RRB NTPC CBT 1 2026 General Intelligence & Reasoning Questions with Solutions

Explanation

Each letter in the cluster shifts forward by 9 places in alphabetical order. For the first letter: C (3) + 9 = L (12), L + 9 = U (21), U + 9 = D (4), and D + 9 = M (13). For the second letter: L (12) + 9 = U (21), U + 9 = D (4), D + 9 = M (13), and M + 9 = V (22). For the third letter: W (23) + 9 = F (6), F + 9 = O (15), O + 9 = X (24), and X + 9 = G (7).

The numerical part increases by 2 in each consecutive term: 31, 33, 35, 37, so the next number is 37 + 2 = 39. Combining the letters and the number gives MVG 39.

Explanation

When seven people sit around a circular table facing the centre, moving clockwise corresponds to moving left, and moving counter-clockwise corresponds to moving right.

Fixing T at a starting position and moving clockwise: V is at the 1st position to the left (1st clockwise) of T. Q is at the 3rd position to the left (3rd clockwise) of T. S is placed at the 2nd position clockwise from T so that R, sitting 2 positions to the left of S, falls at the 4th position clockwise from T, and U, sitting immediately to the left of R, falls at the 5th position clockwise from T. P takes the remaining seat.

The complete clockwise arrangement is T, V, S, Q, R, U, P. Moving 2 positions counter-clockwise (to the right) from S leads to T.

Explanation

From statement I, Celine scored more than Darpan, and Darpan scored more than both Alok and Bharti, giving the relative order Celine > Darpan > (Alok, Bharti). However, the position of Ema relative to Darpan is unknown, so statement I alone is not sufficient.

From statement II, Celine > Ema > Darpan. Since Alok and Bharti are not mentioned, statement II alone is not sufficient.

Combining statements I and II gives the complete descending order: Celine > Ema > Darpan > (Alok, Bharti). Here, Celine is 1st, Ema is 2nd, and Darpan is uniquely identified as the 3rd highest scorer. Therefore, both statements together are required to answer the question.

Explanation

The pattern in the group adds 5 to the alphabetical position of the first letter to get the second letter (+5), and subtracts 4 from the second letter to get the third letter (-4). For INK, the alphabetical positions are I = 9, N = 14, and K = 11. While I + 5 = N (9 + 5 = 14), N - 4 yields J (10) instead of K (11). Since K is obtained by N - 3, INK deviates from the (+5, -4) rule.

Explanation

The analogy follows a positional shift of +11 forward in the alphabetical series for each corresponding letter.

In the first pair BLT : MWE: B (2) + 11 = M (13) L (12) + 11 = W (23) T (20) + 11 = 31 ≡ E (5)

Applying the same +11 shift to the second pair KUC : VFN: K (11) + 11 = V (22) U (21) + 11 = 32 ≡ F (6) C (3) + 11 = N (14)

Explanation

The pattern follows the rule: (First Number × 3) + 5 = Second Number.

18 × 3 + 5 = 54 + 5 = 59 27 × 3 + 5 = 81 + 5 = 86

Applying the same logic to 37: 37 × 3 + 5 = 111 + 5 = 116

Explanation

The pattern followed in the given sets is the successive subtraction of 35, 20, and 25 from each preceding term:

First set: 180 - 35 = 145 145 - 20 = 125 125 - 25 = 100

Second set: 145 - 35 = 110 110 - 20 = 90 90 - 25 = 65

Applying the same operation rule: 165 - 35 = 130 130 - 20 = 110 110 - 25 = 85

Explanation

The pattern in the given series is based on adding consecutive multiples of 7 to each term:

40 - 33 = 7 (7 × 1) 54 - 40 = 14 (7 × 2) 75 - 54 = 21 (7 × 3) 103 - 75 = 28 (7 × 4)

To find the next term, add the next multiple of 7, which is 35 (7 × 5):

103 + 35 = 138

Explanation

Since only P lives above Y, Y must be on floor 5 and P on floor 6.

Q lives immediately below Y, so Q is on floor 4.

There are three people between Y (floor 5) and Z, which places Z on floor 1.

The remaining vacant floors are 2 and 3. Since R lives on an odd-numbered floor, R must be on floor 3.

This leaves floor 2 for S.

Explanation

In syllogism rules, no definite conclusion can be drawn from two particular affirmative (Some-type) statements sharing a term.

For conclusion (I), hens and eagles are connected through turkeys via two particular statements (Some hens are turkeys and Some turkeys are eagles). Combining two particular premises yields no definite relation between hens and eagles.

For conclusion (II), turkeys and ostriches are linked through hens via two particular statements (Some hens are turkeys and Some hens are ostriches). Sharing a middle term across two particular statements creates no valid overlap between turkeys and ostriches.

Explanation

Let the four letters of the original word be indexed in order as positions 1, 2, 3, 4.

The second word in the sequence is obtained by swapping the 3rd and 4th letters (position order 1, 2, 4, 3). The third word is obtained by swapping the 1st and 2nd letters of the original word (position order 2, 1, 3, 4).

For HIKE (1-H, 2-I, 3-K, 4-E): Swapping the 3rd and 4th letters yields HIEK. Swapping the 1st and 2nd letters yields IHKE.

Explanation

The letter pattern advances each letter position by +8 in alphabetical order: First letter: J (10) + 8 = R (18), R + 8 = Z (26), Z + 8 = H (8), H + 8 = P (16) Second letter: H (8) + 8 = P (16), P + 8 = X (24), X + 8 = F (6), F + 8 = N (14) Third letter: F (6) + 8 = N (14), N + 8 = V (22), V + 8 = D (4), D + 8 = L (12)

The number pattern adds consecutive integers starting from +2: 3 + 2 = 5 5 + 3 = 8 8 + 4 = 12 12 + 5 = 17

Explanation

After dropping all symbols (@, ^, , , #, +, ?) from the series, the remaining sequence of numbers from left to right is:

6, 8, 1, 4, 5, 5, 9, 4, 3, 1, 8

Counting from the right end of this sequence: 1st from right: 8 2nd from right: 1 3rd from right: 3 4th from right: 4 5th from right: 9 6th from right: 5 7th from right: 5

Explanation

Comparing the sets of letters in both words, APES has letters {A, P, E, S} represented by digits {4, 5, 8, 3}, and PEAT has letters {P, E, A, T} represented by digits {6, 4, 3, 8}.

The letters A, P, and E are common to both words, which correspond to the common digits 4, 8, and 3. Removing these common elements leaves letter S as the only unique letter in APES and digit 5 as the only unique digit in 4583. Thus, S is coded as 5.

Explanation

Comparing the words 'TIER' (coded as 2735) and 'TIME' (coded as 3475), the letters T, I, and E are common to both, corresponding to the common digits 3, 5, and 7. The letter 'M' is present only in 'TIME', and the digit '4' is present only in its code 3475. Therefore, the code for 'M' is 4.

Explanation

The given statements establish that gardens are completely contained within forests, which are in turn completely contained within meadows. The negative condition specifies only that gardens and parks share no elements.

This restriction applies exclusively to gardens. The portion of forests outside of gardens can still overlap with parks, so conclusion (I) does not definitely hold. Similarly, the portion of meadows outside of gardens can also overlap with parks, so conclusion (II) does not definitely hold. Since a valid conclusion must hold true in all possible cases, neither conclusion logically follows.

Explanation

Floor 5 is occupied by S, and since X lives above S, X must be on floor 6.

Only U lives below Y, which places Y on floor 2 and U on floor 1.

The remaining unoccupied floors are 3 and 4 for the remaining people Z and T. Since Z lives on an even-numbered floor, Z must be on floor 4, leaving T on floor 3.

With Z positioned on floor 4, exactly three people (on floors 1, 2, and 3) live below Z.

Explanation

The pattern in the series is based on decreasing differences between consecutive terms:

65 - 45 = 20 81 - 65 = 16 93 - 81 = 12 101 - 93 = 8

The differences decrease by 4 at each step (20, 16, 12, 8). Following this pattern, the next difference is 8 - 4 = 4.

101 + 4 = 105

Explanation

Dropping all the letters (R, C, E, K, D, T, Y, G, S) from the given series leaves the remaining sequence of symbols and numbers: % * 3 6 7 @ 2 # 4 5

Counting the non-letter elements starting from the right end, the first element is , the second is 5, the third is 4, and the fourth element from the right is #.

Explanation

The pattern follows the addition of a constant number, 92, to the first number to obtain the second number:

52 + 92 = 144 81 + 92 = 173

Applying the same operation to 63:

63 + 92 = 155

Explanation

Numbering the seven positions around the circular table from 1 to 7 in a clockwise direction with everyone facing the center:

Placing S at position 1: B sits second to the right of S, placing B at position 3. Q sits third to the left of S, placing Q at position 5. Since two people sit between P and R when counting clockwise from R, R is at position 4 and P is at position 7. C is an immediate neighbor of P, placing C at position 6. The remaining position 2 is occupied by O.

The clockwise order of positions from 1 to 7 is S, O, B, R, Q, C, P. Facing the center from position 2, the immediate left of O is S and the immediate right of O is B.

Explanation

When the digits of the number 52697148 are arranged in descending order from left to right, the new number formed is 98765421.

In this new number: Digit third from the left = 7 Digit second from the right = 2

Product = 7 × 2 = 14

Explanation

Decoding the given expression P + Q - R × S + T step by step:

P + Q means P is the brother of Q. Q - R means Q is the father of R. R × S means R is the husband of S, making R and S a married couple. S + T indicates that S and T are siblings, placing T in the same generation as S, with R as T's father.

Tracing the relationship from T to P: R is the father of T. Q is the father of R, which makes Q the father's father (paternal grandfather) of T. P is the brother of Q.

Therefore, P is T's Father's Father's Brother.

Explanation

The series follows a pattern where consecutive prime numbers are subtracted from each term:

55 - 2 = 53 53 - 3 = 50 50 - 5 = 45 45 - 7 = 38

The next prime number in the sequence after 7 is 11. Subtracting 11 from 38 yields:

38 - 11 = 27

Explanation

The seven positions from top (7) to bottom (1) are determined as follows:

Since only E is kept above G, E is at position 7 and G is at position 6. Since no box is kept below B, B is at position 1. With two boxes kept between D and B, D is at position 4. Placing the remaining boxes such that A is below C and above F gives C at position 5, A at position 3, and F at position 2.

The final arrangement from top to bottom is E, G, C, D, A, F, B.

Between B (position 1) and G (position 6), there are 4 boxes: F, A, D, and C.

Explanation

The logic followed in the given sets is: Second number = (First number × 4) + 1.

For (18, 73): (18 × 4) + 1 = 72 + 1 = 73 For (23, 93): (23 × 4) + 1 = 92 + 1 = 93

Applying the same rule to 26 gives (26 × 4) + 1 = 104 + 1 = 105.

Explanation

Replacing the mathematical operators according to the given rules: is replaced by × ÷ is replaced by +

• is replaced by - × is replaced by ÷

The expression becomes: 316 × 2 + 37 - 436 ÷ 4

Applying the BODMAS rule: First, perform division: 436 ÷ 4 = 109 Next, perform multiplication: 316 × 2 = 632 Finally, perform addition and subtraction: 632 + 37 - 109 = 669 - 109 = 560

Explanation

Arranging the seven positions from top (1) to bottom (7):

Since only R is kept above A, R is at position 1 and A is at position 2. Since only E is kept below N, N is at position 6 and E is at position 7. Since two boxes are kept between A (2) and S, S is at position 5. Since T is not kept immediately above S (position 4), T is at position 3 and P is at position 4.

The final stack from top to bottom is R, A, T, P, S, N, E.

P is at position 4 and E is at position 7, so the boxes between P and E are S (position 5) and N (position 6), which gives a count of two boxes.

Explanation

Comparing both statements, 'mobile' is the only word common to 'repair the mobile' and 'mobile is lost'. Similarly, 'gf' is the only code common to both 'gf ed Is' and 'sq gf tf'. Thus, the code for 'mobile' is 'gf'.

Explanation

Comparing the letters in MILE (M, I, L, E) and TIME (T, I, M, E), the common letters are M, I, and E.

Comparing their given numeric codes, 9574 and 5429, the common digits are 9, 5, and 4.

The letter T is unique to TIME, and the digit unique to its code 5429 is 2. Thus, the code for T is 2.

Explanation

Statement I gives the inequality Cargo > Bravo > Alpha. Statement II gives the inequality Echo > Delta > Bravo.

Combining both statements, Cargo, Echo, and Delta are all heavier than Bravo, while Alpha is lighter than Bravo. Since Alpha is lighter than Bravo and every other parcel (Cargo, Delta, Echo) is heavier than Bravo, Alpha is the lightest parcel among all five. Neither statement alone accounts for all five parcels, but together they uniquely identify Alpha as the lightest.

Explanation

From top to bottom, let the seven positions be numbered 1 to 7.

Since three boxes are kept above N, N is at position 4. A is placed above N, so A is at position 2. With three boxes between H and A, H must be at position 6.

R is placed immediately below A at position 3. J is not adjacent to H (positions 5 or 7), so J is at position 1. C is kept above G, placing C at position 5 and G at position 7.

The complete order from top to bottom is J, A, R, N, C, H, G. Since H is at position 6, there are 5 boxes kept above H.

Explanation

The letter-clusters in the group follow a positional pattern of +4 and -2 between consecutive letters in the English alphabet. CHE departs from this group rule, as the positions of its letters (C = 3, H = 8, E = 5) follow a pattern of +5 and -3.

Explanation

In this series, the second letter in each cluster is 4 positions ahead of the first letter, and each letter in the second cluster is 3 positions ahead of the corresponding letter in the first cluster. In YC-BE, the position difference between B and E is 3 instead of 4, and shifting C forward by 3 positions yields F rather than E.

Explanation

The second digit from the left in the original number 8134576 is 1. Since 1 is an odd digit, adding 1 to it gives 1 + 1 = 2.

Explanation

The relationship between the given numbers follows the rule where the first number is obtained by multiplying the second number by 9:

First Number = Second Number × 9

Verifying with the given pairs: 12 × 9 = 108 26 × 9 = 234

Applying the same logic for 198: 198 ÷ 9 = 22

Explanation

Decoding the given expression G # N # V + K # T step-by-step: G # N implies G is the daughter of N, making N the mother of G. N # V implies N is the daughter of V. V + K implies V is the mother of K. K # T implies K is the daughter of T.

Since V is the mother of K and K is the daughter of T, T must be the father of K and husband of V. Consequently, T is also the father of N. Since N is the mother of G and T is the father of N, T is G's mother's father.

Explanation

Since all liquid is water and all water is juice, by the transitive property of set inclusions, all liquid is necessarily juice. Thus, conclusion (I) logically follows. Conclusion (II) does not follow because a partial overlap between juice and syrup does not guarantee any direct intersection between syrup and liquid.

Explanation

The pattern followed in each pair of letter-clusters is a forward shift of 7 positions (+7) for each letter in the alphabetical order.

For the left pair, replacing # with DNV: D (+7) = K N (+7) = U V (+7) = C (22 + 7 = 29, which wraps around to 3/C)

For the right pair, replacing % with CMU: V (+7) = C F (+7) = M N (+7) = U

Both pairs follow the identical transformation rule across all three letters.

Explanation

Lg is the daughter of Dv, and Qb is the brother of Lg, which means Qb is the son of Dv. Since Jq is the daughter of Qb, Jq is the daughter of Dv's son, making her Dv's son's daughter.

Explanation

The pattern between the letter-cluster pairs is a positional shift of +1, +2, and +3 for the first, second, and third letters respectively.

Applying the shift to BET gives CGW: B (+1) = C E (+2) = G T (+3) = W

Applying the same shift of +1, +2, +3 to LDM gives: L (+1) = M D (+2) = F M (+3) = P

Explanation

The pattern of mathematical operations across the numbers in each set is: First number to second number: Square the number (x²) Second number to third number: Add 20 (+ 20) Third number to fourth number: Multiply by 3 (× 3)

For the first set: 8² = 64, 64 + 20 = 84, and 84 × 3 = 252. For the second set: 12² = 144, 144 + 20 = 164, and 164 × 3 = 492.

Applying the same set of operations starting with 5: 5² = 25 25 + 20 = 45 45 × 3 = 135

Explanation

The pattern in the series is formed by adding consecutive prime numbers to each preceding term:

98 + 2 = 100 100 + 3 = 103 103 + 5 = 108 108 + 7 = 115

The sequence of added values (2, 3, 5, 7) consists of consecutive prime numbers. The next prime number in this sequence is 11.

115 + 11 = 126

Explanation

From the given statements, all sand is stone and all sand is cement. Since sand is entirely contained within both stone and cement, the area occupied by sand forms a common intersection between cement and stone, which guarantees that some cements are stone. Therefore, conclusion (II) logically follows.

Statement 3 specifies that some cements are mud, establishing an overlap between cement and mud. However, mud can intersect cement entirely outside the portion containing sand, so conclusion (I) does not necessarily follow.

Explanation

Let Point A be at the coordinate origin (0, 0).

After driving 22 km East, the coordinates are (22, 0). Taking a right turn and driving 17 km South gives (22, -17). Turning right and driving 31 km West gives (22 - 31, -17) = (-9, -17). Turning right and driving 19 km North gives (-9, -17 + 19) = (-9, 2). Taking a final right turn and driving 9 km East brings him to Point P at (-9 + 9, 2) = (0, 2).

To reach Point A (0, 0) from Point P (0, 2), he must travel 2 km directly towards South.

Explanation

The series follows a fixed pattern for both the letters and numbers:

For the numbers: 54, 61, 68, 75, ... Each number increases by 7: 75 + 7 = 82

For the letters, each position in the letter group decreases by 5 moving backward in the alphabet:

First letter: S (19) - 5 = N (14) - 5 = I (9) - 5 = D (4) - 5 = Y (25) Second letter: T (20) - 5 = O (15) - 5 = J (10) - 5 = E (5) - 5 = Z (26) Third letter: Q (17) - 5 = L (12) - 5 = G (7) - 5 = B (2) - 5 = W (23)

Combining the letter cluster and number gives YZW 82.

Explanation

A number is immediately preceded by a number and immediately followed by a number if it is the middle digit of three consecutive numbers in the given series.

Examining the contiguous number sequences from left to right: In 9 2 9, the number 2 is preceded by 9 and followed by 9. In 4 9 8 2 9, the number 9 is preceded by 4 and followed by 8, the number 8 is preceded by 9 and followed by 2, and the number 2 is preceded by 8 and followed by 9. In 6 8 6 7, the number 8 is preceded by 6 and followed by 6, and the number 6 is preceded by 8 and followed by 7.

This gives a total count of 6 such numbers.

Explanation

The series follows two distinct patterns for the numbers and the letters:

For the numbers, 14 is added at each step: 14, 28, 42, 56, 70 (14 × 5 = 70)

For the positional values of the letters (A = 1, B = 2, ..., Z = 26): First letter decreases by 12 each step: U(21) → I(9) → W(23) → K(11) → Y(25) Second letter increases by 14 each step: B(2) → P(16) → D(4) → R(18) → F(6) Third letter increases by 14 each step: E(5) → S(19) → G(7) → U(21) → I(9)

Combining the letters and the number gives YFI 70.

Explanation

Let the seven positions around the circular table be numbered 1 to 7 in clockwise order. Since all individuals face the centre, moving clockwise corresponds to moving left, and moving counter-clockwise corresponds to moving right.

Placing C at position 1: F sits third to the left (clockwise) of C, so F is at position 4. C is an immediate neighbour of both A and G, meaning A and G occupy positions 2 and 7. D sits to the immediate right (counter-clockwise) of G. If G were at position 2, the seat to its immediate right would be position 1 (occupied by C), which is invalid. Therefore, G is at position 7, placing D at position 6, and A at position 2. G sits second to the left of B, which means B is two seats behind G in clockwise direction, putting B at position 5. The remaining seat, position 3, is occupied by E.

The full arrangement clockwise from position 1 to 7 is C, A, E, F, B, D, G.

Counting from the right of C (counter-clockwise from position 1), the order of seats is position 7 (G), position 6 (D), and position 5 (B). Thus, exactly 2 people (G and D) sit between B and C.

Explanation

The pattern follows a sequential alphabetical shift of -1, -2, -3, and -4 applied to each corresponding position:

F (-1) = E, K (-2) = I, E (-3) = B, P (-4) = L J (-1) = I, M (-2) = K, H (-3) = E, T (-4) = P

Applying the same logic to PQNW: P (-1) = O Q (-2) = O N (-3) = K W (-4) = S

This gives OOKS.