Population of a village A increased by 5% from 2009 to 2010 and by 20% from 2010 to 2011. Population of the village in 2011 was what per cent more than that in 2009?
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Answer: (A) 26
Explanation
Using the successive percentage change formula:
Net percentage increase = a + b + (a × b) / 100
Substituting a = 5 and b = 20:
Net increase = 5 + 20 + (5 × 20) / 100 = 25 + 1 = 26%
2Numerical Ability
Jar A has 140 litre of mixture of milk and water, in which water is 10%. 30 litre of this mixture was taken out and replaced with 'x' litre milk. If the resultant quantity of milk in the mixture was 112 litre, what is the value of x?
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Answer: (C) 13
Explanation
In 140 litres of mixture, milk constitutes 90%, which is 126 litres. When 30 litres of mixture is removed, the milk removed is 90% of 30 = 27 litres.
Remaining milk in the jar = 126 - 27 = 99 litres.
Adding x litres of milk makes the total milk 112 litres:
99 + x = 112
x = 13 litres
3Numerical Ability
75% of 160 is equal to 40% of y% of 600, What is the value of y?
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Answer: (A) 50
Explanation
75% of 160 = (3 / 4) × 160 = 120
40% of y% of 600 = (40 / 100) × (y / 100) × 600 = 2.4y
2.4y = 120
y = 120 / 2.4 = 50
4Numerical Ability
The side of a square whose area is 256 square metre is equal to the breadth of a rectangle. If the difference between the length and breadth of a rectangle is 2 metre, what is its area? (in square metre)
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Answer: (A) 288
Explanation
Side of the square = √256 = 16 metres.
Breadth of the rectangle (b) = 16 metres.
Since the difference between length and breadth is 2 metres, length (l) = 16 + 2 = 18 metres.
Area of the rectangle = l × b = 18 × 16 = 288 square metres.
5Numerical Ability
Naman invests 50% of his monthly salary in mutual funds. He spends the rest of his salary on rent and buying groceries in the ratio of 3 : 2 respectively. If he spends Rs. 18,000 on groceries, how much does he invest in mutual funds?
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Answer: (A) Rs. 45,000
Explanation
Let the monthly salary be S.
Mutual fund investment = 50% of S = 0.50S.
Remaining salary = 50% of S = 0.50S.
The ratio of expenditure on rent and groceries is 3 : 2, so grocery expenditure = (2 / 5) × 0.50S = 0.20S.
0.20S = 18,000
S = 90,000
Mutual fund investment = 0.50 × 90,000 = Rs. 45,000.
6Numerical Ability
A sum of Rs. 900, when invested in a scheme offering compound interest (compounded annually) for 2 years amounts to Rs. 1296. What is the rate of interest of the given scheme (in per cent per annum)?
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Answer: (D) 20
Explanation
Amount A = P(1 + R / 100)²
1296 = 900(1 + R / 100)²
(1 + R / 100)² = 1296 / 900 = 1.44
1 + R / 100 = √1.44 = 1.2
R / 100 = 0.2
R = 20% per annum
7Numerical Ability
⅛ of a number, x is 3 more than ¹⁄₁₂ of a second number, y. If y is 120% of x, what is the value of x?
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Answer: (B) 120
Explanation
Given equation: x / 8 = y / 12 + 3
Also, y = 120% of x = 1.2x = 6x / 5
Substitute y in the equation:
x / 8 = (6x / 5) / 12 + 3
x / 8 = x / 10 + 3
x / 8 - x / 10 = 3
(5x - 4x) / 40 = 3
x / 40 = 3
x = 120
8Numerical Ability
The cost price of each of the articles A and B is Rs. 270. If article A was sold at a profit of 30% and article B was sold at a profit of 40%, what was the overall profit earned after selling both the articles?
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Answer: (B) Rs. 189
Explanation
Profit on article A = 30% of 270 = Rs. 81
Profit on article B = 40% of 270 = Rs. 108
Total profit = 81 + 108 = Rs. 189
9Numerical Ability
Study the table and answer the given questions.
This table shows the number of people who purchased 4 different magazines (P, Q, R and S) during 5 months (from January to May)
Month Magazine | January | February | March | April | May
P | 55 | 62 | 56 | 44 | 65
Q | 60 | 60 | 64 | 80 | 68
R | 54 | 75 | 42 | 75 | 42
S | 57 | 28 | 45 | 57 | 46
Note: Every person purchased one magazine only.
What was the difference between the total number of people who purchased magazines P and R together in January and those who purchased the same magazines together in March?
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Answer: (A) 11
Explanation
Total purchases of magazines P and R in January = 55 + 54 = 109.
Total purchases of magazines P and R in March = 56 + 42 = 98.
Difference = 109 - 98 = 11.
10Numerical Ability
Study the table and answer the given questions.
This table shows the number of people who purchased 4 different magazines (P, Q, R and S) during 5 months (from January to May)
Month Magazine | January | February | March | April | May
P | 55 | 62 | 56 | 44 | 65
Q | 60 | 60 | 64 | 80 | 68
R | 54 | 75 | 42 | 75 | 42
S | 57 | 28 | 45 | 57 | 46
Note: Every person purchased one magazine only.
Out of the number of people who purchased magazine P in the month of May, 39 were females. What was the respective ratio between the number of males and females who purchased magazine P in the month of May?
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Answer: (E) 2 : 3
Explanation
Total people who purchased magazine P in May = 65.
Number of females = 39.
Number of males = 65 - 39 = 26.
Ratio of males to females = 26 : 39 = 2 : 3.
11Numerical Ability
Study the table and answer the given questions.
This table shows the number of people who purchased 4 different magazines (P, Q, R and S) during 5 months (from January to May)
Month Magazine | January | February | March | April | May
P | 55 | 62 | 56 | 44 | 65
Q | 60 | 60 | 64 | 80 | 68
R | 54 | 75 | 42 | 75 | 42
S | 57 | 28 | 45 | 57 | 46
Note: Every person purchased one magazine only.
What was the average number of people who purchased magazine S in the months of January, March and April?
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Answer: (A) 53
Explanation
To find the average number of people who purchased magazine S in January, March, and April, sum the values for these months and divide by 3:
Average = (57 + 45 + 57) / 3 = 159 / 3 = 53
12Numerical Ability
Study the table and answer the given questions.
This table shows the number of people who purchased 4 different magazines (P, Q, R and S) during 5 months (from January to May)
Month Magazine | January | February | March | April | May
P | 55 | 62 | 56 | 44 | 65
Q | 60 | 60 | 64 | 80 | 68
R | 54 | 75 | 42 | 75 | 42
S | 57 | 28 | 45 | 57 | 46
Note: Every person purchased one magazine only.
What was the respective ratio between the total number of people who purchased magazine Q in the months of February and April together and those who purchased magazine R in the same months together?
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Answer: (A) 14 : 15
Explanation
Sum the number of purchasers for magazine Q in February and April: 60 + 80 = 140. Next, sum the number of purchasers for magazine R in February and April: 75 + 75 = 150. The required ratio is 140 : 150, which simplifies to 14 : 15.
13Numerical Ability
Study the table and answer the given questions.
This table shows the number of people who purchased 4 different magazines (P, Q, R and S) during 5 months (from January to May)
Month Magazine | January | February | March | April | May
P | 55 | 62 | 56 | 44 | 65
Q | 60 | 60 | 64 | 80 | 68
R | 54 | 75 | 42 | 75 | 42
S | 57 | 28 | 45 | 57 | 46
Note: Every person purchased one magazine only.
The number of people who purchased magazine R in the month of March was approximately what percent of those who purchased the same magazine in the month of January?
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Answer: (B) 78
Explanation
The percentage is given by dividing the number of purchasers of magazine R in March by the number of purchasers of magazine R in January, then multiplying by 100:
What will come in place of question mark (?) in the given questions?
6840 - 1820 = ? + 3750
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Answer: (E) 1270
Explanation
First, perform the subtraction on the left side of the equation:
6840 - 1820 = 5020
Then, solve for the unknown value by subtracting 3750 from 5020:
? = 5020 - 3750 = 1270
15Numerical Ability
What will come in place of question mark (?) in the given questions?
5½ + 3¾ = 12 - ?
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Answer: (D) 2¾
Explanation
Convert the mixed numbers into improper fractions and simplify:
5½ + 3¾ = 11/2 + 15/4 = 22/4 + 15/4 = 37/4
To find the missing value, subtract 37/4 from 12:
? = 12 - 37/4 = 48/4 - 37/4 = 11/4 = 2¾
16Numerical Ability
What will come in place of question mark (?) in the given questions?
62 ÷ 12 × 4 = ?
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Answer: (D) 20 ; f⅔
Explanation
Following BODMAS rules, division and multiplication are evaluated from left to right:
62 ÷ 12 × 4 = (62 / 12) × 4
= (31 / 6) × 4
= 124 / 6
= 62 / 3
= 20 ⅔
17Numerical Ability
What will come in place of question mark (?) in the given questions?
1580 + ? = 45 × 40
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Answer: (A) 220
Explanation
First, calculate the product on the right side of the equation:
45 × 40 = 1800
Then, isolate the missing value by subtracting 1580 from 1800:
? = 1800 - 1580 = 220
18Numerical Ability
What will come in place of question mark (?) in the given questions?
(1330 + 1220) ÷ ? = 212.5
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Answer: (B) 12
Explanation
First, evaluate the sum inside the parentheses:
1330 + 1220 = 2550
Next, solve for the unknown divisor:
? = 2550 / 212.5 = 12
19Numerical Ability
What will come in place of question mark (?) in the given questions?
60% of (460 - 340) = ?
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Answer: (A) 72
Explanation
First, calculate the difference inside the parentheses:
460 - 340 = 120
Then, calculate 60% of 120:
(60 / 100) × 120 = 0.6 × 120 = 72
20Numerical Ability
What will come in place of question mark (?) in the given questions?
1200 ÷ ⁴⁄₃ - 800 × 1.1 = ?
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Answer: (C) 20
Explanation
Evaluating the terms separately according to BODMAS rules:
First term: 1200 ÷ (4 / 3) = 1200 × (3 / 4) = 900
Second term: 800 × 1.1 = 880
Subtracting the second term from the first:
900 - 880 = 20
21Numerical Ability
What will come in place of question mark (?) in the given questions?
625 × ¹⁄₂₅ × 4 = 20 × ?
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Answer: (A) 5
Explanation
Evaluating the left-hand side of the equation:
625 × (1 / 25) × 4 = 25 × 4 = 100
Setting up the equation with the missing value:
100 = 20 × ?
? = 100 / 20 = 5
22Numerical Ability
What will come in place of question mark (?) in the given questions?
⅝ of ⁴⁄₁₅ of 372 = ?
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Answer: (D) 62
Explanation
To find the required value, evaluate the given fraction of fraction expression:
(5 / 8) × (4 / 15) × 372
Simplifying the product of the fractions first:
(5 × 4) / (8 × 15) = 20 / 120 = 1 / 6
Now multiply by 372:
(1 / 6) × 372 = 62
23Numerical Ability
What will come in place of question mark (?) in the given questions?
20% of 220 × ? = 35.2
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Answer: (A) 0.8
Explanation
First calculate 20% of 220:
(20 / 100) × 220 = 0.20 × 220 = 44
Substitute this into the original equation:
44 × ? = 35.2
Solving for the question mark:
? = 35.2 / 44 = 0.8
24Numerical Ability
What will come in place of question mark (?) in the given questions?
8.7 × 8.7 - 3.4 × 8.7 + 1.7 × 1.7 = ?
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Answer: (A) 49
Explanation
Rewrite the given expression to identify the standard algebraic formula:
8.7 × 8.7 - 3.4 × 8.7 + 1.7 × 1.7
= (8.7)² - 2 × (1.7) × (8.7) + (1.7)²
This fits the algebraic identity a² - 2ab + b² = (a - b)², where a = 8.7 and b = 1.7.
Substituting these values into the formula:
(8.7 - 1.7)² = (7)² = 49
25Numerical Ability
What will come in place of question mark (?) in the given questions?
189.25 + 329.95 - 444.2 = ?
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Answer: (C) 75
Explanation
Perform the arithmetic operations in sequence from left to right:
First, add the positive terms:
189.25 + 329.95 = 519.20
Next, subtract 444.2 from the result:
519.20 - 444.20 = 75
26Numerical Ability
What will come in place of question mark (?) in the given questions?
278 - 152 ÷ 8 = ?
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Answer: (A) 259
Explanation
According to the BODMAS rule, division must be performed before subtraction.
First, divide 152 by 8:
152 ÷ 8 = 19
Next, subtract 19 from 278:
278 - 19 = 259
27Numerical Ability
What will come in place of question mark (?) in the given questions?
3.6 - 0.8 × 1.5 = 5 - ?
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Answer: (B) 2.6
Explanation
According to the BODMAS rule, perform the multiplication step on the left-hand side first:
0.8 × 1.5 = 1.2
Subtract this from 3.6 to simplify the left-hand side:
3.6 - 1.2 = 2.4
Now solve the resulting equation:
2.4 = 5 - ?
? = 5 - 2.4 = 2.6
28Numerical Ability
What will come in place of the question mark (?) in the following number series?
5 6 24 58 107 ?
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Answer: (C) 170
Explanation
Analyze the differences between consecutive terms in the series:
6 - 5 = 1
24 - 6 = 18
58 - 24 = 34
107 - 58 = 49
Now analyze the second differences between these consecutive first differences:
18 - 1 = 17
34 - 18 = 16
49 - 34 = 15
The second differences decrease by 1 at each step (17, 16, 15, ...). Thus, the next second difference is 14.
The next first difference is:
49 + 14 = 63
Adding this difference to the last term of the series gives:
107 + 63 = 170
29Numerical Ability
What will come in place of the question mark (?) in the following number series?
416 ? 104 52 26 13
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Answer: (A) 208
Explanation
Analyze the relationship between consecutive terms in the given series starting from right to left:
13 × 2 = 26
26 × 2 = 52
52 × 2 = 104
Moving from left to right, each term is obtained by dividing the preceding term by 2:
104 ÷ 2 = 52
52 ÷ 2 = 26
26 ÷ 2 = 13
Applying this pattern to the start of the series:
? = 416 ÷ 2 = 208
208 ÷ 2 = 104
30Numerical Ability
What will come in place of the question mark (?) in the following number series?
452 440 416 368 272 ?
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Answer: (E) 80
Explanation
Analyze the differences between consecutive terms in the decreasing series:
452 - 440 = 12
440 - 416 = 24
416 - 368 = 48
368 - 272 = 96
The differences form a geometric progression where each term is twice the previous difference (12, 24, 48, 96).
The next difference in the sequence is:
96 × 2 = 192
Subtracting this difference from the previous term yields:
272 - 192 = 80
31Numerical Ability
What will come in place of the question mark (?) in the following number series?
13 13 26 78 312 ?
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Answer: (E) 1560
Explanation
The logic of the number series is multiplication by successive natural numbers:
13 × 1 = 13
13 × 2 = 26
26 × 3 = 78
78 × 4 = 312
312 × 5 = 1560
32Numerical Ability
What will come in place of the question mark (?) in the following number series?
8 17 42 91 172 ?
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Answer: (E) 293
Explanation
The differences between consecutive terms follow the pattern of squares of consecutive odd numbers:
17 - 8 = 9 = 3²
42 - 17 = 25 = 5²
91 - 42 = 49 = 7²
172 - 91 = 81 = 9²
The next difference is 11² = 121.
Required term = 172 + 121 = 293
33Numerical Ability
What will come in place of the question mark (?) in the following number series?
7 8 16 43 107 ?
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Answer: (B) 232
Explanation
The differences between consecutive terms are perfect cubes:
8 - 7 = 1 = 1³
16 - 8 = 8 = 2³
43 - 16 = 27 = 3³
107 - 43 = 64 = 4³
The next difference is 5³ = 125.
Required term = 107 + 125 = 232
34Numerical Ability
A person travels 150 km in 1 hour 12 minutes. What distance will he be able to cover in 108 minutes (in km)?
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Answer: (A) 225
Explanation
Total time taken initially is 1 hour 12 minutes, which equals 72 minutes.
Since speed is constant, distance is directly proportional to time:
Distance = (150 / 72) × 108 = 150 × 1.5 = 225 km
35Numerical Ability
Simple interest on Rs. 'x' at the rate of 14 per cent per annum for 2 years is Rs. 364. What is the interest on Rs. (x + 100) at the same rate of interest for 3 years?
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Answer: (E) Rs. 588
Explanation
Using the simple interest formula SI = (P × R × T) / 100:
364 = (x × 14 × 2) / 100
364 = 28x / 100
x = (364 × 100) / 28 = 1300
The new principal is x + 100 = 1300 + 100 = 1400.
Interest on Rs. 1400 at 14% per annum for 3 years:
SI = (1400 × 14 × 3) / 100 = 14 × 42 = 588
36Numerical Ability
A can complete a piece of work in 54 days and B can complete the same piece of work in 45 days. If they work together, what fraction of the same work they can complete in 9 days?
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Answer: (D) ¹¹⁄₃₀
Explanation
Work done by A in 1 day = 1/54
Work done by B in 1 day = 1/45
Combined 1-day work = 1/54 + 1/45 = (5 + 6) / 270 = 11/270
Fraction of work completed in 9 days = 9 × (11/270) = 11/30
37Numerical Ability
The ratio of present ages of A and B is 5 : 6 respectively. A is 7 years younger than B. What would be the respective ratio of their ages (of A and B) 14 years hence?
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Answer: (C) 7 : 8
Explanation
Let the present ages of A and B be 5x and 6x.
Given that A is 7 years younger than B:
6x - 5x = 7
x = 7
Present age of A = 5 × 7 = 35 years
Present age of B = 6 × 7 = 42 years
After 14 years:
A's age = 35 + 14 = 49 years
B's age = 42 + 14 = 56 years
Respective ratio = 49 : 56 = 7 : 8
38Numerical Ability
The area of circle A is 616 cm² . If the radius of circle B is 14 cm more than that of circle A, how much does the radius of circle B measure? (in cm.)
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Answer: (C) 28
Explanation
Area of circle A = π × (r_A)² = 616
(22 / 7) × (r_A)² = 616
(r_A)² = (616 × 7) / 22 = 196
r_A = 14 cm
Radius of circle B = r_A + 14 = 14 + 14 = 28 cm
39Numerical Ability
A boat takes 4 hours 30 minutes to travel 90 km upstream. If the speed of the current is 6 km / h , what is the speed of the boat downstream? (in km / h .)
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Answer: (A) 32
Explanation
Upstream time = 4 hours 30 minutes = 4.5 hours
Upstream speed = Distance / Time = 90 / 4.5 = 20 km/h
Let boat speed in still water be b km/h and current speed be v = 6 km/h.
Upstream speed = b - v = 20
b - 6 = 20
b = 26 km/h
Downstream speed = b + v = 26 + 6 = 32 km/h
40Numerical Ability
The average score of 54 children in a group was 72. Six children of average score 76 joined the group. What was the new average score of the group?
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Answer: (D) 72.4
Explanation
Initial total score of 54 children = 54 × 72 = 3888
Total score of 6 new children = 6 × 76 = 456
New total score = 3888 + 456 = 4344
Total number of children = 54 + 6 = 60
New average score = 4344 / 60 = 72.4
Alternatively, using deviations:
Extra score brought by 6 children = 6 × (76 - 72) = 24
Increase in average = 24 / 60 = 0.4
New average = 72 + 0.4 = 72.4
41Numerical Ability
A container contains mixture of milk and water in which milk is 80%. 75% of mixture is taken out and 10 water is added, now the concentration of milk in the mixture is 60%. Find the quantity of milk initially.
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Answer: (B) 96
Explanation
Let the initial total mixture be M. Initial milk quantity is 0.80 M.
When 75% of the mixture is removed, 25% remains.
Milk remaining = 0.80 × 0.25 M = 0.20 M.
Adding 10 units of water gives total volume = 0.25 M + 10.
The new milk concentration is 60%:
0.20 M / (0.25 M + 10) = 0.60
0.20 M = 0.15 M + 6
0.05 M = 6
M = 120
Initial milk quantity = 0.80 × 120 = 96.
42Numerical Ability
The ratio of investment of A, B, C and D in a business is 2:3:5:7. A and B started the business initially, while C and D joined the business after 4 months. After 1 year the profit of C is equal to the average of the profit of A and D. i.e. 12000 Rs. Then find the Share of B.
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Answer: (B) 10800 Rs
Explanation
Ratio of investments is A : B : C : D = 2 : 3 : 5 : 7.
A and B invested for 12 months, while C and D invested for 8 months.
Effective profit sharing ratio = (2 × 12) : (3 × 12) : (5 × 8) : (7 × 8) = 24 : 36 : 40 : 56 = 6 : 9 : 10 : 14.
Let total profit parts be x. C's share corresponds to 10 parts, which equals Rs. 12000.
1 part = 12000 / 10 = Rs. 1200.
Share of B = 9 parts = 9 × 1200 = Rs. 10800.
43Numerical Ability
The length of a rectangle is increased by 49.99%. While its breadth is decreased by 10.01%. Then find the percentage change in area.
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Answer: (A) 35% increase
Explanation
Percentage change in area = a + b + (a × b) / 100
Substituting a = +49.99% and b = -10.01%:
Net change = 49.99 - 10.01 - (49.99 × 10.01) / 100
= 39.98 - 5.004 = 34.976%
Rounding to the nearest whole percentage gives a 35% increase.
44Numerical Ability
When Rs 6000 invested in a scheme for 6 years at x % simple interest per annum gives Rs 720 more interest as compared to the interest earned when the same principal is invested in another scheme for 4 years at (x + 2)% simple interest per annum. Find x
A shopkeeper bought 150 calculators at the rate of Rs. 250 per calculator. He spent Rs. 2500 on transportation and packing. If the marked price of calculator is Rs. 320 per calculator and the shopkeeper gives a discount of 5% on the marked price then what will be the percentage profit gained by the shopkeeper?
The average weight of 3 men A, B and C is 84kg. Another man D joins the group and the average now becomes 80kg. If another man E, whose weight is 3kg more than that of D, replaces A, then average weight of B, C, D and E becomes 79kg, the weight of A is:
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Answer: (E) None of these
Explanation
Sum of weights of A, B, C = 3 × 84 = 252 kg.
Sum of weights of A, B, C, D = 4 × 80 = 320 kg.
Weight of D = 320 - 252 = 68 kg.
Weight of E = 68 + 3 = 71 kg.
Sum of weights of B, C, D, E = 4 × 79 = 316 kg.
Replacing (B + C + D) with (320 - A):
(320 - A) + 71 = 316
391 - A = 316
A = 75 kg.
47Numerical Ability
A retailer purchases a sewing machine at a discount of 15% and sells it for Rs. 1955. In the bargain he makes a profit of 15%. How much is the discount which he got from the whole sale?
The wheat sold by a shopkeeper contained 10% low quality wheat. What quantity of good quality wheat should be added to 150kg of wheat so that percentage of low quality wheat becomes 5% ?
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Answer: (B) 150kg
Explanation
Initial weight of low quality wheat in 150 kg = 10% of 150 = 15 kg.
Let x kg of good quality wheat be added.
Total weight of mixture = 150 + x.
Percentage of low quality wheat = [15 / (150 + x)] × 100 = 5%
15 / (150 + x) = 1 / 20
300 = 150 + x
x = 150 kg.
49Numerical Ability
An urn contains 6 red, 4 blue and 2 green balls. 3 balls are picked at random, find the probability that all the 3 balls are of same colour.
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Answer: (E) None of these
Explanation
Total balls = 6 + 4 + 2 = 12.
Total sample space outcomes = 12C3 = (12 × 11 × 10) / (3 × 2 × 1) = 220.
Favorable outcomes for 3 balls of same color:
3 red balls = 6C3 = 20
3 blue balls = 4C3 = 4
3 green balls = 2C3 = 0
Total favorable outcomes = 20 + 4 = 24.
Probability = 24 / 220 = 6 / 55.
50Numerical Ability
2 candles of the same height are lighted at the same time. The first is to be consumed in 5 hours and seconds in 4 hours. Assuming that they burn at constant rates, in how many hours their height will be in ratio 3 : 2 ?
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Answer: (A) 20 / 7
Explanation
Let the initial height of each candle be 1 unit.
Burning rate of first candle = 1/5 per hour.
Burning rate of second candle = 1/4 per hour.
After t hours, height of first candle = 1 - t/5 = (5 - t)/5.
Height of second candle = 1 - t/4 = (4 - t)/4.
Equating the ratio of heights to 3/2:
[(5 - t)/5] / [(4 - t)/4] = 3 / 2
[4(5 - t)] / [5(4 - t)] = 3 / 2
8(5 - t) = 15(4 - t)
40 - 8t = 60 - 15t
7t = 20
t = 20 / 7 hours.