If x + y = 14, then the value of x³ + y³ + 42xy is:
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Answer: (A) 2744
Explanation
Using the algebraic identity for the cube of a sum:
(x + y)³ = x³ + y³ + 3xy(x + y)
By substituting the given value x + y = 14 into the identity:
14³ = x³ + y³ + 3xy(14)
Calculating the cube of 14:
14³ = 14 × 14 × 14 = 2744
Substituting this value back into the equation gives:
2744 = x³ + y³ + 42xy
652Quantitative Aptitude
If the length and the breadth of a rectangle are increased by 15% and 20% respectively, then by how much percent the area of the rectangle will increase?
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Answer: (B) 38%
Explanation
Using the successive percentage change formula, the net percentage change in area when two dimensions are increased by x% and y% is given by:
Net percentage increase = x + y + xy/100
Substituting the given values, x = 15% and y = 20%:
Net percentage increase = 15 + 20 + (15 × 20)/100
Net percentage increase = 35 + 300/100
Net percentage increase = 35 + 3 = 38%
653Quantitative Aptitude
By selling a fridge for ₹18,200, Anu loses 15% . Find the cost price of the fridge. (Consider integral part only)
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Answer: (B) ₹21,411
Explanation
To find the cost price, we use the formula: Cost Price = Selling Price / (1 - Loss Percentage). Substituting the given values, Cost Price = 18,200 / 0.85 = 21,411.76, and considering only the integral part gives ₹21,411.
654Quantitative Aptitude
The marked price of a mobile phone is ₹18,000. It is sold with two successive discounts of 25% and 4% . An additional discount of 5% is offered for cash payment. The selling price of the mobile on cash payment is:
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Answer: (A) ₹12,312
Explanation
The selling price after three successive discounts of 25%, 4%, and 5% is calculated as 18,000 * 0.75 * 0.96 * 0.95. This multiplication yields 13,500 * 0.96 * 0.95 = 12,960 * 0.95 = 12,312.
655Quantitative Aptitude
In still water, the speed of a motorboat is 15 km / h . The boat travels 30 km downstream and returns in 4 hours and 30 minutes. The stream's speed (in km / h ) is:
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Answer: (C) 5
Explanation
The formula for the total time taken for a round trip downstream and upstream is T = d / (v + s) + d / (v - s), where d is the distance, v is the speed of the boat in still water, and s is the speed of the stream.
Given that v = 15 km/h, d = 30 km, and the total time T is 4 hours and 30 minutes, which is 9/2 hours, we can substitute these values into the formula:
9/2 = 30 / (15 + s) + 30 / (15 - s)
Dividing both sides of the equation by 3:
3/2 = 10 / (15 + s) + 10 / (15 - s)
Taking the common denominator on the right side:
3/2 = 10 × (15 - s + 15 + s) / (225 - s²)
3/2 = 300 / (225 - s²)
Cross-multiplying to solve for s:
225 - s² = 300 × 2 / 3
225 - s² = 200
s² = 25
s = 5 km/h
656Quantitative Aptitude
The table below gives the numbers of students from five different colleges who participated in the Olympiads of five different subjects during a given year.
| Subjects | College A | College B | College C | College D | College E |
|---|---|---|---|---|---|
| Hindi | 110 | 100 | 125 | 103 | 112 |
| English | 98 | 120 | 80 | 122 | 105 |
| Maths | 130 | 110 | 250 | 160 | 180 |
| Science | 100 | 100 | 150 | 200 | 80 |
| GK | 182 | 200 | 120 | 130 | 183 |
Find the average number of students per college who participated in the English Olympiad
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Answer: (A) 105
Explanation
To find the average number of students per college who participated in the English Olympiad, we use the formula for the arithmetic mean:
Average = Sum of observations / Number of observations
From the table, the number of students who participated in the English Olympiad from the five colleges (A, B, C, D, and E) are:
College A = 98
College B = 120
College C = 80
College D = 122
College E = 105
Summing these values:
Total students = 98 + 120 + 80 + 122 + 105 = 525
Since there are 5 colleges in total, we divide the sum by 5:
Average = 525 / 5 = 105
657Quantitative Aptitude
A cot was marked for £15,000 but sold for £13,500. What was the discount percentage offered on it?
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Answer: (C) 10%
Explanation
The discount percentage is calculated using the formula:
Two years ago, the population of a village was 1,000. The population increased by 10% is the first year and decreased by 10% in the second year. Find the present population.
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Answer: (C) 990
Explanation
The net percentage change in the population due to successive changes of +10% and -10% is given by the formula:
Net change = A + B + (A × B)/100
Substituting A = 10 and B = -10:
Net change = 10 - 10 + (10 × -10)/100 = -1%
This represents a net decrease of 1% over the two-year period.
Present population = Initial population × (1 - 1/100)
Present population = 1000 × 0.99 = 990
659Quantitative Aptitude
The average weight of 18 boys in a class is 45 kg and that of the remaining 8 boys is 48.75 kg. Find the average weight (in kg) of all the boys in the class. (Correct to two decimal places)
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Answer: (C) 46.15
Explanation
The weighted average of a combined group is given by the formula:
Combined Average = (n₁w₁ + n₂w₂) / (n₁ + n₂)
Here, the first group has n₁ = 18 boys with an average weight of w₁ = 45 kg, and the second group has n₂ = 8 boys with an average weight of w₂ = 48.75 kg.
Substituting these values into the formula:
Combined Average = (18 × 45 + 8 × 48.75) / (18 + 8)
Combined Average = (810 + 390) / 26
Combined Average = 1200 / 26
Combined Average = 600 / 13 ≈ 46.15 kg
660Quantitative Aptitude
If m is a natural number, then the average of five consecutive natural numbers, starting with m, is:
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Answer: (B) m+2
Explanation
The five consecutive natural numbers starting with m are m, m + 1, m + 2, m + 3, and m + 4.
The average of these five numbers is calculated by dividing their sum by 5:
Average = (m + (m + 1) + (m + 2) + (m + 3) + (m + 4)) / 5
Average = (5m + 10) / 5
Average = m + 2
Alternatively, for any arithmetic progression with an odd number of terms, the average is always equal to the middle term. Since there are five terms, the middle (third) term is m + 2.
661Quantitative Aptitude
If 5 persons can prepare 5 tables in 5 days, then how long will it take 25 persons to prepare 25 tables?
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Answer: (D) 5 days
Explanation
The relationship between the number of men (M), days (D), and work done (W) is given by the work formula:
What is the value of (4sin ³ x - 3sin x + sin 3x )?
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Answer: (B) 0
Explanation
Using the standard trigonometric identity for the triple-angle of sine:
sin 3x = 3sin x - 4sin³x
We can substitute this identity directly into the given expression:
4sin³x - 3sin x + sin 3x = 4sin³x - 3sin x + (3sin x - 4sin³x)
Combining the like terms simplifies the expression:
(4sin³x - 4sin³x) + (-3sin x + 3sin x) = 0 + 0 = 0
663Quantitative Aptitude
The average weight of a family of 4 members is 45 kg. The grandfather and the grandmother come to visit the family. Now the average weight of the 6 members of the family is 48 kg. Find the average weight of the grandparents (in kg).
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Answer: (D) 54
Explanation
Total weight of the 4 family members is:
4 × 45 = 180 kg
Total weight of the 6 family members after the grandparents arrive is:
6 × 48 = 288 kg
The combined weight of the grandfather and the grandmother is the difference between these two totals:
288 - 180 = 108 kg
The average weight of the grandparents is:
108 ÷ 2 = 54 kg
664Quantitative Aptitude
A chord of 10 cm passes through the centre of a circle. What is the diameter of the circle?
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Answer: (D) 10 cm
Explanation
A chord of a circle is defined as a straight line segment whose endpoints both lie on the circle. The longest possible chord in any circle is one that passes through the center, which by definition is the diameter of that circle. Since the problem specifies that a chord of length 10 cm passes through the center of the circle, this chord is the diameter.
Using the algebraic identity (a + b + c)(a² + b² + c² - ab - bc - ca) = a³ + b³ + c³ - 3abc where a = 2x, b = 3y, and c = 4z, the expression simplifies to (2x)³ + (3y)³ + (4z)³ - 3(2x)(3y)(4z). This yields 8x³ + 27y³ + 64z³ - 72xyz, which matches option B.
666Quantitative Aptitude
Study the given table and answer the question that follows.
| Partners | Present share in percentage |
|---|---|
| Shourya | 18% |
| Tanmay | 22% |
| Bhanu | 25% |
| Dhanya | 35% |
If the company had initially issued 10000 shares between its four partners, and if Tanmay then sold 1000 of his shares to Dhanya, then how many shares did Dhanya finally have?
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Answer: (D) 4500
Explanation
The initial number of shares held by Dhanya is calculated by taking her percentage share of the total issued shares:
Dhanya's initial shares = 35% of 10000 = 0.35 × 10000 = 3500
When Tanmay sells 1000 of his shares to Dhanya, these shares are added to Dhanya's existing shareholding:
Dhanya's final shares = 3500 + 1000 = 4500
667Quantitative Aptitude
Find the mean proportional between 144 and 225.
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Answer: (C) 180
Explanation
The mean proportional between two numbers a and b is given by the formula √(a × b).
Substituting the given values a = 144 and b = 225:
Mean proportional = √(144 × 225)
Using the property of square roots, this can be written as:
√(144 × 225) = √144 × √225
Since √144 = 12 and √225 = 15:
12 × 15 = 180
668Quantitative Aptitude
ABC is similar to △ PQR . The area of △ ABC is 64 cm² , and the area of △ PQR is 121 cm² . If QR = 15.4 cm , what is the length of BC?
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Answer: (C) 11.2 cm
Explanation
For any two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. This relation is expressed as:
Area(ΔABC) / Area(ΔPQR) = (BC / QR)²
Substituting the given values into the formula:
64 / 121 = (BC / 15.4)²
Taking the square root on both sides:
8 / 11 = BC / 15.4
Solving for BC:
BC = (8 × 15.4) / 11
BC = 8 × 1.4
BC = 11.2 cm
669Quantitative Aptitude
The following table represents the weightage of different decision features of an automobile. With the help of this information, calculate the weighted average.
Features Weightage
Safety - 8/10 40%
Comfort - 6/10 20%
Fuel Mileage - 5/10 30%
Exterior looks - 8/10 10%
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Answer: (C) 0.67
Explanation
The weighted average is calculated using the formula:
Weighted Average = ∑ (Value × Weight)
First, convert the scores and the percentage weights into decimal form:
The ratio of time taken by Anamika and Bani to complete a work is 1:3 , respectively. Therefore, Anamika is able to finish a job in 40 days less than Bani. If they work together, they can complete the work in ______ days.
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Answer: (C) 15
Explanation
Let the time taken by Anamika to complete the work be T days and the time taken by Bani be 3T days, as their time ratio is 1:3.
The difference in time taken by them is 40 days:
3T - T = 40
2T = 40
T = 20 days
So, Anamika takes 20 days and Bani takes 3 × 20 = 60 days to complete the work individually.
When working together, the total time taken is:
(Time by Anamika × Time by Bani) / (Time by Anamika + Time by Bani)
= (20 × 60) / (20 + 60)
= 1200 / 80
= 15 days
671Quantitative Aptitude
Simplify: 3ab × (a + b)⁻¹ × (a⁻¹ + b⁻¹)
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Answer: (D) 3
Explanation
Using the negative exponent rule, rewrite the term:
a⁻¹ + b⁻¹ = 1/a + 1/b = (a + b) / ab
Substituting this back into the given expression:
3ab × (a + b)⁻¹ × (a⁻¹ + b⁻¹)
= 3ab × (1 / (a + b)) × ((a + b) / ab)
Multiplying these terms together, the (a + b) and ab terms in the numerator and denominator cancel out:
3ab × (1 / (a + b)) × ((a + b) / ab) = 3
672Quantitative Aptitude
If x + ¹⁄ₓ = 5 , then the value of (3x)/(2x² + 2 - 5x) will be ______.
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Answer: (C) ⅗
Explanation
Given the relation:
x + 1/x = 5
We need to evaluate the expression:
3x / (2x² + 2 - 5x)
To simplify the expression, we divide both the numerator and the denominator by x:
Numerator: 3x / x = 3
Denominator: (2x² + 2 - 5x) / x = 2x + 2/x - 5 = 2(x + 1/x) - 5
Substituting the given value of x + 1/x = 5 into the simplified denominator:
Denominator = 2(5) - 5 = 10 - 5 = 5
Thus, the value of the expression is 3/5.
673Quantitative Aptitude
If a sum on compound interest (compounded yearly) becomes three times in 4 years, then with the same interest rate, the sum will become 81 times in:
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Answer: (D) 16 years
Explanation
Under compound interest, if a sum becomes n times in t years, then it will become nᵏ times in k × t years.
Here, the sum becomes 3 times in 4 years, so n = 3 and t = 4.
We want to find the time required for the sum to become 81 times. Writing 81 as a power of 3:
81 = 3⁴
This gives k = 4.
Applying the formula, the required time is:
k × t = 4 × 4 = 16 years.
Substitute these improper fractions into the expression:
8/3 + 7/3 × 13/7 ÷ 11/2
Following the BODMAS order of operations, perform division first:
13/7 ÷ 11/2 = 13/7 × 2/11 = 26/77
Next, perform multiplication:
7/3 × 26/77 = 26/33
Finally, perform addition by finding a common denominator:
8/3 + 26/33 = 88/33 + 26/33 = 114/33
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, 3:
114/33 = 38/11
Convert the improper fraction 38/11 back into a mixed fraction:
38/11 = 3 5/11
675Quantitative Aptitude
There is a 20% discount on a dozen pairs of shoes marked at ₹7,200. How many pair of shoes can be bought with ₹1,440?
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Answer: (A) 3
Explanation
Marked price of 12 pairs of shoes = ₹7,200
Discount percentage = 20%
Selling price of 12 pairs of shoes = 7200 × (100 - 20)/100 = 7200 × 0.80 = ₹5,760
Selling price of 1 pair of shoes = 5760 / 12 = ₹480
Number of pairs of shoes that can be bought with ₹1,440 = 1440 / 480 = 3
676Quantitative Aptitude
In a right circular cylinder, the ratio of the curved surface to the total surface area is 3:7. Find the ratio of the height of the cylinder to the radius of its base.
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Answer: (A) 3:4
Explanation
The curved surface area (CSA) of a right circular cylinder with radius r and height h is 2πrh.
The total surface area (TSA) of the cylinder is 2πr(h + r).
The ratio of the curved surface area to the total surface area is 3:7.
CSA / TSA = 3/7
Substitute the formulas into the ratio:
2πrh / [2πr(h + r)] = 3/7
Simplify the fraction by cancelling 2πr from the numerator and denominator:
h / (h + r) = 3/7
Cross-multiply to solve for the relationship between h and r:
7h = 3(h + r)
7h = 3h + 3r
4h = 3r
h/r = 3/4
This yields the ratio of the height to the radius as h:r = 3:4.
677Quantitative Aptitude
The salaries of P and Q together amount to ₹1,20,000. P spends 95% of his salary and Q 85% of his. If their savings are the same, then what is P's salary?
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Answer: (C) 90,000
Explanation
Let P and Q represent the salaries of P and Q respectively.
The sum of their salaries is given by the equation:
P + Q = 1,20,000
Since P spends 95% of his salary, his savings are:
100% - 95% = 5% of P
Since Q spends 85% of his salary, his savings are:
100% - 85% = 15% of Q
Their savings are equal, which gives:
5% of P = 15% of Q
0.05 × P = 0.15 × Q
P = 3 × Q
Substituting P = 3 × Q into the first equation:
3 × Q + Q = 1,20,000
4 × Q = 1,20,000
Q = 30,000
Using the value of Q to find P:
P = 3 × 30,000 = 90,000
678Quantitative Aptitude
The monthly income of Manisha was ₹1,20,000 and her monthly expenditure was ₹55,000. Next year, her income increased by 22% and her expenditure increase by 10%. Find the percentage increase in her savings (correct to 2 decimal places).
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Answer: (C) 32.15%
Explanation
Initial savings are calculated as the difference between initial income and initial expenditure:
Initial Savings = 1,20,000 - 55,000 = 65,000
The increase in income is 22% of 1,20,000:
Increase in Income = 0.22 × 1,20,000 = 26,400
The increase in expenditure is 10% of 55,000:
Increase in Expenditure = 0.10 × 55,000 = 5,500
The net increase in savings is the difference between the increase in income and the increase in expenditure:
Increase in Savings = 26,400 - 5,500 = 20,900
The percentage increase in savings is the increase in savings divided by the initial savings, multiplied by 100:
Percentage Increase = (20,900 / 65,000) × 100 = 2,090 / 65 = 32.15%
679Quantitative Aptitude
The table below gives the ratio of a particular firm over five consecutive years. Input/Output
Year Ratio Input/Output
1996 0.8
1997 1.2
1998 0.9
1999 1.6
2000 1.8
If the inputs in the year 1998 was 1,200 crores and total output in the years 1998 and 2000 taken together was 2,500 crores, then what was the input of the firm in the year 2000?
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Answer: (B) 2,100 crores
Explanation
The relationship between Input, Output, and Ratio is given by the formula:
Ratio = Input / Output
This can be rearranged to find the Output:
Output = Input / Ratio
For the year 1998:
Input in 1998 = 1,200 crores
Ratio in 1998 = 0.9
Output in 1998 = 1200 / 0.9 = 4000/3 crores
The total output for the years 1998 and 2000 combined is 2,500 crores. Therefore:
Output in 2000 = 2500 - 4000/3 = (7500 - 4000) / 3 = 3500/3 crores
For the year 2000, the ratio of Input to Output is 1.8. To find the input in 2000:
Input in 2000 = Ratio in 2000 × Output in 2000
Input in 2000 = 1.8 × (3500/3) = 0.6 × 3500 = 2,100 crores
680Quantitative Aptitude
When a certain number is multiplied by 11, the product is a six- digit number containing only 6s. Find the number that is multiplied by 11.
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Answer: (C) 60606
Explanation
Let the required number be x. The product of this number when multiplied by 11 is a six-digit number containing only 6s, which is 666666.
To find x, set up the equation:
x × 11 = 666666
Now, divide 666666 by 11:
x = 666666 ÷ 11
x = 60606
681Quantitative Aptitude
The table below gives the numbers of students from five different colleges who participated in the Olympiads of five different subjects during a given year.
Subjects College A College B College C College D College E
Hindi 110 100 125 103 112
English 98 120 80 122 105
Maths 130 110 250 160 180
Science 100 100 150 200 80
GK 182 200 120 130 183
Which college had the maximum aggregate number of participants in all the five different subject Olympiads taken together during that year?
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Answer: (D) College C
Explanation
To find the college with the maximum aggregate number of participants, we calculate the total sum of participants across all five subjects for each college.
The aggregate participant count for College A is 110 + 98 + 130 + 100 + 182 = 620.
The aggregate participant count for College B is 100 + 120 + 110 + 100 + 200 = 630.
The aggregate participant count for College C is 125 + 80 + 250 + 150 + 120 = 725.
The aggregate participant count for College D is 103 + 122 + 160 + 200 + 130 = 715.
The aggregate participant count for College E is 112 + 105 + 180 + 80 + 183 = 660.
Comparing these aggregates, College C has the highest total with 725 participants.
682Quantitative Aptitude
Under a sale offer, Tanvir was offered a 32% discount on the part of the marked price that was paid in cash, but had to add 1.2% on the part of the marked price paid through a credit card. If Tanvir paid 75% of the marked price in cash and the rest through a credit card, what percentage of the marked price was his total final payment?
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Answer: (D) 76.3%
Explanation
Let the marked price of the item be 100.
Tanvir pays 75% of the marked price in cash and the remaining 25% through a credit card.
Cash portion of the marked price = 75
Credit card portion of the marked price = 25
A discount of 32% is offered on the cash portion, so the actual payment made in cash is:
75 × (1 - 0.32) = 75 × 0.68 = 51
An extra 1.2% is added to the credit card portion, so the actual payment made through the credit card is:
25 × (1 + 0.012) = 25 × 1.012 = 25.3
His total final payment is the sum of both payments:
51 + 25.3 = 76.3
Since the initial marked price was 100, the total final payment of 76.3 represents 76.3% of the marked price.
683Quantitative Aptitude
Find the length of the longest bamboo pole that can be placed in a room 16m long, 12m broad and 10m high.
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Answer: (C) 10√5m
Explanation
The length of the longest bamboo pole that can be placed in a room is equal to the length of the diagonal of the cuboid-shaped room.
The formula for the diagonal d of a cuboid with length l, breadth b, and height h is:
d = √(l² + b² + h²)
Substituting the given values, l = 16 m, b = 12 m, and h = 10 m, into the formula:
d = √(16² + 12² + 10²)
d = √(256 + 144 + 100)
d = √500
d = 10√5 m
684Quantitative Aptitude
The average weight of 8 persons increased by 2.5kg when a new person comes in place of one of them weighting 45kg . What is the weight of the new person?
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Answer: (C) 65kg
Explanation
Using the direct formula for replacement:
Weight of new person = Weight of removed person + (Total number of persons × Increase in average weight)
Given:
Weight of removed person = 45 kg
Total number of persons = 8
Increase in average weight = 2.5 kg
Substituting the values into the formula:
Weight of new person = 45 + 8 × 2.5
Weight of new person = 45 + 20 = 65 kg
685Quantitative Aptitude
The mean proportional between 6 and another number is 30. What is that number?
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Answer: (A) 150
Explanation
The mean proportional between two numbers a and b is given by the formula √(a × b).
Let the unknown number be x. According to the formula:
√(6 × x) = 30
Squaring both sides of the equation yields:
6 × x = 30²
6 × x = 900
Dividing both sides by 6 gives:
x = 150
686Quantitative Aptitude
A thief is spotted by a policeman from a distance of 480 m. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 19 km/h and that of the policeman is 23 km/h, then how far would the thief have to run before he is overtaken?
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Answer: (B) 2280 m
Explanation
The relative speed of the policeman with respect to the thief is the difference in their speeds because they are running in the same direction:
Relative Speed = 23 km/h - 19 km/h = 4 km/h
Converting this relative speed into meters per second:
Relative Speed = 4 × 5/18 = 10/9 m/s
The time taken by the policeman to catch the thief is the initial separation distance divided by their relative speed:
Time = 480 ÷ (10/9) = 480 × 9/10 = 432 seconds
The distance run by the thief during this time is:
Distance = Speed of thief × Time
Converting the thief's speed of 19 km/h into meters per second:
Speed of thief = 19 × 5/18 = 95/18 m/s
Distance = 95/18 × 432 = 95 × 24 = 2280 m
687Quantitative Aptitude
In what proportion must wheat at ₹20.40 per kg be mixed with wheat at ₹25.50 per kg, so that the mixture is worth ₹23.80 per kg?
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Answer: (D) 1: 2
Explanation
The mixture ratio can be determined using the rule of alligation:
Ratio of cheaper wheat to dearer wheat = (Cost of dearer wheat - Mean price) / (Mean price - Cost of cheaper wheat)
Given:
Cost of cheaper wheat = ₹20.40 per kg
Cost of dearer wheat = ₹25.50 per kg
Mean price of the mixture = ₹23.80 per kg
What is the simplified value of cos²(90° - θ) - ([cos(90° - θ) cos θ]²)/(cot θ)?
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Answer: (C) 0
Explanation
By simplifying the expression and correcting a typographical square in the numerator, we get cos²(90 - theta) - [cos(90 - theta) * cos(theta)] / cot(theta). This simplifies to sin²(theta) - [sin(theta) * cos(theta)] / (cos(theta) / sin(theta)) = sin²(theta) - sin²(theta) = 0.
689Quantitative Aptitude
Find the length of diagonal (in cm) of a cube if the volume of the cube is 1331 cm³.
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Answer: (C) 11√3
Explanation
The volume of a cube is given by the formula V = a³, where a is the side length of the cube. Given that the volume is 1331 cm³, the side length is found by taking the cube root:
a = ∛1331 = 11 cm
The length of the diagonal of a cube is given by the formula d = a√3. Substituting the side length into this formula:
d = 11√3 cm
690Quantitative Aptitude
If x⁴ + (1)/(x⁴) = 14159 , Then a Possible value of x + ¹⁄ₓ is:
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Answer: (D) 11
Explanation
Let k = x + 1/x.
Using the algebraic identity:
x² + 1/x² = (x + 1/x)² - 2 = k² - 2
Substitute the given value x⁴ + 1/x⁴ = 14159:
(k² - 2)² - 2 = 14159
(k² - 2)² = 14161
Taking the square root:
k² - 2 = 119
k² = 121
k = ±11
691Quantitative Aptitude
Ruksana travelled at 60 km/h while going from point A to point B, and returned via the same route at a different speed. If Ruksana's overall average speed during the two-way journey was 48 km/h, what was her speed while travelling from B to A?
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Answer: (B) 40 km/h
Explanation
When a person travels equal distances at two different speeds, say v₁ and v₂, the overall average speed for the entire journey is given by the harmonic mean formula:
Average Speed = 2v₁v₂ / (v₁ + v₂)
Given that the speed from A to B is v₁ = 60 km/h, the average speed is 48 km/h, and letting the return speed from B to A be v₂:
48 = 2 × 60 × v₂ / (60 + v₂)
48 = 120v₂ / (60 + v₂)
48 × (60 + v₂) = 120v₂
2880 + 48v₂ = 120v₂
2880 = 72v₂
v₂ = 2880 / 72 = 40
692Quantitative Aptitude
What distance will be covered by a bus moving at 108 km/h in 40 seconds?
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Answer: (D) 1 km 200 m
Explanation
Distance is calculated using the formula:
Distance = Speed × Time
First, convert the speed of the bus from kilometers per hour (km/h) to meters per second (m/s) by multiplying by 5/18:
Speed = 108 × 5/18 = 30 m/s
Next, substitute the speed and the given time of 40 seconds into the formula to find the distance:
Distance = 30 m/s × 40 s = 1200 m
Since 1000 meters equals 1 kilometer, 1200 meters is equivalent to 1 km 200 m.
693Quantitative Aptitude
An arc on a circle that is 15 cm long subtends a 24° angle at the centre. What is the circumference of the circle?
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Answer: (D) 225 cm
Explanation
The length of an arc of a circle is proportional to the angle it subtends at the center. The relation between the arc length, the central angle θ, and the total circumference C of the circle is given by the formula:
Arc Length = (θ / 360°) × C
Substituting the given arc length of 15 cm and the central angle of 24°:
15 = (24° / 360°) × C
Simplifying the ratio of the angles:
24 / 360 = 1 / 15
Substituting this back into the formula yields:
15 = (1 / 15) × C
Solving for C:
C = 15 × 15 = 225 cm
694Quantitative Aptitude
The ratio of the radii of two right circular cylinders is 2:3 . If their heights are in the ratio 5:3 , find the ratio of their volumes.
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Answer: (D) 20:27
Explanation
The volume V of a right circular cylinder is given by the formula:
V = πr²h
Let the radii of the two cylinders be r₁ and r₂, and their heights be h₁ and h₂. The ratio of their volumes V₁/V₂ is:
V₁/V₂ = (π r₁² h₁) / (π r₂² h₂) = (r₁/r₂)² × (h₁/h₂)
Substituting the given ratios r₁/r₂ = 2/3 and h₁/h₂ = 5/3:
V₁/V₂ = (2/3)² × (5/3) = 4/9 × 5/3 = 20/27
695Quantitative Aptitude
An article is sold at a discount of 10% and an additional discount of 40% is allowed on cash payment. If Anita purchased an article by paying ₹2,700 in cash, the marked price of the article was:
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Answer: (A) 5,000
Explanation
Let the marked price of the article be MP. The final selling price after successive discounts of 10% and 40% is given by:
Selling Price = MP × (1 - d₁) × (1 - d₂)
Substituting the given values of 10% and 40% discounts and the final cash payment of ₹2,700:
A dealer allows his customers a discount of 15% and still gains 15% . If an article cost ₹2,500 to the dealer, then its marked price is (correct to nearest integer):
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Answer: (A) 3,382
Explanation
The relationship between the marked price (MP), cost price (CP), profit percentage (P), and discount percentage (D) is given by the formula:
MP / CP = (100 + P) / (100 - D)
Given that the cost price CP is ₹2,500, the profit P is 15%, and the discount D is 15%, substitute these values into the formula:
Rounding to the nearest integer, the marked price is ₹3,382.
697Quantitative Aptitude
The lengths of a pair of parallel sides of a trapezium are 20 cm and 25 cm , respectively, and the perpendicular distance between these two sides is 14 cm . What is the area (in cm² ) of the trapezium?
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Answer: (D) 315
Explanation
The area of a trapezium is given by the formula:
Area = ½ × (a + b) × h
where a and b are the lengths of the parallel sides, and h is the perpendicular distance between them.
Substituting the given values into the formula:
a = 20 cm
b = 25 cm
h = 14 cm
Area = ½ × (20 + 25) × 14
Area = ½ × 45 × 14
Area = 45 × 7
Area = 315 cm²
698Quantitative Aptitude
What is the compound interest on ₹10,625 for 2 years at 8% interest per annum, if interest is compounded annually?
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Answer: (A) ₹1,768
Explanation
The effective rate of compound interest for 2 years at 8% per annum can be calculated using the successive percentage formula: