RRB NTPC CBT 1 2026 General Intelligence & Reasoning Questions with Solutions

Explanation

From Statement I, Mona > Leena > Kriti, but information about Pooja and Reema is missing.

From Statement II, Leena > Pooja > Kriti, but information about Mona and Reema is missing.

Combining both statements yields Mona > Leena > Pooja > Kriti. Since neither statement provides any information regarding Reema's age, Reema could be older or younger than Kriti. Therefore, it is impossible to determine who among the five cousins is the youngest.

Explanation

The pattern in the series involves adding decreasing squares of natural numbers to consecutive terms:

124 - 99 = 25 = 5² 140 - 124 = 16 = 4² 149 - 140 = 9 = 3² 153 - 149 = 4 = 2²

To find the missing term, add 1² = 1 to the last term: 153 + 1 = 154

Explanation

From the given statements, all papers are contained within books, and all books are contained within erasers (Papers ⊂ Books ⊂ Erasers). The fact that some erasers are crayons only guarantees an overlap between the set of erasers and crayons. This overlap may lie entirely outside the subsets of books and papers, so no definite relationship exists between papers and crayons, or between books and crayons.

Explanation

Removing all letters from the series leaves only numbers and symbols in the following order from left to right: 8, 6, *, @, 9, 5, 8, 7, 2, | .

Counting these remaining elements from left to right: 8 is 1st, 6 is 2nd, * is 3rd, @ is 4th, and 9 is 5th.

Explanation

Arranging the seven boxes from top to bottom (position 7 down to position 1) based on the given conditions:

Only G is kept above C, placing G at position 7 (top) and C at position 6. Only E is kept between C and F, placing E at position 5 and F at position 4. Only D is kept below B, placing B at position 2 and D at position 1 (bottom). Box A occupies the remaining position 3.

The order from top to bottom is G, C, E, F, A, B, D. Positioned at 4th from top, box F has three boxes (A, B, and D) kept below it.

Explanation

In the letter cluster pair RT-VX, the alphabetical position values are R = 18, T = 20, V = 22, and X = 24. The positional difference between the last letter of the first cluster (T) and the first letter of the second cluster (V) is +2, creating a uniform pattern of +2, +2, +2 across all four positions. In contrast, the other pairs follow a pattern of +2, +1, +2, where the gap between the two clusters is +1.

Explanation

W is the wife of A, which makes W female and A male. A is the father of M, and M is the brother of P, making P the daughter of W. P is the mother of I, and since I is the sister of R who is the father of E, R is male and the son of P. Therefore, R is W's daughter's son.

Explanation

We need to find symbols that follow the pattern: Number + Symbol + Number.

Scanning the given sequence from left to right: 6 2 @ # | * % ~ 7 = Ω 1 8 ? ∈ § 4 3 5 + 9

Checking each symbol: @ is preceded by 2 and followed by # is preceded by @ and followed by | | is preceded by # and followed by *

• is preceded by | and followed by % % is preceded by * and followed by ~ ~ is preceded by % and followed by 7 = is preceded by 7 and followed by Ω Ω is preceded by = and followed by 1 ? is preceded by 8 and followed by ∈ ∈ is preceded by ? and followed by § § is preceded by ∈ and followed by 4

• is preceded by 5 and followed by 9

Only the symbol '+' fulfills the condition of being immediately preceded by a number (5) and immediately followed by another number (9), giving a total of one such symbol.

Explanation

Placing O on Sunday (last day) and keeping three people between I and O places I on Wednesday.

To have exactly one person between F and H, they must be placed on Tuesday and Thursday with Wednesday (I) between them. Since N has an exam immediately before M, the NM block must occupy Friday and Saturday respectively. This leaves Monday for G.

The complete schedule from Monday to Sunday is: G (Mon), F/H (Tue), I (Wed), H/F (Thu), N (Fri), M (Sat), and O (Sun).

The three people with exams between G (Monday) and N (Friday) are scheduled on Tuesday, Wednesday, and Thursday.

Explanation

Tracking Vihaana's movements step-by-step using coordinates relative to the starting point (0, 0):

Walks 11 km North: (0, 11) Turns left (West) and walks 7 km: (-7, 11) Turns left (South) and walks 11 km: (-7, 0) Turns right (West) and walks 2 km to reach point R: (-9, 0)

Point R is located 9 km along the negative x-axis, which corresponds to 9 km West from the starting point.

Explanation

Let positions 1 to 7 represent the arrangement from left to right:

Position of N is 3 since only two people sit to its left.

Position of E is 5 as E sits second to the right of N.

Position of P is 2 as exactly two people sit between E and P.

Position of C is 7 as exactly three people sit between N and C.

The remaining vacant positions are 1, 4, and 6. Since O sits to the right of Q and to the left of D, Q must be at position 1, O at position 4, and D at position 6.

The final arrangement from left to right is Q, P, N, O, E, D, C.

O is at position 4, leaving positions 5, 6, and 7 (E, D, C) to its right, making a total of three people sitting to the right of O.

Explanation

The pattern follows a positional increment of +2, +3, +4, and +5 for consecutive letters in the English alphabet:

W (+2) = Y, E (+3) = H, L (+4) = P, D (+5) = I A (+2) = C, K (+3) = N, T (+4) = X, N (+5) = S

Applying the same logic to EQBX: E + 2 = G Q + 3 = T B + 4 = F X + 5 = C (wrapping around from Z to A)

Explanation

The relationship between the letter-clusters is based on adding 11 to the alphabetical position of each letter, wrapping around after Z (position 26).

For the left side, CMU transforms into NXF as C (3) + 11 = N (14), M (13) + 11 = X (24), and U (21) + 11 = 32 - 26 = F (6).

Applying the exact same rule to JTB on the right side yields UEM as J (10) + 11 = U (21), T (20) + 11 = 31 - 26 = E (5), and B (2) + 11 = M (13).

Explanation

To find the letters that are immediately preceded by a symbol and immediately followed by a symbol, we look for the pattern: Symbol - Letter - Symbol.

Analyzing the given series from left to right: L is preceded by ∈ and followed by ∈ (∈ L ∈) O is preceded by ∈ and followed by (∈ O ) S is preceded by ∈ and followed by # (∈ S #) T is preceded by # and followed by (# T ) M is preceded by ⊙ and followed by @ (⊙ M @) L is preceded by and followed by ( ( L () E is preceded by ( and followed by ( (( E ()

There are 7 such letters in total.

Explanation

Original number: 7834126 Ascending order: 1234678

Comparing digit positions from left to right: Position 1: 7 → 1 Position 2: 8 → 2 Position 3: 3 → 3 (Unchanged) Position 4: 4 → 4 (Unchanged) Position 5: 1 → 6 Position 6: 2 → 7 Position 7: 6 → 8

The digits at the 3rd position (3) and 4th position (4) remain in the exact same positions as in the original number, giving a total of 2 digits.

Explanation

Combining the statements "Some goats are dogs" and "All dogs are tigers" logically implies that the goats that are dogs are also tigers, which means "Some tigers are goats" is definitely true. Thus, conclusion (II) follows. The relationship between cows and dogs is not given, so conclusion (I) does not follow. Therefore, only conclusion (II) follows.

Explanation

The series follows two distinct addition patterns for the letters and numbers:

For the letters, each corresponding letter moves forward by 3 positions in the alphabetical order: First letter: J (+3) -> M (+3) -> P (+3) -> S (+3) -> V Second letter: M (+3) -> P (+3) -> S (+3) -> V (+3) -> Y Third letter: O (+3) -> R (+3) -> U (+3) -> X (+3) -> A

For the numbers, 11 is added to each term: 50 + 11 = 61 61 + 11 = 72 72 + 11 = 83 83 + 11 = 94

Combining the results yields VYA 94.

Explanation

The pattern of mathematical operations between consecutive numbers in each set is: 1st number to 2nd number: Multiply by 2 (or add the first number to itself) 2nd number to 3rd number: Add 20 3rd number to 4th number: Add 30

In the given sets: 12 × 2 = 24; 24 + 20 = 44; 44 + 30 = 74 18 × 2 = 36; 36 + 20 = 56; 56 + 30 = 86

Applying the same rule to 15 – 30 – 50 – 80: 15 × 2 = 30 30 + 20 = 50 50 + 30 = 80

Explanation

The given series follows a dual pattern for the letter clusters and the numbers:

Letter Cluster Pattern: Each letter in the cluster moves 3 steps backward in the alphabetical order: First letter: L (12) - 3 = I (9), I (9) - 3 = F (6), F (6) - 3 = C (3), C (3) - 3 = Z (26) Second letter: J (10) - 3 = G (7), G (7) - 3 = D (4), D (4) - 3 = A (1), A (1) - 3 = X (24) Third letter: L (12) - 3 = I (9), I (9) - 3 = F (6), F (6) - 3 = C (3), C (3) - 3 = Z (26) The resulting letter cluster is ZXZ.

Number Pattern: The numbers decrease by 8 at each step: 62 - 8 = 54 54 - 8 = 46 46 - 8 = 38 38 - 8 = 30

Combining the letter cluster and number gives ZXZ 30.

Explanation

The pattern adds 14 to the sum of the reverse alphabetical positional values (where A = 26, B = 25, ..., Z = 1) of the letters.

For OENI: Reverse positions = 12 + 22 + 13 + 18 = 65 Code = 65 + 14 = 79

For WASR: Reverse positions = 4 + 26 + 8 + 9 = 47 Code = 47 + 14 = 61

For QJTD: Reverse positions = 10 + 17 + 7 + 23 = 57 Code = 57 + 14 = 71

Explanation

Comparing the words 'TOUR' and 'AUTO', the common letters are T, O, and U. Comparing their respective codes '3894' and '5489', the common digits are 8, 9, and 4.

Eliminating these common elements leaves the letter 'A' in 'AUTO' and the digit '5' in '5489', which directly gives the code for 'A' as 5.

Explanation

Combining "All tea is brunch" and "All brunches are dinner" gives "All tea is dinner", which makes Conclusion (I) logically follow.

Since "All tea is a snack" and "All tea is brunch", the entity "tea" is entirely contained within both the set of snacks and the set of brunches. This ensures a direct overlap between brunches and snacks in the region of tea, which makes Conclusion (II) logically follow.

Explanation

The underlying pattern follows the relation n → n² + 1.

For 9: 9² + 1 = 81 + 1 = 82 For 17: 17² + 1 = 289 + 1 = 290

Applying the same relation to 33: 33² + 1 = 1089 + 1 = 1090

Explanation

Number seven positions from 1 to 7 in a clockwise direction around the table. Since everyone is facing the centre, moving clockwise corresponds to moving left, and moving counter-clockwise corresponds to moving right.

Placing H at position 1, V sits fourth to the left (clockwise) of H at position 5. Since H is to the immediate right (counter-clockwise) of W, W is at position 2. Since three people sit between W and X, X is at position 6. G sitting to the immediate right of I places I at position 4 and G at position 3. The remaining position 7 is occupied by F.

The clockwise order of people is H (1), W (2), G (3), I (4), V (5), X (6), and F (7). Counting from the left (clockwise) of I, the people between I and F are V and X, making a total of 2 people.

Explanation

In the standard English alphabetical order, the letter clusters in this group follow a sequential addition pattern of +3 and +4 between consecutive letters. JMP deviates from this rule as its letters advance by +3 and +3, with J being the 10th letter, M the 13th letter (10 + 3), and P the 16th letter (13 + 3).

Explanation

The differences between consecutive terms in the series follow the sequence of squares of natural numbers:

36 − 35 = 1 = 1² 40 − 36 = 4 = 2² 49 − 40 = 9 = 3² 65 − 49 = 16 = 4²

Adding 5² (25) to the last term: 65 + 25 = 90

Explanation

The logical pattern connecting the first number (x) to the second number (y) is: y = (x ÷ 4) + 4

For the pair 72 and 22: (72 ÷ 4) + 4 = 18 + 4 = 22

For the pair 132 and 37: (132 ÷ 4) + 4 = 33 + 4 = 37

Applying the same logic to 108: (108 ÷ 4) + 4 = 27 + 4 = 31

Explanation

The series follows a clear arithmetic progression for each component:

For the first letter, the positional values decrease by 2 in each step: J (10) → H (8) → F (6) → D (4) → B (2).

For the second letter, the positional values decrease by 2: V (22) → T (20) → R (18) → P (16) → N (14).

For the third letter, the positional values decrease by 2: O (15) → M (13) → K (11) → I (9) → G (7).

For the number, 6 is added in each step: 5 → 11 → 17 → 23 → 29.

Combining these gives BNG 29.

Explanation

The pattern follows a constant positional shift of -8 for each letter in the alphabetical series:

First pair (JGC : BYU): J (10) - 8 = 2 (B) G (7) - 8 = 25 (Y) C (3) - 8 = 21 (U)

Second pair (GDZ : YVR): G (7) - 8 = 25 (Y) D (4) - 8 = 22 (V) Z (26) - 8 = 18 (R)

Replacing # with JGC and % with YVR satisfies the same -8 letter transformation rule on both sides of the proportion.

Explanation

Breaking down the given expression step by step:

D × N means D is the wife of N, making D female and N male. N % P means N is the father of P. Since D is married to N, D is the mother of P. P + K means P is the mother of K (female). K # E means K is the daughter of E. Since P is already the mother of K, E must be the father of K and the husband of P.

Therefore, P is the wife of E, and D is the mother of P. Thus, D is E's wife's mother.

Explanation

The standard pattern for the letter clusters in this group is to add 4 to the alphabetical position of the first letter to get the second letter, and then add 5 to get the third letter (+4, +5). In JNT, the positional values are J = 10, N = 14, and T = 20, which follows a +4, +6 pattern (10 + 4 = 14, 14 + 6 = 20) instead of +4, +5.

Explanation

To find the required symbols, look for the pattern: Letter - Symbol - Number.

Scanning the given series from left to right: K % 7 (where K is a letter, % is a symbol, and 7 is a number) S | 6 (where S is a letter, | is a symbol, and 6 is a number) T # 3 (where T is a letter, # is a symbol, and 3 is a number)

There are three such symbols in the series that meet both conditions.

Explanation

The given series follows two distinct patterns for the letter clusters and the numbers:

For the letter clusters, each letter moves forward by 5 positions in alphabetical order: First letters: T (20) + 5 = Y (25) + 5 = D (4) + 5 = I (9) + 5 = N (14) Second letters: W (23) + 5 = B (2) + 5 = G (7) + 5 = L (12) + 5 = Q (17) Third letters: U (21) + 5 = Z (26) + 5 = E (5) + 5 = J (10) + 5 = O (15)

For the numbers, each term decreases by 8: 89 - 8 = 81 81 - 8 = 73 73 - 8 = 65 65 - 8 = 57

Combining both patterns yields NQO 57.

Explanation

Comparing the letters in SEMI and TIME, the common letters are E, M, and I. Comparing their code digits {3, 6, 1, 5} and {1, 5, 2, 3}, the common digits are 1, 3, and 5. Therefore, the letter set {E, M, I} corresponds to the digit set {1, 3, 5}. In TIME, the only remaining letter is T, which corresponds to the only remaining digit 2.

Explanation

The relation among the numbers in each set (A, B, C) is given by the formula: B = 2 × (A - C)

Applying this to the given sets: 2 × (19 - 7) = 2 × 12 = 24 2 × (12 - 5) = 2 × 7 = 14

Similarly, for (3, 4, 1): 2 × (3 - 1) = 2 × 2 = 4

Explanation

The pattern follows a sequence of alternating addition and subtraction of increasing integers (+1, -2, +3, -4) applied to the alphabetical positions of each letter:

1st letter: +1 2nd letter: -2 3rd letter: +3 4th letter: -4

Applying this rule to the given pairs: D (+1) = E, M (-2) = K, K (+3) = N, Z (-4) = V L (+1) = M, O (-2) = M, J (+3) = M, T (-4) = P

Applying the same pattern to SRLQ: S (+1) = T R (-2) = P L (+3) = O Q (-4) = M

Explanation

Since no one lives above D, D lives on Floor 6. Two people live between D and C, which places C on Floor 3. Q lives below C but above N, placing Q on Floor 2 and N on Floor 1. Two people live between O and Q (Floor 2), placing O on Floor 5. The remaining person, P, lives on Floor 4.

The floor arrangement from top to bottom (6 to 1) is D, O, P, C, Q, N. Between P on Floor 4 and N on Floor 1, two people (C on Floor 3 and Q on Floor 2) reside.

Explanation

The pattern followed in both letter-cluster pairs is a constant positional shift of -3 applied to each letter in alphabetical order.

For the left pair (# : EGC) with # = HJF: H (-3) = E J (-3) = G F (-3) = C

For the right pair (QSO : %) with % = NPL: Q (-3) = N S (-3) = P O (-3) = L

Both pairs follow the identical transformation pattern of moving each letter backward by 3 positions in the alphabet.

Explanation

Arranging the 7 positions clockwise (1 to 7) facing the centre:

Placing B at position 1, two people sit to the left of B (clockwise), placing F at position 4. A sits second to the left of F (clockwise), placing A at position 6. A is to the immediate right of E (counter-clockwise), placing E at position 7. G sits third to the left of E (clockwise), placing G at position 3. D is an immediate neighbour of G, placing D at position 2. The remaining person C takes position 5.

The clockwise order of seats is B, D, G, F, C, A, E.

Counting from the right of G (counter-clockwise from position 3 to position 6), the people sitting between G and A are D, B, and E, which gives a count of 3 people.

Explanation

The pattern follows an alphabetical positional increment of +3 for the first letter, +2 for the second letter, and +1 for the third letter.

In FKM to IMN, F + 3 = I, K + 2 = M, and M + 1 = N. In BAL to ECM, B + 3 = E, A + 2 = C, and L + 1 = M.

Applying the same pattern to OME gives O + 3 = R, M + 2 = O, and E + 1 = F, resulting in ROF.

Explanation

Let the cost price (CP) be ₹100.

Marked Price (MP) = 100 + 160% of 100 = ₹260

Selling Price (SP) needed for a 30% gain = 100 + 30% of 100 = ₹130

Discount required = MP − SP = 260 − 130 = ₹130

Discount percentage = (Discount / MP) × 100 = (130 / 260) × 100 = 50%

Explanation

The pattern in the series is based on subtracting the squares of decreasing consecutive integers:

65 - 5² = 65 - 25 = 40 40 - 4² = 40 - 16 = 24 24 - 3² = 24 - 9 = 15 15 - 2² = 15 - 4 = 11 11 - 1² = 11 - 1 = 10

Explanation

From Statement I, T is taller than M, which is taller than L (T > M > L). This does not provide information about N or V, so Statement I alone is not sufficient.

From Statement II, N is taller than L, which is taller than V (N > L > V). This does not provide information about M or T, so Statement II alone is not sufficient.

Combining both statements gives T > M > L > V and N > L. This indicates that both T and N are taller than L, but it gives no relationship between T and N. Since either T or N could be the tallest tree, the two statements together are still not sufficient.

Explanation

Arrange the days from Monday to Sunday based on the given information: Thursday is assigned to G, and Saturday is assigned to H.

Since N is immediately before F, and O is immediately after F, they form a consecutive three-day block (N, F, O). The only available three consecutive vacant days are Monday, Tuesday, and Wednesday. Monday = N Tuesday = F Wednesday = O

The remaining vacant days are Friday and Sunday. Since M has an exam on a day after I, Friday is assigned to I and Sunday is assigned to M.

The complete schedule is Monday (N), Tuesday (F), Wednesday (O), Thursday (G), Friday (I), Saturday (H), and Sunday (M).

Between O (Wednesday) and M (Sunday), there are three people: G, I, and H.

Explanation

In late 2025, the Polar Satellite Launch Vehicle (PSLV) became the first launch vehicle in India to be fully built and assembled by industry partners end-to-end. Manufactured by a consortium of Hindustan Aeronautics Limited (HAL) and Larsen | Toubro (L | T) under a contract with ISRO's commercial arm, NewSpace India Limited (NSIL), the rocket was produced to carry the Oceansat earth observation satellite into orbit.

Explanation

Comparing the letters in CARD and DRAW, the common letters are A, R, and D. Comparing their given codes 6135 and 1765, the common digits are 1, 5, and 6. Thus, the set {A, R, D} corresponds to {1, 5, 6} in some order. The only unique letter remaining in DRAW is W, which directly matches the remaining unique digit 7.

Explanation

The pattern followed in the given sets is that the middle number is the product of the first and third numbers:

First number × Third number = Second number

Set 1: 44 × 22 = 968 Set 2: 26 × 25 = 650

Similarly, 18 × 6 = 108.

Explanation

The Mahar Movement in Maharashtra was a major socio-political struggle led by Dr. B.R. Ambedkar for Dalit rights, dignity, and social equality. Originating in the late 19th century through early reformist efforts by Gopal Baba Walangkar and Shivram Janba Kamble, the movement was systematically organized in the 1920s under Dr. Ambedkar. It mobilized the Mahar community to fight institutionalized untouchability, demand access to public water resources (as in the historic Mahad Satyagraha of 1927), secure political representation, promote modern education, and assert full socio-political equality.

Explanation

Arranging the given numbers in ascending order gives 167, 173, 187, 199, and 257.

The second highest number is 199, and its second digit is 9. The second lowest number is 173, and its third digit is 3.

Adding the two digits gives 9 + 3 = 12.

Explanation

The pattern followed in the given pairs is: second number = (first number × 5) - 1.

For (14, 69): (14 × 5) - 1 = 70 - 1 = 69 For (18, 89): (18 × 5) - 1 = 90 - 1 = 89

Applying the same operation to 22: (22 × 5) - 1 = 110 - 1 = 109.