The sum of the present ages of a father and son is 50 years. If after 5 years, the father's age will be 5 times the age of the son, then what was the father's age 5 years ago?
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Answer: (A) 40
Explanation
Correct Answer: A
Let F and S be the present ages of the father and the son respectively.
The sum of their present ages is:
F + S = 50
In 5 years, their ages will be F + 5 and S + 5. According to the given condition:
F + 5 = 5(S + 5)
F + 5 = 5S + 25
F - 5S = 20
Subtracting the second equation from the first gives:
6S = 30
S = 5
Substituting S = 5 into the first equation:
F + 5 = 50
F = 45
Thus, the father's present age is 45 years. Five years ago, the father's age was:
45 - 5 = 40 years.
502Quantitative Aptitude
The cost price of a fan is ₹4,400. A merchant wants to make a 24% profit by selling it. At the time of sale, merchant declares a discount of 12% on the marked price. Find the marked price.
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Answer: (D) 6,200
Explanation
The relationship between Cost Price (CP), Marked Price (MP), Profit percentage (P), and Discount percentage (D) is given by the standard formula:
MP / CP = (100 + P) / (100 - D)
Substituting the given values (CP = 4400, P = 24, and D = 12) into the formula:
MP / 4400 = (100 + 24) / (100 - 12)
MP / 4400 = 124 / 88
MP = 4400 × 124 / 88
MP = 50 × 124
MP = 6200
503Quantitative Aptitude
The price of a product increases by 10% in the first year and 20% in the second year. What is the overall percentage increase in the price of the product over the two years?
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Answer: (B) 32%
Explanation
The net percentage change for two successive percentage increases of a% and b% is given by the formula:
Net Increase = a + b + (a × b)/100
Given:
First year increase, a = 10%
Second year increase, b = 20%
Substituting these values into the formula:
Net Increase = 10 + 20 + (10 × 20)/100
Net Increase = 30 + 200/100
Net Increase = 30 + 2
Net Increase = 32%
Alternatively, if the initial price is assumed to be 100:
Price after the first year = 100 × (1 + 10/100) = 110
Price after the second year = 110 × (1 + 20/100) = 110 × 1.2 = 132
Overall increase = 132 - 100 = 32%
504Quantitative Aptitude
Find the whole surface area of a cuboid having a length of 19 cm, breadth of 9 cm and height of 4.5 cm.
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Answer: (C) 594 cm²
Explanation
The total surface area of a cuboid is calculated using the formula:
Total Surface Area = 2 × (lb + bh + hl)
where l is the length, b is the breadth, and h is the height.
Given values:
l = 19 cm
b = 9 cm
h = 4.5 cm
Substituting these values into the formula:
Total Surface Area = 2 × (19 × 9 + 9 × 4.5 + 4.5 × 19)
Total Surface Area = 2 × (171 + 40.5 + 85.5)
Total Surface Area = 2 × 297
Total Surface Area = 594 cm²
505Quantitative Aptitude
Δ ABC ∼ Δ EDF and area(ABC): area(EDF) = 1 : 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to:
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Answer: (D) 16 cm
Explanation
For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides.
Since ΔABC is similar to ΔEDF, the corresponding side to DF is BC. The relationship between their areas and these sides is given by:
area(ΔABC) / area(ΔEDF) = (BC / DF)²
Substituting the given values:
1 / 4 = (8 / DF)²
Taking the square root on both sides:
1 / 2 = 8 / DF
DF = 8 × 2 = 16 cm
506Quantitative Aptitude
Simplify (sin 60° - cos 60°)/(sin 60° + cos 60°)
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Answer: (D) 2 - √3
Explanation
Using the standard trigonometric values:
sin 60° = √3/2
cos 60° = ½
Substituting these values into the given expression:
(sin 60° - cos 60°) / (sin 60° + cos 60°) = (√3/2 - ½) / (√3/2 + ½)
= (√3 - 1) / (√3 + 1)
To simplify, rationalize the denominator by multiplying both the numerator and the denominator by (√3 - 1):
((√3 - 1)(√3 - 1)) / ((√3 + 1)(√3 - 1))
= (√3 - 1)² / ((√3)² - 1²)
= (3 - 2√3 + 1) / (3 - 1)
= (4 - 2√3) / 2
= 2 - √3
507Quantitative Aptitude
The table shows the percentage distribution of the population (only male and female) according to Gender and Literacy.
Gender
| State | Percentage literate | Literate (M : F) | Illiterate (M : F) |
|---|---|---|---|
| A | 55 | 5 : 6 | 4 : 5 |
| B | 72 | 1 : 1 | 3 : 2 |
| C | 78 | 4 : 3 | 3 : 2 |
If state B has 7 crore people, then the number of illiterate females in the state is:
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Answer: (D) 78.4 lakhs
Explanation
The total population of State B is 7 crore, which is equal to 700 lakhs.
The percentage of the literate population in State B is 72%, which means the percentage of the illiterate population is 100% - 72% = 28%.
The total number of illiterate people in State B is calculated as:
Illiterate population = 28% of 700 lakhs = 196 lakhs.
The ratio of illiterate males to illiterate females in State B is given as 3 : 2.
The number of illiterate females in State B is:
Illiterate females = 2/(3 + 2) × 196 lakhs = 2/5 × 196 = 78.4 lakhs.
508Quantitative Aptitude
Out of a class of 200 people, 50 people's average marks is 40, and the remaining 150 people's average is 60. Find the people's weighted average.
Weighted Average = (50 × 40 + 150 × 60) / (50 + 150)
Weighted Average = (2000 + 9000) / 200
Weighted Average = 11000 / 200
Weighted Average = 55
509Quantitative Aptitude
In two successive years, 75 and 50 employees of a company appeared at the departmental examination. Respectively, 84% and 52% of them passed. The average rate of pass percentage is:
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Answer: (C) 71 1/5 %
Explanation
The average pass percentage is calculated by dividing the total number of passed candidates by the total number of candidates who appeared, multiplied by 100.
Number of employees who passed in the first year = 84% of 75 = (84 / 100) × 75 = 63
Number of employees who passed in the second year = 52% of 50 = (52 / 100) × 50 = 26
Total number of employees who passed over both years = 63 + 26 = 89
Total number of employees who appeared over both years = 75 + 50 = 125
Average rate of pass percentage = (Total passed / Total appeared) × 100
Average pass percentage = (89 / 125) × 100 = 89 × 4/5 = 356 / 5 = 71.2%
Converting 71.2% into a mixed fraction:
71.2% = 71 2/10 % = 71 1/5 %
510Quantitative Aptitude
Find the mean proportion to 0.72 and 2.85 (round up to one decimal place).
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Answer: (A) 1.4
Explanation
The mean proportion of two numbers a and b is given by the formula √(a × b).
Given the two numbers:
a = 0.72
b = 2.85
Substitute these values into the formula:
Mean proportion = √(0.72 × 2.85)
Mean proportion = √2.052
Calculating the square root:
√2.052 ≈ 1.432
Rounding 1.432 to one decimal place yields 1.4.
511Quantitative Aptitude
Two circles of radii 3 units and r units, respectively, have a 6 units distance between their centers. If the length of the direct common tangent is √(35) units, then the value of r is ___ units.
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Answer: (B) 4
Explanation
The length of the direct common tangent (L) between two circles with radii r₁ and r₂ and distance between their centers d is given by the formula:
L = √(d² - (r₁ - r₂)²)
Substituting the given values, where L = √35, d = 6, r₁ = r, and r₂ = 3:
√35 = √(6² - (r - 3)²)
Squaring both sides of the equation:
35 = 36 - (r - 3)²
Rearranging the terms:
(r - 3)² = 36 - 35
(r - 3)² = 1
Taking the square root on both sides:
r - 3 = ±1
This gives two possible values for r:
r = 3 + 1 = 4
r = 3 - 1 = 2
512Quantitative Aptitude
Shantanu's income decreased from ₹42,800 to ₹37,236. Find the percentage decrease in his income.
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Answer: (A) 13%
Explanation
Percentage decrease in income is calculated using the formula:
Percentage Decrease = (Original Income - New Income) / Original Income × 100
Substituting the given values:
Original Income = ₹42,800
New Income = ₹37,236
The surface area of a spherical ball is 1386 cm² . What will be its volume?
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Answer: (B) 4851 cm³
Explanation
The surface area of a sphere is given by the formula S = 4πr², where r is the radius of the sphere.
Substituting the given value of the surface area into the formula:
4 × (22/7) × r² = 1386
88/7 × r² = 1386
r² = (1386 × 7) / 88
r² = 110.25
r = 10.5 cm (or 21/2 cm)
The volume of a sphere is given by the formula V = 4/3 πr³.
Substituting the calculated radius into the volume formula:
V = 4/3 × (22/7) × (21/2)³
V = 4/3 × (22/7) × (9261/8)
V = 11 × 21 × 21
V = 4851 cm³
514Quantitative Aptitude
If the speed of a boat in still water is 3 km/h and if its speed upstream is 1 km/h , find the speed of the stream.
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Answer: (C) 2 km/h
Explanation
The formula for the upstream speed of a boat is:
Upstream Speed = Speed of boat in still water - Speed of the stream
Substituting the given values into the formula:
1 km/h = 3 km/h - Speed of the stream
Speed of the stream = 3 km/h - 1 km/h = 2 km/h
515Quantitative Aptitude
The average of 50 numbers is 23. If each number is multiplied by 13, then the new average is:
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Answer: (B) 299
Explanation
According to the properties of arithmetic mean, if each observation in a dataset is multiplied by a constant k, the mean of the new dataset is also multiplied by the same constant k.
Using this relation:
New Average = Old Average × k
Given that the old average is 23 and the constant multiplier k is 13:
New Average = 23 × 13 = 299
516Quantitative Aptitude
In Δ ABC, D and E are points on sides AB and AC , such that DE ∥ BC . If AD = x, DB = x - 3, AE = x + 3 and EC = x - 2 , then the value of x is:
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Answer: (D) 4.5
Explanation
According to the Basic Proportionality Theorem (Thales's Theorem), if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio. Since DE is parallel to BC, we have:
AD / DB = AE / EC
Substituting the given algebraic expressions into the relation:
x / (x - 3) = (x + 3) / (x - 2)
Cross-multiplying the terms:
x(x - 2) = (x - 3)(x + 3)
Expanding both sides using the algebraic identity (a - b)(a + b) = a² - b²:
x² - 2x = x² - 9
Subtracting x² from both sides:
-2x = -9
Dividing by -2:
x = 4.5
517Quantitative Aptitude
My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.
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Answer: (A) 12 years
Explanation
Let the present age of the person be x. Since the father is 25 years older, the father's present age is x + 25.
Five years ago:
The person's age was x - 5.
The father's age was x + 25 - 5 = x + 20.
The sum of their ages five years ago was 39:
(x - 5) + (x + 20) = 39
2x + 15 = 39
2x = 39 - 15
2x = 24
x = 12
518Quantitative Aptitude
What is the area (in square units) of the sector if the radius of the circle is given to be 24 units and the arc length is 7.5 units?
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Answer: (C) 90
Explanation
The area of a sector of a circle can be calculated directly using the formula relating the radius and the arc length:
Area = ½ × r × l
where r is the radius of the circle and l is the length of the arc.
Substituting the given values of r = 24 units and l = 7.5 units:
Area = ½ × 24 × 7.5
Area = 12 × 7.5
Area = 90 square units
519Quantitative Aptitude
If L is the mid- point of side BC of Δ ABC and the area of Δ ABL is 15 cm² , then the area (in sq cm) of Δ ABC is:
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Answer: (C) 30
Explanation
In any triangle, a median divides the triangle into two smaller triangles of equal area. Since L is the mid-point of side BC, AL is the median of ΔABC.
Area(ΔABC) = 2 × Area(ΔABL)
Given that Area(ΔABL) = 15 cm², substituting this value gives:
Area(ΔABC) = 2 × 15 = 30 cm²
520Quantitative Aptitude
If ¹⁵⁄₈ + [(⁵⁄₁₅ of ⁵⁄₁₂ + (¹⁄₁₅)) × 1 ⁷⁄₁₂] is expressed in the form of (a)/(b) where a and b are integers and relatively prime to each other, the value 4b - a is:
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Answer: (C) 189
Explanation
To find the value, we simplify the expression step-by-step:
First, evaluate the term inside the parenthesis:
5/15 of 3/12 = 1/3 × 1/4 = 1/12
Next, add 1/15 to this result:
1/12 + 1/15 = 5/60 + 4/60 = 9/60 = 3/20
Now, multiply by 1 7/12, which is equal to 19/12:
3/20 × 19/12 = 19/80
Subtracting this from 15/8 gives:
15/8 - 19/80 = 150/80 - 19/80 = 131/80
This is in the form of a/b, where a = 131 and b = 80. Since 131 is a prime number, a and b are relatively prime to each other.
We calculate the value of 4b - a:
4b - a = 4 × 80 - 131 = 320 - 131 = 189
521Quantitative Aptitude
If tanA + sinA = x , tanA - sinA = y , what is the value of x² - y² ?
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Answer: (A) 4√(xy)
Explanation
We use the algebraic identity:
x² - y² = (x + y)(x - y)
Given the equations:
x = tan A + sin A
y = tan A - sin A
Adding the two equations:
x + y = 2 tan A
Subtracting the second equation from the first:
x - y = 2 sin A
Substituting these into the identity:
x² - y² = (2 tan A)(2 sin A) = 4 tan A sin A
Now, we calculate the product xy:
xy = (tan A + sin A)(tan A - sin A) = tan² A - sin² A
Expressing tan A in terms of sin A and cos A:
xy = sin² A / cos² A - sin² A
xy = sin² A (1 / cos² A - 1)
xy = sin² A ((1 - cos² A) / cos² A)
xy = sin² A (sin² A / cos² A)
xy = sin² A tan² A
Taking the square root on both sides:
√(xy) = sin A tan A
Substituting sin A tan A = √(xy) back into the expression for x² - y²:
x² - y² = 4√(xy)
522Quantitative Aptitude
An election was held between two candidates. The winning candidate scored 54% of the valid votes and won by 88 votes. If 58 votes were declared invalid, then find the total number of votes polled in the election.
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Answer: (C) 1158
Explanation
Let the total number of valid votes be V.
Since there are only two candidates, the losing candidate received 46% of the valid votes (100% - 54% = 46%).
The difference in the percentage of valid votes between the winning and losing candidates is 54% - 46% = 8%.
We are given that the winning candidate won by 88 votes. Therefore, we can set up the equation:
8% of V = 88
0.08 × V = 88
V = 88 ÷ 0.08 = 1100
The total number of votes polled is the sum of the valid votes and the invalid votes:
Total votes polled = Valid votes + Invalid votes
Total votes polled = 1100 + 58 = 1158
523Quantitative Aptitude
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The numbers in the brackets give the maximum marks in each subject.
Student | Subject (Max. Marks)
--- | ---
| Maths (150) | Chemistry (130) | Physics (120) | Geography (100) | History (60) | Computer Science (40)
Ayush | 90 | 50 | 90 | 60 | 70 | 80
Aman | 100 | 80 | 80 | 40 | 80 | 70
Sajal | 90 | 60 | 70 | 70 | 90 | 70
Rohit | 80 | 65 | 80 | 80 | 60 | 60
Muskan | 80 | 65 | 85 | 95 | 50 | 90
Tanvi | 70 | 75 | 65 | 85 | 40 | 60
Tarun | 65 | 35 | 50 | 77 | 80 | 80
How many students secured a raw score of 135 in Maths?
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Answer: (D) 2
Explanation
To find the number of students who secured a raw score of 135 in Maths, the required percentage is calculated using the maximum marks for the subject, which is 150.
Percentage of marks = (Raw score ÷ Maximum marks) × 100
Percentage of marks = (135 ÷ 150) × 100 = 90%
Looking at the Maths column in the given table, the percentages obtained by the students are:
Ayush: 90%
Aman: 100%
Sajal: 90%
Rohit: 80%
Muskan: 80%
Tanvi: 70%
Tarun: 65%
Two students, Ayush and Sajal, obtained exactly 90% in Maths, meaning 2 students secured a raw score of 135.
524Quantitative Aptitude
The marked price of a table lamp is 2,165. During the festive season, it is sold for 1,710.35. Find the percentage discount offered.
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Answer: (A) 21%
Explanation
The discount percentage is calculated using the formula:
The salary of employees in a factory was reduced by 20% due to economic crisis. In order to have their salary back to original amount, it must be raised by:
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Answer: (B) 25%
Explanation
To find the percentage increase required to restore a reduced value back to its original level, we use the percentage change formula:
Percentage increase = [r / (100 - r)] × 100
where r is the percentage reduction. Given that the salary was reduced by r = 20%:
Alternatively, let the original salary of the employees be ₹100. After a reduction of 20%, the new salary becomes ₹80. To restore this salary back to the original ₹100, it needs to be increased by ₹20. The percentage increase required on the reduced salary of ₹80 is:
(20 / 80) × 100 = 25%
526Quantitative Aptitude
If the price of a commodity is increased by 36% by what percentage (rounded off to 1 decimal place) should its consumption be decreased so that the expenditure of the commodity stays the same?
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Answer: (C) 26.5%
Explanation
The percentage reduction in consumption required to keep the expenditure constant when the price of a commodity increases by r% is given by the formula:
Reduction % = (r ÷ (100 + r)) × 100
Substituting the given price increase of r = 36 into the formula:
Rounding off to one decimal place, the consumption should be decreased by 26.5%.
527Quantitative Aptitude
Tom travelled 285 km in 6 hours. In his total travelling, he travelled the first part by bus at 40km / hr and the remaining part by train at 55km / hr . How much distance has he travelled by train?
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Answer: (C) 165 km
Explanation
Using the relationship Total Time = Time by Train + Time by Bus:
Total Time = (Distance by Train ÷ Speed of Train) + (Distance by Bus ÷ Speed of Bus)
Let d be the distance travelled by train in kilometers. Since the total distance is 285 km, the distance travelled by bus is 285 - d km.
Substituting the given values into the formula:
d/55 + (285 - d)/40 = 6
Multiplying the entire equation by the lowest common multiple of 55 and 40, which is 440:
8d + 11(285 - d) = 6 × 440
8d + 3135 - 11d = 2640
3135 - 3d = 2640
3d = 495
d = 165
The distance Tom travelled by train is 165 km.
528Quantitative Aptitude
A cylindrical candle, 14cm in diameter and length 2cm is melted to form a cuboid candle of dimensions 7cm× 11cm × 2cm . How many cuboidal candles can be obtained?
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Answer: (A) 2
Explanation
Volume of the cylindrical candle is calculated using the formula V = πr²h, where r is the radius and h is the height (length). Given the diameter is 14 cm, the radius r is 7 cm, and the length h is 2 cm.
Volume of the cylinder = (22/7) × 7² × 2 = 22 × 7 × 2 = 308 cm³
Volume of each cuboidal candle is calculated using the formula V = length × width × height.
Volume of the cuboid = 7 × 11 × 2 = 154 cm³
The number of cuboidal candles that can be obtained is the volume of the cylindrical candle divided by the volume of one cuboidal candle.
Number of candles = 308 / 154 = 2
529Quantitative Aptitude
If 10% of 24% of x is 240 , then x = ?
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Answer: (B) 10000
Explanation
We can express the given percentage relationship as an algebraic equation:
10% × 24% × x = 240
Converting the percentages to fractions:
(10/100) × (24/100) × x = 240
(1/10) × (24/100) × x = 240
24x/1000 = 240
To solve for x, multiply both sides by 1000 and divide by 24:
x = (240 × 1000) / 24
Simplifying this gives:
x = 10 × 1000
x = 10000
530Quantitative Aptitude
The simple interest on the sum for 12 years is three- fifth of the sum. The rate of interest per annum is:
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Answer: (D) 5%
Explanation
The formula for simple interest is SI = P × R × T ÷ 100, where P is the principal sum, R is the rate of interest per annum, and T is the time in years.
Given that the simple interest is three-fifth of the sum, SI = 3/5 × P. The time T is 12 years.
Substituting these values into the formula:
3/5 × P = P × R × 12 ÷ 100
Simplifying by canceling P from both sides:
3/5 = 12 × R ÷ 100
This simplifies to:
0.6 = 0.12 × R
R = 0.6 ÷ 0.12 = 5%
531Quantitative Aptitude
In an election, a candidate secured 41% of the votes polled and lost the election by 97,632. What is the number of votes obtained by the winning candidate?
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Answer: (B) 320016
Explanation
Let the total number of votes polled be T. Since the losing candidate secured 41% of the votes, the winning candidate secured the remaining 59% of the votes (100% - 41% = 59%).
The difference in their vote percentages is:
59% - 41% = 18%
This difference represents the margin of loss, which is 97,632 votes:
18% of T = 97,632
T = 97,632 ÷ 0.18 = 542,400
The number of votes obtained by the winning candidate is 59% of this total:
Winning votes = 59% of 542,400 = 0.59 × 542,400 = 320,016
532Quantitative Aptitude
12sin²A + 2cos²A = 7 , where 0< A< 180° . Then cot A is:
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Answer: (B) ± 1
Explanation
Using the fundamental trigonometric identity sin²A + cos²A = 1, we can substitute cos²A = 1 - sin²A into the given equation:
12 sin²A + 2(1 - sin²A) = 7
Expanding and simplifying the equation:
12 sin²A + 2 - 2 sin²A = 7
10 sin²A = 5
sin²A = ½
Now, we find cos²A:
cos²A = 1 - sin²A = 1 - ½ = ½
Using the definition of cotangent:
cot²A = cos²A / sin²A = (½) / (½) = 1
Taking the square root of both sides gives:
cot A = ±1
Since the angle A lies in the range 0 < A < 180°, cot A is positive in the first quadrant (0 < A < 90°) and negative in the second quadrant (90° < A < 180°), which justifies both the positive and negative values.
533Quantitative Aptitude
Fifteen persons working 12 hours a day earn ₹18,000 per week. How many rupees will 18 persons working 9 hours a day earn per week?
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Answer: (B) 16,200
Explanation
The earnings of workers are directly proportional to both the number of persons and the number of hours they work per day. This relationship can be expressed using the formula:
E₁ / (M₁ × H₁) = E₂ / (M₂ × H₂)
where E represents earnings, M represents the number of persons, and H represents the working hours per day.
The 18 persons working 9 hours a day will earn ₹16,200 per week.
534Quantitative Aptitude
Which of the following are the sides of a right-angled triangle?
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Answer: (B) 12cm, 16cm, 20cm
Explanation
According to the Pythagorean theorem, three side lengths a, b, and c, where c is the longest side, form a right-angled triangle if they satisfy the relation:
a² + b² = c²
For the side lengths 12 cm, 16 cm, and 20 cm:
12² + 16² = 144 + 256 = 400
20² = 400
Since 12² + 16² = 20², these dimensions satisfy the theorem. This triplet is a multiple of the standard 3-4-5 right-angled triangle ratio scaled by a factor of 4, where 3×4 = 12, 4×4 = 16, and 5×4 = 20.
535Quantitative Aptitude
There are 12 workers in an office and the average age of all the workers is 35½ years. A new worker joins the office, the average becomes 37 years. The current age of the newly joined worker is:
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Answer: (C) 55 years
Explanation
Using the sum-average relation, the sum of ages of all workers is the product of the number of workers and their average age.
Sum of ages of the 12 original workers = 12 × 35½ = 12 × 35.5 = 426 years
When a new worker joins, the total number of workers becomes 13, and the new average age is 37 years.
Sum of ages of the 13 workers = 13 × 37 = 481 years
The age of the newly joined worker is the difference between these two sums:
Age of the new worker = 481 - 426 = 55 years
536Quantitative Aptitude
Two circles of radius 7 units each, intersect in such a way that the common chord is of length 7 units. What is the common area in square units of the intersection?
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Answer: (D) 98(π/6 - √3/4)
Explanation
The intersection area of two identical circles of radius r = 7 with a common chord of length 7 is formed by two symmetric circular segments.
The triangle formed by the center of one circle and the two endpoints of the common chord has all three sides of length 7, making it an equilateral triangle. Thus, the central angle θ subtended by the chord at the center of each circle is 60°, which is π/3 radians.
The area of a single circular segment is the area of the circular sector minus the area of the equilateral triangle:
Area of segment = (θ/2π) × πr² - (√3/4)r²
Area of segment = (1/6)πr² - (√3/4)r² = r²(π/6 - √3/4)
Since the common area of intersection consists of two such segments, the total area is:
Total Area = 2 × r²(π/6 - √3/4)
Substituting r = 7:
Total Area = 2 × 49(π/6 - √3/4) = 98(π/6 - √3/4)
537Quantitative Aptitude
Find the diameter of a spherical ball whose volume is 38.808 cm³ . (Use π = ²²⁄₇ )
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Answer: (D) 4.2 cm
Explanation
The volume V of a sphere is given by the formula V = (4/3) × π × r³, where r is the radius of the sphere.
Substituting V = 38.808 and π = 22/7:
38.808 = (4/3) × (22/7) × r³
38.808 = (88/21) × r³
r³ = (38.808 × 21) / 88
r³ = 0.441 × 21
r³ = 9.261
Taking the cube root on both sides:
r = 2.1 cm
The diameter of the spherical ball is twice the radius:
Diameter = 2 × r = 2 × 2.1 = 4.2 cm.
538Quantitative Aptitude
Twelve men working for 9 hours a day complete a piece of work in 24 days. In how many days can 8 men working for 12 hours a day complete the same piece of work?
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Answer: (B) 27 days
Explanation
The relationship between the number of men (M), days (D), and working hours per day (H) required to complete a constant amount of work is governed by the joint variation formula:
M₁ × D₁ × H₁ = M₂ × D₂ × H₂
Substituting the given values into the formula:
M₁ = 12 men, D₁ = 24 days, H₁ = 9 hours
M₂ = 8 men, H₂ = 12 hours, and D₂ is the required number of days
12 × 24 × 9 = 8 × D₂ × 12
Dividing both sides by 12:
24 × 9 = 8 × D₂
Solving for D₂:
D₂ = (24 × 9) / 8
D₂ = 3 × 9
D₂ = 27 days
539Quantitative Aptitude
How much water should be added to 60 liters of milk at 1½ liters a rupee so as to have a mixture worth 1⅞ liters a rupee?
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Answer: (A) 15 liters
Explanation
The cost price of milk is 1 / 1½ = ⅔ rupees per liter. Since water is free, its cost price is 0 rupees per liter.
The price of the final mixture is 1 / 1⅞ = 8/15 rupees per liter.
By the rule of alligation, the ratio of milk to water in the mixture is:
(8/15 - 0) : (⅔ - 8/15) = 8/15 : 2/15 = 4 : 1
This means that for every 4 parts of milk, 1 part of water is added.
Since the quantity of milk is 60 liters, which corresponds to 4 parts, the quantity of water corresponding to 1 part is:
60 × ¼ = 15 liters
540Quantitative Aptitude
A bank charges simple interest for R at the rate of r² for n² years. Another bank charges simple interest for R at the rate of r² for n³ years and gives the same interest. The ratio between K and L is:
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Answer: (C) rn:1
Explanation
Simple interest (SI) is calculated using the formula:
SI = (P × R × T) / 100
Let the principal amount for the first bank be K, with a rate of interest r% and time n² years. The simple interest is:
SI₁ = (K × r × n²) / 100
Let the principal amount for the second bank be L, with a rate of interest r²% and time n³ years. The simple interest is:
SI₂ = (L × r² × n³) / 100
Since the interest earned from both banks is the same:
SI₁ = SI₂
(K × r × n²) / 100 = (L × r² × n³) / 100
Canceling the common terms from both sides:
K × r × n² = L × r² × n³
To find the ratio between K and L:
K / L = (r² × n³) / (r × n²)
K / L = rn / 1
Thus, the ratio K : L is rn : 1.
541Quantitative Aptitude
A dozen pairs of gloves of R180 are available at a discount of 10% . How many pairs of gloves can be bought for R 54?
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Answer: (D) 4
Explanation
The marked price of 12 pairs of gloves is ₹180.
At a 10% discount, the selling price for 12 pairs is:
180 × (1 - 0.10) = ₹162
The cost of a single pair of gloves is:
162 ÷ 12 = ₹13.5
The number of pairs of gloves that can be bought for ₹54 is:
54 ÷ 13.5 = 4
542Quantitative Aptitude
A boat can travel 60km downstream in 4 hours. If the speed of the boat in still water is 13 km/h, then in what time will it cover 30 km upstream?
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Answer: (D) 4.2⁸⁄₁₁ hours
Explanation
Downstream speed of the boat is calculated by dividing the downstream distance by the time taken:
Downstream speed = 60 / 4 = 15 km/h
The downstream speed is the sum of the speed of the boat in still water and the speed of the stream. Given that the speed of the boat in still water is 13 km/h, we can find the speed of the stream:
Speed of the stream = Downstream speed - Speed of boat in still water
Speed of the stream = 15 - 13 = 2 km/h
The upstream speed of the boat is the difference between the speed of the boat in still water and the speed of the stream:
Upstream speed = 13 - 2 = 11 km/h
The time required to cover 30 km upstream is calculated by dividing the upstream distance by the upstream speed:
Time taken = 30 / 11 = 2 8/11 hours
543Quantitative Aptitude
If the diameter of a hemisphere is 21 cm, then the curved surface area (in cm² ) of the hemisphere is:
Take π = ²²⁄₇
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Answer: (C) 3.693
Explanation
The curved surface area (CSA) of a hemisphere is given by the formula:
CSA = 2πr²
Given that the diameter of the hemisphere is 21 cm, the radius (r) is:
r = 21/2 cm
Using the value of π = 22/7, substitute the radius into the formula:
CSA = 2 × (22/7) × (21/2)²
CSA = 2 × (22/7) × (21/2) × (21/2)
CSA = 2 × (22/7) × (441/4)
CSA = 11 × 63
CSA = 693 cm²
544Quantitative Aptitude
The ratio of a father's age to his son's age is 7 : 4. The product of the numbers representing their ages is 1372. The ratio of their ages after 8 years will be:
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Answer: (D) 19:12
Explanation
Let the present ages of the father and the son be 7x and 4x respectively.
According to the given condition, the product of their ages is 1372:
(7x) × (4x) = 1372
28x² = 1372
x² = 1372 / 28
x² = 49
x = 7
Using the value of x, we find their present ages:
Father's present age = 7 × 7 = 49 years
Son's present age = 4 × 7 = 28 years
Their ages after 8 years will be:
Father's age = 49 + 8 = 57 years
Son's age = 28 + 8 = 36 years
The ratio of their ages after 8 years is:
57 : 36 = 19 : 12
545Quantitative Aptitude
The following table shows the production of cars in a company from 2016 to 2020.
Years | 2016 | 2017 | 2018 | 2019 | 2020
--- | --- | --- | --- | --- | ---
A | 30 | 23 | 39 | 25 | 18
B | 16 | 10 | 14 | 12 | 8
C | 15 | 18 | 19 | 25 | 30
D | 31 | 12 | 21 | 19 | 20
There was a continuous decrease in the production of cars of which types during the period 2018 to 2020?
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Answer: (B) A,B
Explanation
To find the car types with a continuous decrease in production from 2018 to 2020, we analyze the annual production values for each type during these years.
For car Type A, the production values are 39 in 2018, 25 in 2019, and 18 in 2020. This shows a steady decline since 39 > 25 > 18.
For car Type B, the production values are 14 in 2018, 12 in 2019, and 8 in 2020. This also shows a steady decline since 14 > 12 > 8.
Both car types A and B satisfy the condition of continuous decrease in production during this period.
546Quantitative Aptitude
During the first year the population of a village increased by 5% and during the second year it diminished by 5% . At the end of the second year its population was 47,880. What was the population at the beginning of the first year?
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Answer: (C) 3.48000
Explanation
Let P be the population at the beginning of the first year.
According to the given conditions, the population increases by 5% in the first year and decreases by 5% in the second year. The net relationship between the initial population and the population at the end of the second year is given by the formula:
Final Population = P × (1 + 5/100) × (1 - 5/100)
Substituting the given final population of 47,880 into the formula:
47880 = P × 1.05 × 0.95
47880 = P × 0.9975
P = 47880 / 0.9975
P = 48000
Thus, the population at the beginning of the first year was 48,000.
547Quantitative Aptitude
The capacity of a cylinder tank is 8316 cm³ . If the radius of its base is 21 cm , then find the depth of the tank.
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Answer: (A) 6cm
Explanation
The volume of a cylinder is given by the formula V = pi * r² * h. Substituting the volume of 8316 cubic centimeters and radius of 21 centimeters into the formula gives 8316 = (22/7) * 21 * 21 * h, which simplifies to 8316 = 1386 * h. Solving for h gives a depth of 6 centimeters.
548Quantitative Aptitude
What is the value of cos (x + y) - sin (x - y) + tan (2z) ?
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Answer: (C) cos x.cos y - sin x.sin y - sin x.cos y + cos x.sin y + (2tan z)/(1 - tan²z)
Explanation
The trigonometric expansion formulas are:
cos(x + y) = cos x cos y - sin x sin y
sin(x - y) = sin x cos y - cos x sin y
tan(2z) = 2tan z / (1 - tan²z)
Substituting these standard identities into the given expression:
cos(x + y) - sin(x - y) + tan(2z) = (cos x cos y - sin x sin y) - (sin x cos y - cos x sin y) + 2tan z / (1 - tan²z)
Expanding the terms and distributing the negative sign yields:
cos x cos y - sin x sin y - sin x cos y + cos x sin y + 2tan z / (1 - tan²z)
549Quantitative Aptitude
The perimeter of a minor sector of a circle of radius 4 units subtending an angle of 45° is:
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Answer: (B) 8 + π units
Explanation
The perimeter of a sector of a circle is given by 2r + L, where r is the radius and L is the arc length. For a radius of 4 units and an angle of 45 degrees, the arc length is (45/360) * 2 * pi * 4 = pi, making the total perimeter 2(4) + pi = 8 + pi units.
550Quantitative Aptitude
Mahesh's annual salary increased from ₹2,00,000 to ₹2,40,000. Find the percentage increase in the salary.
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Answer: (C) 3.20%
Explanation
The percentage increase in salary is calculated using the formula:
Percentage Increase = (Increase in Salary / Original Salary) × 100%
Here, the original salary is ₹2,00,000 and the new salary is ₹2,40,000.
The increase in salary is:
2,40,000 - 2,00,000 = ₹40,000
Substituting these values into the formula:
Percentage Increase = (40,000 / 2,00,000) × 100% = 20%