RRB NTPC2016MathematicsPage 4 of 6

RRB NTPC CBT 1 2016 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 151–200 of 252, each with the correct answer and a step-by-step explanation.

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151Mathematics
Rs. 10,000 is being compounded at 20% per annum. Calculate the amount after 2 years if the rate of interest is charged half yearly.
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Answer: (D) 14641

Explanation

When interest is compounded half-yearly, the rate of interest per compounding period is halved, and the time period is doubled.

Principal (P) = Rs. 10,000 Rate per half-year (r) = 20% ÷ 2 = 10% Number of periods (n) = 2 × 2 = 4

Amount (A) = P × (1 + r/100)ⁿ A = 10000 × (1 + 10/100)⁴ A = 10000 × (1.1)⁴ A = 10000 × 1.4641 A = 14,641

152Mathematics
If the standard deviation of a population is 4.5, what would be the population variance?
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Answer: (A) 20.25

Explanation

Population variance is defined as the square of the population standard deviation (σ²). Given the standard deviation σ = 4.5:

Variance = σ² = (4.5)² = 20.25

153Mathematics
Find the value of x if 0.08x + 0.04y = 10 and 0.2(x - 1) + 0.4y = 24.8
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Answer: (A) 125

Explanation

Multiply the first equation 0.08x + 0.04y = 10 by 100 to clear the decimals: 8x + 4y = 1000

Expand and simplify the second equation 0.2(x - 1) + 0.4y = 24.8: 0.2x - 0.2 + 0.4y = 24.8 0.2x + 0.4y = 25

Multiply this equation by 10 to clear the decimals: 2x + 4y = 250

Subtract the second cleared equation from the first: (8x + 4y) - (2x + 4y) = 1000 - 250 6x = 750 x = 125

154Mathematics
Find the LCM of 0.63, 10.5, 2.1, 4.20
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Answer: (A) 63

Explanation

To find the LCM of decimals, convert each decimal into a fraction in its simplest form: 0.63 = 63/100 10.5 = 21/2 2.1 = 21/10 4.20 = 21/5

The formula for the LCM of fractions is LCM of numerators divided by HCF of denominators.

LCM(63, 21, 21, 21) = 63 HCF(100, 2, 10, 5) = 1

LCM = 63 / 1 = 63

155Mathematics
Find the remainder when 4¹³ divided by 3?
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Answer: (A) 1

Explanation

Using modular arithmetic, 4 = 3 × 1 + 1, which means 4 ≡ 1 (mod 3).

Raising both sides to the power of 13 gives: 4¹³ ≡ 1¹³ (mod 3) = 1.

156Mathematics
Ramu can row 9 km/hr in still water. It takes him twice as long to row up as to row down. Find the rate of stream.
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Answer: (C) 3 km/hr

Explanation

When speed in still water is u and rate of stream is v, if the time taken to row upstream is n times the time taken to row downstream for the same distance, the relationship is:

u / v = (n + 1) / (n - 1)

Given u = 9 km/hr and n = 2:

9 / v = (2 + 1) / (2 - 1) 9 / v = 3 / 1 v = 9 / 3 = 3 km/hr

157Mathematics
Nenny's earning was decreased by 60% and after that subsequently increased by 60% . Find the final loss % on his earnings?
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Answer: (B) 36%

Explanation

When a value is sequentially changed by percentage amounts a and b, the net percentage change is given by the formula: Net Percentage Change = a + b + (a × b)/100

For a 60% decrease followed by a 60% increase, a = -60 and b = +60:

Net Change = -60 + 60 + (-60 × 60)/100 Net Change = 0 - 3600/100 = -36%

The negative sign indicates a net loss of 36%.

Alternatively, assuming initial earnings equal 100: Earnings after 60% decrease = 100 × 0.40 = 40 Earnings after subsequent 60% increase = 40 × 1.60 = 64 Final loss = 100 - 64 = 36%

158Mathematics
A bus is running at a speed of 90 kmph. What distance will it cover in 20 seconds?
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Answer: (A) 500 m

Explanation

Distance = Speed × Time.

First, convert speed from km/h to m/s: Speed = 90 × (5/18) = 25 m/s

Now, calculate distance covered in 20 seconds: Distance = 25 × 20 = 500 m

159Mathematics
In what ratio should Darjeeling Tea costing Rs. 400 per kg be mixed with Assam Tea costing Rs. 300 per kg, so that by selling the mixture at Rs. 408 per kg, there is a gain of 20%?
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Answer: (B) 2:3

Explanation

The cost price of the mixture is calculated using the selling price and profit percentage: Cost Price = Selling Price × 100 / (100 + Gain %) Cost Price = 408 × 100 / 120 = Rs. 340 per kg

By applying the rule of alligation: (Quantity of Darjeeling Tea) / (Quantity of Assam Tea) = (340 - 300) / (400 - 340) = 40 / 60 = 2 : 3

160Mathematics
Consider the following statements | choose the correct options: When two straight lines intersect then, 1. Adjacent angles are supplementary 2. Opposite angles are supplementary
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Answer: (D) 1 is correct and 2 is incorrect

Explanation

When two straight lines intersect, any pair of adjacent angles forms a linear pair on a straight line, summing to 180°, which makes them supplementary. In contrast, opposite (vertically opposite) angles formed by two intersecting straight lines are equal to each other, rather than supplementary in general.

161Mathematics
Atul can do a piece of work in 18 days, Aaravya is 50% more efficient than Atul. How much more time does Atul take than Aaravya to do the same piece of work?
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Answer: (B) 6

Explanation

Efficiency and time taken are inversely proportional.

Ratio of efficiency (Aaravya : Atul) = 150 : 100 = 3 : 2 Ratio of time taken (Aaravya : Atul) = 2 : 3

Given Atul's time = 3 units = 18 days 1 unit = 6 days

Aaravya's time = 2 units = 12 days

Extra time taken by Atul = 18 - 12 = 6 days.

162Mathematics
If (x+a) is the H.C.F of 2x²+5x-12 and x²+x-12 then find the value of a.
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Answer: (C) 4

Explanation

Factoring both quadratic expressions:

2x² + 5x - 12 = 2x² + 8x - 3x - 12 = 2x(x + 4) - 3(x + 4) = (2x - 3)(x + 4)

x² + x - 12 = x² + 4x - 3x - 12 = x(x + 4) - 3(x + 4) = (x - 3)(x + 4)

The highest common factor (H.C.F) of both expressions is (x + 4). Comparing (x + a) with (x + 4) yields a = 4.

163Mathematics
The shadow of a tower on ground level is increased by 30 m, when the angle of depression by the sun changes from 60° to 30°. The height of the tower is?
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Answer: (D) 15√3 m

Explanation

For a tower of height h, the relation between the change in shadow length d and the angles of elevation θ₁ and θ₂ is given by the formula d = h(cot θ₁ - cot θ₂).

Here, d = 30 m, θ₁ = 30°, and θ₂ = 60°.

Substituting the values: 30 = h(cot 30° - cot 60°) 30 = h(√3 - 1/√3) 30 = h(2/√3) h = (30 × √3) / 2 = 15√3 m

164Mathematics
Deepak sells all his goods available in his shop at the cost price, but he cheats his customer and gives 20% less goods as he should give. Find his % profit.
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Answer: (C) 25%

Explanation

Profit percentage when cheating in weight/quantity is given by the formula:

Profit % = (Weight Saved / Actual Weight Given) × 100

For a standard order of 100 units, Deepak gives 20% less, which is 80 units.

Profit % = (20 / 80) × 100 = 25%

165Mathematics
What is the minimum value of "Y" for which 267Y2 is divisible by 3?
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Answer: (B) 1

Explanation

A number is divisible by 3 if the sum of its digits is divisible by 3. Summing the digits of 267Y2 gives 2 + 6 + 7 + Y + 2 = 17 + Y. For this sum to be a multiple of 3, the smallest non-negative integer value for Y is 1, as 17 + 1 = 18, which is divisible by 3.

166Mathematics
Ram Naresh got two successive discounts, a bag with a list price of Rs. 400 is available at Rs. 160. If the second discount is 20%, find the first discount.
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Answer: (C) 50%

Explanation

Let the first discount percentage be d%.

The relationship between marked price, selling price, and successive discounts is given by the formula: Selling Price = Marked Price × (1 - d/100) × (1 - Second Discount/100)

Substituting the given values: 160 = 400 × (1 - d/100) × (1 - 20/100) 160 = 400 × (1 - d/100) × 0.8 160 = 320 × (1 - d/100) 1 - d/100 = 160 ÷ 320 1 - d/100 = 0.5 d/100 = 0.5 d = 50%

Alternatively, working backward from the selling price of Rs. 160 after the 20% second discount gives the intermediate price as 160 ÷ 0.8 = Rs. 200. The discount from the initial Rs. 400 list price to Rs. 200 is 200 ÷ 400 × 100 = 50%.

167Mathematics
Vikash purchased 5 bananas for Rs. 4 and sold 4 bananas for Rs. 5. Calculate his % profit?
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Answer: (D) 56.25%

Explanation

To calculate the profit percentage, equalize the number of bananas by taking the LCM of 5 and 4, which is 20.

Cost Price (CP) of 20 bananas = 4 × 4 = Rs. 16 Selling Price (SP) of 20 bananas = 5 × 5 = Rs. 25

Profit = SP - CP = 25 - 16 = Rs. 9

Profit % = (Profit / CP) × 100 = (9 / 16) × 100 = 56.25%

168Mathematics
Anil can do a piece of work in 14 days which Rohit can do in 21 days. They worked together for few days after which Anil left. If Rohit worked alone for 3 days, find the total number of days it took to complete the whole work.
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Answer: (B) 51/5

Explanation

Let total work = LCM(14, 21) = 42 units.

Anil's efficiency = 42 ÷ 14 = 3 units/day Rohit's efficiency = 42 ÷ 21 = 2 units/day

Work done by Rohit alone in the last 3 days = 3 × 2 = 6 units Remaining work done together = 42 - 6 = 36 units Time taken working together = 36 ÷ (3 + 2) = 36/5 days

Total number of days = 36/5 + 3 = 51/5 days.

169Mathematics
If A:B = 3:4 and B:C = 6:5 then A:(A+C) is:
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Answer: (C) 9:19

Explanation

To find the combined ratio A : B : C, equalize the term for B in both ratios by taking the LCM of 4 and 6, which is 12.

A : B = (3 × 3) : (4 × 3) = 9 : 12 B : C = (6 × 2) : (5 × 2) = 12 : 10

Thus, A : B : C = 9 : 12 : 10.

Taking A = 9 and C = 10: A + C = 9 + 10 = 19

A : (A + C) = 9 : 19

170Mathematics
If two complimentary angles are in the ratio of 11:7, find the smaller angle.
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Answer: (A) 35°

Explanation

Complementary angles sum to 90°.

Sum of the ratio terms = 11 + 7 = 18 parts. 18 parts = 90° 1 part = 90° / 18 = 5°

The smaller angle corresponds to 7 parts in the ratio: 7 × 5° = 35°

171Mathematics
If the length of the shadow of a vertical pole on the horizontal ground is √3 times its height, then the angle of elevation
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Answer: (C) 30°

Explanation

Let h be the height of the vertical pole and θ be the angle of elevation of the sun.

The length of the shadow on the ground is √3 h.

Using the right-triangle trigonometric relation: tan θ = height of pole / length of shadow tan θ = h / (√3 h) = 1 / √3

Since tan 30° = 1 / √3, the angle of elevation θ = 30°.

172Mathematics
If the angles of a triangle are in the ratio of 2:5:8, then find the value of the largest angle.
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Answer: (B) 96°

Explanation

The sum of all interior angles in a triangle is 180°.

Given ratio of angles = 2:5:8 Total ratio parts = 2 + 5 + 8 = 15

Largest angle = (8 / 15) × 180° = 8 × 12° = 96°

173Mathematics
Find the unit digit in the given product (4211)¹⁰² x (361)⁵²
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Answer: (B) 1

Explanation

The unit digit of any base ending in 1 raised to any positive integer power is always 1.

Unit digit of (4211)¹⁰² = 1 Unit digit of (361)⁵² = 1

Unit digit of product = 1 × 1 = 1

174Mathematics
The traffic lights at four different road crossings change after every 15sec, 18sec, 27sec and 30 sec respectively. If they all change simultaneously at 6:10:00 hours, then at what time will they again change simultaneously?
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Answer: (A) 6:14:30 hours

Explanation

The traffic lights will change simultaneously at intervals equal to the Least Common Multiple (LCM) of 15, 18, 27, and 30 seconds.

Prime factorization of each number: 15 = 3 × 5 18 = 2 × 3² 27 = 3³ 30 = 2 × 3 × 5

LCM(15, 18, 27, 30) = 2¹ × 3³ × 5¹ = 270 seconds

Converting 270 seconds into minutes: 270 seconds = 4 minutes and 30 seconds

Adding this duration to the initial time of 6:10:00 hours: 6:10:00 hours + 0:04:30 hours = 6:14:30 hours

175Mathematics
The mean of a distribution is 21 and the standard deviation is 7. What is the value of the coefficient variation?
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Answer: (C) 33.33%

Explanation

The Coefficient of Variation (CV) measures relative variability and is calculated using the formula:

Coefficient of Variation = (Standard Deviation / Mean) × 100%

Substituting the given values: CV = (7 / 21) × 100% = (1 / 3) × 100% = 33.33%

176Mathematics
A boy running at 10 / 9ᵗʰ of his actual speed covers 39km in 2 hours 20 minutes and 24 seconds. Find the actual speed of the boy (approx.).
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Answer: (A) 15km / hr

Explanation

Time taken = 2 hours + 20/60 hours + 24/3600 hours = 2 + 1/3 + 1/150 = 117/50 hours.

New speed = Distance / Time = 39 / (117/50) = (39 × 50) / 117 = 50/3 km/hr.

Since the running speed is 10/9 of the actual speed: Actual speed = (9/10) × (50/3) = 15 km/hr.

177Mathematics
Sonam's age after eight years will be half of her father's age. Eight years ago the ratio of their ages was 1: 3. Find the present age of Sonam's father.
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Answer: (B) 56

Explanation

Let Sonam's present age be S and her father's present age be F.

8 years ago, the ratio of their ages was 1:3: (S - 8) / (F - 8) = 1/3 3S - 24 = F - 8 F = 3S - 16

8 years from now, Sonam's age will be half of her father's age: S + 8 = ½(F + 8) 2S + 16 = F + 8 F = 2S + 8

Equating the two expressions for F: 3S - 16 = 2S + 8 S = 24

Substituting S = 24 into F = 2S + 8: F = 2(24) + 8 = 56 years.

178Mathematics
Mohan earns a profit of 20% on selling a jean at 15% discount on printed price. The ratio of the cost price to printed price of the jean is
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Answer: (A) 17:24

Explanation

Using the standard relationship between Cost Price (CP) and Marked/Printed Price (MP):

CP / MP = (100 - Discount%) / (100 + Profit%)

Substituting Discount = 15% and Profit = 20%:

CP / MP = (100 - 15) / (100 + 20) = 85 / 120

Simplifying by dividing both numerator and denominator by 5:

CP / MP = 17 / 24

179Mathematics
The average of five consecutive even numbers is 40. What is the value of smallest of these numbers?
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Answer: (B) 36

Explanation

For any odd number of terms in an arithmetic progression, the average is equal to the middle term.

Here, the average of 5 consecutive even numbers is given as 40, which means the middle (3rd) number is 40.

The smallest (1st) number = 40 - 2 × 2 = 36.

180Mathematics
A sum of money (P) doubles in 10 years. How much would it be in 20 years at the same rate of simple interest?
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Answer: (C) 3P

Explanation

Under simple interest, the interest earned per unit time remains constant.

When a principal P doubles in 10 years, the simple interest earned in 10 years is 2P - P = P.

In 20 years, the total simple interest earned is 2 × P = 2P.

The total amount after 20 years is Principal + Interest = P + 2P = 3P.

181Mathematics
If (a + c + 1) = 0 , then find the value of (a³ + c³ + 1 - 3ac)
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Answer: (D) 0

Explanation

Using the algebraic identity x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx):

Let x = a, y = c, and z = 1.

The expression becomes: a³ + c³ + 1³ - 3(a)(c)(1) = (a + c + 1)(a² + c² + 1 - ac - c - a)

Since (a + c + 1) = 0, substituting this value gives: a³ + c³ + 1 - 3ac = 0 × (a² + c² + 1 - ac - c - a) = 0

182Mathematics
If (x+y)²-xy=0, then find the value of (x³-y³)/(x-y).
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Answer: (C) 0

Explanation

Using the algebraic identity for difference of cubes: x³ - y³ = (x - y)(x² + xy + y²)

Dividing both sides by (x - y): (x³ - y³)/(x - y) = x² + xy + y²

Expanding the given condition: (x + y)² - xy = 0 x² + 2xy + y² - xy = 0 x² + xy + y² = 0

Substituting x² + xy + y² = 0 yields (x³ - y³)/(x - y) = 0.

183Mathematics
A ladder is resting against a vertical wall. The top of the ladder is at a height of 9 m from the floor. When the bottom of the ladder is pulled 3 m further away, the top of the ladder touches the bottom of the wall. What is the length of the ladder?
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Answer: (B) 15 m

Explanation

Let L be the length of the ladder and x be the initial distance of the base of the ladder from the wall.

By Pythagoras' theorem for the initial right-angled triangle formed by the wall, floor, and ladder: L² = x² + 9² L² = x² + 81

When the base of the ladder is pulled 3 m further away, the top of the ladder reaches the bottom of the wall (height = 0), meaning the ladder lies flat on the ground: L = x + 3, which gives x = L - 3

Substituting x = L - 3 into the Pythagorean equation: L² = (L - 3)² + 81 L² = L² - 6L + 9 + 81 6L = 90 L = 15 m

184Mathematics
Study the following table carefully and answer the questions based on it. The following table shows the domestic sales of cars of five manufacturers from 2005 to 2010. (All the figures are in thousands) Manufacturer 2005 2006 2007 2008 2009 2010 L 440 480 470 500 520 510 M 400 410 415 415 420 430 N 380 390 390 400 420 495 O 360 380 400 415 440 500 P 480 440 440 420 425 435 During 2006, what is the approximate share domestic sales of cars of the manufacturer M?
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Answer: (A) 19.5%

Explanation

Total domestic sales of cars of all five manufacturers in 2006 = 480 + 410 + 390 + 380 + 440 = 2100 thousand.

Domestic sales of car manufacturer M in 2006 = 410 thousand.

Percentage share of manufacturer M = (410 / 2100) × 100 ≈ 19.52% ≈ 19.5%.

185Mathematics
Study the following table carefully and answer the questions based on it. The following table shows the domestic sales of cars of five manufacturers from 2005 to 2010. (All the figures are in thousands) Manufacturer 2005 2006 2007 2008 2009 2010 L 440 480 470 500 520 510 M 400 410 415 415 420 430 N 380 390 390 400 420 495 O 360 380 400 415 440 500 P 480 440 440 420 425 435 During 2010, the sales of which manufacturer has shown the maximum percentage increase over the previous year?
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Answer: (C) N

Explanation

Percentage increase = [(Sales in 2010 - Sales in 2009) / Sales in 2009] × 100

For manufacturer N, sales increased from 420 thousand in 2009 to 495 thousand in 2010. Percentage increase for N = [(495 - 420) / 420] × 100 = (75 / 420) × 100 ≈ 17.86%.

This growth rate of 17.86% is the highest percentage increase recorded in 2010 over the previous year.

186Mathematics
Study the following table carefully and answer the questions based on it. The following table shows the domestic sales of cars of five manufacturers from 2005 to 2010. (All the figures are in thousands) Manufacturer 2005 2006 2007 2008 2009 2010 L 440 480 470 500 520 510 M 400 410 415 415 420 430 N 380 390 390 400 420 495 O 360 380 400 415 440 500 P 480 440 440 420 425 435 With respect to which of the following combinations, is the sales of cars the highest over the given period?
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Answer: (A) L,2009

Explanation

From the given table, manufacturer L recorded domestic car sales of 520 thousand units in the year 2009. Comparing the sales values for the given combinations, 520 thousand is the highest sales figure recorded across the entire dataset.

187Mathematics
Atul and Binay together complete a piece of work in 5 days. If Binay alone can complete the same work in 8 days, how many days can Atul take to complete the same work alone?
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Answer: (A) 40/3 days

Explanation

Using the standard work-time formula, if two people together take T days to complete a task and one person alone takes B days, the time taken by the other person A working alone is given by:

A = (T × B) / (B - T)

Given: Together time (T) = 5 days Binay's time (B) = 8 days

Substituting the values: A = (5 × 8) / (8 - 5) = 40/3 days

Alternatively, calculating 1 day's work: Combined 1 day work = 1/5 Binay's 1 day work = 1/8 Atul's 1 day work = 1/5 - 1/8 = (8 - 5) / 40 = 3/40

Taking the reciprocal, Atul alone takes 40/3 days to complete the work.

188Mathematics
Find the dividend if the divisor is (x+2), quotient is (4x-5) and the remainder is 12.
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Answer: (B) 4x²+3x+2

Explanation

Dividend = (Divisor × Quotient) + Remainder

Substituting the given polynomial values into the formula: Dividend = (x + 2)(4x - 5) + 12 = 4x² - 5x + 8x - 10 + 12 = 4x² + 3x + 2

189Mathematics
What sum will produce the same interest in 9 years at the rate 8% simple interest as Rs. 800 produce in 3 years at 9 / 2% per annum?
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Answer: (C) Rs. 150

Explanation

Simple Interest SI = (P × R × T) / 100.

First, calculate the interest produced by Rs. 800 in 3 years at (9/2)% per annum: SI = (800 × 9 × 3) / (2 × 100) = Rs. 108

Equating this to the simple interest produced by the required principal sum P in 9 years at 8% per annum: (P × 8 × 9) / 100 = 108 72P / 100 = 108 P = (108 × 100) / 72 = Rs. 150

190Mathematics
Naveen purchased a gas cylinder and a stove for Rs.4500. He sold the gas cylinder at a gain of 25% and the stove at a loss of 20%, still gaining 4% on the whole. Find the cost of the gas cylinder.
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Answer: (B) Rs.2400

Explanation

Using the rule of alligation for the gain/loss percentages:

Ratio of Cost Price of Cylinder to Stove = (4 - (-20)) : (25 - 4) = 24 : 21 = 8 : 7

Sum of ratio terms = 8 + 7 = 15

Cost price of the gas cylinder = (8 / 15) × 4500 = Rs. 2400

191Mathematics
In new government policy, the price of onion is raised by 35%. By what % should a person reduce onion consumption so that the expenditure on it does not increase?
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Answer: (C) 26%

Explanation

Percentage reduction in consumption = [r / (100 + r)] × 100

Substituting r = 35%: Percentage reduction = [35 / (100 + 35)] × 100 = (35 / 135) × 100 = 700 / 27 = 25.92% ≈ 26%

192Mathematics
The mean of 10 observations is 13. Two more observations are included and the new mean becomes 14. The mean of two new observations is
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Answer: (A) 19

Explanation

Sum of initial 10 observations = 10 × 13 = 130

With 2 additional observations, total observations become 12. Sum of total 12 observations = 12 × 14 = 168

Sum of the 2 new observations = 168 - 130 = 38 Mean of the 2 new observations = 38 / 2 = 19

193Mathematics
If the standard deviation of a population is 6.5, what would be the population variance?
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Answer: (B) 42.25

Explanation

Population variance (σ²) is equal to the square of the population standard deviation (σ).

Variance = (Standard Deviation)² = 6.5² = 42.25

194Mathematics
How many natural numbers between 15 and 85 are divisible by 7?
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Answer: (B) 10

Explanation

The smallest natural number greater than 15 divisible by 7 is 21 (7 × 3), and the largest natural number less than 85 divisible by 7 is 84 (7 × 12).

The total number of multiples is given by: Count = 12 - 3 + 1 = 10

195Mathematics
Which value is closest to [5.168 x 4453 x 3.194 / 67.999 x 4224.017]
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Answer: (A) 0.2

Explanation

Approximating the given expression by rounding off the terms: 5.168 ≈ 5.2 3.194 ≈ 3.2 67.999 ≈ 68 4453 / 4224.017 ≈ 1.054

Evaluating the simplified expression: (5.2 × 3.2 × 1.054) / 68 ≈ 17.54 / 68 ≈ 0.258

Evaluating the difference between 0.258 and the options shows that 0.2 has the smallest absolute difference.

196Mathematics
Which of the following ratio is greatest?
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Answer: (D) 21:29

Explanation

When the difference between the denominator and the numerator is constant for a set of proper fractions, the fraction with the largest numerator and denominator has the greatest value.

For each ratio, the difference between the denominator and the numerator is 8: 15 - 7 = 8 23 - 15 = 8 25 - 17 = 8 29 - 21 = 8

A proper fraction with numerator n and denominator d can be written as n/d = 1 - (8/d). As the denominator d increases, the term 8/d decreases, making 1 - (8/d) larger. Since 21:29 has the largest denominator (29), its value 21/29 ≈ 0.724 is the greatest.

197Mathematics
If 3.5x = 0.07y ,then find the result of [y-x]/y+x]
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Answer: (C) 49/51

Explanation

From the given equation 3.5x = 0.07y, the ratio of x to y is: x / y = 0.07 / 3.5 = 7 / 350 = 1 / 50

This gives y = 50x. Substituting y = 50x into the expression (y - x) / (y + x): (50x - x) / (50x + x) = 49x / 51x = 49 / 51

198Mathematics
Find 150% of X, if X is the least number which when divided by 6, 7, 8, 9 and 12 leaves remainders 2, 3, 4, 5 and 8 respectively.
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Answer: (A) 750

Explanation

The difference between each divisor and its corresponding remainder is constant: 6 - 2 = 7 - 3 = 8 - 4 = 9 - 5 = 12 - 8 = 4.

The least number X is given by: X = LCM(6, 7, 8, 9, 12) - 4

Calculating the LCM of 6, 7, 8, 9, and 12: LCM = 2³ × 3² × 7 = 8 × 9 × 7 = 504

Thus, X = 504 - 4 = 500.

Now, calculating 150% of X: 150% of 500 = (150 / 100) × 500 = 750

199Mathematics
For real a, b and c if a² + b² + c² = ab + bc + ca , then find the value of (a + b + c)²
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Answer: (A) 9a²

Explanation

Multiplying both sides of the equation a² + b² + c² = ab + bc + ca by 2 and rearranging gives:

(a - b)² + (b - c)² + (c - a)² = 0

Since a, b, and c are real numbers, the sum of squares equals zero if and only if each term is zero, which implies a = b = c.

Substituting b = a and c = a into the expression:

(a + b + c)² = (a + a + a)² = (3a)² = 9a²

200Mathematics
If Sunita earns 75/4% more than her boyfriend, find the approximate % her boyfriend earns less than Sunita.
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Answer: (A) 16%

Explanation

Percentage less = [r / (100 + r)] × 100%

Here, r = 75/4%.

Percentage boyfriend earns less = [(75/4) / (100 + 75/4)] × 100 = [(75/4) / (475/4)] × 100 = (75 / 475) × 100 = (3 / 19) × 100 = 300 / 19 = 15.79% ≈ 16%

Answer key

Tap a number to jump to that question.

  1. 151D
  2. 152A
  3. 153A
  4. 154A
  5. 155A
  6. 156C
  7. 157B
  8. 158A
  9. 159B
  10. 160D
  11. 161B
  12. 162C
  13. 163D
  14. 164C
  15. 165B
  16. 166C
  17. 167D
  18. 168B
  19. 169C
  20. 170A
  21. 171C
  22. 172B
  23. 173B
  24. 174A
  25. 175C
  26. 176A
  27. 177B
  28. 178A
  29. 179B
  30. 180C
  31. 181D
  32. 182C
  33. 183B
  34. 184A
  35. 185C
  36. 186A
  37. 187A
  38. 188B
  39. 189C
  40. 190B
  41. 191C
  42. 192A
  43. 193B
  44. 194B
  45. 195A
  46. 196D
  47. 197C
  48. 198A
  49. 199A
  50. 200A

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