RRB NTPC2021MathematicsPage 4 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 151–200 of 1,785, each with the correct answer and a step-by-step explanation.

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151Mathematics
A sum of money was lent on compound interest. It became ₹500 at the end of the first year and ₹550 at the end of second year. Find the rate of compound interest per annum.
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Answer: (D) 10%

Explanation

In compound interest, the amount at the end of the first year serves as the principal for the second year.

Interest earned during the second year = Amount after 2nd year - Amount after 1st year = ₹550 - ₹500 = ₹50

Rate of interest per annum = (Interest in 2nd year / Amount after 1st year) × 100 = (50 / 500) × 100 = 10% per annum.

152Mathematics
371¹ + 372¹ + 373¹ + 374¹ + 375¹ is divisible by:
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Answer: (A) 5

Explanation

Sum of five consecutive terms of an arithmetic progression is given by 5 × middle term.

Here, the middle term is 373 and the number of terms is 5.

Sum = 5 × 373 = 1865

Since 5 is a prime factor of the product, the sum is divisible by 5.

153Mathematics
A man's income at first increased by 20% and later on increased again by 30% . Find the total percent increase.
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Answer: (D) 56

Explanation

For successive percentage increases of A% and B%, the effective total percentage increase is given by the formula:

Net Percentage Increase = A + B + (A × B / 100)

Substituting A = 20% and B = 30%:

Net Percentage Increase = 20 + 30 + (20 × 30 / 100) = 50 + 6 = 56%

Alternatively, assuming an initial income of 100, the first increase makes it 120, and a further 30% increase raises it to 120 × 1.30 = 156, resulting in an overall increase of 56%.

154Mathematics
If one angle of a parallelogram is 39° less than twice the smallest angle, then the smallest angle of the parallelogram is:
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Answer: (C) 73°

Explanation

In a parallelogram, adjacent angles are supplementary, so their sum is equal to 180°.

Let the smallest angle be x. The adjacent angle is given as 2x - 39°.

x + (2x - 39°) = 180° 3x - 39° = 180° 3x = 219° x = 73°

155Mathematics
110 are contained in a box which consists of one rupee, 50 paise and 25 paise coins in the ratio 1 : 2 : 3. What is the number of 50 paise coins?
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Answer: (C) 80

Explanation

Let the number of ₹1, 50 paise, and 25 paise coins be x, 2x, and 3x respectively.

Converting the values to rupees: Value of ₹1 coins = 1 × x = x Value of 50 paise coins = 0.50 × 2x = x Value of 25 paise coins = 0.25 × 3x = 0.75x

Total value = x + x + 0.75x = 2.75x = ₹110

x = 110 / 2.75 = 40

Number of 50 paise coins = 2x = 2 × 40 = 80.

156Mathematics
On dividing 15,971 by a certain number, the quotient is 55 and the remainder is 21. Find the divisor.
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Answer: (C) 290

Explanation

According to the division algorithm: Dividend = (Divisor × Quotient) + Remainder

Substituting the given values into the formula: 15,971 = (Divisor × 55) + 21 Divisor × 55 = 15,971 - 21 Divisor × 55 = 15,950 Divisor = 15,950 ÷ 55 = 290

157Mathematics
The mean of a, b, c, d, e and f is 36. If the mean of b, d and f is 28, find the mean of a, c and e.
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Answer: (C) 44

Explanation

Sum of all 6 numbers (a + b + c + d + e + f) = 36 × 6 = 216. Sum of 3 numbers (b + d + f) = 28 × 3 = 84.

Subtracting the sum of (b, d, f) from the total sum gives: a + c + e = 216 - 84 = 132.

Mean of a, c, and e = 132 / 3 = 44.

158Mathematics
The product of the LCM and HCF of two positive numbers is 72. The difference of these two numbers is 1. Find the numbers.
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Answer: (D) 8 and 9

Explanation

For any two positive numbers x and y, the product of the numbers is equal to the product of their LCM and HCF: x × y = LCM × HCF = 72

The difference between the two numbers is given as 1, so y = x - 1. Substituting this into the product equation gives: x(x - 1) = 72 x² - x - 72 = 0 (x - 9)(x + 8) = 0

Since x must be a positive number, x = 9, which gives y = 9 - 1 = 8. Therefore, the two numbers are 8 and 9.

159Mathematics
The HCF and LCM of two numbers are 75 and 450 respectively. If the first number is divided by 3, the quotient is 75. The second number is:
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Answer: (D) 150

Explanation

First number = 3 × 75 = 225.

Using the formula for two numbers: First number × Second number = HCF × LCM

Substituting the given values: 225 × Second number = 75 × 450 Second number = (75 × 450) / 225 = 150

160Mathematics
What is the smallest four digit number formed by using the digits 3, 5, 0, 6?
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Answer: (D) 3056

Explanation

To form the smallest four-digit number using the digits 3, 5, 0, 6, the thousands place must be filled by the smallest non-zero digit, which is 3. The remaining digits are then arranged in ascending order (0, 5, 6) in the hundreds, tens, and units places to minimize the overall value, giving 3056.

161Mathematics
Vicky can complete a piece of work in 40 days. He worked for 8 days, then Gurpreet Singh finished it in 32 days. In how many days can Vicky and Gurpreet Singh together complete the work?
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Answer: (B) 20 days

Explanation

Work done by Vicky in 8 days = 8/40 = 1/5 of the total work. Remaining work = 1 - 1/5 = 4/5 of the total work.

Gurpreet Singh completes 4/5 of the work in 32 days, so Gurpreet's total time to complete the work alone = 32 × (5/4) = 40 days.

Since both Vicky and Gurpreet Singh can complete the work individually in 40 days, their combined 1-day work = 1/40 + 1/40 = 2/40 = 1/20.

Time taken together = 1 / (1/20) = 20 days.

162Mathematics
What is the sum of the cube of the natural numbers from 1 to 10, both inclusive?
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Answer: (B) 3025

Explanation

The sum of the cubes of the first n natural numbers is given by the formula: Sum = [n(n + 1) / 2]²

Substituting n = 10 into the formula: Sum = [10 × 11 / 2]² = 55² = 3025

163Mathematics
Heena covers a certain distance by train at 110km / h and she returned to the starting point covering the same distance, driving a car at 50km / h . Find her average speed for the whole journey.
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Answer: (D) 68.75 km/h

Explanation

When a person covers the same distance at two different speeds x and y, the average speed for the entire journey is given by the formula:

Average Speed = 2xy / (x + y)

Substituting x = 110 km/h and y = 50 km/h:

Average Speed = (2 × 110 × 50) / (110 + 50) = 11000 / 160 = 68.75 km/h

164Mathematics
How much should we add to each of 7 and 9 so that the ratio of the two numbers thus formed is 13:14 .
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Answer: (B) 19

Explanation

Let x be the number added to each term. Setting up the linear equation from the given ratio:

(7 + x) / (9 + x) = 13 / 14

Cross-multiplying gives:

14 × (7 + x) = 13 × (9 + x) 98 + 14x = 117 + 13x 14x - 13x = 117 - 98 x = 19

Adding 19 yields 7 + 19 = 26 and 9 + 19 = 28, forming the ratio 26:28 = 13:14.

165Mathematics
A maximum of how many pieces of exact 17 cm length can be cut from a 960 cm long rod?
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Answer: (A) 56

Explanation

To determine the maximum number of 17 cm pieces, divide the total length of the rod by the length of each piece and take the integer portion:

Number of pieces = ⌊960 ÷ 17⌋ = 56

Multiplying 17 × 56 gives 952 cm, leaving a remainder of 8 cm, which is less than 17 cm and cannot form another complete piece.

166Mathematics
A book was sold for ₹230 with a profit of 15%. If it was sold for ₹210, then what would have been the percentage of profit or loss?
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Answer: (B) 5% profit

Explanation

Cost Price (CP) = Selling Price × 100 / (100 + Profit%) CP = 230 × 100 / (100 + 15) = 230 × 100 / 115 = ₹200

When the book is sold for ₹210: Profit = New Selling Price - CP = 210 - 200 = ₹10 Profit% = (Profit / CP) × 100 = (10 / 200) × 100 = 5% profit

167Mathematics
The given table shows the number of passengers on an aircraft and their corresponding weight (in kg), for a total of 40 passengers. Answer the question given below based on the table. No of passengers 4 15 6 5 3 7 Weight in kg 90 60 75 78 72 45 What is the average weight of all the 40 passengers?
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Answer: (A) 65.77 kg

Explanation

Average weight = Σ(f × x) / Σf

Total weight of all passengers = (4 × 90) + (15 × 60) + (6 × 75) + (5 × 78) + (3 × 72) + (7 × 45) = 360 + 900 + 450 + 390 + 216 + 315 = 2631 kg

Total number of passengers = 40

Average weight = 2631 / 40 = 65.775 kg ≈ 65.77 kg

168Mathematics
Two men start walking together to a certain destination, one at the speed of 3km / h and another at the speed of 3.75km / h . The latter arrives half an hour before the former. The distance is:
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Answer: (C) 7.5 km

Explanation

Using the formula for time difference when distance is constant: Time difference = (Distance / Speed₁) − (Distance / Speed₂)

Let the distance be D km. Substituting the given speeds and time difference of half an hour (0.5 hours): D/3 − D/3.75 = 0.5 D/3 − 4D/15 = 0.5 (5D − 4D) / 15 = 0.5 D / 15 = 0.5 D = 15 × 0.5 = 7.5 km

169Mathematics
The difference between a 7% profit and a 6% loss while selling an item is 104. What is the cost price of the item?
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Answer: (D) 800

Explanation

Let the cost price of the item be 100%.

The net percentage difference between a 7% profit and a 6% loss is: 7% + 6% = 13%

Given that this 13% difference corresponds to 104:

1% of Cost Price = 104 ÷ 13 = 8

Cost Price (100%) = 8 × 100 = 800

170Mathematics
A retailer marks all his goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
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Answer: (C) 12.50%

Explanation

Net profit percentage can be determined directly using the formula: Profit % = M - D - (M × D)/100, where M is the markup percentage and D is the discount percentage.

Substituting M = 50% and D = 25%: Profit % = 50 - 25 - (50 × 25)/100 = 25 - 12.5 = 12.50%

Alternatively, taking the cost price as ₹100: Marked Price = ₹100 + 50% of ₹100 = ₹150 Selling Price = ₹150 - 25% of ₹150 = 150 - 37.50 = ₹112.50 Actual Profit = ₹112.50 - ₹100 = ₹12.50, which equals a 12.50% profit.

171Mathematics
What will be the amount (in ₹) of annual payment that will discharge a debt of ₹1,025 due in 2 years at the rate of 5% compound interest per annum?
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Answer: (B) 551.25

Explanation

For equal annual installments under compound interest, the formula relating present debt P to annual installment x at interest rate r% over 2 years is:

P = x / (1 + r/100) + x / (1 + r/100)²

Substituting P = 1025 and r = 5:

1025 = x / (1 + 5/100) + x / (1 + 5/100)² 1025 = 20x / 21 + 400x / 441 1025 = (420x + 400x) / 441 1025 = 820x / 441 x = (1025 × 441) / 820 = 551.25

172Mathematics
Ramesh Sharma borrows 8,000 for 3 years at 5% p.a. simple interest. He lends it to Manohar at 7% p.a. for 3 years. Find his gain.
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Answer: (B) 480

Explanation

Gain = Principal × Net Interest Rate Difference × Time / 100

Here, Principal = 8000, Rate difference = 7% - 5% = 2%, and Time = 3 years.

Gain = 8000 × 2 × 3 / 100 = 480.

173Mathematics
How much of an 80% orange juice drink must be mixed with 36 litres of a 25% orange juice drink to obtain a mixture that has 60% orange juice?
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Answer: (C) 63litres

Explanation

Using the rule of alligation, the ratio of the volume of the 80% drink to the volume of the 25% drink is:

(60 - 25) : (80 - 60) = 35 : 20 = 7 : 4

Since 4 parts of the ratio correspond to 36 litres of the 25% drink, 1 part equals 36 ÷ 4 = 9 litres.

The required volume of the 80% drink (7 parts) is 7 × 9 = 63 litres.

174Mathematics
The dimensions of an ice compartment in a refrigerator 8cm × 5cm × 4cm . How many ice cubes will it hold, if each ice cube is 2 cm on its edge?
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Answer: (C) 20

Explanation

Number of ice cubes = Volume of ice compartment / Volume of one ice cube

Volume of rectangular compartment = length × width × height = 8 cm × 5 cm × 4 cm = 160 cm³

Volume of one cubic ice cube = edge³ = (2 cm)³ = 8 cm³

Number of ice cubes = 160 / 8 = 20

175Mathematics
When 40 is subtracted from a number, it reduces to its 60% . What is the number?
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Answer: (B) 100

Explanation

Subtracting 40 from a number reduces it to 60% of its original value, which means 40 represents 40% (100% − 60%) of the number.

Let the number be x. 0.40 × x = 40 x = 40 / 0.40 = 100

176Mathematics
From an external point P, tangents PA and PB are drawn to a circle with centre O. If ∠ PAB = 55° , find ∠ AOB .
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Answer: (C) 110°

Explanation

Since radius OA is perpendicular to tangent PA at point A, ∠OAP = 90°.

Given ∠PAB = 55°, ∠OAB = ∠OAP − ∠PAB = 90° − 55° = 35°.

Since OA = OB (radii of the circle), ΔOAB is an isosceles triangle with ∠OBA = ∠OAB = 35°.

In ΔOAB, the sum of interior angles is 180°: ∠AOB = 180° − (∠OAB + ∠OBA) = 180° − (35° + 35°) = 110°.

177Mathematics
The angle formed by the pages of a fully open book, with just few pages, is theoretically:
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Answer: (B) Straight angle

Explanation

When a book is fully opened flat, the two opposing pages spread out completely along a single straight line in cross-section, forming a flat plane. The measure of the angle formed at the spine between the left and right pages is 180°, which is geometrically classified as a straight angle.

178Mathematics
Consider the following statements and decide which of them is/are correct. 1) Every prime is odd. 2) Product of any two prime numbers is odd.
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Answer: (C) Neither 1 nor 2

Explanation

The number 2 is an even prime number, so not every prime number is odd. Furthermore, the product of 2 and any other prime number, such as 2 × 3 = 6, results in an even number rather than an odd number.

179Mathematics
Solve the following. (⅕x - ⅙y)(5x + 6y) = ?
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Answer: (A) x² + ¹¹ˣʸ⁄₃₀ - y²

Explanation

Expand the product using the distributive property:

((1/5)x - (1/6)y)(5x + 6y) = (1/5)x(5x + 6y) - (1/6)y(5x + 6y) = x² + (6/5)xy - (5/6)xy - y²

Combine the middle xy terms by finding a common denominator of 30:

(6/5 - 5/6)xy = ((36 - 25) / 30)xy = (11/30)xy

This simplifies the expression to x² + 11xy/30 - y².

180Mathematics
Due to 25% reduction in the price of wheat per kg, John is able to buy 5 kg more for ₹600. What is the original price of wheat per kg?
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Answer: (B) 40

Explanation

A 25% reduction on an expenditure of ₹600 saves 25% × 600 = ₹150. This saved amount buys 5 kg of additional wheat, so the reduced price of wheat per kg = 150 ÷ 5 = ₹30. Since the reduced price represents 75% (or 0.75) of the original price, the original price per kg = 30 ÷ 0.75 = ₹40.

181Mathematics
Three numbers are in the ratio 1:2:3 and their HCF is 12. The respective numbers are:
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Answer: (A) 12, 24, 36

Explanation

Let the three numbers be 1x, 2x, and 3x, where x is their highest common factor. Since the numbers 1, 2, and 3 are co-prime, the HCF of 1x, 2x, and 3x is x.

Given HCF = 12, we get x = 12.

Substituting x = 12 into the ratio: First number = 1 × 12 = 12 Second number = 2 × 12 = 24 Third number = 3 × 12 = 36

182Mathematics
If a carton containing a dozen mirrors is dropped, which of the following can be the ratio of number of broken mirrors to unbroken mirrors?
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Answer: (D) 5:1

Explanation

Total mirrors in a dozen = 12.

For a ratio of broken to unbroken mirrors to be valid, the sum of the ratio terms must be a factor of the total number of mirrors, because individual mirrors cannot be fractional.

For the ratio 5:1, the sum of the ratio terms is 5 + 1 = 6. Since 6 divides 12 completely (12 ÷ 6 = 2), this gives 10 broken mirrors and 2 unbroken mirrors, which is a valid whole-number distribution.

183Mathematics
A shopkeeper cheats to the extent of 10% while buying as well as while selling. While he was eventually caught and punished, at what percent was he gaining till then?
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Answer: (A) 21%

Explanation

When a shopkeeper cheats by x% while buying and y% while selling, the overall gain percentage is calculated using the successive percentage change formula:

Net Gain % = x + y + (x × y) / 100

Substituting x = 10 and y = 10:

Net Gain % = 10 + 10 + (10 × 10) / 100 = 20 + 1 = 21%

184Mathematics
An Army General wishes to arrange his 40125 soldiers in rows and columns in the form of a square. After arranging them, he found that some of them are left out. How many soldiers are left out?
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Answer: (B) 125

Explanation

To arrange soldiers in equal rows and columns, the number of arranged soldiers must form a perfect square.

The largest integer whose square is less than or equal to 40125 is 200, because: 200² = 40000 201² = 40401

The maximum number of soldiers that can form a square grid is 40000 (200 rows of 200 soldiers each).

Number of soldiers left out = 40125 − 40000 = 125.

185Mathematics
Simplification of (0.2 × 0.2 + 0.02 × 0.02 - 0.4 × 0.02)/(0.36) gives:
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Answer: (B) 0.09

Explanation

Using the algebraic identity a² + b² - 2ab = (a - b)², let a = 0.2 and b = 0.02:

Numerator = (0.2)² + (0.02)² - 2 × 0.2 × 0.02 = (0.2 - 0.02)² = (0.18)² = 0.0324

Dividing by the denominator: 0.0324 / 0.36 = 0.09

186Mathematics
Which of the following statement(s) is/are true. 1) Every whole number is a natural number. 2) Every integer is a rational number. 3) Every rational number is an integer.
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Answer: (B) 2

Explanation

A rational number is defined as any number that can be expressed in the form p/q, where p and q are integers and q ≠ 0. Every integer z can be written as z/1, where both z and 1 are integers and the denominator is non-zero. This satisfies the definition of a rational number, which makes statement 2 true.

187Mathematics
The value of cos(sec- 1x+ cosec- 1x),|x|≥1 is:
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Answer: (A) 0

Explanation

By the inverse trigonometric identity, for any real number x satisfying |x| ≥ 1:

sec⁻¹x + cosec⁻¹x = π/2

Substituting this identity into the given expression yields:

cos(sec⁻¹x + cosec⁻¹x) = cos(π/2) = 0

188Mathematics
Two-fifth of one-fourth of three-seventh of a number is 15. What is the half of that number?
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Answer: (A) 175

Explanation

Let the number be x.

According to the given condition: (2/5) × (1/4) × (3/7) × x = 15

Simplifying the fraction: (3/70) × x = 15 x = (15 × 70) / 3 x = 350

Half of the number = 350 / 2 = 175

189Mathematics
In a five digit number, the digit in the hundred's place is 2 and the digit in the unit's place is twice the digit in the hundred's place. The number has no thousands. The digit in the ten thousand's place is the sum of the digit in the hundred's place and the digit in the unit's place. The digit in the ten's place is the digit in the ten thousand's place minus 1. The number is:
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Answer: (A) 60254

Explanation

Let the five-digit number be represented by digits in the positions of ten thousand's (T), thousand's (Th), hundred's (H), ten's (t), and unit's (u).

Given: Hundred's digit (H) = 2 Unit's digit (u) = 2 × H = 2 × 2 = 4 Thousand's digit (Th) = 0 Ten thousand's digit (T) = H + u = 2 + 4 = 6 Ten's digit (t) = T - 1 = 6 - 1 = 5

Placing these digits together gives T Th H t u = 60254.

190Mathematics
A is 50% as efficient as B. C completes half of the task completed by A and B together in a day. If C alone completes the task in 40 days, then A, B and C together can complete the task in:
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Answer: (A) 13 ⅓ days

Explanation

Let the daily efficiency of B be 2 units/day. Since A is 50% as efficient as B, the efficiency of A is 1 unit/day. The combined daily work of A and B is 1 + 2 = 3 units/day.

Since C completes half of the work done by A and B together in a day, the efficiency of C is 3 / 2 = 1.5 units/day.

Total work = Efficiency of C × Time taken by C = 1.5 × 40 = 60 units.

Combined daily efficiency of A, B, and C = 1 + 2 + 1.5 = 4.5 units/day.

Time taken by A, B, and C together = Total work / Combined efficiency = 60 / 4.5 = 40/3 = 13⅓ days.

191Mathematics
A train is moving at a uniform speed of 75 km/h. Find the time required by the train to cover a distance of 250 km.
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Answer: (D) 3 h 20 min

Explanation

Time = Distance / Speed

Given Distance = 250 km and Speed = 75 km/h: Time = 250 / 75 = 10 / 3 hours = 3⅓ hours

Converting ⅓ hour into minutes: ⅓ × 60 = 20 minutes

Therefore, the total time required is 3 hours 20 minutes.

192Mathematics
Find the principal value of sin⁻¹((1)/(√2)).
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Answer: (B) (π)/(4)

Explanation

The principal value branch of sin⁻¹(x) is [-π/2, π/2].

Since sin(π/4) = 1/√2 and π/4 lies in the interval [-π/2, π/2], we have sin⁻¹(1/√2) = π/4.

193Mathematics
The ratio of the velocities of the hour hand and minute hand of a clock is:
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Answer: (B) 1:12

Explanation

The minute hand completes one full revolution of 360° in 1 hour (60 minutes), giving it a speed of 6° per minute. The hour hand completes one full revolution of 360° in 12 hours (720 minutes), giving it a speed of 0.5° per minute.

The ratio of the velocity of the hour hand to that of the minute hand is 0.5 : 6 = 1 : 12.

194Mathematics
What is the sum of the angle complementary to 15° and the angle supplementary to 125° ?
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Answer: (C) 130°

Explanation

Complementary angles sum to 90°, so the complement of 15° is 90° − 15° = 75°.

Supplementary angles sum to 180°, so the supplement of 125° is 180° − 125° = 55°.

The required sum is 75° + 55° = 130°.

195Mathematics
The least number by which 294 must be multiplied to make it a perfect square, is:
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Answer: (D) 6

Explanation

Prime factorization of 294 gives: 294 = 2¹ × 3¹ × 7²

For a number to be a perfect square, the exponent of each prime factor in its factorization must be an even number. The prime factors 2 and 3 both have an odd exponent of 1.

To make all exponents even, 294 must be multiplied by 2 × 3 = 6.

196Mathematics
Find the least number that must be added to 1300 so as to get a perfect square.
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Answer: (D) 69

Explanation

To find the least number to be added to 1300 to make it a perfect square, identify the smallest perfect square greater than 1300.

Evaluating adjacent squares around 1300: 36² = 1296 37² = 1369

Since 1296 < 1300 < 1369, the smallest perfect square greater than 1300 is 37² = 1369.

Subtracting 1300 from 1369 gives the required least number: 1369 - 1300 = 69

197Mathematics
What is the value of the digits A and B? BAxB3=57A
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Answer: (A) A = 5,B = 2

Explanation

Substituting B = 2 and A = 5 into the given expression: BA = 25 B3 = 23

Multiplying these two numbers gives: 25 × 23 = 575

This matches 57A where the units digit A is 5.

198Mathematics
In triangle ABC, ∠ A is 12° more than the measure of ∠ C . The measure of ∠ B is 4 times as great as the measure of ∠ C What are the measures of the angles A, B and C respectively?
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Answer: (B) 40°,112°,28°

Explanation

Let the measure of angle C be x. Then, angle A = x + 12° and angle B = 4x.

Using the angle sum property of a triangle: Angle A + Angle B + Angle C = 180° (x + 12°) + 4x + x = 180° 6x + 12° = 180° 6x = 168° x = 28°

Substituting x = 28° gives: Angle A = 28° + 12° = 40° Angle B = 4 × 28° = 112° Angle C = 28°

199Mathematics
For the data set 1, 2, 3, 5, 2, 3, 4, 6, 6, 8, 3, 4, 5 which of the following options is INCORRECT?
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Answer: (D) Mean = Mode

Explanation

Mean = Sum of observations / Number of observations = 52 / 13 = 4.

Arranging the 13 observations in ascending order: 1, 2, 2, 3, 3, 3, 4, 4, 5, 5, 6, 6, 8.

The mode is the value with the highest frequency, which is 3 (appearing 3 times).

Since the mean is 4 and the mode is 3, Mean ≠ Mode.

200Mathematics
A man bought 2 articles for ₹3,000 each. He sold one article at 10% profit and another at 5% profit. Find the total percentage profit he earned.
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Answer: (B) 7.5%

Explanation

When two articles are purchased at the same cost price, the overall profit percentage is simply the arithmetic mean of the individual profit percentages.

Overall Profit Percentage = (Profit₁% + Profit₂%) / 2 = (10% + 5%) / 2 = 15% / 2 = 7.5%

Alternatively, total cost price = ₹3,000 + ₹3,000 = ₹6,000. Total profit = (10% of ₹3,000) + (5% of ₹3,000) = ₹300 + ₹150 = ₹450. Total Profit Percentage = (450 / 6000) × 100 = 7.5%

Answer key

Tap a number to jump to that question.

  1. 151D
  2. 152A
  3. 153D
  4. 154C
  5. 155C
  6. 156C
  7. 157C
  8. 158D
  9. 159D
  10. 160D
  11. 161B
  12. 162B
  13. 163D
  14. 164B
  15. 165A
  16. 166B
  17. 167A
  18. 168C
  19. 169D
  20. 170C
  21. 171B
  22. 172B
  23. 173C
  24. 174C
  25. 175B
  26. 176C
  27. 177B
  28. 178C
  29. 179A
  30. 180B
  31. 181A
  32. 182D
  33. 183A
  34. 184B
  35. 185B
  36. 186B
  37. 187A
  38. 188A
  39. 189A
  40. 190A
  41. 191D
  42. 192B
  43. 193B
  44. 194C
  45. 195D
  46. 196D
  47. 197A
  48. 198B
  49. 199D
  50. 200B

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