SSC CHSL2016Quantitative AptitudePage 18 of 34

SSC CHSL Tier 1 2016 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 851–900 of 1,696, each with the correct answer and a step-by-step explanation.

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851Quantitative Aptitude
If x - y = 7 and xy = 32, then value of (x² + y²) is
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Answer: (C) 113

Explanation

By using the algebraic identity: (x - y)² = x² + y² - 2xy

We can rewrite the equation to solve for x² + y²: x² + y² = (x - y)² + 2xy

Substituting the given values, x - y = 7 and xy = 32, into the equation: x² + y² = 7² + 2(32) x² + y² = 49 + 64 x² + y² = 113

852Quantitative Aptitude
A wholesaler sells a watch to a retailer at a profit of 33% and the retailer sells it to a customer at a loss of 20%. If the customer pays Rs 2,181.2, what had it cost the wholesaler?
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Answer: (A) Rs 2050

Explanation

Let the cost price of the watch for the wholesaler be CP.

According to the given transaction details, the wholesaler sells the watch to the retailer at a profit of 33%, and the retailer sells it to the customer at a loss of 20%.

Using the formula for successive percentage changes: Final Price = CP × (1 + Profit%/100) × (1 - Loss%/100)

Substituting the given values: 2181.2 = CP × (1 + 33/100) × (1 - 20/100) 2181.2 = CP × 1.33 × 0.80 2181.2 = CP × 1.064

Solving for CP: CP = 2181.2 / 1.064 CP = 2050

Therefore, the cost to the wholesaler was Rs 2050.

853Quantitative Aptitude
Product of digits of a 2-digit number is 12. If we add 36 to the number, the new number obtained is a number formed by interchange of the digits. What is the number.
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Answer: (C) 26

Explanation

Let the tens digit of the two-digit number be x and the units digit be y. The original number is 10x + y.

The product of the digits is given as xy = 12.

When 36 is added to the number, the digits are reversed to form the number 10y + x: (10x + y) + 36 = 10y + x 9y - 9x = 36 y - x = 4 y = x + 4

Substituting y = x + 4 into the product equation: x(x + 4) = 12 x² + 4x - 12 = 0 (x + 6)(x - 2) = 0

Since the digits of a number must be positive integers, x = 2.

Using y = x + 4, the units digit y is 6.

This gives the original number as 26.

854Quantitative Aptitude
If csc π/4 - sin π/3 = x, then the value of x is
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Answer: (B) (2√2-√3)/2

Explanation

The trigonometric values of the given angles are:

csc π/4 = √2 sin π/3 = √3/2

Substituting these values into the given equation:

x = csc π/4 - sin π/3 x = √2 - √3/2

Taking the common denominator of 2:

x = (2√2 - √3)/2

This directly yields the value of x.

855Quantitative Aptitude
If √(sec²A - 1)/secA = x, then the value of x is
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Answer: (C) sinA

Explanation

Using the fundamental trigonometric identity: sec²A - 1 = tan²A

Taking the square root: √(sec²A - 1) = tanA

Substitute this into the given expression: x = tanA / secA

Since tanA = sinA / cosA and secA = 1 / cosA, we have: x = (sinA / cosA) / (1 / cosA) x = sinA

856Quantitative Aptitude
A solid right circular cone of radius 4 cm and height 7 cm is put inside a cylindrical vessel of radius 5 cm and height 8 cm. How much water in cubic cm will be required to fill the cylindrical vessel completely?
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Answer: (C) 511.24 cubic cms

Explanation

The volume of water required to fill the cylindrical vessel completely is equal to the difference between the volume of the cylindrical vessel and the volume of the solid right circular cone.

The volume of a cylinder is given by the formula: Volume of cylinder = π × r₁² × h₁

Using the radius of the cylinder r₁ = 5 cm and height h₁ = 8 cm: Volume of cylinder = π × 5² × 8 = 200π cubic cm

The volume of a cone is given by the formula: Volume of cone = 1/3 × π × r₂² × h₂

Using the radius of the cone r₂ = 4 cm and height h₂ = 7 cm: Volume of cone = 1/3 × π × 4² × 7 = 112π / 3 cubic cm

The volume of water required is: Volume of water = 200π - 112π / 3 = 488π / 3 cubic cm

Using the value of π = 22/7: Volume of water = 488/3 × 22/7 = 10736 / 21 ≈ 511.24 cubic cm

857Quantitative Aptitude
If the amount received at the end of 2nd and 3rd year at Compound Interest on a certain Principal is Rs 24200, and Rs 26620 respectively, what is the rate of interest?
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Answer: (A) 10 percent

Explanation

In compound interest, the amount at the end of any year acts as the principal for the succeeding year. The relationship between the amounts at the end of the consecutive second and third years is:

A₃ = A₂ × (1 + R/100)

Here, the amount at the end of the second year A₂ = 24200 and the amount at the end of the third year A₃ = 26620. Substituting these values into the formula:

26620 = 24200 × (1 + R/100)

1 + R/100 = 26620 / 24200

1 + R/100 = 11 / 10

R/100 = 11/10 - 1

R/100 = 1/10

R = 10%

858Quantitative Aptitude
Two numbers are 50% and 80% lesser than a third number. By how much percent is the second number to be enhanced to make it equal to the first number?
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Answer: (A) 150 percent

Explanation

Let the third number be 100.

Since the first number is 50% lesser than the third number, the first number is 100 - 50 = 50.

Since the second number is 80% lesser than the third number, the second number is 100 - 80 = 20.

To make the second number equal to the first number, it must be increased by 50 - 20 = 30.

The required percentage increase is (30 / 20) × 100% = 150%.

859Quantitative Aptitude
Manoj can do a piece of work in 42 hours. If he is joined by Jayashree who is 100% more efficient, in what time they will finish the work together?
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Answer: (C) 14 hours

Explanation

Let Manoj's efficiency be 1 unit of work per hour. Since Manoj completes the work in 42 hours, the total work is 42 units.

Jayashree is 100% more efficient than Manoj, which means her efficiency is twice that of Manoj. Therefore, Jayashree's efficiency is 2 units of work per hour.

When working together, their combined efficiency is the sum of their individual efficiencies, which is 1 + 2 = 3 units of work per hour.

The time taken by both of them to finish the work together is calculated by dividing the total work by their combined efficiency, which gives 42 ÷ 3 = 14 hours.

860Quantitative Aptitude
The measures of the three angles of a triangle are in the ratio 1:2:3. What is the measure of the biggest angle?
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Answer: (C) 90°

Explanation

The sum of the interior angles of a triangle is always 180°.

Let the measures of the three angles be x, 2x, and 3x based on the ratio 1:2:3.

Using the angle sum property of a triangle: x + 2x + 3x = 180° 6x = 180° x = 30°

The measure of the biggest angle is 3x: 3 × 30° = 90°

861Quantitative Aptitude
The average revenues of 13 consecutive years of a company is Rs 70 lakhs. If the average of first 7 years is Rs 65 lakhs and that of last 7 years is Rs 77 lakhs, find the revenue for the 7th year.
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Answer: (B) Rs 84 lakhs

Explanation

The total revenue for all 13 years is obtained by multiplying the number of years by their average: 13 × 70 = 910 lakhs

The sum of the revenues for the first 7 years is: 7 × 65 = 455 lakhs

The sum of the revenues for the last 7 years is: 7 × 77 = 539 lakhs

In this calculation, the 7th year is included in both the first 7 years and the last 7 years. Therefore, adding these two sums counts the 7th year twice. The revenue of the 7th year is calculated by subtracting the total 13-year revenue from the sum of the first 7 and last 7 years: (455 + 539) - 910 = 994 - 910 = 84 lakhs

862Quantitative Aptitude
Profit of Rs 144000 has to be divided among three partners Akram, Bipin and Chintan in the ratio 3:2:7. How much Rs. Chintan get?
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Answer: (A) 84000

Explanation

To find Chintan's share of the profit, use the ratio division formula:

Share = (Individual ratio term / Sum of all ratio terms) × Total profit

The ratio of profit sharing among Akram, Bipin, and Chintan is 3:2:7.

Sum of the ratio terms = 3 + 2 + 7 = 12

The total profit is ₹144000.

Chintan's share = (7 / 12) × 144000

Chintan's share = 7 × 12000 = 84000

863Quantitative Aptitude
Area of ______ equals half the product of its diagonal.
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Answer: (C) Kite

Explanation

The area of a kite with diagonals of lengths d₁ and d₂ is calculated using the formula:

Area = ½ × d₁ × d₂

Since the diagonals of a kite intersect at right angles (90°), the kite can be split into two triangles by one of its diagonals. The area of the kite is the sum of the areas of these two triangles, which simplifies directly to half the product of the diagonals.

864Quantitative Aptitude
The costs of daily ticket of local train is Rs. 50 and Monthly Pass costs is Rs. 1125. If I buy the Monthly Pass and travel for 30 days in a month then I save?
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Answer: (B) 25 percent

Explanation

Total cost of daily tickets for 30 days = 30 × 50 = 1500

Cost of the Monthly Pass = 1125

Total savings = 1500 - 1125 = 375

Percentage savings = (Total savings / Total cost of daily tickets) × 100 = (375 / 1500) × 100 = 25%

865Quantitative Aptitude
Refer the below data table and answer the following Question. Weight (kg) Height (m) Apeksha 59 1.8 Apsara 51 1.72 Aradhana 62 1.57 Archana 74 1.68 Who has the least weight to height ratio?
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Answer: (B) Apsara

Explanation

The weight to height ratio is calculated by dividing the weight in kg by the height in meters.

Calculating the ratio for each person:

Apeksha: 59 / 1.8 = 32.78 kg/m

Apsara: 51 / 1.72 = 29.65 kg/m

Aradhana: 62 / 1.57 = 39.49 kg/m

Archana: 74 / 1.68 = 44.05 kg/m

Apsara has the least weight to height ratio of 29.65 kg/m.

866Quantitative Aptitude
Refer the below data table and answer the following Question. Year Company's % Profit 2011 15 2012 5 2013 10 2014 25 2015 15 What was the revenue of the company if its expenditure was Rs 525 crore in the year when its % profit was the least?
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Answer: (D) 551.25

Explanation

The year with the least percentage profit is 2012, where the profit is 5%.

The formula relating profit percentage, revenue, and expenditure is: Profit % = (Revenue - Expenditure) / Expenditure × 100

Rearranging the formula to solve for Revenue gives: Revenue = Expenditure × (1 + Profit % / 100)

Substituting the given expenditure of Rs 525 crore and the profit of 5% into the equation: Revenue = 525 × (1 + 5 / 100) Revenue = 525 × 1.05 Revenue = 551.25 crore

867Quantitative Aptitude
The following table shows the number of children in each house of a society. Number of Children Number of Houses 0 7 1 7 2 13 3 3 What is the average number of children per house?
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Answer: (B) 1.4

Explanation

The average number of children per house is calculated using the formula for the weighted mean:

Average = ∑(x × f) / ∑ f

where x represents the number of children and f represents the number of houses.

First, calculate the total number of houses: ∑ f = 7 + 7 + 13 + 3 = 30

Next, calculate the total number of children: ∑(x × f) = (0 × 7) + (1 × 7) + (2 × 13) + (3 × 3) = 0 + 7 + 26 + 9 = 42

Dividing the total number of children by the total number of houses gives: Average = 42 ÷ 30 = 1.4

868Quantitative Aptitude
Refer the below data table and answer the following Question. Partners Present % share Anand 20 Basu 5 Chinmay 25 Dhiraj 20 Ejaz 30 If the company has issued 6 lakh shares between its five partners and if Chinmay offers to sell 15,000 of his shares to Dhiraj, then Dhiraj will have how many shares?
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Answer: (B) 135000 shares

Explanation

Dhiraj's initial shareholding is 20% of the total issued shares. Since the company has issued 6,00,000 shares, Dhiraj's initial number of shares is calculated as:

Initial shares = 20% of 6,00,000 = 0.20 × 6,00,000 = 1,20,000 shares

When Chinmay sells 15,000 of his shares to Dhiraj, Dhiraj's total shares increase by 15,000:

Final shares = 1,20,000 + 15,000 = 1,35,000 shares

869Quantitative Aptitude
What are the co-ordinates of the centroid of a triangle, whose vertices are A(-2,5), B(3,-2) and C(5,3)?
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Answer: (C) (2,2)

Explanation

The centroid of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is calculated using the formula:

(x, y) = ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3)

Substituting the coordinates of the given vertices A(-2,5), B(3,-2), and C(5,3) into the formula:

x-coordinate = (-2 + 3 + 5)/3 = 6/3 = 2

y-coordinate = (5 + (-2) + 3)/3 = 6/3 = 2

870Quantitative Aptitude
Ravindra walks at 6 km/hr and Riya cycles at 11 km/hr towards each other. What was the distance between them when they started if they meet after 42 minutes?
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Answer: (D) 11.9 kms

Explanation

When two objects move towards each other, their relative speed is the sum of their individual speeds.

Relative speed = 6 km/hr + 11 km/hr = 17 km/hr

The time given is 42 minutes. Converting this into hours: Time = 42 / 60 hours = 0.7 hours

The initial distance between them is the product of their relative speed and the time taken to meet: Distance = Relative speed × Time = 17 km/hr × 0.7 hours = 11.9 km

871Quantitative Aptitude
If cot 135° = x, then the value of x is
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Answer: (C) -1

Explanation

The value of cot 135° can be calculated using the trigonometric identity cot(180° - θ) = -cot θ.

Substituting θ = 45°: cot 135° = cot(180° - 45°) = -cot 45°

Since cot 45° = 1: cot 135° = -1

Thus, the value of x is -1.

872Quantitative Aptitude
The slopes of two lines are 1/√3 and √3. What is the angle between these two lines?
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Answer: (D) 30°

Explanation

The angle θ between two lines with slopes m₁ and m₂ is given by the formula:

tan θ = |(m₂ - m₁) / (1 + m₁ m₂)|

Given the slopes of the two lines: m₁ = 1/√3 m₂ = √3

Substituting these values into the formula:

tan θ = |(√3 - 1/√3) / (1 + √3 × 1/ √3)|

The numerator simplifies to: √3 - 1/√3 = (3 - 1) / √3 = 2/ √3

The denominator simplifies to: 1 + √3 × 1/√3 = 1 + 1 = 2

Now, compute tan θ: tan θ = (2/√3) / 2 = 1/ √3

Since tan 30° = 1/ √3, the angle between the two lines is 30°.

873Quantitative Aptitude
If √((1 - cos²A))/cos A = x, then the value of x is
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Answer: (C) tanA

Explanation

Using the fundamental trigonometric identity, sin²A + cos²A = 1, we can rewrite the term inside the square root as:

sin²A = 1 - cos²A

Taking the square root on both sides gives:

√(1 - cos²A) = sin A

Substituting this back into the original expression for x:

x = sin A / cos A

Using the quotient identity of trigonometry, the ratio of sin A to cos A is equal to tan A:

x = tan A

874Quantitative Aptitude
If x + 2(3-5x) > -1 - 2x < 5 - x/3; then the value of x is
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Answer: (A) -3

Explanation

The given expression consists of two inequalities that must be solved simultaneously.

First, solve the inequality: x + 2(3-5x) > -1 - 2x

Expanding and simplifying both sides: x + 6 - 10x > -1 - 2x -9x + 6 > -1 - 2x -7x > -7

Dividing by -7 and reversing the inequality sign: x < 1

Second, solve the inequality: -1 - 2x < 5 - x/3

Multiplying the entire inequality by 3 to clear the fraction: -3 - 6x < 15 - x -5x < 18

Dividing by -5 and reversing the inequality sign: x > -18/5 x > -3.6

Combining both results, x must satisfy the range: -3.6 < x < 1

Among the given options, only -3 lies within this range.

875Quantitative Aptitude
An angle is four times its complementary angle. What is the measure of the angle?
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Answer: (A) 72°

Explanation

Let the measure of the angle be x.

Two angles are complementary if their sum is 90°. Therefore, the complementary angle of x is 90° - x.

Based on the given condition: x = 4(90° - x) x = 360° - 4x 5x = 360° x = 72°

876Quantitative Aptitude
In a Kite ____.
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Answer: (A) One diagonal bisects the other

Explanation

A kite is a quadrilateral with two pairs of equal-length adjacent sides. The diagonal connecting the vertices where the unequal sides meet acts as a line of symmetry. This axis of symmetry perpendicularly bisects the other diagonal, which means that one diagonal of a kite always bisects the other.

877Quantitative Aptitude
Akhilesh is two times as good a workman as Bansi and therefore is able to finish a job in 39 days less than Bansi. Working together, they can do it in
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Answer: (C) 26 days

Explanation

If a person A is n times as efficient as person B and completes a work in d days less than B, the time taken by both of them working together is given by the formula: Time together = n × d / (n² - 1)

Given that Akhilesh is n = 2 times as efficient as Bansi and finishes the job in d = 39 days less than Bansi, the time taken working together is: Time together = 2 × 39 / (2² - 1) = 78 / 3 = 26 days

878Quantitative Aptitude
If (4x - 3) = (3x + 8), then the numerical value of (x + 1)³ is
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Answer: (C) 1728

Explanation

To find the value of x, solve the given linear equation: 4x - 3 = 3x + 8

Subtracting 3x from both sides: x - 3 = 8

Adding 3 to both sides: x = 11

Substitute the value of x into the expression (x + 1)³: (x + 1)³ = (11 + 1)³ = 12³

Calculating the cube of 12: 12³ = 12 × 12 × 12 = 1728

879Quantitative Aptitude
The sum of all prime numbers between 58 and 62 is
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Answer: (C) 120

Explanation

The prime numbers between 58 and 62 are 59 and 61. The sum of these prime numbers is 59 + 61 = 120.

880Quantitative Aptitude
25% discount is offered on an item. By applying a promo code the customer wins 22% cash back. What is the effective discount?
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Answer: (A) 41.5 percent

Explanation

Let the marked price of the item be 100 units.

After applying the initial 25% discount, the price of the item becomes: 100 - 25% of 100 = 75 units

The customer then gets 22% cash back on this discounted price of 75 units. Cash back amount = 22% of 75 = (22 / 100) × 75 = 16.5 units

The final price paid by the customer is: 75 - 16.5 = 58.5 units

The total savings from the initial price of 100 units is: 100 - 58.5 = 41.5 units

This represents an effective discount of: (41.5 / 100) × 100% = 41.5%

881Quantitative Aptitude
39 is 5.2% of?
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Answer: (B) 750

Explanation

To find the number, use the standard percentage formula:

Value = (Percentage / 100) × Base

Let the unknown base number be x. Substituting the given values into the formula:

39 = (5.2 / 100) × x

Rearranging the terms to solve for x:

x = (39 × 100) / 5.2

x = 3900 / 5.2

Multiplying both the numerator and the denominator by 10 to eliminate the decimal:

x = 39000 / 52

Simplifying the fraction by dividing both numbers by 13:

x = 3000 / 4

x = 750

882Quantitative Aptitude
A sum fetched a total simple interest of Rs. 8100 at the rate of 6% per year in 9 years. What is the sum?
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Answer: (A) Rs 15000

Explanation

The simple interest is calculated using the standard formula SI = (P × R × T) / 100, where P represents the principal sum, R represents the annual rate of interest, and T represents the time period in years.

Substituting the given values into this formula: 8100 = (P × 6 × 9) / 100

8100 = 54P / 100

P = (8100 × 100) / 54

P = 150 × 100

P = 15000

883Quantitative Aptitude
The first and last terms of an arithmetic progression are 29 and -49. If the sum of the series is -140, then it has how many terms?
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Answer: (B) 14

Explanation

The sum of an arithmetic progression is given by the formula S = (n/2) × (a + l), where S is the sum of the series, n is the number of terms, a is the first term, and l is the last term.

Substituting the given values, first term a = 29, last term l = -49, and sum S = -140:

-140 = (n/2) × (29 - 49) -140 = (n/2) × (-20) -140 = n × (-10) n = 14

884Quantitative Aptitude
The average weight of Sudesh, Jyothi and Ritu is 89 kg. If the average weight of Sudesh and Jyothi be 98 kg and that of Jyothi and Ritu be 83 kg, then the weight of Jyothi is
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Answer: (C) 95

Explanation

Sum of the weights of Sudesh, Jyothi, and Ritu = 89 × 3 = 267 kg

Sum of the weights of Sudesh and Jyothi = 98 × 2 = 196 kg

Sum of the weights of Jyothi and Ritu = 83 × 2 = 166 kg

Adding the two-person sum values together: (Sudesh + Jyothi) + (Jyothi + Ritu) = 196 + 166 = 362 kg Sudesh + 2 × Jyothi + Ritu = 362 kg

Subtracting the sum of all three individuals from this equation isolates the weight of Jyothi: Jyothi = (Sudesh + 2 × Jyothi + Ritu) - (Sudesh + Jyothi + Ritu) Jyothi = 362 - 267 = 95 kg

885Quantitative Aptitude
By increasing the price of entry ticket to a fair in the ratio 7:17, the number of visitors to the fair has decreased in the ratio 9:5. In what ratio has the total collection increased or decreased?
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Answer: (C) increased in the ratio 63:85

Explanation

Total collection is the product of the ticket price and the number of visitors.

Let the initial price of the entry ticket be 7p and the increased price be 17p. Let the initial number of visitors be 9v and the decreased number of visitors be 5v.

Initial collection = 7p × 9v = 63pv New collection = 17p × 5v = 85pv

Ratio of initial collection to new collection = 63pv : 85pv = 63 : 85

Since 85 is greater than 63, the total collection has increased in the ratio 63:85.

886Quantitative Aptitude
What is the value of √([(1 - sin A)/(1 + sin A)])?
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Answer: (C) cos A/(1 + sin A)

Explanation

To simplify the expression √((1 - sin A)/(1 + sin A)), multiply both the numerator and the denominator inside the square root by (1 + sin A):

√(((1 - sin A)(1 + sin A))/((1 + sin A)(1 + sin A)))

Using the trigonometric identity 1 - sin² A = cos² A in the numerator:

√((1 - sin² A)/(1 + sin A)²) = √(cos² A/(1 + sin A)²)

Taking the square root of both the numerator and the denominator:

cos A/(1 + sin A)

887Quantitative Aptitude
Raghuram sells a machine for Rs 43 lakhs at a loss. Had he sold it for Rs 53 lakh, his gain would have been 7 times the former loss. Find the cost price of the machine.
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Answer: (D) Rs 44.25 lakhs

Explanation

Let the cost price of the machine be CP lakhs.

When the machine is sold for Rs 43 lakhs, the loss is: Loss = CP - 43

When the machine is sold for Rs 53 lakhs, the gain is: Gain = 53 - CP

The problem states that the gain is 7 times the former loss: Gain = 7 × Loss 53 - CP = 7 × (CP - 43) 53 - CP = 7CP - 301 8CP = 354 CP = 354 / 8 = 44.25 lakhs

888Quantitative Aptitude
Refer the below data table and answer the following Question. Division / Std Boys Girls Division A / Standard 5 30 30 Division B / Standard 5 30 35 Division C / Standard 5 25 10 Division A / Standard 6 30 10 Division B / Standard 6 40 30 Division C / Standard 6 20 40 What is the ratio of boys to girls?
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Answer: (B) 35 : 31

Explanation

To find the ratio of boys to girls, calculate the total number of boys and the total number of girls across all divisions.

Total number of boys = 30 + 30 + 25 + 30 + 40 + 20 = 175 Total number of girls = 30 + 35 + 10 + 10 + 30 + 40 = 155

The ratio of boys to girls is 175 : 155. Dividing both terms by their greatest common divisor, which is 5, yields 35 : 31.

889Quantitative Aptitude
Refer the below data table and answer the following Question. Marks Number of students 40 and above 10 30 and above 40 20 and above 69 10 and above 81 0 and above 102 How many students have scored marks 20 or more but less than 40?
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Answer: (D) 59

Explanation

The number of students who have scored marks 20 or more but less than 40 is calculated by finding the difference between the number of students who scored 20 and above and those who scored 40 and above.

From the given data table: Number of students scoring 20 and above = 69 Number of students scoring 40 and above = 10

Subtracting the number of students scoring 40 and above from the number of students scoring 20 and above gives: 69 - 10 = 59

890Quantitative Aptitude
Refer the below data table and answer the following Question. Year GDP growth rate for the year (in %) 2011 3 2012 -7 2013 -7 2014 4 2015 3 If the GDP of the country was $1 trillion at the end of 2013, what was it at the beginning of 2015?
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Answer: (B) $1.04 trillion

Explanation

The GDP at the beginning of 2015 is equivalent to the GDP at the end of 2014.

Using the percentage increase formula:

Value_new = Value_initial × (1 + r/100)

Here, the initial value is the GDP at the end of 2013, which is 1 trillion. The growth rate r during the year 2014 is 4%.

GDP at the beginning of 2015 = 1 trillion × (1 + 4/100) = 1.04 trillion

891Quantitative Aptitude
Refer the below data table and answer the following Question. Subjects Marks scored English / अंग्रेजी 45 Hindi / हिंदी 70 Math / गणित 30 Science / विज्ञान 80 Arts / कला 35 Five points are to be deducted from this students average of marks scored because of poor attendance. What will be this student's net average marks scored?
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Answer: (C) 47

Explanation

The average marks of the student are calculated by dividing the sum of marks in all five subjects by the total number of subjects.

Sum of marks scored = 45 + 70 + 30 + 80 + 35 = 260

Total number of subjects = 5

Average marks scored = 260 / 5 = 52

Since five points are to be deducted from this average due to poor attendance:

Net average marks scored = 52 - 5 = 47

892Quantitative Aptitude
The price of an article is cut by 31%, to restore to its original value, the new price must be increased by
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Answer: (B) 44.93 percent

Explanation

Let the original price of the article be 100.

After a price cut of 31%, the new price becomes: 100 - 31 = 69

To restore the price to its original value of 100, the increase required on the new price of 69 is 31.

The required percentage increase is calculated using the formula: Percentage increase = (Increase / New Price) × 100

Substituting the values: Percentage increase = (31 / 69) × 100 Percentage increase = 3100 / 69 Percentage increase ≈ 44.93%

893Quantitative Aptitude
If cot 240° = x, then the value of x is
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Answer: (C) 1/√3

Explanation

The trigonometric function cotangent has a period of 180°, which gives the relation cot(180° + θ) = cot θ.

For θ = 60°: cot 240° = cot(180° + 60°) = cot 60°

Since cot 60° = cos 60° / sin 60° = (1/2) / (√3/2) = 1/√3, the value of x is 1/√3.

894Quantitative Aptitude
Akka can bake 100 cakes in 20 hours, Akka and Tai together can bake 75 cakes in 10 hours. How many cakes Tai can bake in 20 hours?
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Answer: (B) 50

Explanation

To find the number of cakes Tai can bake, we first calculate the individual baking rates per hour.

Akka's baking rate = 100 cakes / 20 hours = 5 cakes/hour.

Akka and Tai's combined baking rate = 75 cakes / 10 hours = 7.5 cakes/hour.

Tai's baking rate = Combined rate - Akka's rate = 7.5 cakes/hour - 5 cakes/hour = 2.5 cakes/hour.

Using Tai's rate, the number of cakes Tai can bake in 20 hours is: 2.5 cakes/hour × 20 hours = 50 cakes.

895Quantitative Aptitude
Among three numbers, the first is twice the second and thrice the third. If the average of three numbers is 396, then what is the difference between the first and the third number?
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Answer: (C) 432

Explanation

Let the first number be x. Since the first number is twice the second and thrice the third, the second number is x/2 and the third number is x/3.

The average of the three numbers is 396, which means their sum is: x + x/2 + x/3 = 396 × 3 11x/6 = 1188 11x = 7128 x = 648

The first number is 648 and the third number is: 648/3 = 216

The difference between the first and the third number is: 648 - 216 = 432

896Quantitative Aptitude
The point Q(a,b) is first reflected in y-axis to Q1 and Q1 is reflected in x-axis to (-5,3). The co-ordinates of point Q are
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Answer: (D) (5,-3)

Explanation

Reflection of a point (x, y) in the y-axis changes the sign of its x-coordinate, yielding (-x, y). Reflection of a point (x, y) in the x-axis changes the sign of its y-coordinate, yielding (x, -y).

Applying these transformations to the point Q(a, b): First, reflecting Q(a, b) in the y-axis gives Q1(-a, b). Next, reflecting Q1(-a, b) in the x-axis gives the final coordinates (-a, -b).

We are given that this final point is (-5, 3). Comparing the coordinates: -a = -5, which gives a = 5 -b = 3, which gives b = -3

Thus, the coordinates of the initial point Q are (5, -3).

897Quantitative Aptitude
Raghavendra sells a machine for Rs 43 lakhs at a loss. Had he sold it for Rs 52 lakh, his gain would have been 5 times the former loss. Find the cost price of the machine.
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Answer: (C) Rs 44.5 lakhs

Explanation

Let CP be the cost price of the machine in lakhs.

When the machine is sold for ₹43 lakhs, the loss incurred is CP - 43.

When the machine is sold for ₹52 lakhs, the gain obtained is 52 - CP.

According to the given condition, the gain is 5 times the loss: 52 - CP = 5 × (CP - 43)

Solving the equation: 52 - CP = 5CP - 215 6CP = 267 CP = 267 / 6 = 44.5

The cost price of the machine is ₹44.5 lakhs.

898Quantitative Aptitude
If √(sec² A - 1) = x, then the value of x is
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Answer: (B) tanA

Explanation

Using the fundamental trigonometric identity: sec² A - tan² A = 1

Rearranging the terms: sec² A - 1 = tan² A

Taking the square root on both sides gives: √(sec² A - 1) = tan A

Since the given relation is √(sec² A - 1) = x, substituting the identity yields: x = tan A

899Quantitative Aptitude
To cover a distance of 234 km in 1.6 hours what should be the average speed of the car in meters/second?
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Answer: (A) 40.625 m/s

Explanation

Average speed is calculated using the formula Speed = Distance / Time.

Given: Distance = 234 km Time = 1.6 hours

Average speed in km/h = 234 / 1.6 = 146.25 km/h

To convert the speed from kilometers per hour to meters per second, multiply the value by the conversion factor 5/18.

Average speed in m/s = 146.25 × 5/18 = 40.625 m/s

900Quantitative Aptitude
What is the value of cos² A/(1 + sin A)?
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Answer: (B) 1 - sinA

Explanation

Using the fundamental trigonometric identity, sin² A + cos² A = 1, we can express cos² A as 1 - sin² A.

Substituting this into the given expression: cos² A / (1 + sin A) = (1 - sin² A) / (1 + sin A)

Applying the algebraic identity a² - b² = (a - b)(a + b) to the numerator: (1 - sin A)(1 + sin A) / (1 + sin A)

Canceling the common term (1 + sin A) from the numerator and the denominator simplifies the expression to 1 - sin A.

Answer key

Tap a number to jump to that question.

  1. 851C
  2. 852A
  3. 853C
  4. 854B
  5. 855C
  6. 856C
  7. 857A
  8. 858A
  9. 859C
  10. 860C
  11. 861B
  12. 862A
  13. 863C
  14. 864B
  15. 865B
  16. 866D
  17. 867B
  18. 868B
  19. 869C
  20. 870D
  21. 871C
  22. 872D
  23. 873C
  24. 874A
  25. 875A
  26. 876A
  27. 877C
  28. 878C
  29. 879C
  30. 880A
  31. 881B
  32. 882A
  33. 883B
  34. 884C
  35. 885C
  36. 886C
  37. 887D
  38. 888B
  39. 889D
  40. 890B
  41. 891C
  42. 892B
  43. 893C
  44. 894B
  45. 895C
  46. 896D
  47. 897C
  48. 898B
  49. 899A
  50. 900B

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