SSC CHSL2024Quantitative AptitudePage 11 of 13

SSC CHSL Tier 1 2024 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 501–550 of 648, each with the correct answer and a step-by-step explanation.

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501Quantitative Aptitude
The sum of the present ages of a father and son is 50 years. If after 5 years, the father's age will be 5 times the age of the son, then what was the father's age 5 years ago?
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Answer: (A) 40

Explanation

Correct Answer: A

Let F and S be the present ages of the father and the son respectively.

The sum of their present ages is: F + S = 50

In 5 years, their ages will be F + 5 and S + 5. According to the given condition: F + 5 = 5(S + 5) F + 5 = 5S + 25 F - 5S = 20

Subtracting the second equation from the first gives: 6S = 30 S = 5

Substituting S = 5 into the first equation: F + 5 = 50 F = 45

Thus, the father's present age is 45 years. Five years ago, the father's age was: 45 - 5 = 40 years.

502Quantitative Aptitude
The cost price of a fan is ₹4,400. A merchant wants to make a 24% profit by selling it. At the time of sale, merchant declares a discount of 12% on the marked price. Find the marked price.
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Answer: (D) 6,200

Explanation

The relationship between Cost Price (CP), Marked Price (MP), Profit percentage (P), and Discount percentage (D) is given by the standard formula:

MP / CP = (100 + P) / (100 - D)

Substituting the given values (CP = 4400, P = 24, and D = 12) into the formula:

MP / 4400 = (100 + 24) / (100 - 12)

MP / 4400 = 124 / 88

MP = 4400 × 124 / 88

MP = 50 × 124

MP = 6200

503Quantitative Aptitude
The price of a product increases by 10% in the first year and 20% in the second year. What is the overall percentage increase in the price of the product over the two years?
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Answer: (B) 32%

Explanation

The net percentage change for two successive percentage increases of a% and b% is given by the formula:

Net Increase = a + b + (a × b)/100

Given: First year increase, a = 10% Second year increase, b = 20%

Substituting these values into the formula:

Net Increase = 10 + 20 + (10 × 20)/100 Net Increase = 30 + 200/100 Net Increase = 30 + 2 Net Increase = 32%

Alternatively, if the initial price is assumed to be 100: Price after the first year = 100 × (1 + 10/100) = 110 Price after the second year = 110 × (1 + 20/100) = 110 × 1.2 = 132 Overall increase = 132 - 100 = 32%

504Quantitative Aptitude
Find the whole surface area of a cuboid having a length of 19 cm, breadth of 9 cm and height of 4.5 cm.
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Answer: (C) 594 cm²

Explanation

The total surface area of a cuboid is calculated using the formula:

Total Surface Area = 2 × (lb + bh + hl)

where l is the length, b is the breadth, and h is the height.

Given values: l = 19 cm b = 9 cm h = 4.5 cm

Substituting these values into the formula:

Total Surface Area = 2 × (19 × 9 + 9 × 4.5 + 4.5 × 19) Total Surface Area = 2 × (171 + 40.5 + 85.5) Total Surface Area = 2 × 297 Total Surface Area = 594 cm²

505Quantitative Aptitude
Δ ABC ∼ Δ EDF and area(ABC): area(EDF) = 1 : 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to:
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Answer: (D) 16 cm

Explanation

For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides.

Since ΔABC is similar to ΔEDF, the corresponding side to DF is BC. The relationship between their areas and these sides is given by:

area(ΔABC) / area(ΔEDF) = (BC / DF)²

Substituting the given values:

1 / 4 = (8 / DF)²

Taking the square root on both sides:

1 / 2 = 8 / DF

DF = 8 × 2 = 16 cm

506Quantitative Aptitude
Simplify (sin 60° - cos 60°)/(sin 60° + cos 60°)
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Answer: (D) 2 - √3

Explanation

Using the standard trigonometric values: sin 60° = √3/2 cos 60° = ½

Substituting these values into the given expression: (sin 60° - cos 60°) / (sin 60° + cos 60°) = (√3/2 - ½) / (√3/2 + ½) = (√3 - 1) / (√3 + 1)

To simplify, rationalize the denominator by multiplying both the numerator and the denominator by (√3 - 1): ((√3 - 1)(√3 - 1)) / ((√3 + 1)(√3 - 1)) = (√3 - 1)² / ((√3)² - 1²) = (3 - 2√3 + 1) / (3 - 1) = (4 - 2√3) / 2 = 2 - √3

507Quantitative Aptitude
The table shows the percentage distribution of the population (only male and female) according to Gender and Literacy. Gender | State | Percentage literate | Literate (M : F) | Illiterate (M : F) | |---|---|---|---| | A | 55 | 5 : 6 | 4 : 5 | | B | 72 | 1 : 1 | 3 : 2 | | C | 78 | 4 : 3 | 3 : 2 | If state B has 7 crore people, then the number of illiterate females in the state is:
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Answer: (D) 78.4 lakhs

Explanation

The total population of State B is 7 crore, which is equal to 700 lakhs.

The percentage of the literate population in State B is 72%, which means the percentage of the illiterate population is 100% - 72% = 28%.

The total number of illiterate people in State B is calculated as: Illiterate population = 28% of 700 lakhs = 196 lakhs.

The ratio of illiterate males to illiterate females in State B is given as 3 : 2.

The number of illiterate females in State B is: Illiterate females = 2/(3 + 2) × 196 lakhs = 2/5 × 196 = 78.4 lakhs.

508Quantitative Aptitude
Out of a class of 200 people, 50 people's average marks is 40, and the remaining 150 people's average is 60. Find the people's weighted average.
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Answer: (C) 55

Explanation

The weighted average formula is given by:

Weighted Average = (n₁ × A₁ + n₂ × A₂) / (n₁ + n₂)

Where: n₁ = 50, A₁ = 40 n₂ = 150, A₂ = 60

Substituting these values into the formula:

Weighted Average = (50 × 40 + 150 × 60) / (50 + 150) Weighted Average = (2000 + 9000) / 200 Weighted Average = 11000 / 200 Weighted Average = 55

509Quantitative Aptitude
In two successive years, 75 and 50 employees of a company appeared at the departmental examination. Respectively, 84% and 52% of them passed. The average rate of pass percentage is:
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Answer: (C) 71 1/5 %

Explanation

The average pass percentage is calculated by dividing the total number of passed candidates by the total number of candidates who appeared, multiplied by 100.

Number of employees who passed in the first year = 84% of 75 = (84 / 100) × 75 = 63

Number of employees who passed in the second year = 52% of 50 = (52 / 100) × 50 = 26

Total number of employees who passed over both years = 63 + 26 = 89

Total number of employees who appeared over both years = 75 + 50 = 125

Average rate of pass percentage = (Total passed / Total appeared) × 100 Average pass percentage = (89 / 125) × 100 = 89 × 4/5 = 356 / 5 = 71.2%

Converting 71.2% into a mixed fraction: 71.2% = 71 2/10 % = 71 1/5 %

510Quantitative Aptitude
Find the mean proportion to 0.72 and 2.85 (round up to one decimal place).
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Answer: (A) 1.4

Explanation

The mean proportion of two numbers a and b is given by the formula √(a × b).

Given the two numbers: a = 0.72 b = 2.85

Substitute these values into the formula: Mean proportion = √(0.72 × 2.85) Mean proportion = √2.052

Calculating the square root: √2.052 ≈ 1.432

Rounding 1.432 to one decimal place yields 1.4.

511Quantitative Aptitude
Two circles of radii 3 units and r units, respectively, have a 6 units distance between their centers. If the length of the direct common tangent is √(35) units, then the value of r is ___ units.
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Answer: (B) 4

Explanation

The length of the direct common tangent (L) between two circles with radii r₁ and r₂ and distance between their centers d is given by the formula:

L = √(d² - (r₁ - r₂)²)

Substituting the given values, where L = √35, d = 6, r₁ = r, and r₂ = 3:

√35 = √(6² - (r - 3)²)

Squaring both sides of the equation:

35 = 36 - (r - 3)²

Rearranging the terms:

(r - 3)² = 36 - 35 (r - 3)² = 1

Taking the square root on both sides:

r - 3 = ±1

This gives two possible values for r:

r = 3 + 1 = 4 r = 3 - 1 = 2

512Quantitative Aptitude
Shantanu's income decreased from ₹42,800 to ₹37,236. Find the percentage decrease in his income.
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Answer: (A) 13%

Explanation

Percentage decrease in income is calculated using the formula: Percentage Decrease = (Original Income - New Income) / Original Income × 100

Substituting the given values: Original Income = ₹42,800 New Income = ₹37,236

Decrease in income = 42,800 - 37,236 = 5,564

Percentage Decrease = (5,564 / 42,800) × 100 Percentage Decrease = 5,564 / 428 Percentage Decrease = 13%

513Quantitative Aptitude
The surface area of a spherical ball is 1386 cm² . What will be its volume?
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Answer: (B) 4851 cm³

Explanation

The surface area of a sphere is given by the formula S = 4πr², where r is the radius of the sphere.

Substituting the given value of the surface area into the formula: 4 × (22/7) × r² = 1386 88/7 × r² = 1386 r² = (1386 × 7) / 88 r² = 110.25 r = 10.5 cm (or 21/2 cm)

The volume of a sphere is given by the formula V = 4/3 πr³.

Substituting the calculated radius into the volume formula: V = 4/3 × (22/7) × (21/2)³ V = 4/3 × (22/7) × (9261/8) V = 11 × 21 × 21 V = 4851 cm³

514Quantitative Aptitude
If the speed of a boat in still water is 3 km/h and if its speed upstream is 1 km/h , find the speed of the stream.
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Answer: (C) 2 km/h

Explanation

The formula for the upstream speed of a boat is: Upstream Speed = Speed of boat in still water - Speed of the stream

Substituting the given values into the formula: 1 km/h = 3 km/h - Speed of the stream Speed of the stream = 3 km/h - 1 km/h = 2 km/h

515Quantitative Aptitude
The average of 50 numbers is 23. If each number is multiplied by 13, then the new average is:
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Answer: (B) 299

Explanation

According to the properties of arithmetic mean, if each observation in a dataset is multiplied by a constant k, the mean of the new dataset is also multiplied by the same constant k.

Using this relation: New Average = Old Average × k

Given that the old average is 23 and the constant multiplier k is 13: New Average = 23 × 13 = 299

516Quantitative Aptitude
In Δ ABC, D and E are points on sides AB and AC , such that DE ∥ BC . If AD = x, DB = x - 3, AE = x + 3 and EC = x - 2 , then the value of x is:
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Answer: (D) 4.5

Explanation

According to the Basic Proportionality Theorem (Thales's Theorem), if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio. Since DE is parallel to BC, we have:

AD / DB = AE / EC

Substituting the given algebraic expressions into the relation:

x / (x - 3) = (x + 3) / (x - 2)

Cross-multiplying the terms:

x(x - 2) = (x - 3)(x + 3)

Expanding both sides using the algebraic identity (a - b)(a + b) = a² - b²:

x² - 2x = x² - 9

Subtracting x² from both sides:

-2x = -9

Dividing by -2:

x = 4.5

517Quantitative Aptitude
My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.
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Answer: (A) 12 years

Explanation

Let the present age of the person be x. Since the father is 25 years older, the father's present age is x + 25.

Five years ago: The person's age was x - 5. The father's age was x + 25 - 5 = x + 20.

The sum of their ages five years ago was 39: (x - 5) + (x + 20) = 39 2x + 15 = 39 2x = 39 - 15 2x = 24 x = 12

518Quantitative Aptitude
What is the area (in square units) of the sector if the radius of the circle is given to be 24 units and the arc length is 7.5 units?
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Answer: (C) 90

Explanation

The area of a sector of a circle can be calculated directly using the formula relating the radius and the arc length:

Area = ½ × r × l

where r is the radius of the circle and l is the length of the arc.

Substituting the given values of r = 24 units and l = 7.5 units:

Area = ½ × 24 × 7.5 Area = 12 × 7.5 Area = 90 square units

519Quantitative Aptitude
If L is the mid- point of side BC of Δ ABC and the area of Δ ABL is 15 cm² , then the area (in sq cm) of Δ ABC is:
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Answer: (C) 30

Explanation

In any triangle, a median divides the triangle into two smaller triangles of equal area. Since L is the mid-point of side BC, AL is the median of ΔABC.

Area(ΔABC) = 2 × Area(ΔABL)

Given that Area(ΔABL) = 15 cm², substituting this value gives:

Area(ΔABC) = 2 × 15 = 30 cm²

520Quantitative Aptitude
If ¹⁵⁄₈ + [(⁵⁄₁₅ of ⁵⁄₁₂ + (¹⁄₁₅)) × 1 ⁷⁄₁₂] is expressed in the form of (a)/(b) where a and b are integers and relatively prime to each other, the value 4b - a is:
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Answer: (C) 189

Explanation

To find the value, we simplify the expression step-by-step:

First, evaluate the term inside the parenthesis: 5/15 of 3/12 = 1/3 × 1/4 = 1/12

Next, add 1/15 to this result: 1/12 + 1/15 = 5/60 + 4/60 = 9/60 = 3/20

Now, multiply by 1 7/12, which is equal to 19/12: 3/20 × 19/12 = 19/80

Subtracting this from 15/8 gives: 15/8 - 19/80 = 150/80 - 19/80 = 131/80

This is in the form of a/b, where a = 131 and b = 80. Since 131 is a prime number, a and b are relatively prime to each other.

We calculate the value of 4b - a: 4b - a = 4 × 80 - 131 = 320 - 131 = 189

521Quantitative Aptitude
If tanA + sinA = x , tanA - sinA = y , what is the value of x² - y² ?
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Answer: (A) 4√(xy)

Explanation

We use the algebraic identity: x² - y² = (x + y)(x - y)

Given the equations: x = tan A + sin A y = tan A - sin A

Adding the two equations: x + y = 2 tan A

Subtracting the second equation from the first: x - y = 2 sin A

Substituting these into the identity: x² - y² = (2 tan A)(2 sin A) = 4 tan A sin A

Now, we calculate the product xy: xy = (tan A + sin A)(tan A - sin A) = tan² A - sin² A

Expressing tan A in terms of sin A and cos A: xy = sin² A / cos² A - sin² A xy = sin² A (1 / cos² A - 1) xy = sin² A ((1 - cos² A) / cos² A) xy = sin² A (sin² A / cos² A) xy = sin² A tan² A

Taking the square root on both sides: √(xy) = sin A tan A

Substituting sin A tan A = √(xy) back into the expression for x² - y²: x² - y² = 4√(xy)

522Quantitative Aptitude
An election was held between two candidates. The winning candidate scored 54% of the valid votes and won by 88 votes. If 58 votes were declared invalid, then find the total number of votes polled in the election.
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Answer: (C) 1158

Explanation

Let the total number of valid votes be V.

Since there are only two candidates, the losing candidate received 46% of the valid votes (100% - 54% = 46%).

The difference in the percentage of valid votes between the winning and losing candidates is 54% - 46% = 8%.

We are given that the winning candidate won by 88 votes. Therefore, we can set up the equation:

8% of V = 88

0.08 × V = 88

V = 88 ÷ 0.08 = 1100

The total number of votes polled is the sum of the valid votes and the invalid votes:

Total votes polled = Valid votes + Invalid votes

Total votes polled = 1100 + 58 = 1158

523Quantitative Aptitude
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination. The numbers in the brackets give the maximum marks in each subject. Student | Subject (Max. Marks) --- | --- | Maths (150) | Chemistry (130) | Physics (120) | Geography (100) | History (60) | Computer Science (40) Ayush | 90 | 50 | 90 | 60 | 70 | 80 Aman | 100 | 80 | 80 | 40 | 80 | 70 Sajal | 90 | 60 | 70 | 70 | 90 | 70 Rohit | 80 | 65 | 80 | 80 | 60 | 60 Muskan | 80 | 65 | 85 | 95 | 50 | 90 Tanvi | 70 | 75 | 65 | 85 | 40 | 60 Tarun | 65 | 35 | 50 | 77 | 80 | 80 How many students secured a raw score of 135 in Maths?
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Answer: (D) 2

Explanation

To find the number of students who secured a raw score of 135 in Maths, the required percentage is calculated using the maximum marks for the subject, which is 150.

Percentage of marks = (Raw score ÷ Maximum marks) × 100 Percentage of marks = (135 ÷ 150) × 100 = 90%

Looking at the Maths column in the given table, the percentages obtained by the students are: Ayush: 90% Aman: 100% Sajal: 90% Rohit: 80% Muskan: 80% Tanvi: 70% Tarun: 65%

Two students, Ayush and Sajal, obtained exactly 90% in Maths, meaning 2 students secured a raw score of 135.

524Quantitative Aptitude
The marked price of a table lamp is 2,165. During the festive season, it is sold for 1,710.35. Find the percentage discount offered.
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Answer: (A) 21%

Explanation

The discount percentage is calculated using the formula:

Discount Percentage = ((Marked Price - Selling Price) / Marked Price) × 100

Substituting the given values:

Marked Price = 2165 Selling Price = 1710.35

Discount = 2165 - 1710.35 = 454.65

Discount Percentage = (454.65 / 2165) × 100 = 45465 / 2165 = 21%

525Quantitative Aptitude
The salary of employees in a factory was reduced by 20% due to economic crisis. In order to have their salary back to original amount, it must be raised by:
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Answer: (B) 25%

Explanation

To find the percentage increase required to restore a reduced value back to its original level, we use the percentage change formula:

Percentage increase = [r / (100 - r)] × 100

where r is the percentage reduction. Given that the salary was reduced by r = 20%:

Percentage increase = [20 / (100 - 20)] × 100 Percentage increase = (20 / 80) × 100 Percentage increase = ¼ × 100 = 25%

Alternatively, let the original salary of the employees be ₹100. After a reduction of 20%, the new salary becomes ₹80. To restore this salary back to the original ₹100, it needs to be increased by ₹20. The percentage increase required on the reduced salary of ₹80 is:

(20 / 80) × 100 = 25%

526Quantitative Aptitude
If the price of a commodity is increased by 36% by what percentage (rounded off to 1 decimal place) should its consumption be decreased so that the expenditure of the commodity stays the same?
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Answer: (C) 26.5%

Explanation

The percentage reduction in consumption required to keep the expenditure constant when the price of a commodity increases by r% is given by the formula:

Reduction % = (r ÷ (100 + r)) × 100

Substituting the given price increase of r = 36 into the formula:

Reduction % = (36 ÷ (100 + 36)) × 100 Reduction % = (36 ÷ 136) × 100 Reduction % = (9 ÷ 34) × 100 Reduction % = 900 ÷ 34 Reduction % ≈ 26.47%

Rounding off to one decimal place, the consumption should be decreased by 26.5%.

527Quantitative Aptitude
Tom travelled 285 km in 6 hours. In his total travelling, he travelled the first part by bus at 40km / hr and the remaining part by train at 55km / hr . How much distance has he travelled by train?
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Answer: (C) 165 km

Explanation

Using the relationship Total Time = Time by Train + Time by Bus:

Total Time = (Distance by Train ÷ Speed of Train) + (Distance by Bus ÷ Speed of Bus)

Let d be the distance travelled by train in kilometers. Since the total distance is 285 km, the distance travelled by bus is 285 - d km.

Substituting the given values into the formula: d/55 + (285 - d)/40 = 6

Multiplying the entire equation by the lowest common multiple of 55 and 40, which is 440: 8d + 11(285 - d) = 6 × 440 8d + 3135 - 11d = 2640 3135 - 3d = 2640 3d = 495 d = 165

The distance Tom travelled by train is 165 km.

528Quantitative Aptitude
A cylindrical candle, 14cm in diameter and length 2cm is melted to form a cuboid candle of dimensions 7cm× 11cm × 2cm . How many cuboidal candles can be obtained?
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Answer: (A) 2

Explanation

Volume of the cylindrical candle is calculated using the formula V = πr²h, where r is the radius and h is the height (length). Given the diameter is 14 cm, the radius r is 7 cm, and the length h is 2 cm.

Volume of the cylinder = (22/7) × 7² × 2 = 22 × 7 × 2 = 308 cm³

Volume of each cuboidal candle is calculated using the formula V = length × width × height.

Volume of the cuboid = 7 × 11 × 2 = 154 cm³

The number of cuboidal candles that can be obtained is the volume of the cylindrical candle divided by the volume of one cuboidal candle.

Number of candles = 308 / 154 = 2

529Quantitative Aptitude
If 10% of 24% of x is 240 , then x = ?
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Answer: (B) 10000

Explanation

We can express the given percentage relationship as an algebraic equation:

10% × 24% × x = 240

Converting the percentages to fractions:

(10/100) × (24/100) × x = 240

(1/10) × (24/100) × x = 240

24x/1000 = 240

To solve for x, multiply both sides by 1000 and divide by 24:

x = (240 × 1000) / 24

Simplifying this gives:

x = 10 × 1000

x = 10000

530Quantitative Aptitude
The simple interest on the sum for 12 years is three- fifth of the sum. The rate of interest per annum is:
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Answer: (D) 5%

Explanation

The formula for simple interest is SI = P × R × T ÷ 100, where P is the principal sum, R is the rate of interest per annum, and T is the time in years.

Given that the simple interest is three-fifth of the sum, SI = 3/5 × P. The time T is 12 years.

Substituting these values into the formula: 3/5 × P = P × R × 12 ÷ 100

Simplifying by canceling P from both sides: 3/5 = 12 × R ÷ 100

This simplifies to: 0.6 = 0.12 × R

R = 0.6 ÷ 0.12 = 5%

531Quantitative Aptitude
In an election, a candidate secured 41% of the votes polled and lost the election by 97,632. What is the number of votes obtained by the winning candidate?
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Answer: (B) 320016

Explanation

Let the total number of votes polled be T. Since the losing candidate secured 41% of the votes, the winning candidate secured the remaining 59% of the votes (100% - 41% = 59%).

The difference in their vote percentages is: 59% - 41% = 18%

This difference represents the margin of loss, which is 97,632 votes: 18% of T = 97,632 T = 97,632 ÷ 0.18 = 542,400

The number of votes obtained by the winning candidate is 59% of this total: Winning votes = 59% of 542,400 = 0.59 × 542,400 = 320,016

532Quantitative Aptitude
12sin²A + 2cos²A = 7 , where 0< A< 180° . Then cot A is:
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Answer: (B) ± 1

Explanation

Using the fundamental trigonometric identity sin²A + cos²A = 1, we can substitute cos²A = 1 - sin²A into the given equation:

12 sin²A + 2(1 - sin²A) = 7

Expanding and simplifying the equation:

12 sin²A + 2 - 2 sin²A = 7 10 sin²A = 5 sin²A = ½

Now, we find cos²A:

cos²A = 1 - sin²A = 1 - ½ = ½

Using the definition of cotangent:

cot²A = cos²A / sin²A = (½) / (½) = 1

Taking the square root of both sides gives:

cot A = ±1

Since the angle A lies in the range 0 < A < 180°, cot A is positive in the first quadrant (0 < A < 90°) and negative in the second quadrant (90° < A < 180°), which justifies both the positive and negative values.

533Quantitative Aptitude
Fifteen persons working 12 hours a day earn ₹18,000 per week. How many rupees will 18 persons working 9 hours a day earn per week?
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Answer: (B) 16,200

Explanation

The earnings of workers are directly proportional to both the number of persons and the number of hours they work per day. This relationship can be expressed using the formula:

E₁ / (M₁ × H₁) = E₂ / (M₂ × H₂)

where E represents earnings, M represents the number of persons, and H represents the working hours per day.

Substituting the given values into the formula:

M₁ = 15 persons, H₁ = 12 hours, E₁ = ₹18,000 M₂ = 18 persons, H₂ = 9 hours, E₂ = unknown earnings

18,000 / (15 × 12) = E₂ / (18 × 9)

18,000 / 180 = E₂ / 162

100 = E₂ / 162

E₂ = 100 × 162 = 16,200

The 18 persons working 9 hours a day will earn ₹16,200 per week.

534Quantitative Aptitude
Which of the following are the sides of a right-angled triangle?
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Answer: (B) 12cm, 16cm, 20cm

Explanation

According to the Pythagorean theorem, three side lengths a, b, and c, where c is the longest side, form a right-angled triangle if they satisfy the relation:

a² + b² = c²

For the side lengths 12 cm, 16 cm, and 20 cm:

12² + 16² = 144 + 256 = 400 20² = 400

Since 12² + 16² = 20², these dimensions satisfy the theorem. This triplet is a multiple of the standard 3-4-5 right-angled triangle ratio scaled by a factor of 4, where 3×4 = 12, 4×4 = 16, and 5×4 = 20.

535Quantitative Aptitude
There are 12 workers in an office and the average age of all the workers is 35½ years. A new worker joins the office, the average becomes 37 years. The current age of the newly joined worker is:
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Answer: (C) 55 years

Explanation

Using the sum-average relation, the sum of ages of all workers is the product of the number of workers and their average age.

Sum of ages of the 12 original workers = 12 × 35½ = 12 × 35.5 = 426 years

When a new worker joins, the total number of workers becomes 13, and the new average age is 37 years.

Sum of ages of the 13 workers = 13 × 37 = 481 years

The age of the newly joined worker is the difference between these two sums:

Age of the new worker = 481 - 426 = 55 years

536Quantitative Aptitude
Two circles of radius 7 units each, intersect in such a way that the common chord is of length 7 units. What is the common area in square units of the intersection?
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Answer: (D) 98(π/6 - √3/4)

Explanation

The intersection area of two identical circles of radius r = 7 with a common chord of length 7 is formed by two symmetric circular segments.

The triangle formed by the center of one circle and the two endpoints of the common chord has all three sides of length 7, making it an equilateral triangle. Thus, the central angle θ subtended by the chord at the center of each circle is 60°, which is π/3 radians.

The area of a single circular segment is the area of the circular sector minus the area of the equilateral triangle: Area of segment = (θ/2π) × πr² - (√3/4)r² Area of segment = (1/6)πr² - (√3/4)r² = r²(π/6 - √3/4)

Since the common area of intersection consists of two such segments, the total area is: Total Area = 2 × r²(π/6 - √3/4)

Substituting r = 7: Total Area = 2 × 49(π/6 - √3/4) = 98(π/6 - √3/4)

537Quantitative Aptitude
Find the diameter of a spherical ball whose volume is 38.808 cm³ . (Use π = ²²⁄₇ )
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Answer: (D) 4.2 cm

Explanation

The volume V of a sphere is given by the formula V = (4/3) × π × r³, where r is the radius of the sphere.

Substituting V = 38.808 and π = 22/7:

38.808 = (4/3) × (22/7) × r³

38.808 = (88/21) × r³

r³ = (38.808 × 21) / 88

r³ = 0.441 × 21

r³ = 9.261

Taking the cube root on both sides:

r = 2.1 cm

The diameter of the spherical ball is twice the radius:

Diameter = 2 × r = 2 × 2.1 = 4.2 cm.

538Quantitative Aptitude
Twelve men working for 9 hours a day complete a piece of work in 24 days. In how many days can 8 men working for 12 hours a day complete the same piece of work?
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Answer: (B) 27 days

Explanation

The relationship between the number of men (M), days (D), and working hours per day (H) required to complete a constant amount of work is governed by the joint variation formula:

M₁ × D₁ × H₁ = M₂ × D₂ × H₂

Substituting the given values into the formula: M₁ = 12 men, D₁ = 24 days, H₁ = 9 hours M₂ = 8 men, H₂ = 12 hours, and D₂ is the required number of days

12 × 24 × 9 = 8 × D₂ × 12

Dividing both sides by 12: 24 × 9 = 8 × D₂

Solving for D₂: D₂ = (24 × 9) / 8 D₂ = 3 × 9 D₂ = 27 days

539Quantitative Aptitude
How much water should be added to 60 liters of milk at 1½ liters a rupee so as to have a mixture worth 1⅞ liters a rupee?
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Answer: (A) 15 liters

Explanation

The cost price of milk is 1 / 1½ = ⅔ rupees per liter. Since water is free, its cost price is 0 rupees per liter.

The price of the final mixture is 1 / 1⅞ = 8/15 rupees per liter.

By the rule of alligation, the ratio of milk to water in the mixture is: (8/15 - 0) : (⅔ - 8/15) = 8/15 : 2/15 = 4 : 1

This means that for every 4 parts of milk, 1 part of water is added.

Since the quantity of milk is 60 liters, which corresponds to 4 parts, the quantity of water corresponding to 1 part is: 60 × ¼ = 15 liters

540Quantitative Aptitude
A bank charges simple interest for R at the rate of r² for n² years. Another bank charges simple interest for R at the rate of r² for n³ years and gives the same interest. The ratio between K and L is:
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Answer: (C) rn:1

Explanation

Simple interest (SI) is calculated using the formula: SI = (P × R × T) / 100

Let the principal amount for the first bank be K, with a rate of interest r% and time n² years. The simple interest is: SI₁ = (K × r × n²) / 100

Let the principal amount for the second bank be L, with a rate of interest r²% and time n³ years. The simple interest is: SI₂ = (L × r² × n³) / 100

Since the interest earned from both banks is the same: SI₁ = SI₂ (K × r × n²) / 100 = (L × r² × n³) / 100

Canceling the common terms from both sides: K × r × n² = L × r² × n³

To find the ratio between K and L: K / L = (r² × n³) / (r × n²) K / L = rn / 1

Thus, the ratio K : L is rn : 1.

541Quantitative Aptitude
A dozen pairs of gloves of R180 are available at a discount of 10% . How many pairs of gloves can be bought for R 54?
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Answer: (D) 4

Explanation

The marked price of 12 pairs of gloves is ₹180.

At a 10% discount, the selling price for 12 pairs is: 180 × (1 - 0.10) = ₹162

The cost of a single pair of gloves is: 162 ÷ 12 = ₹13.5

The number of pairs of gloves that can be bought for ₹54 is: 54 ÷ 13.5 = 4

542Quantitative Aptitude
A boat can travel 60km downstream in 4 hours. If the speed of the boat in still water is 13 km/h, then in what time will it cover 30 km upstream?
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Answer: (D) 4.2⁸⁄₁₁ hours

Explanation

Downstream speed of the boat is calculated by dividing the downstream distance by the time taken: Downstream speed = 60 / 4 = 15 km/h

The downstream speed is the sum of the speed of the boat in still water and the speed of the stream. Given that the speed of the boat in still water is 13 km/h, we can find the speed of the stream: Speed of the stream = Downstream speed - Speed of boat in still water Speed of the stream = 15 - 13 = 2 km/h

The upstream speed of the boat is the difference between the speed of the boat in still water and the speed of the stream: Upstream speed = 13 - 2 = 11 km/h

The time required to cover 30 km upstream is calculated by dividing the upstream distance by the upstream speed: Time taken = 30 / 11 = 2 8/11 hours

543Quantitative Aptitude
If the diameter of a hemisphere is 21 cm, then the curved surface area (in cm² ) of the hemisphere is: Take π = ²²⁄₇
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Answer: (C) 3.693

Explanation

The curved surface area (CSA) of a hemisphere is given by the formula: CSA = 2πr²

Given that the diameter of the hemisphere is 21 cm, the radius (r) is: r = 21/2 cm

Using the value of π = 22/7, substitute the radius into the formula: CSA = 2 × (22/7) × (21/2)² CSA = 2 × (22/7) × (21/2) × (21/2) CSA = 2 × (22/7) × (441/4) CSA = 11 × 63 CSA = 693 cm²

544Quantitative Aptitude
The ratio of a father's age to his son's age is 7 : 4. The product of the numbers representing their ages is 1372. The ratio of their ages after 8 years will be:
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Answer: (D) 19:12

Explanation

Let the present ages of the father and the son be 7x and 4x respectively.

According to the given condition, the product of their ages is 1372: (7x) × (4x) = 1372 28x² = 1372 x² = 1372 / 28 x² = 49 x = 7

Using the value of x, we find their present ages: Father's present age = 7 × 7 = 49 years Son's present age = 4 × 7 = 28 years

Their ages after 8 years will be: Father's age = 49 + 8 = 57 years Son's age = 28 + 8 = 36 years

The ratio of their ages after 8 years is: 57 : 36 = 19 : 12

545Quantitative Aptitude
The following table shows the production of cars in a company from 2016 to 2020. Years | 2016 | 2017 | 2018 | 2019 | 2020 --- | --- | --- | --- | --- | --- A | 30 | 23 | 39 | 25 | 18 B | 16 | 10 | 14 | 12 | 8 C | 15 | 18 | 19 | 25 | 30 D | 31 | 12 | 21 | 19 | 20 There was a continuous decrease in the production of cars of which types during the period 2018 to 2020?
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Answer: (B) A,B

Explanation

To find the car types with a continuous decrease in production from 2018 to 2020, we analyze the annual production values for each type during these years.

For car Type A, the production values are 39 in 2018, 25 in 2019, and 18 in 2020. This shows a steady decline since 39 > 25 > 18.

For car Type B, the production values are 14 in 2018, 12 in 2019, and 8 in 2020. This also shows a steady decline since 14 > 12 > 8.

Both car types A and B satisfy the condition of continuous decrease in production during this period.

546Quantitative Aptitude
During the first year the population of a village increased by 5% and during the second year it diminished by 5% . At the end of the second year its population was 47,880. What was the population at the beginning of the first year?
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Answer: (C) 3.48000

Explanation

Let P be the population at the beginning of the first year.

According to the given conditions, the population increases by 5% in the first year and decreases by 5% in the second year. The net relationship between the initial population and the population at the end of the second year is given by the formula:

Final Population = P × (1 + 5/100) × (1 - 5/100)

Substituting the given final population of 47,880 into the formula:

47880 = P × 1.05 × 0.95

47880 = P × 0.9975

P = 47880 / 0.9975

P = 48000

Thus, the population at the beginning of the first year was 48,000.

547Quantitative Aptitude
The capacity of a cylinder tank is 8316 cm³ . If the radius of its base is 21 cm , then find the depth of the tank.
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Answer: (A) 6cm

Explanation

The volume of a cylinder is given by the formula V = pi * r² * h. Substituting the volume of 8316 cubic centimeters and radius of 21 centimeters into the formula gives 8316 = (22/7) * 21 * 21 * h, which simplifies to 8316 = 1386 * h. Solving for h gives a depth of 6 centimeters.

548Quantitative Aptitude
What is the value of cos (x + y) - sin (x - y) + tan (2z) ?
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Answer: (C) cos x.cos y - sin x.sin y - sin x.cos y + cos x.sin y + (2tan z)/(1 - tan²z)

Explanation

The trigonometric expansion formulas are: cos(x + y) = cos x cos y - sin x sin y sin(x - y) = sin x cos y - cos x sin y tan(2z) = 2tan z / (1 - tan²z)

Substituting these standard identities into the given expression: cos(x + y) - sin(x - y) + tan(2z) = (cos x cos y - sin x sin y) - (sin x cos y - cos x sin y) + 2tan z / (1 - tan²z)

Expanding the terms and distributing the negative sign yields: cos x cos y - sin x sin y - sin x cos y + cos x sin y + 2tan z / (1 - tan²z)

549Quantitative Aptitude
The perimeter of a minor sector of a circle of radius 4 units subtending an angle of 45° is:
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Answer: (B) 8 + π units

Explanation

The perimeter of a sector of a circle is given by 2r + L, where r is the radius and L is the arc length. For a radius of 4 units and an angle of 45 degrees, the arc length is (45/360) * 2 * pi * 4 = pi, making the total perimeter 2(4) + pi = 8 + pi units.

550Quantitative Aptitude
Mahesh's annual salary increased from ₹2,00,000 to ₹2,40,000. Find the percentage increase in the salary.
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Answer: (C) 3.20%

Explanation

The percentage increase in salary is calculated using the formula:

Percentage Increase = (Increase in Salary / Original Salary) × 100%

Here, the original salary is ₹2,00,000 and the new salary is ₹2,40,000.

The increase in salary is: 2,40,000 - 2,00,000 = ₹40,000

Substituting these values into the formula: Percentage Increase = (40,000 / 2,00,000) × 100% = 20%

This corresponds to the value of 20% in Option C.

Answer key

Tap a number to jump to that question.

  1. 501A
  2. 502D
  3. 503B
  4. 504C
  5. 505D
  6. 506D
  7. 507D
  8. 508C
  9. 509C
  10. 510A
  11. 511B
  12. 512A
  13. 513B
  14. 514C
  15. 515B
  16. 516D
  17. 517A
  18. 518C
  19. 519C
  20. 520C
  21. 521A
  22. 522C
  23. 523D
  24. 524A
  25. 525B
  26. 526C
  27. 527C
  28. 528A
  29. 529B
  30. 530D
  31. 531B
  32. 532B
  33. 533B
  34. 534B
  35. 535C
  36. 536D
  37. 537D
  38. 538B
  39. 539A
  40. 540C
  41. 541D
  42. 542D
  43. 543C
  44. 544D
  45. 545B
  46. 546C
  47. 547A
  48. 548C
  49. 549B
  50. 550C

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