Karuna reads {1}{4} th of a book in one hour. What fraction of the book will she be able to read in 2 h 15 min?
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Answer: (A) {9}{16}
Explanation
Time in hours = 2 + 15/60 = 2 + 1/4 = 9/4 hours.
Fraction of the book read = Reading rate × Time = 1/4 × 9/4 = 9/16.
453Mathematics
The average marks obtained by a group of 25 students was 36. One student left the group, as a result of which the average of the remaining students rose to 37.5. Soon after another student joined the same group, as a result of which the average marks dropped to 37.2. Find the average marks of the student who left and the student who joined the group.
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Answer: (D) 15
Explanation
Initial total marks of 25 students = 25 × 36 = 900
Total marks of 24 students after one student leaves = 24 × 37.5 = 900
Marks of the student who left = 900 - 900 = 0
Total marks after a new student joins (25 students) = 25 × 37.2 = 930
Marks of the student who joined = 930 - 900 = 30
Average marks of the two students = (0 + 30) ÷ 2 = 15
454Mathematics
Each interior angle of a regular polygon is 140°.
Find the number of sides of the polygon.
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Answer: (A) 9
Explanation
Exterior angle of a regular polygon = 180° - Interior angle = 180° - 140° = 40°.
The sum of all exterior angles of any convex polygon is 360°. Therefore, the number of sides n = 360° / 40° = 9.
455Mathematics
If 5tan α = 4 , then find the value of (5sinα - 3cosα)/(5sinα + 2cosα) .
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Answer: (C) ⅙
Explanation
Dividing both the numerator and the denominator by cos α gives:
(5 sin α - 3 cos α) / (5 sin α + 2 cos α) = (5 tan α - 3) / (5 tan α + 2)
Given 5 tan α = 4, substituting this value directly into the expression yields:
(4 - 3) / (4 + 2) = 1 / 6
456Mathematics
If length of a rectangle is doubled, what change should be made in its breadth so that its area remains the same?
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Answer: (B) Breadth should be halved
Explanation
Area of a rectangle is given by the formula Area = Length × Breadth (A = L × B). When the length is doubled (L' = 2L), to maintain the same area (A' = A), the new breadth B' must satisfy 2L × B' = L × B. Solving for B' yields B' = B / 2, which means the breadth must be halved.
457Mathematics
At what annual rate of compound interest, compounded semi-annually, will ₹57,600 become ₹72,900 in one year?
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Answer: (A) 25% per annum
Explanation
For interest compounded semi-annually over 1 year (2 compounding periods), the amount formula is A = P(1 + r/200)², where P is the principal and r is the annual interest rate.
Taking the square root on both sides:
1 + r/200 = 9 / 8
r/200 = 1 / 8
r = 200 / 8 = 25% per annum
458Mathematics
Simple interest on ₹50,000 at certain rate for 5 years is ₹20,000. The rate of interest is:
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Answer: (A) 8% per annum
Explanation
Simple Interest formula is SI = (P × R × T) / 100, where P is the principal amount, R is the rate of interest per annum, and T is the time period in years.
Rearranging the formula to solve for the rate of interest:
R = (SI × 100) / (P × T)
Substituting the given values into the formula:
R = (20000 × 100) / (50000 × 5)
R = 2000000 / 250000 = 8% per annum.
459Mathematics
A scooterist travels for 5 h, the first half of the distance at 21 km/h, and the rest at 24 km/h. Find the distance travelled.
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Answer: (A) 112 km
Explanation
When a journey is divided into two equal half-distances covered at speeds v₁ and v₂, the average speed for the entire journey is given by the harmonic mean formula:
Total Distance = Average Speed × Total Time = (112 / 5) × 5 = 112 km
460Mathematics
A man and a woman can complete a job in 8 and 12 days respectively. How many women must assist 2 men to complete the job in 2 days?
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Answer: (C) 3
Explanation
Work done by 1 man in 1 day = 1/8
Work done by 1 woman in 1 day = 1/12
Work done by 2 men in 2 days = 2 × 2 × (1/8) = ½
Remaining work = 1 - ½ = ½
Let n be the required number of women.
Work done by n women in 2 days = n × 2 × (1/12) = n/6
Equating the work done by women to the remaining work:
n/6 = ½
n = 3
461Mathematics
Evaluate:
3 tan 25°tan 35°tan 45°tan 55°tan 65°
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Answer: (B) 3
Explanation
Using the complementary angle identity tan(90° - θ) = cot θ:
tan 65° = cot 25°
tan 55° = cot 35°
Since tan θ × cot θ = 1 and tan 45° = 1, regroup the given expression:
3 × (tan 25° × tan 65°) × (tan 35° × tan 55°) × tan 45°
= 3 × (tan 25° × cot 25°) × (tan 35° × cot 35°) × 1
= 3 × 1 × 1 × 1 = 3
462Mathematics
Simplify.
10 - 2 1/5 + 5 1/5
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Answer: (D) 13
Explanation
Convert the mixed fractions into improper fractions:
2 1/5 = 11/5
5 1/5 = 26/5
Substitute these into the expression:
10 - 11/5 + 26/5
Combine the terms with the common denominator 5:
10 + (-11 + 26) / 5
= 10 + 15/5
= 10 + 3
= 13
463Mathematics
A and B together can do a piece of work in 21 days. With the help of C, they can finish it in 14 days. In how many days will C alone be able to finish the work?
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Answer: (C) 42 days
Explanation
Using the formula for work rate when adding a person to a group:
Time taken by C alone = (t₁ × t₂) / (t₁ - t₂)
Here, t₁ = 21 days (time taken by A and B together) and t₂ = 14 days (time taken by A, B, and C together).
Time taken by C alone = (21 × 14) / (21 - 14) = 294 / 7 = 42 days.
464Mathematics
Mean of first ten odd natural numbers is:
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Answer: (B) 10
Explanation
The sum of the first n odd natural numbers is given by the formula S = n². Therefore, the mean of the first n odd natural numbers is:
Mean = S / n = n² / n = n
For the first 10 odd natural numbers (n = 10), the mean is simply 10.
465Mathematics
An observer 1.5 m tall is 24.5 m away from a 26 m high tower. The angle of elevation of the top of the tower from the eye of the observer is:
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Answer: (C) 45°
Explanation
The height of the tower above the observer's eye level is:
h = 26 m - 1.5 m = 24.5 m
The horizontal distance from the observer to the tower is d = 24.5 m.
Using the trigonometric relation for the angle of elevation θ:
tan θ = h / d = 24.5 / 24.5 = 1
Since tan 45° = 1, the angle of elevation θ = 45°.
466Mathematics
The average of salaries of husband and wife is 65,000 and ratio of their salaries is 15:11 respectively. How much is the salary of the wife?
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Answer: (B) ₹55,000
Explanation
Sum of salaries = Average × 2 = 65,000 × 2 = ₹1,30,000
A letter of English alphabet is chosen at random. Probability of getting a vowel is:
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Answer: (A) 5/26
Explanation
Probability of an event = (Number of favorable outcomes) / (Total number of possible outcomes).
The total number of letters in the English alphabet is 26, which represents the total number of possible outcomes. The vowels in the English alphabet are A, E, I, O, and U, making a total of 5 favorable outcomes.
Therefore, the probability of choosing a vowel is 5/26.
468Mathematics
Simplify.
320 ÷ 8 × 8 ÷ 4 × ½
180 × 5 ÷ 45 - 4
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Answer: (A) ⁵⁄₂
Explanation
Evaluating the numerator using the BODMAS rule (working from left to right for multiplication and division):
Numerator = 320 ÷ 8 × 8 ÷ 4 × ½
= 40 × 8 ÷ 4 × ½
= 320 ÷ 4 × ½
= 80 × ½
= 40
Dividing the numerator by the denominator gives 40 ÷ 16 = 5/2.
469Mathematics
A card is drawn at random from a pack of playing cards. What is the probability of getting a face card?
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Answer: (C) 3/13
Explanation
Probability = (Number of favorable outcomes) / (Total number of outcomes)
In a standard deck of 52 playing cards, the face cards consist of Jacks, Queens, and Kings. Since each of the 4 suits contains 3 face cards, the total number of face cards is 3 × 4 = 12.
Probability = 12 / 52 = 3 / 13
470Mathematics
Find the mean of the following data:
x: 19 21 23 25 27 29 31
f: 13 15 16 18 16 15 13
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Answer: (B) 25
Explanation
The mean of a frequency distribution is calculated using the formula x̄ = Σ(f × x) / Σf.
Sum of frequencies Σf = 13 + 15 + 16 + 18 + 16 + 15 + 13 = 106
By symmetry, since the values of x and their corresponding frequencies are symmetrically distributed around x = 25, the mean lies directly at the central value 25 without requiring calculation.
471Mathematics
If A exceeds B by 25% and B is less than C by 30% , then the ratio of A and C is:
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Answer: (D) 7 : 8
Explanation
Using percentage-to-fraction conversions:
A / B = (100 + 25) / 100 = 125 / 100 = 5 / 4
B / C = (100 - 30) / 100 = 70 / 100 = 7 / 10
To find the ratio of A to C, multiply the two ratios:
A / C = (A / B) × (B / C) = (5 / 4) × (7 / 10) = 35 / 40 = 7 / 8
472Mathematics
If two litres of water is evaporated from a 5 litre solution containing 3% salt, then what is the percentage of salt in the remaining solution?
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Answer: (D) 5%
Explanation
Using the mass balance equation for salt:
Initial Volume × Initial Concentration = Final Volume × Final Concentration
5 × 3% = 3 × Final Concentration
Final Concentration = (5 × 3%) / 3 = 5%
473Mathematics
The value of 27× 4.15 + 30.8÷ 22 is:
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Answer: (B) 113.45
Explanation
Following BODMAS rules, perform multiplication and division before addition:
First term: 27 × 4.15 = 112.05
Second term: 30.8 ÷ 22 = 1.4
Now, add the results together:
112.05 + 1.4 = 113.45
474Mathematics
The product of two positive numbers is 0.60. If one number is ¹⁄₁₅ th of the other, then what are the two numbers?
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Answer: (A) 0.2, 3.0
Explanation
Let the two positive numbers be x and y, where x = y / 15.
Given that x × y = 0.60, substituting y = 15x gives:
15x² = 0.60
x² = 0.04
x = 0.2
Substituting x = 0.2 back into y = 15x gives y = 15 × 0.2 = 3.0.
475Mathematics
To complete a given task, Imran takes 11 days, Tahir takes 15 days and Amla takes 13 days. Working together they finish the task and get 2,012. What will be the share of Imran provided the daily wage is the same for all?
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Answer: (C) 780
Explanation
When individuals work together to complete a task, the total wages are shared in the ratio of their work efficiencies (work done per day).
Efficiency ratio of Imran, Tahir, and Amla = 1/11 : 1/15 : 1/13
Multiplying each term by the product of the denominators (11 × 15 × 13 = 2145):
Ratio = (15 × 13) : (11 × 13) : (11 × 15) = 195 : 143 : 165
Three prime numbers are arranged in descending order. If the product of the first two is 323 and that of the last two is 221, then what is the value of the biggest prime number?
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Answer: (C) 19
Explanation
Let the three prime numbers in descending order be p₁, p₂, and p₃, where p₁ > p₂ > p₃.
The given products are:
p₁ × p₂ = 323
p₂ × p₃ = 221
Since p₂ is a common factor of both 323 and 221, p₂ = gcd(323, 221).
Using the trigonometric identity 2 cos² θ - 1 = cos 2θ:
x² + 1/x² = 2 cos 2θ
487Mathematics
In tossing three coins at a time, the probability of getting at least one heads is:
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Answer: (C) 7/8
Explanation
The total number of possible outcomes when tossing three coins is 2³ = 8. Using the complement rule, the probability of getting at least one head is given by:
P(at least one head) = 1 − P(no heads)
Since there is only 1 outcome with no heads (TTT), P(no heads) = 1/8.
P(at least one head) = 1 − 1/8 = 7/8.
488Mathematics
Find the value of 7 × 0.7 × 0.07 × 0.007 × 70 :
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Answer: (C) 0.16807
Explanation
The given product can be calculated by multiplying the non-zero digits and adjusting for the net power of 10:
7 × 7 × 7 × 7 × 7 = 7⁵ = 16807
Counting the net decimal shift:
1 (from 0.7) + 2 (from 0.07) + 3 (from 0.007) - 1 (from 70) = 5 decimal places to the left.
Shifting 16807 left by 5 decimal places:
16807 × 10⁻⁵ = 0.16807
489Mathematics
Find the simple interest for an amount of 2,500 at 8¼% per annum for the period from 1ˢᵗ March 2018 to 12ᵗʰ May 2018.
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Answer: (A) 41.25
Explanation
Simple Interest (SI) = (P × R × T) / 100
Given Principal (P) = ₹2,500
Rate of Interest (R) = 8¼% = 33/4% per annum
The period from 1st March 2018 to 12th May 2018 consists of:
March = 31 days
April = 30 days
May = 12 days
Total time = 31 + 30 + 12 = 73 days
Converting days into years:
T = 73 / 365 = 1/5 year
Substituting the values into the formula:
SI = (2500 × 33/4 × 1/5) / 100
SI = (25 × 33) / 20
SI = 165 / 4 = 41.25
490Mathematics
A retailer buys 20 pens at the marked price of 15 pens from a wholesaler. If he sells these 20 pens giving a discount of 1% , then what is the profit percent of the retailer?
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Answer: (A) 32%
Explanation
Let the marked price (MP) of 1 pen be ₹1.
Cost price (CP) of 20 pens = MP of 15 pens = ₹15.
Selling price (SP) of 20 pens after a 1% discount on the marked price = ₹20 × (1 - 0.01) = ₹19.80.
Find the radius of the circle x² + y² + 7x + 4y + 9 = 0 .
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Answer: (C) (√(29))/(2)
Explanation
For the standard equation of a circle x² + y² + 2gx + 2fy + c = 0, the radius is given by the formula r = √(g² + f² - c).
Comparing x² + y² + 7x + 4y + 9 = 0 with the standard equation gives:
2g = 7 → g = 7/2
2f = 4 → f = 2
c = 9
Substituting these values into the radius formula:
r = √((7/2)² + 2² - 9)
r = √(49/4 + 4 - 9)
r = √(49/4 - 5)
r = √((49 - 20)/4)
r = √(29/4) = √29/2
494Mathematics
A man covered a distance of 32km . After 1 hour 20 minutes he noticed that the distance he covered is ⁵⁄₇ th of the remaining distance. What was his speed in km / hr ?
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Answer: (C) 10 km/hr
Explanation
The ratio of covered distance to remaining distance is 5 : 7. Therefore, out of 12 total parts, the covered distance represents 5 parts.
Distance covered = (5 ÷ 12) × 32 = 40/3 km.
Time taken = 1 hour 20 minutes = 1 + 20/60 = 4/3 hours.
If the perimeter of a square is 160 cm. What is the diagonal of the square (in cm)?
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Answer: (C) 40√2 cm
Explanation
For a square of side length a, the perimeter is P = 4a and the diagonal length is d = a√2.
Given perimeter P = 160 cm:
a = 160 / 4 = 40 cm
Substituting the side length into the diagonal formula:
d = 40√2 cm
496Mathematics
Three numbers are in the ratio 1:2:3 . If their HCF is 8, then what is their LCM?
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Answer: (C) 48
Explanation
For any numbers in the ratio a : b : c with a highest common factor of HCF, the least common multiple is given by the formula:
LCM = HCF × LCM(a, b, c)
Given the ratio 1 : 2 : 3 and HCF = 8:
LCM(1, 2, 3) = 6
LCM = 8 × 6 = 48
497Mathematics
Tony purchases two cars A and B at a total cost of ₹6,50,000. He sells car A with 20% profit and car B at a loss of 25% and gets the same selling price for both the cars. What are the purchasing prices of car A and car B respectively?
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Answer: (D) ₹2,50,000; ₹4,00,000
Explanation
Let CP_A and CP_B be the cost prices of cars A and B respectively. Since the selling price of both cars is the same, 120% of CP_A equals 75% of CP_B:
1.20 × CP_A = 0.75 × CP_B
CP_A / CP_B = 0.75 / 1.20 = 5 / 8
Dividing the total cost of ₹6,50,000 in the ratio 5:8 gives:
A son is 24 years younger than his father, and in 2 years, he will be half of the age of his father. What is the age of the father?
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Answer: (C) 46 Years
Explanation
Let F be the current age of the father and S be the current age of the son.
According to the given conditions:
F - S = 24
S + 2 = ½ × (F + 2)
Simplifying the second equation:
2S + 4 = F + 2
F - 2S = 2
Subtracting this from the first equation (F - S = 24):
(F - S) - (F - 2S) = 24 - 2
S = 22
Substituting S = 22 back into F = S + 24 yields F = 22 + 24 = 46 years.
500Mathematics
A sum of money doubles itself at compound interest in 12 years. In how many years will it become 4 times?
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Answer: (B) 24
Explanation
Under compound interest, if a sum of money becomes k times itself in t years, it becomes kⁿ times itself in n × t years. Here, the money doubles (k = 2) in 12 years (t = 12). To become 4 times itself, which is 2² (n = 2), the required time is n × t = 2 × 12 = 24 years.