A sum of money was lent on compound interest. It became ₹500 at the end of the first year and ₹550 at the end of second year. Find the rate of compound interest per annum.
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Answer: (D) 10%
Explanation
In compound interest, the amount at the end of the first year serves as the principal for the second year.
Interest earned during the second year = Amount after 2nd year - Amount after 1st year = ₹550 - ₹500 = ₹50
Rate of interest per annum = (Interest in 2nd year / Amount after 1st year) × 100
= (50 / 500) × 100 = 10% per annum.
152Mathematics
371¹ + 372¹ + 373¹ + 374¹ + 375¹ is divisible by:
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Answer: (A) 5
Explanation
Sum of five consecutive terms of an arithmetic progression is given by 5 × middle term.
Here, the middle term is 373 and the number of terms is 5.
Sum = 5 × 373 = 1865
Since 5 is a prime factor of the product, the sum is divisible by 5.
153Mathematics
A man's income at first increased by 20% and later on increased again by 30% . Find the total percent increase.
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Answer: (D) 56
Explanation
For successive percentage increases of A% and B%, the effective total percentage increase is given by the formula:
Alternatively, assuming an initial income of 100, the first increase makes it 120, and a further 30% increase raises it to 120 × 1.30 = 156, resulting in an overall increase of 56%.
154Mathematics
If one angle of a parallelogram is 39° less than twice the smallest angle, then the smallest angle of the parallelogram is:
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Answer: (C) 73°
Explanation
In a parallelogram, adjacent angles are supplementary, so their sum is equal to 180°.
Let the smallest angle be x. The adjacent angle is given as 2x - 39°.
x + (2x - 39°) = 180°
3x - 39° = 180°
3x = 219°
x = 73°
155Mathematics
110 are contained in a box which consists of one rupee, 50 paise and 25 paise coins in the ratio 1 : 2 : 3. What is the number of 50 paise coins?
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Answer: (C) 80
Explanation
Let the number of ₹1, 50 paise, and 25 paise coins be x, 2x, and 3x respectively.
Converting the values to rupees:
Value of ₹1 coins = 1 × x = x
Value of 50 paise coins = 0.50 × 2x = x
Value of 25 paise coins = 0.25 × 3x = 0.75x
Total value = x + x + 0.75x = 2.75x = ₹110
x = 110 / 2.75 = 40
Number of 50 paise coins = 2x = 2 × 40 = 80.
156Mathematics
On dividing 15,971 by a certain number, the quotient is 55 and the remainder is 21. Find the divisor.
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Answer: (C) 290
Explanation
According to the division algorithm:
Dividend = (Divisor × Quotient) + Remainder
Substituting the given values into the formula:
15,971 = (Divisor × 55) + 21
Divisor × 55 = 15,971 - 21
Divisor × 55 = 15,950
Divisor = 15,950 ÷ 55 = 290
157Mathematics
The mean of a, b, c, d, e and f is 36. If the mean of b, d and f is 28, find the mean of a, c and e.
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Answer: (C) 44
Explanation
Sum of all 6 numbers (a + b + c + d + e + f) = 36 × 6 = 216.
Sum of 3 numbers (b + d + f) = 28 × 3 = 84.
Subtracting the sum of (b, d, f) from the total sum gives:
a + c + e = 216 - 84 = 132.
Mean of a, c, and e = 132 / 3 = 44.
158Mathematics
The product of the LCM and HCF of two positive numbers is 72. The difference of these two numbers is 1. Find the numbers.
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Answer: (D) 8 and 9
Explanation
For any two positive numbers x and y, the product of the numbers is equal to the product of their LCM and HCF:
x × y = LCM × HCF = 72
The difference between the two numbers is given as 1, so y = x - 1. Substituting this into the product equation gives:
x(x - 1) = 72
x² - x - 72 = 0
(x - 9)(x + 8) = 0
Since x must be a positive number, x = 9, which gives y = 9 - 1 = 8. Therefore, the two numbers are 8 and 9.
159Mathematics
The HCF and LCM of two numbers are 75 and 450 respectively. If the first number is divided by 3, the quotient is 75. The second number is:
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Answer: (D) 150
Explanation
First number = 3 × 75 = 225.
Using the formula for two numbers:
First number × Second number = HCF × LCM
Substituting the given values:
225 × Second number = 75 × 450
Second number = (75 × 450) / 225 = 150
160Mathematics
What is the smallest four digit number formed by using the digits 3, 5, 0, 6?
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Answer: (D) 3056
Explanation
To form the smallest four-digit number using the digits 3, 5, 0, 6, the thousands place must be filled by the smallest non-zero digit, which is 3. The remaining digits are then arranged in ascending order (0, 5, 6) in the hundreds, tens, and units places to minimize the overall value, giving 3056.
161Mathematics
Vicky can complete a piece of work in 40 days. He worked for 8 days, then Gurpreet Singh finished it in 32 days. In how many days can Vicky and Gurpreet Singh together complete the work?
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Answer: (B) 20 days
Explanation
Work done by Vicky in 8 days = 8/40 = 1/5 of the total work.
Remaining work = 1 - 1/5 = 4/5 of the total work.
Gurpreet Singh completes 4/5 of the work in 32 days, so Gurpreet's total time to complete the work alone = 32 × (5/4) = 40 days.
Since both Vicky and Gurpreet Singh can complete the work individually in 40 days, their combined 1-day work = 1/40 + 1/40 = 2/40 = 1/20.
Time taken together = 1 / (1/20) = 20 days.
162Mathematics
What is the sum of the cube of the natural numbers from 1 to 10, both inclusive?
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Answer: (B) 3025
Explanation
The sum of the cubes of the first n natural numbers is given by the formula:
Sum = [n(n + 1) / 2]²
Substituting n = 10 into the formula:
Sum = [10 × 11 / 2]² = 55² = 3025
163Mathematics
Heena covers a certain distance by train at 110km / h and she returned to the starting point covering the same distance, driving a car at 50km / h . Find her average speed for the whole journey.
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Answer: (D) 68.75 km/h
Explanation
When a person covers the same distance at two different speeds x and y, the average speed for the entire journey is given by the formula:
Average Speed = 2xy / (x + y)
Substituting x = 110 km/h and y = 50 km/h:
Average Speed = (2 × 110 × 50) / (110 + 50) = 11000 / 160 = 68.75 km/h
164Mathematics
How much should we add to each of 7 and 9 so that the ratio of the two numbers thus formed is 13:14 .
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Answer: (B) 19
Explanation
Let x be the number added to each term. Setting up the linear equation from the given ratio:
When the book is sold for ₹210:
Profit = New Selling Price - CP = 210 - 200 = ₹10
Profit% = (Profit / CP) × 100 = (10 / 200) × 100 = 5% profit
167Mathematics
The given table shows the number of passengers on an aircraft and their corresponding weight (in kg), for a total of 40 passengers. Answer the question given below based on the table.
No of passengers 4 15 6 5 3 7
Weight in kg 90 60 75 78 72 45
What is the average weight of all the 40 passengers?
Two men start walking together to a certain destination, one at the speed of 3km / h and another at the speed of 3.75km / h . The latter arrives half an hour before the former. The distance is:
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Answer: (C) 7.5 km
Explanation
Using the formula for time difference when distance is constant:
Time difference = (Distance / Speed₁) − (Distance / Speed₂)
Let the distance be D km. Substituting the given speeds and time difference of half an hour (0.5 hours):
D/3 − D/3.75 = 0.5
D/3 − 4D/15 = 0.5
(5D − 4D) / 15 = 0.5
D / 15 = 0.5
D = 15 × 0.5 = 7.5 km
169Mathematics
The difference between a 7% profit and a 6% loss while selling an item is 104. What is the cost price of the item?
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Answer: (D) 800
Explanation
Let the cost price of the item be 100%.
The net percentage difference between a 7% profit and a 6% loss is:
7% + 6% = 13%
Given that this 13% difference corresponds to 104:
1% of Cost Price = 104 ÷ 13 = 8
Cost Price (100%) = 8 × 100 = 800
170Mathematics
A retailer marks all his goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
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Answer: (C) 12.50%
Explanation
Net profit percentage can be determined directly using the formula: Profit % = M - D - (M × D)/100, where M is the markup percentage and D is the discount percentage.
Substituting M = 50% and D = 25%:
Profit % = 50 - 25 - (50 × 25)/100 = 25 - 12.5 = 12.50%
Alternatively, taking the cost price as ₹100:
Marked Price = ₹100 + 50% of ₹100 = ₹150
Selling Price = ₹150 - 25% of ₹150 = 150 - 37.50 = ₹112.50
Actual Profit = ₹112.50 - ₹100 = ₹12.50, which equals a 12.50% profit.
171Mathematics
What will be the amount (in ₹) of annual payment that will discharge a debt of ₹1,025 due in 2 years at the rate of 5% compound interest per annum?
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Answer: (B) 551.25
Explanation
For equal annual installments under compound interest, the formula relating present debt P to annual installment x at interest rate r% over 2 years is:
Since OA = OB (radii of the circle), ΔOAB is an isosceles triangle with ∠OBA = ∠OAB = 35°.
In ΔOAB, the sum of interior angles is 180°:
∠AOB = 180° − (∠OAB + ∠OBA) = 180° − (35° + 35°) = 110°.
177Mathematics
The angle formed by the pages of a fully open book, with just few pages, is theoretically:
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Answer: (B) Straight angle
Explanation
When a book is fully opened flat, the two opposing pages spread out completely along a single straight line in cross-section, forming a flat plane. The measure of the angle formed at the spine between the left and right pages is 180°, which is geometrically classified as a straight angle.
178Mathematics
Consider the following statements and decide which of them is/are correct.
1) Every prime is odd.
2) Product of any two prime numbers is odd.
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Answer: (C) Neither 1 nor 2
Explanation
The number 2 is an even prime number, so not every prime number is odd. Furthermore, the product of 2 and any other prime number, such as 2 × 3 = 6, results in an even number rather than an odd number.
179Mathematics
Solve the following.
(⅕x - ⅙y)(5x + 6y) = ?
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Answer: (A) x² + ¹¹ˣʸ⁄₃₀ - y²
Explanation
Expand the product using the distributive property:
Combine the middle xy terms by finding a common denominator of 30:
(6/5 - 5/6)xy = ((36 - 25) / 30)xy = (11/30)xy
This simplifies the expression to x² + 11xy/30 - y².
180Mathematics
Due to 25% reduction in the price of wheat per kg, John is able to buy 5 kg more for ₹600. What is the original price of wheat per kg?
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Answer: (B) 40
Explanation
A 25% reduction on an expenditure of ₹600 saves 25% × 600 = ₹150. This saved amount buys 5 kg of additional wheat, so the reduced price of wheat per kg = 150 ÷ 5 = ₹30. Since the reduced price represents 75% (or 0.75) of the original price, the original price per kg = 30 ÷ 0.75 = ₹40.
181Mathematics
Three numbers are in the ratio 1:2:3 and their HCF is 12. The respective numbers are:
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Answer: (A) 12, 24, 36
Explanation
Let the three numbers be 1x, 2x, and 3x, where x is their highest common factor. Since the numbers 1, 2, and 3 are co-prime, the HCF of 1x, 2x, and 3x is x.
Given HCF = 12, we get x = 12.
Substituting x = 12 into the ratio:
First number = 1 × 12 = 12
Second number = 2 × 12 = 24
Third number = 3 × 12 = 36
182Mathematics
If a carton containing a dozen mirrors is dropped, which of the following can be the ratio of number of broken mirrors to unbroken mirrors?
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Answer: (D) 5:1
Explanation
Total mirrors in a dozen = 12.
For a ratio of broken to unbroken mirrors to be valid, the sum of the ratio terms must be a factor of the total number of mirrors, because individual mirrors cannot be fractional.
For the ratio 5:1, the sum of the ratio terms is 5 + 1 = 6. Since 6 divides 12 completely (12 ÷ 6 = 2), this gives 10 broken mirrors and 2 unbroken mirrors, which is a valid whole-number distribution.
183Mathematics
A shopkeeper cheats to the extent of 10% while buying as well as while selling. While he was eventually caught and punished, at what percent was he gaining till then?
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Answer: (A) 21%
Explanation
When a shopkeeper cheats by x% while buying and y% while selling, the overall gain percentage is calculated using the successive percentage change formula:
Net Gain % = x + y + (x × y) / 100
Substituting x = 10 and y = 10:
Net Gain % = 10 + 10 + (10 × 10) / 100 = 20 + 1 = 21%
184Mathematics
An Army General wishes to arrange his 40125 soldiers in rows and columns in the form of a square. After arranging them, he found that some of them are left out. How many soldiers are left out?
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Answer: (B) 125
Explanation
To arrange soldiers in equal rows and columns, the number of arranged soldiers must form a perfect square.
The largest integer whose square is less than or equal to 40125 is 200, because:
200² = 40000
201² = 40401
The maximum number of soldiers that can form a square grid is 40000 (200 rows of 200 soldiers each).
Number of soldiers left out = 40125 − 40000 = 125.
Which of the following statement(s) is/are true.
1) Every whole number is a natural number.
2) Every integer is a rational number.
3) Every rational number is an integer.
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Answer: (B) 2
Explanation
A rational number is defined as any number that can be expressed in the form p/q, where p and q are integers and q ≠ 0. Every integer z can be written as z/1, where both z and 1 are integers and the denominator is non-zero. This satisfies the definition of a rational number, which makes statement 2 true.
187Mathematics
The value of cos(sec- 1x+ cosec- 1x),|x|≥1 is:
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Answer: (A) 0
Explanation
By the inverse trigonometric identity, for any real number x satisfying |x| ≥ 1:
sec⁻¹x + cosec⁻¹x = π/2
Substituting this identity into the given expression yields:
cos(sec⁻¹x + cosec⁻¹x) = cos(π/2) = 0
188Mathematics
Two-fifth of one-fourth of three-seventh of a number is 15. What is the half of that number?
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Answer: (A) 175
Explanation
Let the number be x.
According to the given condition:
(2/5) × (1/4) × (3/7) × x = 15
Simplifying the fraction:
(3/70) × x = 15
x = (15 × 70) / 3
x = 350
Half of the number = 350 / 2 = 175
189Mathematics
In a five digit number, the digit in the hundred's place is 2 and the digit in the unit's place is twice the digit in the hundred's place. The number has no thousands. The digit in the ten thousand's place is the sum of the digit in the hundred's place and the digit in the unit's place. The digit in the ten's place is the digit in the ten thousand's place minus 1. The number is:
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Answer: (A) 60254
Explanation
Let the five-digit number be represented by digits in the positions of ten thousand's (T), thousand's (Th), hundred's (H), ten's (t), and unit's (u).
Placing these digits together gives T Th H t u = 60254.
190Mathematics
A is 50% as efficient as B. C completes half of the task completed by A and B together in a day. If C alone completes the task in 40 days, then A, B and C together can complete the task in:
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Answer: (A) 13 ⅓ days
Explanation
Let the daily efficiency of B be 2 units/day. Since A is 50% as efficient as B, the efficiency of A is 1 unit/day. The combined daily work of A and B is 1 + 2 = 3 units/day.
Since C completes half of the work done by A and B together in a day, the efficiency of C is 3 / 2 = 1.5 units/day.
Total work = Efficiency of C × Time taken by C = 1.5 × 40 = 60 units.
Combined daily efficiency of A, B, and C = 1 + 2 + 1.5 = 4.5 units/day.
Time taken by A, B, and C together = Total work / Combined efficiency = 60 / 4.5 = 40/3 = 13⅓ days.
191Mathematics
A train is moving at a uniform speed of 75 km/h. Find the time required by the train to cover a distance of 250 km.
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Answer: (D) 3 h 20 min
Explanation
Time = Distance / Speed
Given Distance = 250 km and Speed = 75 km/h:
Time = 250 / 75 = 10 / 3 hours = 3⅓ hours
Therefore, the total time required is 3 hours 20 minutes.
192Mathematics
Find the principal value of sin⁻¹((1)/(√2)).
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Answer: (B) (π)/(4)
Explanation
The principal value branch of sin⁻¹(x) is [-π/2, π/2].
Since sin(π/4) = 1/√2 and π/4 lies in the interval [-π/2, π/2], we have sin⁻¹(1/√2) = π/4.
193Mathematics
The ratio of the velocities of the hour hand and minute hand of a clock is:
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Answer: (B) 1:12
Explanation
The minute hand completes one full revolution of 360° in 1 hour (60 minutes), giving it a speed of 6° per minute. The hour hand completes one full revolution of 360° in 12 hours (720 minutes), giving it a speed of 0.5° per minute.
The ratio of the velocity of the hour hand to that of the minute hand is 0.5 : 6 = 1 : 12.
194Mathematics
What is the sum of the angle complementary to 15° and the angle supplementary to 125° ?
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Answer: (C) 130°
Explanation
Complementary angles sum to 90°, so the complement of 15° is 90° − 15° = 75°.
Supplementary angles sum to 180°, so the supplement of 125° is 180° − 125° = 55°.
The required sum is 75° + 55° = 130°.
195Mathematics
The least number by which 294 must be multiplied to make it a perfect square, is:
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Answer: (D) 6
Explanation
Prime factorization of 294 gives:
294 = 2¹ × 3¹ × 7²
For a number to be a perfect square, the exponent of each prime factor in its factorization must be an even number. The prime factors 2 and 3 both have an odd exponent of 1.
To make all exponents even, 294 must be multiplied by 2 × 3 = 6.
196Mathematics
Find the least number that must be added to 1300 so as to get a perfect square.
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Answer: (D) 69
Explanation
To find the least number to be added to 1300 to make it a perfect square, identify the smallest perfect square greater than 1300.
Since 1296 < 1300 < 1369, the smallest perfect square greater than 1300 is 37² = 1369.
Subtracting 1300 from 1369 gives the required least number:
1369 - 1300 = 69
197Mathematics
What is the value of the digits A and B?
BAxB3=57A
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Answer: (A) A = 5,B = 2
Explanation
Substituting B = 2 and A = 5 into the given expression:
BA = 25
B3 = 23
Multiplying these two numbers gives:
25 × 23 = 575
This matches 57A where the units digit A is 5.
198Mathematics
In triangle ABC, ∠ A is 12° more than the measure of ∠ C . The measure of ∠ B is 4 times as great as the measure of ∠ C What are the measures of the angles A, B and C respectively?
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Answer: (B) 40°,112°,28°
Explanation
Let the measure of angle C be x. Then, angle A = x + 12° and angle B = 4x.
Using the angle sum property of a triangle:
Angle A + Angle B + Angle C = 180°
(x + 12°) + 4x + x = 180°
6x + 12° = 180°
6x = 168°
x = 28°
Substituting x = 28° gives:
Angle A = 28° + 12° = 40°
Angle B = 4 × 28° = 112°
Angle C = 28°
199Mathematics
For the data set 1, 2, 3, 5, 2, 3, 4, 6, 6, 8, 3, 4, 5 which of the following options is INCORRECT?
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Answer: (D) Mean = Mode
Explanation
Mean = Sum of observations / Number of observations = 52 / 13 = 4.
Arranging the 13 observations in ascending order: 1, 2, 2, 3, 3, 3, 4, 4, 5, 5, 6, 6, 8.
The mode is the value with the highest frequency, which is 3 (appearing 3 times).
Since the mean is 4 and the mode is 3, Mean ≠ Mode.
200Mathematics
A man bought 2 articles for ₹3,000 each. He sold one article at 10% profit and another at 5% profit. Find the total percentage profit he earned.
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Answer: (B) 7.5%
Explanation
When two articles are purchased at the same cost price, the overall profit percentage is simply the arithmetic mean of the individual profit percentages.