RRB NTPC2021MathematicsPage 11 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 501–550 of 1,785, each with the correct answer and a step-by-step explanation.

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501Mathematics
Details of the number of students from various schools playing different sports is given in the table below. Study the table and answer the question. Games | Schools A | B | C | D | E Badminton | 34 | 67 | 23 | 78 | 56 Table Tennis | 21 | 40 | 26 | 32 | 29 Football | 12 | 22 | 19 | 16 | 21 Basketball | 09 | 13 | 07 | 12 | 06 Cricket | 98 | 121 | 78 | 84 | 67 Name the sports that have the minimum and maximum participation respectively, of students from all the schools.
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Answer: (A) Basketball and Cricket

Explanation

To find the total participation for each sport across all five schools, sum the number of students playing each game:

Badminton: 34 + 67 + 23 + 78 + 56 = 258 Table Tennis: 21 + 40 + 26 + 32 + 29 = 148 Football: 12 + 22 + 19 + 16 + 21 = 90 Basketball: 9 + 13 + 7 + 12 + 6 = 47 Cricket: 98 + 121 + 78 + 84 + 67 = 448

Basketball has the overall minimum participation with 47 students, and Cricket has the overall maximum participation with 448 students.

502Mathematics
The measure of the greatest length which can measure 24~m 32~m and 42~m completely is:
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Answer: (B) 2 m

Explanation

The greatest length that can measure the given lengths completely is their Highest Common Factor (HCF).

Prime factorisation of the given numbers: 24 = 2³ × 3 32 = 2⁵ 42 = 2 × 3 × 7

The highest common factor is the lowest power of the common prime factor, which is 2¹ = 2 m.

503Mathematics
Calculate the smallest number which should be subtracted from 0.000327 to make it a perfect square.
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Answer: (D) 0.000003

Explanation

0.000327 can be written as 327 × 10⁻⁶. The largest perfect square less than 327 is 324, which is 18².

Therefore, the largest perfect square less than 0.000327 is: 324 × 10⁻⁶ = (18 × 10⁻³)² = (0.018)² = 0.000324

Subtracting this perfect square from the given number: 0.000327 − 0.000324 = 0.000003

504Mathematics
Study the given information in the table and answer the question that follows. The following table shows the details of the number of people who booked a ticket and travelled from Punjab, during the years 2015 to 2018. Year | Punjab | Tickets booked | Actually Travelled 2015 | 2400 | 2200 2016 | 2300 | 2000 2017 | 2600 | 2500 2018 | 2800 | 2450 Total | 10100 | 9150 In which year was the number of people who travelled as a percentage of those who booked tickets, the minimum?
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Answer: (D) 2016

Explanation

The percentage of people who actually travelled out of those who booked tickets for each year is calculated using the formula: Percentage = (Actually Travelled / Tickets Booked) × 100

2015: (2200 / 2400) × 100 = 91.67% 2016: (2000 / 2300) × 100 = 86.96% 2017: (2500 / 2600) × 100 = 96.15% 2018: (2450 / 2800) × 100 = 87.50%

Comparing the percentages, 86.96% in 2016 is the lowest value among all years.

505Mathematics
The table below gives the details of maximum marks and marks obtained by different students in the subjects Mathematics, English, Physics, Chemistry, Computer Science, and Photography: Students | Pundir | Anil | Devesh | Ramit | Naman Subjects | Max. Marks | Marks Obtained Mathematics | 100 | 67 | 84 | 65 | 90 Physics | 100 | 56 | 89 | 72 | 88 Chemistry | 100 | 57 | 79 | 62 | 92 English | 100 | 72 | 69 | 80 | 82 Computer Sc. | 50 | 33 | 39 | 34 | 41 Photography | 50 | 40 | 45 | 47 | 45 Total | 500 | 355 | 405 | 360 | 440 What is approximate average percentage of marks of all the students?
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Answer: (B) 75%

Explanation

To find the average percentage, sum the actual marks obtained by each student across all six subjects (out of 500 total maximum marks per student):

  • Pundir: 67 + 56 + 57 + 72 + 33 + 40 = 325
  • Anil: 84 + 89 + 79 + 69 + 39 + 45 = 405
  • Devesh: 65 + 72 + 62 + 80 + 34 + 47 = 360
  • Ramit: 90 + 88 + 92 + 82 + 41 + 45 = 438

Total marks obtained by all 4 students = 1528 out of a total maximum of 2000. Average percentage = (1528 / 2000) * 100 = 76.4%, which is approximately 75%.

506Mathematics
The table below gives the details of computer printers sold by XYZ company over a period of 5 years. Year | Types of Printers | L-1100 | L-1101 | L-1102 | L-1103 | L-1104 | Total 2014 | 523 | 345 | 678 | 340 | 740 | 2626 2015 | 673 | 451 | 822 | 235 | 905 | 3086 2016 | 567 | 389 | 907 | 423 | 867 | 3153 2017 | 590 | 562 | 1022 | 548 | 913 | 3635 2018 | 623 | 677 | 1245 | 674 | 988 | 4207 Total | 2976 | 2424 | 4674 | 2220 | 4413 | 16707 What is the approximate share of the sales of printer model L-1102 as a percentage of total sales of printers in the year 2015?
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Answer: (C) 27%

Explanation

Percentage share = (Sales of L-1102 in 2015 / Total sales in 2015) × 100

From the given table: Sales of printer model L-1102 in 2015 = 822 Total sales of printers in 2015 = 3086

Required percentage = (822 / 3086) × 100 = 26.63% ≈ 27%

507Mathematics
What is the third number in a group of three numbers with a combined average of 29, when the average of the other two numbers is 13?
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Answer: (A) 61

Explanation

Sum of the three numbers = 3 × 29 = 87.

Sum of the other two numbers = 2 × 13 = 26.

Third number = 87 - 26 = 61.

508Mathematics
If length of each side of a cube is doubled, then its volume the original volume.
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Answer: (C) becomes 8 times

Explanation

The volume of a cube with side length s is given by the formula V = s³.

When the length of each side is doubled, the new side length becomes 2s. Substituting this into the formula gives the new volume V':

V' = (2s)³ = 8s³ = 8V

509Mathematics
Babu purchased a car for ₹3,00,000/- and a bike for his son for ₹1,00,000/-. He sold the car at a profit of 10% and bike at a loss of 20%. What is the net gain or loss?
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Answer: (B) 2.5% gain

Explanation

Total Cost Price = ₹3,00,000 + ₹1,00,000 = ₹4,00,000

Gain on car = 10% of ₹3,00,000 = ₹30,000 Loss on bike = 20% of ₹1,00,000 = ₹20,000

Net Gain = ₹30,000 - ₹20,000 = ₹10,000

Net Gain Percentage = (Net Gain / Total Cost Price) × 100 = (10,000 / 4,00,000) × 100 = 2.5% gain

510Mathematics
Two persons A and B are travelling towards each other at the speeds of 10 km/h and 14 km/h. The distance between them is 24 km. Find the time taken by them to meet each other.
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Answer: (C) 1 h

Explanation

Relative speed of two objects moving towards each other is the sum of their individual speeds: Relative speed = 10 km/h + 14 km/h = 24 km/h

Time taken to meet = Total distance / Relative speed = 24 km / 24 km/h = 1 h

511Mathematics
A principal amount of ₹6,000/- borrowed for compound interest is raised to ₹7,986 in 3 years. What is the rate of interest?
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Answer: (C) 10%

Explanation

The compound interest formula is A = P(1 + r/100)ᵗ, where A is the total amount, P is the principal, r is the rate of interest per annum, and t is the time period in years.

Substituting the given values: 7986 = 6000(1 + r/100)³ 7986 / 6000 = (1 + r/100)³

Simplifying the fraction by dividing both numerator and denominator by 6: 1331 / 1000 = (1 + r/100)³

Taking the cube root on both sides: (11 / 10)³ = (1 + r/100)³ 11 / 10 = 1 + r/100 1.1 = 1 + r/100 r / 100 = 0.1 r = 10%

512Mathematics
If cos x - 3sin x = √5sin x , then the value of tan x is:
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Answer: (A) (3 - √5)/(4)

Explanation

Rearranging the given equation: cos x = 3 sin x + √5 sin x cos x = (3 + √5) sin x

Dividing both sides by cos x: 1 = (3 + √5) tan x tan x = 1 / (3 + √5)

Rationalizing the denominator by multiplying the numerator and denominator by (3 - √5): tan x = (3 - √5) / ((3 + √5)(3 - √5)) tan x = (3 - √5) / (3² - (√5)²) tan x = (3 - √5) / (9 - 5) tan x = (3 - √5) / 4

513Mathematics
Ram has a movie in his pen drive that takes 1.75 GB of space. He wants to share it with his friends. The speed of transferring the file is 2 MB/s. How much time will it take to transfer the file? (1 GB = 1000 MB)
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Answer: (B) 14 min 35 s

Explanation

Time = File Size ÷ Speed

File size in MB = 1.75 × 1000 MB = 1750 MB. Transfer speed = 2 MB/s.

Total time = 1750 MB ÷ 2 MB/s = 875 seconds.

Converting seconds to minutes and seconds: 875 ÷ 60 = 14 minutes with a remainder of 35 seconds, since 14 × 60 = 840 seconds and 875 − 840 = 35 seconds.

514Mathematics
The difference between the place values of 2 and 4 in the number 275413 is:
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Answer: (B) 199600

Explanation

In the number 275413, the digit 2 is in the hundred-thousands place, so its place value is 2 × 100000 = 200000. The digit 4 is in the hundreds place, so its place value is 4 × 100 = 400.

Difference = 200000 − 400 = 199600.

515Mathematics
Solve the given equation. √((544)² - (256)²) = ?
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Answer: (A) 480

Explanation

Using the algebraic identity a² - b² = (a - b)(a + b):

(544)² - (256)² = (544 - 256)(544 + 256) = 288 × 800 = 230400

Taking the square root:

√(230400) = √(2304 × 100) = 48 × 10 = 480

516Mathematics
If x:y = 2:3 , then (4x + 3y):(2x + 5y) = ?
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Answer: (B) 17:19

Explanation

Since x:y = 2:3, substitute x = 2 and y = 3 directly into the given expression:

4x + 3y = 4(2) + 3(3) = 8 + 9 = 17 2x + 5y = 2(2) + 5(3) = 4 + 15 = 19

Evaluating the fraction (4x + 3y) / (2x + 5y) gives 17/19, which equals 17:19.

517Mathematics
The value of √(142884) is:
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Answer: (D) 378

Explanation

Using the algebraic identity (a - b)² = a² - 2ab + b² with a = 380 and b = 2:

378² = (380 - 2)² = 380² - 2 × 380 × 2 + 2² = 144400 - 1520 + 4 = 142884

Taking the square root on both sides gives √142884 = 378.

518Mathematics
If a cos θ - b sin θ = c , then find the value of a sin θ + b cos θ .
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Answer: (B) ± √(a² + b² - c²)

Explanation

Let x = a sin θ + b cos θ.

Squaring and adding the two equations: (a cos θ - b sin θ)² + (a sin θ + b cos θ)² = a² cos² θ + b² sin² θ - 2ab sin θ cos θ + a² sin² θ + b² cos² θ + 2ab sin θ cos θ = a²(cos² θ + sin² θ) + b²(sin² θ + cos² θ) = a² + b²

Substituting the given equation c = a cos θ - b sin θ: c² + x² = a² + b² x² = a² + b² - c² x = ± √(a² + b² - c²)

519Mathematics
If (0.008)/(x) = 0.01 , then x = ?
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Answer: (B) 0.8

Explanation

0.008 / x = 0.01

x = 0.008 / 0.01

Multiplying both numerator and denominator by 100:

x = 0.8 / 1 = 0.8

520Mathematics
40% of the goods are sold at 2% loss while the rest of the goods are sold at 4% profit. If there is a total profit of 250, then the cost price of goods sold is:
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Answer: (A) 15,625/-

Explanation

Let the total cost price of the goods be C.

Net profit percentage = (60% × 4%) - (40% × 2%) = 2.4% - 0.8% = 1.6%

Given that the total profit is 250: 1.6% of C = 250 (1.6 / 100) × C = 250 C = (250 × 100) / 1.6 = 25000 / 1.6 = 15,625

521Mathematics
If A lies in the second quadrant and 13sin A - 12 = 0 , then 5sin A + 12cos A + tan² A - (sec² A - 1) = ?
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Answer: (A) 0

Explanation

Given 13 sin A - 12 = 0, we have sin A = 12/13. Since A lies in the second quadrant, cos A is negative: cos A = -√(1 - sin² A) = -√(1 - (12/13)²) = -5/13

Using the trigonometric identity sec² A - 1 = tan² A, the expression simplifies directly: tan² A - (sec² A - 1) = tan² A - tan² A = 0

Substituting the values into the given expression: 5 sin A + 12 cos A + tan² A - (sec² A - 1) = 5(12/13) + 12(-5/13) + 0 = 60/13 - 60/13 = 0

522Mathematics
If Raju is thrice as good workman as Ravi and takes 20 days less than him to complete a piece of work, then find the time taken by Ravi to complete the work.
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Answer: (B) 30 days

Explanation

Ratio of efficiency of Raju to Ravi = 3 : 1. Since efficiency is inversely proportional to time, the ratio of time taken by Raju and Ravi is 1 : 3.

Let the time taken by Raju be x days and Ravi be 3x days. Difference in time = 3x - x = 2x days

Given, 2x = 20 days, which gives x = 10 days. Time taken by Ravi = 3x = 3 × 10 = 30 days.

523Mathematics
The mean of 20 observations is 50. It was later found that two observations 13 and 24 were incorrectly recorded as 31 and 42. The correct mean is:
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Answer: (D) 48.20

Explanation

Correct Mean = Incorrect Mean + [(Sum of correct observations - Sum of incorrect observations) ÷ Number of observations]

Substitute the given values into the formula: Correct Mean = 50 + [(13 + 24 - 31 - 42) ÷ 20] Correct Mean = 50 + [(-36) ÷ 20] Correct Mean = 50 - 1.80 = 48.20

524Mathematics
The HCF of two numbers is 4 and their product is 48. Find the numbers.
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Answer: (B) 4,12

Explanation

Let the two numbers be 4a and 4b, where a and b are co-prime integers.

Product of the numbers = 4a × 4b = 16ab Given that the product is 48: 16ab = 48 ab = 3

Since 3 is a prime number, the only co-prime pair for (a, b) is (1, 3). Substituting these values gives the numbers as 4 × 1 = 4 and 4 × 3 = 12.

525Mathematics
Solve the given equation. 2 - [2 - {2 - 2(2 + 2)} ] = ?
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Answer: (B) - 6

Explanation

Using the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction), evaluate the expression step-by-step from the innermost brackets outward:

Innermost parentheses: (2 + 2) = 4 Curly braces: 2 - 2(4) = 2 - 8 = -6 Square brackets: 2 - (-6) = 2 + 6 = 8 Outer expression: 2 - 8 = -6

526Mathematics
Which is the descending order in the following fractions?
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Answer: (B) ¹⁶⁄₁₇, ⁶⁄₇, ¹¹⁄₁₃, ⅚

Explanation

To arrange the fractions in descending order, convert each fraction to its decimal form:

16/17 ≈ 0.9412 6/7 ≈ 0.8571 11/13 ≈ 0.8462 5/6 ≈ 0.8333

Comparing the values: 0.9412 > 0.8571 > 0.8462 > 0.8333, giving the order 16/17, 6/7, 11/13, 5/6.

527Mathematics
If (√2 +1)³ = a + b√2 , then the correct relation between a and b is
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Answer: (C) a - b = 2

Explanation

Using the algebraic expansion (x + y)³ = x³ + 3x²y + 3xy² + y³:

(√2 + 1)³ = (√2)³ + 3(√2)²(1) + 3(√2)(1)² + 1³ = 2√2 + 6 + 3√2 + 1 = 7 + 5√2

Comparing this with a + b√2 gives a = 7 and b = 5.

Substituting these values yields a - b = 7 - 5 = 2.

528Mathematics
If 5A - 2B = 0 and 4B - 5C = 0 , then C:A = ?
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Answer: (B) 2:1

Explanation

From 5A - 2B = 0, express B in terms of A: B = 5A / 2

Substitute B into the second equation, 4B - 5C = 0: 4(5A / 2) - 5C = 0 10A - 5C = 0 5C = 10A C / A = 10 / 5 = 2 / 1

Thus, C:A = 2:1.

529Mathematics
The greatest number of three digits which is exactly divisible by 3, 4, 5 and 8 is:
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Answer: (C) 960

Explanation

The required number must be a multiple of the least common multiple (LCM) of 3, 4, 5, and 8.

LCM(3, 4, 5, 8) = 120

The greatest three-digit number is 999. Dividing 999 by the LCM: 999 = 120 × 8 + 39

Subtracting the remainder 39 from 999 gives the greatest three-digit number divisible by 3, 4, 5, and 8: 999 - 39 = 960

530Mathematics
The interior angle of a regular polygon is 108° . The number of the sides of the polygon is:
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Answer: (C) 5

Explanation

The exterior angle of a regular polygon is 180° - 108° = 72°.

The number of sides n is given by: n = 360° / exterior angle = 360° / 72° = 5.

531Mathematics
The volume of a hemisphere is 19404 cm³ . Its radius is: (Use π = ²²⁄₇ )
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Answer: (C) 21 cm

Explanation

The volume of a hemisphere is given by the formula V = (2/3) × π × r³, where r is the radius.

Substituting the given values: 19404 = (2/3) × (22/7) × r³ 19404 = (44/21) × r³ r³ = (19404 × 21) ÷ 44 r³ = 441 × 21 r³ = 21³ r = 21 cm

532Mathematics
X, Y and Z together earn 2,400/- in 15 days. X and Y together earn 1,840/- in 16 days. Y and Z together earn 1,530/- in 18 days. What is the daily earning (in ₹) of Y?
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Answer: (A) 40

Explanation

Daily earning of (X + Y + Z) = 2,400 / 15 = ₹160 Daily earning of (X + Y) = 1,840 / 16 = ₹115 Daily earning of (Y + Z) = 1,530 / 18 = ₹85

Daily earning of Y = (Daily earning of X + Y) + (Daily earning of Y + Z) - (Daily earning of X + Y + Z) = 115 + 85 - 160 = ₹40

533Mathematics
The product of two numbers is 64 and their sum is 20. If the first number is greater than the second, then the ratio of the two numbers is:
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Answer: (C) 4:1

Explanation

Let the two numbers be x and y, where x > y.

Given x + y = 20 and xy = 64.

Using the algebraic identity (x - y)² = (x + y)² - 4xy: (x - y)² = 20² - 4(64) = 400 - 256 = 144 x - y = 12

Solving x + y = 20 and x - y = 12 gives: x = 16 and y = 4

Since the first number is greater than the second, the required ratio is 16 : 4 = 4 : 1.

534Mathematics
In an examination, 90% of students passed and 260 students failed. The total number of the students is:
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Answer: (A) 2600

Explanation

Percentage of failed students = 100% - 90% = 10%

Let the total number of students be N. 10% of N = 260 (10 / 100) × N = 260 N = (260 × 100) / 10 = 2600

535Mathematics
A invests two equal amounts in two banks giving rates of simple interest as 10% per annum and 12% per annum respectively. At the end of the year, the interest earned is ₹1,650/-. The amount invested in each bank is:
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Answer: (C) ₹7,500/-

Explanation

Let the principal amount invested in each bank be P.

Total Simple Interest = P × (R₁ + R₂) × T / 100

Substituting the given values: 1,650 = P × (10 + 12) × 1 / 100 1,650 = P × 22 / 100 P = (1,650 × 100) / 22 = 7,500

536Mathematics
The least number that should be added to 1549 so that the sum is exactly divisible by 2, 3, 5 and 7 is:
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Answer: (C) 131

Explanation

The least common multiple (LCM) of prime numbers 2, 3, 5, and 7 is 2 × 3 × 5 × 7 = 210.

Dividing 1549 by 210 gives a quotient of 7 and a remainder of 79: 1549 = 210 × 7 + 79

The least number that must be added to 1549 to make it a multiple of 210 is: 210 - 79 = 131

537Mathematics
Find the median of 45, 76, 32, 58, 16, 27, 64 and 35.
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Answer: (B) 40

Explanation

Arranging the given 8 numbers in ascending order: 16, 27, 32, 35, 45, 58, 64, 76

Since the number of terms n = 8 (even), the median is the average of the middle two terms (the 4th and 5th terms):

Median = (35 + 45) / 2 = 80 / 2 = 40

538Mathematics
A glass cylinder with diameter 20 cm has water to a height of 9 cm. A metal cube of 8 cm edge is immersed in it completely. Calculate the height (correct to 1 decimal place) by which the water will rise in the cylinder (by taking π = 3.142 ).
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Answer: (C) 1.6 cm

Explanation

When a solid object is completely immersed in liquid, the volume of displaced liquid equals the volume of the immersed object.

Volume of the metal cube = edge³ = 8³ = 512 cm³

The radius of the glass cylinder r = 20 / 2 = 10 cm.

Let h be the height by which the water level rises in the cylinder.

Volume of displaced water in cylinder = π × r² × h 3.142 × 10² × h = 512 314.2 × h = 512 h = 512 / 314.2 ≈ 1.629 cm

Correct to one decimal place, the height by which water rises is 1.6 cm.

539Mathematics
District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters. For an election, 25% of the rural voters were shifted to the urban area. Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking. Two candidates, A and B, contested the election. Candidate B swept the urban vote, while Candidate A found favour with the rural voters. Voters who were both honest and hardworking voted for NOTA. How many votes were polled in favour of candidate A, candidate B and NOTA, respectively?
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Answer: (B) 19500, 13000 and 17500

Explanation

Initial rural voters = 80% of 50,000 = 40,000 Initial urban voters = 20% of 50,000 = 10,000

After shifting 25% of rural voters (25% of 40,000 = 10,000) to the urban area: Final rural voters = 40,000 - 10,000 = 30,000 Final urban voters = 10,000 + 10,000 = 20,000

Voters who are both honest and hardworking constitute 35% of the voters in each area and vote for NOTA: NOTA votes from rural area = 35% of 30,000 = 10,500 NOTA votes from urban area = 35% of 20,000 = 7,000 Total NOTA votes = 10,500 + 7,000 = 17,500

The remaining 65% of voters in each area vote for their respective candidates: Candidate A (rural voters) = 65% of 30,000 = 19,500 Candidate B (urban voters) = 65% of 20,000 = 13,000

540Mathematics
A fruit seller has some oranges. He sells 60% of them and still has 380 oranges. Originally, he had ______ oranges.
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Answer: (C) 950

Explanation

Percentage of remaining oranges = 100% - 60% = 40%.

Since 40% of the total number of oranges is equal to 380: Total oranges = (380 × 100) / 40 = 950.

541Mathematics
Determine the smallest number which when divided by 12,16,20,25 and 30 leaves the same remainder 3 in each case.
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Answer: (C) 1203

Explanation

The smallest number that leaves a remainder r when divided by a set of numbers is given by:

Required Number = LCM(given numbers) + r

First, find the prime factorizations: 12 = 2² × 3 16 = 2⁴ 20 = 2² × 5 25 = 5² 30 = 2 × 3 × 5

LCM(12, 16, 20, 25, 30) = 2⁴ × 3¹ × 5² = 16 × 3 × 25 = 1200

Required Number = 1200 + 3 = 1203

542Mathematics
The difference between a 16% profit and a 12% loss while selling an article is ₹70 . What is the cost price of the article?
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Answer: (C) 250

Explanation

The percentage difference between a 16% profit (+16%) and a 12% loss (-12%) is 16% - (-12%) = 28%.

Given that 28% of the cost price equals 70:

Cost Price = (70 × 100) / 28 = 250

543Mathematics
Find the mean of the following data. 8,- 2,9,6,13,17,12
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Answer: (C) 9

Explanation

Mean = (Sum of observations) ÷ (Total number of observations)

Sum = 8 + (-2) + 9 + 6 + 13 + 17 + 12 = 63 Total number of observations = 7

Mean = 63 ÷ 7 = 9

544Mathematics
The perimeter of a rectangle is 100m and its length is 29m . Find its width.
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Answer: (B) 21 m

Explanation

Perimeter of a rectangle = 2 × (length + width)

100 = 2 × (29 + width) 50 = 29 + width width = 50 - 29 = 21 m

545Mathematics
Ramu can reach a certain place in 30 hours. If he reduces his speed by ¹⁄₁₅ th, he goes 10 km less in that time. Find his speed.
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Answer: (D) 5 km/h

Explanation

Since time is constant at 30 hours, distance covered is directly proportional to speed. A reduction in speed by 1/15 results in a 1/15 reduction in the total distance covered.

Given that the reduction in distance is 10 km: 1/15 × Total Distance = 10 km Total Distance = 10 × 15 = 150 km

Speed = Total Distance / Time = 150 / 30 = 5 km/h.

546Mathematics
Simplify the following. ⅖× [2 + {3 + (12 + 4 + 3)} ]
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Answer: (D) 9⅗

Explanation

Following the BODMAS rule, evaluate the expression step-by-step from the innermost brackets:

Inner parenthesis: 12 + 4 + 3 = 19 Curly braces: 3 + 19 = 22 Square brackets: 2 + 22 = 24

Multiply by 2/5: (2/5) × 24 = 48/5

Converting 48/5 into a mixed fraction gives 9 3/5.

547Mathematics
The ratio of the age of Naresh to that of Suresh is 6:5 and the sum of their ages is 44 years. The ratio of their respective ages after 15 years will be:
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Answer: (A) 39:35

Explanation

Let the present ages of Naresh and Suresh be 6x and 5x years respectively.

Given that the sum of their ages is 44 years: 6x + 5x = 44 11x = 44 x = 4

Naresh's present age = 6 × 4 = 24 years Suresh's present age = 5 × 4 = 20 years

After 15 years: Naresh's age = 24 + 15 = 39 years Suresh's age = 20 + 15 = 35 years

Therefore, the ratio of their ages after 15 years is 39:35.

548Mathematics
If sin x - 5cos x = 2√6cos x, then the value of cot x is:
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Answer: (D) 5 - 2√6

Explanation

Divide the given equation sin x - 5 cos x = 2√6 cos x by cos x: tan x - 5 = 2√6 tan x = 5 + 2√6

Since cot x = 1 / tan x: cot x = 1 / (5 + 2√6)

Rationalizing the denominator by multiplying both the numerator and denominator by (5 - 2√6): cot x = (5 - 2√6) / ((5 + 2√6)(5 - 2√6)) cot x = (5 - 2√6) / (25 - 24) cot x = 5 - 2√6

549Mathematics
Qamar sold 18 toys for ₹980, thereby making a loss equal to the cost price of 4 toys. What was the cost price of each toy?
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Answer: (D) 70

Explanation

Loss = Total Cost Price - Total Selling Price

Given that the loss on 18 toys equals the cost price of 4 toys: Loss = 18 CP - Total SP 4 CP = 18 CP - 980 18 CP - 4 CP = 980 14 CP = 980 CP = 980 / 14 = ₹70

550Mathematics
If ᵃ⁄₃ = ᵇ⁄₄ = ᶜ⁄₇ , then (a + b + c)/(c) is equal to:
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Answer: (D) 2

Explanation

Let a/3 = b/4 = c/7 = k.

Then, a = 3k, b = 4k, and c = 7k.

Substituting these values into the given expression: (a + b + c) / c = (3k + 4k + 7k) / 7k = 14k / 7k = 2

Answer key

Tap a number to jump to that question.

  1. 501A
  2. 502B
  3. 503D
  4. 504D
  5. 505B
  6. 506C
  7. 507A
  8. 508C
  9. 509B
  10. 510C
  11. 511C
  12. 512A
  13. 513B
  14. 514B
  15. 515A
  16. 516B
  17. 517D
  18. 518B
  19. 519B
  20. 520A
  21. 521A
  22. 522B
  23. 523D
  24. 524B
  25. 525B
  26. 526B
  27. 527C
  28. 528B
  29. 529C
  30. 530C
  31. 531C
  32. 532A
  33. 533C
  34. 534A
  35. 535C
  36. 536C
  37. 537B
  38. 538C
  39. 539B
  40. 540C
  41. 541C
  42. 542C
  43. 543C
  44. 544B
  45. 545D
  46. 546D
  47. 547A
  48. 548D
  49. 549D
  50. 550D

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