IBPS RRB Clerk2016Numerical AbilityPage 3 of 4

IBPS RRB Clerk Prelims 2016 Numerical Ability Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 101–150 of 158, each with the correct answer and a step-by-step explanation.

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101Numerical Ability
(364 + 514 - ?) + 4 = 200
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Answer: (C) 78

Explanation

Simplify the sum inside the parentheses: 364 + 514 = 878

Set up the equation with division: (878 - ?) ÷ 4 = 200 878 - ? = 200 × 4 = 800 ? = 878 - 800 = 78

102Numerical Ability
In the month of March, Hiten spent 45% of his monthly salary on paying bill and rent. Out of the remaining salary, he invested 60% in PPF and the remaining he deposited in bank. He deposited ₹15,400/- in bank. If in April, he got an increment of 10%, what was his salary in April?
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Answer: (B) ₹77,000/-

Explanation

Let March salary be S. Remaining salary after spending 45% on bill and rent = 100% - 45% = 55% of S. Amount deposited in bank = 100% - 60% = 40% of remaining salary = 0.40 × 0.55 × S = 0.22 S.

Given 0.22 S = ₹15,400: S = 15,400 ÷ 0.22 = ₹70,000

In April, salary increased by 10%: April salary = 70,000 × 1.10 = ₹77,000

103Numerical Ability
A person covers a certain distance by travelling at a uniform speed of 120 km/h for 90 min. At what speed will he have to travel in order to cover the same distance in 1 hour 20 min? (in km/h)
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Answer: (A) 135

Explanation

Calculate total distance using Distance = Speed × Time: Time = 90 min = 1.5 hours Distance = 120 km/h × 1.5 h = 180 km

Convert target time to hours: 1 hour 20 min = 1 + 20/60 = 4/3 hours

Calculate required speed = Distance ÷ Time: Speed = 180 ÷ (4/3) = 180 × (3 / 4) = 135 km/h

104Numerical Ability
In Jar A, 120 litre milk was mixed with 24 litre water. 12 litre of this mixture was taken out and 3 litre water was added. If 27 litre of newly formed mixture is taken out, what will be the resultant quantity of water in Jar A? (in litre)
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Answer: (A) 20

Explanation

Initial ratio of milk to water in Jar A is 120 : 24 = 5 : 1. When 12 litres of mixture is removed, milk removed is 12 × (5/6) = 10 litres, and water removed is 12 × (1/6) = 2 litres. Remaining milk = 110 litres, and remaining water = 22 litres. After adding 3 litres of water, new water quantity = 25 litres, and total mixture = 135 litres. The new milk to water ratio is 110 : 25 = 22 : 5. When 27 litres of this new mixture is removed, water removed is 27 × (5/27) = 5 litres. The resultant quantity of water remaining in Jar A = 25 - 5 = 20 litres.

105Numerical Ability
A boat, whose speed is 15 km/h in still water goes 30 km downstream and comes back in a total of 4 hours 30 min. What is the speed of the stream? (in km/h)
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Answer: (C) 5

Explanation

The formula for total time taken in round-trip boat motion is Total Time = Distance / (u + v) + Distance / (u - v), where u is boat speed in still water and v is stream speed. Given distance = 30 km, u = 15 km/h, and total time = 4.5 hours: 30 / (15 + v) + 30 / (15 - v) = 4.5 30 × (15 - v + 15 + v) / (225 - v²) = 4.5 900 / (225 - v²) = 4.5 225 - v² = 200 v² = 25 v = 5 km/h.

106Numerical Ability
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's present age?
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Answer: (A) 16 years

Explanation

Let the ages of Kunal and Sagar six years ago be 6x and 5x respectively. Their present ages are 6x + 6 and 5x + 6. Four years hence, their ages will be 6x + 10 and 5x + 10. According to the given ratio: (6x + 10) / (5x + 10) = 11 / 10 10 × (6x + 10) = 11 × (5x + 10) 60x + 100 = 55x + 110 5x = 10 x = 2 Sagar's present age = 5x + 6 = 5(2) + 6 = 16 years.

107Numerical Ability
A number X is 150 more than a second number, Y. If the sum of X and Y is 5 times Y, what is the value of Y?
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Answer: (A) 50

Explanation

The problem provides two algebraic equations: X = Y + 150 and X + Y = 5Y. Substituting X from the first equation into the second equation yields: (Y + 150) + Y = 5Y 2Y + 150 = 5Y Subtracting 2Y from both sides gives: 3Y = 150 Y = 50.

108Numerical Ability
A square field has an area of 50625 m². Find the cost of fencing around it at ₹15 per metre (in ₹).
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Answer: (C) ₹13,500/-

Explanation

The formula for the area of a square is side², which gives the length of one side as the square root of the area. side = √50625 = 225 metres. The boundary length needing fencing is the perimeter of the square, calculated as: Perimeter = 4 × side = 4 × 225 = 900 metres. Multiplying the perimeter by the fencing rate gives: Total Cost = 900 × ₹15 = ₹13,500.

109Numerical Ability
The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What will be the weight of the new person (in kg)?
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Answer: (C) 85

Explanation

When one person is replaced by a new person, the change in total weight equals the total number of persons multiplied by the increase in average weight. Increase in total weight = Number of persons × Increase in average Increase in total weight = 8 × 2.5 = 20 kg. Weight of new person = Weight of replaced person + Increase in total weight Weight of new person = 65 + 20 = 85 kg.

110Numerical Ability
50% of a number is 18 less than two-third of that number. Find the number.
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Answer: (D) 108

Explanation

Let the unknown number be x. Expressing 50% of the number gives ½x, and two-third of the number gives ⅔x. According to the given condition, ⅔x - ½x = 18. Taking the common denominator of 6, we get (4 - 3)x / 6 = 18, which simplifies to x / 6 = 18. Multiplying both sides by 6 yields x = 108.

111Numerical Ability
A bag contains 20 tickets numbered from 1 to 20. Two tickets are drawn at random. What is the probability that both numbers are prime?
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Answer: (B) ¹⁴⁄₉₅

Explanation

The total number of prime numbers from 1 to 20 is 8 (which are 2, 3, 5, 7, 11, 13, 17, 19). The total number of ways to draw 2 tickets out of 20 is given by 20C2 = (20 × 19) / 2 = 190. The number of favorable ways to draw 2 prime tickets from the 8 prime numbers is 8C2 = (8 × 7) / 2 = 28. Probability = Favorable outcomes / Total outcomes = 28 / 190 = 14 / 95.

112Numerical Ability
Study the table and answer the given questions. Number of people who watched 4 different movies (W, X, Y and Z) during 5 days (from Monday to Friday) of a particular week Days/Movie Monday Tuesday Wednesday Thursday Friday W 28 26 18 24 32 X 30 34 36 30 26 Y 54 60 55 45 32 Z 50 55 58 60 68 What was the respective ratio between the total number of people who watched movie X on Monday and Wednesday together and those who watched movie Z on the same days together?
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Answer: (C) 11 : 18

Explanation

From the table, the number of people who watched movie X on Monday is 30 and on Wednesday is 36, giving a total of 30 + 36 = 66. Similarly, the number of people who watched movie Z on Monday is 50 and on Wednesday is 56, giving a total of 50 + 56 = 106. The ratio between the total number of people who watched movie X on Monday and Wednesday together to those who watched movie Z on the same days together is 66 : 106, which simplifies to 33 : 53.

113Numerical Ability
Study the table and answer the given questions. Number of people who watched 4 different movies (W, X, Y and Z) during 5 days (from Monday to Friday) of a particular week Days/Movie Monday Tuesday Wednesday Thursday Friday W 28 26 18 24 32 X 30 34 36 30 26 Y 54 60 55 45 32 Z 50 55 56 60 68 What was the difference between the total number of people who watched movies X and Z together on Tuesday and those who watched the same together on Thursday?
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Answer: (D) 1

Explanation

To find the required difference, sum the viewers for movies X and Z on each specified day from the table. On Tuesday: Viewers of X = 34, Viewers of Z = 55. Total = 34 + 55 = 89. On Thursday: Viewers of X = 30, Viewers of Z = 60. Total = 30 + 60 = 90. Difference = 90 - 89 = 1.

114Numerical Ability
Study the table and answer the given questions. Number of people who watched 4 different movies (W, X, Y and Z) during 5 days (from Monday to Friday) of a particular week Days/Movie Monday Tuesday Wednesday Thursday Friday W 28 26 18 24 32 X 30 34 36 30 26 Y 54 60 55 45 32 Z 50 55 56 60 68 What was the average number of people who watched movie W on Monday, Wednesday and Friday?
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Answer: (C) 26

Explanation

The total number of people who watched movie W on Monday, Wednesday, and Friday is obtained by summing the respective values from the table: Monday = 28 Wednesday = 18 Friday = 32 Sum = 28 + 18 + 32 = 78. Average viewers = Sum of viewers / Number of days = 78 / 3 = 26.

115Numerical Ability
Study the table and answer the given questions. Number of people who watched 4 different movies (W, X, Y and Z) during 5 days (from Monday to Friday) of a particular week Days/Movie Monday Tuesday Wednesday Thursday Friday W 28 26 18 24 32 X 30 34 36 30 26 Y 54 60 55 45 32 Z 50 55 56 60 68 The number of people who watched movie Y on Wednesday was approximately what percent of those who watched the same movie on Friday?
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Answer: (B) 172

Explanation

From the table, the number of people who watched movie Y on Wednesday is 55, and the number of people who watched movie Y on Friday is 32. To calculate the percentage: Percentage = (Movie Y on Wednesday / Movie Y on Friday) × 100 Percentage = (55 / 32) × 100 = 171.875%. Rounding off to the nearest whole integer yields 172%.

116Numerical Ability
Study the table and answer the given questions. Number of people who watched 4 different movies (W, X, Y and Z) during 5 days (from Monday to Friday) of a particular week Days/Movie Monday Tuesday Wednesday Thursday Friday W 28 26 18 24 32 X 30 34 36 30 26 Y 54 60 55 45 32 Z 50 55 56 60 68 If the number of people who watched movie Z on Saturday was 32 more than those who watched the same movie on Friday, what was the total number of people who watched movie Z on Saturday?
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Answer: (C) 100

Explanation

From the table, the number of people who watched movie Z on Friday is 68. Adding 32 to this value gives 68 + 32 = 100 people who watched movie Z on Saturday.

117Numerical Ability
The compound interest on a certain sum for 2 years at 10% per annum is ₹525/-. The simple interest on the same sum for double the time at half the rate percent per annum is ........
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Answer: (B) ₹500/-

Explanation

The effective compound interest rate for 2 years at 10% per annum is 10 + 10 + (10 × 10)/100 = 21%. Given CI = ₹525, the principal P = 525 / 0.21 = ₹2500. For simple interest, the new time is T = 2 × 2 = 4 years, and the new rate is R = 10 / 2 = 5%. Simple Interest = (P × R × T) / 100 = (2500 × 5 × 4) / 100 = ₹500.

118Numerical Ability
A circle and rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What will be the area of the circle? (in m²)
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Answer: (E) Other than those given as options

Explanation

Perimeter of the rectangle = 2 × (18 + 26) = 88 cm. Since the circle has the same perimeter, 2 × (22/7) × r = 88 cm, which yields a radius r = 14 cm. Area of the circle = πr² = (22/7) × 14² = 616 cm² = 0.0616 m².

119Numerical Ability
What will come in place of question mark (?) in the following number series? 12 13 17 26 42 ?
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Answer: (E) Other than those given as options

Explanation

The differences between consecutive terms in the series 12, 13, 17, 26, 42 are 1, 4, 9, and 16, which correspond to 1², 2², 3², and 4². Adding the next square number, 5² = 25, to 42 gives 42 + 25 = 67.

120Numerical Ability
What will come in place of question mark (?) in the following number series? 1 2 8 48 384 ?
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Answer: (B) 3840

Explanation

The pattern in the series involves multiplying each term by consecutive even numbers: 1 × 2 = 2 2 × 4 = 8 8 × 6 = 48 48 × 8 = 384 384 × 10 = 3840

121Numerical Ability
What will come in place of question mark (?) in the following number series? 157 150 136 115 87 ?
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Answer: (C) 52

Explanation

The pattern is formed by subtracting consecutive multiples of 7 from each term: 157 - 7 = 150 150 - 14 = 136 136 - 21 = 115 115 - 28 = 87 87 - 35 = 52

122Numerical Ability
What will come in place of question mark (?) in the following number series? 1 4 18 44 83 ?
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Answer: (D) 136

Explanation

First-level differences are: 4 - 1 = 3 18 - 4 = 14 44 - 18 = 26 83 - 44 = 39

Second-level differences are: 14 - 3 = 11 26 - 14 = 12 39 - 26 = 13

Continuing the second difference pattern with 14: 39 + 14 = 53 83 + 53 = 136

123Numerical Ability
What will come in place of question mark (?) in the following number series? 8 4 4 6 12 ?
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Answer: (A) 30

Explanation

The multiplier increases by 0.5 at each step: 8 × 0.5 = 4 4 × 1 = 4 4 × 1.5 = 6 6 × 2 = 12 12 × 2.5 = 30

124Numerical Ability
What will come in place of question mark (?) in the following questions? 80.137 × 9 + 2.11 × 139.7 = ?
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Answer: (B) 1016

Explanation

80.137 × 9 = 721.233 2.11 × 139.7 = 294.767 721.233 + 294.767 = 1016

125Numerical Ability
What will come in place of question mark (?) in the following questions? 7802 + 132 - 8963 + 1326 = ? × 33
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Answer: (D) 9

Explanation

7802 + 132 - 8963 + 1326 = ? × 33 7934 - 8963 + 1326 = ? × 33 -1029 + 1326 = ? × 33 297 = ? × 33 ? = 297 ÷ 33 = 9

126Numerical Ability
What will come in place of question mark (?) in the following questions? 21.9 % of 650 = ? + 23.12
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Answer: (E) Other than those given as options

Explanation

21.9% of 650 = (21.9 × 650) / 100 = 142.35 142.35 = ? + 23.12 ? = 142.35 - 23.12 = 119.23

127Numerical Ability
What will come in place of question mark (?) in the following questions? 6666 ÷ 66 ÷ 0.25 = ?
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Answer: (B) 404

Explanation

Applying order of operations from left to right: 6666 ÷ 66 = 101 101 ÷ 0.25 = 101 × 4 = 404

128Numerical Ability
What will come in place of question mark (?) in the following questions? √? + 18 = √(2704)
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Answer: (B) 1156

Explanation

√2704 = 52 √? + 18 = 52 √? = 52 - 18 = 34 ? = 34² = 1156

129Numerical Ability
What will come in place of question mark (?) in the following questions? 217 + 435 - 317 + 5110 = ?
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Answer: (E) Other than those given as options

Explanation

217 + 435 - 317 + 5110 = (217 - 317) + 435 + 5110 = -100 + 435 + 5110 = 335 + 5110 = 5445

130Numerical Ability
What will come in place of question mark (?) in the following questions? 164 × 43 - 6070 = ?
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Answer: (E) 982

Explanation

According to the order of operations (BODMAS), multiplication is performed before subtraction.

First, calculate the product of 164 and 43: 164 × 43 = 164 × (40 + 3) = (164 × 40) + (164 × 3) = 6560 + 492 = 7052

Next, subtract 6070 from the calculated product: 7052 - 6070 = 982

131Numerical Ability
What will come in place of question mark (?) in the following questions? 14.5 % of 740 - ? % of 320 = 87.3
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Answer: (B) 6.25

Explanation

To solve for the missing value, first calculate the value of the given percentage term on the left side: 14.5% of 740 = (14.5 / 100) × 740 = 0.145 × 740 = 107.3

Substitute 107.3 into the equation in place of the first term: 107.3 - ?% of 320 = 87.3

Rearrange the equation to isolate the term containing the question mark: ?% of 320 = 107.3 - 87.3 = 20

Express the percentage as a fraction and solve for ?: (? / 100) × 320 = 20 ? = (20 × 100) / 320 = 2000 / 320 = 6.25

132Numerical Ability
What will come in place of question mark (?) in the following questions? (27)³ × 3⁴ ÷ (81)² = 3^?
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Answer: (B) 5

Explanation

Convert every term to base 3: 27 = 3³, so (27)³ = 3⁹, and 81 = 3⁴, so (81)² = 3⁸. The expression becomes 3⁹ × 3⁴ ÷ 3⁸. Adding the exponents in the numerator gives 3¹³, then dividing by 3⁸ gives 3¹³⁻⁸ = 3⁵. Equating this to 3^? gives ? = 5.

133Numerical Ability
What will come in place of question mark (?) in the following questions? 37.135 of25+125of1.061=√?+894
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Answer: (D) 27889

Explanation

First, evaluate the two products on the left-hand side of the equation: 37.135 × 25 = 928.375 125 × 1.061 = 132.625

Add the two results together to simplify the left-hand side: 928.375 + 132.625 = 1061

Substitute this total back into the original equation: 1061 = √? + 894

Isolate the square root term by subtracting 894 from both sides: √? = 1061 - 894 = 167

Square both sides of the equation to find the value of ?: ? = 167² = (170 - 3)² = 28900 - 1020 + 9 = 27889

134Numerical Ability
What will come in place of question mark (?) in the following questions? 4376+3209-1784+97=3125+?
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Answer: (C) 2773

Explanation

Simplify the numerical expression on the left-hand side of the equation by performing the operations sequentially from left to right: 4376 + 3209 = 7585 7585 - 1784 = 5801 5801 + 97 = 5898

Now set up the equation with the simplified left-hand side: 5898 = 3125 + ?

Isolate the unknown variable ? by subtracting 3125 from 5898: ? = 5898 - 3125 = 2773

135Numerical Ability
What will come in place of question mark (?) in the following questions? √? +14 = √(2601)
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Answer: (B) 1369

Explanation

First, calculate the square root on the right-hand side of the equation: √2601 = 51

Substitute 51 back into the equation: √? + 14 = 51

Subtract 14 from both sides of the equation to isolate the square root term: √? = 51 - 14 = 37

To solve for ?, square both sides of the equation: ? = 37² = (40 - 3)² = 1600 - 240 + 9 = 1369

136Numerical Ability
What will come in place of question mark (?) in the following questions? 85% of420+?%of1080=735
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Answer: (C) 35

Explanation

First, calculate the value of the known percentage term: 85% of 420 = (85 / 100) × 420 = 0.85 × 420 = 357

Substitute this value into the equation: 357 + ?% of 1080 = 735

Subtract 357 from 735 to isolate the unknown percentage expression: ?% of 1080 = 735 - 357 = 378

Solve for the unknown value ?: (? / 100) × 1080 = 378 ? = (378 × 100) / 1080 = 3780 / 108 = 35

137Numerical Ability
What will come in place of question mark (?) in the following questions? 3024 + 54 of19-84=?
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Answer: (D) 980

Explanation

Following the standard order of operations (BODMAS), perform division first, followed by multiplication, and lastly subtraction.

First, divide 3024 by 54: 3024 ÷ 54 = 56

Next, multiply the resulting quotient by 19: 56 × 19 = 56 × (20 - 1) = 1120 - 56 = 1064

Finally, subtract 84 from the product to obtain the final value: 1064 - 84 = 980

138Numerical Ability
What will come in place of question mark (?) in the following questions? 30% of1225-64%of555=?
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Answer: (B) 12.3

Explanation

To evaluate the expression, calculate each percentage term on the left-hand side separately.

First percentage calculation: 30% of 1225 = (30 / 100) × 1225 = 0.30 × 1225 = 367.5

Second percentage calculation: 64% of 555 = (64 / 100) × 555 = 0.64 × 555 = 355.2

Subtract the second calculated value from the first: 367.5 - 355.2 = 12.3

139Numerical Ability
Study the following table and answer the questions given below. Number of tourists who visit different cities by different modes of transport Cities | Car | Train | Bus | Bike | By 'Air' Delhi | 192 | 188 | 172 | 191 | 174 Mumbai | 180 | 166 | 178 | 187 | 182 Chandigarh | 156 | 194 | 163 | 181 | 148 Dehradun | 132 | 185 | 142 | 170 | 148 Mussoorie | 149 | 159 | 155 | 149 | 183 Jaipur | 168 | 163 | 158 | 142 | 174 What the average number of tourists who come by Train?
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Answer: (C) 175.83

Explanation

To calculate the average number of tourists traveling by Train across all cities, first sum the values listed under the Train column for each city: Delhi = 188 Mumbai = 166 Chandigarh = 194 Dehradun = 185 Mussoorie = 159 Jaipur = 163

Total tourists by Train = 188 + 166 + 194 + 185 + 159 + 163 = 1055

Calculate the average by dividing the total number of tourists by the total number of cities (6): Average = 1055 / 6 = 175.833... ≈ 175.83

140Numerical Ability
Study the following table and answer the questions given below. Number of tourists who visit different cities by different modes of transport Cities | Car | Train | Bus | Bike | By 'Air' Delhi | 192 | 188 | 172 | 191 | 174 Mumbai | 180 | 166 | 178 | 187 | 182 Chandigarh | 156 | 194 | 163 | 181 | 148 Dehradun | 132 | 185 | 142 | 170 | 148 Mussoorie | 149 | 159 | 155 | 149 | 183 Jaipur | 168 | 163 | 158 | 142 | 174 What is the difference between the total number of tourists who went to Mumbai and that to Mussoorie by all the vehicles?
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Answer: (B) 98

Explanation

Total tourists visiting Mumbai across all modes of transport = 180 + 166 + 178 + 187 + 182 = 893. Total tourists visiting Mussoorie across all modes of transport = 149 + 159 + 155 + 149 + 183 = 795. Required difference = 893 - 795 = 98.

141Numerical Ability
Study the following table and answer the questions given below. Number of tourists who visit different cities by different modes of transport Cities | Car | Train | Bus | Bike | By 'Air' Delhi | 192 | 188 | 172 | 191 | 174 Mumbai | 180 | 166 | 178 | 187 | 182 Chandigarh | 156 | 194 | 163 | 181 | 148 Dehradun | 132 | 185 | 142 | 170 | 148 Mussoorie | 149 | 159 | 155 | 149 | 183 Jaipur | 168 | 163 | 158 | 142 | 174 What is the percentage of tourists who went to Dehradun by Train compared to the number of tourists who went to Chandigarh by Air?
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Answer: (A) 125

Explanation

Number of tourists visiting Dehradun by train = 185. Number of tourists visiting Chandigarh by air = 148. Percentage = (185 / 148) × 100 = 1.25 × 100 = 125%.

142Numerical Ability
Study the following table and answer the questions given below. Number of tourists who visit different cities by different modes of transport Cities | Car | Train | Bus | Bike | By 'Air' Delhi | 192 | 188 | 172 | 191 | 174 Mumbai | 180 | 166 | 178 | 187 | 182 Chandigarh | 156 | 194 | 163 | 181 | 148 Dehradun | 132 | 185 | 142 | 170 | 148 Mussoorie | 149 | 159 | 155 | 149 | 183 Jaipur | 168 | 163 | 158 | 142 | 174 What is the difference between the average number of tourists who went by Air to the average number of tourists who went by Bus?
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Answer: (C) 6.83

Explanation

Total tourists traveling by air = 174 + 182 + 148 + 148 + 183 + 174 = 1009. Average tourists by air = 1009 / 6 = 168.17. Total tourists traveling by bus = 172 + 178 + 163 + 142 + 155 + 158 = 968. Average tourists by bus = 968 / 6 = 161.33. Difference between the two averages = (1009 - 968) / 6 = 41 / 6 ≈ 6.83.

143Numerical Ability
Study the following table and answer the questions given below. Number of tourists who visit different cities by different modes of transport Cities | Car | Train | Bus | Bike | By 'Air' Delhi | 192 | 188 | 172 | 191 | 174 Mumbai | 180 | 166 | 178 | 187 | 182 Chandigarh | 156 | 194 | 163 | 181 | 148 Dehradun | 132 | 185 | 142 | 170 | 148 Mussoorie | 149 | 159 | 155 | 149 | 183 Jaipur | 168 | 163 | 158 | 142 | 174 What is the ratio of the number of tourists to Delhi who went by Car to that to Mumbai who went by Air?
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Answer: (C) 96:91

Explanation

Number of tourists traveling to Delhi by car = 192. Number of tourists traveling to Mumbai by air = 182. Required ratio = 192 : 182 = (192 / 2) : (182 / 2) = 96 : 91.

144Numerical Ability
If the wheel of a bicycle makes 560 revolutions in travelling 1.1 km, what is its radius? (use π = ²²⁄₇ )
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Answer: (A) 31.25 cm

Explanation

Distance covered = 1.1 km = 110000 cm. Distance covered in N revolutions = N × 2 × π × r. 560 × 2 × (22 / 7) × r = 110000 3520 × r = 110000 r = 110000 / 3520 = 31.25 cm.

145Numerical Ability
Elena's age after 15 years will be 5 times her age 5 years back. What is her present age?
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Answer: (A) 10 years

Explanation

Let Elena's present age be x years. According to the given condition, x + 15 = 5 × (x - 5). Expanding and solving for x: x + 15 = 5x - 25 4x = 40 x = 10 years.

146Numerical Ability
A man purchased a cow for 3000 and sold it the same day for 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of
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Answer: (B) 0%

Explanation

Present worth (PW) of ₹3600 due 2 years hence at 10% per annum simple interest is given by PW = S / (1 + (r × t) / 100). PW = 3600 / (1 + (10 × 2) / 100) = 3600 / 1.2 = ₹3000. Since the purchase price is ₹3000 and the present worth of the selling price is ₹3000, the effective gain is 0%.

147Numerical Ability
A man takes 3 hours 45 minutes to row a boat 15 km downstream a river and 2 hours 30 minutes to cover a distance of 5 km upstream. Find the speed of the stream.
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Answer: (A) 1 kmph

Explanation

Downstream speed = Distance / Time = 15 km / 3.75 hours = 4 km/h. Upstream speed = Distance / Time = 5 km / 2.5 hours = 2 km/h. Speed of the stream = (Downstream speed - Upstream speed) / 2 = (4 - 2) / 2 = 1 km/h.

148Numerical Ability
A cistern 6 m-long and 4-m wide contains water up to a height of 1 m 25 cm. Find the total area of the wet surface of the cistern.
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Answer: (B) 49 sqm

Explanation

Area of wet surface = Base area + 2 × Height × (Length + Width) Length = 6 m, Width = 4 m, Height = 1.25 m. Base area = 6 × 4 = 24 m². Area of 4 wet side walls = 2 × 1.25 × (6 + 4) = 2.5 × 10 = 25 m². Total wet surface area = 24 + 25 = 49 m².

149Numerical Ability
In terms of percentage profit, which of following is the best transaction?
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Answer: (D) CP 60, Profit 29

Explanation

Profit percentage = (Profit / Cost Price) × 100. For a cost price of 60 and profit of 29, the profit percentage is (29 / 60) × 100 = 48.33%, which is higher than the percentage profit of any other listed transaction.

150Numerical Ability
The milk and water in two vessels A and B are in the ratio of 4:3 and 2:3 respectively. In what ratio should the liquids in both the vessels be mixed to obtain a new mixture in vessel C consisting of half milk and half water?
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Answer: (B) 7:5

Explanation

Milk proportion in Vessel A = 4/7 Milk proportion in Vessel B = 2/5 Desired milk proportion in Mixture C = 1/2

By the rule of alligation: Ratio of Vessel A to Vessel B = (1/2 - 2/5) : (4/7 - 1/2) = (1/10) : (1/14) = 14 : 10 = 7 : 5.

Answer key

Tap a number to jump to that question.

  1. 101C
  2. 102B
  3. 103A
  4. 104A
  5. 105C
  6. 106A
  7. 107A
  8. 108C
  9. 109C
  10. 110D
  11. 111B
  12. 112C
  13. 113D
  14. 114C
  15. 115B
  16. 116C
  17. 117B
  18. 118E
  19. 119E
  20. 120B
  21. 121C
  22. 122D
  23. 123A
  24. 124B
  25. 125D
  26. 126E
  27. 127B
  28. 128B
  29. 129E
  30. 130E
  31. 131B
  32. 132B
  33. 133D
  34. 134C
  35. 135B
  36. 136C
  37. 137D
  38. 138B
  39. 139C
  40. 140B
  41. 141A
  42. 142C
  43. 143C
  44. 144A
  45. 145A
  46. 146B
  47. 147A
  48. 148B
  49. 149D
  50. 150B

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