RRB NTPC2021MathematicsPage 35 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1701–1750 of 1,785, each with the correct answer and a step-by-step explanation.

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1701Mathematics
A dealer sells a table for 400, making a profit of 25%. He sells another table at a loss of 10% and on the whole he makes neither profit nor loss. How much (in ₹) did the second table cost him?
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Answer: (D) 800

Explanation

For the first table: Selling Price = ₹400 with a 25% profit. Cost Price = 400 ÷ 1.25 = ₹320. Profit on the first table = 400 - 320 = ₹80.

Since there is no net profit or loss overall, the gain from the first table equals the loss from the second table.

Loss on the second table = 10% of its Cost Price = ₹80. Cost Price of the second table = 80 ÷ 0.10 = ₹800.

1702Mathematics
A certain sum of money amounts to ₹2,613 in 6 years at 5% simple interest per annum. In how many years will it amount to ₹3,015 at the same rate?
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Answer: (A) 10 years

Explanation

Amount under simple interest is given by A = P + (P × R × T / 100) = P(1 + RT / 100).

Given A₁ = ₹2,613, R = 5%, and T₁ = 6 years: 2,613 = P(1 + (5 × 6) / 100) = 1.3P P = 2,613 / 1.3 = ₹2,010

To reach an amount A₂ = ₹3,015 at the same rate: Simple Interest required = A₂ - P = 3,015 - 2,010 = ₹1,005

Using T₂ = (SI × 100) / (P × R): T₂ = (1,005 × 100) / (2,010 × 5) = 1,00,500 / 10,050 = 10 years.

1703Mathematics
A certain sum of money is divided among A, B and C. A gets one-third of the amount. B gets thrice as much as what C gets and C gets 1,200 less than what A gets. Find the share (in π ) of A.
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Answer: (D) 2,400

Explanation

Let total sum be T. Since A receives one-third of the total amount, T = 3A.

Since total amount T = A + B + C, substituting T = 3A gives: 2A = B + C

Given that B = 3C and C = A - 1200: 2A = 3C + C 2A = 4C A = 2C

Substituting C = A - 1200 into A = 2C: A = 2(A - 1200) A = 2A - 2400 A = 2400

1704Mathematics
Simplify the given expression. (5 + 5×5)/(5×5 + 5)× (⅕÷(⅕×⅕))/((⅕×⅕)÷⅕) - (5 - ⅕)× ¹⁰⁄₂
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Answer: (D) 1

Explanation

Break the expression into simplified components following BODMAS rules:

First fraction: (5 + 5 × 5) / (5 × 5 + 5) = (5 + 25) / (25 + 5) = 30 / 30 = 1

Second fraction: Numerator = (1/5) ÷ (1/25) = (1/5) × 25 = 5 Denominator = (1/25) ÷ (1/5) = (1/25) × 5 = 1/5 Second fraction = 5 / (1/5) = 25

Subtrahend part: (5 - 1/5) × (10 / 2) = (24/5) × 5 = 24

Combining the simplified parts: (1 × 25) - 24 = 25 - 24 = 1

1705Mathematics
John, Johnny and Janardan can finish a task in a field in 6, 12, and 24 days, respectively. In how many days will they finish the task working together?
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Answer: (C) 3³⁄₇ days

Explanation

Combined work done by John, Johnny, and Janardan in one day = 1/6 + 1/12 + 1/24 = (4 + 2 + 1) / 24 = 7/24

Total time required to finish the task working together = 24/7 = 3 3/7 days.

1706Mathematics
Narendra finishes a job in 10 days. Amit completes the same job in 12 days. How many days will it take for both of them to finish the job while working together?
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Answer: (A) 5 5/11

Explanation

Using the combined work formula, Time = (a × b) / (a + b), where a = 10 days and b = 12 days:

Total days = (10 × 12) / (10 + 12) = 120 / 22 = 60 / 11 = 5 5/11 days.

1707Mathematics
What is the compound ratio of 45: 75, 3: 5, 51: 68 and 256: 81?
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Answer: (A) 64

Explanation

The compound ratio of a set of ratios is found by multiplying all the antecedents (first terms) together to form the new antecedent, and all the consequents (second terms) together to form the new consequent.

Simplifying each given ratio: 45 : 75 = 3 : 5 3 : 5 = 3 : 5 51 : 68 = 3 : 4 256 : 81 = 256 : 81

Multiplying the simplified fractions: (3 / 5) × (3 / 5) × (3 / 4) × (256 / 81) = (27 / 100) × (256 / 81) = 256 / 300 = 64 / 75

This simplifies to 64 : 75.

1708Mathematics
If a : b :: 3 : 4 then the value of the expression (5a - 3b)/(7a + 2b) is:
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Answer: (A) 3/29

Explanation

Since the expression (5a - 3b)/(7a + 2b) is homogeneous in a and b, we can directly substitute a = 3 and b = 4 into the given expression.

Numerator = 5a - 3b = 5(3) - 3(4) = 15 - 12 = 3 Denominator = 7a + 2b = 7(3) + 2(4) = 21 + 8 = 29

Required value = 3/29

1709Mathematics
A square is inscribed in a circle which is inscribed in an equilateral triangle. If one side of the triangle is x, then the area of square is:
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Answer: (D) ⅙x²

Explanation

For an equilateral triangle of side x, the inradius r of the inscribed circle is given by: r = x / (2√3)

The diameter of this circle is: d = 2r = x / √3

A square inscribed in a circle has a diagonal equal to the diameter of the circle. Therefore, the diagonal of the square is x / √3.

Using the formula for the area of a square in terms of its diagonal d: Area = d² / 2 = (x / √3)² / 2 = (x² / 3) / 2 = (1/6)x²

1710Mathematics
What is the distance of a vehicle from a tower of 150 m, if the angle of depression to the vehicle is 45° ?
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Answer: (B) 150 m

Explanation

In the right-angled triangle formed by the tower, the line of sight, and the ground:

tan θ = Height / Distance

Given θ = 45° and Height = 150 m:

tan 45° = 150 / Distance 1 = 150 / Distance Distance = 150 m

1711Mathematics
What will the value of the following expression be? ( (6 + 3)/(3) ) - 5 × (4 + 5)
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Answer: (B) -42

Explanation

Using the BODMAS rule, first solve the operations inside the parentheses, then perform division and multiplication, and finally subtraction:

(6 + 3) = 9 (4 + 5) = 9

Substituting these values into the expression gives:

(9 ÷ 3) - 5 × 9 = 3 - 45 = -42

1712Mathematics
Find the HCF of 12 × 15, 15 × 21, 21 × 12
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Answer: (A) 9

Explanation

To find the Highest Common Factor (HCF), express each product in terms of its prime factors:

12 × 15 = (2² × 3) × (3 × 5) = 2² × 3² × 5 15 × 21 = (3 × 5) × (3 × 7) = 3² × 5 × 7 21 × 12 = (3 × 7) × (2² × 3) = 2² × 3² × 7

The common prime factor present in all three numbers is 3, with the lowest power being 2 in each case.

HCF = 3² = 9

1713Mathematics
In an election a candidate with 37% votes loses by a difference of 520000 votes to the winning candidate. What is the total number of votes cast in that election with two contestants?
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Answer: (D) 2000000

Explanation

Percentage of votes obtained by the winning candidate = 100% − 37% = 63%.

Difference in vote percentage between the winning and losing candidate = 63% − 37% = 26%.

Since the difference in votes is 5,20,000: 26% of Total Votes = 5,20,000

Total number of votes cast = (5,20,000 / 26) × 100 = 20,000 × 100 = 20,00,000.

1714Mathematics
What is the value of (4 + √2)/(√2 + 1) ?
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Answer: (B) 3√2 - 2

Explanation

To rationalize the denominator, multiply the numerator and the denominator by the conjugate of the denominator, which is (√2 - 1):

(4 + √2) / (√2 + 1) = [(4 + √2)(√2 - 1)] / [(√2 + 1)(√2 - 1)]

Expanding the numerator gives: (4 + √2)(√2 - 1) = 4√2 - 4 + 2 - √2 = 3√2 - 2

Expanding the denominator using the identity (a + b)(a - b) = a² - b² gives: (√2 + 1)(√2 - 1) = (√2)² - 1² = 2 - 1 = 1

Dividing the numerator by the denominator gives 3√2 - 2.

1715Mathematics
What is the ratio of volumes of two spheres where the curved surface areas are in the ratio of 1:4?
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Answer: (C) 1:8

Explanation

The surface area of a sphere is proportional to the square of its radius (A ∝ r²), while its volume is proportional to the cube of its radius (V ∝ r³).

Given the ratio of surface areas A₁/A₂ = 1/4, the ratio of their radii is: r₁/r₂ = √(A₁/A₂) = √(1/4) = 1/2

Substituting the radius ratio into the volume relation gives: V₁/V₂ = (r₁/r₂)³ = (1/2)³ = 1/8

1716Mathematics
If x + ¹⁄ₓ = 2 , then the value of x² + (1)/(x²) = ?
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Answer: (D) 2

Explanation

Using the standard algebraic identity: (x + 1/x)² = x² + 1/x² + 2

Substitute x + 1/x = 2 into the identity: 2² = x² + 1/x² + 2 4 = x² + 1/x² + 2 x² + 1/x² = 4 - 2 = 2

Alternatively, x + 1/x = 2 directly implies x = 1. Substituting x = 1 into x² + 1/x² gives 1² + 1/1² = 2.

1717Mathematics
If √(2916) = 54 then what is the value of the following? √(29.16) +√(0.2916) +√(0.002916) +√(0.0002916)
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Answer: (B) 5.9994

Explanation

Using √2916 = 54, the square root of a decimal number has half as many decimal places as the original number:

√29.16 = 5.4 √0.2916 = 0.54 √0.002916 = 0.054 √0.0002916 = 0.0054

Adding these values together:

5.4 + 0.54 + 0.054 + 0.0054 = 5.9994

1718Mathematics
Big Mart is offering 5% discount on card payment. How much percentage above cost price should the marked price be so as to make a profit of 10% ?
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Answer: (D) 15 ¹⁵⁄₁₉%

Explanation

Let the cost price (CP) be ₹100.

To earn a profit of 10%, the selling price (SP) is: SP = 100 + 10 = ₹110

Since a discount of 5% is offered on the marked price (MP): SP = MP × (1 - 5/100) = MP × (19/20) 110 = MP × (19/20) MP = (110 × 20) / 19 = 2200 / 19 = 115 15/19

The percentage by which the marked price exceeds the cost price is: Markup % = MP - CP = 115 15/19 - 100 = 15 15/19%

1719Mathematics
Sita can clean a hotel in 20 days. Rita can clean the same hotel in 30 days. How many days will they take to clean the hotel together?
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Answer: (B) 12 days

Explanation

When two individuals take A and B days respectively to complete a work independently, the total time taken to complete the work together is given by the formula:

Time taken together = (A × B) / (A + B)

Substituting A = 20 and B = 30:

Time taken together = (20 × 30) / (20 + 30) = 600 / 50 = 12 days.

1720Mathematics
The average of five students in a class test is 39.20 and the average of three of them is 41. What is the average of the remaining two students?
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Answer: (C) 36.5

Explanation

Sum of marks of all 5 students = 5 × 39.20 = 196 Sum of marks of 3 students = 3 × 41 = 123 Sum of marks of the remaining 2 students = 196 - 123 = 73

Average of the remaining 2 students = 73 / 2 = 36.5

1721Mathematics
An amount becomes eight- fifth of the original amount in 5 years at what percentage rate of simple interest per annum?
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Answer: (C) 12

Explanation

Using the simple interest formula SI = (P × R × T) / 100:

Amount A = (8/5)P Interest SI = A - P = (8/5)P - P = (3/5)P

Substituting SI = (3/5)P and T = 5 into the formula: (3/5)P = (P × R × 5) / 100 3/5 = R / 20 R = (3 × 20) / 5 = 12% per annum

1722Mathematics
Sachin Tendulkar scored his 100th international cricket century against which team?
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Answer: (A) Bangladesh

Explanation

Sachin Tendulkar scored his historic 100th international century against Bangladesh on March 16, 2012, during an Asia Cup match at the Sher-e-Bangla National Stadium in Mirpur, Dhaka. He scored 114 runs off 147 balls, becoming the first cricketer in history to reach the milestone of 100 international centuries, which comprises 51 Test centuries and 49 One Day International (ODI) centuries.

1723Mathematics
In a computer, a menu contains a list of:
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Answer: (A) commands

Explanation

In a computer interface, a menu is a graphical control element that displays a list of executable commands, functions, or options to the user. Selecting a menu item triggers a specific action or command within the software application, such as saving a file, editing text, or printing a document.

1724Mathematics
How many factors of 2² × 3¹ × 5² × 7¹ are divisible by 50 but not by 100?
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Answer: (A) 4

Explanation

To find the factors of N = 2² × 3¹ × 5² × 7¹ that are divisible by 50 (2¹ × 5²) but not by 100 (2² × 5²), we express each factor in prime factorization form 2ᵃ × 3ᵇ × 5ᶜ × 7ᵈ.

For a factor to be divisible by 50, the exponent of 5 must be at least 2 (c = 2) and the exponent of 2 must be at least 1. To ensure the factor is not divisible by 100, the exponent of 2 cannot be 2 or higher, which forces a = 1.

The available choices for each prime factor's exponent are: For prime 2: a = 1 (1 possibility) For prime 3: b = 0 or 1 (2 possibilities) For prime 5: c = 2 (1 possibility) For prime 7: d = 0 or 1 (2 possibilities)

Total required factors = 1 × 2 × 1 × 2 = 4.

1725Mathematics
A path around the inner side of a rectangular park measuring 37 m × 30 m occupies 570 m² . What is the width of the path?
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Answer: (C) 5 m

Explanation

The area of a path of width x running along the inner boundary of a rectangular field of length L and breadth B is given by: Area of path = 2x(L + B - 2x)

Given L = 37 m, B = 30 m, and Area = 570 m²: 570 = 2x(37 + 30 - 2x) 570 = 2x(67 - 2x) 285 = x(67 - 2x) 2x² - 67x + 285 = 0

Factoring the quadratic equation: (x - 5)(2x - 57) = 0

Since x = 57/2 = 28.5 m would reduce the inner dimensions below zero, the width of the path is x = 5 m.

1726Mathematics
Narendra's mother is four times as old as Narendra. Four years ago, his mother was six times as old as Narendra was. What are their Present ages?
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Answer: (B) 10 years, 40 years

Explanation

Let Narendra's present age be x years, making his mother's present age 4x years.

Four years ago, Narendra was (x - 4) years old and his mother was (4x - 4) years old.

According to the given condition: 4x - 4 = 6(x - 4) 4x - 4 = 6x - 24 2x = 20 x = 10

Narendra's present age is 10 years, and his mother's present age is 40 years (4 × 10).

1727Mathematics
What is the total number of odd and even divisors of 120, respectively?
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Answer: (B) 4, 12

Explanation

Prime factorization of 120 is 2³ × 3¹ × 5¹.

The number of odd divisors is found by taking only the powers of the odd prime factors 3¹ and 5¹: Odd divisors = (1 + 1) × (1 + 1) = 4

The total number of divisors is calculated using all prime factors: Total divisors = (3 + 1) × (1 + 1) × (1 + 1) = 16

Subtracting the odd divisors from the total number of divisors gives the even divisors: Even divisors = 16 − 4 = 12

1728Mathematics
If ABCD is a cyclic quadrilateral and ABC is an equilateral triangle find the angle of CDA.
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Answer: (B) 120°

Explanation

Since ABC is an equilateral triangle, each of its interior angles is 60°, so ∠ABC = 60°. In a cyclic quadrilateral, the sum of opposite angles is 180°. Therefore, ∠ABC + ∠CDA = 180°, which gives ∠CDA = 180° - 60° = 120°.

1729Mathematics
If a shopkeeper added 20% on the cost price as marked price and gave 20% discount, then how much was his profit or loss percent?
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Answer: (D) 4% loss

Explanation

Net percentage change = a + b + (a × b)/100

Here, markup percentage a = +20 and discount percentage b = -20.

Net change = 20 - 20 + (20 × -20)/100 = -400/100 = -4%

The negative result indicates a loss of 4%.

1730Mathematics
What is the cost price of articles sold for ₹390 if 20% is the total gain?
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Answer: (D) ₹325

Explanation

Cost Price = (Selling Price × 100) / (100 + Gain%)

Cost Price = (390 × 100) / (100 + 20) = (390 × 100) / 120 = ₹325

1731Mathematics
What will the value of the following expression be? 20 - [15 - {4 - (8 - 6 + 3)} ]
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Answer: (B) 4

Explanation

Using the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction), evaluate the nested brackets from inside out:

Innermost round brackets: 8 - 6 + 3 = 2 + 3 = 5

Curly braces: 4 - 5 = -1

Square brackets: 15 - (-1) = 15 + 1 = 16

Outer expression: 20 - 16 = 4

1732Mathematics
The angle of elevation of a lamp post changes from 30° to 60° when a person walks 30 m towards it. Find the height of the lamp post.
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Answer: (C) 15√3m

Explanation

The height h of an object when moving a distance d towards it, changing the angle of elevation from α to β, is given by the formula:

h = d / (cot α - cot β)

Given d = 30 m, α = 30°, and β = 60°:

cot 30° = √3 cot 60° = 1/√3

cot 30° - cot 60° = √3 - 1/√3 = 2/√3

Substituting these values into the formula:

h = 30 / (2/√3) = (30 × √3) / 2 = 15√3 m

1733Mathematics
Arrange the following numbers in their increasing order. (1) -0.96 (2) 0.83 (3) 0.24 (4) -0.64 (5) 0.58
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Answer: (D) 1,4,3,5,2

Explanation

Arranging the given real numbers in increasing order from smallest to largest:

Negative numbers are smaller than positive numbers, and among negative numbers, the number with the larger absolute value is smaller. Therefore, -0.96 is smaller than -0.64.

Ordering the positive numbers by magnitude gives 0.24 < 0.58 < 0.83.

Combining all the numbers in ascending order: -0.96 (1) < -0.64 (4) < 0.24 (3) < 0.58 (5) < 0.83 (2)

This yields the sequence 1, 4, 3, 5, 2.

1734Mathematics
A mother is now three times as old as her daughter. 5 years ago, she was four times as old as her daughter. What is the current age of the daughter?
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Answer: (D) 15 years

Explanation

Let the current age of the daughter be d years. Mother's current age = 3d years.

Five years ago: Mother's age = 3d - 5 Daughter's age = d - 5

According to the problem statement: 3d - 5 = 4(d - 5) 3d - 5 = 4d - 20 4d - 3d = 20 - 5 d = 15

1735Mathematics
60% of 40% of 32% of an amount is ₹432. What is the amount (in ₹)?
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Answer: (C) 5,625

Explanation

Let x be the total amount in ₹.

(60/100) × (40/100) × (32/100) × x = 432

Converting fractions to simplest form: (3/5) × (2/5) × (8/25) × x = 432 (48 / 625) × x = 432

Solving for x: x = (432 × 625) / 48 x = 9 × 625 x = 5,625

1736Mathematics
The possible value of x in the equation √((x)/(1 - x)) +√((1 - x)/(x)) = ²⁵⁄₁₂ is:
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Answer: (B) 9/25 or 16/25

Explanation

Let y = √(x/(1 - x)). The given equation simplifies to:

y + 1/y = 25/12 (y² + 1)/y = 25/12 12y² - 25y + 12 = 0

Factoring the quadratic equation gives: (4y - 3)(3y - 4) = 0 y = 3/4 or y = 4/3

Case 1: When y = 3/4 √(x/(1 - x)) = 3/4 x/(1 - x) = 9/16 16x = 9 - 9x 25x = 9 x = 9/25

Case 2: When y = 4/3 √(x/(1 - x)) = 4/3 x/(1 - x) = 16/9 9x = 16 - 16x 25x = 16 x = 16/25

1737Mathematics
If x + y + z = 0 , then what will be the value of (x²)/(yz) +(y²)/(zx) +(z²)/(xy)?
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Answer: (B) 3

Explanation

Taking the common denominator xyz, the given expression simplifies to:

(x² / yz) + (y² / zx) + (z² / xy) = (x³ + y³ + z³) / xyz

According to the algebraic identity, x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx).

Since x + y + z = 0, the right-hand side becomes 0, which gives x³ + y³ + z³ = 3xyz.

Substituting this into the expression:

3xyz / xyz = 3

1738Mathematics
The two unequal sides of a rectangle are in the ratio of 3:4. If the perimeter is 42 cm, then the length of diagonal will be:
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Answer: (C) 15cm

Explanation

Let the two adjacent sides of the rectangle be 3x and 4x.

Perimeter = 2 × (3x + 4x) = 14x 14x = 42 cm x = 3 cm

Using the Pythagorean theorem, the length of the diagonal is: Diagonal = √((3x)² + (4x)²) = √(25x²) = 5x

Substituting x = 3 cm: Diagonal = 5 × 3 = 15 cm

1739Mathematics
The difference between the compound interest and the simple interest accrued, at the same rate of interest, on an amount of 16,000 in 2 years was 1,000. What was the rate of interest percent per annum?
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Answer: (B) 25%

Explanation

The difference between compound interest and simple interest for 2 years is given by the formula:

Difference = P × (R / 100)²

Substituting P = 16,000 and Difference = 1,000 into the formula:

1,000 = 16,000 × (R / 100)² (R / 100)² = 1,000 / 16,000 (R / 100)² = 1 / 16

Taking the square root on both sides:

R / 100 = 1 / 4 R = 25%

1740Mathematics
If (1 + tan A)(1 + tan B) = 2 , then what will be the value of tan (A + B) ?
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Answer: (D) 1

Explanation

Expanding the given equation: (1 + tan A)(1 + tan B) = 2 1 + tan A + tan B + tan A tan B = 2 tan A + tan B = 1 - tan A tan B

Dividing both sides by (1 - tan A tan B): (tan A + tan B) / (1 - tan A tan B) = 1

Using the compound angle identity tan(A + B) = (tan A + tan B) / (1 - tan A tan B): tan(A + B) = 1

1741Mathematics
For a symmetric distribution, the empirical relationship between mean, median and mode is:
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Answer: (A) Mean = Median = Mode

Explanation

In a symmetric distribution, data values are evenly and balancedly distributed around the center. As a result, the highest peak representing the most frequent value (mode), the central value dividing the dataset into two equal halves (median), and the arithmetic average (mean) all coincide at the exact same central point. Therefore, Mean = Median = Mode.

1742Mathematics
A, B and C begin together to move around a circular stadium and they complete their revolutions in 42 s, 63 s and 84 s respectively. After how much time will they come together at the starting point?
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Answer: (C) 252 s

Explanation

The time after which all three will meet again at the starting point is equal to the Least Common Multiple (LCM) of their individual revolution times: LCM(42, 63, 84).

Prime factorisation of the given times: 42 = 2 × 3 × 7 63 = 3² × 7 84 = 2² × 3 × 7

LCM(42, 63, 84) = 2² × 3² × 7 = 4 × 9 × 7 = 252 s.

1743Mathematics
If x³ + (1)/(x³) = 18 , then what will be the value of x + ¹⁄ₓ ?
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Answer: (C) 3

Explanation

Using the standard algebraic identity: x³ + 1/x³ = (x + 1/x)³ - 3(x + 1/x)

Let k = x + 1/x. Substituting x³ + 1/x³ = 18 into the identity gives: k³ - 3k = 18 k³ - 3k - 18 = 0

Substituting k = 3 into the equation: 3³ - 3(3) = 27 - 9 = 18

1744Mathematics
If the selling price of an article is 3 times the discount offered and if the percentage of the discount is equal to the percentage profit, find the ratio of the discount offered to the cost price.
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Answer: (B) 5:12

Explanation

Let the discount offered be D. Selling Price (SP) = 3D Marked Price (MP) = SP + Discount = 3D + D = 4D

Discount percentage = (Discount / MP) × 100 = (D / 4D) × 100 = 25%

Since profit percentage equals discount percentage, Profit = 25%. Cost Price (CP) = SP / (1 + Profit/100) = 3D / 1.25 = 12D / 5

Ratio of discount offered to cost price = D : (12D / 5) = 5 : 12

1745Mathematics
The value of ((5.4)³ - 0.064)/((5.4)² + 2.16 + 0.16) is:
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Answer: (B) 5

Explanation

Using the algebraic identity a³ - b³ = (a - b)(a² + ab + b²), let a = 5.4 and b = 0.4 (since 0.4³ = 0.064).

The given expression is in the form: [(5.4)³ - (0.4)³] / [(5.4)² + (5.4 × 0.4) + (0.4)²]

Canceling the common term (a² + ab + b²) from the numerator and denominator leaves: a - b = 5.4 - 0.4 = 5

1746Mathematics
Solve the following. (1 + ¹⁄ₓ)(1 + (1)/(x + 1))(1 + (1)/(x + 2))(1 + (1)/(x + 3)) = ?
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Answer: (D) (x + 4)/(x)

Explanation

Simplifying each factor in the product gives:

1 + 1/x = (x + 1)/x 1 + 1/(x + 1) = (x + 2)/(x + 1) 1 + 1/(x + 2) = (x + 3)/(x + 2) 1 + 1/(x + 3) = (x + 4)/(x + 3)

Multiplying these terms together:

[(x + 1)/x] × [(x + 2)/(x + 1)] × [(x + 3)/(x + 2)] × [(x + 4)/(x + 3)]

All intermediate numerators and denominators cancel out in a telescoping manner, leaving:

(x + 4) / x

1747Mathematics
Four cows are tethered to the four corners of a square field of length 28 m so that each cow can just touch the two cows in the adjacent corners. If the grass in the area inside the square field that was accessible to the cows was enough to feed them for 22 days, for how many days would the grass that is beyond the reach of these cows be able to feed them if someone cuts it and leaves it inside the grazable parts? [Use π = 22 / 7 ]
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Answer: (A) 6

Explanation

Side of the square field = 28 m Radius of each tethered quadrant, r = 28 ÷ 2 = 14 m

Grazable area = 4 × (¼ × π × r²) = π × r² = (22/7) × 14 × 14 = 616 m²

Total area of the square field = 28 × 28 = 784 m²

Area beyond reach = Total area - Grazable area = 784 - 616 = 168 m²

Daily consumption rate = Grazable area ÷ Days = 616 ÷ 22 = 28 m²/day

Days for remaining grass = Ungrazable area ÷ Daily consumption rate = 168 ÷ 28 = 6 days

1748Mathematics
The value of (tan 45° - tan 30°)/(1 + tan 45° tan 30°)$ is:
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Answer: (B) 2 - √3

Explanation

Using the compound angle formula tan(A - B) = (tan A - tan B) / (1 + tan A tan B):

Setting A = 45° and B = 30°, the given expression reduces to tan(45° - 30°) = tan 15°.

Substituting tan 45° = 1 and tan 30° = 1/√3 into the expression: tan 15° = (1 - 1/√3) / (1 + 1/√3) = (√3 - 1) / (√3 + 1)

Multiplying the numerator and denominator by (√3 - 1) to rationalize the denominator: tan 15° = (√3 - 1)² / ((√3 + 1)(√3 - 1)) = (3 + 1 - 2√3) / (3 - 1) = (4 - 2√3) / 2 = 2 - √3

1749Mathematics
The speeds of three trains are in the ratio of 2:3:5 . The amount of time taken by these trains to travel the same distance is in the ratio of:
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Answer: (A) ½:⅓:⅕

Explanation

Time is inversely proportional to speed when the distance traveled is constant (Time = Distance / Speed).

Given the ratio of the speeds of the three trains is 2 : 3 : 5, the ratio of the time taken to cover the same distance is: 1/2 : 1/3 : 1/5

1750Mathematics
Atulit buys an old bicycle for R4,000 and spends R400 towards its repairs. If he sells the bicycle for R5,000 , his percentage gain is:
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Answer: (D) 13⁷⁄₁₁%

Explanation

Total Cost Price = Purchase Price + Repair Cost Total Cost Price = ₹4,000 + ₹400 = ₹4,400

Gain = Selling Price - Total Cost Price Gain = ₹5,000 - ₹4,400 = ₹600

Gain % = (Gain / Total Cost Price) × 100 Gain % = (600 / 4,400) × 100 = 150 / 11 = 13 7/11%

Answer key

Tap a number to jump to that question.

  1. 1701D
  2. 1702A
  3. 1703D
  4. 1704D
  5. 1705C
  6. 1706A
  7. 1707A
  8. 1708A
  9. 1709D
  10. 1710B
  11. 1711B
  12. 1712A
  13. 1713D
  14. 1714B
  15. 1715C
  16. 1716D
  17. 1717B
  18. 1718D
  19. 1719B
  20. 1720C
  21. 1721C
  22. 1722A
  23. 1723A
  24. 1724A
  25. 1725C
  26. 1726B
  27. 1727B
  28. 1728B
  29. 1729D
  30. 1730D
  31. 1731B
  32. 1732C
  33. 1733D
  34. 1734D
  35. 1735C
  36. 1736B
  37. 1737B
  38. 1738C
  39. 1739B
  40. 1740D
  41. 1741A
  42. 1742C
  43. 1743C
  44. 1744B
  45. 1745B
  46. 1746D
  47. 1747A
  48. 1748B
  49. 1749A
  50. 1750D

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