Substituting the values of x³ and x into the expression x³ − 3x:
x³ − 3x = (18√3 + 14√5) − 3(√3 + √5)
= 18√3 + 14√5 − 3√3 − 3√5
= 15√3 + 11√5
52Quantitative Aptitude
A set of 10 chairs, each marked at Rs. 500, is sold for Rs. 4200. What is the percentage discount allowed?
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Answer: (C) 16%
Explanation
The total marked price of the 10 chairs is calculated by multiplying the quantity by the marked price of a single chair:
Total Marked Price = 10 × 500 = Rs. 5000
The selling price of the set is Rs. 4200.
The discount amount is the difference between the total marked price and the selling price:
Discount = 5000 - 4200 = Rs. 800
The discount percentage is calculated using the formula:
Discount Percentage = (Discount / Total Marked Price) × 100
Discount Percentage = (800 / 5000) × 100 = 16%
53Quantitative Aptitude
A regular right pyramid with an equilateral triangular base of side 16 cm is fully immersed in a cylindrical tank of radius 8 cm. Initially, the water level in the tank is 20 cm. After immersion, the water level rises to 22.5 cm. Find the perpendicular height of the pyramid.
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Answer: (A) (5π√3)/(2) cm
Explanation
The volume of the displaced water in the cylindrical tank is equal to the volume of the fully immersed regular right pyramid.
The volume of the displaced water is calculated using the formula:
V = π × R² × h
where R is the radius of the cylindrical tank and h is the rise in the water level. Given R = 8 cm and h = 22.5 - 20 = 2.5 cm, the volume is:
V = π × 8² × 2.5 = 160π cm³
The volume of a regular right pyramid is calculated using the formula:
V = ⅓ × Area of base × Height
The base of the pyramid is an equilateral triangle with side a = 16 cm. Its area is:
Area of base = (√3/4) × a² = (√3/4) × 16² = 64√3 cm²
Let H be the perpendicular height of the pyramid. Equating the volume of the pyramid to the volume of the displaced water:
⅓ × 64√3 × H = 160π
Solving for H:
H = (160π × 3) / (64√3)
H = 480π / (64√3)
H = 15π / (2√3)
H = 5π√3/2 cm
54Quantitative Aptitude
A regular right pyramid has a square base of side 14cm and a vertical height of 24cm . Find the slant height and the total surface area of the pyramid (approximately).
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Answer: (A) 25.0cm , 896cm²
Explanation
The slant height l of a regular right pyramid with a square base of side a and vertical height h is calculated using the Pythagorean theorem on the right triangle formed by the vertical height, the inradius of the base, and the slant height:
l = √(h² + (a/2)²)
Substituting h = 24 cm and a = 14 cm:
l = √(24² + (14/2)²)
l = √(576 + 7²)
l = √(576 + 49)
l = √625
l = 25 cm
The total surface area (TSA) of the pyramid is the sum of the area of the square base and the lateral surface area of the four triangular faces:
TSA = a² + 4 × (½ × a × l)
TSA = a² + 2 × a × l
The decimal representation of an irrational number is:
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Answer: (B) Non-terminating and non-repeating
Explanation
An irrational number is a real number that cannot be expressed as a fraction p/q, where p and q are integers and q is not equal to 0. Consequently, when written in decimal form, its expansion continues infinitely without ever ending and without establishing any periodic pattern or sequence of digits that repeats. This is exemplified by well-known irrational numbers such as π, which is approximately 3.14159..., or √2, which is approximately 1.41421..., where the digits continue indefinitely without establishing a repeating cycle.
56Quantitative Aptitude
A trader purchased two electronic gadgets. He earned 20% profit on the first gadget and incurred 15% loss on the second gadget. The cost price of the first gadget was 50% more than that of the second. If the net gain on the transaction was Rs. 75, find the cost price of each gadget.
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Answer: (C) Rs. 750 and Rs. 500
Explanation
Let the cost price of the second gadget be x. Since the cost price of the first gadget is 50% more than that of the second, its cost price is 1.5x.
The profit earned on the first gadget is 20% of 1.5x, which is 0.20 × 1.5x = 0.30x.
The loss incurred on the second gadget is 15% of x, which is 0.15 × x = 0.15x.
The net gain is the difference between the profit and the loss:
Net Gain = 0.30x - 0.15x = 0.15x
We are given that the net gain is Rs. 75:
0.15x = 75
x = 75 / 0.15 = 500
Thus, the cost price of the second gadget is Rs. 500, and the cost price of the first gadget is 1.5 × 500 = Rs. 750.
57Quantitative Aptitude
Two containers have mixtures of milk and water in the ratios 5 : 4 and 9 : 5 respectively. In what ratio should these mixtures be mixed to obtain a
final mixture with milk and water in the ratio 7 : 5?
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Answer: (C) 15:7
Explanation
Using the rule of alligation on the concentration of milk in the mixtures:
In the first container, the fraction of milk is M₁ = 5 / (5 + 4) = 5/9.
In the second container, the fraction of milk is M₂ = 9 / (9 + 5) = 9/14.
In the final mixture, the fraction of milk is M_f = 7 / (7 + 5) = 7/12.
The ratio in which the two mixtures must be mixed is:
Ratio = |M₂ - M_f| : |M₁ - M_f|
Multiplying both terms by their least common multiple, 252:
Ratio = (5/84) × 252 : (1/36) × 252
Ratio = 15 : 7
58Quantitative Aptitude
If 4cos A + 2sec A = 4√2, where 0°< A< 90° , then find the value of angle A.
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Answer: (B) 45°
Explanation
To find the value of angle A, we rewrite the equation by substituting sec A = 1/cos A:
4cos A + 2/cos A = 4√2
Let x = cos A. The equation becomes:
4x + 2/x = 4√2
Multiplying the entire equation by x to eliminate the fraction gives:
4x² - 4√2 x + 2 = 0
Dividing the entire equation by 2:
2x² - 2√2 x + 1 = 0
We can rewrite this quadratic equation as a perfect square:
(√2 x - 1)² = 0
Taking the square root on both sides:
√2 x - 1 = 0
x = 1/√2
Substituting x back as cos A:
cos A = 1/√2
Since A lies in the interval 0° < A < 90°, the angle whose cosine value is 1/√2 is 45°.
59Quantitative Aptitude
Which one of the following statements is INCORRECT?
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Answer: (C) Every rational number is an irrational number
Explanation
A rational number is defined as any number that can be expressed in the form p/q, where p and q are integers and q ≠ 0. An irrational number, by definition, is a real number that cannot be expressed as a ratio of two integers. Since these two sets of numbers are mutually exclusive and completely disjoint, no rational number can ever be an irrational number.
60Quantitative Aptitude
A man and a boy together earn Rs. 960 as wages for 6 days of work. The efficiency of the man is three times that of the boy. What are the daily wages of the boy?
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Answer: (C) Rs. 40
Explanation
Daily wage of the man and the boy together is:
Total wage ÷ Number of days = 960 ÷ 6 = Rs. 160
Wages are distributed in proportion to efficiency. Since the man is three times as efficient as the boy, the ratio of the man's daily wage to the boy's daily wage is 3 : 1.
Let the daily wage of the boy be x.
The daily wage of the man is 3x.
3x + x = 160
4x = 160
x = 40
The daily wage of the boy is Rs. 40.
61Quantitative Aptitude
If 2sin² A + √3cos A - 2 = 0 , then find the value of tan A.
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Answer: (B) 1 / √3
Explanation
Using the trigonometric identity sin² A = 1 - cos² A, we can substitute this into the given equation:
2(1 - cos² A) + √3 cos A - 2 = 0
Expanding and simplifying the equation:
2 - 2 cos² A + √3 cos A - 2 = 0
-2 cos² A + √3 cos A = 0
cos A (√3 - 2 cos A) = 0
This gives two possible solutions: cos A = 0 or cos A = √3/2.
If cos A = 0, then tan A is undefined.
If cos A = √3/2, we find the value of tan A using the relation:
tan A = sin A / cos A = √(1 - cos² A) / cos A
Substituting cos A = √3/2:
tan A = √(1 - 3/4) / (√3/2) = (½) / (√3/2) = 1/√3
62Quantitative Aptitude
X, Y, and Z invest Rs. 24,000, Rs. 36,000, and Rs. 60,000 respectively in a business. If the total profit after one year is Rs. 60,000, what is Y's share of the profit?
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Answer: (A) Rs. 18,000
Explanation
Profit is shared in proportion to the capital invested by each partner when the investment duration is equal.
The ratio of investments of X, Y, and Z is:
24,000 : 36,000 : 60,000 = 2 : 3 : 5
Sum of the ratio terms = 2 + 3 + 5 = 10
Y's share of the profit is calculated as:
(3 / 10) × 60,000 = 18,000
63Quantitative Aptitude
The curved surface area of a right circular cylinder is equal to its volume. Which of the following conditions is true?
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Answer: (A) r = 2
Explanation
Curved surface area of a right circular cylinder is given by the formula:
CSA = 2πrh
Volume of a right circular cylinder is given by the formula:
V = πr²h
Equating the curved surface area and the volume:
2πrh = πr²h
Dividing both sides by πrh (where r ≠ 0 and h ≠ 0):
r = 2
64Quantitative Aptitude
A circle is inscribed in a square whose side is 14cm . Find the area of the portion of the square that lies outside the circle.
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Answer: (A) 42.0cm²
Explanation
The area of the portion of the square lying outside the inscribed circle is the difference between the area of the square and the area of the circle.
For a square of side s, the area is s². Since the circle is inscribed in the square, its diameter is equal to the side of the square, which means its radius r is s/2.
Given s = 14 cm:
The radius of the circle r = 14 / 2 = 7 cm.
The area of the square is:
14² = 196 cm²
The area of the circle is:
πr² = (22/7) × 7² = 154 cm²
The area of the portion of the square outside the circle is:
196 - 154 = 42 cm²
65Quantitative Aptitude
If a² +b² +c² = 180 and ab + bc - ca = 44 , then find the value of (a - b + c)² .
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Answer: (D) 92
Explanation
The algebraic identity for the square of a trinomial is:
(x + y + z)² = x² + y² + z² + 2(xy + yz + zx)
By substituting x = a, y = -b, and z = c into the identity, we get:
(a - b + c)² = a² + (-b)² + c² + 2(a(-b) + (-b)c + ca)
(a - b + c)² = a² + b² + c² - 2(ab + bc - ca)
Substitute the given values of a² + b² + c² = 180 and ab + bc - ca = 44 into this equation:
(a - b + c)² = 180 - 2(44)
(a - b + c)² = 180 - 88
(a - b + c)² = 92
66Quantitative Aptitude
A cone and a hemisphere have equal curved surface areas and the same radius r. Find the slant height of the cone.
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Answer: (C) l = 2r
Explanation
The curved surface area of a cone with radius r and slant height l is given by the formula:
CSA_cone = πrl
The curved surface area of a hemisphere with radius r is given by the formula:
CSAₕemisphere = 2πr²
Since both solids have equal curved surface areas:
πrl = 2πr²
Dividing both sides of the equation by πr gives:
l = 2r
67Quantitative Aptitude
A certain sum is invested at compound interest, compounded annually. The interest earned in the first year is Rs. 1,800 and in the second year is Rs. 2,160. Find 50% of the principal amount.
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Answer: (A) Rs. 4,500
Explanation
The interest earned in the first year represents the simple interest on the principal amount P for one year.
First year interest (I₁) = P × r / 100 = 1,800
In the second year, the interest earned includes the interest on the principal plus the interest earned on the first year's interest.
Second year interest (I₂) = I₁ + (I₁ × r / 100)
Substitute the given values into the equation:
2,160 = 1,800 + (1,800 × r / 100)
360 = 18 × r
r = 20%
Using the rate of interest, the principal amount P is calculated as:
P × 20 / 100 = 1,800
P = 1,800 × 5 = 9,000
To find 50% of the principal amount:
50% of P = 9,000 × 0.5 = 4,500
68Quantitative Aptitude
A rectangular solid has a base diagonal of 13cm and a height of 12cm . If the area of its base is 54cm² , find the volume of the solid.
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Answer: (B) 648 cubic cm
Explanation
The volume V of a rectangular solid is given by the formula:
V = Base Area × Height
Given that the area of the base is 54 cm² and the height of the solid is 12 cm, the volume can be directly calculated by substituting these values into the formula:
V = 54 × 12 = 648 cm³
Thus, the volume of the solid is 648 cubic cm.
69Quantitative Aptitude
A painting was purchased for Rs. 12,500. It was marked at a price 32% higher than its cost price and then sold at a discount of 15% on the marked price. What was the percentage profit or loss in the transaction?
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Answer: (B) 12.2% Profit
Explanation
Correct Answer: B
We can find the overall percentage profit or loss directly using the successive percentage change formula:
Net percentage change = a + b + ab/100
Here, the markup percentage (a) is +32% and the discount percentage (b) is -15%.
Substituting these values into the formula:
Net percentage change = 32 - 15 + (32 × (-15))/100
Net percentage change = 17 - 4.8 = 12.2%
Since the net percentage change is positive, the transaction resulted in a 12.2% profit. The actual cost price of the painting is not required to calculate the percentage profit.
70Quantitative Aptitude
In a competitive examination, 55% of the candidates qualified in Reasoning, 65% qualified in Quantitative Aptitude, and 40% qualified in both subjects. What percentage of candidates qualified in at least one of the two subjects?
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Answer: (A) 80%
Explanation
By the principle of inclusion-exclusion for two sets, the percentage of candidates who qualified in at least one of the two subjects is given by the formula:
P(R ∪ Q) = P(R) + P(Q) - P(R ∩ Q)
Here, P(R) represents the percentage of candidates who qualified in Reasoning, which is 55%.
P(Q) represents the percentage of candidates who qualified in Quantitative Aptitude, which is 65%.
P(R ∩ Q) represents the percentage of candidates who qualified in both subjects, which is 40%.
Substituting these values into the formula:
P(R ∪ Q) = 55% + 65% - 40%
P(R ∪ Q) = 120% - 40% = 80%
71Quantitative Aptitude
A student scored 25% higher marks in English than in History. If the average marks obtained in the two subjects is 90, what are his marks in History?
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Answer: (B) 80
Explanation
Let the marks obtained in History be H.
The student scored 25% higher marks in English (E) than in History, which gives:
E = H + 0.25H = 1.25H
The average of the marks in both subjects is 90:
(E + H) / 2 = 90
E + H = 180
Substituting the value of E in terms of H into the equation:
1.25H + H = 180
2.25H = 180
H = 180 / 2.25
H = 80
72Quantitative Aptitude
P and Q invested Rs. 40,000 and Rs. 60,000 respectively in a business. After 4 months, R joined them with an investment of Rs. 80,000. What will be the ratio of their profits at the end of one year?
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Answer: (C) 6:9:8
Explanation
The ratio of profit sharing among partners in a business is determined by the formula: Profit = Capital × Time.
P invested Rs. 40,000 for 12 months.
Q invested Rs. 60,000 for 12 months.
R joined after 4 months, which means R invested Rs. 80,000 for 8 months (12 - 4 = 8).
The ratio of their profits at the end of one year is:
P's profit : Q's profit : R's profit = (40,000 × 12) : (60,000 × 12) : (80,000 × 8)
= 4,80,000 : 7,20,000 : 6,40,000
Dividing each part by 80,000 simplifies the ratio to:
6 : 9 : 8
73Quantitative Aptitude
The average score of 20 students in a class test was calculated as 64.5. Later, it was discovered that the marks of one student were mistakenly recorded as 55 instead of 75. What is the correct average score of the class after correction?
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Answer: (B) 65.5
Explanation
The correct average score is found using the average correction formula:
Correct Average = Incorrect Average + (Correct Value - Incorrect Value) / n
Using the given values:
Incorrect Average = 64.5
Incorrect Value = 55
Correct Value = 75
Number of students (n) = 20
Substituting these values into the formula:
Correct Average = 64.5 + (75 - 55) / 20
Correct Average = 64.5 + 20 / 20
Correct Average = 64.5 + 1
Correct Average = 65.5
74Quantitative Aptitude
A solid cube is cut into two equal cuboids by a plane passing through its mid-height. By what percentage does the total surface area increase?
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Answer: (B) 33.33%
Explanation
Let the side length of the solid cube be a.
The total surface area of the original cube is given by the formula:
Original Surface Area = 6a²
When the cube is cut into two equal cuboids by a plane passing through its mid-height, a single cut is made parallel to its base. This cut exposes two new identical surfaces, each having an area equal to the face of the cube, which is a².
The total surface area of the two resulting cuboids combined is:
New Surface Area = 6a² + 2a² = 8a²
The increase in total surface area is:
Increase = 8a² - 6a² = 2a²
The percentage increase in the total surface area is calculated as:
Percentage Increase = (Increase / Original Surface Area) × 100%
Percentage Increase = (2a² / 6a²) × 100% = (1/3) × 100% ≈ 33.33%
75Quantitative Aptitude
A shopkeeper buys 40 bags of rice at Rs. 600 per bag. He sells 25 bags at a profit of 12% and the remaining bags at a loss of 8%. Find the overall percentage profit or loss.
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Answer: (A) 4.5% Profit
Explanation
To find the overall percentage profit or loss, we can use the weighted average method. Since the cost price of each bag is the same, we can use the number of bags as weights.
The shopkeeper sells 25 bags at a 12% profit and the remaining 15 bags at an 8% loss. The ratio of the two quantities of bags is 25 to 15, which simplifies to 5 to 3.
Since the resulting value is positive, the shopkeeper makes an overall profit of 4.5%.
76Quantitative Aptitude
Rs. 15,000 is invested at the rate of 10% p.a. for 3 years at simple interest in scheme A. The amount received is then invested for 2 years at 5% p.a., compounded annually in scheme B. Find the final amount.
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Answer: (A) Rs. 21498.75
Explanation
For Scheme A, the simple interest earned on the investment is calculated using the formula:
SI = P × R × T / 100
Substituting P = ₹15,000, R = 10%, and T = 3 years:
SI = 15000 × 10 × 3 / 100 = ₹4,500
The total amount received from Scheme A (A₁) is:
A₁ = P + SI = 15000 + 4500 = ₹19,500
For Scheme B, this amount of ₹19,500 is invested for 2 years at 5% p.a. compounded annually. The final compound interest amount (A₂) is calculated using the formula:
A₂ = P₂ × (1 + R₂/100)ⁿ
A box contains Rs. 10, Rs. 5 and Rs. 2 coins in the ratio 4 : 3 : 2. The total amount in the box is Rs. 1,180. Find the number of Rs. 5 coins.
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Answer: (D) 60
Explanation
Let the number of Rs. 10, Rs. 5, and Rs. 2 coins in the box be 4x, 3x, and 2x respectively.
The total value of these coins is calculated as:
Total Value = (10 × 4x) + (5 × 3x) + (2 × 2x)
Total Value = 40x + 15x + 4x
Total Value = 59x
Given that the total amount in the box is Rs. 1,180, we can write:
59x = 1180
x = 1180 ÷ 59
x = 20
The number of Rs. 5 coins is 3x:
Number of Rs. 5 coins = 3 × 20 = 60
78Quantitative Aptitude
A and B invest Rs. 24,000 and Rs. 36,000 respectively in a business. At the end of the year, B receives Rs. 1200 more than A as profit. What is the total profit?
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Answer: (B) Rs. 6000
Explanation
In a partnership, when the investment duration is the same for all partners, the profits are distributed in the ratio of their initial investments.
The ratio of the investments of A and B is:
Ratio = 24,000 : 36,000 = 2 : 3
Let the profit share of A be 2x and that of B be 3x.
The difference between their profit shares is:
3x - 2x = x
According to the question, B receives Rs. 1200 more than A, which means:
x = 1200
The total profit is the sum of the profit shares of A and B:
Total Profit = 2x + 3x = 5x
Substituting the value of x:
Total Profit = 5 × 1200 = 6000
Thus, the total profit is Rs. 6000.
79Quantitative Aptitude
If sin θ + sin² θ = 1 , then find the value of cos² θ + cos⁴ θ .
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Answer: (B) 1
Explanation
The given equation is sin θ + sin² θ = 1.
By rearranging the terms, we get:
sin θ = 1 - sin² θ
Using the fundamental trigonometric identity sin² θ + cos² θ = 1, we know that:
1 - sin² θ = cos² θ
Therefore:
sin θ = cos² θ
Squaring both sides of this equation yields:
sin² θ = cos⁴ θ
We need to find the value of cos² θ + cos⁴ θ. Substituting the values of cos² θ and cos⁴ θ in terms of sin θ into this expression gives:
cos² θ + cos⁴ θ = sin θ + sin² θ
Since it is given that sin θ + sin² θ = 1, we have:
cos² θ + cos⁴ θ = 1
80Quantitative Aptitude
How many perfect squares lie between 5,000 and 15,000 (both excluded)?
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Answer: (B) 52
Explanation
To find the number of perfect squares n² between 5000 and 15000, we find the range of the integer n such that:
5000 < n² < 15000
Taking the square root of the inequality:
√5000 < n < √15000
Since n must be an integer, the values of n range from the first integer greater than 70.71 to the last integer less than 122.47.
Smallest integer n = 71
Largest integer n = 122
To find the total number of integers in this range, we use the formula:
Number of terms = (Largest term - Smallest term) + 1
Number of terms = 122 - 71 + 1 = 52
81Quantitative Aptitude
If sin p × cos(90° − p) = 1/4, where 0° < p < 90°, then find the value of cot²2p + cos²3p.
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Answer: (B) 1/3
Explanation
Using the trigonometric identity cos(90° − p) = sin p, the given equation simplifies to:
sin p × sin p = 1/4
sin²p = 1/4
Since 0° < p < 90°, taking the positive square root gives:
sin p = 1/2
This yields p = 30°.
Now, substitute p = 30° into the required expression:
Substituting the standard trigonometric values cot 60° = 1/√3 and cos 90° = 0:
(1/√3)² + 0² = 1/3 + 0 = 1/3
82Quantitative Aptitude
A person travels from City A to City B, a distance of 300km . He travels the first 100km at 50km / h , the next 100km at 40km / h , and the remaining distance at xkm / h . If the overall average speed is 50km / h , find the value of x .
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Answer: (C) 66 2/3 km / h
Explanation
The average speed of a journey is given by the formula:
Average Speed = Total Distance ÷ Total Time
The total distance is 300 km, and the overall average speed is 50 km/h.
The journey is split into three equal parts of 100 km each:
Time taken for the first 100 km at 50 km/h:
t₁ = 100 / 50 = 2 hours
Time taken for the next 100 km at 40 km/h:
t₂ = 100 / 40 = 2.5 hours
Time taken for the remaining 100 km at x km/h:
t₃ = 100 / x hours
The total time is:
Total Time = t₁ + t₂ + t₃ = 2 + 2.5 + 100/x = 4.5 + 100/x hours
Using the average speed formula:
50 = 300 / (4.5 + 100/x)
A person invested Rs. 25,000 each in two schemes for 2 years. One scheme offers 12% p.a. simple interest and the other offers 12% p.a. compound interest, compounded annually. Find the difference between the interest earned from both schemes.
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Answer: (A) Rs. 360
Explanation
The difference between compound interest and simple interest for a period of 2 years is given by the formula P(R/100)². Substituting P = Rs. 25,000 and R = 12% into the formula yields 25000 * (12/100)² = 25000 * 0.0144 = Rs. 360.
84Quantitative Aptitude
A man travels a total distance of 600km . He covers 60% of the distance by train at 75km / h and the remaining distance by bus at 50km / h . Find the approximate average speed of the whole journey.
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Answer: (B) 62.5 km / h
Explanation
Average speed of a journey is given by the formula:
Average Speed = Total Distance ÷ Total Time
First, the distance covered by train is 60% of 600 km, which is:
d₁ = 0.60 × 600 = 360 km
The time taken by train at a speed of 75 km/h is:
t₁ = 360 ÷ 75 = 4.8 hours
The remaining distance covered by bus is 40% of 600 km, which is:
d₂ = 0.40 × 600 = 240 km
The time taken by bus at a speed of 50 km/h is:
t₂ = 240 ÷ 50 = 4.8 hours
The total time for the entire journey is:
T = t₁ + t₂ = 4.8 + 4.8 = 9.6 hours
Using the average speed formula:
Average Speed = 600 ÷ 9.6 = 62.5 km/h
85Quantitative Aptitude
A mixture containing 30% alcohol is mixed with another mixture containing x% alcohol in the ratio 2:3 . If the resulting mixture contains 24% alcohol, find the value of x .
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Answer: (B) 20
Explanation
Using the weighted average formula, the percentage of alcohol in the final mixture is calculated as (2 * 30 + 3 * x) / (2 + 3) = 24. Solving the equation 60 + 3x = 120 gives 3x = 60, which yields x = 20.
86Quantitative Aptitude
A laptop is marked at Rs. 40,000. A customer gets a discount of 20% . Since he makes full payment in cash, he gets an additional 5% discount. How much does he pay?
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Answer: (A) Rs. 30,400
Explanation
The final price after successive discounts of d₁% and d₂% on the marked price is given by the formula:
Final Price = Marked Price × (1 - d₁/100) × (1 - d₂/100)
Given that the marked price is Rs. 40,000, the first discount is 20%, and the additional cash discount is 5%:
Final Price = 40,000 × (1 - 0.20) × (1 - 0.05)
Final Price = 40,000 × 0.80 × 0.95
Final Price = 32,000 × 0.95
Final Price = 30,400
87Quantitative Aptitude
The selling price of a wall clock is Rs. 1,710, after allowing a discount of 5% . What is the marked price of the clock?
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Answer: (C) Rs. 1,800
Explanation
The relation between the selling price, marked price, and discount percentage is given by the formula:
A class consists of 100 students with an average age of 18 years. Later, some new students join the class. As a result, the average age becomes 17.6 years. If the average age of the new students is 16 years, find the number of students who joined later.
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Answer: (B) 25
Explanation
Using the mixture and alligation method, the ratio of the number of initial students to the number of new students is determined by the differences between their individual average ages and the combined average age.
Difference for initial students: |18 - 17.6| = 0.4
Difference for new students: |16 - 17.6| = 1.6
The ratio of the number of initial students to the number of new students is 1.6 : 0.4, which simplifies to 4 : 1.
Since the initial number of students is 100, representing 4 parts of the ratio, 1 part represents the number of new students:
100 ÷ 4 = 25
89Quantitative Aptitude
In a college survey, 60% of the students like English, 50% like Hindi, and 35% like both English and Hindi. Among the remaining students, 20% prefer Sanskrit, while the rest have no preference. If the total number of students surveyed is 1000, how many students have no preference for any of the three subjects?
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Answer: (B) 200
Explanation
The percentage of students who like English or Hindi or both is calculated using the set union formula:
Percentage = E + H - (E ∩ H)
Substituting the given percentages:
Percentage = 60% + 50% - 35% = 75%
The remaining percentage of students who do not like English or Hindi is:
Remaining percentage = 100% - 75% = 25%
For a total of 1000 surveyed students, the number of remaining students is:
Remaining students = 25% of 1000 = 250
Among these 250 students, 20% prefer Sanskrit, which means the remaining 80% have no preference for any of the three subjects.
No preference = 80% of 250 = 0.80 × 250 = 200
90Quantitative Aptitude
A piece of work is to be completed in 240 days. Due to strikes, only 75% of the days were actually worked. If the work done per working day remains constant, by what percentage should the daily work be increased to complete the work on time?
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Answer: (C) 33.33%
Explanation
The total work done is the product of the daily work rate and the number of working days:
Work = Rate × Time
Since the total work to be completed remains constant, the required daily work rate is inversely proportional to the number of working days:
Rate ∝ 1 / Time
Let the original number of days be Tₒld and the new number of days actually worked due to strikes be Tₙew.
Tₙew = 75% of Tₒld = 0.75 Tₒld
The percentage increase in the daily work rate is:
Percentage Increase = ((Rₙew - Rₒld) / Rₒld) × 100%
Percentage Increase = (4/3 - 1) × 100% = 1/3 × 100% = 33.33%
91Quantitative Aptitude
Which of the following numbers is NOT a perfect square?
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Answer: (D) 750
Explanation
Correct Answer: D
A perfect square cannot end with an odd number of zeros. The number 750 ends with a single zero, which mathematically prevents it from being a perfect square.
Furthermore, the square root of 750 is √750 ≈ 27.386, which is not an integer. The consecutive integers 27 and 28 have squares of 27² = 729 and 28² = 784. Since 750 lies strictly between these two consecutive perfect squares, it is not a perfect square.
92Quantitative Aptitude
A shopkeeper bought 5 identical chairs for a total cost of Rs. 7,500. He sold three chairs at a gain of 20% each and the remaining two chairs at a loss of 10% each. What is his overall profit or loss percentage?
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Answer: (A) 8% Profit
Explanation
The overall profit or loss percentage on identical items depends only on the number of items and their respective profit or loss rates, making the total cost of ₹7,500 redundant for this calculation.
Using the weighted average formula:
Overall Percentage = (n₁ × r₁ + n₂ × r₂) / (n₁ + n₂)
Here, n₁ = 3 chairs with a gain rate r₁ = +20%, and n₂ = 2 chairs with a loss rate r₂ = -10%.
Since the result is positive, it represents an overall profit of 8%.
93Quantitative Aptitude
If (a - b) = 6 and (a³ - b³) = 936 , then find the value of (a × b) .
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Answer: (D) 40
Explanation
Using the algebraic identity:
a³ - b³ = (a - b)³ + 3ab(a - b)
Substitute the given values (a - b) = 6 and (a³ - b³) = 936 into the formula:
936 = 6³ + 3ab(6)
Simplify and solve for ab:
936 = 216 + 18ab
18ab = 720
ab = 40
94Quantitative Aptitude
A ladder of length 50 ~m is leaning against a vertical wall and makes an angle θ with the ground such that sin θ = 48 / 50 . Find the horizontal distance of the foot of the ladder from the wall.
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Answer: (A) 14 ~m
Explanation
In a right-angled triangle formed by the ladder, the wall, and the ground, the length of the ladder represents the hypotenuse (h), which is 50 m.
The vertical height (y) of the wall where the ladder touches is given by:
y = h × sin θ = 50 × (48/50) = 48 m
Using the Pythagorean theorem, the horizontal distance (x) of the foot of the ladder from the wall is:
x² + y² = h²
x² + 48² = 50²
x² + 2304 = 2500
x² = 2500 - 2304
x² = 196
x = √196 = 14 m
95Quantitative Aptitude
Two partners, P and Q, invest in a business in the ratio 3 : 7. If Q's share in the profit is Rs. 1400, what is the total profit?
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Answer: (B) 2000
Explanation
In a business partnership, profits are shared in the same ratio as the investments of the partners when the time period is constant.
Investment ratio of P to Q = 3 : 7
Let the shares of P and Q in the profit be 3x and 7x respectively.
The share of Q is given as ₹1400.
7x = 1400
x = 200
The total profit is the sum of P's and Q's shares:
Total profit = 3x + 7x = 10x
Substituting the value of x:
Total profit = 10 × 200 = 2000
96Quantitative Aptitude
X, Y, and Z invest Rs. 15,000, Rs. 25,000, and Rs. 10,000 respectively in a business for the same period. What percentage of the total profit will Y get?
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Answer: (C) 50%
Explanation
When the time period of investment is the same for all partners, the profit sharing ratio is directly proportional to the ratio of their investments.
Y's percentage share of the total profit = (Y's investment / Total investment) × 100
Y's percentage share of the total profit = (25,000 / 50,000) × 100 = 50%
97Quantitative Aptitude
A container contains a mixture of two liquids, A and B, in the proportion 7 : 5. If 9 liters of the mixture is replaced by 9 liters of Liquid B, then the ratio of the two liquids becomes 7 : 9. How much of liquid A was there in the container initially?
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Answer: (C) 21 litres
Explanation
Using the volume conservation method, let the total volume of the container be V.
Initially, the ratio of liquid A to liquid B is 7 : 5, which means the fraction of liquid A in the mixture is 7/12.
When 9 liters of the mixture is removed and replaced by 9 liters of liquid B, the total volume of the mixture remains V. The quantity of liquid A in the new mixture is entirely due to the remaining V - 9 liters of the original mixture.
The fraction of liquid A in the final mixture is 7 / (7 + 9) = 7/16.
Equating the quantity of liquid A before and after the replacement:
(V - 9) × 7/12 = V × 7/16
Dividing both sides by 7:
(V - 9) / 12 = V / 16
Cross-multiplying to solve for V:
16(V - 9) = 12V
4(V - 9) = 3V
4V - 36 = 3V
V = 36 liters
The total initial volume of the mixture was 36 liters.
The initial quantity of liquid A is:
36 × 7/12 = 21 liters