RRB NTPC2021MathematicsPage 21 of 36

RRB NTPC CBT 1 2021 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1001–1050 of 1,785, each with the correct answer and a step-by-step explanation.

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1001Mathematics
A and B can complete a piece of work in 56 and 70 days respectively. They began the work together but A left after some days and B finished the remaining work in 34 days. After how many days did A leave?
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Answer: (C) 16

Explanation

Total work = LCM(56, 70) = 280 units.

Efficiency of A = 280 / 56 = 5 units/day Efficiency of B = 280 / 70 = 4 units/day

Work completed by B alone in the last 34 days = 34 × 4 = 136 units. Remaining work completed by A and B together = 280 - 136 = 144 units.

Combined efficiency of A and B = 5 + 4 = 9 units/day. Number of days A worked with B = 144 / 9 = 16 days.

1002Mathematics
If p:q=9:2 , then find the ratio (4p+7q):(4p-7q)
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Answer: (B) 25:11

Explanation

Given p : q = 9 : 2, substitute p = 9 and q = 2 directly into the given expression:

4p + 7q = 4(9) + 7(2) = 36 + 14 = 50 4p - 7q = 4(9) - 7(2) = 36 - 14 = 22

Therefore, the ratio (4p + 7q) : (4p - 7q) = 50 : 22 = 25 : 11.

1003Mathematics
The selling price of 150 items is equal to the cost price of 125 items. What will be the percentage loss?
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Answer: (A) 16 {2}{3}

Explanation

Let CP be the cost price and SP be the selling price of one item.

Given, 150 × SP = 125 × CP SP / CP = 125 / 150 = 5 / 6

Loss = CP - SP = 6 - 5 = 1

Loss Percentage = (Loss / CP) × 100 = (1 / 6) × 100 = 16⅔%

1004Mathematics
Find the value of x. 1⅕ -3²⁄₄÷ 1¾÷ (x + 3⅛)÷ 1⅐ = 1
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Answer: (C) x = 5⅝

Explanation

Convert all mixed fractions to improper fractions: 1 1/5 = 6/5 3 2/4 = 7/2 1 3/4 = 7/4 3 1/8 = 25/8 1 1/7 = 8/7

Substitute these into the given equation: 6/5 - [7/2 ÷ 7/4 ÷ (x + 25/8) ÷ 8/7] = 1

First, simplify (7/2 ÷ 7/4): (7/2) × (4/7) = 2

The equation simplifies to: 6/5 - [2 ÷ (x + 25/8) ÷ 8/7] = 1 6/5 - 1 = 2 ÷ (x + 25/8) ÷ (8/7) 1/5 = 2 × (1 / (x + 25/8)) × (7/8) 1/5 = (14/8) / (x + 25/8) 1/5 = 14 / (8x + 25)

Cross-multiply to solve for x: 8x + 25 = 70 8x = 45 x = 45/8 = 5 5/8

1005Mathematics
Find the second term in a sequence of numbers that leaves the remainders 1, 2 and 7 when divided by 2, 3 and 8 respectively.
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Answer: (D) 47

Explanation

When the difference between each divisor and its corresponding remainder is constant (2 - 1 = 1, 3 - 2 = 1, 8 - 7 = 1), the numbers in the sequence follow the formula:

N = LCM(2, 3, 8) × k - 1

Calculating LCM(2, 3, 8) = 24 gives the general term N = 24k - 1.

For the second term (k = 2): N = 24 × 2 - 1 = 47

1006Mathematics
What is the value of sin 15° ?
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Answer: (D) (√6 - √2)/(4)

Explanation

Using the angle difference formula sin(A - B) = sin A cos B - cos A sin B:

sin 15° = sin(45° - 30°) = sin 45° cos 30° - cos 45° sin 30°

Substituting the standard trigonometric values: sin 45° = 1/√2, cos 45° = 1/√2 sin 30° = ½, cos 30° = √3/2

sin 15° = (1/√2) × (√3/2) - (1/√2) × (½) = (√3 - 1) / (2√2)

Multiplying the numerator and denominator by √2 to rationalize: sin 15° = (√6 - √2) / 4

1007Mathematics
Find the value of ab, if a + b = 5 and a² - b² = 75
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Answer: (C) -50

Explanation

Using the algebraic identity a² - b² = (a + b)(a - b): 75 = 5 × (a - b) a - b = 15

Using the identity 4ab = (a + b)² - (a - b)²: 4ab = 5² - 15² 4ab = 25 - 225 4ab = -200 ab = -50

1008Mathematics
Find the value of 3(x+y) if x= { {3}+1}{ {3}- 1} and y= { {3}- 1}{ {3}+1}
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Answer: (C) 12

Explanation

Using the identity (a+b)/(a-b) + (a-b)/(a+b) = 2(a² + b²)/(a² - b²), let a = √3 and b = 1.

x + y = [(√3 + 1)² + (√3 - 1)²] / [(√3)² - 1²] x + y = 2((√3)² + 1²) / (3 - 1) = 2(3 + 1) / 2 = 4

Therefore, 3(x + y) = 3 × 4 = 12.

1009Mathematics
National Highways Authority of India (NHAI) was set up in:
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Answer: (D) 1988

Explanation

The National Highways Authority of India (NHAI) was set up under the National Highways Authority of India Act, 1988. It functions as an autonomous agency under the Ministry of Road Transport and Highways, responsible for the development, maintenance, and management of the national highway network across the country.

1010Mathematics
A square park is surrounded by a path of uniform width 1.5 m all around it. The area of the path is 225m² .Find the perimeter of the park.
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Answer: (A) 144m

Explanation

Let x be the side length of the inner square park. Since the path has a uniform width of 1.5 m all around, the side length of the outer square including the path is x + 2(1.5) = x + 3 m.

Area of the path = (Outer side)² − (Inner side)² 225 = (x + 3)² − x² 225 = x² + 6x + 9 − x² 225 = 6x + 9 6x = 216 x = 36 m

Perimeter of the park = 4 × x = 4 × 36 = 144 m.

1011Mathematics
82% of a number is 738. What is 90% of that number?
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Answer: (D) 810

Explanation

If 82% of the number is 738, then 1% of the number is 738 ÷ 82 = 9.

Therefore, 90% of the number is 90 × 9 = 810.

1012Mathematics
If a sum invested at simple interest, triples itself in 8 years, how many times of itself will it be in 12 years?
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Answer: (B) 4 times

Explanation

Under simple interest, the interest earned is directly proportional to time. When a principal P triples in 8 years, the simple interest earned in 8 years is 3P - P = 2P.

Interest earned per year = 2P / 8 = P / 4. Interest earned in 12 years = 12 × (P / 4) = 3P.

Total amount after 12 years = Principal + Interest = P + 3P = 4P.

1013Mathematics
If (a²+ {1}{a²})=18 then find (a- {1}{a})
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Answer: (C) 4

Explanation

Using the algebraic identity (a - 1/a)² = a² + 1/a² - 2:

Substituting a² + 1/a² = 18 gives: (a - 1/a)² = 18 - 2 = 16

Taking the square root on both sides yields: a - 1/a = √16 = 4

1014Mathematics
The domain of cosec x is:
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Answer: (A) R-{π π |n∈ Z}

Explanation

The cosecant function is defined as cosec x = 1 / sin x. For cosec x to be well-defined, the denominator sin x must not be equal to zero. Since sin x = 0 whenever x is an integral multiple of π (i.e., x = nπ where n ∈ Z), these values must be excluded from the set of all real numbers R. Thus, the domain of cosec x is R - {nπ | n ∈ Z}.

1015Mathematics
Which of the following is a prime number?
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Answer: (B) 173

Explanation

To determine if a number is prime, check for divisibility by prime numbers up to its square root. For 173, √173 ≈ 13.15, so the prime numbers to test are 2, 3, 5, 7, 11, and 13. Since 173 is not divisible by any of these prime numbers (173 ÷ 7 = 24 remainder 5, 173 ÷ 11 = 15 remainder 8, 173 ÷ 13 = 13 remainder 4), it has no positive factors other than 1 and 173, making it a prime number.

1016Mathematics
The values of the mode and the mean are 25.2 and 27.5 respectively in a moderately asymmetrical distribution. Find the value of the median of the distribution.
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Answer: (D) 26.73

Explanation

For a moderately asymmetrical distribution, Karl Pearson's empirical formula relating mean, median, and mode is:

Mode = 3 × Median - 2 × Mean

Substituting the given values into the formula: 25.2 = 3 × Median - 2 × 27.5 25.2 = 3 × Median - 55 3 × Median = 80.2 Median = 80.2 / 3 = 26.733 ≈ 26.73

1017Mathematics
Calculate the mean for following set of values- 2.2,4.2,6.4,8.3,10.5
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Answer: (C) 6.32

Explanation

Mean = (Sum of all values) / (Total number of values)

Sum of the given values = 2.2 + 4.2 + 6.4 + 8.3 + 10.5 = 31.6 Total number of values = 5

Mean = 31.6 / 5 = 6.32

1018Mathematics
Which Indian state shares borders with China, Nepal and Bhutan?
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Answer: (C) Sikkim

Explanation

Sikkim is located in the northeastern part of India, nestled in the Himalayas. It shares international borders with three countries: Nepal to its west, China (Tibet Autonomous Region) to its north and northeast, and Bhutan to its east. Within India, it shares its southern border with West Bengal.

1019Mathematics
Simplify. {1}{5.8}+ {1}{8.11}+ {1}{11.14}+ {1}{14.17}
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Answer: (B) {4}{85}

Explanation

The given expression is a telescoping series of the form 1/(a × b) where the difference between factors in each denominator is d = 3.

Sum = (1/d) × (1/first factor - 1/last factor)

Here, d = 3, the first factor is 5, and the last factor is 17.

Sum = (1/3) × (1/5 - 1/17) Sum = (1/3) × ((17 - 5) / (5 × 17)) Sum = (1/3) × (12 / 85) Sum = 4 / 85

Alternatively, for a telescoping series with n terms: Sum = n / (first factor × last factor) = 4 / (5 × 17) = 4 / 85

1020Mathematics
If 2x+y=15,y+2z=17 and x+2y=9 ,then the value of 4x+3y+z=?
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Answer: (C) 39

Explanation

Solving the system of simultaneous linear equations:

From 2x + y = 15 and x + 2y = 9, multiply the first equation by 2 and subtract the second equation: 2(2x + y) - (x + 2y) = 2(15) - 9 3x = 21 x = 7

Substitute x = 7 into 2x + y = 15: 2(7) + y = 15 y = 1

Substitute y = 1 into y + 2z = 17: 1 + 2z = 17 2z = 16 z = 8

Evaluating the required expression: 4x + 3y + z = 4(7) + 3(1) + 8 = 28 + 3 + 8 = 39

1021Mathematics
Find the number of sides of a regular polygon if each interior angle is 165°.
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Answer: (B) 24

Explanation

The sum of an interior angle and an exterior angle of a regular polygon is 180°. Therefore, each exterior angle = 180° - 165° = 15°.

Since the sum of all exterior angles of a convex polygon is 360°, the number of sides n = 360° / 15° = 24.

1022Mathematics
When 106 is subtracted from a number, it reduces to its 47%. What is 11.5% of that number?
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Answer: (C) 23

Explanation

Let the original number be x.

Subtracting 106 reduces the number to 47% of its value, which means the difference corresponds to 53% of the number: (100% - 47%) of x = 106 53% of x = 106 1% of x = 106 / 53 = 2 x = 200

Now, calculate 11.5% of 200: 11.5% of 200 = 11.5 × 2 = 23

1023Mathematics
Find the area of a triangle whose sides are 5 cm, 7 cm and 11 cm.
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Answer: (C) 12.97 cm²

Explanation

Using Heron's formula, the area of a triangle with side lengths a = 5 cm, b = 7 cm, and c = 11 cm is given by Area = √(s(s - a)(s - b)(s - c)), where s is the semi-perimeter.

s = (a + b + c) / 2 = (5 + 7 + 11) / 2 = 11.5 cm

Substitute the values into the formula: Area = √(11.5 × (11.5 - 5) × (11.5 - 7) × (11.5 - 11)) Area = √(11.5 × 6.5 × 4.5 × 0.5) Area = √168.1875 ≈ 12.97 cm²

1024Mathematics
What will be the simple interest on ₹10,000 at 12% per annum for 5 years?
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Answer: (B) ₹6,000

Explanation

Simple Interest (SI) = (P × R × T) / 100

Given: Principal (P) = ₹10,000 Rate of interest (R) = 12% Time period (T) = 5 years

Substituting the given values into the formula: SI = (10,000 × 12 × 5) / 100 = 100 × 60 = ₹6,000

1025Mathematics
What is the value of cot(15°) - tan(15°)?
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Answer: (C) 2√3

Explanation

Using the trigonometric identity cot(θ) - tan(θ) = 2 cot(2θ):

For θ = 15°: cot(15°) - tan(15°) = 2 cot(30°)

Since cot(30°) = √3: cot(15°) - tan(15°) = 2 × √3 = 2√3

Alternatively, substituting the standard values tan(15°) = 2 - √3 and cot(15°) = 2 + √3: (2 + √3) - (2 - √3) = 2√3

1026Mathematics
By how much is ⅙ th of 432 smaller than ¾ th of 216?
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Answer: (C) 90

Explanation

(1/6) × 432 = 72

(3/4) × 216 = 3 × 54 = 162

Difference = 162 - 72 = 90

1027Mathematics
IfA:B=2:3,B:C=2:3andC:D=3:4,thenA:D=?
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Answer: (C) 1:3

Explanation

To find the ratio A:D, multiply the given consecutive ratios:

A/D = (A/B) × (B/C) × (C/D)

Substituting the given values into the formula: A/D = (2/3) × (2/3) × (3/4) = 12/36 = 1/3

1028Mathematics
Sunil and Kamal took loan of 40,000 each for 1 year 6 months from a moneylender who charged simple interest from Sunil @ 11% per annum and compound interest from Kamal @ 10% per annum compounded semi-annually. Who paid more interest and by what amount?
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Answer: (B) Sunil paid 295 more

Explanation

Simple interest paid by Sunil for 1.5 years at 11% per annum: SI = (P × R × T) / 100 = (40,000 × 11 × 1.5) / 100 = ₹6,600

Compound interest paid by Kamal with semi-annual compounding at 5% per half-year for 3 half-years: Amount = P × (1 + r/100)ⁿ = 40,000 × (1 + 5/100)³ = 40,000 × (21/20)³ = ₹46,305 CI = Amount - Principal = 46,305 - 40,000 = ₹6,305

Difference = 6,600 - 6,305 = ₹295 extra paid by Sunil.

1029Mathematics
A shopkeeper incurred a loss of 10% by selling an item for ₹1,980. At what price (in ₹) should he sell that item to gain 15% ?
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Answer: (C) 2,530

Explanation

Using the direct formula: New Selling Price = Old Selling Price × (100 + Gain%) / (100 - Loss%)

Substituting the given values: New Selling Price = 1980 × (100 + 15) / (100 - 10) New Selling Price = 1980 × 115 / 90 New Selling Price = 22 × 115 = ₹2,530

1030Mathematics
If cos x - 3sin x = √3 sin x, then the value of tan x is:
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Answer: (A) 3- √3 / 6

Explanation

Rearranging the given equation: cos x = 3 sin x + √3 sin x cos x = (3 + √3) sin x

Dividing both sides by (3 + √3) cos x: tan x = sin x / cos x = 1 / (3 + √3)

Rationalizing the denominator by multiplying the numerator and denominator by (3 - √3): tan x = (3 - √3) / ((3 + √3)(3 - √3)) tan x = (3 - √3) / (3² - (√3)²) tan x = (3 - √3) / (9 - 3) tan x = (3 - √3) / 6

1031Mathematics
A retailer buys a bag containing 54 kg oranges at ₹25 per kg. Later upon sorting he finds that 4 kg oranges are rotten, he throws them and sells the remaining ones at ₹36 per kg. Find his profit percent.
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Answer: (C) 33 1/3%

Explanation

Total Cost Price (CP) = 54 × 25 = ₹1350. Usable quantity of oranges = 54 - 4 = 50 kg. Total Selling Price (SP) = 50 × 36 = ₹1800. Profit = SP - CP = 1800 - 1350 = ₹450. Profit percentage = (Profit / CP) × 100 = (450 / 1350) × 100 = 33 1/3%.

1032Mathematics
The ratio of the length to the breadth of a rectangular field is 7 : 6. If the breadth is 35 m less than the length, then the perimeter of the field is:
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Answer: (A) 910 m

Explanation

Let the length and breadth of the rectangular field be 7x and 6x respectively.

Given that the breadth is 35 m less than the length: 7x - 6x = 35 x = 35

The formula for the perimeter of a rectangle is: Perimeter = 2 × (Length + Breadth) Perimeter = 2 × (7x + 6x) = 26x

Substituting the value of x: Perimeter = 26 × 35 = 910 m

1033Mathematics
The descending order of the fractions ⅔, ⅙, ⅕, ³⁄₇ is:
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Answer: (A) ⅔, ³⁄₇, ⅕, ⅙

Explanation

Converting each fraction into its decimal value: 2/3 ≈ 0.667 3/7 ≈ 0.429 1/5 = 0.200 1/6 ≈ 0.167

Arranging these decimal values from largest to smallest gives 0.667 > 0.429 > 0.200 > 0.167. Replacing the decimals with their original fractional forms gives 2/3, 3/7, 1/5, 1/6.

1034Mathematics
Anupam and Vineet standing together started running in opposite direction on 2km long circular racing track. They ran at the speeds of 9km / h and 11km / h respectively. After how much time will they meet on the track?
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Answer: (A) 6 min

Explanation

When two objects move in opposite directions, their relative speed is the sum of their individual speeds: Relative Speed = 9 km/h + 11 km/h = 20 km/h

The time taken to meet on a circular track of length 2 km is given by: Time = Distance / Relative Speed = 2 km / 20 km/h = 1/10 hour

Converting hours to minutes: Time = (1/10) × 60 minutes = 6 minutes

1035Mathematics
Simplify the following. ((tan 40°)/(cos ec50°))² + ((cot 40°)/(sec 50°))²
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Answer: (D) 1

Explanation

Using the complementary angle identities, cosec 50° = sec 40° and sec 50° = cosec 40°.

First term: tan 40° / cosec 50° = tan 40° / sec 40° = (sin 40° / cos 40°) / (1 / cos 40°) = sin 40°

Second term: cot 40° / sec 50° = cot 40° / cosec 40° = (cos 40° / sin 40°) / (1 / sin 40°) = cos 40°

Squaring both terms and adding them gives: (sin 40°)² + (cos 40°)² = sin² 40° + cos² 40° = 1

1036Mathematics
A man can complete a work in 20 days and a woman can complete the same work in 45 days. In how many days 2 men and 3 women can complete the same work?
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Answer: (B) 6 days

Explanation

1 man's 1-day work = 1/20 1 woman's 1-day work = 1/45

1-day work of 2 men and 3 women = 2(1/20) + 3(1/45) = 1/10 + 1/15 = (3 + 2)/30 = 5/30 = 1/6

Total time required = 1 ÷ (1/6) = 6 days.

1037Mathematics
If polynomials 4x³ + ax² - 3x + 1 and x⁴ + x³ - x² + 6 leave the same remainder when each is divided by (x - 1), then the value of a is:
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Answer: (D) 5

Explanation

By the Remainder Theorem, when a polynomial P(x) is divided by (x - 1), the remainder is P(1).

For the first polynomial P(x) = 4x³ + ax² - 3x + 1: P(1) = 4(1)³ + a(1)² - 3(1) + 1 = 4 + a - 3 + 1 = a + 2

For the second polynomial Q(x) = x⁴ + x³ - x² + 6: Q(1) = 1⁴ + 1³ - 1² + 6 = 1 + 1 - 1 + 6 = 7

Since both polynomials leave the same remainder when divided by (x - 1): P(1) = Q(1) a + 2 = 7 a = 5

1038Mathematics
40% of the first number is 12 and 50% of the second number is 24. The ratio of the first number to the second number is:
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Answer: (D) 5 : 8

Explanation

Let the first number be x and the second number be y.

Using the given percentages: 40% of x = 12 ⇒ x = (12 × 100) / 40 = 30 50% of y = 24 ⇒ y = (24 × 100) / 50 = 48

The ratio of the first number to the second number is: x : y = 30 : 48 = 5 : 8

1039Mathematics
A sum of money at simple interest doubles itself in 4 years 4 months. In how much time will it triple itself?
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Answer: (A) 8⅔ years

Explanation

Time taken to double, T₁ = 4 years 4 months = 4 + 4/12 = 13/3 years.

At simple interest, the interest earned is directly proportional to time.

For the sum to double, the interest earned equals the principal in 13/3 years. For the sum to triple, the interest earned must be twice the principal.

Time required = 2 × (13/3) = 26/3 = 8⅔ years.

1040Mathematics
If the angles of a triangle are in the ratio 4:5:6 , find the smallest angle (in ° ).
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Answer: (A) 48

Explanation

The sum of all interior angles in a triangle is 180°.

Given the ratio of the angles is 4 : 5 : 6, total ratio parts = 4 + 5 + 6 = 15.

Value of 1 part = 180° ÷ 15 = 12°

Smallest angle = 4 parts = 4 × 12° = 48°

1041Mathematics
What is the SI unit of pressure?
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Answer: (B) Pascal

Explanation

Pressure is defined as the force applied perpendicular to the surface of an object per unit area (P = F/A). In the International System of Units (SI), force is measured in newtons (N) and area in square meters (m²). Therefore, the SI unit of pressure is newton per square meter (N/m²), which is officially named the Pascal (Pa) in honor of the scientist Blaise Pascal (1 Pa = 1 N/m²).

1042Mathematics
A wheel completes 21000 revolutions covering a distance of 66 km. Find the radius of the wheel.
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Answer: (D) ½ m

Explanation

Distance covered by a rotating wheel in N revolutions is given by: Distance = N × 2πr

Converting distance into metres: 66 km = 66000 m.

Substituting the given values: 66000 = 21000 × 2 × (22/7) × r 66000 = 3000 × 44 × r 66000 = 132000 × r r = 66000 / 132000 = ½ m

1043Mathematics
With whom is the Statement of Intent (SOI) signed by NITI Aayog as part of the Atal Innovation Mission to open the Digital Disha Programme?
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Answer: (A) Adobe

Explanation

NITI Aayog's Atal Innovation Mission (AIM) signed a Statement of Intent (SOI) with Adobe to drive digital literacy and foster creative skills among school children in India. Under this collaboration, Adobe implements its Digital Disha Programme across schools equipped with Atal Tinkering Labs (ATLs), providing students and educators with free access to creative learning tools such as Adobe Spark Premium to enhance technology-based learning.

1044Mathematics
The mean of the squares of first ten natural numbers is:
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Answer: (A) 77 2

Explanation

The formula for the mean of the squares of the first n natural numbers is:

Mean = (n + 1)(2n + 1) / 6

For the first 10 natural numbers (n = 10):

Mean = (10 + 1)(2 × 10 + 1) / 6 = (11 × 21) / 6 = 77 / 2

1045Mathematics
Which of the following equations represent a line parallel to y- axis?
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Answer: (B) x + 3 = 4 - 2x

Explanation

A line parallel to the y-axis has a constant x-coordinate for all values of y, giving it an equation of the form x = k, where k is a constant.

Simplifying x + 3 = 4 - 2x: 3x = 1 x = ⅓

Since this simplifies to x = ⅓, it represents a vertical line parallel to the y-axis.

1046Mathematics
If the mean of six observations 5, 7, 9, α , 11 and 12 is 9, then the value of α is :
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Answer: (D) 10

Explanation

Mean = (Sum of observations) / (Total number of observations)

9 = (5 + 7 + 9 + α + 11 + 12) / 6 9 = (44 + α) / 6 54 = 44 + α α = 54 - 44 = 10

1047Mathematics
LCM of 14, 21, 25 and 70 is:
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Answer: (D) 1050

Explanation

To find the Least Common Multiple (LCM) of 14, 21, 25, and 70, write each number in its prime factorized form: 14 = 2 × 7 21 = 3 × 7 25 = 5² 70 = 2 × 5 × 7

Taking the highest power of every prime factor involved: LCM = 2¹ × 3¹ × 5² × 7¹ = 2 × 3 × 25 × 7 = 1050

1048Mathematics
Simplify the following. (225÷ 25 - 10)× 5 + 2 - 7× 3
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Answer: (A) - 24

Explanation

Following the BODMAS rule (Brackets, Orders, Division/Multiplication, Addition/Subtraction):

Evaluate the expression inside the bracket: (225 ÷ 25 - 10) = 9 - 10 = -1

Perform multiplication: (-1) × 5 + 2 - 7 × 3 = -5 + 2 - 21

Perform addition and subtraction from left to right: -5 + 2 - 21 = -3 - 21 = -24

1049Mathematics
If a²ˣ = b,b²ʸ = c,c²ᶻ = a then the value of xyz is:
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Answer: (D) ⅛

Explanation

Given the exponential equations: a⁽2x) = b b⁽2y) = c c⁽2z) = a

Substituting the expression for b into the second equation: (a⁽2x))⁽2y) = c a⁽4xy) = c

Substituting this expression for c into the third equation: (a⁽4xy))⁽2z) = a a⁽8xyz) = a¹

Equating the exponents on both sides: 8xyz = 1 xyz = 1/8

1050Mathematics
Solve the following. (√(196))/(7) × (√(441))/(7) × (120)/(√(225)) = ?
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Answer: (D) 48

Explanation

Simplify each square root and fraction in the given expression:

√196 = 14 √441 = 21 √225 = 15

Substitute these values into the expression:

(14 ÷ 7) × (21 ÷ 7) × (120 ÷ 15) = 2 × 3 × 8 = 48

Answer key

Tap a number to jump to that question.

  1. 1001C
  2. 1002B
  3. 1003A
  4. 1004C
  5. 1005D
  6. 1006D
  7. 1007C
  8. 1008C
  9. 1009D
  10. 1010A
  11. 1011D
  12. 1012B
  13. 1013C
  14. 1014A
  15. 1015B
  16. 1016D
  17. 1017C
  18. 1018C
  19. 1019B
  20. 1020C
  21. 1021B
  22. 1022C
  23. 1023C
  24. 1024B
  25. 1025C
  26. 1026C
  27. 1027C
  28. 1028B
  29. 1029C
  30. 1030A
  31. 1031C
  32. 1032A
  33. 1033A
  34. 1034A
  35. 1035D
  36. 1036B
  37. 1037D
  38. 1038D
  39. 1039A
  40. 1040A
  41. 1041B
  42. 1042D
  43. 1043A
  44. 1044A
  45. 1045B
  46. 1046D
  47. 1047D
  48. 1048A
  49. 1049D
  50. 1050D

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