SSC CHSL2022Quantitative AptitudePage 8 of 10

SSC CHSL Tier 1 2022 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 351–400 of 480, each with the correct answer and a step-by-step explanation.

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351Quantitative Aptitude
Instead of increasing a number successively by 20 percent and 30 percent, it is decreased by 22 percent. Resultant value is what percentage of the required correct value?
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Answer: (D) 50 percent

Explanation

Let the original number be 100.

The required correct value is obtained by successively increasing the number by 20% and 30%. Using the successive percentage change formula: Net percentage increase = a + b + (a × b)/100

Substituting a = 20 and b = 30: Net increase = 20 + 30 + (20 × 30)/100 = 56% Required correct value = 100 + 56 = 156

The actual resultant value is obtained by decreasing the original number by 22%: Resultant value = 100 - 22 = 78

The percentage of the required correct value that the resultant value represents is: (Resultant value ÷ Required correct value) × 100 Substituting the calculated values: (78 ÷ 156) × 100 = ½ × 100 = 50%

352Quantitative Aptitude
On Selling a book at 8 / 15 of the marked price there is a loss of 20 percent. What will be the ratio of marked price and cost price of the book?
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Answer: (D) 3:2

Explanation

Let the marked price be MP and the cost price be CP.

The selling price (SP) is given as 8/15 of the marked price: SP = (8/15) × MP

Since there is a loss of 20%, the selling price is also equal to 80% of the cost price: SP = (80/100) × CP = (4/5) × CP

Equating the two expressions for SP: (8/15) × MP = (4/5) × CP

To find the ratio of marked price to cost price, we solve for MP / CP: MP / CP = (4/5) × (15/8) = 3/2

353Quantitative Aptitude
In a Δ RST , Z is a point on side ST and SZ = ZT . If ∠ RZS = 90 degree and RS = 10 cm, then what is the value of RT ?
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Answer: (B) 10 cm

Explanation

In triangle RST, Z is a point on side ST such that SZ = ZT, which makes RZ the median to side ST. Since angle RZS = 90°, RZ is also the altitude to side ST.

In right triangles RZS and RZT, RZ is a common side, angle RZS = angle RZT = 90°, and SZ = ZT. By Side-Angle-Side congruence, triangle RZS is congruent to triangle RZT.

Since corresponding parts of congruent triangles are equal, the side RS must equal RT. Given that RS = 10 cm, the length of RT is also 10 cm.

354Quantitative Aptitude
If x² + y² = 29 and x - y = 3 , then what is the value of 4xy ?
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Answer: (A) 40

Explanation

Using the algebraic identity: (x - y)² = x² + y² - 2xy

Substitute the given values x² + y² = 29 and x - y = 3 into the identity: 3² = 29 - 2xy 9 = 29 - 2xy

Rearranging the terms to find 2xy: 2xy = 29 - 9 2xy = 20

Multiplying both sides by 2 gives the value of 4xy: 4xy = 2 × 20 = 40

355Quantitative Aptitude
Two trains, one 125 metres and the other 375 metres long are running in opposite directions on parallel tracks, at the speed of 81 km/hr and 63 km/hr respectively. How much time will they take to cross each other?
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Answer: (C) 12.5 seconds

Explanation

When two objects move in opposite directions, their relative speed is the sum of their individual speeds.

Relative speed = 81 + 63 = 144 km/hr

To convert this speed into meters per second, multiply by 5/18: Relative speed = 144 × 5/18 = 40 m/s

The total distance that needs to be covered for the two trains to completely cross each other is the sum of their individual lengths.

Total distance = 125 + 375 = 500 meters

Using the formula for time, Time = Distance / Speed: Time = 500 / 40 = 12.5 seconds

356Quantitative Aptitude
If a⁴ + (1)/(a⁴) = 194 , then what is the value of (a⁶ + 1)/(a³) ?
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Answer: (C) 52

Explanation

To find the value of (a⁶ + 1)/a³, we can rewrite the expression as a³ + 1/a³.

We are given: a⁴ + 1/a⁴ = 194

Add 2 to both sides of the equation to form a perfect square: a⁴ + 1/a⁴ + 2 = 196 (a² + 1/a²)² = 196 a² + 1/a² = √196 = 14

Again, add 2 to both sides of this equation: a² + 1/a² + 2 = 16 (a + 1/a)² = 16 a + 1/a = √16 = 4

Now, using the algebraic identity for the sum of cubes: a³ + 1/a³ = (a + 1/a)³ - 3(a + 1/a)

Substitute the value of (a + 1/a) = 4 into the identity: a³ + 1/a³ = 4³ - 3(4) a³ + 1/a³ = 64 - 12 = 52

357Quantitative Aptitude
If A alone can complete a work in 20 days and B alone can complete the same work in 30 days, then which of the following statement(s) is/are correct? I. Ratio of efficiency of A and B is 3:2. II. Working together A and B can complete the same work in 12 days.
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Answer: (B) Both I and II

Explanation

Efficiency is inversely proportional to the time taken to complete a work. Since A takes 20 days and B takes 30 days, the ratio of their efficiencies is 30:20, which simplifies to 3:2. This confirms statement I is correct.

The time taken by both working together is calculated using the formula T = (x × y) / (x + y), where x and y are the individual days taken. Substituting the values gives T = (20 × 30) / (20 + 30) = 600 / 50 = 12 days. This confirms statement II is correct.

358Quantitative Aptitude
The length of rectangular sheet of paper is 24 cm more than the breadth and perimeter of the rectangular sheet is 128 cm. Find the length of the rectangular sheet.
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Answer: (B) 44 cm

Explanation

The perimeter P of a rectangle is given by the formula P = 2(l + b), where l is the length and b is the breadth.

According to the given conditions: l = b + 24, which can be rewritten as b = l - 24

The perimeter is 128 cm: 2(l + b) = 128 l + b = 64

Substituting b = l - 24 into the equation: l + (l - 24) = 64 2l - 24 = 64 2l = 88 l = 44 cm

359Quantitative Aptitude
Rs. 6000 is lent at the annual rate of 10 percent for 2 years. Which of the following is statement(s) is/are correct? I. Simple interest to be received on this sum is Rs. 1200 II. Compound Interest (compounding annually) to be received on this sum is Rs. 1260
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Answer: (B) Both statement I and II are correct

Explanation

Simple interest is calculated using the formula: Simple Interest = (Principal × Rate × Time) / 100 Substituting the given values: Simple Interest = (6000 × 10 × 2) / 100 = 1200 Thus, Statement I is correct.

Compound interest is calculated using the formula: Amount = Principal × (1 + Rate / 100)ᵀⁱᵐᵉ Substituting the given values: Amount = 6000 × (1 + 10 / 100)² = 6000 × (1.1)² = 6000 × 1.21 = 7260 Compound Interest = Amount - Principal = 7260 - 6000 = 1260 Thus, Statement II is also correct.

360Quantitative Aptitude
If tan θ + cot θ = 2 , then what is the value of tan θ - cot θ ?
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Answer: (A) 0

Explanation

Given the trigonometric relation tan θ + cot θ = 2. Since cot θ is the reciprocal of tan θ, this relation can be written as:

tan θ + 1/tan θ = 2

Multiplying the entire equation by tan θ yields the quadratic equation:

tan² θ - 2 tan θ + 1 = 0

This is a perfect square trinomial:

(tan θ - 1)² = 0

Solving for tan θ gives:

tan θ = 1

Since tan θ = 1, then cot θ = 1/tan θ = 1.

Substituting these values into the required expression:

tan θ - cot θ = 1 - 1 = 0

361Quantitative Aptitude
If (a - b) = 5 and ab = 150 then what is the value of (a³ - b³)
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Answer: (C) 2375

Explanation

The algebraic identity for the difference of two cubes is: a³ - b³ = (a - b)³ + 3ab(a - b)

Substitute the given values a - b = 5 and ab = 150 into this formula: a³ - b³ = 5³ + 3 × 150 × 5 a³ - b³ = 125 + 2250 a³ - b³ = 2375

362Quantitative Aptitude
A wheel makes 500 revolutions in covering a distance of 44 km. Find the radius of the wheel.
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Answer: (A) 14m

Explanation

The total distance covered by a wheel is the product of the number of revolutions and the circumference of the wheel.

Distance = Number of revolutions × 2πr

Here, the total distance is 44 km, which is equal to 44000 m. The number of revolutions is 500.

44000 = 500 × 2 × (22/7) × r 44000 = 1000 × (22/7) × r 44 = (22/7) × r r = 44 × 7 / 22 r = 14 m

363Quantitative Aptitude
Length of chord MN is 40 cm. Distance of chord MN from the centre is 15 cm. What will be the radius of this circle?
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Answer: (D) 25cm

Explanation

A perpendicular drawn from the center of a circle to a chord bisects the chord.

If we draw a perpendicular from the center O to the chord MN at point D, then D bisects MN. Therefore: MD = MN / 2 = 40 / 2 = 20 cm

The perpendicular distance from the center to the chord is OD = 15 cm.

In the right-angled triangle ODM, the radius r (which is the hypotenuse OM) is calculated using the Pythagorean theorem: r² = OD² + MD² r² = 15² + 20² r² = 225 + 400 r² = 625 r = √625 = 25 cm

Alternatively, using the standard Pythagorean triplet (3, 4, 5) scaled by a factor of 5 directly gives the sides as (15, 20, 25), where 25 cm is the hypotenuse and represents the radius.

364Quantitative Aptitude
What is cosec90°/(1 - cos² 60°)
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Answer: (B) 4/3

Explanation

Using the standard trigonometric values: cosec 90° = 1 cos 60° = ½

Substituting these values into the given expression: cosec 90° / (1 - cos² 60°) = 1 / (1 - (½)²)

Simplifying the denominator: 1 - (½)² = 1 - ¼ = ¾

Now, evaluating the fraction: 1 / (¾) = 4/3

365Quantitative Aptitude
Find the value of 1200 + 15× [45 + (17 - 2)] of 2 + [-2(1 + 2)]
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Answer: (D) 474

Explanation

To find the value of the given expression, we use the BODMAS rule (Brackets, Of, Division, Multiplication, Addition, Subtraction), where the division symbol ÷ is used in place of the misprinted + signs in the first two terms:

1200 ÷ 15 × [45 ÷ (17 - 2)] of 2 + [-2(1 + 2)]

First, solve the innermost round brackets: 17 - 2 = 15 1 + 2 = 3

Substitute these back into the expression: 1200 ÷ 15 × [45 ÷ 15] of 2 + [-2(3)]

Next, solve the square brackets: 45 ÷ 15 = 3 -2 × 3 = -6

The expression becomes: 1200 ÷ 15 × 3 of 2 + [-6]

Now, evaluate the "of" operator, which has higher precedence than division and multiplication: 3 of 2 = 3 × 2 = 6

This simplifies the expression to: 1200 ÷ 15 × 6 - 6

Perform the division and multiplication operations from left to right: 1200 ÷ 15 = 80 80 × 6 = 480

Finally, perform the subtraction: 480 - 6 = 474

366Quantitative Aptitude
The table given below shows the number of male teacher and female teachers in 5 schools. | Schools | Male teachers | Female teachers | | :--- | :--- | :--- | | L | 160 | 180 | | M | 180 | 170 | | N | 170 | 120 | | P | 150 | 110 | | Q | 130 | 130 | Which of the following statement is correct? I. The number of male teachers in school L is 135.44 percent of the number of female teachers in school P. II. The ratio of number of female teachers in M and N together to the number of male teachers in N and P together is 29:32.
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Answer: (A) Only II

Explanation

To evaluate Statement I, calculate the percentage of male teachers in school L with respect to female teachers in school P: Percentage = (160 ÷ 110) × 100% = 145.45% This makes Statement I incorrect.

To evaluate Statement II, find the sum of female teachers in schools M and N: 170 + 120 = 290 Next, find the sum of male teachers in schools N and P: 170 + 150 = 320 The ratio of these two sums is: 290 : 320 = 29 : 32 This makes Statement II correct.

367Quantitative Aptitude
In the Lok Sabha election, Party A got 30% of the total votes. Party B got 25% of the total votes. Party C got the remaining votes and they got 9000 more votes than Party A. Find the number of votes Party B got.
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Answer: (D) 15000

Explanation

Let the total number of votes polled in the election be 100%.

The percentage of votes received by Party A is 30% and by Party B is 25%.

The remaining votes received by Party C is equal to 100% - (30% + 25%) = 45%.

The difference in percentage of votes between Party C and Party A is 45% - 30% = 15%.

According to the question, Party C got 9000 more votes than Party A. Therefore, 15% of the total votes corresponds to 9000.

Using the unitary method, 1% of the total votes is 9000 ÷ 15 = 600.

The number of votes received by Party B, which is 25% of the total votes, is 25 × 600 = 15000.

368Quantitative Aptitude
If sin x = 1 / 2 , then find the value of (sec²x + cos e²x) - (tan²x + cot²x) .
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Answer: (D) 2

Explanation

The given expression can be rearranged as follows: (sec²x + cosec²x) - (tan²x + cot²x) = (sec²x - tan²x) + (cosec²x - cot²x)

Using the standard trigonometric identities: sec²x - tan²x = 1 cosec²x - cot²x = 1

Substituting these identities into the equation: 1 + 1 = 2

369Quantitative Aptitude
How many prime numbers are there between 20 and 50?
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Answer: (D) 7

Explanation

To find the number of prime numbers between 20 and 50, we list the numbers in this range that have exactly two distinct factors, namely 1 and the number itself.

The prime numbers in this range are 23, 29, 31, 37, 41, 43, and 47.

Counting these values, we find there are exactly 7 prime numbers between 20 and 50. All other numbers in this range are composite because they can be factored further by prime numbers such as 2, 3, 5, or 7.

370Quantitative Aptitude
If 2p + 5q = 12 and pq = 3 , find the value of 4p² + 25q² .
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Answer: (C) 84

Explanation

The algebraic identity for the square of a binomial is: (a + b)² = a² + b² + 2ab

By setting a = 2p and b = 5q, the expansion becomes: (2p + 5q)² = (2p)² + (5q)² + 2(2p)(5q) (2p + 5q)² = 4p² + 25q² + 20pq

Substitute the given values, 2p + 5q = 12 and pq = 3, into this equation: 12² = 4p² + 25q² + 20(3) 144 = 4p² + 25q² + 60

Rearranging the terms to solve for the required expression: 4p² + 25q² = 144 - 60 4p² + 25q² = 84

371Quantitative Aptitude
In a triangle ABC, AB = 6cm , BC = 11cm . How many integral values of AC can be possible?
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Answer: (D) 11

Explanation

Correct Answer: D

According to the triangle inequality theorem, the length of any side of a triangle must be strictly greater than the absolute difference of the other two sides and strictly less than their sum.

Let the length of AC be x.

|BC - AB| < x < BC + AB

Substituting the given values AB = 6 cm and BC = 11 cm into the inequality:

|11 - 6| < x < 11 + 6 5 < x < 17

The possible integral values for x are the integers strictly between 5 and 17, which are 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, and 16.

The number of such integral values is calculated as: (17 - 5) - 1 = 11

Alternatively, using the direct formula for the number of possible integer values of the third side when two sides are known: Number of values = 2 × min(side1, side2) - 1 Number of values = 2 × 6 - 1 = 11

372Quantitative Aptitude
The table given below shows the cost price and value of profit of 6 articles. | Articles | Cost price | Profit | | :--- | :--- | :--- | | D | 700 | 200 | | E | 600 | 150 | | F | 400 | 300 | | G | 500 | 400 | | H | 300 | 250 | | I | 800 | 350 | Which of the following statement is NOT correct? I. The profit of D, E and F is 30.63 percent of the cost price of G, H and I. II. The ratio of total cost price to the total profit is 1 : 2.
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Answer: (A) Both I and II

Explanation

To determine which statements are incorrect, we evaluate each statement individually.

For Statement I, we calculate the total profit of D, E, and F, which is 200 + 150 + 300 = 650. The total cost price of G, H, and I is 500 + 300 + 800 = 1600. The required percentage is (650 / 1600) × 100 = 40.625%. Since the statement claims this value is 30.63%, Statement I is incorrect.

For Statement II, the total cost price of all articles is 700 + 600 + 400 + 500 + 300 + 800 = 3300. The total profit of all articles is 200 + 150 + 300 + 400 + 250 + 350 = 1650. The ratio of total cost price to total profit is 3300 : 1650, which simplifies to 2 : 1. Since the statement claims the ratio is 1 : 2, Statement II is incorrect.

373Quantitative Aptitude
A family consists of a father, mother and son. The ratio of their present ages is 8 : 5 : 2 and the present age of the father is 48 years. What will be the average age of family after 3 years?
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Answer: (C) 33 years

Explanation

Let the present ages of the father, mother, and son be represented by 8x, 5x, and 2x respectively.

Since the present age of the father is 48 years: 8x = 48 x = 6

Using this value of x, the present ages of the mother and the son are: Mother = 5 × 6 = 30 years Son = 2 × 6 = 12 years

The sum of their present ages is 48 + 30 + 12 = 90 years.

The present average age of the family of 3 members is 90 / 3 = 30 years.

Since the age of each of the 3 members increases by 3 years after 3 years, the average age of the family also increases by exactly 3 years.

Average age after 3 years = 30 + 3 = 33 years.

374Quantitative Aptitude
What is the equivalent single discount of two successive discounts of 12% and 10% ?
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Answer: (D) 20.8 percent

Explanation

The equivalent single discount of two successive discounts of a% and b% is calculated using the formula:

Equivalent Discount = a + b - (a × b)/100

Substituting the given values, a = 12 and b = 10:

Equivalent Discount = 12 + 10 - (12 × 10)/100 Equivalent Discount = 22 - 120/100 Equivalent Discount = 22 - 1.2 Equivalent Discount = 20.8%

375Quantitative Aptitude
Janki purchased 10 dozens of corn at the rate of Rs.180 per dozen. She sold each corn at the rate of Rs.22. What was her percent profit?
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Answer: (A) 46.6 percent

Explanation

Cost price (CP) of 1 dozen corns = Rs. 180

Since 1 dozen contains 12 items, the CP of 1 corn = 180 / 12 = Rs. 15

Selling price (SP) of 1 corn = Rs. 22

The formula for profit percentage is: Profit% = ((SP - CP) / CP) × 100

Substituting the values: Profit% = ((22 - 15) / 15) × 100 Profit% = (7 / 15) × 100 Profit% = 700 / 15 ≈ 46.6%

376Quantitative Aptitude
What is the value of x² + 4y² + z² - 4xy + 4yz - 2xz?
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Answer: (C) (2y - x + z)²

Explanation

The given algebraic expression is x² + 4y² + z² - 4xy + 4yz - 2xz.

This expression can be factored using the standard algebraic identity: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Comparing the terms of the given expression with the identity, we have: a² = (-x)² = x² b² = (2y)² = 4y² c² = z² = z²

The product terms are: 2ab = 2(-x)(2y) = -4xy 2bc = 2(2y)(z) = 4yz 2ca = 2(z)(-x) = -2xz

Substituting these values into the identity gives: (-x + 2y + z)² = x² + 4y² + z² - 4xy + 4yz - 2xz

Rearranging the terms inside the square, we get: (2y - x + z)²

377Quantitative Aptitude
The area (in cm²) of biggest circle that could be drawn in a square of side 18 cm is:
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Answer: (B) 81π

Explanation

The largest circle that can be inscribed inside a square of side s has a diameter d equal to the side length of the square.

Given the side of the square s = 18 cm, the diameter of the largest circle is: d = 18 cm

The radius r of this circle is half of its diameter: r = d / 2 = 18 / 2 = 9 cm

The area A of a circle is calculated using the formula: A = πr²

Substituting the radius into the formula yields: A = π × 9² = 81π cm²

378Quantitative Aptitude
If in the sales department of a company, the average salary per employee is Rs.350, average salary of 10 senior employees is Rs.450 per employee and average salary of remaining staff is Rs.250 per employee, then what is the total number of employees working in the sales department?
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Answer: (B) 20

Explanation

Using the method of alligation, the ratio of senior employees to the remaining staff can be determined by comparing their average salaries to the overall average salary.

The difference between the average salary of senior employees and the overall average is 450 - 350 = 100. The difference between the overall average and the average salary of the remaining staff is 350 - 250 = 100.

Since the differences are equal, the ratio of senior employees to the remaining staff is 100:100, which simplifies to 1:1.

Given that there are 10 senior employees, there must also be 10 remaining staff.

Therefore, the total number of employees working in the sales department is 10 + 10 = 20.

379Quantitative Aptitude
Ram needs to reach the examination center in 6 hours, the journey itself is 250 km. If Ram has covered (3/5)th of the distance in 3.5 hours then what is the speed required to reach the destination 30 minutes early than the required time ?
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Answer: (A) 50 km/h

Explanation

To find the required speed, we determine the remaining distance and the remaining time to reach the destination 30 minutes early.

Total distance is 250 km. Ram covers 3/5 of this distance: Distance covered = 3/5 × 250 = 150 km Remaining distance = 250 - 150 = 100 km

The total time allowed to reach the center is 6 hours. Since Ram wants to arrive 30 minutes (0.5 hours) early, his target total time is: Target total time = 6 - 0.5 = 5.5 hours

He has already traveled for 3.5 hours, so the remaining time available is: Remaining time = 5.5 - 3.5 = 2 hours

The required speed to cover the remaining distance of 100 km in 2 hours is: Required speed = Remaining distance / Remaining time = 100 / 2 = 50 km/h

380Quantitative Aptitude
P, Q and R are partners and invest in a business. P invests 1/5th of total investments and Q invests 1/4th of the total investments. What is the ratio of investments of P, Q and R respectively?
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Answer: (B) 4:5:11

Explanation

To find the ratio of investments, assume the total investment is the least common multiple of the denominators 5 and 4, which is 20 units.

P's investment = 1/5 of 20 = 4 units

Q's investment = 1/4 of 20 = 5 units

R's investment = 20 - (4 + 5) = 11 units

The ratio of the investments of P, Q, and R is 4:5:11.

381Quantitative Aptitude
What is the value of (a + b + c)!(a - b)² + (b - c)² + (c - a)² ?
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Answer: (B) 2a³ + 2b³ + 2c³ - 6abc

Explanation

The given expression is (a + b + c)[(a - b)² + (b - c)² + (c - a)²].

Expanding the terms inside the square brackets: (a - b)² + (b - c)² + (c - a)² = a² - 2ab + b² + b² - 2bc + c² + c² - 2ca + a² = 2a² + 2b² + 2c² - 2ab - 2bc - 2ca = 2(a² + b² + c² - ab - bc - ca)

Multiplying this result by (a + b + c) gives: 2(a + b + c)(a² + b² + c² - ab - bc - ca)

Using the standard algebraic identity (a + b + c)(a² + b² + c² - ab - bc - ca) = a³ + b³ + c³ - 3abc, we can simplify the expression: 2(a³ + b³ + c³ - 3abc) = 2a³ + 2b³ + 2c³ - 6abc

382Quantitative Aptitude
Speed of stream is 4 km/hr and the speed of boat is 11 km/hr. In how much time will the boat cover a distance of 21 km upstream and 45 km downstream?
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Answer: (A) 6 hours

Explanation

Using the formulas for boat and stream speed:

Upstream speed = Speed of boat - Speed of stream = 11 - 4 = 7 km/hr Downstream speed = Speed of boat + Speed of stream = 11 + 4 = 15 km/hr

Time taken to travel upstream = Upstream distance / Upstream speed = 21 / 7 = 3 hours Time taken to travel downstream = Downstream distance / Downstream speed = 45 / 15 = 3 hours

Total time taken = Upstream time + Downstream time = 3 + 3 = 6 hours

383Quantitative Aptitude
What is the value of (cos e A + 1)/(cos e A - 1) +(cos e A - 1)/(cos e A + 1)
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Answer: (D) 2 sec A

Explanation

The expression is simplified by finding a common denominator:

√((cosec A + 1)/(cosec A - 1)) + √((cosec A - 1)/(cosec A + 1))

Combining the terms under a single common denominator:

((cosec A + 1) + (cosec A - 1)) / √(cosec² A - 1)

Simplifying the numerator: cosec A + 1 + cosec A - 1 = 2 cosec A

Using the trigonometric identity cosec² A - 1 = cot² A, the denominator simplifies to: √(cot² A) = cot A

Substituting these simplified terms back: 2 cosec A / cot A

Expressing the trigonometric functions in terms of sine and cosine: (2 / sin A) / (cos A / sin A) = 2 / cos A = 2 sec A

384Quantitative Aptitude
The average of 10 consecutive integers is 33/2. What is the average of first three integers?
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Answer: (B) 13

Explanation

The average of a set of consecutive integers (which forms an arithmetic progression) is equal to the average of its first and last terms. Let the 10 consecutive integers be n, n+1, ..., n+9.

The average of these 10 consecutive integers is given by: (n + (n + 9)) / 2 = 33/2 2n + 9 = 33 2n = 24 n = 12

The first three integers in this sequence are 12, 13, and 14.

The average of these first three consecutive integers is the middle term: (12 + 13 + 14) / 3 = 13

385Quantitative Aptitude
In Δ STU , SX is the median on TU. If SX = TX , then what is the value of ∠ TSU ?
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Answer: (D) 90 degree

Explanation

Since SX is the median on TU, X is the midpoint of TU, which gives TX = UX.

We are given that SX = TX. Combining these relations, we get SX = TX = UX.

In ΔSTX, since SX = TX, the opposite angles are equal. Let ∠XST = ∠XTS = α.

In ΔSUX, since SX = UX, the opposite angles are equal. Let ∠XSU = ∠XUS = β.

The sum of angles in ΔSTU is ∠T + ∠U + ∠TSU = 180°.

Substituting the angle variables gives: α + β + (α + β) = 180° 2(α + β) = 180° α + β = 90°

Since ∠TSU = α + β, the value of ∠TSU is 90°.

386Quantitative Aptitude
Median of an equilateral triangle is 15√3 cm. What is the side of this triangle?
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Answer: (C) 30 cm

Explanation

In an equilateral triangle, the median is also the altitude. The relation between the altitude h and the side length a of an equilateral triangle is given by the formula h = (√3 / 2) × a.

Substituting the given median value into the formula: 15√3 = (√3 / 2) × a

Dividing both sides by √3: 15 = a / 2

Solving for a: a = 15 × 2 = 30 cm

387Quantitative Aptitude
The simple interest accrued on a certain principal is Rs. 1200 in 3 years at the rate of 8% per annum. What would be the compound interest (compounding annually) accrued on twice of that principal at the rate of 10% per annum in 2 years?
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Answer: (C) Rs.2,100

Explanation

Simple interest is calculated using the formula SI = (P × R × T) / 100, where P is the principal, R is the rate of interest per annum, and T is the time in years.

Substituting the given values: 1200 = (P × 8 × 3) / 100 1200 = 24P / 100 P = (1200 × 100) / 24 P = 5000

The new principal is twice the original principal: P' = 2 × 5000 = 10000

For compound interest compounding annually at 10% per annum for 2 years, the effective rate of interest can be calculated using the successive percentage formula: Effective rate = 10 + 10 + (10 × 10) / 100 = 21%

Now, calculate the compound interest accrued on the new principal: Compound Interest = 10000 × 21% = 10000 × 21/100 = 2100

388Quantitative Aptitude
AD is the median of Δ ABC . G is the centroid of Δ ABC . If AG = 14 cm, then what is the length of AD?
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Answer: (D) 21 cm

Explanation

The centroid G of a triangle divides each median in the ratio 2:1 from the vertex. For the median AD, the centroid G divides it such that AG : GD = 2 : 1.

This means that the length of AG is two-thirds of the total length of the median AD:

AG = (2/3) × AD

Substituting the given value of AG = 14 cm into the relation:

14 = (2/3) × AD

AD = 14 × 3/2 = 21 cm

389Quantitative Aptitude
If tan A = 3 , then what is the value of 3 sin A cos A?
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Answer: (B) 9/10

Explanation

The expression 3 sin A cos A can be written in terms of tan A by dividing and multiplying by cos² A, which is equivalent to dividing the expression by sin² A + cos² A:

3 sin A cos A = 3 sin A cos A / (sin² A + cos² A)

Dividing the numerator and the denominator by cos² A gives:

3 sin A cos A = 3 tan A / (tan² A + 1)

Substituting the given value tan A = 3 into the formula:

3 sin A cos A = 3 × 3 / (3² + 1) = 9 / (9 + 1) = 9/10

390Quantitative Aptitude
The price of a commodity is decreased by 25 percent and therefore a household increased the consumption of that commodity by 20 kg to keep the expenditure same. What was the earlier consumption?
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Answer: (A) 60 kg

Explanation

Let the original price be P and the original consumption be C.

The relationship between expenditure, price, and consumption is given by: Expenditure = Price × Consumption

Since the expenditure remains constant after the price decrease of 25% and consumption increase of 20 kg: P × C = 0.75P × (C + 20)

Dividing both sides by P: C = 0.75(C + 20) C = 0.75C + 15 0.25C = 15 C = 60 kg

391Quantitative Aptitude
What is the value of (a² + b² + 4c² - ab - 2bc - 2ca)(a + b + 2c) ?
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Answer: (D) a³ + b³ + 8c³ - 6abc

Explanation

The given algebraic expression can be simplified using the standard algebraic identity:

(x + y + z)(x² + y² + z² - xy - yz - zx) = x³ + y³ + z³ - 3xyz

By comparing the given expression (a + b + 2c)(a² + b² + 4c² - ab - 2bc - 2ca) with the identity, we can substitute: x = a y = b z = 2c

Substituting these values into the RHS of the identity:

x³ + y³ + z³ - 3xyz = a³ + b³ + (2c)³ - 3(a)(b)(2c) = a³ + b³ + 8c³ - 6abc

392Quantitative Aptitude
Radii of two circles are 11 cm and 3 cm. Distance between their centres is 17 cm. What is the length of the Direct common tangent?
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Answer: (D) 15 cm

Explanation

Correct Answer: D

The length of the direct common tangent (L) to two circles is given by the formula:

L = √(d² - (R - r)²)

where d is the distance between the centres of the two circles, R is the radius of the larger circle, and r is the radius of the smaller circle.

Given: d = 17 cm R = 11 cm r = 3 cm

Substituting these values into the formula: L = √(17² - (11 - 3)²) L = √(17² - 8²) L = √(289 - 64) L = √225 L = 15 cm

393Quantitative Aptitude
The table given below shows the salary of 6 employees of a company. | Employees | Salary | |---|---| | P | 200 | | Q | 650 | | R | 350 | | S | 250 | | T | 450 | | U | 300 | What is the total salary of all the employees?
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Answer: (D) 2200

Explanation

The total salary of all the employees is the sum of the individual salaries of P, Q, R, S, T, and U.

Total Salary = 200 + 650 + 350 + 250 + 450 + 300 = 2200

394Quantitative Aptitude
If x + ¹⁄ₓ = -2 , then what is the value of x⁷ + x⁻⁷ + x² + x⁻²?(x< 0)
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Answer: (D) 0

Explanation

The given equation is x + 1/x = -2.

Multiplying the entire equation by x gives: x² + 1 = -2x x² + 2x + 1 = 0

This is a perfect square quadratic equation: (x + 1)² = 0 x = -1

Substituting x = -1 into the expression x⁷ + x⁻⁷ + x² + x⁻²: (-1)⁷ + (-1)⁻⁷ + (-1)² + (-1)⁻²

Since -1 raised to any odd power is -1, we have: (-1)⁷ = -1 (-1)⁻⁷ = 1/(-1)⁷ = -1

Since -1 raised to any even power is 1, we have: (-1)² = 1 (-1)⁻² = 1/(-1)² = 1

Adding these values together: -1 + (-1) + 1 + 1 = 0

395Quantitative Aptitude
The ratio of time taken in completing a work by a man and woman is 2 : 3. The ratio and the woman can complete the work together in 24 days. In how many days can the woman complete the work alone ?
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Answer: (C) 60 days

Explanation

Let the time taken by the man to complete the work be 2x days and by the woman be 3x days.

The individual one-day work rates of the man and the woman are 1/(2x) and 1/(3x) respectively.

Together, they can complete the work in 24 days, which means their combined one-day work rate is 1/24.

We can set up the equation: 1/(2x) + 1/(3x) = 1/24

To solve for x, we find a common denominator on the left side: (3 + 2) / 6x = 1/24 5 / 6x = 1/24 6x = 5 × 24 6x = 120 x = 20

The time taken by the woman alone to complete the work is 3x days: 3 × 20 = 60 days.

396Quantitative Aptitude
A dealer sells two machines at the rate of Rs. 15000 per machine. On one he earns a profit of 20 percent and on the other he loses 40 percent. What is his profit/loss percentage in the whole transaction?
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Answer: (A) 20 percent loss

Explanation

Selling price (SP) of each machine is Rs. 15000. Total selling price of both machines = 2 × 15000 = Rs. 30000.

The cost price (CP) of the first machine sold at 20% profit is: CP₁ = 15000 / (1 + 0.20) = 15000 / 1.2 = Rs. 12500.

The cost price (CP) of the second machine sold at 40% loss is: CP₂ = 15000 / (1 - 0.40) = 15000 / 0.6 = Rs. 25000.

Total cost price of both machines = 12500 + 25000 = Rs. 37500.

Since total CP is greater than total SP, there is a net loss: Net Loss = 37500 - 30000 = Rs. 7500.

Loss percentage = (Net Loss / Total CP) × 100 = (7500 / 37500) × 100 = 20%.

397Quantitative Aptitude
How many solid spherical balls of radius 6 cm can be made by melting a solid hemisphere of radius 12 cm?
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Answer: (A) 4

Explanation

By the principle of conservation of volume, the total volume of the spherical balls is equal to the volume of the melted hemisphere.

The volume of a hemisphere of radius R is: V_h = (2/3) π R³

The volume of a sphere of radius r is: V_s = (4/3) π r³

Let n be the number of spherical balls. The relation is: n × V_s = V_h n × (4/3) π r³ = (2/3) π R³

Simplifying the equation: n = ((2/3) / (4/3)) × (R / r)³ n = ½ × (R / r)³

Substituting the given values, R = 12 cm and r = 6 cm: n = ½ × (12 / 6)³ n = ½ × 2³ n = ½ × 8 n = 4

398Quantitative Aptitude
A shopkeeper allows 20 percent discount on the marked price of an article and he suffers a loss of 5 percent. If the article is sold at marked price, then what will be the profit percentage?
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Answer: (C) 18.75 percent

Explanation

Let the Cost Price of the article be CP and the Marked Price be MP.

When a discount of 20% is allowed on the MP, the Selling Price (SP) is: SP = MP × (1 - 20/100) = 0.80 × MP

Since there is a loss of 5% at this Selling Price: SP = CP × (1 - 5/100) = 0.95 × CP

Equating the two expressions for SP: 0.80 × MP = 0.95 × CP MP / CP = 0.95 / 0.80 = 95 / 80 = 19 / 16

If the article is sold at the marked price, the new Selling Price is equal to MP. Profit Percentage = ((MP - CP) / CP) × 100 Profit Percentage = ((19 - 16) / 16) × 100 Profit Percentage = (3 / 16) × 100 = 18.75%

399Quantitative Aptitude
If the radius of the circle is 42 cm and the angle formed at the centre by an arc is 150°. What is the length of the corresponding arc?
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Answer: (C) 110 cm

Explanation

The length of an arc of a circle is given by the formula:

L = (θ / 360°) × 2πr

Given: Radius r = 42 cm Central angle θ = 150° π ≈ 22/7

Substituting these values into the formula:

L = (150 / 360) × 2 × (22 / 7) × 42

Simplifying the fraction and the terms:

L = (5 / 12) × 2 × 22 × 6

L = (5 / 12) × 264

L = 5 × 22

L = 110 cm

400Quantitative Aptitude
What is the sum of all three digit numbers which are divisible by 15?
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Answer: (C) 32850

Explanation

The three-digit numbers divisible by 15 form an arithmetic progression. The first three-digit number divisible by 15 is 105, and the last is 990. The common difference is 15.

Using the formula for the n-th term of an arithmetic progression: l = a + (n - 1)d

Substituting the values: 990 = 105 + (n - 1) × 15 885 = (n - 1) × 15 n - 1 = 59 n = 60

Using the sum formula for an arithmetic progression: S = (n / 2) × (a + l)

Substituting the values: S = (60 / 2) × (105 + 990) S = 30 × 1095 S = 32850

Answer key

Tap a number to jump to that question.

  1. 351D
  2. 352D
  3. 353B
  4. 354A
  5. 355C
  6. 356C
  7. 357B
  8. 358B
  9. 359B
  10. 360A
  11. 361C
  12. 362A
  13. 363D
  14. 364B
  15. 365D
  16. 366A
  17. 367D
  18. 368D
  19. 369D
  20. 370C
  21. 371D
  22. 372A
  23. 373C
  24. 374D
  25. 375A
  26. 376C
  27. 377B
  28. 378B
  29. 379A
  30. 380B
  31. 381B
  32. 382A
  33. 383D
  34. 384B
  35. 385D
  36. 386C
  37. 387C
  38. 388D
  39. 389B
  40. 390A
  41. 391D
  42. 392D
  43. 393D
  44. 394D
  45. 395C
  46. 396A
  47. 397A
  48. 398C
  49. 399C
  50. 400C

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