If the angles of a triangle are in the ratio of 2:3:7, then find the ratio of the greatest angle to the smallest angle.
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Answer: (A) 7:2
Explanation
Let the three angles of the triangle be 2x, 3x, and 7x. Among these, the greatest angle is 7x and the smallest angle is 2x. The ratio of the greatest angle to the smallest angle is given by 7x : 2x = 7:2.
202Mathematics
An angle is 3 0° more than one half of its complement. Find difference between the greater and the smaller angles.
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Answer: (A) 1 0°
Explanation
Let the angle be x. Its complement is (90° - x).
According to the given condition:
x = ½(90° - x) + 30°
x = 45° - ½x + 30°
1.5x = 75°
x = 50°
The complement angle is 90° - 50° = 40°.
The difference between the greater and smaller angles is 50° - 40° = 10°.
203Mathematics
What are the components of (x⁶ - x⁴ - x⁵ - x⁴ + x² - 4)?
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Answer: (D) Neither (x - 1) or (x + 1)
Explanation
By the Factor Theorem, a linear expression (x - a) is a factor of a polynomial P(x) if and only if P(a) = 0.
Simplifying the given polynomial by combining like terms:
P(x) = x⁶ - x⁵ - 2x⁴ + x² - 4
To check if (x - 1) is a factor, substitute x = 1:
P(1) = 1⁶ - 1⁵ - 2(1)⁴ + 1² - 4 = 1 - 1 - 2 + 1 - 4 = -5 ≠ 0
To check if (x + 1) is a factor, substitute x = -1:
P(-1) = (-1)⁶ - (-1)⁵ - 2(-1)⁴ + (-1)² - 4 = 1 + 1 - 2 + 1 - 4 = -3 ≠ 0
Since neither P(1) nor P(-1) equals zero, neither (x - 1) nor (x + 1) is a factor.
204Mathematics
Find the simple interest on Rs. 50 for 6 months at the rate of 10 paise per rupee per month.
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Answer: (D) Rs. 30
Explanation
Interest on 1 rupee for 1 month = 10 paise = Rs. 0.10
Simple Interest = Principal × Rate per rupee per month × Time in months
= 50 × 0.10 × 6
= Rs. 30
205Mathematics
Two numbers are in the ratio 5:6.When 6 is added to each, the ratio becomes 7:8 then the numbers are
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Answer: (C) 15 | 18
Explanation
Let the original numbers be represented by the ratio 5:6, so they are 5x and 6x.
Adding 6 to each number increases the ratio terms from 5 to 7 and from 6 to 8, representing a uniform increase of 2 ratio units.
2 ratio units = 6
1 ratio unit = 3
Therefore, the original numbers are 5 × 3 = 15 and 6 × 3 = 18.
206Mathematics
The ratio between the speeds of two buses is 11:9. If the second bus runs 270 kms in 15 hours, then the speed of the first bus is?
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Answer: (D) 22 km/hr
Explanation
Speed of the second bus = Distance ÷ Time = 270 ÷ 15 = 18 km/hr.
The ratio of the speeds of the two buses is given as 11:9.
Speed of the first bus = (11/9) × 18 = 22 km/hr.
207Mathematics
The product of the ages of Swati and Aparna is 120. If thrice the age of Aparna is more than Swati's age by 2 years, find the age of Swati.
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Answer: (A) 18
Explanation
Let S and A be the ages of Swati and Aparna respectively.
From the given conditions:
S × A = 120
3A - S = 2
Substituting A = 120 / S into the second equation:
3(120 / S) - S = 2
360 - S² = 2S
S² + 2S - 360 = 0
Factoring the quadratic equation:
(S + 20)(S - 18) = 0
Since age cannot be negative, S = 18.
208Mathematics
A wholesaler sold a water purifier at a loss of 40%. If the selling price has been increased by Rs. 125, then wholesaler will get the profit of 10%. What was the cost price of the purifier?
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Answer: (A) Rs. 250
Explanation
Let the cost price of the water purifier be CP.
Initial selling price at 40% loss = 60% of CP
New selling price at 10% profit = 110% of CP
The increase of Rs. 125 in the selling price represents the total percentage change from a 40% loss to a 10% profit:
Read the following table carefully and answer the questions given below:
The percentage change in sales of six departmental stores from 2010 to 2012 is shown in the following table:
Store | Percentage Change From 2010 to 2011 | From 2011 to 2012
P | +20 | -20
Q | -20 | +9
R | +5 | +12
S | -7 | -15
T | +17 | -8
U | +21 | +9
Sales in store P amounted to Rs. 80 lakhs in 2010. What was the sales amount of the same store in 2012?
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Answer: (A) 76.8 lakhs
Explanation
Using the net percentage change formula for successive percentage changes of +20% and -20%:
Net Change = a + b + (a × b)/100 = 20 - 20 + (20 × -20)/100 = -4%
Read the following table carefully and answer the questions given below:
The percentage change in sales of six departmental stores from 2010 to 2012 is shown in the following table:
Store Percentage Change
From 2010 to 2011 From 2011 to 2012
P +20 -20
Q -20 +9
R +5 +12
S -7 -15
T +17 -8
U +21 +9
In store T the sales for 2011 amounted to about what percentage of the sales for 2012?
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Answer: (B) 109
Explanation
The percentage change in sales for store T from 2011 to 2012 is -8%.
Sales in 2012 = Sales in 2011 × (1 - 0.08) = 0.92 × Sales in 2011
To find the sales for 2011 as a percentage of the sales for 2012:
Percentage = (Sales in 2011 / Sales in 2012) × 100
Percentage = (1 / 0.92) × 100 = 108.69% ≈ 109%
216Mathematics
Sunil and Gopal are partners in a business. Sunil invests Rs. 20,000 for 9 months and Gopal invests Rs. 30,000 for 12 months. Find the share of Sunil from the total profit of Rs. 60,000.
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Answer: (D) Rs. 20000
Explanation
The ratio of profit distribution is directly proportional to the product of investment amount and time duration.
Ratio of profit distribution (Sunil : Gopal) = 1,80,000 : 3,60,000 = 1 : 2
Sunil's share = (1 / 3) × 60,000 = Rs. 20,000
217Mathematics
The mean of a distribution is 11 and the standard deviation is 5. What is the value of the coefficient variation?
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Answer: (A) 45.45%
Explanation
The coefficient of variation (CV) measures the relative variability of a dataset and is calculated using the formula:
Coefficient of Variation = (Standard Deviation / Mean) × 100
Substituting the given values into the formula:
CV = (5 / 11) × 100 = 45.45%
218Mathematics
The mean of 14 observations is 11. One more observation is included and the new mean becomes 12. The 15th observation is
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Answer: (C) 26
Explanation
Sum of observations = Mean × Number of observations
Sum of initial 14 observations = 14 × 11 = 154
Sum of all 15 observations = 15 × 12 = 180
15th observation = Sum of 15 observations − Sum of 14 observations
15th observation = 180 − 154 = 26
219Mathematics
Five women can do a work in thirty six days. If the ratio between the capacity of a man and a woman is 3:1, then find how many days it will take 5 men to complete the same work?
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Answer: (A) 12 days
Explanation
Let the daily efficiency of a man and a woman be 3 units and 1 unit respectively.
Total Work = 5 women × 36 days = 5 × 1 × 36 = 180 units
Daily work done by 5 men = 5 × 3 = 15 units
Number of days required = Total Work / Daily work of 5 men = 180 / 15 = 12 days
220Mathematics
If (sin A + cos A) / (sin A - cos A) = 5 / 4 , the value of (tan 2A + 1) / (tan 2A - 1) = ?
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Answer: (A) 41/40
Explanation
By applying componendo and dividendo to the given equation:
(sin A + cos A + sin A - cos A) / (sin A + cos A - sin A + cos A) = (5 + 4) / (5 - 4)
2 sin A / 2 cos A = 9 / 1
tan A = 9
Squaring both sides:
tan² A = 9² = 81
Substituting tan² A = 81 into the required expression:
Two numbers are in ratio 4:9 and their HCF is 11. Their LCM is:
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Answer: (A) 396
Explanation
For two numbers in the co-prime ratio a : b, their LCM is given by the formula:
LCM = HCF × a × b
Here, the ratio terms a = 4 and b = 9 are co-prime, and the HCF is 11.
LCM = 11 × 4 × 9 = 396
226Mathematics
A jug has two holes. The 1ˢᵗ hole alone makes the jug empty in 15 minutes and 2ⁿᵈ hole alone makes the jug empty in 20 minutes. If water leaks out at a constant rate, how long in minutes does it take if both the holes together empty the jug?
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Answer: (D) 8⁴⁄₇
Explanation
Using the combined work formula, time taken together T = (t₁ × t₂) / (t₁ + t₂), where t₁ = 15 minutes and t₂ = 20 minutes:
Monica takes 9 hrs 15 minutes in walking a distance and riding back to same place where she started. She could walk both ways in 11 hrs 12 minutes. The time taken by her to ride back both ways is:
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Answer: (A) 7 hrs 18 min
Explanation
Let W be the time taken to walk one way and R be the time taken to ride one way.
Time for walking and riding (W + R) = 9 hrs 15 min
Time for walking both ways (2W) = 11 hrs 12 min
The time taken to ride both ways (2R) is given by:
2R = 2 × (W + R) − 2W
2R = 2 × (9 hrs 15 min) − (11 hrs 12 min)
2R = 18 hrs 30 min − 11 hrs 12 min = 7 hrs 18 min
231Mathematics
The table below represents the distance (in km) travelled by six trucks on six different days of the week. Read the table and answer the questions based on it.
Day Truck
P Q R S T U
Monday 240 250 320 325 330 300
Tuesday 320 264 308 314 318 314
Wednesday 324 294 330 312 310 325
Thursday 288 300 310 278 260 275
Friday 366 302 288 292 270 268
Saturday 292 284 260 274 280 242
If to travel the given distance, the time taken by Truck Q on Friday was 8 hours, then what was its average speed on that day?
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Answer: (A) 37.75km/hr
Explanation
Average Speed = Total Distance ÷ Total Time
From the table, the distance travelled by Truck Q on Friday is 302 km.
Given time taken = 8 hours.
Average speed = 302 ÷ 8 = 37.75 km/hr
232Mathematics
The table below represents the distance (in km) travelled by six trucks on six different days of the week. Read the table and answer the questions based on it.
Day Truck
P Q R S T U
Monday 240 250 320 325 330 300
Tuesday 320 264 308 314 318 314
Wednesday 324 294 330 312 310 325
Thursday 288 300 310 278 260 275
Friday 366 302 288 292 270 268
Saturday 292 284 260 274 280 242
What is the average distance travelled by Truck S on all the days together?
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Answer: (B) 1795/6 km
Explanation
Average distance = Total distance travelled / Total number of days
Total distance travelled by Truck S across the 6 days:
325 + 314 + 312 + 278 + 292 + 274 = 1795 km
Number of days = 6
Average distance = 1795/6 km
233Mathematics
The table below represents the distance (in km) travelled by six trucks on six different days of the week. Read the table and answer the questions based on it.
Day Truck
P Q R S T U
Monday 240 250 320 325 330 300
Tuesday 320 264 308 314 318 314
Wednesday 324 294 330 312 310 325
Thursday 288 300 310 278 260 275
Friday 366 302 288 292 270 268
Saturday 292 284 260 274 280 242
What is the total distance travelled by all the trucks together on Saturday?
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Answer: (D) 1632 km
Explanation
The total distance travelled by all six trucks on Saturday is calculated by summing the distances covered by trucks P, Q, R, S, T, and U on that day:
Total distance = 292 + 284 + 260 + 274 + 280 + 242 = 1632 km.
234Mathematics
Mr. Piyush sold a bus for Rs.3400 with a loss of 15% . At what price should the bus be sold to get a profit of 15% ?
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Answer: (D) 4600
Explanation
Target Selling Price = Given SP × (100 + Desired Profit %) ÷ (100 - Given Loss %)
Divide Rs.156 in the ratio 1:2:4:5. The rupees in the respective ratios are given by:
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Answer: (C) 13, 26, 52 | 65
Explanation
Sum of the ratio terms = 1 + 2 + 4 + 5 = 12 parts.
Value of each ratio part = 156 / 12 = 13.
Multiplying each term of the ratio by 13 gives the respective shares:
1 × 13 = 13
2 × 13 = 26
4 × 13 = 52
5 × 13 = 65
236Mathematics
Which is the correct ascending order of the given numbers?
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Answer: (C) ²⁄₇,0.3,³⁄₇
Explanation
Converting the fractions to decimal values:
2/7 ≈ 0.286
0.3 = 0.300
3/7 ≈ 0.429
Comparing the decimal values from smallest to largest gives 0.286 < 0.300 < 0.429, which corresponds to the ascending order 2/7, 0.3, 3/7.
237Mathematics
Mr. Yudish borrowed Rs.3500 at 4% per annum compound interest. The compound interest compounded annually for 2 years is:
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Answer: (A) 285.6
Explanation
Effective compound interest rate for 2 years at 4% per annum is calculated using the successive percentage change formula:
Effective Rate = R + R + (R × R)/100 = 4 + 4 + (4 × 4)/100 = 8.16%
Mr. Yashawanth invested money in FD. How much will he get on maturity, if Rs.10000 is invested at 20% per annum compound interest for 6 months, compounded quarterly?
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Answer: (B) 11025
Explanation
The formula for compound amount when interest is compounded quarterly is A = P(1 + r/100)ⁿ, where P is the principal, r is the quarterly rate of interest, and n is the number of quarters.
Given:
Principal (P) = ₹10,000
Quarterly rate (r) = 20% / 4 = 5%
Number of quarters (n) = 6 months / 3 months = 2
Substituting the values into the formula:
A = 10000 × (1 + 5/100)²
A = 10000 × (1.05)²
A = 10000 × 1.1025 = ₹11,025
239Mathematics
The variance of a set of data is 144. Then the standard deviation of the data is:
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Answer: (B) 12
Explanation
Standard deviation is defined as the positive square root of variance:
Standard Deviation = √(Variance)
Substituting the given variance:
Standard Deviation = √144 = 12
Because standard deviation is a measure of dispersion and distance from the mean, it is always a non-negative quantity.
240Mathematics
A shopkeeper cheats to the extent of 9% while buying and selling fruits, by using tampered weights. His total gain in percentage is:
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Answer: (B) 18.81
Explanation
When a trader cheats by x% while buying and x% while selling using tampered weights, the total percentage gain is given by the successive percentage change formula:
Net Gain % = x + x + (x × x)/100
Substituting x = 9:
Net Gain % = 9 + 9 + (9 × 9)/100 = 18 + 0.81 = 18.81%
241Mathematics
If sin x = ⅘ , then (tan x)/(cot x) = ?
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Answer: (D) ¹⁶⁄₉
Explanation
tan x / cot x = tan x / (1 / tan x) = tan² x
Given sin x = 4/5, the opposite side is 4 and the hypotenuse is 5. Using the Pythagorean theorem, the adjacent side is √(5² - 4²) = 3.
Therefore, tan x = 4/3.
Substituting tan x gives tan² x = (4/3)² = 16/9.
242Mathematics
The number of sides of a regular polygon whose exterior angles are each 45° is:
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Answer: (C) 8
Explanation
The sum of all exterior angles of any convex polygon is always 360°. For a regular polygon with n sides, all exterior angles are equal, so each exterior angle is given by the formula:
Exterior Angle = 360° / n
Substituting the given exterior angle of 45°:
45° = 360° / n
n = 360° / 45° = 8
243Mathematics
The cash difference between the selling price of an article at a profit of 2% and 14% is Rs.3. The ratio of two selling prices is:
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Answer: (A) 17:19
Explanation
Let the cost price of the article be C.
First selling price (SP₁) at 2% profit = 102% of C
Second selling price (SP₂) at 14% profit = 114% of C
Ratio of the two selling prices = SP₁ : SP₂ = 102 : 114
Dividing both terms by 6 gives 17 : 19. The given cash difference of Rs. 3 is extra information and is not required to calculate the ratio.
244Mathematics
Simplify: 2⁴ ÷ 2⁻¹
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Answer: (C) 32
Explanation
Using the quotient rule of exponents, aᵐ ÷ aⁿ = aᵐ⁻ⁿ:
2⁴ ÷ 2⁻¹ = 2⁴⁻⁽⁻¹⁾ = 2⁴⁺¹ = 2⁵ = 32
245Mathematics
Correct expression of 0.0236 = ?
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Answer: (A) ¹³⁄₅₅₀
Explanation
For a mixed recurring decimal where 36 repeats endlessly (0.023636...):
Numerator = (Entire number) - (Non-recurring part) = 236 - 2 = 234
Denominator = Number of 9s equal to recurring digits followed by 0s equal to non-recurring decimal digits = 9900
The mode of the data -3, 4, 0, 4, -2, -5, 1, 7, 10, 5 is:
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Answer: (B) 4
Explanation
The mode of a dataset is defined as the value that appears most frequently. In the given set of data (-5, -3, -2, 0, 1, 4, 4, 5, 7, 10), the number 4 appears twice, while all other numbers appear only once. Since 4 has the highest frequency of occurrence, it is the mode of the dataset.
247Mathematics
Compute of 54367× 9999 = ?
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Answer: (D) 543615633
Explanation
To multiply a number by 9999, use the identity 9999 = (10000 - 1):
Expand the given expression using the distributive property:
7x + 3x(x - 4) = 7x + 3x² - 12x
Group and combine the like terms (7x and -12x):
3x² + (7x - 12x) = 3x² - 5x
249Mathematics
If the product of two numbers is 3192 and their LCM is 56 then their HCF is:
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Answer: (D) 57
Explanation
For any two numbers, the relation between their product, HCF, and LCM is:
Product of two numbers = HCF × LCM
Substituting the given values into the formula:
3192 = HCF × 56
HCF = 3192 ÷ 56 = 57
250Mathematics
Prashanth is twice as good a sportsman as Tarun and together they finish a piece of work in 21 days. In how many days will Tarun alone finish the work?
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Answer: (B) 63
Explanation
Ratio of efficiency of Prashanth to Tarun = 2 : 1.
Combined efficiency = 2 + 1 = 3 units per day.
Total work = Combined efficiency × Days taken together = 3 × 21 = 63 units.
Time taken by Tarun alone = Total work / Efficiency of Tarun = 63 / 1 = 63 days.