SSC CHSL Tier 1 2023 General Intelligence & Reasoning Questions with Solutions

Explanation

Interchanging the operators + and - in the given equation: 85 + 28 × 3 - 114 ÷ 6 = 150

Applying the BODMAS rule, first perform the division operation: 114 ÷ 6 = 19

Next, perform the multiplication operation: 28 × 3 = 84

Substitute these values back into the expression: 85 + 84 - 19 = 150

Now, perform the addition: 169 - 19 = 150

Finally, perform the subtraction: 150 = 150

The Left Hand Side equals the Right Hand Side, balancing the equation.

Explanation

The three alike number-pairs follow the pattern where the second number is 9 less than the cube of the first number. This is represented by the formula y = x³ - 9.

For the pair 9:720, we have 9³ - 9 = 729 - 9 = 720. For the pair 7:334, we have 7³ - 9 = 343 - 9 = 334. For the pair 11:1322, we have 11³ - 9 = 1331 - 9 = 1322.

The pair 5:134 violates this pattern because 5³ - 9 equals 116, whereas the given value is 134, which is obtained by adding 9 to the cube of 5 instead of subtracting it.

Explanation

The relationship between the letter groups is based on shifting each letter forward by 7 positions in the English alphabetical order.

Applying this +7 shift to the letters of the given group: J (10th letter) + 7 = 17, which is Q K (11th letter) + 7 = 18, which is R M (13th letter) + 7 = 20, which is T I (9th letter) + 7 = 16, which is P

This results in the sequence QRTP.

Explanation

To find the day of the week on 9 July 1978, we first calculate the number of odd days between 13 December 1969 and 13 December 1977.

The number of years between these two dates is 8 years. Within this period, there are 2 leap years (1972 and 1976) and 6 ordinary years. Since a leap year has 2 odd days and an ordinary year has 1 odd day, the total number of odd days is (2 × 2) + (6 × 1) = 10 odd days. Taking 10 mod 7 gives 3 odd days. Adding 3 days to Saturday, 13 December 1977 is Tuesday.

Next, we count the number of days from 13 December 1977 to 9 July 1978: Remaining days in December 1977 = 18 days January 1978 = 31 days February 1978 = 28 days March 1978 = 31 days April 1978 = 30 days May 1978 = 31 days June 1978 = 30 days July 1978 = 9 days

The total number of days is 18 + 31 + 28 + 31 + 30 + 31 + 30 + 9 = 208 days.

The number of odd days is 208 mod 7 = 5. Adding 5 days to Tuesday results in Sunday.

Explanation

Each letter-cluster in the series is obtained by shifting the letters of the previous cluster forward by 3 positions in alphabetical order.

For the first letter: A (1) + 3 = D (4); D (4) + 3 = G (7); G (7) + 3 = J (10).

For the second letter: K (11) + 3 = N (14); N (14) + 3 = Q (17); Q (17) + 3 = T (20).

For the third letter: R (18) + 3 = U (21); U (21) + 3 = X (24); X (24) + 3 = A (27, which wraps around to 1).

For the fourth letter: W (23) + 3 = Z (26); Z (26) + 3 = C (3, wrapping around); C (3) + 3 = F (6).

Combining these results gives the letter-cluster JTAF.

Explanation

The coding pattern adds the sum of the positional values of all alphabets in the word to the total number of letters in that word.

For REPLACE: Sum of positional values = R(18) + E(5) + P(16) + L(12) + A(1) + C(3) + E(5) = 60 Number of letters = 7 Code = 60 + 7 = 67

For PETRIFY: Sum of positional values = P(16) + E(5) + T(20) + R(18) + I(9) + F(6) + Y(25) = 99 Number of letters = 7 Code = 99 + 7 = 106

For CRACKED: Sum of positional values = C(3) + R(18) + A(1) + C(3) + K(11) + E(5) + D(4) = 45 Number of letters = 7 Code = 45 + 7 = 52

Explanation

The series follows a pattern where the difference between consecutive terms is the square of consecutive natural numbers starting from 1.

The first difference is 16 - 15 = 1, which is 1². The second difference is 20 - 16 = 4, which is 2². The third difference is 29 - 20 = 9, which is 3². The fourth difference is 45 - 29 = 16, which is 4².

Following this pattern, the difference between the fifth term and the missing term must be 5², which is 25. Adding 25 to the fifth term gives 45 + 25 = 70.

Explanation

The relation between the first number x and the second number y in each given set follows the formula y = 2x - 10.

Applying this rule to the given sets: For (45, 80): 2 × 45 - 10 = 90 - 10 = 80 For (37, 64): 2 × 37 - 10 = 74 - 10 = 64

Applying the same rule to the set in option C: For (65, 120): 2 × 65 - 10 = 130 - 10 = 120

Explanation

The given series follows an alternating pattern of multiplying by 2 and adding 4.

Starting with the first term: 6 × 2 = 12

Applying the next step of the pattern, which is to add 4 to the current term: 12 + 4 = 16

Continuing the pattern to verify the subsequent terms: 16 × 2 = 32 32 + 4 = 36 36 × 2 = 72

Explanation

The relationship between the numbers in each pair is defined by the formula:

First number = Second number × 9

In the pair 100: 12, this relation does not hold because 12 × 9 = 108, which is not equal to 100.

Explanation

The series follows a specific alphabetical progression for each position of the letter in the terms.

For the first letter of each term, the alphabetical positions increase by 2: B (2) + 2 = D (4) D (4) + 2 = F (6) F (6) + 2 = H (8) H (8) + 2 = J (10)

For the second letter of each term, the alphabetical positions decrease by 3: R (18) - 3 = O (15) O (15) - 3 = L (12) L (12) - 3 = I (9) I (9) - 3 = F (6)

For the third letter of each term, the alphabetical positions increase by 2: G (7) + 2 = I (9) I (9) + 2 = K (11) K (11) + 2 = M (13) M (13) + 2 = O (15)

Combining these letters gives JFO.

Explanation

The statement All blue are dogs means that the set of blue is entirely contained within the set of dogs. Similarly, All pink are dogs means the set of pink is also entirely contained within the set of dogs. Since no definite relationship is defined between the blue and pink sets, they can either overlap or be completely disjoint. Therefore, it is possible for the set of blue and the set of pink to have no elements in common, making the conclusion No blue is pink is a possibility logically correct.

Furthermore, because No dog is silver is given, and both blue and pink are subsets of dogs, neither blue nor pink can have any intersection with silver. This makes the conclusions Some pink are silver and Some blue are silver definitely false. Thus, only conclusion II logically follows.

Explanation

By decoding the expression Q × R - S ÷ T + U step-by-step to find the relation between S and U:

T + U means T is the mother of U. S ÷ T means S is the father of T.

Combining these two relations, S is the father of U's mother T, which makes S the mother's father of U.

Explanation

In the letter-cluster TUX, the alphabetical positions of the letters are T = 20, U = 21, and X = 24. The difference between consecutive letters is +1 followed by +3. This violates the pattern of +3 followed by -1 which defines the group.

Explanation

The numbers in the given sets follow the mathematical relationship where the second number is equal to one-fourth of the product of the first and third numbers.

Second number = (First number × Third number) ÷ 4

Applying this logic to the given sets: For (22, 44, 8): (22 × 8) ÷ 4 = 176 ÷ 4 = 44 For (32, 48, 6): (32 × 6) ÷ 4 = 192 ÷ 4 = 48

Applying the same logic to the set (42, 63, 6): (42 × 6) ÷ 4 = 252 ÷ 4 = 63

Explanation

By converting the letters to their respective numerical positions in the English alphabetical order (where A = 1, B = 2, and so on), we can determine the relationship between the letter groups.

For the first pair, DGEC is related to KNLJ: D (4) + 7 = K (11) G (7) + 7 = N (14) E (5) + 7 = L (12) C (3) + 7 = J (10)

For the second pair, NQOM is related to UXVT: N (14) + 7 = U (21) Q (17) + 7 = X (24) O (15) + 7 = V (22) M (13) + 7 = T (20)

In both cases, each letter is shifted forward by 7 positions. Applying this same +7 shift logic to ILJH: I (9) + 7 = 16, which is P L (12) + 7 = 19, which is S J (10) + 7 = 17, which is Q H (8) + 7 = 15, which is O

This gives the combination PSQO.

Explanation

Comparing the words LEASE and PLEASE, the only additional letter in PLEASE is P.

Similarly, comparing the codes for the two words, LEASE is coded using the digits 1, 4, 9, 3, and 6, while PLEASE is coded using the digits 9, 4, 1, 3, 6, and 0.

The only digit present in the code for PLEASE that does not appear in the code for LEASE is 0. Since P is the only letter added to LEASE to form PLEASE, the letter P corresponds to the digit 0.

Explanation

The relation follows a specific rule where each letter in the word is replaced by the letter that comes after its alphabetical opposite (Opposite letter + 1).

The opposite of a letter is found by subtracting its alphabetical position from 27: Opposite position = 27 - original position

Applying this rule to PLEASE: P (16): Opposite is K (11). K + 1 = L (12) L (12): Opposite is O (15). O + 1 = P (16) E (5): Opposite is V (22). V + 1 = W (23) A (1): Opposite is Z (26). Z + 1 = A (27, which wraps around to 1) S (19): Opposite is H (8). H + 1 = I (9) E (5): Opposite is V (22). V + 1 = W (23)

Putting these coded letters together in order gives LPWAIW.

Explanation

S is married to G, and G is the son of M. Since K is the daughter of S, K is the daughter of G and S, which makes K the granddaughter of M. A is the only grandson of M, which means A is the son of G and S. Since K and A share the same parents, G and S, K is the sister of A.

Explanation

The logic followed in the given sets is that the second number is obtained by squaring the first number and adding 1.

y = x² + 1

For the first pair (11, 122): 11² + 1 = 121 + 1 = 122

For the second pair (32, 1025): 32² + 1 = 1024 + 1 = 1025

Applying this same relation to the pair (13, 170): 13² + 1 = 169 + 1 = 170

Explanation

Conclusion I follows directly from the first statement, All summers are hot. Since the entire class of summer is included in the class of hot, there is a mutual intersection between the two classes, which means some hot is summer.

Conclusion II follows directly from the third statement, No water is ice. The proposition No A is B is mutually exclusive, meaning its converse No B is A is always true. Thus, because no water is ice, no ice is water.

Explanation

The relationship between the first number x and the second number y in the given pairs follows the formula y = x⁴ + 2.

Using this formula for the given pairs: 3⁴ + 2 = 81 + 2 = 83 7⁴ + 2 = 2401 + 2 = 2403

Applying the same formula to the number 2: 2⁴ + 2 = 16 + 2 = 18

Explanation

The given series is -4, -1, 4, ?, 20, 31, 44.

To find the pattern, we calculate the differences between consecutive terms: -1 - (-4) = 3 4 - (-1) = 5 31 - 20 = 11 44 - 31 = 13

The differences between successive terms form a sequence of consecutive odd numbers: 3, 5, 7, 9, 11, 13.

Applying this pattern, the difference between the third term and the missing term is 7: 4 + 7 = 11

The next difference between the fifth term 20 and the missing term 11 is indeed 9: 20 - 11 = 9

This confirms the pattern and identifies 11 as the missing term.

Explanation

The triad 19 – 37 – 73 follows the pattern of multiplying by 2 and then subtracting 1 to get the next number: 37 = (19 × 2) - 1 73 = (37 × 2) - 1

This differs from the common pattern shared by the other triads, which is to multiply by 2 and then add 1 to get the subsequent numbers.

Explanation

The pattern followed in the given pairs is that each letter of the first cluster is shifted forward by 5 positions in alphabetical order to obtain the corresponding letter of the second cluster.

In the first pair ADK : FIP, the alphabetical positions are: A (1) + 5 = F (6) D (4) + 5 = I (9) K (11) + 5 = P (16)

In the second pair LPQ : QUV, the alphabetical positions are: L (12) + 5 = Q (17) P (16) + 5 = U (21) Q (17) + 5 = V (22)

Applying the same pattern to MOR: M (13) + 5 = R (18) O (15) + 5 = T (20) R (18) + 5 = W (23)

This yields the pair MOR : RTW.

Explanation

By comparing the two coded words, we can identify the common letters and their corresponding digit codes. The words TECH and CHEW share the letters C, E, and H.

The digit codes for TECH are 6, 4, 3, and 9, while the digit codes for CHEW are 4, 1, 6, and 3. The common digits between the two codes are 3, 4, and 6, which must represent the common letters C, E, and H in some order.

By removing these common letters and digits, the remaining letter in TECH is T, and the remaining digit is 9. Therefore, the code for T is 9.

Explanation

The terms of the series decrease by consecutive multiples of 5, starting from 15. The relation between successive terms Tₙ and Tₙ₊₁ is given by:

Tₙ - Tₙ₊₁ = 10 + 5n

For n = 1: T₁ - T₂ = 10 + 5(1) = 15 117 - 102 = 15

For n = 2: T₂ - T₃ = 10 + 5(2) = 20 102 - T₃ = 20 T₃ = 82

For n = 3: T₃ - T₄ = 10 + 5(3) = 25 82 - 57 = 25

For n = 4: T₄ - T₅ = 10 + 5(4) = 30 57 - 27 = 30

Explanation

The given word-pair Scatter: Combine consists of antonyms, as scatter means to separate and distribute widely, while combine means to join or bring together. The pair Diminish: Shrink consists of synonyms, as both words mean to make or become smaller or less in size, extent, or importance. Therefore, this pair does not represent the same antonymous relationship.

Explanation

Arranging the letters of the word CAREFUL in alphabetical order gives the sequence: A, C, E, F, L, R, U.

In this new letter-cluster: The letter second from the left is C. The letter fourth from the right is F.

In the standard English alphabetical series, the letters that lie between C and F are D and E. Thus, there are exactly two letters between them.

Explanation

The letters of the word SECTION are S, E, C, T, I, O, N.

When these letters are arranged in alphabetical order, they become C, E, I, N, O, S, T.

By comparing the original word with the alphabetically sorted word: Original: S E C T I O N Sorted: C E I N O S T

Only the letter E is in the second position in both the original word and the alphabetical arrangement. All other letters change their positions. Therefore, the position of only one letter remains unchanged.

Explanation

Correct Answer: B

In the other triads, the relationship between the three numbers x : y : z is defined by the formulas y = x² and z = y/2. For the triad 9 : 81 : 45, the first number x = 9 gives the second number as 9² = 81, but the third number is 45 instead of 81/2 = 40.5. This makes it the odd triad as it does not satisfy the common pattern.

Explanation

Each letter in the first group is shifted forward by 6 positions in alphabetical order to obtain the corresponding letter in the second group.

For ILMK to ORSQ: I (9) + 6 = O (15) L (12) + 6 = R (18) M (13) + 6 = S (19) K (11) + 6 = Q (17)

For FIJH to LOPN: F (6) + 6 = L (12) I (9) + 6 = O (15) J (10) + 6 = P (16) H (8) + 6 = N (14)

Applying this same relationship to TWXV: T (20) + 6 = Z (26) W (23) + 6 = 29, which wraps around the 26-letter alphabet to C (3) X (24) + 6 = 30, which wraps around to D (4) V (22) + 6 = 28, which wraps around to B (2)

This yields the letters ZCDB.

Explanation

The coding pattern involves taking the sum of the positional values of the letters in the English alphabetical order (A=1, B=2, ..., Z=26) and multiplying that sum by 3.

For ABCDE: Positional values are A=1, B=2, C=3, D=4, E=5. Sum = 1 + 2 + 3 + 4 + 5 = 15. Code = 15 × 3 = 45.

For OPQR: Positional values are O=15, P=16, Q=17, R=18. Sum = 15 + 16 + 17 + 18 = 66. Code = 66 × 3 = 198.

Applying the same logic to XYZ: Positional values are X=24, Y=25, Z=26. Sum = 24 + 25 + 26 = 75. Code = 75 × 3 = 225.

Explanation

The series is constructed by interleaving letters from the forward alphabetical sequence (A, B, C, D, ...) and the reverse alphabetical sequence (Z, Y, X, W, ...).

The sequence of forward letters is: A, B, C, D, E, F, G, H, I, J...

The sequence of reverse letters is: Z, Y, X, W, V, U, T, S, R, Q...

The series is divided into three groups:

Group 1: AB_Z Using the first two forward letters (A, B) and the first two reverse letters (Y, Z), the sequence is: A B Y Z (filling the first blank with Y).

Group 2: C_ _WX Using the next three forward letters (C, D, E) and the next two reverse letters (W, X), the sequence is: C D E W X (filling the second and third blanks with D and E).

Group 3: F_UV GHI_TQR Using the next five forward letters (F, G, H, I, J) and the next six reverse letters (V, U, T, S, R, Q), the sequence is: F S U V G H I J T Q R (filling the fourth and fifth blanks with S and J).

Combining the filled letters in sequence gives YDESJ.

Explanation

The given mathematical expression is: 49 × 7 ÷ 13 - 87 + 12 = ?

By interchanging '×' and '÷', and '+' and '-', the equation becomes: 49 ÷ 7 × 13 + 87 - 12 = ?

Applying the BODMAS rule:

First, perform the division: 49 ÷ 7 = 7

The equation becomes: 7 × 13 + 87 - 12 = ?

Next, perform the multiplication: 7 × 13 = 91

The equation becomes: 91 + 87 - 12 = ?

Now, perform the addition: 91 + 87 = 178

Finally, perform the subtraction: 178 - 12 = 166

Explanation

By comparing the two coded words, the letters common to both MOST and STOW are S, O, and T. Looking at their respective digit codes, 3472 and 2634, the common digits are 2, 3, and 4. This means the letters S, O, and T must correspond to the digits 2, 3, and 4 in some order. Excluding these common letters and digits from the word MOST and its code 3472, the remaining letter is M and the remaining unique digit is 7. Therefore, the code for M is 7.

Explanation

The standard pattern of the groups is established by adding 3 to the alphabetical position of the first letter to obtain the second letter, and then adding 4 to the position of the second letter to obtain the third letter. For NQV, the alphabetical positions of N, Q, and V are 14, 17, and 22 respectively. While the difference between N and Q is 3 (17 - 14 = 3), the difference between Q and V is 5 (22 - 17 = 5), which deviates from this +3, +4 pattern.

Explanation

The series follows a specific mathematical pattern for each corresponding letter in the clusters:

For the first letter, the alphabetical positions decrease by 2: E (5) minus 2 is C (3), C (3) minus 2 is A (1), and A (1) minus 2 is Y (25 in cyclic order).

For the second letter, the positions increase by 2: N (14) plus 2 is P (16), P (16) plus 2 is R (18), and R (18) plus 2 is T (20).

For the third letter, the positions decrease by 2: Q (17) minus 2 is O (15), O (15) minus 2 is M (13), and M (13) minus 2 is K (11).

For the fourth letter, the positions increase by 2: R (18) plus 2 is T (20), T (20) plus 2 is V (22), and V (22) plus 2 is X (24).

Applying this pattern to the missing term yields ARMV.

Explanation

The letters in the equation represent standard mathematical operators. We can determine their values by finding a consistent mapping that satisfies the equation to yield the correct option.

Since 65 is perfectly divisible by 13, let A represent division (÷). 65 ÷ 13 = 5

Let B represent multiplication (×). 5 × 6 = 30

Let C represent addition (+) and D represent subtraction (-).

Substituting these operators into the given expression: 153 + 65 ÷ 13 × 6 - 85

Applying the BODMAS rule: First, perform division: 153 + 5 × 6 - 85

Next, perform multiplication: 153 + 30 - 85

Finally, perform addition and subtraction: 183 - 85 = 98

Explanation

From the given coded relations, we can decode the expression step-by-step:

T × U means T is the father of U.

U - V means U is the husband of V. This establishes that U and V are a married couple, with U being the male and V being the female.

V + W means V is the mother of W. Consequently, U is the father of W.

W ÷ X means W is the brother of X. Since W and X are siblings, they share the same parents, making U the father of X.

Since T is the father of U, and U is the father of X, T is the father's father of X.

Explanation

The logic followed by the other number-pairs is that the second number is obtained by multiplying the first number by 5 and then subtracting 3. This is represented by the formula y = 5x - 3.

For the pair 31:158, applying this formula gives 31 × 5 - 3 = 155 - 3 = 152, which is not equal to 158. Instead, this pair follows the relation 31 × 5 + 3 = 158, making it the odd one out.

Explanation

To find the day of the week on 7 April 2006 starting from Friday, 8 March 1996, we calculate the total number of odd days between the two dates.

First, calculate the odd days from 8 March 1996 to 8 March 2006: The number of years is 10 years (2006 - 1996). In this period, there are 2 leap years (2000 and 2004) and 8 ordinary years. The year 1996 is a leap year, but since we start from 8 March, its leap day (29 February) is not included. Odd days from years = (8 × 1) + (2 × 2) = 12 odd days.

Next, calculate the odd days from 8 March 2006 to 7 April 2006: Remaining days in March = 31 - 8 = 23 days. Days in April = 7 days. Total days = 23 + 7 = 30 days. Odd days from these days = 30 mod 7 = 2 odd days.

Total odd days = 12 + 2 = 14 odd days. Since 14 mod 7 = 0, there are 0 odd days. Adding 0 days to Friday gives Friday.

Explanation

The given series is 4, 7, 13, 22, ?, 49, 67.

To find the pattern, we calculate the differences between consecutive terms: 7 - 4 = 3 13 - 7 = 6 22 - 13 = 9

The differences between the terms are successive multiples of 3, which are 3, 6, 9, 12, 15, 18, and so on.

Following this pattern, the next difference must be 12. Adding 12 to the preceding term of 22 yields: 22 + 12 = 34

We can verify this pattern with the subsequent terms: 34 + 15 = 49 49 + 18 = 67

Both values perfectly match the rest of the sequence, confirming that the missing number is 34.

Explanation

The series is composed of five 4-letter groups where the blanks are filled in the sequence A, L, W, P, H to form the following terms:

First term: L S X A Second term: W U T L Third term: N S W P Fourth term: P O Y L Fifth term: H R K A

Let us analyze the position of letters in each column of the 5 groups:

In the fourth column, the letters are A, L, P, L, A. The alphabetical positions of these letters are 1, 12, 16, 12, and 1, which form a perfectly symmetric palindrome pattern. The differences between consecutive letters in this column are +11, +4, -4, and -11, which are also symmetric.

In the second column, the letters are S, U, S, O, R with alphabetical positions 19, 21, 19, 15, and 18. This gives consecutive differences of +2, -2, -4, and +3.

In the third column, the letters are X, T, W, Y, K with alphabetical positions 24, 20, 23, 25, and 11. This gives consecutive differences of -4, +3, +2, and -14.

In the first column, the letters are L, W, N, P, H with alphabetical positions 12, 23, 14, 16, and 8. This gives consecutive differences of +11, -9, +2, and -8.

Filling the blanks with the letters A, L, W, P, H in order completes this logically structured series.

Explanation

The first statement states that some aprons are chopsticks. In syllogism, a particular affirmative statement of the form Some A are B can be logically converted to Some B are A. Therefore, it logically follows that some chopsticks are aprons, making conclusion I valid.

The third statement states that all forks are knives, which means the entire set of forks is included within the set of knives. This directly contradicts conclusion II, which claims that no forks are knives. Therefore, conclusion II is invalid, and only conclusion I follows.

Explanation

The series progresses by alternately adding 2 and 5 to the preceding term:

111 + 2 = 113 113 + 5 = 118 118 + 2 = 120 120 + 5 = 125 125 + 2 = 127

Following this pattern, the next term is obtained by adding 5 to 127:

127 + 5 = 132

Explanation

The relationship between the first number (x) and the second number (y) in the given pairs is defined by the formula:

y = 5x - 3

Applying this formula to the given pairs: For (12, 57): 12 × 5 - 3 = 60 - 3 = 57 For (16, 77): 16 × 5 - 3 = 80 - 3 = 77

Applying the same formula to the pair (8, 37): 8 × 5 - 3 = 40 - 3 = 37

Explanation

Three days ago was Friday, which means today is Monday (Friday + 3 days = Monday).

To find the day 150 days ago from today, we divide 150 by 7 to find the number of complete weeks and remaining odd days: 150 ÷ 7 = 21 weeks with a remainder of 3 days.

Going back 150 days from Monday is equivalent to going back 3 days: Monday - 3 days = Friday.

Explanation

In the alphabetical series, the standard pattern followed by the other groups is subtracting 5 positions from the first letter to get the second, and then adding 2 positions to get the third.

For CYF, the numerical positions of the letters are C = 3, Y = 25, and F = 6. The progression from C to Y involves subtracting 4 positions, and the progression from Y to F involves adding 7 positions. Because CYF follows a -4, +7 pattern instead of the consistent -5, +2 pattern, it does not belong to the group.

Explanation

The original equation is: 25 × 6 – 4 ÷ 18 + 9 = ?

To solve the expression, we interchange '+' and '÷', and '×' and '–'.

The modified equation is: 25 - 6 × 4 + 18 ÷ 9

Applying the BODMAS rule:

First, perform the division: 18 ÷ 9 = 2

The equation becomes: 25 - 6 × 4 + 2

Next, perform the multiplication: 6 × 4 = 24

The equation becomes: 25 - 24 + 2

Finally, perform addition and subtraction: 25 - 24 + 2 = 1 + 2 = 3