SSC CHSL2021Quantitative AptitudePage 3 of 17

SSC CHSL Tier 1 2021 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 101–150 of 802, each with the correct answer and a step-by-step explanation.

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101Quantitative Aptitude
If x + y + z = 0, then find the value of (x²)/(x² - yz) + (y²)/(y² - zx) + (z²)/(z² - xy).
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Answer: (A) 2

Explanation

Given that x + y + z = 0, we can write z = -x - y.

Substituting this value of z into the denominators of the three terms, we get:

x² - yz = x² - y(-x - y) = x² + xy + y²

y² - zx = y² - (-x - y)x = y² + x² + xy = x² + xy + y²

z² - xy = (-x - y)² - xy = x² + 2xy + y² - xy = x² + xy + y²

Since all three denominators are equal, we can combine the terms over the common denominator:

Expression = (x² + y² + z²) / (x² + xy + y²)

By substituting z² = (x + y)² = x² + 2xy + y² into the numerator, we obtain:

x² + y² + z² = x² + y² + (x² + 2xy + y²) = 2x² + 2xy + 2y² = 2(x² + xy + y²)

Therefore, the expression becomes:

2(x² + xy + y²) / (x² + xy + y²) = 2

102Quantitative Aptitude
The value of sin 35°cos 55° + cos 35°sin 55° is:
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Answer: (D) 1

Explanation

Using the trigonometric identity for the sum of two angles:

sin(A + B) = sin A cos B + cos A sin B

By substituting A = 35° and B = 55° into this formula, the expression can be simplified as:

sin 35° cos 55° + cos 35° sin 55° = sin(35° + 55°)

Simplifying the angle:

35° + 55° = 90°

Since the sine of 90° is equal to 1:

sin 90° = 1

103Quantitative Aptitude
If r + ¹⁄ᵣ = 11, then the value of (r³ + (1)/(r³))/(r² + (1)/(r²) - 1) is ______.
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Answer: (A) 11

Explanation

Using the algebraic identity for the sum of cubes, the numerator can be factored as:

r³ + 1/r³ = (r + 1/r)(r² - 1 + 1/r²)

Substitute this factored form into the given expression:

(r³ + 1/r³) / (r² + 1/r² - 1) = (r + 1/r)(r² + 1/r² - 1) / (r² + 1/r² - 1)

The common terms in the numerator and the denominator cancel out, simplifying the expression to:

r + 1/r

Given that r + 1/r = 11, the value of the expression is directly 11.

104Quantitative Aptitude
Three smaller cubes with sides of 3, 4, and 5 cm are melted together to form a large cube. What is the ratio of the smaller cubes' total surface area to the larger cube's total surface area?
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Answer: (C) 25:18

Explanation

The total volume of the three smaller cubes is the sum of their individual volumes: Volume = 3³ + 4³ + 5³ = 27 + 64 + 125 = 216 cm³

Since the three cubes are melted to form a single larger cube, the volume of the larger cube is also 216 cm³. Let the side of the larger cube be A. A³ = 216 A = ∛216 = 6 cm

The sum of the total surface areas of the three smaller cubes is: Total Surface Area (small) = 6 × (3² + 4² + 5²) Total Surface Area (small) = 6 × (9 + 16 + 25) = 6 × 50 = 300 cm²

The total surface area of the larger cube is: Total Surface Area (large) = 6 × A² = 6 × 6² = 6 × 36 = 216 cm²

The ratio of the smaller cubes' total surface area to the larger cube's total surface area is: Ratio = 300 : 216

Dividing both terms by their greatest common divisor, which is 12: Ratio = 25 : 18

105Quantitative Aptitude
Rajesh purchased a machine for ₹5,000 and paid ₹250 for its transportation. If he sells the machine for ₹5,075, what is his percentage profit or loss? (Correct to two decimal places)
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Answer: (C) Loss of 3.33%

Explanation

Total cost price (CP) of the machine includes both the purchase price and the transportation cost: CP = ₹5,000 + ₹250 = ₹5,250

The selling price (SP) is ₹5,075. Since the cost price is greater than the selling price, there is a loss.

Loss = CP - SP Loss = ₹5,250 - ₹5,075 = ₹175

Loss percentage = (Loss / CP) × 100 Loss percentage = (175 / 5250) × 100 Loss percentage = (1 / 30) × 100 = 3.33%

106Quantitative Aptitude
The effective annual rate of interest, corresponding to a nominal rate of 6% per annum, compounded half- yearly, is:
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Answer: (B) 0.0609

Explanation

The effective annual rate of interest, E, is calculated using the formula:

E = (1 + r/n)ⁿ - 1

where r is the nominal annual rate of interest and n is the compounding frequency per year.

Given that the nominal rate is 6% per annum (r = 0.06) and the compounding is half-yearly (n = 2), the values are substituted as follows:

E = (1 + 0.06/2)² - 1 E = (1.03)² - 1 E = 1.0609 - 1 E = 0.0609

This calculation yields an effective annual rate of interest of 0.0609.

107Quantitative Aptitude
An arc on a circle that is 18 cm long, subtends a 28.8° angle at the centre. What is the circumference of the circle?
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Answer: (C) 225 cm

Explanation

The length of an arc s that subtends an angle θ at the center of a circle is related to the total circumference C of the circle by the formula:

s = (θ / 360) × C

By substituting the given values of arc length s = 18 cm and angle θ = 28.8° into the formula:

18 = (28.8 / 360) × C

Rearranging the equation to solve for C:

C = (18 × 360) / 28.8

C = 6480 / 28.8

C = 225 cm

108Quantitative Aptitude
The following table gives data about literacy rates of four different states obtained during four censuses in the country. StatesYears | Karnataka | Gujarat | Andhra Pradesh | Kerala 2011 | 75.6 | 79.3 | 67.7 | 93.9 2001 | 66.6 | 69.1 | 60.5 | 90.9 1991 | 56.0 | 61.3 | 44.1 | 89.8 1981 | 46.2 | 44.9 | 35.7 | 78.9 Which state has the lowest literacy rates as per all the four censuses from which data is provided
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Answer: (B) Andhra Pradesh

Explanation

An analysis of the census data across all four specified years shows that Andhra Pradesh consistently recorded the lowest literacy rate among the four states in every single census.

In the 1981 census, Andhra Pradesh had a literacy rate of 35.7%, which was lower than the rates of Gujarat (44.9%), Karnataka (46.2%), and Kerala (78.9%).

In the 1991 census, the literacy rate of Andhra Pradesh rose to 44.1%, but this remained the lowest among the group, with Karnataka at 56.0%, Gujarat at 61.3%, and Kerala at 89.8%.

During the 2001 census, Andhra Pradesh recorded 60.5% literacy, which was again the lowest compared to Karnataka (66.6%), Gujarat (69.1%), and Kerala (90.9%).

Finally, in the 2011 census, Andhra Pradesh registered a literacy rate of 67.7%, continuing to be the lowest among the four states, while Karnataka stood at 75.6%, Gujarat at 79.3%, and Kerala at 93.9%.

109Quantitative Aptitude
Find the volume of the cylinder circumscribing a sphere with a diameter of 14 cm. (Use π = 22 / 7 )
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Answer: (A) 2156 cm3

Explanation

A cylinder circumscribing a sphere has a radius r equal to the radius of the sphere, and a height h equal to the diameter of the sphere.

Given the diameter of the sphere is 14 cm: r = 14 / 2 = 7 cm h = 14 cm

The volume V of the cylinder is given by the formula: V = π r² h

Substituting the given values: V = (22/7) × 7² × 14 V = 22 × 7 × 14 V = 154 × 14 V = 2156 cm³

110Quantitative Aptitude
A sum of money was invested at 10% interest per year, compounded half- yearly for 18 months. If the amount payable on maturity was ₹83,349, what was the sum invested?
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Answer: (D) ₹72,000

Explanation

The compound interest formula when interest is compounded half-yearly is A = P(1 + r)ⁿ, where A is the maturity amount, P is the principal sum, r is the rate of interest per compounding period, and n is the total number of compounding periods.

For half-yearly compounding over 18 months: The half-yearly rate r = 10% / 2 = 5% = 0.05 The number of half-yearly periods n = 18 / 6 = 3

Substituting the given maturity amount A = ₹83,349: 83349 = P(1 + 0.05)³ 83349 = P(1.05)³ 83349 = P × 1.157625

Solving for P: P = 83349 / 1.157625 = 72000

111Quantitative Aptitude
A bought a toy at a discount of 35% . If he paid ₹975, then find the marked price of the toy.
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Answer: (D) ₹1,500

Explanation

The relationship between the marked price, discount percentage, and the selling price is given by the formula:

Selling Price = Marked Price × (100 - Discount Percentage) / 100

Given that the selling price is ₹975 and the discount is 35%, we can substitute these values into the formula:

975 = Marked Price × (100 - 35) / 100

975 = Marked Price × 65 / 100

Marked Price = (975 × 100) / 65

Marked Price = 15 × 100

Marked Price = 1500

112Quantitative Aptitude
Calculate the 3ʳᵈ proportional to 14 and 28.
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Answer: (D) 56

Explanation

The third proportional of two numbers a and b is defined as the number x such that a : b = b : x, which simplifies to the formula:

x = b² / a

In this problem, the two given numbers are a = 14 and b = 28. Substituting these values into the formula:

x = 28² / 14 x = (28 × 28) / 14 x = 2 × 28 x = 56

113Quantitative Aptitude
Expand x² + 2x + 3 about x = -2
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Answer: (B) (x + 2)² - 2(x + 2) + 3

Explanation

To expand the polynomial f(x) = x² + 2x + 3 about x = -2, we can perform a simple change of variable. Let y = x + 2, which implies x = y - 2.

Substituting x = y - 2 into the original expression: f(x) = (y - 2)² + 2(y - 2) + 3

Expanding the terms gives: f(x) = (y² - 4y + 4) + (2y - 4) + 3 f(x) = y² - 2y + 3

Substituting y = x + 2 back into the expression yields: f(x) = (x + 2)² - 2(x + 2) + 3

114Quantitative Aptitude
The marked price of 42 items was equal to the cost price of 70 items. The selling price of 25 items was equal to the marked price of 21 items. Calculate the percentage profit or loss from the sale of each item.
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Answer: (D) 40% profit

Explanation

Let CP, MP, and SP be the cost price, marked price, and selling price of a single item, respectively.

According to the first condition: 42 × MP = 70 × CP MP/CP = 70/42 = 5/3 MP = (5/3) × CP

According to the second condition: 25 × SP = 21 × MP SP/MP = 21/25 SP = (21/25) × MP

By substituting the value of MP from the first equation into the second equation: SP = (21/25) × (5/3) × CP SP = (7/5) × CP SP = 1.4 × CP

The profit percentage is calculated using the formula: Profit % = ((SP - CP)/CP) × 100 Profit % = ((1.4 × CP - CP)/CP) × 100 Profit % = 0.4 × 100 = 40% profit

115Quantitative Aptitude
Priya covers a certain distance by her car at a speed of 21 km/h and returns at a speed of 17 km/h. What is her average speed during the travel?
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Answer: (A) 18¹⁵⁄₁₉km / h

Explanation

When a journey covers equal distances at two different speeds, v₁ and v₂, the average speed is calculated using the formula:

Average Speed = 2 × v₁ × v₂ / (v₁ + v₂)

Given that the speed of the car while going is v₁ = 21 km/h and the speed while returning is v₂ = 17 km/h, substitute these values into the formula:

Average Speed = (2 × 21 × 17) / (21 + 17)

Average Speed = 714 / 38

Dividing both the numerator and the denominator by 2 simplifies the fraction to 357 / 19.

Converting 357 / 19 into a mixed fraction: 357 ÷ 19 = 18 with a remainder of 15, which is written as 18 15/19 km/h.

116Quantitative Aptitude
If two supplementary angles differ by 74°, then one of the angles is:
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Answer: (D) 53°

Explanation

Two angles are supplementary when their sum is 180 degrees. Let the two angles be x and y, with x being the larger angle.

According to the given conditions: x + y = 180° x - y = 74°

Subtracting the second equation from the first equation gives: 2y = 180° - 74° 2y = 106° y = 53°

Substituting the value of y back into the first equation: x + 53° = 180° x = 127°

Thus, the two supplementary angles are 127° and 53°. Among the given choices, 53° represents one of these angles.

117Quantitative Aptitude
By selling an article for £255, there is a loss of 15%. When the article is sold for £357, the net result in the transaction is:
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Answer: (A) 19% profit

Explanation

The Cost Price (CP) of the article can be calculated using the formula: CP = Selling Price × 100 / (100 - Loss %)

Given that the Selling Price is £255 and the loss is 15%: CP = 255 × 100 / (100 - 15) CP = 255 × 100 / 85 CP = 3 × 100 = 300

When the article is sold for a new Selling Price of £357, the net result is a profit because the Selling Price is greater than the Cost Price.

Profit = New Selling Price - CP Profit = 357 - 300 = 57

The profit percentage is calculated as: Profit % = (Profit / CP) × 100% Profit % = (57 / 300) × 100% = 19%

118Quantitative Aptitude
The difference between a single discount of 20% and two successive discounts of 16% and 4% on a bill of £50,000 is:
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Answer: (C) £320

Explanation

The difference between a single discount of (x + y)% and two successive discounts of x% and y% on a principal amount P is given by the formula:

Difference = (x × y / 100)% of P

In this case, the single discount of 20% is equal to the sum of the two successive discounts of 16% and 4% (since 16 + 4 = 20).

Here, x = 16, y = 4, and P = 50,000.

Substituting these values into the formula:

Difference = (16 × 4 / 100)% of 50,000 Difference = 0.64% of 50,000 Difference = (0.64 / 100) × 50,000 Difference = 0.64 × 500 Difference = 320

119Quantitative Aptitude
The average weight of 8 men is increased by 2 kg when one of them, whose weight is 90 kg, is replaced by another man. What is the weight of the new man?
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Answer: (D) 106 kg

Explanation

The increase in the average weight of 8 men when one man is replaced is 2 kg. This means the overall sum of the weights of the 8 men increases by:

Total increase = Number of men × Increase in average weight Total increase = 8 × 2 = 16 kg

Since the weight of the replaced man is 90 kg, the weight of the new man must be 16 kg more than this to cause the 16 kg increase in the total weight:

Weight of the new man = Weight of the replaced man + Total increase Weight of the new man = 90 + 16 = 106 kg

120Quantitative Aptitude
Kuldeep offers his customers a discount of 10% on the marked price of a suitcase and he still makes a profit of 20%. What is the actual cost of the suitcase marked for ₹2,500?
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Answer: (B) ₹1,875

Explanation

The relationship between the Cost Price (CP) and the Marked Price (MP) is given by the formula:

CP/MP = (100 - Discount%) / (100 + Profit%)

Substituting the given values: Marked Price (MP) = ₹2,500 Discount% = 10% Profit% = 20%

CP/2500 = (100 - 10) / (100 + 20) CP/2500 = 90/120 CP/2500 = 3/4 CP = 2500 × 3/4 = 1875

121Quantitative Aptitude
Study the table and answer the question. | Age of the child | 5 years | 6 years | 7 years | 8 years | 9 years | |---|---|---|---|---|---| | Weight (in kg) | 20 | 22 | 22 | 27 | 25 | The sum of the weights of which two kids (referred to their ages) exceeds 50 kg?
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Answer: (B) 8 years and 9 years

Explanation

The weight of the child aged 8 years is 27 kg, and the weight of the child aged 9 years is 25 kg. Adding these two values gives:

27 kg + 25 kg = 52 kg

Since 52 kg is greater than 50 kg, the sum of the weights of the children of these two ages exceeds 50 kg.

122Quantitative Aptitude
X does a work in 6 days, while Y does it in 12 days. If they work alternatively and X begins, in how many days will the work be finished?
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Answer: (C) 8

Explanation

Let the total work be the least common multiple of 6 and 12, which is 12 units.

The efficiency of X is 12 ÷ 6 = 2 units per day. The efficiency of Y is 12 ÷ 12 = 1 unit per day.

They work on alternate days, beginning with X: On Day 1, X completes 2 units of work. On Day 2, Y completes 1 unit of work.

Thus, in a 2-day cycle, the total work completed is 2 + 1 = 3 units.

To complete the entire 12 units of work, the number of cycles required is 12 ÷ 3 = 4 cycles.

Since each cycle consists of 2 days, the total time taken to finish the work is 4 × 2 = 8 days.

123Quantitative Aptitude
What should be subtracted from 246837 to make it divisible by 13?
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Answer: (B) 6

Explanation

To find the number that should be subtracted from 246837 to make it divisible by 13, we must find the remainder when 246837 is divided by 13.

Performing the division: 246837 ÷ 13 = 18987 with a remainder of 6

Subtracting this remainder of 6 from the original number yields 246831, which is perfectly divisible by 13 (13 × 18987 = 246831).

124Quantitative Aptitude
The fourth proportional to 14, 21, 28 is:
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Answer: (C) 42

Explanation

If four numbers a, b, c, and d are in proportion, then the ratio of the first two is equal to the ratio of the last two, expressed as a/b = c/d, where d is the fourth proportional to a, b, and c.

Substituting the given values a = 14, b = 21, and c = 28 into the relation:

d = (b × c) / a

d = (21 × 28) / 14

d = 21 × 2

d = 42

125Quantitative Aptitude
After spending 20% of his salary on grocery and 30% of the remainder on monthly house rent, a man is left with £8,400. What is his monthly salary?
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Answer: (D) 15,000

Explanation

Using the successive percentage change formula, the remaining amount after consecutive expenditures is given by:

Remaining Amount = Salary × (1 - r₁) × (1 - r₂)

Here, r₁ = 20% = 0.20 and r₂ = 30% = 0.30.

Substituting the given values:

8400 = Salary × (1 - 0.20) × (1 - 0.30) 8400 = Salary × 0.80 × 0.70 8400 = Salary × 0.56 Salary = 8400 / 0.56 Salary = 840000 / 56 Salary = 15000

126Quantitative Aptitude
A car travelled distances of 10km, 20km and 30km at speeds of 30km / h, 40km / h and 60km / h, respectively. The average speed of the car is:
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Answer: (A) 45 km/h

Explanation

Average speed is defined as the total distance travelled divided by the total time taken.

Total Distance = 10 + 20 + 30 = 60 km

Total Time is the sum of the times taken for each part of the journey: Time 1 = 10 km ÷ 30 km/h = 1/3 h Time 2 = 20 km ÷ 40 km/h = 1/2 h Time 3 = 30 km ÷ 60 km/h = 1/2 h

Total Time = 1/3 + 1/2 + 1/2 = 1/3 + 1 = 4/3 h

Average Speed = Total Distance ÷ Total Time = 60 ÷ (4/3) = 60 × 3/4 = 45 km/h

127Quantitative Aptitude
If x = √(10) +√(11), y = √(10) -√(11), then value of 7x² - 50xy + 7y² =
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Answer: (A) 344

Explanation

To find the value of 7x² - 50xy + 7y², we first calculate the sum and product of x and y.

Sum of x and y: x + y = (√10 + √11) + (√10 - √11) = 2√10

Product of x and y: xy = (√10 + √11)(√10 - √11) = (√10)² - (√11)² = 10 - 11 = -1

We can express x² + y² using the standard algebraic identity: x² + y² = (x + y)² - 2xy x² + y² = (2√10)² - 2(-1) x² + y² = 40 + 2 = 42

Now, substitute these values into the target expression: 7x² - 50xy + 7y² = 7(x² + y²) - 50xy = 7(42) - 50(-1) = 294 + 50 = 344

128Quantitative Aptitude
The distance between stations A and B is 778 kilometres. A train travels from station A to station B at a uniform speed of 84km / h and then returns to station A at a uniform speed of 56km / h. What is the train's average speed (in km/h) throughout the journey?
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Answer: (A) 67.2

Explanation

When a journey covers equal distances at two different speeds, say v₁ and v₂, the average speed for the entire journey is given by the harmonic mean of the speeds, represented by the formula:

Average speed = 2 × v₁ × v₂ / (v₁ + v₂)

Given: v₁ = 84 km/h v₂ = 56 km/h

Substituting these values into the formula:

Average speed = 2 × 84 × 56 / (84 + 56) Average speed = 9408 / 140 Average speed = 67.2 km/h

The distance of 778 km between the stations does not affect the calculation of the average speed since the distance traveled at each speed is equal.

129Quantitative Aptitude
The population of a city increases by 10% annually. If its present population is 21,000, what will be the population in 3 years?
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Answer: (A) 27951

Explanation

The population of the city after n years is calculated using the compound growth formula:

P_future = P × (1 + R/100)ⁿ

Here, the present population P is 21000, the annual growth rate R is 10%, and the time period n is 3 years.

Substituting these values into the formula:

P_future = 21000 × (1 + 10/100)³ P_future = 21000 × (1.1)³ P_future = 21000 × 1.331 P_future = 21 × 1331 P_future = 27951

130Quantitative Aptitude
A motorcycle covers 50 km at a speed of 25 km/h. Find the speed of the motorcycle for the next 50 km of the journey so that the average speed of the whole journey will be 30 km/h.
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Answer: (B) 37.5 km/h

Explanation

When a journey covers two equal distances of 50 km each at different speeds, v₁ and v₂, the average speed of the entire journey is given by the harmonic mean of the two speeds:

Average Speed = 2 × v₁ × v₂ / (v₁ + v₂)

Given that the speed for the first 50 km (v₁) is 25 km/h, the average speed for the whole journey is 30 km/h, and the speed for the next 50 km is v₂:

30 = 2 × 25 × v₂ / (25 + v₂)

30 = 50 × v₂ / (25 + v₂)

3 × (25 + v₂) = 5 × v₂

75 + 3 × v₂ = 5 × v₂

2 × v₂ = 75

v₂ = 37.5 km/h

131Quantitative Aptitude
Which of the following numbers is divisible by 15?
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Answer: (B) 3,06,045

Explanation

A number is divisible by 15 if it is divisible by both 3 and 5.

For a number to be divisible by 5, its last digit must be either 0 or 5. The number 3,06,045 ends in 5, which satisfies this condition.

For a number to be divisible by 3, the sum of its digits must be a multiple of 3. Finding the sum of the digits for 3,06,045: 3 + 0 + 6 + 0 + 4 + 5 = 18

Since 18 is divisible by 3, the number 3,06,045 is also divisible by 3.

Since 3,06,045 is divisible by both 3 and 5, it is divisible by 15.

132Quantitative Aptitude
Among the following options, which are NOT sides of a triangle?
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Answer: (D) 3 cm, 5 cm and 1 cm

Explanation

According to the triangle inequality theorem, the sum of the lengths of any two sides of a triangle must be strictly greater than the length of the remaining side. If we take the two shorter sides, their sum must exceed the length of the longest side.

For the side lengths 3 cm, 5 cm, and 1 cm, the two shorter sides are 3 cm and 1 cm. Their sum is 3 + 1 = 4 cm. Since this sum is less than the longest side of 5 cm, they violate the triangle inequality theorem and cannot form the sides of a triangle.

133Quantitative Aptitude
Arun alone can finish a work in 12 days and Shama alone can do it in 15 days. How much time will be taken to finish the work, if Arun and Shama work together?
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Answer: (D) 6 2/3 days

Explanation

To find the time taken by Arun and Shama to finish the work together, we use the formula for combined work:

T = (A × B) / (A + B)

Here, Arun's time A is 12 days and Shama's time B is 15 days. Substituting these values into the formula gives:

T = (12 × 15) / (12 + 15) T = 180 / 27 T = 20 / 3 days T = 6 2/3 days

134Quantitative Aptitude
Simplify the following expression. 3⁶⁄₇ - {5⅐ - (2³⁄₇ - 3⁵⁄₇ - 4)}
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Answer: (B) 10 7

Explanation

Convert the mixed fractions into improper fractions: 3 6/7 = (3 × 7 + 6)/7 = 27/7 5 1/7 = (5 × 7 + 1)/7 = 36/7 2 3/7 = (2 × 7 + 3)/7 = 17/7 3 5/7 = (3 × 7 + 5)/7 = 26/7 4 = 28/7

The expression can be written as: 27/7 - {36/7 - (17/7 - (26/7 - 28/7))}

Following BODMAS rules, first simplify the innermost part containing the vinculum (bar bracket): 26/7 - 28/7 = -2/7

Now evaluate the expression inside the round brackets: 17/7 - (-2/7) = 17/7 + 2/7 = 19/7

Next, evaluate the expression inside the curly brackets: 36/7 - 19/7 = 17/7

Finally, complete the subtraction: 27/7 - 17/7 = 10/7

135Quantitative Aptitude
If a + b = 2c , then the value of (a)/(a - c) +(c)/(b - c) is:
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Answer: (B) 1

Explanation

From the given equation: a + b = 2c

We can rearrange the terms to establish a relationship between the variables: a - c = c - b

Multiplying both sides by -1 gives: b - c = -(a - c)

Substitute this relationship directly into the expression to find its value: a / (a - c) + c / (b - c)

Replacing the term (b - c) with -(a - c) in the denominator: a / (a - c) + c / (-(a - c)) = a / (a - c) - c / (a - c) = (a - c) / (a - c) = 1

136Quantitative Aptitude
The average runs of a cricket player in 20 matches is 30. If the average of the first 12 matches is 40, find the average of the last 8 matches.
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Answer: (B) 15

Explanation

The sum of runs in all 20 matches is: 20 × 30 = 600

The sum of runs in the first 12 matches is: 12 × 40 = 480

The sum of runs in the remaining 8 matches is: 600 - 480 = 120

The average of the last 8 matches is: 120 ÷ 8 = 15

137Quantitative Aptitude
The following table shows the number of students of seven colleges participating in extra-curricular activities. Study the table and answer the question that follows. College → A B C D E F G Extra-Curricular Activities I 150 250 450 50 350 250 150 II 50 150 150 50 50 50 50 III 100 50 400 125 100 500 150 IV 250 125 350 275 250 150 150 The colleges in which the minimum number of students participate in extra-curricular activities are:
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Answer: (C) D and G

Explanation

To find the colleges with the minimum number of participating students, the total number of participants across all four extra-curricular activities is calculated for each college.

The sum for College D is 50 + 50 + 125 + 275 = 500.

The sum for College G is 150 + 50 + 150 + 150 = 500.

The sum for College A is 150 + 50 + 100 + 250 = 550, while College B has a sum of 250 + 150 + 50 + 125 = 575. College C has a sum of 450 + 150 + 400 + 350 = 1350, College E has a sum of 350 + 50 + 100 + 250 = 750, and College F has a sum of 250 + 50 + 500 + 150 = 950.

College D and College G have the lowest overall student participation with 500 students each.

138Quantitative Aptitude
Find the volume of the cuboid, if its length is twice more than its breadth and its breadth is 8cm , which is twice its height.
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Answer: (A) 768cm³

Explanation

The volume of a cuboid is calculated using the formula: V = l × b × h where l is the length, b is the breadth, and h is the height.

The breadth (b) is given as 8 cm.

Since the breadth is twice the height (b = 2h), the height is: h = 8 / 2 = 4 cm

The length (l) is twice more than its breadth, which means it is equal to the breadth plus twice the breadth: l = b + 2b = 3b = 3 × 8 = 24 cm

Now, substituting these values to find the volume: Volume = 24 × 8 × 4 = 768 cm³

139Quantitative Aptitude
If x - ¹⁄ₓ = 11 and x > 0 , what is the value of (x² - (1)/(x²))?
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Answer: (B) 55√5

Explanation

We are given x - 1/x = 11 and x > 0.

Using the algebraic identity: (x + 1/x)² = (x - 1/x)² + 4

Substitute the given value: (x + 1/x)² = 11² + 4 (x + 1/x)² = 121 + 4 = 125

Since x > 0, the sum x + 1/x must be positive: x + 1/x = √125 = 5√5

Now, using the difference of squares identity: x² - 1/x² = (x - 1/x)(x + 1/x)

Substitute the known values: x² - 1/x² = 11 × 5√5 = 55√5

140Quantitative Aptitude
The ratio of the cost price to the marked price of an article is 4 : 7. A discount of 25% is given on the marked price and the shopkeeper made a profit of ₹50. Find the cost price of the article.
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Answer: (A) ₹160

Explanation

Let the cost price and the marked price of the article be 4x and 7x respectively.

Since a discount of 25% is offered on the marked price, the selling price is 75% of the marked price: Selling Price = 7x × 0.75 = 5.25x

The profit earned by the shopkeeper is the difference between the selling price and the cost price: Profit = 5.25x - 4x = 1.25x

Equating this to the given profit of ₹50: 1.25x = 50 x = 40

Substituting the value of x to find the cost price: Cost Price = 4 × 40 = 160

141Quantitative Aptitude
A shopkeeper claims that he is selling sugar at Rs.27/kg which cost him Rs.30/kg, but he gives 750 grams instead of 1000 grams. What is his profit or loss percentage?
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Answer: (D) 20% profit

Explanation

The cost price of 1000 g of sugar is ₹30. Since the shopkeeper gives 750 g instead of 1000 g, the actual cost price incurred by him is only for 750 g.

Actual Cost Price of 750 g sugar = (30 ÷ 1000) × 750 = ₹22.50

The selling price for this quantity is ₹27.

Actual Selling Price = ₹27

Profit = Selling Price - Cost Price = 27 - 22.50 = ₹4.50

Profit percentage = (Profit ÷ Cost Price) × 100 = (4.50 ÷ 22.50) × 100 = 20%

142Quantitative Aptitude
Two trains having lengths of 230 m and 240 m are 130 m apart. They start moving towards each other on parallel tracks, at speeds of 160 km/h and 200 km/h, respectively. In how much time will the trains cross each other?
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Answer: (B) 6 sec

Explanation

When two objects move towards each other, their relative speed is the sum of their individual speeds.

Relative Speed = 160 km/h + 200 km/h = 360 km/h

Converting the relative speed into m/s: 360 × 5/18 = 100 m/s

To completely cross each other, the total distance they must cover together is the sum of their lengths and the initial distance separating them: Total Distance = 230 m + 240 m + 130 m = 600 m

Using the formula Time = Distance / Speed: Time = 600 / 100 = 6 seconds

143Quantitative Aptitude
40% of the cost price of an article is equal to 30% of its selling price. The approximate percentage of profit or loss on the cost price is:
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Answer: (D) 33.33% profit

Explanation

Let the Cost Price of the article be CP and the Selling Price be SP.

According to the given condition: 40% of CP = 30% of SP

This equation can be written as: 0.40 × CP = 0.30 × SP

By simplifying the relation, we get: 4 × CP = 3 × SP SP / CP = 4/3

This ratio indicates that if the Cost Price is 3 units, the Selling Price is 4 units. Since the Selling Price is greater than the Cost Price, there is a profit.

Profit = SP - CP = 4 - 3 = 1 unit

The profit percentage is calculated on the Cost Price: Profit percentage = (Profit / CP) × 100 Profit percentage = (1/3) × 100 ≈ 33.33%

144Quantitative Aptitude
Find the radius of the circle x² + y² - 4x + 6y = 12 .
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Answer: (C) 5

Explanation

The standard equation of a circle is x² + y² + 2gx + 2fy + c = 0, where the radius r is given by the formula r = √(g² + f² - c).

Comparing the given equation x² + y² - 4x + 6y - 12 = 0 with the standard equation, we get: 2g = -4, which gives g = -2 2f = 6, which gives f = 3 c = -12

Substituting these values into the radius formula: r = √((-2)² + 3² - (-12)) r = √(4 + 9 + 12) r = √25 r = 5

145Quantitative Aptitude
In what time will 3,90,625 amount to 4,56,976 at 8 % per annum, interest being compounded half-yearly?
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Answer: (A) 2 years

Explanation

The formula for the amount under half-yearly compound interest is:

A = P × (1 + R / 200)ⁿ

where A is the amount, P is the principal, R is the annual interest rate, and n is the number of half-years.

Substituting the given values into the formula:

4,56,976 = 3,90,625 × (1 + 8 / 200)ⁿ

4,56,976 / 3,90,625 = (1 + 1 / 25)ⁿ

4,56,976 / 3,90,625 = (26 / 25)ⁿ

Expressing the fraction on the left side with base 26/25:

25⁴ = 3,90,625 26⁴ = 4,56,976

So, (26 / 25)⁴ = (26 / 25)ⁿ

Comparing the exponents gives n = 4 half-years.

Since there are 2 half-years in a year, the time period is 4 / 2 = 2 years.

146Quantitative Aptitude
Find the compound interest on 1,60,000 at 10% per annum for 2 years if the interest is compounded half-yearly.
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Answer: (B) 34,481

Explanation

When interest is compounded half-yearly, the rate of interest is halved and the number of compounding periods is doubled.

Here, Principal (P) is 1,60,000, the annual rate (R) is 10%, and the time (t) is 2 years.

The half-yearly interest rate (r) is 10% / 2 = 5%. The number of compounding periods (n) is 2 × 2 = 4.

The formula for compound interest (CI) is: CI = P × ((1 + r/100)ⁿ - 1)

Substituting the given values into the formula: CI = 1,60,000 × ((1 + 5/100)⁴ - 1) CI = 1,60,000 × ((21/20)⁴ - 1) CI = 1,60,000 × (194481/160000 - 1) CI = 1,60,000 × (34481/160000) CI = 34,481

147Quantitative Aptitude
A, B and C can do a work in 5 days, 6 days and 10 days, respectively. Working together, in how many days will they finish the same work?
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Answer: (A) 2⅐

Explanation

To find the time taken when they work together, we first determine the total work by taking the Least Common Multiple (LCM) of the individual days, which are 5, 6, and 10.

LCM(5, 6, 10) = 30 units.

The efficiency (work done per day) of each person is: Efficiency of A = 30 ÷ 5 = 6 units/day Efficiency of B = 30 ÷ 6 = 5 units/day Efficiency of C = 30 ÷ 10 = 3 units/day

The combined efficiency of A, B, and C working together is: 6 + 5 + 3 = 14 units/day

The number of days they will take to finish the work together is: Total work ÷ Combined efficiency = 30 ÷ 14 = 15/7 = 2 1/7 days.

148Quantitative Aptitude
The diameter of the base of a right-circular cylinder is 12 cm and the height of the cylinder is 2.45 times the radius of its base. Find the volume of the cylinder. [Use π = ²²⁄₇ ]
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Answer: (C) 1663.2 cm³

Explanation

The radius of the base of the cylinder is half of its diameter, so r = 12 ÷ 2 = 6 cm.

The height of the cylinder is 2.45 times its radius, which gives h = 2.45 × 6 = 14.7 cm.

The volume of a right-circular cylinder is calculated using the formula V = πr²h.

Substituting the given values into the formula with π = 22/7:

V = (22/7) × 6² × 14.7

V = (22/7) × 36 × 14.7

V = 22 × 36 × 2.1

V = 792 × 2.1

V = 1663.2 cm³

149Quantitative Aptitude
If y varies directly with x, and y = 61 when x = 42 , find y when x = 54 (consider integral value).
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Answer: (B) 78

Explanation

Since y varies directly with x, their relationship is defined by the direct variation formula:

y₁ / x₁ = y₂ / x₂

Substituting the given values into the equation:

61 / 42 = y₂ / 54

Solving for y₂:

y₂ = (61 × 54) / 42

y₂ = (61 × 9) / 7

y₂ = 549 / 7

y₂ ≈ 78.43

Considering the nearest integral value, y is equal to 78.

150Quantitative Aptitude
What is the area of an equilateral triangle whose each sides is 12 cm ?
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Answer: (A) 36√3cm²

Explanation

The area of an equilateral triangle with side length a is given by the formula:

Area = (√3 / 4) × a²

Substituting the given side length a = 12 cm into the formula:

Area = (√3 / 4) × 12 × 12 Area = √3 × 3 × 12 Area = 36√3 cm²

Answer key

Tap a number to jump to that question.

  1. 101A
  2. 102D
  3. 103A
  4. 104C
  5. 105C
  6. 106B
  7. 107C
  8. 108B
  9. 109A
  10. 110D
  11. 111D
  12. 112D
  13. 113B
  14. 114D
  15. 115A
  16. 116D
  17. 117A
  18. 118C
  19. 119D
  20. 120B
  21. 121B
  22. 122C
  23. 123B
  24. 124C
  25. 125D
  26. 126A
  27. 127A
  28. 128A
  29. 129A
  30. 130B
  31. 131B
  32. 132D
  33. 133D
  34. 134B
  35. 135B
  36. 136B
  37. 137C
  38. 138A
  39. 139B
  40. 140A
  41. 141D
  42. 142B
  43. 143D
  44. 144C
  45. 145A
  46. 146B
  47. 147A
  48. 148C
  49. 149B
  50. 150A

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