SSC CHSL2016Quantitative AptitudePage 25 of 34

SSC CHSL Tier 1 2016 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 1201–1250 of 1,696, each with the correct answer and a step-by-step explanation.

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1201Quantitative Aptitude
Coefficient of x in (x + 11)(3 - 5x) is ____.
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Answer: (D) -52

Explanation

To find the coefficient of x in the expansion of (x + 11)(3 - 5x), we can expand the product of the two linear terms:

(x + 11)(3 - 5x) = x(3) - x(5x) + 11(3) - 11(5x) = 3x - 5x² + 33 - 55x

Combining the like terms of x gives:

-5x² + (3 - 55)x + 33 = -5x² - 52x + 33

In this simplified polynomial, the term associated with x is -52x, which means the coefficient of x is -52.

1202Quantitative Aptitude
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
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Answer: (B) 37.5 days

Explanation

Time taken by A to complete 4/5 (80%) of the work is 20 days, which means A completes the whole work alone in 20 × 5/4 = 25 days. A's 1-day work rate is 1/25.

The remaining 1/5 (20%) of the work is completed by A and B together in 3 days. Consequently, they can complete the entire work together in 3 × 5 = 15 days, making their combined 1-day work rate 1/15.

B's 1-day work rate is calculated by subtracting A's rate from their combined rate: 1/15 - 1/25 = 5/75 - 3/75 = 2/75

This gives B's time to complete the work as 75/2 = 37.5 days.

1203Quantitative Aptitude
What is the HCF (highest common factor) of 77 and 275?
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Answer: (B) 11

Explanation

The prime factorization of the given numbers is: 77 = 7 × 11 275 = 5 × 5 × 11 = 5² × 11

The highest common factor (HCF) of two or more numbers is the product of the lowest powers of their common prime factors. The only prime factor common to both 77 and 275 is 11, which has a power of 1 in both factorization expressions. Thus, the HCF of 77 and 275 is 11.

1204Quantitative Aptitude
To travel 648 km, an Express train takes 12 hours more than Rajdhani. If however, the speed of the Express train is doubled, it takes 6 hours less than Rajdhani. The speed of Rajdhani is ____.
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Answer: (D) 27 km/hr

Explanation

Let the time taken by the Rajdhani train to travel the distance of 648 km be T hours.

Initially, the Express train takes 12 hours more than the Rajdhani train, so the time taken by the Express train is T + 12 hours.

When the speed of the Express train is doubled, the time it takes to cover the same distance is halved. Therefore, the new time taken by the Express train is (T + 12) / 2 hours.

According to the given condition, this new time is 6 hours less than the time taken by the Rajdhani train: (T + 12) / 2 = T - 6

Solving this equation: T + 12 = 2T - 12 T = 24 hours

The Rajdhani train takes 24 hours to travel 648 km.

The speed of the Rajdhani train is: Speed = Distance / Time = 648 / 24 = 27 km/hr

1205Quantitative Aptitude
A trader had 16 quintals of wheat. He sold a part of it at 17% profit and the rest at 27% profit, so that he made a total profit of 21%. How much wheat did he sell at 27% profit?
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Answer: (B) 640 kg

Explanation

By the rule of alligation, the ratio of the quantity of wheat sold at 17% profit to the quantity sold at 27% profit is:

(27 - 21) : (21 - 17) = 6 : 4 = 3 : 2

The total quantity of wheat is 16 quintals. Since 1 quintal equals 100 kg, the total weight of the wheat is:

16 × 100 = 1600 kg

Using the ratio, the quantity of wheat sold at 27% profit is:

1600 × (2 / (3 + 2)) = 1600 × 2/5 = 640 kg

1206Quantitative Aptitude
If the number 583_437 is completely divisible by 9, then the smallest whole number in the place of the blank digit will be
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Answer: (D) 6

Explanation

According to the divisibility rule of 9, a number is completely divisible by 9 if the sum of its individual digits is divisible by 9.

Let the missing digit in the blank space be x. The sum of the digits of the number 583x437 is:

5 + 8 + 3 + x + 4 + 3 + 7 = 30 + x

For the sum 30 + x to be divisible by 9, it must equal the nearest multiple of 9 greater than or equal to 30, which is 36.

Solving for x:

30 + x = 36 x = 6

1207Quantitative Aptitude
If Girish's salary is 4/9 times of Harishankar's and Shirish's salary is 5/6 times of Harishankar's, what is the ratio of Girish's salary to Shirish's.
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Answer: (C) 8:15

Explanation

Let Harishankar's salary be H, Girish's salary be G, and Shirish's salary be S.

According to the given information, Girish's salary is: G = (4/9) × H

Shirish's salary is: S = (5/6) × H

The ratio of Girish's salary to Shirish's salary is: G : S = (4/9)H : (5/6)H

To simplify this ratio, we divide the two fractions: G / S = (4/9) / (5/6) G / S = (4/9) × (6/5) G / S = 24 / 45

By dividing both the numerator and the denominator by their greatest common divisor, which is 3, we get: G / S = 8 / 15

Thus, the ratio is 8:15.

1208Quantitative Aptitude
If 5 - x > 1 + 3x and 5 + 5x ≥ 2 + 2x; then x can take which of the following values?
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Answer: (D) 0

Explanation

To find the values x can take, we solve both inequalities individually.

For the first inequality: 5 - x > 1 + 3x Subtracting 1 and adding x on both sides: 4 > 4x Dividing by 4: x < 1

For the second inequality: 5 + 5x ≥ 2 + 2x Subtracting 2 and 2x on both sides: 3x ≥ -3 Dividing by 3: x ≥ -1

Combining both solution sets, we get the range: -1 ≤ x < 1

Among the options, only 0 lies within this interval.

1209Quantitative Aptitude
Find the value of p, if 2x - 4, 4x + p and 6x - 12 are in arithmetic progression.
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Answer: (D) -8

Explanation

If three terms a, b, and c are in arithmetic progression, the middle term is the arithmetic mean of the other two terms, which gives the relation: 2b = a + c

Substituting the given terms a = 2x - 4, b = 4x + p, and c = 6x - 12 into this formula: 2(4x + p) = (2x - 4) + (6x - 12)

Expanding both sides: 8x + 2p = 8x - 16

Subtracting 8x from both sides: 2p = -16

Dividing by 2: p = -8

1210Quantitative Aptitude
Points P and Q lie on side AB and AC of triangle ABC respectively such that segment PQ is parallel to side BC. If the ratio of areas of triangle APQ: triangle ABC is 16:25. Then the ratio of AP:PB is?
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Answer: (D) 4:1

Explanation

Since segment PQ is parallel to side BC, triangle APQ is similar to triangle ABC.

For similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides: Area(APQ) / Area(ABC) = (AP / AB)²

Substituting the given ratio: 16 / 25 = (AP / AB)²

Taking the square root on both sides: AP / AB = 4 / 5

Since point P lies on the side AB, we have AB = AP + PB. Substituting this into the ratio: AP / (AP + PB) = 4 / 5

Cross-multiplying the terms: 5 × AP = 4 × (AP + PB) 5 × AP = 4 × AP + 4 × PB AP = 4 × PB

Dividing both sides by PB: AP / PB = 4 / 1

1211Quantitative Aptitude
A man spends 59% of his income and saves the rest. What percentage of his expenditure does he save?
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Answer: (D) 69.49 percent

Explanation

Let the income of the man be 100 units.

Since he spends 59% of his income, his expenditure is 59 units.

His savings are the remaining portion of his income: Savings = Income - Expenditure = 100 - 59 = 41 units

The percentage of his expenditure that he saves is calculated as: Percentage = (Savings / Expenditure) × 100 Percentage = (41 / 59) × 100 = 4100 / 59 ≈ 69.49%

1212Quantitative Aptitude
Line segment AB is parallel to line segment CD. AD intersects BC in E. If lengths of AE, BC and ED are 12 cm, 12 cm and 18 cm respectively, what is the length of EC?
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Answer: (D) 7.2 cm

Explanation

Since AB is parallel to CD and the lines AD and BC intersect at E, the alternate interior angles are equal. Specifically, angle BAE is equal to angle CDE, and angle ABE is equal to angle DCE. Additionally, angle AEB and angle DEC are vertically opposite angles and thus equal. Therefore, triangle AEB is similar to triangle DEC.

By the property of similar triangles, the ratio of their corresponding sides is equal: AE / DE = BE / EC

Given that AE = 12 cm, DE = 18 cm, and BC = 12 cm, let the length of EC be x cm. Since BC is the sum of BE and EC, the length of BE can be expressed as 12 - x cm.

Substituting these values into the ratio: 12 / 18 = (12 - x) / x

Simplifying the fraction: 2 / 3 = (12 - x) / x

Cross-multiplying gives: 2x = 3(12 - x) 2x = 36 - 3x 5x = 36 x = 7.2

1213Quantitative Aptitude
A sum fetched a total simple interest of Rs 5320 at the rate of 7% per year in 5 years. What is the sum?
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Answer: (C) Rs 15200

Explanation

The formula for simple interest is SI = (P × R × T) / 100, where SI is the simple interest, P is the principal sum, R is the annual rate of interest, and T is the time in years.

Rearranging the formula to find the principal sum P: P = (SI × 100) / (R × T)

Substituting the given values: P = (5320 × 100) / (7 × 5) P = 532000 / 35 P = 15200

1214Quantitative Aptitude
Curved surface area of a cylinder is 660 sq cm. If circumference of its base is 44 cm, find the volume of the cylinder?
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Answer: (B) 2310 cubic cm

Explanation

The volume of a cylinder is given by the formula V = π × r² × h, where r is the radius of the base and h is the height of the cylinder.

First, find the radius from the circumference of the base: 2 × π × r = 44 2 × 22/7 × r = 44 r = 7 cm

Next, find the height from the curved surface area (CSA) of the cylinder: CSA = 2 × π × r × h = 660 Since 2 × π × r = 44: 44 × h = 660 h = 15 cm

Finally, calculate the volume of the cylinder: Volume = π × r² × h Volume = 22/7 × 7² × 15 Volume = 22 × 7 × 15 Volume = 2310 cubic cm

1215Quantitative Aptitude
Two numbers are 35% and 50% lesser than a third number. By how much percent is the second number to be enhanced to make it equal to the first number?
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Answer: (D) 30 percent

Explanation

Let the third number be 100.

Since the first and second numbers are 35% and 50% lesser than the third number respectively: First number = 100 - 35 = 65 Second number = 100 - 50 = 50

To make the second number equal to the first number, it must be increased by 65 - 50 = 15.

The required percentage enhancement is calculated with respect to the second number: Percentage enhancement = (Increase / Second number) × 100 Percentage enhancement = (15 / 50) × 100 = 30%

1216Quantitative Aptitude
What is the value of cos 11π/6?
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Answer: (D) √3/2

Explanation

Using the trigonometric identity cos(2π - θ) = cos θ, the given expression can be written as:

cos(11π/6) = cos(2π - π/6)

Applying the identity:

cos(2π - π/6) = cos(π/6)

Since the standard value of cos(π/6) is √3/2, the value of cos(11π/6) is √3/2.

1217Quantitative Aptitude
3cosA is equal to
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Answer: (B) 4cos³A - cos3A

Explanation

The standard trigonometric triple-angle identity for cosine is:

cos3A = 4cos³A - 3cosA

By rearranging this identity to isolate 3cosA, we get:

3cosA = 4cos³A - cos3A

This directly matches the given expression.

1218Quantitative Aptitude
cosA/(1 - sin A) is equal to
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Answer: (B) (secA + tanA)

Explanation

To simplify the expression cosA / (1 - sinA), multiply both the numerator and the denominator by (1 + sinA):

(cosA × (1 + sinA)) / ((1 - sinA) × (1 + sinA))

= (cosA × (1 + sinA)) / (1 - sin²A)

Using the fundamental trigonometric identity 1 - sin²A = cos²A, the expression becomes:

(cosA × (1 + sinA)) / cos²A

= (1 + sinA) / cosA

= (1 / cosA) + (sinA / cosA)

= secA + tanA

1219Quantitative Aptitude
Refer the below data table and answer the following Question. Weight (kg) Height in meter Sunita 60 1.5 Anjali 55 1.2 Vimla 75 1.6 Preeti 70 1.4 Who has the least weight to height ratio?
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Answer: (A) Sunita

Explanation

The weight to height ratio is calculated by dividing the weight in kilograms by the height in meters.

For Sunita, the ratio is: 60 ÷ 1.5 = 40

The ratios for the others are: Anjali: 55 ÷ 1.2 ≈ 45.83 Vimla: 75 ÷ 1.6 = 46.875 Preeti: 70 ÷ 1.4 = 50

Comparing these values, Sunita has the lowest weight to height ratio of 40.

1220Quantitative Aptitude
Refer the below data table and answer the following Question. Year Company's % Profit 2011 5 2012 15 2013 25 2014 10 2015 10 What was the Revenue of the company if its Expenditure was Rs 200 crore in the year when its % profit was the least?
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Answer: (A) 210

Explanation

The least percentage profit in the given table is 5% in the year 2011.

The percentage profit of a company is calculated using the formula: Profit % = ((Revenue - Expenditure) / Expenditure) × 100

Given that the expenditure is ₹200 crore: 5 = ((Revenue - 200) / 200) × 100 5 = (Revenue - 200) / 2 10 = Revenue - 200 Revenue = 210 crore

1221Quantitative Aptitude
The following table shows the number of children in each house of a society. Number of Children Number of Houses 0 3 1 13 2 18 3 3 What is the average number of children per house?
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Answer: (C) 1.57

Explanation

The average number of children per house is calculated using the weighted mean formula:

Average = ∑(f × x) / ∑f

Here, x represents the number of children and f represents the number of houses.

First, calculate the total number of children, which is the sum of the products of the number of children and the number of houses: ∑(f × x) = (0 × 3) + (1 × 13) + (2 × 18) + (3 × 3) = 0 + 13 + 36 + 9 = 58

Next, calculate the total number of houses: ∑f = 3 + 13 + 18 + 3 = 37

Divide the total number of children by the total number of houses to find the average: Average = 58 / 37 ≈ 1.57

1222Quantitative Aptitude
Refer the below data table and answer the following Question. Partners Present % share Anand 25 Basu 5 Chinmay 25 Dhiraj 20 Ejaz 25 If the company has issued six lakh shares between its five partners and if Anand offers to sell 15,000 of his shares to Ejaz, then Ejaz will have how many shares?
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Answer: (A) 165000 shares

Explanation

The total number of shares issued by the company is six lakh, which is equal to 6,00,000.

As per the given table, Ejaz holds a 25% share of the company.

The initial number of shares held by Ejaz is calculated as: Initial shares = 25% of 6,00,000 = 0.25 × 6,00,000 = 1,50,000

When Anand sells 15,000 of his shares to Ejaz, the total number of shares held by Ejaz increases by 15,000.

The final number of shares with Ejaz is: Final shares = 1,50,000 + 15,000 = 1,65,000

1223Quantitative Aptitude
A bank offers 15% compound interest per half year. A customer deposits Rs 2400 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is
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Answer: (B) Rs 1134

Explanation

Total interest earned is the sum of the interest gained on each of the two deposits.

The first deposit of Rs 2400 is made on 1st January and earns interest for two half-year periods. Amount at the end of the year = 2400 × (1 + 15/100)² = 2400 × (1.15)² = 2400 × 1.3225 = Rs 3174 Interest from the first deposit = 3174 - 2400 = Rs 774

The second deposit of Rs 2400 is made on 1st July and earns interest for one half-year period. Amount at the end of the year = 2400 × (1 + 15/100) = 2400 × 1.15 = Rs 2760 Interest from the second deposit = 2760 - 2400 = Rs 360

Total interest gained by the customer at the end of the year = 774 + 360 = Rs 1134

1224Quantitative Aptitude
If sec A + tan A = x, then the value of x is
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Answer: (D) cos A/(1 - sin A)

Explanation

We are given that x = sec A + tan A.

Expressing sec A and tan A in terms of sin A and cos A: x = 1/cos A + sin A/cos A x = (1 + sin A)/cos A

Multiplying both the numerator and the denominator by (1 - sin A): x = (1 + sin A)(1 - sin A) / [cos A(1 - sin A)]

Using the trigonometric identity 1 - sin² A = cos² A: x = (1 - sin² A) / [cos A(1 - sin A)] x = cos² A / [cos A(1 - sin A)] x = cos A / (1 - sin A)

1225Quantitative Aptitude
Find two numbers such that their mean proportion is 16 and third proportion is 1024.
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Answer: (B) 4 and 64

Explanation

Let the two numbers be a and b.

The mean proportion of two numbers a and b is given by the formula √(ab), and their third proportion is given by the formula b²/a.

Given: √(ab) = 16 b²/a = 1024

Squaring the mean proportion equation: ab = 16² = 256 a = 256/b

Substituting the expression for a into the third proportion equation: b² / (256/b) = 1024 b³ = 1024 × 256 b³ = 2¹⁰ × 2⁸ b³ = 2¹⁸

Taking the cube root on both sides: b = 2⁶ = 64

Substituting the value of b to find a: a = 256 / 64 = 4

The two numbers are 4 and 64.

1226Quantitative Aptitude
A cone of radius 3.5 cm and height 12 cm is completely filled with water. This water is emptied into an empty cylindrical vessel of radius 7 cm. What will be the height of water in this vessel?
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Answer: (D) 1 cm

Explanation

The volume of water transferred from the cone to the cylinder remains constant.

Volume of the cone = (1/3) × π × r₁² × h₁ Volume of the cylinder = π × r₂² × h₂

Equating the two volumes: (1/3) × π × r₁² × h₁ = π × r₂² × h₂ (1/3) × r₁² × h₁ = r₂² × h₂

Given r₁ = 3.5 cm, h₁ = 12 cm, and r₂ = 7 cm: (1/3) × (3.5)² × 12 = 7² × h₂ 4 × 12.25 = 49 × h₂ 49 = 49 × h₂ h₂ = 1 cm

1227Quantitative Aptitude
If the length of the side of an equilateral triangle is 8 cm, what is its area?
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Answer: (C) 16√3 sq cm

Explanation

The area of an equilateral triangle with side length a is given by the formula:

Area = (√3 / 4) × a²

Substituting the given side length a = 8 cm into the formula:

Area = (√3 / 4) × 8² Area = (√3 / 4) × 64 Area = 16√3 sq cm

1228Quantitative Aptitude
A line passing through the origin perpendicularly cuts the line 3x - 2y = 6 at point M. Find M?
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Answer: (B) (18/13, -12/13)

Explanation

The slope of the given line 3x - 2y = 6 is m₁ = 3/2. Since the line passing through the origin is perpendicular to it, the product of their slopes must be -1. Therefore, the slope of the perpendicular line is m₂ = -2/3.

The equation of this perpendicular line passing through the origin (0, 0) is: y = (-2/3)x 2x + 3y = 0

To find the coordinates of the intersection point M, we solve the system of equations: 3x - 2y = 6 2x + 3y = 0

From the second equation, we get x = -3y/2. Substituting this into the first equation: 3(-3y/2) - 2y = 6 -9y/2 - 2y = 6 -13y/2 = 6 y = -12/13

Substituting y = -12/13 back into the expression for x: x = -3(-12/13) / 2 = 18/13

This gives the coordinates of M as (18/13, -12/13).

1229Quantitative Aptitude
The average weight of Shubha, Govinda and Reshma is 65 kg. If the average weight of Shubha and Govinda be 63 kg and that of Govinda and Reshma be 70 kg, then the weight of Govinda is
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Answer: (B) 71

Explanation

Let the weights of Shubha, Govinda, and Reshma be S, G, and R respectively.

The sum of the weights of Shubha, Govinda, and Reshma is: S + G + R = 3 × 65 = 195 kg

The sum of the weights of Shubha and Govinda is: S + G = 2 × 63 = 126 kg

The sum of the weights of Govinda and Reshma is: G + R = 2 × 70 = 140 kg

Adding these two equations gives: S + 2G + R = 126 + 140 = 266 kg

To find the weight of Govinda, subtract the sum of the weights of all three individuals from this combined sum: G = (S + 2G + R) - (S + G + R) G = 266 - 195 = 71 kg

1230Quantitative Aptitude
Find length of the arc whose central angle is 45° and radius of the circle is 28 cm?
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Answer: (D) 22 cm

Explanation

The length of an arc of a circle is given by the formula L = (θ/360°) × 2πr, where θ is the central angle, r is the radius of the circle, and π is 22/7.

Substituting θ = 45° and r = 28 cm into the formula:

L = (45°/360°) × 2 × (22/7) × 28

Simplifying the central angle ratio, 45°/360° equals 1/8. The calculation becomes:

L = (1/8) × 2 × 22 × 4

Since 2 × 4 is 8, the 8 in the denominator cancels out with the 8 in the numerator:

L = 22 cm

1231Quantitative Aptitude
The two numbers are 63 and 77, HCF is 7, Find the LCM.
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Answer: (B) 693

Explanation

The fundamental relation between two numbers, their HCF, and their LCM is:

Product of two numbers = HCF × LCM

Substituting the given values into the formula: 63 × 77 = 7 × LCM

LCM = (63 × 77) / 7 LCM = 9 × 77 LCM = 693

1232Quantitative Aptitude
The total cost of a washing machine with an electric chimney was Rs 57,750. The electric chimney was sold at a profit of 34% and the washing machine at a loss of 24%. If the sale price was the same in both the items, then the cost price of the cheaper item was ______.
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Answer: (B) Rs 20900

Explanation

Let the cost price of the electric chimney be C and that of the washing machine be W.

The total cost of both items is: C + W = 57,750

The selling price of the electric chimney at a 34% profit is 1.34 × C. The selling price of the washing machine at a 24% loss is 0.76 × W.

Since the selling prices of both items are equal: 1.34 × C = 0.76 × W 134 × C = 76 × W C / W = 38 / 67

The ratio of the cost price of the electric chimney to the washing machine is 38 : 67. The electric chimney is the cheaper item because it corresponds to fewer parts in the ratio.

The cost price of the electric chimney is: (38 / (38 + 67)) × 57,750 = (38 / 105) × 57,750 = 38 × 550 = 20,900

1233Quantitative Aptitude
If (7 - 12x) - (3x - 7) = 14, then the value of x is ______.
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Answer: (B) 0

Explanation

We are given the equation: (7 - 12x) - (3x - 7) = 14

Removing the parentheses by distributing the negative sign: 7 - 12x - 3x + 7 = 14

Combining the like terms on the left side: 14 - 15x = 14

Subtracting 14 from both sides of the equation: -15x = 0

Dividing both sides by -15 yields: x = 0

1234Quantitative Aptitude
Find the roots of the quadratic equation 6x² - 11x - 35 = 0
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Answer: (B) -5/3, 7/2

Explanation

For the quadratic equation ax² + bx + c = 0, the roots can be found by splitting the middle term. In the given equation 6x² - 11x - 35 = 0, the product of the coefficient of x² and the constant term is 6 × (-35) = -210, and their sum is -11. The two factors of -210 that add up to -11 are -21 and 10.

Rewriting the equation by splitting the middle term: 6x² - 21x + 10x - 35 = 0

Grouping and factoring the terms: 3x(2x - 7) + 5(2x - 7) = 0 (3x + 5)(2x - 7) = 0

Setting each factor to zero: 3x + 5 = 0 which gives x = -5/3 2x - 7 = 0 which gives x = 7/2

1235Quantitative Aptitude
If 5x + 2 < 4x + 1 and 2(x - 4) - 2 ≤ 4x - 1; then x can take which of the following values?
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Answer: (D) -2

Explanation

Solving the first inequality: 5x + 2 < 4x + 1 x < -1

Solving the second inequality: 2(x - 4) - 2 ≤ 4x - 1 2x - 8 - 2 ≤ 4x - 1 2x - 10 ≤ 4x - 1 -9 ≤ 2x x ≥ -4.5

Combining both inequalities, the solution set for x is: -4.5 ≤ x < -1

The value -2 lies within this range.

1236Quantitative Aptitude
Two students appeared for an examination. One of them secured 10 marks more than the other and his marks were 75% of the sum of their marks. The marks obtained by them are
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Answer: (D) 15 and 5

Explanation

Let the marks obtained by the two students be x and y, where x is the higher score.

According to the given conditions: x - y = 10 x = 0.75 × (x + y)

Substituting x = y + 10 into the second equation: y + 10 = 0.75 × (y + 10 + y) y + 10 = 0.75 × (2y + 10) y + 10 = 1.5y + 7.5 0.5y = 2.5 y = 5

Substituting the value of y back into the first equation: x = 5 + 10 = 15

The marks obtained by the two students are 15 and 5.

1237Quantitative Aptitude
By increasing the price of entry ticket to a fair in the ratio 3:7, the number of visitors to the fair has decreased in the ratio 16:13. In what ratio has the total collection increased or decreased?
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Answer: (B) increased in the ratio 48:91

Explanation

Total collection is the product of the ticket price and the number of visitors.

Let the initial price of the entry ticket be 3x and the new price be 7x. Let the initial number of visitors be 16y and the new number of visitors be 13y.

Initial total collection = 3x × 16y = 48xy New total collection = 7x × 13y = 91xy

Comparing the initial collection to the new collection yields the ratio 48xy:91xy, which simplifies to 48:91. Since 91 is greater than 48, the total collection has increased in the ratio 48:91.

1238Quantitative Aptitude
To cover a distance of 315 km in 2.8 hours what should be the average speed of the car in meters/second?
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Answer: (D) 31.25 m/s

Explanation

Average speed is calculated using the formula:

Average Speed = Distance / Time

Given: Distance = 315 km Time = 2.8 hours

First, calculate the average speed in km/h:

Average Speed = 315 / 2.8 = 112.5 km/h

To convert the speed from km/h to m/s, multiply the value by the conversion factor 5/18:

Average Speed in m/s = 112.5 × 5/18 = 31.25 m/s

1239Quantitative Aptitude
In an arithmetic progression, if 17 is the 3rd term, -25 is the 17th term, then -1 is which term?
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Answer: (C) 9

Explanation

The n-th term of an arithmetic progression is given by the formula: aₙ = a + (n - 1)d

where a is the first term and d is the common difference.

Using the given values for the 3rd term and the 17th term: a₃ = a + 2d = 17 a₁₇ = a + 16d = -25

Subtracting the equation for the 3rd term from the equation for the 17th term: (a + 16d) - (a + 2d) = -25 - 17 14d = -42 d = -3

Substituting the value of d into the equation for the 3rd term: a + 2(-3) = 17 a - 6 = 17 a = 23

To find which term is -1, we substitute a = 23 and d = -3 into the n-th term formula: aₙ = a + (n - 1)d -1 = 23 + (n - 1)(-3) -24 = (n - 1)(-3) n - 1 = 8 n = 9

1240Quantitative Aptitude
The area of a square is 100 sq cm, find length of its diagonal?
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Answer: (A) 10√2 cm

Explanation

The relation between the area of a square and its diagonal is given by the formula:

Area = d² / 2

where d is the length of the diagonal.

Substituting the given area of 100 sq cm into the formula:

100 = d² / 2

d² = 200

d = √200 = 10√2 cm

Alternatively, the side of the square s is √100 = 10 cm. The diagonal of a square with side s is s√2, which yields 10√2 cm.

1241Quantitative Aptitude
The distance between the points (4,-8) and (k,0) is 10. Find k?
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Answer: (B) k = 10 or -2

Explanation

The distance d between two points (x₁, y₁) and (x₂, y₂) is given by the distance formula:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

Substituting the points (4, -8) and (k, 0), and the distance d = 10:

10 = √((k - 4)² + (0 - (-8))²)

100 = (k - 4)² + 64

36 = (k - 4)²

Taking the square root:

k - 4 = ±6

For the positive root: k - 4 = 6 k = 10

For the negative root: k - 4 = -6 k = -2

1242Quantitative Aptitude
Praful has done 1/2 of a job in 30 days, Sarabjit completes the rest of the job in 10 days. In how many days can they together do the job?
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Answer: (C) 15 days

Explanation

Praful completes ½ of the job in 30 days, which means he can complete the entire job in 60 days. His daily work rate is 1/60 of the job.

Sarabjit completes the remaining ½ of the job in 10 days, which means he can complete the entire job in 20 days. His daily work rate is 1/20 of the job.

Their combined daily work rate is: 1/60 + 1/20 = 1/60 + 3/60 = 4/60 = 1/15

Thus, they can complete the job together in 15 days.

1243Quantitative Aptitude
Ticket for an adult is Rs 500 and a child is Rs 200. 1 child goes free with two adults. If a group has 20 adults and 8 children what will be the discount the group get?
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Answer: (B) 13,79 percent

Explanation

Total cost of tickets without any discount is calculated by adding the total cost for adults and children. Cost for 20 adults = 20 × 500 = Rs 10000 Cost for 8 children = 8 × 200 = Rs 1600 Total original cost = 10000 + 1600 = Rs 11600

Since two adults allow one child to enter for free, 20 adults can allow up to 20 / 2 = 10 children to enter for free. Since there are only 8 children in the group, all 8 children will get free entry. Total discount received by the group is the ticket price of the 8 children: Discount = 8 × 200 = Rs 1600

Discount percentage is calculated as: Discount % = (Discount / Total original cost) × 100 Discount % = (1600 / 11600) × 100 = 1600 / 116 = 400 / 29 ≈ 13.79%

1244Quantitative Aptitude
A factory buys 8 machines. 3 Machine A, 2 Machine B and rest Machine C. Prices of the machines are Rs 100000, Rs 80000 and Rs 45000 respectively. Calculate the average cost of these machines?
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Answer: (A) 74375

Explanation

The average cost of the machines is calculated by dividing the total cost of all machines by the total number of machines purchased.

First, determine the quantity of each type of machine: Machine A = 3 Machine B = 2 Machine C = 8 - (3 + 2) = 3

Next, calculate the total cost by summing the individual costs: Total Cost = (3 × 100000) + (2 × 80000) + (3 × 45000) Total Cost = 300000 + 160000 + 135000 Total Cost = 595000

Now, divide the total cost by the total quantity of machines: Average Cost = 595000 ÷ 8 Average Cost = 74375

1245Quantitative Aptitude
What is the equation of the line which passes through the points (2,3) and (-4,1)?
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Answer: (A) x - 3y = -7

Explanation

The slope m of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by the formula:

m = (y₂ - y₁) / (x₂ - x₁)

Substituting the given points (2, 3) and (-4, 1) into the formula:

m = (1 - 3) / (-4 - 2) = -2 / -6 = 1/3

The equation of a line with slope m passing through a point (x₁, y₁) is given by the point-slope form:

y - y₁ = m(x - x₁)

Substituting the point (2, 3) and the slope m = 1/3:

y - 3 = 1/3(x - 2)

Multiplying both sides by 3 to eliminate the fraction:

3(y - 3) = x - 2

3y - 9 = x - 2

Rearranging the terms to align the variables on one side and the constant on the other:

x - 3y = -7

1246Quantitative Aptitude
In ΔABC, the angle bisector of ∠A cuts BC at E. Find length of AC, if lengths of AB, BE and EC are 9 cm, 3.6 cm and 2.4 cm?
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Answer: (D) 6 cm

Explanation

By the Angle Bisector Theorem, the angle bisector of an angle in a triangle divides the opposite side into segments that are proportional to the adjacent sides. Therefore, in ΔABC with the angle bisector AE cutting BC at E, the relation is:

AB / AC = BE / EC

Substituting the given values:

9 / AC = 3.6 / 2.4

Simplifying the ratio of the segments:

3.6 / 2.4 = 3 / 2

Solving for AC:

9 / AC = 3 / 2

AC = (9 × 2) / 3 = 6 cm

1247Quantitative Aptitude
The effective annual rate of interest corresponding to a nominal rate of 22% per annum payable half-yearly is
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Answer: (B) 23.21 percent

Explanation

The effective annual rate of interest, E, is calculated using the formula:

E = (1 + r/n)ⁿ - 1

where r is the nominal annual rate of interest and n is the number of compounding periods per year.

Given that the nominal rate r is 22% (or 0.22) and the interest is compounded half-yearly (n = 2):

E = (1 + 0.22/2)² - 1

E = (1 + 0.11)² - 1

E = (1.11)² - 1

E = 1.2321 - 1

E = 0.2321, which is equal to 23.21%

1248Quantitative Aptitude
In a triangle, the length of the opposite side of the angle which measures 45° is 8√2 cm, what is the length of the side opposite to the angle which measures 90°?
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Answer: (A) 16 cm

Explanation

By the Law of Sines in a triangle, the ratio of the length of a side to the sine of its opposite angle is constant:

a / sin(A) = b / sin(B)

Given that the side opposite to the 45° angle has a length of 8√2 cm, we can set a = 8√2 cm, A = 45°, and B = 90°. We need to find the length of the side b opposite to the 90° angle.

Substituting the known values:

(8√2) / sin(45°) = b / sin(90°)

Since sin(45°) = 1/√2 and sin(90°) = 1, this simplifies to:

(8√2) / (1/√2) = b / 1

8√2 × √2 = b

b = 8 × 2 = 16 cm

1249Quantitative Aptitude
If the volume of a cylinder is 2156 cubic cm and height is 14 cm, find its radius?
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Answer: (D) 7 cm

Explanation

The volume V of a cylinder is calculated using the formula V = π r² h, where r is the radius and h is the height.

Given that the volume V is 2156 cubic cm and the height h is 14 cm, and taking the value of π as 22/7, the equation can be written as:

2156 = (22/7) × r² × 14

Simplifying the equation by dividing 14 by 7:

2156 = 22 × r² × 2

2156 = 44 × r²

Dividing both sides by 44 to find the value of r²:

r² = 2156 ÷ 44

r² = 49

Taking the square root on both sides yields:

r = 7 cm

1250Quantitative Aptitude
What is the value of cot 4π/3?
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Answer: (A) 1/√3

Explanation

Using the trigonometric identity cot(π + θ) = cot θ, we can rewrite the angle as:

cot(4π/3) = cot(π + π/3)

Since the angle 4π/3 lies in the third quadrant, where the cotangent function is positive, the expression simplifies to:

cot(π/3)

Because cot(π/3) is the reciprocal of tan(π/3), and tan(π/3) = √3, we get:

cot(π/3) = 1/tan(π/3) = 1/√3

Answer key

Tap a number to jump to that question.

  1. 1201D
  2. 1202B
  3. 1203B
  4. 1204D
  5. 1205B
  6. 1206D
  7. 1207C
  8. 1208D
  9. 1209D
  10. 1210D
  11. 1211D
  12. 1212D
  13. 1213C
  14. 1214B
  15. 1215D
  16. 1216D
  17. 1217B
  18. 1218B
  19. 1219A
  20. 1220A
  21. 1221C
  22. 1222A
  23. 1223B
  24. 1224D
  25. 1225B
  26. 1226D
  27. 1227C
  28. 1228B
  29. 1229B
  30. 1230D
  31. 1231B
  32. 1232B
  33. 1233B
  34. 1234B
  35. 1235D
  36. 1236D
  37. 1237B
  38. 1238D
  39. 1239C
  40. 1240A
  41. 1241B
  42. 1242C
  43. 1243B
  44. 1244A
  45. 1245A
  46. 1246D
  47. 1247B
  48. 1248A
  49. 1249D
  50. 1250A

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