A dealer sells a table for 400, making a profit of 25%. He sells another table at a loss of 10% and on the whole he makes neither profit nor loss. How much (in ₹) did the second table cost him?
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Answer: (D) 800
Explanation
For the first table:
Selling Price = ₹400 with a 25% profit.
Cost Price = 400 ÷ 1.25 = ₹320.
Profit on the first table = 400 - 320 = ₹80.
Since there is no net profit or loss overall, the gain from the first table equals the loss from the second table.
Loss on the second table = 10% of its Cost Price = ₹80.
Cost Price of the second table = 80 ÷ 0.10 = ₹800.
1702Mathematics
A certain sum of money amounts to ₹2,613 in 6 years at 5% simple interest per annum. In how many years will it amount to ₹3,015 at the same rate?
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Answer: (A) 10 years
Explanation
Amount under simple interest is given by A = P + (P × R × T / 100) = P(1 + RT / 100).
Given A₁ = ₹2,613, R = 5%, and T₁ = 6 years:
2,613 = P(1 + (5 × 6) / 100) = 1.3P
P = 2,613 / 1.3 = ₹2,010
To reach an amount A₂ = ₹3,015 at the same rate:
Simple Interest required = A₂ - P = 3,015 - 2,010 = ₹1,005
A certain sum of money is divided among A, B and C. A gets one-third of the amount. B gets thrice as much as what C gets and C gets 1,200 less than what A gets. Find the share (in π ) of A.
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Answer: (D) 2,400
Explanation
Let total sum be T. Since A receives one-third of the total amount, T = 3A.
Since total amount T = A + B + C, substituting T = 3A gives:
2A = B + C
Given that B = 3C and C = A - 1200:
2A = 3C + C
2A = 4C
A = 2C
Substituting C = A - 1200 into A = 2C:
A = 2(A - 1200)
A = 2A - 2400
A = 2400
1704Mathematics
Simplify the given expression.
(5 + 5×5)/(5×5 + 5)× (⅕÷(⅕×⅕))/((⅕×⅕)÷⅕) - (5 - ⅕)× ¹⁰⁄₂
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Answer: (D) 1
Explanation
Break the expression into simplified components following BODMAS rules:
John, Johnny and Janardan can finish a task in a field in 6, 12, and 24 days, respectively. In how many days will they finish the task working together?
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Answer: (C) 3³⁄₇ days
Explanation
Combined work done by John, Johnny, and Janardan in one day = 1/6 + 1/12 + 1/24 = (4 + 2 + 1) / 24 = 7/24
Total time required to finish the task working together = 24/7 = 3 3/7 days.
1706Mathematics
Narendra finishes a job in 10 days. Amit completes the same job in 12 days. How many days will it take for both of them to finish the job while working together?
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Answer: (A) 5 5/11
Explanation
Using the combined work formula, Time = (a × b) / (a + b), where a = 10 days and b = 12 days:
What is the compound ratio of 45: 75, 3: 5, 51: 68 and 256: 81?
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Answer: (A) 64
Explanation
The compound ratio of a set of ratios is found by multiplying all the antecedents (first terms) together to form the new antecedent, and all the consequents (second terms) together to form the new consequent.
The common prime factor present in all three numbers is 3, with the lowest power being 2 in each case.
HCF = 3² = 9
1713Mathematics
In an election a candidate with 37% votes loses by a difference of 520000 votes to the winning candidate. What is the total number of votes cast in that election with two contestants?
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Answer: (D) 2000000
Explanation
Percentage of votes obtained by the winning candidate = 100% − 37% = 63%.
Difference in vote percentage between the winning and losing candidate = 63% − 37% = 26%.
Since the difference in votes is 5,20,000:
26% of Total Votes = 5,20,000
Total number of votes cast = (5,20,000 / 26) × 100 = 20,000 × 100 = 20,00,000.
1714Mathematics
What is the value of (4 + √2)/(√2 + 1) ?
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Answer: (B) 3√2 - 2
Explanation
To rationalize the denominator, multiply the numerator and the denominator by the conjugate of the denominator, which is (√2 - 1):
Expanding the denominator using the identity (a + b)(a - b) = a² - b² gives:
(√2 + 1)(√2 - 1) = (√2)² - 1² = 2 - 1 = 1
Dividing the numerator by the denominator gives 3√2 - 2.
1715Mathematics
What is the ratio of volumes of two spheres where the curved surface areas are in the ratio of 1:4?
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Answer: (C) 1:8
Explanation
The surface area of a sphere is proportional to the square of its radius (A ∝ r²), while its volume is proportional to the cube of its radius (V ∝ r³).
Given the ratio of surface areas A₁/A₂ = 1/4, the ratio of their radii is:
r₁/r₂ = √(A₁/A₂) = √(1/4) = 1/2
Substituting the radius ratio into the volume relation gives:
V₁/V₂ = (r₁/r₂)³ = (1/2)³ = 1/8
1716Mathematics
If x + ¹⁄ₓ = 2 , then the value of x² + (1)/(x²) = ?
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Answer: (D) 2
Explanation
Using the standard algebraic identity:
(x + 1/x)² = x² + 1/x² + 2
Big Mart is offering 5% discount on card payment. How much percentage above cost price should the marked price be so as to make a profit of 10% ?
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Answer: (D) 15 ¹⁵⁄₁₉%
Explanation
Let the cost price (CP) be ₹100.
To earn a profit of 10%, the selling price (SP) is:
SP = 100 + 10 = ₹110
Since a discount of 5% is offered on the marked price (MP):
SP = MP × (1 - 5/100) = MP × (19/20)
110 = MP × (19/20)
MP = (110 × 20) / 19 = 2200 / 19 = 115 15/19
The percentage by which the marked price exceeds the cost price is:
Markup % = MP - CP = 115 15/19 - 100 = 15 15/19%
1719Mathematics
Sita can clean a hotel in 20 days. Rita can clean the same hotel in 30 days. How many days will they take to clean the hotel together?
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Answer: (B) 12 days
Explanation
When two individuals take A and B days respectively to complete a work independently, the total time taken to complete the work together is given by the formula:
Time taken together = (A × B) / (A + B)
Substituting A = 20 and B = 30:
Time taken together = (20 × 30) / (20 + 30) = 600 / 50 = 12 days.
1720Mathematics
The average of five students in a class test is 39.20 and the average of three of them is 41. What is the average of the remaining two students?
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Answer: (C) 36.5
Explanation
Sum of marks of all 5 students = 5 × 39.20 = 196
Sum of marks of 3 students = 3 × 41 = 123
Sum of marks of the remaining 2 students = 196 - 123 = 73
Average of the remaining 2 students = 73 / 2 = 36.5
1721Mathematics
An amount becomes eight- fifth of the original amount in 5 years at what percentage rate of simple interest per annum?
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Answer: (C) 12
Explanation
Using the simple interest formula SI = (P × R × T) / 100:
Amount A = (8/5)P
Interest SI = A - P = (8/5)P - P = (3/5)P
Substituting SI = (3/5)P and T = 5 into the formula:
(3/5)P = (P × R × 5) / 100
3/5 = R / 20
R = (3 × 20) / 5 = 12% per annum
1722Mathematics
Sachin Tendulkar scored his 100th international cricket century against which team?
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Answer: (A) Bangladesh
Explanation
Sachin Tendulkar scored his historic 100th international century against Bangladesh on March 16, 2012, during an Asia Cup match at the Sher-e-Bangla National Stadium in Mirpur, Dhaka. He scored 114 runs off 147 balls, becoming the first cricketer in history to reach the milestone of 100 international centuries, which comprises 51 Test centuries and 49 One Day International (ODI) centuries.
1723Mathematics
In a computer, a menu contains a list of:
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Answer: (A) commands
Explanation
In a computer interface, a menu is a graphical control element that displays a list of executable commands, functions, or options to the user. Selecting a menu item triggers a specific action or command within the software application, such as saving a file, editing text, or printing a document.
1724Mathematics
How many factors of 2² × 3¹ × 5² × 7¹ are divisible by 50 but not by 100?
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Answer: (A) 4
Explanation
To find the factors of N = 2² × 3¹ × 5² × 7¹ that are divisible by 50 (2¹ × 5²) but not by 100 (2² × 5²), we express each factor in prime factorization form 2ᵃ × 3ᵇ × 5ᶜ × 7ᵈ.
For a factor to be divisible by 50, the exponent of 5 must be at least 2 (c = 2) and the exponent of 2 must be at least 1. To ensure the factor is not divisible by 100, the exponent of 2 cannot be 2 or higher, which forces a = 1.
The available choices for each prime factor's exponent are:
For prime 2: a = 1 (1 possibility)
For prime 3: b = 0 or 1 (2 possibilities)
For prime 5: c = 2 (1 possibility)
For prime 7: d = 0 or 1 (2 possibilities)
Total required factors = 1 × 2 × 1 × 2 = 4.
1725Mathematics
A path around the inner side of a rectangular park measuring 37 m × 30 m occupies 570 m² . What is the width of the path?
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Answer: (C) 5 m
Explanation
The area of a path of width x running along the inner boundary of a rectangular field of length L and breadth B is given by:
Area of path = 2x(L + B - 2x)
Given L = 37 m, B = 30 m, and Area = 570 m²:
570 = 2x(37 + 30 - 2x)
570 = 2x(67 - 2x)
285 = x(67 - 2x)
2x² - 67x + 285 = 0
Since x = 57/2 = 28.5 m would reduce the inner dimensions below zero, the width of the path is x = 5 m.
1726Mathematics
Narendra's mother is four times as old as Narendra. Four years ago, his mother was six times as old as Narendra was.
What are their Present ages?
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Answer: (B) 10 years, 40 years
Explanation
Let Narendra's present age be x years, making his mother's present age 4x years.
Four years ago, Narendra was (x - 4) years old and his mother was (4x - 4) years old.
According to the given condition:
4x - 4 = 6(x - 4)
4x - 4 = 6x - 24
2x = 20
x = 10
Narendra's present age is 10 years, and his mother's present age is 40 years (4 × 10).
1727Mathematics
What is the total number of odd and even divisors of 120, respectively?
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Answer: (B) 4, 12
Explanation
Prime factorization of 120 is 2³ × 3¹ × 5¹.
The number of odd divisors is found by taking only the powers of the odd prime factors 3¹ and 5¹:
Odd divisors = (1 + 1) × (1 + 1) = 4
The total number of divisors is calculated using all prime factors:
Total divisors = (3 + 1) × (1 + 1) × (1 + 1) = 16
Subtracting the odd divisors from the total number of divisors gives the even divisors:
Even divisors = 16 − 4 = 12
1728Mathematics
If ABCD is a cyclic quadrilateral and ABC is an equilateral triangle find the angle of CDA.
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Answer: (B) 120°
Explanation
Since ABC is an equilateral triangle, each of its interior angles is 60°, so ∠ABC = 60°. In a cyclic quadrilateral, the sum of opposite angles is 180°. Therefore, ∠ABC + ∠CDA = 180°, which gives ∠CDA = 180° - 60° = 120°.
1729Mathematics
If a shopkeeper added 20% on the cost price as marked price and gave 20% discount, then how much was his profit or loss percent?
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Answer: (D) 4% loss
Explanation
Net percentage change = a + b + (a × b)/100
Here, markup percentage a = +20 and discount percentage b = -20.
What will the value of the following expression be?
20 - [15 - {4 - (8 - 6 + 3)} ]
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Answer: (B) 4
Explanation
Using the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction), evaluate the nested brackets from inside out:
Innermost round brackets:
8 - 6 + 3 = 2 + 3 = 5
Curly braces:
4 - 5 = -1
Square brackets:
15 - (-1) = 15 + 1 = 16
Outer expression:
20 - 16 = 4
1732Mathematics
The angle of elevation of a lamp post changes from 30° to 60° when a person walks 30 m towards it. Find the height of the lamp post.
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Answer: (C) 15√3m
Explanation
The height h of an object when moving a distance d towards it, changing the angle of elevation from α to β, is given by the formula:
h = d / (cot α - cot β)
Given d = 30 m, α = 30°, and β = 60°:
cot 30° = √3
cot 60° = 1/√3
cot 30° - cot 60° = √3 - 1/√3 = 2/√3
Substituting these values into the formula:
h = 30 / (2/√3) = (30 × √3) / 2 = 15√3 m
1733Mathematics
Arrange the following numbers in their increasing order.
(1) -0.96
(2) 0.83
(3) 0.24
(4) -0.64
(5) 0.58
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Answer: (D) 1,4,3,5,2
Explanation
Arranging the given real numbers in increasing order from smallest to largest:
Negative numbers are smaller than positive numbers, and among negative numbers, the number with the larger absolute value is smaller. Therefore, -0.96 is smaller than -0.64.
Ordering the positive numbers by magnitude gives 0.24 < 0.58 < 0.83.
Combining all the numbers in ascending order:
-0.96 (1) < -0.64 (4) < 0.24 (3) < 0.58 (5) < 0.83 (2)
This yields the sequence 1, 4, 3, 5, 2.
1734Mathematics
A mother is now three times as old as her daughter. 5 years ago, she was four times as old as her daughter. What is the current age of the daughter?
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Answer: (D) 15 years
Explanation
Let the current age of the daughter be d years.
Mother's current age = 3d years.
Five years ago:
Mother's age = 3d - 5
Daughter's age = d - 5
According to the problem statement:
3d - 5 = 4(d - 5)
3d - 5 = 4d - 20
4d - 3d = 20 - 5
d = 15
1735Mathematics
60% of 40% of 32% of an amount is ₹432. What is the amount (in ₹)?
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Answer: (C) 5,625
Explanation
Let x be the total amount in ₹.
(60/100) × (40/100) × (32/100) × x = 432
Converting fractions to simplest form:
(3/5) × (2/5) × (8/25) × x = 432
(48 / 625) × x = 432
Solving for x:
x = (432 × 625) / 48
x = 9 × 625
x = 5,625
1736Mathematics
The possible value of x in the equation √((x)/(1 - x)) +√((1 - x)/(x)) = ²⁵⁄₁₂ is:
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Answer: (B) 9/25 or 16/25
Explanation
Let y = √(x/(1 - x)). The given equation simplifies to:
According to the algebraic identity, x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx).
Since x + y + z = 0, the right-hand side becomes 0, which gives x³ + y³ + z³ = 3xyz.
Substituting this into the expression:
3xyz / xyz = 3
1738Mathematics
The two unequal sides of a rectangle are in the ratio of 3:4. If the perimeter is 42 cm, then the length of diagonal will be:
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Answer: (C) 15cm
Explanation
Let the two adjacent sides of the rectangle be 3x and 4x.
Perimeter = 2 × (3x + 4x) = 14x
14x = 42 cm
x = 3 cm
Using the Pythagorean theorem, the length of the diagonal is:
Diagonal = √((3x)² + (4x)²) = √(25x²) = 5x
Substituting x = 3 cm:
Diagonal = 5 × 3 = 15 cm
1739Mathematics
The difference between the compound interest and the simple interest accrued, at the same rate of interest, on an amount of 16,000 in 2 years was 1,000. What was the rate of interest percent per annum?
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Answer: (B) 25%
Explanation
The difference between compound interest and simple interest for 2 years is given by the formula:
Difference = P × (R / 100)²
Substituting P = 16,000 and Difference = 1,000 into the formula:
If (1 + tan A)(1 + tan B) = 2 , then what will be the value of tan (A + B) ?
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Answer: (D) 1
Explanation
Expanding the given equation:
(1 + tan A)(1 + tan B) = 2
1 + tan A + tan B + tan A tan B = 2
tan A + tan B = 1 - tan A tan B
Dividing both sides by (1 - tan A tan B):
(tan A + tan B) / (1 - tan A tan B) = 1
Using the compound angle identity tan(A + B) = (tan A + tan B) / (1 - tan A tan B):
tan(A + B) = 1
1741Mathematics
For a symmetric distribution, the empirical relationship between mean, median and mode is:
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Answer: (A) Mean = Median = Mode
Explanation
In a symmetric distribution, data values are evenly and balancedly distributed around the center. As a result, the highest peak representing the most frequent value (mode), the central value dividing the dataset into two equal halves (median), and the arithmetic average (mean) all coincide at the exact same central point. Therefore, Mean = Median = Mode.
1742Mathematics
A, B and C begin together to move around a circular stadium and they complete their revolutions in 42 s, 63 s and 84 s respectively. After how much time will they come together at the starting point?
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Answer: (C) 252 s
Explanation
The time after which all three will meet again at the starting point is equal to the Least Common Multiple (LCM) of their individual revolution times: LCM(42, 63, 84).
Prime factorisation of the given times:
42 = 2 × 3 × 7
63 = 3² × 7
84 = 2² × 3 × 7
If x³ + (1)/(x³) = 18 , then what will be the value of x + ¹⁄ₓ ?
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Answer: (C) 3
Explanation
Using the standard algebraic identity:
x³ + 1/x³ = (x + 1/x)³ - 3(x + 1/x)
Let k = x + 1/x. Substituting x³ + 1/x³ = 18 into the identity gives:
k³ - 3k = 18
k³ - 3k - 18 = 0
Substituting k = 3 into the equation:
3³ - 3(3) = 27 - 9 = 18
1744Mathematics
If the selling price of an article is 3 times the discount offered and if the percentage of the discount is equal to the percentage profit, find the ratio of the discount offered to the cost price.
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Answer: (B) 5:12
Explanation
Let the discount offered be D.
Selling Price (SP) = 3D
Marked Price (MP) = SP + Discount = 3D + D = 4D
All intermediate numerators and denominators cancel out in a telescoping manner, leaving:
(x + 4) / x
1747Mathematics
Four cows are tethered to the four corners of a square field of length 28 m so that each cow can just touch the two cows in the adjacent corners. If the grass in the area inside the square field that was accessible to the cows was enough to feed them for 22 days, for how many days would the grass that is beyond the reach of these cows be able to feed them if someone cuts it and leaves it inside the grazable parts? [Use π = 22 / 7 ]
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Answer: (A) 6
Explanation
Side of the square field = 28 m
Radius of each tethered quadrant, r = 28 ÷ 2 = 14 m