RRB NTPC2021MathematicsPage 33 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1601–1650 of 1,785, each with the correct answer and a step-by-step explanation.

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1601Mathematics
In a certain code language, all letters of the English alphabet are coded with odd numbers as follows: A=1,B=3,C=5 and so on. How will HEAD be coded as in that language?
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Answer: (D) 15917

Explanation

The coding follows the formula Code = 2n - 1, where n is the 1-based position of the letter in the English alphabet.

Applying this formula to each letter in HEAD: H (8th letter): 2 × 8 - 1 = 15 E (5th letter): 2 × 5 - 1 = 9 A (1st letter): 2 × 1 - 1 = 1 D (4th letter): 2 × 4 - 1 = 7

Combining these coded values in order yields 15917.

1602Mathematics
A train takes 15 s to pass completely through a station platform 50 m long and 10 s through another station platform 20 m long. Find the length of the train.
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Answer: (A) 40 m

Explanation

Let L be the length of the train in meters and v be its speed in m/s.

The speed of the train can be found by taking the ratio of the difference in platform lengths to the difference in time taken: v = (50 - 20) / (15 - 10) = 30 / 5 = 6 m/s

When passing the 50 m platform, the total distance covered by the train is L + 50: L + 50 = v × 15 L + 50 = 6 × 15 = 90 L = 90 - 50 = 40 m

1603Mathematics
At a speed of 60 km/h a train crosses a pole in 33 s. Find the length of the train.
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Answer: (A) 550m

Explanation

Length of train = Speed × Time

Speed in m/s = 60 × (5/18) = 50/3 m/s

Length of train = (50/3) × 33 = 550 m

1604Mathematics
Solve the following. (0.032× 0.0032) + 0.00032 = ?
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Answer: (A) 0.0004224

Explanation

First, calculate the product inside the parentheses: 0.032 × 0.0032 = (32 × 10⁻³) × (32 × 10⁻⁴) = 1024 × 10⁻⁷ = 0.0001024

Next, add 0.00032 to this result: 0.0001024 + 0.00032 = 0.0004224

1605Mathematics
Solve the following. ½ [ ⅓ - ( ½ - ¼ ) + ½ - ¼ ] = ?
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Answer: (C) ⅙

Explanation

Evaluating the expression step-by-step:

Inside the parentheses: ½ - ¼ = ¼

Substituting this back into the bracket: ⅓ - ¼ + ½ - ¼

Combining the like terms: -¼ - ¼ = -½ -½ + ½ = 0

So the bracket simplifies to ⅓.

Finally, multiplying by the outside fraction: ½ × ⅓ = ⅙

1606Mathematics
The average of 3 consecutive natural numbers (which are in increasing order) is K. If two more consecutive numbers, just next to the first set of numbers, are added, then the new average will become:
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Answer: (B) K + 1

Explanation

For any set of consecutive numbers, the average is always equal to the middle term.

Since the average of the first 3 consecutive numbers is K, the middle term is K, making the three numbers K - 1, K, and K + 1.

Adding the next two consecutive numbers extends the set to 5 terms: K - 1, K, K + 1, K + 2, and K + 3. The middle term of these 5 numbers is K + 1, which is the new average.

1607Mathematics
Find the compound interest (correct to two places of decimals) for 2 years of ₹1,800 at the rate of 10% per annum, compounded half yearly.
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Answer: (B) ₹387.91

Explanation

When interest is compounded half-yearly, the annual interest rate is halved and the number of time periods is doubled.

Rate per half-year R = 10% / 2 = 5% Number of half-years n = 2 × 2 = 4

Amount A = P × (1 + R/100)ⁿ A = 1,800 × (1 + 5/100)⁴ A = 1,800 × (1.05)⁴ A = 1,800 × 1.21550625 = ₹2,187.91

Compound Interest = Amount - Principal Compound Interest = ₹2,187.91 - ₹1,800 = ₹387.91

1608Mathematics
What should be subtracted from (¾ - ⅔) to get ⁻¹⁄₆?
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Answer: (C) ¼

Explanation

Let the required number be x.

(3/4 - 2/3) - x = -1/6

First, simplify the term in parentheses: 3/4 - 2/3 = (9 - 8) / 12 = 1/12

Substitute this back into the equation: 1/12 - x = -1/6 x = 1/12 + 1/6 x = 1/12 + 2/12 x = 3/12 x = 1/4

1609Mathematics
The value of tan 75°-cot75° is equal to:
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Answer: (D) 2 {3}

Explanation

Using the identity tan θ - cot θ = -2 cot 2θ:

tan 75° - cot 75° = -2 cot(2 × 75°) = -2 cot 150°

Since cot 150° = cot(180° - 30°) = -cot 30° = -√3:

tan 75° - cot 75° = -2 × (-√3) = 2√3

Alternatively, tan 75° = 2 + √3 and cot 75° = 2 - √3. Subtracting cot 75° from tan 75° gives (2 + √3) - (2 - √3) = 2√3.

1610Mathematics
A man purchases an item for ₹950 and sells it for ₹1000. Find his percentage gain.
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Answer: (B) 5%19

Explanation

Gain = Selling Price - Cost Price = 1000 - 950 = ₹50.

Gain Percentage = (Gain / Cost Price) × 100 = (50 / 950) × 100 = 100 / 19 % = 5 5/19 %

1611Mathematics
'Durgeshnandini' was written by:
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Answer: (C) Bankim Chandra Chattopadhyay

Explanation

'Durgeshnandini' (The Chieftain's Daughter) was written by Bankim Chandra Chattopadhyay and published in 1865. It was his debut Bengali novel, which played a pioneering role in the development of Indian historical fiction and helped lay the foundation for modern Bengali prose literature.

1612Mathematics
As on Jan 2021, Which is the biggest thermal power plant in India?
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Answer: (A) Vindhyachal Thermal Power Station

Explanation

Vindhyachal Thermal Power Station, located in the Singrauli district of Madhya Pradesh, is a coal-fired power plant operated by the National Thermal Power Corporation (NTPC). With an installed capacity of 4,760 MW, it stands as the largest thermal power generation facility in India.

1613Mathematics
The average of a, 11, 23 and 17 is 15 and the average of a, b, 12 and 25 is 16. The value of (a)/(b) is:
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Answer: (D) ½

Explanation

Sum = Average × Number of terms.

From the first given condition: a + 11 + 23 + 17 = 15 × 4 a + 51 = 60 a = 9

From the second given condition: a + b + 12 + 25 = 16 × 4 9 + b + 37 = 64 b + 46 = 64 b = 18

The value of a/b = 9/18 = ½.

1614Mathematics
If 10_P__ᵣ = 5040, find the value of r.
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Answer: (D) 4

Explanation

The formula for permutations is ⁿPᵣ = n! / (n - r)!, which represents the product of r consecutive decreasing integers starting from n.

Expanding 5040 as a product of consecutive integers starting from 10: 10 × 9 × 8 × 7 = 5040

Since the product contains 4 terms, r = 4.

1615Mathematics
If the discount and percentage profit are both 20% , then by what percentage is the marked price above the cost price?
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Answer: (B) 50%

Explanation

The relationship between Marked Price (MP), Cost Price (CP), Profit percentage (P%), and Discount percentage (D%) is given by the formula:

MP / CP = (100 + P%) / (100 - D%)

Substituting P = 20 and D = 20:

MP / CP = (100 + 20) / (100 - 20) = 120 / 80 = 3 / 2 = 1.5

Percentage by which MP is above CP = ((MP - CP) / CP) × 100 = (1.5 - 1) × 100 = 50%

1616Mathematics
How many four-digit numbers are completely divisible by 5, 12 and 18?
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Answer: (D) 50

Explanation

A number is completely divisible by 5, 12, and 18 if it is divisible by their Least Common Multiple (LCM).

LCM(5, 12, 18) = 180

Four-digit numbers range from 1000 to 9999.

Smallest 4-digit multiple of 180 = 180 × 6 = 1080 Largest 4-digit multiple of 180 = 180 × 55 = 9900

The number of such 4-digit multiples corresponds to the range of multipliers from 6 to 55: Count = 55 - 6 + 1 = 50

1617Mathematics
The GCD of two numbers is 9 and their LCM is 270. If one number is 27, then what will be the second number?
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Answer: (C) 90

Explanation

For any two positive integers, Product of two numbers = GCD × LCM.

Let the second number be x. 27 × x = 9 × 270 x = (9 × 270) / 27 x = 90

1618Mathematics
The difference between simple interest and compound interest on ₹1,00,000 for 18 months at 12% per annum reckoned half yearly is:
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Answer: (B) ₹1,101.6

Explanation

For 18 months compounded half-yearly, the number of compounding periods n = 3 and the rate per period r = 12% / 2 = 6% = 0.06.

The formula for the difference between compound interest and simple interest for 3 periods is: Difference = P × r² × (3 + r)

Substituting P = ₹1,00,000 and r = 0.06: Difference = 1,00,000 × (0.06)² × (3 + 0.06) Difference = 1,00,000 × 0.0036 × 3.06 Difference = 360 × 3.06 = ₹1,101.6

1619Mathematics
Solve the following: 0.25(0.25× 0.25)÷ 0.625=?
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Answer: (D) 0.025

Explanation

Convert the given decimals into fractions for simple evaluation: 0.25 = 1/4 0.625 = 5/8

Substitute these fraction values into the expression: 0.25 × (0.25 × 0.25) ÷ 0.625 = (1/4 × 1/4 × 1/4) ÷ (5/8) = (1/64) ÷ (5/8) = (1/64) × (8/5) = 1 / (8 × 5) = 1/40 = 0.025

1620Mathematics
If 2a+ {1}{2a}=6, , what will be the value of 64a⁶+ {1}{64a⁶} ?
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Answer: (B) 39202

Explanation

Let x = 2a. The given equation becomes x + 1/x = 6.

To find 64a⁶ + 1/(64a⁶), we need the value of x⁶ + 1/x⁶.

Using the algebraic identity x³ + 1/x³ = (x + 1/x)³ - 3(x + 1/x): x³ + 1/x³ = 6³ - 3(6) = 216 - 18 = 198

Next, using the identity x⁶ + 1/x⁶ = (x³ + 1/x³)² - 2: x⁶ + 1/x⁶ = 198² - 2 = 39204 - 2 = 39202

1621Mathematics
The sum of two angles of a triangle is equal to its third angle. The measure of the third angle is:
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Answer: (A) 90°

Explanation

Let the three interior angles of the triangle be A, B, and C. By the angle sum property of a triangle:

A + B + C = 180°

Given that the sum of two angles equals the third angle (A + B = C), substitute C for (A + B) in the angle sum equation:

C + C = 180° 2C = 180° C = 90°

1622Mathematics
Mohan earns ₹60 on first day and spends ₹50 on the second day. He again earns ₹60 on the third day and spends ₹50 on the fourth day, and so on. On which day will he have ₹200 with him before spending?
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Answer: (C) 29th

Explanation

Mohan earns ₹60 on odd days and spends ₹50 on even days, resulting in a net gain of ₹10 every 2-day cycle.

To reach ₹200 on an earning day before spending, he needs ₹140 accumulated from full 2-day cycles, followed by the ₹60 earned on the next odd day (140 + 60 = 200).

Number of 2-day cycles required to reach ₹140 = 140 / 10 = 14 cycles. Days in 14 cycles = 14 × 2 = 28 days.

He earns ₹60 and reaches ₹200 on the very next day, which is the 29th day.

1623Mathematics
Find the divisor, given that dividend is 2200, remainder is 13 and the divisor is one-third of the quotient.
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Answer: (C) 27

Explanation

By the division algorithm: Dividend = (Divisor × Quotient) + Remainder

Let the divisor be D. Since the divisor is one-third of the quotient, the quotient Q = 3D.

Substituting the given values: 2200 = (D × 3D) + 13 2200 - 13 = 3D² 2187 = 3D² D² = 729 D = √729 = 27

1624Mathematics
Study the given table and answer the question that follows. The table shows the population of different age-groups in different places. Age-GroupsPlaces 12-17 years 18-25 years 26-40 years TotalPopulation Pune 120000 40000 65000 225000 Delhi 50000 80000 120000 250000 Goa 30000 75000 70000 175000 Bengaluru 40000 50000 110000 200000 If 25% of the people in the age-group of 18-25 years move from Delhi to Goa, then what will be the total population of Goa?
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Answer: (D) 195000

Explanation

Number of people in the 18-25 years age-group in Delhi = 80000

Number of people moving from Delhi to Goa = 25% of 80000 = (25 / 100) × 80000 = 20000

Original total population of Goa = 175000

New total population of Goa = 175000 + 20000 = 195000

1625Mathematics
Study the given table and answer the question that follows. The table shows the population of different age-groups in different places. Age-GroupsPlaces 12-17 years 18-25 years 26-40 years TotalPopulation Pune 120000 40000 65000 225000 Delhi 50000 80000 120000 250000 Goa 30000 75000 70000 175000 Bengaluru 40000 50000 110000 200000 In January, 20% of the people in the age-group of 26-40 years moved from Pune to Delhi. In February, 10% of the people in the age-group of 18-25 years moved from Bengaluru to Delhi. In March, 20% of the people in the age-group of 18-25 years moved from Delhi to Goa. Assuming that there was no movement of people other than as stated above from January to April, what will be the total population of Delhi in the month of April?
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Answer: (D) 251000

Explanation

Initial population of Delhi = 250,000

January migration into Delhi: 20% of Pune's 26-40 age group (65,000) = 0.20 × 65,000 = 13,000

February migration into Delhi: 10% of Bengaluru's 18-25 age group (50,000) = 0.10 × 50,000 = 5,000

Updated 18-25 age group population in Delhi = 80,000 + 5,000 = 85,000

March migration out of Delhi to Goa: 20% of Delhi's updated 18-25 age group (85,000) = 0.20 × 85,000 = 17,000

Net change in Delhi's population = +13,000 + 5,000 - 17,000 = +1,000

Total population of Delhi in April = 250,000 + 1,000 = 251,000

1626Mathematics
The speed of three buses are in the ratio of 5 : 4 : 6. The ratio between the time taken by them to travel the same distance will be:
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Answer: (D) 12:15:10

Explanation

When distance is constant, time is inversely proportional to speed (Time = Distance / Speed).

Given speed ratio = 5 : 4 : 6

Ratio of time taken = (1/5) : (1/4) : (1/6)

To clear the fractions, multiply each term by the LCM of denominators (LCM of 5, 4, 6 = 60): (1/5 × 60) : (1/4 × 60) : (1/6 × 60) = 12 : 15 : 10

1627Mathematics
6% of (25% of ₹900) is:
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Answer: (A) 13.50

Explanation

Using the percentage formula, Percentage = (Rate / 100) × Base Value:

First, calculate 25% of ₹900: 25% of ₹900 = (25 / 100) × 900 = 225

Next, calculate 6% of ₹225: 6% of ₹225 = (6 / 100) × 225 = 13.50

Alternatively, multiplying the percentages directly: (6 / 100) × (25 / 100) × 900 = (150 × 900) / 10000 = 13.50

1628Mathematics
What should be added to (½ +⅓ +⅕) to get 3?
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Answer: (C) ⁵⁹⁄₃₀

Explanation

Let x be the required value to be added.

(½ + ⅓ + ⅕) + x = 3

Taking the LCM of the denominators 2, 3, and 5, which is 30: ½ + ⅓ + ⅕ = 15/30 + 10/30 + 6/30 = 31/30

Now, substituting the sum into the equation: 31/30 + x = 3 x = 3 - 31/30 x = (90 - 31) / 30 x = 59/30

1629Mathematics
ABCD is a square and Q is a point in its interior such that Δ QAB is equilateral. The measure of ∠ QCB is:
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Answer: (D) 75°

Explanation

In square ABCD, AB = BC and ∠ABC = 90°. Since △QAB is equilateral, QB = AB and ∠QBA = 60°.

Since QB = AB and BC = AB, it follows that QB = BC, making △QBC an isosceles triangle.

The angle ∠QBC = ∠ABC - ∠QBA = 90° - 60° = 30°.

In △QBC, the angles opposite to equal sides are equal, so ∠QCB = ∠BQC. Using the angle sum property of a triangle: ∠QBC + ∠QCB + ∠BQC = 180° 30° + 2 × ∠QCB = 180° 2 × ∠QCB = 150° ∠QCB = 75°

1630Mathematics
If n₄ = 70 , then find n.
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Answer: (B) 8

Explanation

Using the formula for combinations: ⁿC₄ = n(n - 1)(n - 2)(n - 3) / 24

Given that ⁿC₄ = 70: n(n - 1)(n - 2)(n - 3) / 24 = 70 n(n - 1)(n - 2)(n - 3) = 70 × 24 = 1680

Expressing 1680 as the product of four consecutive decreasing integers: 1680 = 8 × 7 × 6 × 5

Comparing the highest factors on both sides gives n = 8.

1631Mathematics
What is the least number that when divided by 18 and 24 leaves a reminder of 11 and 17, respectively?
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Answer: (D) 65

Explanation

When a number leaves remainders r₁ and r₂ when divided by divisors d₁ and d₂ such that the difference (d₁ - r₁) = (d₂ - r₂) = k is constant, the required least number is given by LCM(d₁, d₂) - k.

Here, 18 - 11 = 7 and 24 - 17 = 7, so k = 7.

LCM(18, 24) = 72

Required least number = 72 - 7 = 65

1632Mathematics
A, B, C, D and E have different heights. Only 2 people are shorter than D. E is taller than F, but shorter than A. A is not the tallest. How many people are taller than C?
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Answer: (A) None, as C is the tallest.

Explanation

Arranging the positions in descending order of height: 1 (tallest) > 2 > 3 > 4 > 5 (shortest)

Since only two people are shorter than D, D must be in position 3: _ > _ > D > _ > _

The given conditions state that A is taller than E, and E is taller than F, yielding the relative order A > E > F. Since A is not the tallest, A cannot be in position 1. Therefore, A must occupy position 2, while E and F occupy positions 4 and 5 respectively: _ > A > D > E > F

The remaining person, C, must occupy position 1 as the tallest individual. Consequently, zero people are taller than C.

1633Mathematics
Find the value of - 5{- 5 - (- 5 - 2) - 5} .
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Answer: (B) 15

Explanation

Using the order of operations (BODMAS):

Evaluate the innermost parentheses: 5 - 2 = - 7

Substitute this back into the curly brackets: 5 - (- 7) - 5 = - 5 + 7 - 5 = - 3

Multiply by the outer term: 5 × (- 3) = 15

1634Mathematics
The LCM of two numbers is 1024, and one of them is a prime number. Find their GCD.
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Answer: (A) 2

Explanation

The prime factorisation of 1024 is 2¹⁰. Since the LCM of two numbers is 1024, all prime factors of both numbers must be factors of 1024. The only prime factor of 1024 is 2, which means the prime number among the two given numbers is 2. As 2 is a factor of 1024, the greatest common divisor (GCD) of 2 and a number whose LCM with 2 is 1024 is 2.

1635Mathematics
The ratio between two numbers is 3:5 and their sum is 80. Find the greater of the two numbers.
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Answer: (B) 50

Explanation

Let the two numbers be 3x and 5x.

3x + 5x = 80 8x = 80 x = 10

The greater number = 5x = 5 × 10 = 50.

1636Mathematics
In a cuboid, the sum of the squares of its three dimensions is equal to half of its total surface area. If the volume of the cuboid is 729 cm³ , then find its lateral surface area (in cm² ).
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Answer: (C) 324

Explanation

Let the length, breadth, and height of the cuboid be l, b, and h respectively.

Given condition: l² + b² + h² = ½ × 2(lb + bh + hl) l² + b² + h² - lb - bh - hl = 0

Multiplying both sides by 2 gives: (l - b)² + (b - h)² + (h - l)² = 0

Since the sum of non-negative squares is zero, l = b = h. Thus, the cuboid is a cube.

Given volume l³ = 729 cm³, which gives side length l = 9 cm.

Lateral surface area of the cube = 4l² = 4 × 9² = 4 × 81 = 324 cm².

1637Mathematics
Shyam gets back the amount he had invested in buying 100 books by selling 65 of them. What is his profit percentage?
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Answer: (A) 53 11/13 %

Explanation

Let the cost price of 1 book be CP and the selling price of 1 book be SP.

Given that the selling price of 65 books equals the cost price of 100 books: 65 × SP = 100 × CP SP / CP = 100 / 65 = 20 / 13

Profit percentage = [(SP - CP) / CP] × 100 = [(20 - 13) / 13] × 100 = (7 / 13) × 100 = 700 / 13 % = 53 11/13 %

1638Mathematics
Ram and Shyam can finish a work in 30 days, Shyam and Bharti can finish it in 40 days and Bharti and Ram can finish it in 60 days. How long will they three together take to finish the work?
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Answer: (B) 26 2/3 days

Explanation

1-day work of Ram and Shyam = 1/30 1-day work of Shyam and Bharti = 1/40 1-day work of Bharti and Ram = 1/60

Adding these three pairs gives 2 × (1-day work of Ram + Shyam + Bharti) = 1/30 + 1/40 + 1/60 = (4 + 3 + 2)/120 = 9/120 = 3/40.

Therefore, 1-day work of Ram, Shyam, and Bharti together = 3/(40 × 2) = 3/80.

Total time taken by all three together = 80/3 = 26 2/3 days.

1639Mathematics
The HCF of all the natural numbers from 200 to 478 is:
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Answer: (A) 1

Explanation

The highest common factor (HCF) of any two consecutive natural numbers n and n + 1 is always 1, because gcd(n, n + 1) = gcd(n, 1) = 1. Since the set of natural numbers from 200 to 478 includes consecutive integers such as 200 and 201, the only factor common to all the numbers in the range is 1.

1640Mathematics
The average of 7, 14, 21, 28, ... 77 is:
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Answer: (D) 42

Explanation

For an arithmetic progression, the average of the terms is equal to the average of the first and last terms:

Average = (First term + Last term) / 2

Substituting the first term (7) and the last term (77):

Average = (7 + 77) / 2 = 84 / 2 = 42

1641Mathematics
If x:y = y:z = 2:3 , then find x:y:z
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Answer: (D) 4:6:9

Explanation

Given x : y = 2 : 3 and y : z = 2 : 3. To make the common term y equal in both ratios, multiply x : y by 2 and y : z by 3.

x : y = (2 × 2) : (3 × 2) = 4 : 6 y : z = (2 × 3) : (3 × 3) = 6 : 9

Combining both ratios yields x : y : z = 4 : 6 : 9.

1642Mathematics
A certain number of women went to a hotel. Each woman spent as many rupees as one-fourth of the number of women. If the total bill paid was ₹20,449, then how many women visited the hotel?
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Answer: (B) 286

Explanation

Let N be the total number of women visiting the hotel.

Each woman spent N/4 rupees.

Total bill = Number of women × Amount spent by each woman 20,449 = N × (N/4) N² = 20,449 × 4 N² = 81,796 N = √81,796 = 286

1643Mathematics
Which of the following political parties is NOT in alliance with Maha Vikas Aghadi (English: Maharashtra Development Front) Government?
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Answer: (C) Janata Dal (United)

Explanation

Janata Dal (United) is a regional political party primarily based in Bihar and affiliated with the National Democratic Alliance. It has no presence or political coalition with the Maha Vikas Aghadi in Maharashtra.

1644Mathematics
Find the value of ((0.9 × 0.9 × 0.9))/(0.9).
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Answer: (B) 0.81

Explanation

Cancelling the common factor 0.9 in the numerator and denominator yields:

(0.9 × 0.9 × 0.9) / 0.9 = 0.9 × 0.9 = 0.81

1645Mathematics
In which of the following cities is the Tomb of Sheikh Salim Chisti located?
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Answer: (A) Fatehpur Sikri

Explanation

The Tomb of Sheikh Salim Chishti is located within the courtyard of the Jama Masjid at Fatehpur Sikri, Uttar Pradesh. It was constructed by Mughal Emperor Akbar between 1580 and 1581 to honor the Sufi saint Sheikh Salim Chishti, who had predicted the birth of Akbar's son, Prince Salim (Emperor Jahangir). Built with white marble and featuring exquisite serpent brackets and intricately carved jali screens, it is considered one of the finest examples of Mughal architecture.

1646Mathematics
In a Δ ABC , if ∠ A + ∠ B = 110° and ∠ B - ∠ A = 10° , then which of the following statements holds true for the triangle?
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Answer: (A) AB is the longest side and BC is the shortest side.

Explanation

Solving the given equations: ∠A + ∠B = 110° ∠B - ∠A = 10°

Adding both equations gives 2∠B = 120°, which yields ∠B = 60°. Substituting this into ∠A + 60° = 110° gives ∠A = 50°.

Using the angle sum property of a triangle (∠A + ∠B + ∠C = 180°): ∠C = 180° - 110° = 70°

Comparing the interior angles gives ∠A (50°) < ∠B (60°) < ∠C (70°).

In any triangle, the side opposite the largest angle is the longest side, and the side opposite the smallest angle is the shortest side. The side opposite to largest angle ∠C (70°) is AB, and the side opposite to smallest angle ∠A (50°) is BC. Therefore, AB is the longest side and BC is the shortest side.

1647Mathematics
If a woman covers a distance of 10⅕ km in 3 hours, then find the distance covered by her in 5 hours.
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Answer: (C) 17km

Explanation

Distance covered in 3 hours = 10⅕ km = 51/5 km

Speed = Distance ÷ Time = (51/5) ÷ 3 = 17/5 km/h

Distance covered in 5 hours = Speed × Time = (17/5) × 5 = 17 km

1648Mathematics
Which of the following companies is NOT on the list of Maharatna Companies in India?
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Answer: (D) Cement Corporation of India

Explanation

Cement Corporation of India Limited (CCI) was incorporated in 1965 as a Central Public Sector Enterprise under the administrative control of the Ministry of Heavy Industries. It is categorized as a Miniratna enterprise and does not hold Maharatna status, which is granted to larger public sector units with extensive financial autonomy.

1649Mathematics
Which of the following types of light carries a signal from a television remote to the device it controls?
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Answer: (D) Infrared

Explanation

Television remotes use infrared light to transmit signals to electronic devices. A light-emitting diode (LED) at the front of the remote pulses invisible infrared light at a specific frequency, typically around 940 nanometers, to send binary-coded signals. An infrared receiver on the device detects these light pulses and converts them back into electrical signals that execute specific commands, such as changing channels or adjusting the volume.

1650Mathematics
What is the smallest positive integer required to be added to 2712 to make the sum a perfect cube?
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Answer: (B) 32

Explanation

The smallest perfect cube greater than 2712 is 14³, which equals 2744 (since 13³ = 2197 and 14³ = 2744).

To find the required positive integer to be added: 2744 - 2712 = 32

Answer key

Tap a number to jump to that question.

  1. 1601D
  2. 1602A
  3. 1603A
  4. 1604A
  5. 1605C
  6. 1606B
  7. 1607B
  8. 1608C
  9. 1609D
  10. 1610B
  11. 1611C
  12. 1612A
  13. 1613D
  14. 1614D
  15. 1615B
  16. 1616D
  17. 1617C
  18. 1618B
  19. 1619D
  20. 1620B
  21. 1621A
  22. 1622C
  23. 1623C
  24. 1624D
  25. 1625D
  26. 1626D
  27. 1627A
  28. 1628C
  29. 1629D
  30. 1630B
  31. 1631D
  32. 1632A
  33. 1633B
  34. 1634A
  35. 1635B
  36. 1636C
  37. 1637A
  38. 1638B
  39. 1639A
  40. 1640D
  41. 1641D
  42. 1642B
  43. 1643C
  44. 1644B
  45. 1645A
  46. 1646A
  47. 1647C
  48. 1648D
  49. 1649D
  50. 1650B

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