
Explanation
Converting the ratios into decimal form:
15/28 ≈ 0.536
5/18 ≈ 0.278
13/21 ≈ 0.619
19/27 ≈ 0.704
Comparing the decimal values shows that 19/27 (≈ 0.704) is the largest value among them.
582Mathematics
Find the median of the following values.
5,10,3,7,2,9,6,2and11
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Answer: (A) 6
Explanation
To find the median, arrange the given dataset in ascending order: 2, 2, 3, 5, 6, 7, 9, 10, 11.
The total number of observations is n = 9. Since n is odd, the median is given by the formula for the ((n + 1) / 2)-th term, which corresponds to the 5th term.
The 5th value in the ordered list is 6.
583Mathematics
Find the value of sin ((5π)/(3)) .
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Answer: (C) -(√3)/(2)
Explanation
Using the reduction formula sin(2π - θ) = -sin(θ) for an angle in the fourth quadrant:
sin(5π/3) = sin(2π - π/3) = -sin(π/3)
Since sin(π/3) = √3/2, substituting this value gives:
sin(5π/3) = -√3/2
584Mathematics
If √(5ⁿ) = 5, then n = ?
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Answer: (C) 2
Explanation
Squaring both sides of the equation √(5ⁿ) = 5 gives:
5ⁿ = 5²
Since the bases on both sides are equal, equating the exponents directly yields n = 2.
585Mathematics
The ratio of two numbers is 5 : 3 and their sum is 560. Find the value of the smaller of the two numbers.
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Answer: (D) 210
Explanation
Let the two numbers be 5x and 3x.
5x + 3x = 560
8x = 560
x = 70
The smaller of the two numbers corresponds to 3x:
3 × 70 = 210
586Mathematics
If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40% , then find his average speed (to 2 decimal places) for both the trips.
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Answer: (D) 58.33km / h
Explanation
Return speed = 50 + (40% of 50) = 70 km/h
When equal distances are covered at two different speeds v₁ and v₂, the average speed is given by:
Average speed = (2 × v₁ × v₂) / (v₁ + v₂)
Substituting v₁ = 50 km/h and v₂ = 70 km/h:
Average speed = (2 × 50 × 70) / (50 + 70) = 7000 / 120 = 58.33 km/h
587Mathematics
All trigonometric functions are periodic. What is the period of cos x ?
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Answer: (C) 2π
Explanation
A function f(x) is periodic with period T > 0 if T is the smallest positive real number such that f(x + T) = f(x) for all x in its domain. For the cosine function, cos(x + 2π) = cos x holds for all real numbers x, and 2π is the smallest positive value for which this equality is universally true.
588Mathematics
Giri can complete a piece of work in 6 days. With the help of her friend, she can complete it in 4 days. In how many days can her friend complete the work alone?
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Answer: (A) 12
Explanation
When individual time (x) and combined time (y) are given, the time taken by the second person working alone is calculated using the formula:
Time = (x × y) / (x - y)
Given x = 6 days and y = 4 days:
Time = (6 × 4) / (6 - 4) = 24 / 2 = 12 days
Alternatively, using the LCM method:
Assume total work = LCM(6, 4) = 12 units
Giri's efficiency = 12 / 6 = 2 units/day
Combined efficiency = 12 / 4 = 3 units/day
Friend's efficiency = 3 - 2 = 1 unit/day
Time taken by friend alone = 12 / 1 = 12 days
589Mathematics
Kishore plans to tile his kitchen floor with square tiles. Each side of the tile is 10 cm. The kitchen is 2.4 m long and 1.6 m wide. How many tiles will Kishore need?
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Answer: (C) 384
Explanation
Number of tiles required = (Length × Width) ÷ (Side of tile)²
Convert the dimensions of the kitchen from meters to centimeters:
Length = 2.4 m = 240 cm
Width = 1.6 m = 160 cm
Area of the kitchen floor = 240 cm × 160 cm = 38,400 cm²
Area of one square tile = 10 cm × 10 cm = 100 cm²
Number of tiles needed = 38,400 ÷ 100 = 384
590Mathematics
A frequency polygon is drawn using ______.
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Answer: (C) midpoint of classes and frequencies
Explanation
A frequency polygon is a graphical representation of quantitative data constructed by plotting the frequency of each class interval against its midpoint (or class mark) on a graph. The midpoints are marked on the horizontal axis and the corresponding frequencies are marked on the vertical axis, after which consecutive points are connected with straight line segments.
591Mathematics
Find the value of
18 - [6 ÷ 3 × {8 - (10 × ½)}].
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Answer: (B) 12
Explanation
Using the BODMAS rule, solve the operations inside the brackets in order from innermost to outermost:
If three-fourth of a number is 50 more than its one-third, then find the number.
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Answer: (C) 120
Explanation
Let the required number be x.
According to the given condition:
(3/4)x - (1/3)x = 50
Subtracting the fractions on the left-hand side:
(9/12 - 4/12)x = 50
(5/12)x = 50
x = (50 × 12) / 5
x = 120
593Mathematics
In ABC PQ II AB. P and Q are on BC and CA respectively. If CQ:QA=1:3 and CP=4, then what is the value of BC?
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Answer: (A) 16
Explanation
By the Basic Proportionality Theorem (Thales' Theorem), if a line is drawn parallel to one side of a triangle, it divides the other two sides in the same ratio. Since PQ is parallel to AB with P on BC and Q on CA:
CP / PB = CQ / QA
Substituting CQ / QA = ⅓ and CP = 4:
4 / PB = ⅓
PB = 12
The total length of side BC is:
BC = CP + PB = 4 + 12 = 16
594Mathematics
Two intersecting circles are said to be orthogonal if the angle between them is a/an
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Answer: (D) right angle
Explanation
The angle between two intersecting circles is defined as the angle between their tangents at the point of intersection. Two circles are said to be orthogonal when these tangents intersect at a right angle (90°). At the point of intersection of two orthogonal circles, the radius of one circle is tangent to the second circle.
595Mathematics
Find the value of 860% of 50÷ 50% of 860.
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Answer: (B) 1
Explanation
According to the BODMAS rule, the "of" operation takes precedence over division.
First, evaluate the expressions on both sides of the division operator:
860% of 50 = (860 / 100) × 50 = 430
50% of 860 = (50 / 100) × 860 = 430
Now, perform the division:
430 ÷ 430 = 1
596Mathematics
What should be added to 21.707 to get 29.053?
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Answer: (C) 7.346
Explanation
To find the number that must be added to 21.707 to obtain 29.053, subtract 21.707 from 29.053:
29.053 - 21.707 = 7.346
597Mathematics
A man purchased a fan which had a printed price of 200. If he received two successive discounts of 30% and 20% then how much did he pay for the fan?