SSC CHSL2021Quantitative AptitudePage 6 of 17

SSC CHSL Tier 1 2021 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 251–300 of 802, each with the correct answer and a step-by-step explanation.

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251Quantitative Aptitude
Using the formula tan ˣ⁄₂ = (1 - cos x)/(sin x) , find the value of tan 22.5° .
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Answer: (A) √2 - 1

Explanation

To find the value of tan 22.5° using the formula tan(x/2) = (1 - cos x) / sin x, we can substitute x = 45° so that x/2 = 22.5°.

The trigonometric values for 45° are: cos 45° = 1/√2 sin 45° = 1/√2

Substituting these values into the given formula: tan 22.5° = (1 - 1/√2) / (1/√2)

To simplify, multiply both the numerator and the denominator by √2: tan 22.5° = (√2 - 1) / 1 tan 22.5° = √2 - 1

252Quantitative Aptitude
Find the value of 'a' using the concept of BODMAS. 42÷ 2 + a× 3 - 22 = 8
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Answer: (D) 3

Explanation

Following the BODMAS rule, the operations must be performed in the order of Division, Multiplication, Addition, and then Subtraction.

The given equation is: 42 ÷ 2 + a × 3 - 22 = 8

First, perform the division operation: 42 ÷ 2 = 21

Substitute this value back into the equation: 21 + a × 3 - 22 = 8

Next, perform the multiplication: a × 3 = 3a

Substitute this term back: 21 + 3a - 22 = 8

Combine the constant terms: 3a - 1 = 8

Solve for a by adding 1 to both sides and dividing by 3: 3a = 8 + 1 3a = 9 a = 9 ÷ 3 a = 3

253Quantitative Aptitude
In an examination, the Average marks of 7 children was 20, that of 3 children was 45, that of another 4 children was 15 and that of 2 children was 0. What is the average marks of all the 16 children? (Correct to one decimal place)
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Answer: (B) 20.9

Explanation

The weighted average formula is used to find the average marks of all the children:

Average = (n₁a₁ + n₂a₂ + n₃a₃ + n₄a₄) / (n₁ + n₂ + n₃ + n₄)

Here, the number of children in each group and their respective average marks are: Group 1: n₁ = 7, a₁ = 20 Group 2: n₂ = 3, a₂ = 45 Group 3: n₃ = 4, a₃ = 15 Group 4: n₄ = 2, a₄ = 0

Substitute these values to find the total marks: Total marks = (7 × 20) + (3 × 45) + (4 × 15) + (2 × 0) = 140 + 135 + 60 + 0 = 335

Total number of children = 7 + 3 + 4 + 2 = 16

Average marks of all 16 children = 335 / 16 = 20.9375

Rounding to one decimal place gives 20.9.

254Quantitative Aptitude
A washing machine is sold at a discount of 10% on its marked price. A further discount of 5% on the initial selling price is offered if a person makes the payment in cash. If the marked price of the machine is 54,000 , how much will a customer paying in cash have to pay for purchasing it?
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Answer: (C) ₹46,170

Explanation

The final price for a customer paying in cash is calculated using successive discounts on the marked price. The formula for the final selling price after successive discounts is:

Final Price = Marked Price × (1 - d₁/100) × (1 - d₂/100)

Here, the marked price is ₹54,000, the first discount d₁ is 10%, and the second cash discount d₂ is 5%. Substituting these values:

Final Price = 54,000 × (1 - 10/100) × (1 - 5/100) Final Price = 54,000 × 0.9 × 0.95 Final Price = 54,000 × 0.855 Final Price = ₹46,170

255Quantitative Aptitude
The length, breadth and height of a room are 7m , 4m and 9m , respectively. Find the cost of whitewashing the walls of the room and the ceiling at the rate of £7.50 per m² .
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Answer: (B) 1,695

Explanation

The total area to be whitewashed includes the area of the four walls and the area of the ceiling.

Area of the four walls = 2h(l + b) Area of the ceiling = lb

Substituting the given values of length (l) = 7 m, breadth (b) = 4 m, and height (h) = 9 m:

Area of the four walls = 2 × 9 × (7 + 4) = 18 × 11 = 198 m² Area of the ceiling = 7 × 4 = 28 m²

Total area to be whitewashed = 198 + 28 = 226 m²

The rate of whitewashing is 7.50 per m².

Total cost of whitewashing = Total area × Rate Total cost of whitewashing = 226 × 7.50 = 1695

256Quantitative Aptitude
Find the selling price of an article if a shopkeeper allows two successive discounts of 5% each on the marked price of £80.
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Answer: (C) 72.20

Explanation

The selling price of an article after allowing successive discounts can be calculated directly using the formula:

Selling Price = Marked Price × (1 - d₁/100) × (1 - d₂/100)

Here, the Marked Price is £80, and the two successive discounts, d₁ and d₂, are both 5%.

Selling Price = 80 × (1 - 5/100) × (1 - 5/100)

Selling Price = 80 × 0.95 × 0.95

Selling Price = 80 × 0.9025

Selling Price = 72.20

257Quantitative Aptitude
Which of the following numbers is NOT divisible by 15?
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Answer: (D) 2995

Explanation

A number is divisible by 15 if it is divisible by both 3 and 5.

For a number to be divisible by 5, its last digit must be either 0 or 5. The number 2995 ends with 5, so it is divisible by 5.

For a number to be divisible by 3, the sum of its digits must be divisible by 3. The sum of the digits of 2995 is 2 + 9 + 9 + 5 = 25. Since 25 is not divisible by 3, 2995 is not divisible by 3.

Consequently, 2995 is not divisible by 15.

258Quantitative Aptitude
If sin θ = (√3)/(2) , and θ is an acute angle, find the value of cos 3θ .
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Answer: (C) -1

Explanation

Given that sin θ = √3/2 and θ is an acute angle, the value of θ is 60°.

Substituting θ = 60° into the expression cos 3θ gives: cos 3θ = cos(3 × 60°) = cos 180°

Since cos 180° = -1, the value of cos 3θ is -1.

259Quantitative Aptitude
Simplify (5 × 5 × 5 × 5 × 5)⁵ × (5 × 5 × 5)⁵ ÷ 5 = (125)⁷ .
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Answer: (C) 13

Explanation

The expression on the left-hand side can be simplified using the laws of exponents:

(5 × 5 × 5 × 5 × 5)⁵ × (5 × 5 × 5)⁵ ÷ 5 = (5⁵)⁵ × (5³)⁵ ÷ 5¹ = 5²⁵ × 5¹⁵ ÷ 5¹ = 5²⁵⁺¹⁵⁻¹ = 5³⁹

To express 5³⁹ as a power of 125, we write 125 as 5³:

5³⁹ = (5³)¹³ = (125)¹³

Comparing this to the right-hand side, the required exponent value is 13.

260Quantitative Aptitude
If the length, breadth and height of a cuboid are 7.5m , 22m and 13m , respectively, then find the volume of the cuboid.
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Answer: (A) 2145 m3

Explanation

The volume of a cuboid is calculated using the formula:

Volume = length × breadth × height

Given the dimensions of the cuboid: Length = 7.5 m Breadth = 22 m Height = 13 m

Substituting these values into the formula:

Volume = 7.5 m × 22 m × 13 m Volume = 165 × 13 Volume = 2145 m³

261Quantitative Aptitude
What is the average of first 10 multiples of 6?
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Answer: (D) 33

Explanation

The average of first n multiples of a number k is given by the formula k × (n + 1) / 2. Here, the number is k = 6 and the number of terms is n = 10. Substituting these values into the formula gives 6 × (10 + 1) / 2 = 3 × 11 = 33. Alternatively, because the multiples form an arithmetic progression, the average is simply the mean of the first term 6 and the last term 60, which is (6 + 60) / 2 = 33.

262Quantitative Aptitude
The price of a bike is ₹75,500. What will be the price of the bike after a reduction of 17%?
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Answer: (C) 62,665

Explanation

Using the formula for percentage reduction: New Price = Original Price × (1 - r/100)

Here, the original price of the bike is ₹75,500 and the reduction rate (r) is 17%.

New Price = 75,500 × (1 - 0.17) New Price = 75,500 × 0.83 New Price = 62,665

263Quantitative Aptitude
If the compound interest on a principal for one year is ₹350 and the compound interest for the second year is ₹420, find the rate of interest.
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Answer: (B) 20%

Explanation

The compound interest for the first year is ₹350. The compound interest for the second year is ₹420.

In compound interest, the interest for any year is the interest on the preceding year's amount. Therefore, the difference between the compound interest of the second year and the first year represents the interest earned on the first year's interest.

Difference in interest = ₹420 - ₹350 = ₹70

This difference of ₹70 is the interest earned on the first year's interest of ₹350 over a period of one year.

Rate of interest (R) = (Difference in interest / Interest of first year) × 100%

R = (70 / 350) × 100%

R = (1 / 5) × 100% = 20%

264Quantitative Aptitude
The area of quadrilateral is 336m² and the perpendiculars drawn to one diagonal from the opposite vertices are 16m and 12m long. Find the length of this diagonal.
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Answer: (D) 24 cm

Explanation

The area of a quadrilateral with diagonal d and perpendicular offsets h₁ and h₂ from the opposite vertices is given by the formula:

Area = ½ × d × (h₁ + h₂)

Substituting the given values of Area = 336, h₁ = 16, and h₂ = 12:

336 = ½ × d × (16 + 12)

336 = ½ × d × 28

336 = 14 × d

d = 336 / 14

d = 24

Therefore, the length of the diagonal is 24 units.

265Quantitative Aptitude
Simplify the following expression. ((62×62×62)- 3(62×62×22)+3(62×22×22)- (22×22×22))/(8×8×8)
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Answer: (C) 125

Explanation

The numerator of the given expression matches the standard algebraic expansion of (a - b)³: a³ - 3a²b + 3ab² - b³ = (a - b)³

By substituting a = 62 and b = 22, the numerator simplifies to: (62 - 22)³ = 40³

The denominator is: 8 × 8 × 8 = 8³

Dividing the simplified numerator by the denominator: 40³ / 8³ = (40 / 8)³ = 5³ = 125

266Quantitative Aptitude
The base of a parallelogram is twice as long as its corresponding height. If the area of the parallelogram is 144cm², find the mentioned height.
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Answer: (B) 6√2 cm

Explanation

The area of a parallelogram is given by the formula: Area = base × height

Let the height of the parallelogram be h cm. Since the base is twice as long as its corresponding height, the base is 2h cm.

Substituting these values into the formula: 2h × h = 144 2h² = 144 h² = 72 h = √72 h = 6√2 cm

267Quantitative Aptitude
What is the mean proportional between 64 and 4096?
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Answer: (A) 512

Explanation

The mean proportional between two numbers a and b is given by the formula √(ab).

Given the two numbers: a = 64 b = 4096

Substituting these values into the formula: Mean proportional = √(64 × 4096)

Using the property of square roots, this can be simplified as: Mean proportional = √64 × √4096

Since √64 = 8 and √4096 = 64, we compute: Mean proportional = 8 × 64 = 512

268Quantitative Aptitude
A and B together can finish a job in 40 days. A can do the same job on her own in 60 days. How long will B take to do the three- fourth of the same work all alone?
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Answer: (A) 90 days

Explanation

Let the total work be 120 units, which is the least common multiple of 40 and 60.

The combined daily work rate of A and B is 120 / 40 = 3 units/day. The daily work rate of A alone is 120 / 60 = 2 units/day.

The daily work rate of B alone is the difference between their combined rate and A's rate: 3 - 2 = 1 unit/day.

Three-fourth of the total work is ¾ × 120 = 90 units.

The time taken by B alone to complete this three-fourth of the work is 90 units ÷ 1 unit/day = 90 days.

269Quantitative Aptitude
A sum of £5,000 was deposited for 3 years at 10% per annum, compounded annually. The difference between the interest for 2 years and that for 3 years is:
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Answer: (D) ₹605

Explanation

The difference between the compound interest for 3 years and 2 years is equal to the interest earned in the 3rd year.

First, the accumulated amount at the end of 2 years (A₂) is given by the formula: A₂ = P(1 + R/100)²

Substituting the given values: A₂ = 5000(1 + 10/100)² A₂ = 5000(1.1)² A₂ = 5000 × 1.21 = 6050

The interest for the 3rd year is the interest earned on this 2nd-year amount: Interest in 3rd year = A₂ × R/100 Interest in 3rd year = 6050 × 10/100 = 605

270Quantitative Aptitude
If cotθ = cot 30° cot 60° and θ is an acute angle, then 2θ is equal to:
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Answer: (A) 90°

Explanation

Given the equation: cot θ = cot 30° cot 60°

Using the standard trigonometric values: cot 30° = √3 cot 60° = 1/√3

Substituting these values into the equation: cot θ = √3 × (1/ √3) cot θ = 1

Since θ is given to be an acute angle, the value of θ is: θ = 45°

Using the value of θ, we find: 2θ = 2 × 45° = 90°

271Quantitative Aptitude
A shopkeeper mixes three types of rice costing ₹50 per kg, ₹60 per kg and ₹75 per kg in the ratio of 3 : 1 : 2. The average cost of the mixture per kg is:
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Answer: (D) ₹60

Explanation

The average cost of the mixture can be directly computed using the weighted average formula:

Average Cost = (w₁C₁ + w₂C₂ + w₃C₃) ÷ (w₁ + w₂ + w₃)

Here, the ratios of the quantities represent the weights, which are w₁ = 3, w₂ = 1, and w₃ = 2. The respective costs per kg are C₁ = ₹50, C₂ = ₹60, and C₃ = ₹75.

Substituting these values into the formula:

Average Cost = (3 × 50 + 1 × 60 + 2 × 75) ÷ (3 + 1 + 2)

Average Cost = (150 + 60 + 150) ÷ 6

Average Cost = 360 ÷ 6 = ₹60 per kg

272Quantitative Aptitude
If x + 2y = 10 and 2xy = 9 , then one of the value of x - 2y is:
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Answer: (A) 8

Explanation

By using the algebraic identity: (A - B)² = (A + B)² - 4AB

Let A = x and B = 2y. This gives the relation: (x - 2y)² = (x + 2y)² - 4(x)(2y) (x - 2y)² = (x + 2y)² - 4(2xy)

Substitute the given values of x + 2y = 10 and 2xy = 9 into the equation: (x - 2y)² = 10² - 4(9) (x - 2y)² = 100 - 36 (x - 2y)² = 64

Taking the square root on both sides: x - 2y = ±√64 x - 2y = ±8

Hence, one of the possible values for x - 2y is 8.

273Quantitative Aptitude
One single discount which is equivalent to 20% , 10% and 5% is given by:
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Answer: (D) 31.60%

Explanation

Using the successive discount formula, the equivalent discount of two successive discounts x% and y% is given by the formula: x + y - xy/100

First, calculate the equivalent discount for the first two discounts of 20% and 10%: 20 + 10 - (20 × 10)/100 = 30 - 2 = 28%

Next, calculate the equivalent discount for this result of 28% and the third discount of 5%: 28 + 5 - (28 × 5)/100 = 33 - 1.4 = 31.6%

Alternatively, if the initial marked price is assumed to be 100, the final selling price after three successive discounts is: 100 × (1 - 0.20) × (1 - 0.10) × (1 - 0.05) = 100 × 0.80 × 0.90 × 0.95 = 68.4

The equivalent single discount is: 100 - 68.4 = 31.6%

274Quantitative Aptitude
P sold an item to Q at a 20% gain, and Q sold it to R at a loss of 10% . If R bought the item for ₹1,080, then at what price did P purchase it?
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Answer: (C) ₹1000

Explanation

Let the purchase price of P be x.

Since P sold the item to Q at a 20% gain, the cost price for Q is: Cost Price of Q = x × 1.20

Q then sold the item to R at a 10% loss, making the cost price for R: Cost Price of R = Cost Price of Q × 0.90 = x × 1.20 × 0.90 = 1.08x

We are given that R bought the item for ₹1,080: 1.08x = 1080 x = 1080 / 1.08 x = 1000

275Quantitative Aptitude
A householder spent his monthly salary of ₹7,200 on different items. If he spent ₹4,000 on food and ₹400 on education, then the central angles respectively are:
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Answer: (A) 200°,20°

Explanation

The central angle for an item in a pie chart is calculated using the formula: Central Angle = (Component Value / Total Value) × 360°

Given that the total salary is ₹7,200:

For food: Central Angle = (4000 / 7200) × 360° = 200°

For education: Central Angle = (400 / 7200) × 360° = 20°

276Quantitative Aptitude
Rice worth ₹96 per kg and ₹104 per kg are mixed with a third variety in the ratio 1:1: 2. If the mixture is worth ₹113 per kg, the price of the third variety of rice per kg will be:
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Answer: (B) ₹126

Explanation

The weighted average formula for the cost of a mixture of three items is:

Average Price = (w₁P₁ + w₂P₂ + w₃P₃) / (w₁ + w₂ + w₃)

Here, P₁ = ₹96, P₂ = ₹104, and P₃ is the unknown price of the third variety, represented as x. The mixing ratio w₁ : w₂ : w₃ is 1 : 1 : 2, and the average price of the mixture is ₹113 per kg.

Substituting these values into the formula:

113 = (1 × 96 + 1 × 104 + 2 × x) / (1 + 1 + 2)

113 = (200 + 2x) / 4

Multiplying both sides by 4:

452 = 200 + 2x

2x = 452 - 200

2x = 252

x = 126

277Quantitative Aptitude
Successive discounts of 10% and 20% are given on the purchase of a purse. If the price of the purse is ₹2,250, find the selling price.
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Answer: (D) ₹1,620

Explanation

Correct Answer: D

The selling price after successive discounts is calculated using the formula:

Selling Price = Marked Price × (1 - d₁/100) × (1 - d₂/100)

Here, the marked price is ₹2,250, and the successive discounts are d₁ = 10% and d₂ = 20%.

Selling Price = 2250 × (1 - 10/100) × (1 - 20/100) Selling Price = 2250 × 0.9 × 0.8 Selling Price = 2250 × 0.72 Selling Price = 1620

278Quantitative Aptitude
What is the surface area of a sphere whose diameter is 30cm ? [Use π = 3.14 ]
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Answer: (B) 2826

Explanation

The surface area of a sphere is calculated using the formula:

A = 4πr²

The diameter of the sphere is given as 30 cm, which means its radius r is:

r = 30 / 2 = 15 cm

Substituting r = 15 cm and π = 3.14 into the formula:

A = 4 × 3.14 × 15²

A = 4 × 3.14 × 225

A = 900 × 3.14

A = 2826 cm²

279Quantitative Aptitude
Find the compound interest on ₹5,50,000 at 7% per annum for 2 years, compounded annually.
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Answer: (D) 79,695

Explanation

The effective compound interest rate for 2 years at 7% per annum can be calculated using the successive percentage change formula:

Effective Rate = R + R + (R × R)/100 Effective Rate = 7 + 7 + (7 × 7)/100 = 14.49%

The compound interest (CI) is the effective rate percentage of the principal amount:

CI = 14.49% of ₹5,50,000 CI = (14.49 / 100) × 5,50,000 CI = 14.49 × 5,500 CI = 79,695

280Quantitative Aptitude
What is the smallest natural number that should be added to 54321 so that the sum is divisible by 6?
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Answer: (D) 3

Explanation

For a number to be divisible by 6, it must be divisible by both 2 and 3. Dividing 54321 by 6 yields a quotient of 9053 and a remainder of 3.

To find the smallest natural number to add to make it divisible by 6, we subtract the remainder from the divisor: 6 − 3 = 3

Adding 3 to 54321 gives 54324, which is an even number and has a digit sum of 18, making it divisible by both 2 and 3, and therefore divisible by 6.

281Quantitative Aptitude
How many spherical balls of radius 5 cm can be made by melting a spherical clay ball having a radius of 15 cm?
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Answer: (D) 27

Explanation

The volume of a sphere is given by the formula V = (4/3) π r³, where r is the radius of the sphere.

Let the radius of the larger spherical clay ball be R = 15 cm and the radius of each smaller spherical ball be r = 5 cm.

Since the total volume of clay remains conserved during melting, the number of smaller balls, n, that can be made is the ratio of the volume of the larger ball to the volume of a single smaller ball:

n = ((4/3) π R³) / ((4/3) π r³) n = (R / r)³

Substituting the given radii:

n = (15 / 5)³ n = 3³ n = 27

282Quantitative Aptitude
The average monthly expenditure of a family for the first four months is ₹13,750, for the next three months is ₹11,750 and for the last five months is ₹31,750. If the family saves ₹15,550 during the whole year, find the average monthly income of the family during the year. (Consider integral part only)
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Answer: (B) 22,045

Explanation

The formula for the average monthly income of the family over the year is:

Average Monthly Income = (Total Annual Expenditure + Total Annual Savings) ÷ 12

First, calculate the total annual expenditure by multiplying the average expenditure of each period by the number of months in that period:

Expenditure for the first 4 months = 4 × 13,750 = 55,000 Expenditure for the next 3 months = 3 × 11,750 = 35,250 Expenditure for the last 5 months = 5 × 31,750 = 158,750

Total Annual Expenditure = 55,000 + 35,250 + 158,750 = 249,000

Next, determine the total annual income by adding the total annual savings to the total annual expenditure:

Total Annual Income = 249,000 + 15,550 = 264,550

Now, divide the total annual income by 12 to find the average monthly income:

Average Monthly Income = 264,550 ÷ 12 ≈ 22,045.83

Considering only the integral part, the average monthly income of the family is 22,045.

283Quantitative Aptitude
What is the value of 12-8÷2- (16 of -2+3×5-4)?
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Answer: (C) 29

Explanation

To evaluate the expression, follow the BODMAS rule (Brackets, Of, Division, Multiplication, Addition, Subtraction). The expression is:

12 - 8 ÷ 2 - (16 of -2 + 3 × 5 - 4)

First, evaluate the operations inside the parentheses.

Begin with the of operation: 16 of -2 = 16 × (-2) = -32

Next, perform the multiplication: 3 × 5 = 15

Now, perform addition and subtraction inside the parentheses: -32 + 15 - 4 = -17 - 4 = -21

The parenthetical part simplifies to -21, so the expression becomes: 12 - 8 ÷ 2 - (-21)

Next, perform the division: 8 ÷ 2 = 4

Substitute this value and simplify the subtraction of the negative number: 12 - 4 + 21

Finally, perform the addition and subtraction: 8 + 21 = 29

284Quantitative Aptitude
'A' and 'B' are two stations 494 km apart. A train starts from station 'A' at 3 p.m. and travels towards station 'B' at 83 km/h. Another train starts from station 'B' at 4 p.m. and travels towards station 'A' at 54 km/h. At what time do they meet?
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Answer: (A) 7 p.m.

Explanation

First, calculate the distance covered by the first train before the second train starts. From 3 p.m. to 4 p.m., the train from station A travels for 1 hour at a speed of 83 km/h, covering a distance of 83 km.

The remaining distance between the two stations at 4 p.m. is 494 km - 83 km = 411 km.

Since the two trains are traveling towards each other, their relative speed is the sum of their individual speeds. Relative speed = 83 km/h + 54 km/h = 137 km/h.

The time taken for the trains to meet after 4 p.m. is found by dividing the remaining distance by their relative speed. Time taken = 411 km ÷ 137 km/h = 3 hours.

Adding these 3 hours to 4 p.m. gives the meeting time as 7 p.m.

285Quantitative Aptitude
One of the angles of a triangle is 108° , and the other two angles are equal. What is the measure of each of these equal angles?
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Answer: (A) 36°

Explanation

By the angle sum property of a triangle, the sum of all interior angles is 180°. Let the measure of each of the two equal angles be x.

108° + x + x = 180°

Simplifying this relation: 108° + 2x = 180° 2x = 180° - 108° 2x = 72° x = 36°

286Quantitative Aptitude
For what value(s) of k will the expression p + ⅑√p +k² be a perfect square?
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Answer: (D) k = ± ¹⁄₁₈

Explanation

Let √p = x. The given expression can be written as: x² + 1/9 x + k²

For this expression to be a perfect square, it must be in the form of the algebraic identity (x + a)² = x² + 2ax + a².

Comparing the coefficients of the given expression with the identity: 2a = 1/9 a = 1/18

Since the constant term is k², we have: k² = a² k² = (1/18)² k = ±1/18

287Quantitative Aptitude
In a panchayat election Candidate A secured 30% of the total votes and did NOT qualify by 6 votes. Candidate B secured 40% of the total votes and got 6 votes more than the bare minimum to qualify. The total number of votes were ______.
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Answer: (D) 120

Explanation

Let V be the total number of votes.

Candidate A secured 30% of V and fell short of the qualifying mark by 6 votes. Candidate B secured 40% of V and exceeded the qualifying mark by 6 votes.

The difference in percentage of votes secured by the two candidates is: 40% - 30% = 10% of V

The absolute difference in their votes is: 6 + 6 = 12 votes

We equate the percentage difference to the vote difference: 10% of V = 12 0.10 × V = 12 V = 12 / 0.10 = 120

288Quantitative Aptitude
The average of 10 observations is 21. A new observation is included and the average of these 11 numbers is 1 less than the previous average. The 11ᵗʰ observation is
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Answer: (C) 10

Explanation

The sum of the first 10 observations is equal to 10 × 21 = 210.

The new average of the 11 observations is 1 less than the previous average, which is 21 - 1 = 20.

The sum of these 11 observations is equal to 11 × 20 = 220.

The value of the 11th observation is the difference between the sum of 11 observations and the sum of 10 observations, which is 220 - 210 = 10.

289Quantitative Aptitude
Which of the following is the least 6- digit number that is divisible by 93?
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Answer: (A) 100068

Explanation

To find the least 6-digit number divisible by 93, we start with the smallest 6-digit number, which is 100000.

Dividing 100000 by 93: 100000 = 93 × 1075 + 25

The remainder is 25. To find the next multiple of 93, we add the difference between the divisor and the remainder to 100000: 100000 + (93 - 25) = 100000 + 68 = 100068

290Quantitative Aptitude
A number x is three times another number y. If the sum of both the numbers is 20, then x and y, respectively, are:
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Answer: (B) 15 and 5

Explanation

Let the two numbers be x and y. According to the given conditions: x = 3y x + y = 20

By substituting the first equation into the second: 3y + y = 20 4y = 20 y = 5

Now, substitute the value of y back into the first equation to find x: x = 3 × 5 = 15

291Quantitative Aptitude
A person could save 20% of his income. A year later, his income increased by 25% but he could save the same amount only as before. By what percentage has his expenditure increased?
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Answer: (C) 31.25%

Explanation

Let the initial income of the person be 100. Since he saves 20% of his income, his initial savings are 20 and his initial expenditure is 100 - 20 = 80.

A year later, his income increases by 25%, making his new income 125. He saves the same absolute amount as before, so his new savings are still 20. This means his new expenditure is 125 - 20 = 105.

The increase in expenditure is 105 - 80 = 25.

The percentage increase in expenditure is calculated as: (Increase in expenditure / Initial expenditure) × 100% = (25 / 80) × 100% = 31.25%

292Quantitative Aptitude
The marked price of a table fan is ₹3,750 and is available to the retailer at a discount of 20% . At what price should the retailer sell it to earn a profit of 15% ?
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Answer: (D) ₹3,450

Explanation

Cost Price (CP) for the retailer is calculated from the marked price after applying the 20% discount: CP = 3750 × (1 - 0.20) = 3750 × 0.80 = ₹3,000

To earn a profit of 15%, the Selling Price (SP) is calculated on this cost price: SP = CP × (1 + 0.15) = 3000 × 1.15 = ₹3,450

293Quantitative Aptitude
Ravi drove for 4 hours at a speed of 70 miles per hour and for 2 hours at 40 miles per hour. What was his average speed (in miles per hour) for the whole journey?
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Answer: (B) 60

Explanation

The formula for average speed is the total distance divided by the total time taken.

In the first part of the journey, the distance covered is 70 miles per hour × 4 hours = 280 miles. In the second part of the journey, the distance covered is 40 miles per hour × 2 hours = 80 miles.

The total distance is 280 + 80 = 360 miles. The total time taken is 4 + 2 = 6 hours.

Average speed = 360 miles / 6 hours = 60 miles per hour.

294Quantitative Aptitude
What is the product of (x + a) and (x + b) ?
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Answer: (A) x² + (a + b)x + ab

Explanation

To find the product of (x + a) and (x + b), we use the distributive property to expand the expression:

(x + a)(x + b) = x(x) + x(b) + a(x) + a(b)

Simplifying each term gives:

x² + bx + ax + ab

By factoring out the common variable x from the middle terms, we get:

x² + (a + b)x + ab

295Quantitative Aptitude
What is the height of a solid right circular cylinder whose radius is 3 cm and total surface area is 60 cm² ?
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Answer: (C) 7 cm

Explanation

The formula for the total surface area of a solid right circular cylinder is: Total Surface Area = 2πr(r + h)

Given that the radius (r) is 3 cm and the total surface area is 60π cm², these values can be substituted into the formula: 60π = 2 × π × 3 × (3 + h)

Simplifying the equation: 60π = 6π(3 + h)

Dividing both sides by 6π: 10 = 3 + h

Solving for height (h): h = 7 cm

296Quantitative Aptitude
45 people can repair a road in 10 days, working 6 hours a day. In how many days can 30 people, working 6 hours a day, complete the same work?
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Answer: (D) 15

Explanation

Using the work equivalence formula: M₁ × D₁ × H₁ = M₂ × D₂ × H₂

where M represents the number of people, D represents the number of days, and H represents the number of working hours per day.

Given: M₁ = 45, D₁ = 10, H₁ = 6 M₂ = 30, H₂ = 6

Substituting these values into the formula: 45 × 10 × 6 = 30 × D₂ × 6

Since the daily hours are the same on both sides, we simplify to: 45 × 10 = 30 × D₂ 450 = 30 × D₂ D₂ = 450 / 30 D₂ = 15

297Quantitative Aptitude
What is the area (in cm² ) of an equilateral triangle of side 20~cm ?
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Answer: (A) 100√3

Explanation

The area of an equilateral triangle with side length a is given by the formula:

Area = (√3/4) × a²

Given that the side of the equilateral triangle is a = 20 cm, we substitute this value into the formula:

Area = (√3/4) × 20² Area = (√3/4) × 400 Area = 100√3 cm²

298Quantitative Aptitude
Under a discount scheme, a dozen pair of gloves quoted at £200 is available at a discount of 20% . How many pairs of gloves can be bought for £320?
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Answer: (D) 24

Explanation

Discounted price of 12 pairs (1 dozen pairs) of gloves = £200 × (100 - 20)% = £200 × 0.8 = £160.

This means 12 pairs of gloves cost £160.

Number of pairs of gloves that can be purchased for £320 = 12 × (320 / 160) = 12 × 2 = 24.

299Quantitative Aptitude
The value of sin 73° + cos 137° is:
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Answer: (A) sin 13°

Explanation

Using the trigonometric identity cos θ = -sin(θ - 90°), cos 137° can be written as: cos 137° = cos(90° + 47°) = -sin 47°

Substituting this into the original expression gives: sin 73° + cos 137° = sin 73° - sin 47°

Applying the sum-to-product formula, sin A - sin B = 2 cos((A + B)/2) sin((A - B)/2), where A = 73° and B = 47°: sin 73° - sin 47° = 2 cos((73° + 47°)/2) sin((73° - 47°)/2) = 2 cos 60° sin 13°

Substituting the known value cos 60° = ½: 2 × ½ × sin 13° = sin 13°

300Quantitative Aptitude
The diameter of the base of a right-circular cylinder is 12~cm and the height of the cylinder is 2.45 times the radius of its base. Find the curved surface area of the cylinder. [Use π = ²²⁄₇ ]
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Answer: (D) 554.4 cm²

Explanation

The curved surface area of a cylinder is calculated using the formula: Curved Surface Area = 2πrh

Given: Diameter of the base = 12 cm Radius of the base, r = 12 / 2 = 6 cm Height of the cylinder, h = 2.45 × r = 2.45 × 6 = 14.7 cm

Substituting the given values into the formula with π = 22/7: Curved Surface Area = 2 × (22/7) × 6 × 14.7 Curved Surface Area = 2 × 22 × 6 × 2.1 Curved Surface Area = 44 × 12.6 Curved Surface Area = 554.4 cm²

Answer key

Tap a number to jump to that question.

  1. 251A
  2. 252D
  3. 253B
  4. 254C
  5. 255B
  6. 256C
  7. 257D
  8. 258C
  9. 259C
  10. 260A
  11. 261D
  12. 262C
  13. 263B
  14. 264D
  15. 265C
  16. 266B
  17. 267A
  18. 268A
  19. 269D
  20. 270A
  21. 271D
  22. 272A
  23. 273D
  24. 274C
  25. 275A
  26. 276B
  27. 277D
  28. 278B
  29. 279D
  30. 280D
  31. 281D
  32. 282B
  33. 283C
  34. 284A
  35. 285A
  36. 286D
  37. 287D
  38. 288C
  39. 289A
  40. 290B
  41. 291C
  42. 292D
  43. 293B
  44. 294A
  45. 295C
  46. 296D
  47. 297A
  48. 298D
  49. 299A
  50. 300D

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