Which among the below option can be a square root of?
(x² - 14x + 49)(x² + 6x + 9)
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Answer: (C) (x - 7)(x + 3)
Explanation
Factoring the first quadratic polynomial using the algebraic identity (a - b)² = a² - 2ab + b²:
x² - 14x + 49 = (x - 7)²
Similarly, factoring the second quadratic polynomial using the algebraic identity (a + b)² = a² + 2ab + b²:
x² + 6x + 9 = (x + 3)²
Multiplying these two factored forms, the given expression is represented as:
(x - 7)²(x + 3)²
Taking the square root of this expression gives:
√((x - 7)²(x + 3)²) = (x - 7)(x + 3)
702Quantitative Aptitude
If (x³ + y³)^⅔ = (x² + y²) , then the value of (x² + y²)/(xy) x ≠ 0, y ≠ 0 , is:
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Answer: (A) ⅔
Explanation
To find the value of (x² + y²)/(xy), we start by simplifying the given equation:
(x³ + y³)⁽2/3) = x² + y²
By cubing both sides of the equation, we get:
(x³ + y³)² = (x² + y²)³
Expanding both sides using algebraic identities:
x⁶ + 2x³y³ + y⁶ = x⁶ + 3x⁴y² + 3x²y⁴ + y⁶
Subtracting x⁶ and y⁶ from both sides simplifies the equation to:
2x³y³ = 3x⁴y² + 3x²y⁴
Since x ≠ 0 and y ≠ 0, we can divide the entire equation by x²y²:
2xy = 3x² + 3y²
2xy = 3(x² + y²)
Rearranging the terms to find the ratio:
(x² + y²)/(xy) = 2/3
703Quantitative Aptitude
The radius of a hemispherical bowl is given as 7 cm. What is the capacity of the bowl? (π = ²²⁄₇)
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Answer: (A) 718⅔ cm³
Explanation
The capacity of a hemispherical bowl is given by the volume formula:
V = ⅔πr³
Substituting the given radius r = 7 cm and π = 22/7:
V = ⅔ × (22/7) × 7³
V = ⅔ × 22 × 7 × 7
V = ⅔ × 1078
V = 2156/3
V = 718 ⅔ cm³
704Quantitative Aptitude
A pipe can fill a tank in 15 hours. Due to leakage in the bottom it is filled in 20 hours. If the tank is full, and the pipe is closed, how much time will the leak take to empty the entire tank?
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Answer: (A) 60 hrs
Explanation
The time taken by a leak to empty a full tank, when the inlet pipe takes x hours to fill it and due to the leak it takes y hours, is given by the standard relation:
Time = (x × y) / (y - x)
Here, the inlet pipe takes x = 15 hours to fill the tank, and with the leak, it takes y = 20 hours.
Substituting these values into the formula:
Time = (15 × 20) / (20 - 15) = 300 / 5 = 60 hours
705Quantitative Aptitude
Find the 4ᵗʰ proportional to 5, 10 and 12.
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Answer: (B) 24
Explanation
The fourth proportional x to three numbers a, b, and c is defined by the proportion a : b = c : x, which gives the formula x = (b × c) / a.
Substituting the given values a = 5, b = 10, and c = 12 into the formula:
x = (10 × 12) / 5
x = 120 / 5
x = 24
706Quantitative Aptitude
A man borrowed some money and returned it in two equal instalments of ₹3,025 each. If the rate of interest is 10% per annum, compound annually, find the sum borrowed.
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Answer: (D) 5,250
Explanation
The present value of a loan returned in two equal annual installments at compound interest is given by the relation:
P = I / (1 + r/100) + I / (1 + r/100)²
where P represents the sum borrowed, I is the amount of each installment, and r is the annual rate of interest.
By substituting the given parameters, I = 3025 and r = 10, the relation becomes:
P = 3025 / (1 + 10/100) + 3025 / (1 + 10/100)²
P = 3025 / (11/10) + 3025 / (11/10)²
P = (3025 × 10) / 11 + (3025 × 100) / 121
P = 2750 + 2500
P = 5250
707Quantitative Aptitude
In an election between two candidates, one of the candidates secured 35% of the votes cast and was defeated by the other candidate by 1296 votes. If there were no invalid votes, then the total number of votes polled was:
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Answer: (D) 4320
Explanation
Let the total number of votes polled be V. Since there were no invalid votes, the winning candidate received 100% - 35% = 65% of the total votes.
The difference in votes between the winner and the loser is 65% - 35% = 30% of the total votes.
According to the problem, this difference is equal to 1296 votes:
30% of V = 1296
(30 / 100) × V = 1296
V = (1296 × 100) / 30
V = 4320
708Quantitative Aptitude
What is the value of 1980 ÷ 9 + [-77 + {-1980 + (¼ of 7920)}] ?
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Answer: (D) 143
Explanation
Using the BODMAS rule, the expression is solved in the order of brackets, of, division, multiplication, addition, and subtraction.
First, evaluate the innermost parenthesis containing the "of" operation:
1/4 of 7920 = 1980
Next, evaluate the curly braces:
-1980 + 1980 = 0
Now, evaluate the square brackets:
-77 + 0 = -77
Next, perform the division:
1980 ÷ 9 = 220
Finally, combine the results of the division and bracket calculations:
220 + [-77] = 220 - 77 = 143
709Quantitative Aptitude
Vinod had ₹10,000 with him. He lent a part of it at 8% per annum simple interest and the remaining at 10% per annum. His total annual income was ₹880. Find the sum lent at 8% .
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Answer: (B) 6,000
Explanation
Applying the rule of allegation, the overall annual interest rate obtained on the total investment is:
(880 ÷ 10,000) × 100 = 8.8%
The interest rates of the two parts are 8% and 10%, while the mean rate is 8.8%.
The ratio of the sum lent at 8% to the sum lent at 10% is:
(10 - 8.8) : (8.8 - 8) = 1.2 : 0.8 = 3 : 2
The sum lent at 8% is:
(3 ÷ (3 + 2)) × 10,000 = 3/5 × 10,000 = 6,000
710Quantitative Aptitude
During his entire school life, John's average marks in science was 80% and his average marks in mathematics was 90% . If his combined average marks in science and mathematics was 84% , while the total marks obtained by him in science was 54,000, what was John's total marks obtained in mathematics?
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Answer: (C) 36000
Explanation
Using the allegation method, we can determine the ratio of Science to Mathematics marks.
Science average is 80%
Mathematics average is 90%
Combined average is 84%
Applying allegation:
Ratio of Science to Mathematics = (90 - 84) : (84 - 80) = 6 : 4 = 3 : 2
Given that the total marks obtained in Science is 54,000, we associate this with the 3 units in our ratio:
3 units = 54,000
1 unit = 18,000
Since the marks obtained in Mathematics correspond to 2 units:
2 units = 2 × 18,000 = 36,000
711Quantitative Aptitude
Namitha gives a 20% discount on all things in her shop and yet makes a profit of 12% . What is the cost price of an item with marked price of ₹280?
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Answer: (D) ₹200
Explanation
The direct relationship between the Cost Price (CP) and the Marked Price (MP) when given the Discount percentage (D) and Profit percentage (P) is given by:
CP / MP = (100 - D) / (100 + P)
Substitute the given values, D = 20%, P = 12%, and MP = ₹280:
CP / 280 = (100 - 20) / (100 + 12)
CP / 280 = 80 / 112
CP / 280 = 5 / 7
CP = 280 × 5 / 7
CP = 40 × 5 = 200
712Quantitative Aptitude
Aman has taken a loan of ₹50,000 from a bank at the rate of 8% to be compounded annually. How much does he have to pay after 3 years? (Nearest to a ₹)
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Answer: (C) ₹62,986
Explanation
The formula for the total amount to be paid with compound interest is:
A = P × (1 + R/100)ⁿ
Here, the principal amount P is ₹50,000, the annual rate of interest R is 8%, and the time period n is 3 years.
Substituting these values into the formula:
A = 50000 × (1 + 8/100)³
A = 50000 × (1.08)³
A = 50000 × 1.259712
A = 62985.6
Rounding 62985.6 to the nearest rupee gives ₹62,986.
713Quantitative Aptitude
A man runs 200 metres in 24 seconds. His speed is:
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Answer: (A) 30 km/h
Explanation
To find the speed in kilometres per hour, we use the standard formula:
Speed = Distance / Time
Given:
Distance = 200 metres
Time = 24 seconds
First, calculate the speed in metres per second:
Speed = 200 / 24 metres per second
To convert the speed from metres per second to kilometres per hour, we multiply by the conversion factor 18/5:
Speed = (200 / 24) × (18 / 5) km/h
Simplifying the expression:
Speed = (200 / 5) × (18 / 24) km/h
Speed = 40 × (3 / 4) km/h
Speed = 10 × 3 = 30 km/h
714Quantitative Aptitude
If x is the fourth proportional of 48, 72 and 108, what is the value of x?
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Answer: (D) 162
Explanation
The fourth proportional x of three numbers a, b, and c is defined by the relation a/b = c/x, which gives the formula:
x = (b × c) / a
Substituting the given values a = 48, b = 72, and c = 108 into the formula:
x = (72 × 108) / 48
Dividing 72 and 48 by their greatest common divisor 24:
x = (3 × 108) / 2
x = 3 × 54
x = 162
715Quantitative Aptitude
In an election between Ram and Shyamal, one got 30% of the total votes and thus lost by 900 votes. If 90% of the voters voted and no invalid or illegal votes were cast, then what was the numbers of voters in the voting list?
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Answer: (B) 2500
Explanation
Let V be the total number of voters in the voting list.
Since 90% of the voters cast their votes and there are no invalid or illegal votes, the total number of votes cast is 90% of V, which represents 100% of the valid votes.
The losing candidate received 30% of the total votes cast. Since this is a two-way election, the winning candidate must have received the remaining 70% of the total votes cast.
The difference in their vote shares is 70% - 30% = 40% of the total votes cast.
We are given that the losing candidate lost by 900 votes, which means the difference between the winner and the loser is 900.
Setting up the relation:
40% of total votes cast = 900
Total votes cast = 900 / 0.40 = 2250
Since the total votes cast represents 90% of the voters on the voting list:
90% of V = 2250
V = 2250 / 0.90 = 2500
716Quantitative Aptitude
A seller gives 4 toys free of cost on buying 14 toys. What percent does the customer get as a discount?
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Answer: (B) 22%
Explanation
The discount percentage is calculated by dividing the number of free toys by the total number of toys received by the customer, then multiplying by 100.
Total number of toys received by the customer = 14 purchased toys + 4 free toys = 18 toys
Rounding to the nearest integer, the discount percentage is 22%.
717Quantitative Aptitude
Which one of the following numbers is divisible by 24?
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Answer: (B) 478656
Explanation
A number is divisible by 24 if it is divisible by both 3 and 8, as 24 = 3 × 8 and 3 and 8 are co-prime.
To test divisibility of 478656 by 8, we check its last three digits, which are 656. Since 656 ÷ 8 = 82, the number is divisible by 8.
To test divisibility of 478656 by 3, we sum its digits: 4 + 7 + 8 + 6 + 5 + 6 = 36. Since 36 is divisible by 3, the number is divisible by 3.
Since 478656 is divisible by both 3 and 8, it is divisible by 24.
718Quantitative Aptitude
While travelling from Nashik to Daman, Harsh drove for 1 hour at a speed of 50 km/h and for the next three hours at 60 km/h. What was his average speed for the whole trip?
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Answer: (B) 57.5 km/h
Explanation
Average speed is calculated by dividing the total distance travelled by the total time taken for the journey.
In the first part of the trip, the distance covered is the product of speed and time, which is 50 km/h × 1 h = 50 km.
In the second part of the trip, the distance covered is 60 km/h × 3 h = 180 km.
The total distance for the entire trip is 50 km + 180 km = 230 km.
The total time taken is 1 h + 3 h = 4 h.
Dividing the total distance by the total time gives the average speed:
Average Speed = 230 km ÷ 4 h = 57.5 km/h
719Quantitative Aptitude
6 men or 2 women or 4 boys can finish a work in 77 days. How many days will 1 man, 1 woman and 1 boy together take to finish the same work?
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Answer: (C) 84
Explanation
Let the efficiency of a man, a woman, and a boy be M, W, and B respectively.
According to the question, the total work can be represented as:
Total Work = 6M × 77 = 2W × 77 = 4B × 77
This gives the relation between their efficiencies:
6M = 2W = 4B
Dividing by the least common multiple of 6, 2, and 4, which is 12:
M/2 = W/6 = B/3
Let these ratios equal a constant k, so M = 2k, W = 6k, and B = 3k.
The total work is:
6 × 2k × 77 = 924k
The combined efficiency of 1 man, 1 woman, and 1 boy working together is:
1M + 1W + 1B = 2k + 6k + 3k = 11k
The number of days required by them to complete the work together is:
Total Work ÷ Combined Efficiency = 924k ÷ 11k = 84 days
720Quantitative Aptitude
Raghuvir purchased some perishable items for sale but 36% of those items could not be sold and went bad. However, Raghuvir managed to sell the rest of the items at a price that helped him earn an overall profit of 28%. At what percentage above the cost price of each item did Raghuvir sell each of the items that did not go bad?
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Answer: (A) 100%
Explanation
Let the total number of items purchased be 100 and the cost price of each item be ₹1. The total cost price is 100 × ₹1 = ₹100.
Since 36% of the items went bad, the number of items successfully sold is 100 - 36 = 64.
To earn an overall profit of 28%, the total selling price of the sold items must be ₹100 × 1.28 = ₹128.
The selling price of each of the 64 sold items is ₹128 ÷ 64 = ₹2.
Since the cost price of each item is ₹1 and the selling price is ₹2, the items were sold at a price ₹1 above the cost price. The percentage above the cost price is (1 / 1) × 100 = 100%.
721Quantitative Aptitude
After melting three cubes of sides 6 cm, 8 cm and 10 cm, a big cube is made. Find the side of the new cube.
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Answer: (D) 12 cm
Explanation
When the three smaller cubes are melted to form a single larger cube, the total volume remains conserved.
The volume of a cube with side s is given by the formula V = s³.
The sum of the volumes of the three individual cubes is:
V = 6³ + 8³ + 10³
V = 216 + 512 + 1000
V = 1728 cm³
Let S be the side of the newly formed big cube. Its volume is:
S³ = 1728
Taking the cube root on both sides:
S = ∛1728
S = 12 cm
722Quantitative Aptitude
Find the volume of a sphere of diameter 21 cm (use π = ²²⁄₇)
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Answer: (D) 4851 cm3
Explanation
The volume of a sphere is given by the formula V = 4/3 × π × r³, where r is the radius of the sphere.
Given that the diameter of the sphere is 21 cm, its radius r is 21/2 cm.
Substituting the radius r = 21/2 cm and π = 22/7 into the formula:
V = 4/3 × 22/7 × (21/2) × (21/2) × (21/2)
The terms 3 and 7 in the denominator multiply to 21, which cancels with one 21 in the numerator. The term 4 in the numerator cancels with 2 × 2 in the denominator. The term 22 in the numerator divided by the remaining 2 in the denominator yields 11.
This simplifies the calculation to:
V = 11 × 21 × 21
V = 11 × 441
V = 4851 cm³
723Quantitative Aptitude
If cos (x - y) = (√3)/(2) and sin (x + y) = 1, where x and y are positive acute angles and x ≥ y, then x and y are: (0° < (x + y) ≤ 90°)
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Answer: (D) 60°; 30°
Explanation
We are given:
cos(x - y) = √3/2
Since x and y are positive acute angles and x ≥ y, the value of (x - y) must be acute or zero. The angle whose cosine is √3/2 in this range is 30°. Therefore, we have:
x - y = 30°
We are also given:
sin(x + y) = 1
For the range 0° < (x + y) ≤ 90°, the angle whose sine is 1 is 90°. Therefore, we have:
x + y = 90°
Adding the two equations:
(x - y) + (x + y) = 30° + 90°
2x = 120°
x = 60°
Substituting x = 60° into the equation x + y = 90°:
60° + y = 90°
y = 30°
724Quantitative Aptitude
The length of each side of a regular hexagon is 10 cm. What is the area of the hexagon?
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Answer: (D) 150√3 cm²
Explanation
The formula for the area of a regular hexagon with side length a is:
Area = (3√3 / 2) × a²
A regular hexagon consists of six equilateral triangles of side length a. The area of one such equilateral triangle is (√3 / 4) × a². Multiplying this by six yields the area formula for the entire hexagon.
Substituting the given side length a = 10 cm into the formula:
Area = (3√3 / 2) × 10²
Area = (3√3 / 2) × 100
Area = 3√3 × 50
Area = 150√3 cm²
725Quantitative Aptitude
The factors of a² - 1 - 2x - x² are
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Answer: (B) (a + 1 + x) (a - 1 - x)
Explanation
The given algebraic expression is a² - 1 - 2x - x².
Grouping the terms involving x and the constant 1 together:
a² - 1 - 2x - x² = a² - (x² + 2x + 1)
Using the standard identity (m + n)² = m² + 2mn + n², we can rewrite the terms inside the parentheses:
x² + 2x + 1 = (x + 1)²
Substituting this back into the expression gives:
a² - (x + 1)²
Now, applying the difference of squares identity, A² - B² = (A + B)(A - B), where A = a and B = x + 1:
a² - (x + 1)² = (a + (x + 1))(a - (x + 1))
= (a + 1 + x)(a - 1 - x)
726Quantitative Aptitude
The area of a square is 9 m² + 12 m + 4. Find the measure of the side of the square.
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Answer: (A) 3 m + 2
Explanation
The area of a square with side length s is given by the formula:
Area = s²
The given area of the square is represented by the quadratic expression 9m² + 12m + 4. This expression can be factored as a perfect square trinomial using the algebraic identity:
(a + b)² = a² + 2ab + b²
By rewriting the terms of the expression:
9m² = (3m)²
4 = 2²
12m = 2 × (3m) × 2
Substituting these into the identity yields:
9m² + 12m + 4 = (3m)² + 2 × (3m) × 2 + 2² = (3m + 2)²
Equating this to the area formula:
s² = (3m + 2)²
Taking the square root of both sides gives the measure of the side of the square:
s = 3m + 2
727Quantitative Aptitude
A man spends 10½% of his salary on items of daily use and 30% of the remainder on house rent; after that, he is left with Rs 12,000. How much is his salary (consider the round-up value)?
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Answer: (B) 19,154
Explanation
Let the salary of the man be S.
The man spends 10.5% of his salary on daily use items.
The remaining salary after this expenditure is:
100% - 10.5% = 89.5% of S
Next, he spends 30% of this remainder on house rent, which means he is left with 70% of the remainder.
The final amount left with him is:
70% of 89.5% of S = 12,000
This relation is expressed as:
0.70 × 0.895 × S = 12,000
0.6265 × S = 12,000
S = 12,000 / 0.6265
S ≈ 19,154.03
Rounding to the nearest whole value, the salary is Rs 19,154.
728Quantitative Aptitude
Simplify p³ + 27
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Answer: (D) (p + 3)(p² - 3p + 9)
Explanation
Using the algebraic identity for the sum of two cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The given expression p³ + 27 can be written as p³ + 3³. Substituting a = p and b = 3 into the identity yields:
(p + 3)(p² - (p)(3) + 3²) = (p + 3)(p² - 3p + 9)
729Quantitative Aptitude
A way of punching data that exhibits the values of the variables and corresponding frequencies is called:
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Answer: (D) frequency distribution
Explanation
A frequency distribution is a systematic method of organizing and presenting raw data in a tabular or graphical format. It displays the distinct values or intervals of a variable alongside their corresponding frequencies, which represent the number of times each value or interval occurs in the dataset. This allows for an immediate understanding of the pattern, spread, and central tendencies of the data.
730Quantitative Aptitude
Two tangents TP and TQ are drawn to a circle with centre O from an external point T. If TP = 7 cm, find the length of TQ.
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Answer: (A) 7 cm
Explanation
According to the properties of circles, the lengths of two tangents drawn from an external point to a circle are equal. Since TP and TQ are two tangents drawn from the same external point T to the circle with centre O, their lengths must be equal, meaning TP = TQ. Given that TP = 7 cm, the length of TQ is also 7 cm.
731Quantitative Aptitude
If the 9- digit number 5p42978n6 is divisible by 72, what is the value of 2p - 1 , where n is the second largest of all the possible values of n? Given that p and n are natural numbers.
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Answer: (C) 15
Explanation
For a number to be divisible by 72, it must be divisible by both 8 and 9, as 8 and 9 are coprime factors of 72.
For divisibility by 8, the last three digits of the number, 8n6, must form a three-digit number that is divisible by 8. Testing digit values for n from 1 to 9, the three-digit number 8n6 is divisible by 8 when n = 1 (816), n = 5 (856), or n = 9 (896).
Among these possible values of n, which are 1, 5, and 9, the second largest value is n = 5.
For divisibility by 9, the sum of the digits of the number 5p42978n6 must be divisible by 9.
Sum of digits = 5 + p + 4 + 2 + 9 + 7 + 8 + n + 6
Substituting n = 5:
Sum of digits = 5 + p + 4 + 2 + 9 + 7 + 8 + 5 + 6 = 46 + p
For 46 + p to be a multiple of 9, the nearest multiple of 9 greater than 46 is 54.
46 + p = 54
p = 8
Using the value of p = 8, we calculate 2p - 1:
2p - 1 = 2 × 8 - 1 = 15
732Quantitative Aptitude
If the length of the diagonal of a cube is 6√3 cm, then the length of the edge of the cube is:
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Answer: (A) 6 cm
Explanation
The length of the diagonal of a cube with edge length a is given by the formula d = a√3.
Substituting the given diagonal value of 6√3 cm into the formula:
6√3 = a√3
Dividing both sides by √3, we get:
a = 6 cm
733Quantitative Aptitude
The height of a right circular cone is 6 cm and its base diameter is 16 cm. Find the volume of this cone.
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Answer: (C) 128πcm3
Explanation
The volume V of a right circular cone is calculated using the formula V = ⅓πr²h, where r represents the base radius and h represents the height.
Given that the base diameter is 16 cm, the radius r is half of the diameter, which is 8 cm. The height h is 6 cm.
Substituting these values into the formula:
V = ⅓ × π × 8² × 6
V = ⅓ × π × 64 × 6
V = 128π cm³
734Quantitative Aptitude
Champa buys type 1 sugar at 45 per kg. He mixes it with type 2 sugar having a price of 48 per kg. The final mixture becomes worth 46 per kg. What is the ratio of the quantities of type 1 sugar to type 2 sugar in the final mixture?
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Answer: (D) 2:1
Explanation
Using the rule of alligation, the ratio of the quantities of the two types of sugar can be determined directly.
Let the quantity of Type 1 sugar be Q₁ and its cost price be CP₁ = 45 per kg. Let the quantity of Type 2 sugar be Q₂ and its cost price be CP₂ = 48 per kg. The mean price of the mixture is M = 46 per kg.
The formula for the ratio of the quantities is:
Q₁ / Q₂ = (CP₂ - M) / (M - CP₁)
Substituting the given values into the formula:
Q₁ / Q₂ = (48 - 46) / (46 - 45)
Q₁ / Q₂ = 2 / 1
Thus, the ratio of the quantity of Type 1 sugar to Type 2 sugar is 2:1.
735Quantitative Aptitude
If cosec θ + cot θ = 5 then cosec θ is equal to
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Answer: (C) ½ (5 + ⅕)
Explanation
We use the fundamental trigonometric identity:
cosec² θ - cot² θ = 1
This can be factored as:
(cosec θ + cot θ)(cosec θ - cot θ) = 1
Given that cosec θ + cot θ = 5, we can substitute this into the identity:
5 × (cosec θ - cot θ) = 1
cosec θ - cot θ = 1/5
By adding the two equations:
cosec θ + cot θ = 5
cosec θ - cot θ = 1/5
We get:
2 cosec θ = 5 + 1/5
cosec θ = ½ (5 + 1/5)
736Quantitative Aptitude
A retailer offers the following discount schemes for an article to his customers.
A. Two equal successive discounts of 15% .
B. Two successive discounts of 12% and 18% .
C. Buy 7 articles and get 3 free.
Which scheme is favourable to a customer? (assuming buys articles in a multiple of 10)
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Answer: (B) Only C
Explanation
The effective discount for each scheme is calculated to find the most favorable one for the customer.
For Scheme A, the successive discount formula is x + y - xy/100.
Effective discount = 15 + 15 - (15 × 15)/100 = 30 - 2.25 = 27.75%
For Scheme B, using the same formula:
Effective discount = 12 + 18 - (12 × 18)/100 = 30 - 2.16 = 27.84%
For Scheme C, the customer gets 3 articles free on purchasing 7 articles, which means a total of 10 articles are received.
Effective discount = (Free articles / Total articles) × 100 = (3 / 10) × 100 = 30%
Comparing the three schemes, Scheme C offers the maximum discount of 30%, which is higher than the 27.75% from Scheme A and 27.84% from Scheme B. This makes Scheme C the most favorable scheme.
737Quantitative Aptitude
The average of 16 numbers is 23. The average of the first 7 numbers is 21 and that of the last 8 numbers is 24. Find the 8th number.
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Answer: (C) 29
Explanation
The total sum of all 16 numbers is obtained by multiplying their average by the total count:
16 × 23 = 368
The sum of the first 7 numbers is:
7 × 21 = 147
The sum of the last 8 numbers is:
8 × 24 = 192
The combined sum of these 15 numbers (the first 7 and the last 8) is:
147 + 192 = 339
The remaining 8th number is the difference between the total sum of all 16 numbers and the sum of these 15 numbers:
368 - 339 = 29
738Quantitative Aptitude
If a solid piece of iron in the form of a cuboid, of dimensions 49 ~cm × 33 ~cm × 24 ~cm , is moulded to form a solid sphere, then the radius of the sphere is ______. [Use π = 22 / 7 ]
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Answer: (D) 21 cm
Explanation
Correct Answer: D
When a solid cuboid is molded into a solid sphere, its volume remains conserved. Therefore, the volume of the cuboid is equal to the volume of the sphere.
The ratio of the distances Ravina and Suhel had to travel from their respective houses to their workplaces was 4:7. If Suhel had to travel 63 km, how much did Ravina have to travel?
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Answer: (D) 36 km
Explanation
Let the distance Ravina had to travel be R and the distance Suhel had to travel be S. The ratio of their travel distances is R:S = 4:7.
Given that Suhel had to travel a distance of S = 63 km, we can find Ravina's travel distance R using the ratio:
R/S = 4/7
Substituting the value of S:
R/63 = 4/7
R = (4 × 63) / 7
R = 4 × 9
R = 36 km
740Quantitative Aptitude
64% of the students of a class are girls and 81.25% of the girls have chosen soccer as their favourite sport. If 143 girls have chosen soccer as their favourite sport, what is the total number of students in the class?
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Answer: (D) 275
Explanation
Convert the percentages to fractional forms for quicker calculation:
64% = 64/100 = 16/25
81.25% = 13/16 (since 1/16 = 6.25%, then 13 × 6.25% = 81.25%)
Let the total number of students in the class be T.
Number of girls = (16/25) × T
Number of girls who chose soccer = (13/16) × (16/25) × T = 143
The factor of 16 in the numerator and denominator cancels out, simplifying the equation to:
(13/25) × T = 143
T = (143 × 25) / 13
T = 11 × 25
T = 275
741Quantitative Aptitude
The table below gives the profit/loss of a company during each of five consecutive years. Study this table and answer the question that follows. [Note: A negative value will denote a loss.]
Year | 2016 | 2017 | 2018 | 2019 | 2020
Profit/Loss (in Rs. lakh) | 20 | 30 | -10 | -5 | 35
What was the total profit or loss of the company during the last three years given in the table, taken together?
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Answer: (D) Profit of Rs.20 lakhs
Explanation
The last three years given in the table are 2018, 2019, and 2020.
The profit/loss values for these years are:
For 2018: -10 lakh
For 2019: -5 lakh
For 2020: 35 lakh
To find the total profit or loss over these three years, we sum the respective values:
Total Profit/Loss = -10 + (-5) + 35
Total Profit/Loss = -15 + 35
Total Profit/Loss = 20 lakh
Since the resulting value is positive, it represents a net profit of Rs. 20 lakhs.
Since the cost price must be a positive value, we discard the negative root and obtain x = 400.
744Quantitative Aptitude
A sum of money amounts to ₹4,624 in 2 years and to ₹4,913 in 3 years at a certain rate of interest, when interest is compounded per annum. The sum is ______.
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Answer: (D) ₹4,096
Explanation
Under compound interest compounded annually, the amount A after t years is given by the formula:
A = P × (1 + r/100)ᵗ
Substituting the given values for 2 years and 3 years:
P × (1 + r/100)² = 4624
P × (1 + r/100)³ = 4913
Dividing the second equation by the first equation gives the value of the compounding factor:
1 + r/100 = 4913 / 4624
1 + r/100 = 17 / 16
Substituting this compounding factor back into the equation for 2 years:
P × (17/16)² = 4624
P × 289/256 = 4624
P = (4624 × 256) / 289
P = 16 × 256
P = 4096
745Quantitative Aptitude
If x + ¹⁄ₓ = 10 , then find the value of (7x)/(x² + 1 - 8x) .
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Answer: (A) 3.5
Explanation
Given:
x + 1/x = 10
By multiplying both sides by x, we get:
x² + 1 = 10x
The given expression to evaluate is:
7x / (x² + 1 - 8x)
Four runners started running simultaneously from a point on a circular track. They took 400 seconds, 600 seconds, 720 seconds and 900 seconds to complete one round. After how much time did they meet at the starting point for the first time since the race started?
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Answer: (C) 3600 sec
Explanation
To find the time when the four runners meet at the starting point for the first time, we calculate the Least Common Multiple (LCM) of the individual times they take to complete one round: 400 seconds, 600 seconds, 720 seconds, and 900 seconds.
The prime factorization of each number is:
400 = 2⁴ × 5²
600 = 2³ × 3 × 5²
720 = 2⁴ × 3² × 5
900 = 2² × 3² × 5²
The LCM is obtained by taking the highest power of each prime factor involved:
For prime 2, the highest power is 2⁴
For prime 3, the highest power is 3²
For prime 5, the highest power is 5²
LCM = 2⁴ × 3² × 5² = 16 × 9 × 25 = 3600 seconds
747Quantitative Aptitude
In an election between two candidates, 15% of the voters did not cast their votes and 10% of the votes polled were found invalid. The successful candidate got 55% of the valid votes and won by a majority of 6120 votes. The number of voters enrolled on the voters list was:
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Answer: (B) 80000
Explanation
Let V be the total number of enrolled voters.
Since 15% of the voters did not cast their votes, the percentage of voters who polled their votes is 100% - 15% = 85%.
Out of the polled votes, 10% were invalid, meaning 90% of the polled votes were valid. The total number of valid votes is:
Valid votes = V × 0.85 × 0.90 = 0.765V
The successful candidate got 55% of the valid votes, which means the losing candidate got 100% - 55% = 45% of the valid votes. The majority by which the successful candidate won is the difference between these two shares:
Majority = 55% - 45% = 10% of valid votes
We are given that this majority equals 6120 votes. We can set up the equation:
0.10 × 0.765V = 6120
0.0765V = 6120
V = 6120 ÷ 0.0765
V = 80000
748Quantitative Aptitude
If x - 2y = 3 and 2xy = 5 , then find the value of (x + 2y)²
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Answer: (A) 29
Explanation
Using the algebraic identity (A + B)² = (A - B)² + 4AB, we substitute A = x and B = 2y to get:
If a² +b² +(1)/(a²) +(1)/(b²) = 4 a≠ 0 b≠ 0 , then the value of a⁴ +b⁴ is:
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Answer: (D) 2
Explanation
The given equation can be grouped as:
(a² + 1/a²) + (b² + 1/b²) = 4
According to the algebraic property of real numbers, for any non-zero real number x, the sum of its square and the reciprocal of its square is always greater than or equal to 2:
x² + 1/x² ≥ 2
This is because (x - 1/x)² ≥ 0, which expands to x² + 1/x² - 2 ≥ 0, meaning x² + 1/x² ≥ 2.
Applying this to both terms in the equation:
a² + 1/a² ≥ 2
b² + 1/b² ≥ 2
Adding these two inequalities gives:
(a² + 1/a²) + (b² + 1/b²) ≥ 4
For the sum to be exactly equal to 4, both parts must reach their minimum possible value of 2 simultaneously:
a² + 1/a² = 2 → a² = 1
b² + 1/b² = 2 → b² = 1
Substituting these values to find the required expression:
a⁴ + b⁴ = (a²)² + (b²)² = 1² + 1² = 1 + 1 = 2
750Quantitative Aptitude
A die is thrown 1,000 times with the frequencies for the outcomes 1, 2, 3, 4, 5 and 6 as given in the following table. How many times is the number appearing on the die greater than or equal to 5?
Outcome 1 2 3 4 5 6
Frequency 179 150 157 149 175 190
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Answer: (A) 365
Explanation
The number of times the outcome on the die is greater than or equal to 5 is found by summing the individual frequencies of the outcomes 5 and 6.
From the provided table:
Frequency of outcome 5 = 175
Frequency of outcome 6 = 190