RRB NTPC2016MathematicsPage 3 of 6

RRB NTPC CBT 1 2016 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 101–150 of 252, each with the correct answer and a step-by-step explanation.

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101Mathematics
If sin x = ⅘ , then sec² x - 1 = ?
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Answer: (C) ¹⁶⁄₉

Explanation

Using the trigonometric identity, sec² x - 1 = tan² x.

Given sin x = 4/5, the value of cos x is: cos x = √(1 - sin² x) = √(1 - 16/25) = √(9/25) = 3/5

Now, tan x = sin x / cos x = (4/5) / (3/5) = 4/3.

Substituting this into the identity: sec² x - 1 = tan² x = (4/3)² = 16/9

102Mathematics
Find the HCF of 1757, 2259.
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Answer: (C) 251

Explanation

Using Euclid's division algorithm to find the Highest Common Factor (HCF):

2259 = 1757 × 1 + 502 1757 = 502 × 3 + 251 502 = 251 × 2 + 0

Since the remainder becomes zero when divided by 251, the HCF of 1757 and 2259 is 251.

103Mathematics
Given w = - 2 , x = 3 , y = 0 | z = -½ , find the value of w² √((z² + y²)) .
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Answer: (C) 2

Explanation

Substituting the given values into the expression w² √(z² + y²):

w² = (-2)² = 4 z² = (-½)² = ¼ y² = 0² = 0

Calculating the square root term: √(z² + y²) = √(¼ + 0) = √(¼) = ½

Multiplying the results: w² √(z² + y²) = 4 × ½ = 2

104Mathematics
Solve: x - 3 = 3x + 7.
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Answer: (B) -5

Explanation

Rearranging the linear equation x - 3 = 3x + 7 to group variable terms on one side and constant terms on the other:

3x - x = -3 - 7 2x = -10 x = -10 / 2 x = -5

Substituting x = -5 back into the original equation yields -5 - 3 = -8 on the left-hand side and 3(-5) + 7 = -8 on the right-hand side, confirming the solution.

105Mathematics
Compute 33800/520/5.
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Answer: (C) 13

Explanation

Following the standard left-to-right order of operations for sequential division:

33800 / 520 / 5 = (33800 / 520) / 5

First, divide 33800 by 520: 33800 / 520 = 65

Next, divide 65 by 5: 65 / 5 = 13

106Mathematics
The length of a diagonal in cms of a rectangle of length 5 cm and width 3 cm is:
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Answer: (A) √(34)

Explanation

By the Pythagorean theorem, the length of the diagonal d of a rectangle with length l and width w is given by d = √(l² + w²).

Substituting l = 5 cm and w = 3 cm:

d = √(5² + 3²) = √(25 + 9) = √34 cm

As distance is always a non-negative geometric quantity, the diagonal length is strictly positive.

107Mathematics
The number of sides of a regular polygon whose exterior angles are each 72° is?
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Answer: (C) 5

Explanation

The sum of all exterior angles of a regular polygon is always 360°. The number of sides n is given by:

n = 360° / Exterior Angle

Substituting the given exterior angle of 72°:

n = 360° / 72° = 5

108Mathematics
Mr. Ibrahim borrowed Rs.7500 at 5% per annum compound interest. The compound interest compounded annually for 2 years is.
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Answer: (A) 768.75

Explanation

For a principal P at rate r% compounded annually for 2 years, the effective interest rate is 2r + r²/100 %.

Here, r = 5%, so the effective interest rate = 2(5) + 5²/100 = 10.25%.

Compound Interest = 7500 × 10.25% = 7500 × (10.25 / 100) = 75 × 10.25 = 768.75.

109Mathematics
Rakshanth is twice as good a tradesman as Verma and together they finish a piece of work in 19 days. In how many days will Verma alone finish the work?
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Answer: (B) 57

Explanation

Ratio of efficiency of Rakshanth and Verma = 2 : 1. Combined efficiency = 2 + 1 = 3 units/day.

Total work = Combined efficiency × Days taken together = 3 × 19 = 57 units.

Days taken by Verma alone = Total work / Verma's efficiency = 57 / 1 = 57 days.

110Mathematics
Two numbers are in ratio 2:5 and their HCF is 18. Their LCM is.
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Answer: (A) 180

Explanation

For two numbers in the ratio a:b (where a and b are co-prime) with an HCF of H, their LCM is given by:

LCM = a × b × H

Substituting the given values (a = 2, b = 5, and H = 18):

LCM = 2 × 5 × 18 = 180

111Mathematics
The number of sides of a regular polygon whose exterior angles are each 40° is:
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Answer: (C) 9

Explanation

The sum of all exterior angles of any regular polygon is always 360°. The number of sides n is given by the formula n = 360° / exterior angle.

Substituting the given exterior angle of 40°:

n = 360° / 40° = 9

112Mathematics
Simplify: (25)³^/²
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Answer: (C) 125

Explanation

Using the exponent rule (aᵐ)ⁿ = aᵐⁿ:

(25)⁽3/2) = (5²)⁽3/2) = 5⁽2 × 3/2) = 5³ = 125.

113Mathematics
The length of a diagonal in cm of a rectangle of length 9 cm and width 5 cm is
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Answer: (A) √106

Explanation

By the Pythagorean theorem, the length of the diagonal d of a rectangle with length l and width w is given by the formula d = √(l² + w²). Substituting the given values l = 9 cm and w = 5 cm gives d = √(9² + 5²) = √(81 + 25) = √106 cm. Since geometric length is always a positive quantity, the length of the diagonal is √106 cm.

114Mathematics
Manoj is twice as efficient a fisherman as Anuraj and together they finish a piece of work in 22 days. In how many days will Anuraj alone complete the work?
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Answer: (B) 66

Explanation

Efficiency ratio of Manoj to Anuraj = 2 : 1.

Combined efficiency per day = 2 + 1 = 3 units.

Total work = Combined efficiency × Time taken together = 3 × 22 = 66 units.

Time taken by Anuraj alone = Total work ÷ Anuraj's efficiency = 66 ÷ 1 = 66 days.

115Mathematics
Two numbers are in ratio 4:5 and their HCF is 13. Their LCM is:
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Answer: (A) 260

Explanation

For two numbers in the ratio a:b (where a and b are co-prime) and having HCF h, their LCM is given by the formula:

LCM = h × a × b

Substituting h = 13, a = 4, and b = 5:

LCM = 13 × 4 × 5 = 260

116Mathematics
Simplify: ⁵⁄₂₈ ÷ ²⁸⁄₃₅ ÷ ²⁰⁄₁₁₂
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Answer: (B) 5/4

Explanation

To simplify the given expression, convert each division operation into multiplication by taking the reciprocal of the dividing fraction:

5/28 ÷ 28/35 ÷ 20/112 = (5/28) × (35/28) × (112/20)

Simplifying the fractions where possible: 35/28 reduces to 5/4 by dividing numerator and denominator by 7. 112/20 reduces to 28/5 by dividing numerator and denominator by 4.

Substituting these back into the expression: (5/28) × (5/4) × (28/5)

Canceling the common terms 28 and 5 from the numerator and denominator: = 5/4

117Mathematics
A telephone bill costs Rs.13 for 19 minutes. What is the cost in rupees for 15 minutes 50 seconds? (Rounded to one decimal).
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Answer: (A) 10.8

Explanation

Using unitary method, convert time into seconds: Total time = 19 minutes = 19 × 60 = 1140 seconds Given time = 15 minutes 50 seconds = (15 × 60) + 50 = 950 seconds

Cost for 950 seconds = 13 × (950 / 1140) = 13 × (5 / 6) = 65 / 6 = 10.833... ≈ 10.8 rupees.

118Mathematics
Compute: 4082 ÷ 157 - 23
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Answer: (B) 3

Explanation

First, divide 4082 by 157: 4082 ÷ 157 = 26

Next, perform the subtraction: 26 - 23 = 3

119Mathematics
Solve: 1000x - 5 = - 6
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Answer: (B) ⁻¹⁄₁₀₀₀

Explanation

To solve the linear equation for x:

1000x - 5 = -6

Add 5 to both sides: 1000x = -6 + 5 1000x = -1

Divide both sides by 1000: x = -1/1000

120Mathematics
If the product of two numbers is 2522 and their LCM is 97 then their HCF is:
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Answer: (D) 26

Explanation

For any two positive integers, the fundamental relation between their product, Highest Common Factor (HCF), and Least Common Multiple (LCM) is given by:

Product of two numbers = HCF × LCM

Substituting the given values into the formula: 2522 = HCF × 97

HCF = 2522 ÷ 97 = 26

121Mathematics
Keerthana takes 9hrs 20minutes in walking a distance and riding back to same place where she started. She could walk both ways in 11hrs 15minutes. The time taken by her to ride back both ways is:
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Answer: (A) 7 hrs 25 min

Explanation

Let W be the time taken to walk one way and R be the time taken to ride one way.

Given that W + R = 9 hours 20 minutes, doubling this gives 2(W + R) = 18 hours 40 minutes, which represents the combined time to walk both ways and ride both ways.

The time taken to walk both ways is 2W = 11 hours 15 minutes.

Subtracting 2W from 2(W + R) gives the total time taken to ride back both ways (2R): 2R = 18 hours 40 minutes - 11 hours 15 minutes = 7 hours 25 minutes.

122Mathematics
The mean of the data 2, 9, 9, 3, 6, 9, 4 is:
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Answer: (B) 6

Explanation

The arithmetic mean is calculated using the formula: Mean = (Sum of all observations) / (Total number of observations)

Sum of observations = 2 + 9 + 9 + 3 + 6 + 9 + 4 = 42 Total number of observations = 7

Mean = 42 / 7 = 6

123Mathematics
Mr. Akshar sold a bus for Rs. 20,400 with a loss of 15% . At what price should the bus be sold to get a profit of 15% ?
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Answer: (D) Rs. 27,600

Explanation

Using the direct selling price formula:

New Selling Price = Given Selling Price × (100 + Profit%) / (100 - Loss%)

Substituting the given values:

New Selling Price = 20,400 × (100 + 15) / (100 - 15) = 20,400 × 115 / 85 = 20,400 × 23 / 17 = 1,200 × 23 = Rs. 27,600

124Mathematics
Mr. Devesh borrowed Rs. 4,500 at 4% per annum compound interest. The compound interest compounded annually for 2 years is:
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Answer: (A) Rs. 367.2

Explanation

Effective compound interest rate for 2 years at 4% per annum = 4 + 4 + (4 × 4) / 100 = 8.16%.

Compound Interest = Principal × Effective Rate = 4500 × 8.16 / 100 = 45 × 8.16 = Rs. 367.2

125Mathematics
Divide Rs. 221 in the ratio 1:3:6:7. The rupees in the respective ratios are
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Answer: (C) 13, 39, 78 | 91

Explanation

Sum of the ratio terms = 1 + 3 + 6 + 7 = 17 parts.

Value per ratio part = 221 / 17 = 13.

Multiplying each term of the ratio by 13 gives the respective amounts: 1 × 13 = 13 3 × 13 = 39 6 × 13 = 78 7 × 13 = 91

126Mathematics
If Tan A = ¹⁵⁄₈ and Tan B = ⁷⁄₂₄ , then Tan (A - B) = ?
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Answer: (A) 304/297

Explanation

Using the trigonometric identity: tan(A - B) = (tan A - tan B) / (1 + tan A × tan B)

Substitute tan A = 15/8 and tan B = 7/24 into the formula:

tan A - tan B = 15/8 - 7/24 = 45/24 - 7/24 = 38/24

1 + tan A × tan B = 1 + (15/8 × 7/24) = 1 + 105/192 = 297/192

tan(A - B) = (38/24) ÷ (297/192) = (38/24) × (192/297) = 38 × 8 / 297 = 304/297

127Mathematics
The value of 2.31 × 0.34 = ?
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Answer: (B) 0.7854

Explanation

To find the product of 2.31 and 0.34, multiply the numbers ignoring the decimal points first:

231 × 34 = 7854

Count the total number of decimal places in both factors: 2.31 has two decimal places and 0.34 has two decimal places, giving a total of four decimal places. Placing the decimal point four places from the right yields 0.7854.

128Mathematics
Correct expression of 0.018 = ?
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Answer: (C) ¹⁸⁄₁₀₀₀

Explanation

To convert a decimal number to a fraction, place the digits after the decimal point over a power of 10 corresponding to the number of decimal digits. Since 0.018 has three decimal places, the denominator is 10³ = 1000, giving 18/1000.

129Mathematics
Which is the correct ascending order of the given numbers?
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Answer: (C) 1/5,1/3,2/5

Explanation

Converting each fraction into its decimal form:

1/5 = 0.20 1/3 = 0.33... 2/5 = 0.40

Arranging these decimal values in increasing order gives 0.20 < 0.33 < 0.40, which corresponds to 1/5, 1/3, 2/5.

130Mathematics
Simplify: 5x - 2x(x - 1)
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Answer: (D) 7x - 2x²

Explanation

Expanding the given algebraic expression using the distributive property: 5x - 2x(x - 1) = 5x - 2x² + 2x

Combining the like terms: (5x + 2x) - 2x² = 7x - 2x²

131Mathematics
If sin x = ⅘ , then (sec x)/(sin x) = ?
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Answer: (D) ²⁵⁄₁₂

Explanation

In a right-angled triangle with sin x = 4/5, the opposite side is 4 and the hypotenuse is 5. Using the Pythagorean theorem, the adjacent side is √(5² - 4²) = 3.

Therefore, cos x = 3/5, which gives sec x = 1/cos x = 5/3.

Evaluating the given expression: sec x / sin x = (5/3) / (4/5) = (5/3) × (5/4) = 25/12

132Mathematics
Ms. Alina borrowed Rs. 650 at 6% per annum simple interest. What amount will she pay to clear her debt after 4 years?
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Answer: (C) Rs. 806

Explanation

Simple Interest SI = (P × R × T) / 100 Total Amount = Principal + SI

Given Principal P = Rs. 650, Rate R = 6%, and Time T = 4 years: SI = (650 × 6 × 4) / 100 = Rs. 156

Total Amount = 650 + 156 = Rs. 806

133Mathematics
The order of rotational symmetry of a trapezium is:
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Answer: (C) 1

Explanation

Rotational symmetry refers to the number of times a geometric figure matches its original orientation during a complete rotation of 360°. A trapezium aligns with its original shape only after completing a full turn of 360°. Consequently, the order of rotational symmetry of a trapezium is 1.

134Mathematics
The median of the data -3, 4, 0, 4, -2, -5, 1, 7, 10, 5 is:
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Answer: (B) 2.5

Explanation

To find the median, arrange the given 10 observations in ascending order: -5, -3, -2, 0, 1, 4, 4, 5, 7, 10

Since the total number of observations n = 10 is even, the median is the mean of the (n/2)th and ((n/2) + 1)th terms, which correspond to the 5th and 6th values in the sorted list.

5th term = 1 6th term = 4

Median = (1 + 4) / 2 = 5 / 2 = 2.5

135Mathematics
Chandan travelled equal distance with speed of 3 km/hr, 4 km/hr and 8 km/hr and takes a total time of 42.5 minutes. Find the total distance in km.
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Answer: (D) 3

Explanation

Let each equal distance be d km. The total distance travelled is 3d km.

Time = Distance / Speed

Total time in hours = d/3 + d/4 + d/8 = d × (8 + 6 + 3) / 24 = 17d/24 hours

Converting total time from minutes to hours: 42.5 minutes = 42.5 / 60 = 17 / 24 hours

Equating both: 17d/24 = 17/24 d = 1 km

Total distance = 3 × 1 = 3 km

136Mathematics
4 men can build a small house in 12 days. How long would it take for 6 men to build the same house?
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Answer: (B) 8 days

Explanation

Using the work-equivalence formula M₁ × D₁ = M₂ × D₂:

4 × 12 = 6 × D₂ 48 = 6 × D₂ D₂ = 48 / 6 = 8 days

137Mathematics
The cash difference between the selling price of an article at a profit of 2% and 12% is Rs.3. The ratio of two selling prices is:
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Answer: (A) 51:56

Explanation

Let the cost price of the article be 100 units.

First selling price at 2% profit = 100 + 2 = 102 units Second selling price at 12% profit = 100 + 12 = 112 units

Ratio of the two selling prices = 102 : 112 = 51 : 56

138Mathematics
A shopkeeper cheats to the extent of 8% while buying and selling fruits, by using tampered weights, his total gain in percentage is:
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Answer: (B) 16.64

Explanation

When a trader cheats by x% while buying and y% while selling using faulty weights, the net percentage profit is calculated using the successive percentage formula:

Net Gain % = x + y + (x × y)/100

Given x = 8% and y = 8%:

Net Gain % = 8 + 8 + (8 × 8)/100 = 16 + 64/100 = 16 + 0.64 = 16.64%

139Mathematics
Given w = -2 , x = 3 , y = 0 | z = -½ . Find the value of (z)/(w) +x .
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Answer: (A) 3¼

Explanation

Substitute the given values into the expression: z/w + x = (-½) / (-2) + 3

Dividing -½ by -2 gives ¼.

Adding 3 to ¼ gives: ¼ + 3 = 3¼

140Mathematics
Compute: 28854 ÷ 458 ÷ 9
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Answer: (C) 7

Explanation

Using the standard order of operations for sequential division, operations are evaluated from left to right:

28854 ÷ 458 ÷ 9 = (28854 ÷ 458) ÷ 9 = 28854 ÷ (458 × 9)

Multiplying the divisors: 458 × 9 = 4122

Dividing the dividend by 4122: 28854 ÷ 4122 = 7

141Mathematics
Mohan invested Rs. 100,000 in a garment business. After few months, Sohan joined him with Rs. 40000. At the end of the year, the total profit was divided between them in ratio 3 : 1. After how many months did Sohan join the business?
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Answer: (B) 2

Explanation

Profit ratio in a partnership is equal to the ratio of the products of their respective investments and time periods: Profit ratio = (Capital₁ × Time₁) / (Capital₂ × Time₂)

Let Mohan's time be 12 months and Sohan's time in the business be t months. Substituting the given values:

3 / 1 = (100000 × 12) / (40000 × t) 3 / 1 = 30 / t 3t = 30 t = 10 months

Sohan was active in the business for 10 months, which means he joined after 12 - 10 = 2 months.

142Mathematics
If two complimentary angles are in the ratio of 4:5, find the greater angle.
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Answer: (B) 50°

Explanation

Complementary angles add up to 90°. For two angles in the ratio 4:5, the total number of parts is 4 + 5 = 9.

Value of one part = 90° / 9 = 10°

The greater angle corresponds to 5 parts = 5 × 10° = 50°.

143Mathematics
The table below depicts the no. of pages printed by 6 Printers in 5 different months. Study the table carefully and answer the following questions Number of Pages Printed by 6 Printers in 5 Different Months Month | Printer P | Printer Q | Printer R | Printer S | Printer T | Printer U 1st | 664 | 618 | 628 | 552 | 638 | 419 2nd | 569 | 441 | 519 | 438 | 621 | 537 3rd | 440 | 614 | 503 | 527 | 541 | 742 4th | 256 | 563 | 347 | 651 | 412 | 321 5th | 717 | 429 | 598 | 582 | 519 | 693 What is the average number of pages printed by all the given printers in 4th month?
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Answer: (C) 425

Explanation

Average = (Total pages printed in 4th month) ÷ (Number of printers)

Sum of pages printed by printers P, Q, R, S, T, and U in the 4th month: = 256 + 563 + 347 + 651 + 412 + 321 = 2550

Average = 2550 ÷ 6 = 425

144Mathematics
The table below depicts the no. of pages printed by 6 Printers in 5 different months. Study the table carefully and answer the following questions Number of Pages Printed by 6 Printers in 5 Different Months Month | Printer P | Printer Q | Printer R | Printer S | Printer T | Printer U 1st | 664 | 618 | 628 | 552 | 638 | 419 2nd | 569 | 441 | 519 | 438 | 621 | 537 3rd | 440 | 614 | 503 | 527 | 541 | 742 4th | 256 | 563 | 347 | 651 | 412 | 321 5th | 717 | 429 | 598 | 582 | 519 | 693 Which printer printed maximum number of pages in all the given months together?
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Answer: (A) Printer S

Explanation

The total number of pages printed by Printer S across all 5 months is calculated by summing its monthly output: 552 + 438 + 527 + 651 + 582 = 2750 pages. Comparing this with the total pages printed by the other printers over the same period (P = 2646, Q = 2665, R = 2595, T = 2731, U = 2712), Printer S has the highest overall total.

145Mathematics
The table below depicts the no. of pages printed by 6 Printers in 5 different months. Study the table carefully and answer the following questions Number of Pages Printed by 6 Printers in 5 Different Months Month | Printer P | Printer Q | Printer R | Printer S | Printer T | Printer U 1st | 664 | 618 | 628 | 552 | 638 | 419 2nd | 569 | 441 | 519 | 438 | 621 | 537 3rd | 440 | 614 | 503 | 527 | 541 | 742 4th | 256 | 563 | 347 | 651 | 412 | 321 5th | 717 | 429 | 598 | 582 | 519 | 693 What is the ratio between the number of pages printed by printer Q in second month and the number of pages printed by printer U in the fifth month?
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Answer: (B) 7:11

Explanation

Number of pages printed by Printer Q in the 2nd month = 441 Number of pages printed by Printer U in the 5th month = 693

Required Ratio = 441 : 693

Dividing both terms by 63: 441 ÷ 63 = 7 693 ÷ 63 = 11

The simplified ratio is 7:11.

146Mathematics
If 10x² - 6xy + y² - 4x + 4 = 0 , then find the value of (x + 2y) .
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Answer: (C) 14

Explanation

Rearranging the given equation into a sum of two perfect squares: 10x² - 6xy + y² - 4x + 4 = 0 (9x² - 6xy + y²) + (x² - 4x + 4) = 0 (3x - y)² + (x - 2)² = 0

Since the sum of two squared real terms is zero, each term must individually equal zero: x - 2 = 0 ⇒ x = 2 3x - y = 0 ⇒ y = 3x = 6

Substituting x = 2 and y = 6 into (x + 2y): x + 2y = 2 + 2(6) = 2 + 12 = 14

147Mathematics
The mean of a distribution is 20 and the standard deviation is 4. What is the value of the coefficient variation?
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Answer: (B) 20%

Explanation

The Coefficient of Variation (CV) measures the relative variability of a dataset and is given by the formula:

Coefficient of Variation = (Standard Deviation / Mean) × 100%

Substituting the given values: Coefficient of Variation = (4 / 20) × 100% = 0.20 × 100% = 20%

148Mathematics
If the angles of a triangle are in the ratio of 2:5:8, then find the value of the smallest angle.
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Answer: (D) 24°

Explanation

Sum of interior angles of a triangle is always 180°.

Sum of ratio terms = 2 + 5 + 8 = 15

Smallest angle = (2 / 15) × 180° = 2 × 12° = 24°

149Mathematics
When Bablu decreases the selling price of the shoes from Rs. 360 to Rs. 345, his loss increases by 4%. The cost price of the shoes is :
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Answer: (B) Rs. 375

Explanation

The decrease in the selling price is 360 - 345 = Rs. 15. Since loss increases by 4% of the cost price (CP) due to this price drop, 4% of CP = 15. Therefore, CP = (15 × 100) / 4 = Rs. 375.

150Mathematics
What is the average of first 30 multiples of 9?
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Answer: (C) 139.5

Explanation

The average of the first n multiples of a number k is given by the formula:

Average = k × (n + 1) / 2

Substituting k = 9 and n = 30:

Average = 9 × (30 + 1) / 2 = 9 × 31 / 2 = 279 / 2 = 139.5

Alternatively, since the multiples form an arithmetic progression, the average is simply the mid-point of the first term (9) and the last term (270):

Average = (9 + 270) / 2 = 139.5

Answer key

Tap a number to jump to that question.

  1. 101C
  2. 102C
  3. 103C
  4. 104B
  5. 105C
  6. 106A
  7. 107C
  8. 108A
  9. 109B
  10. 110A
  11. 111C
  12. 112C
  13. 113A
  14. 114B
  15. 115A
  16. 116B
  17. 117A
  18. 118B
  19. 119B
  20. 120D
  21. 121A
  22. 122B
  23. 123D
  24. 124A
  25. 125C
  26. 126A
  27. 127B
  28. 128C
  29. 129C
  30. 130D
  31. 131D
  32. 132C
  33. 133C
  34. 134B
  35. 135D
  36. 136B
  37. 137A
  38. 138B
  39. 139A
  40. 140C
  41. 141B
  42. 142B
  43. 143C
  44. 144A
  45. 145B
  46. 146C
  47. 147B
  48. 148D
  49. 149B
  50. 150C

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