SSC CHSL Tier 1 2016 Quantitative Aptitude Questions with Solutions

Explanation

To find the percentage of students who chose Engineering who are girls, first calculate the total number of students in the Engineering stream.

Total Engineering students = Boys in Engineering + Girls in Engineering Total Engineering students = 75 + 20 = 95

The number of girls who opted for Engineering is 20.

Now, calculate the percentage of these girls relative to the total number of Engineering students: Percentage = (Girls in Engineering / Total Engineering students) × 100 Percentage = (20 / 95) × 100 Percentage = 21.05%

Explanation

The given table displays the cumulative production of cars at the end of each month.

To find the total number of cars manufactured during the months of April and May, we subtract the cumulative production at the end of March from the cumulative production at the end of May.

Cumulative production up to May = 2580 Cumulative production up to March = 1540

Cars manufactured in April and May = Cumulative production up to May - Cumulative production up to March Cars manufactured in April and May = 2580 - 1540 = 1040

Explanation

To find the total calories burned in the given week, first calculate the total distance jogged during the week by adding the distances for all seven days:

Total distance = 4 + 5 + 4 + 1.5 + 4.5 + 5 + 2.5 = 26.5 km

Given that jogging 5 km burns 400 calories, the number of calories burned per kilometer is:

Calories per km = 400 ÷ 5 = 80 calories/km

Using this rate, the total calories burned for the weekly distance of 26.5 km is:

Total calories burned = 26.5 km × 80 calories/km = 2120 calories

Explanation

Total expenses = 11 + 3 + 4 + 6 + 4 = 28 lakhs

Rent and Taxes = 4 + 4 = 8 lakhs

Percentage of Rent and Taxes = (Rent and Taxes / Total Expenses) × 100

Substituting the values: Percentage = (8 / 28) × 100 = (2 / 7) × 100 ≈ 28.57%

Explanation

A kite is a quadrilateral with two distinct pairs of adjacent equal sides. By symmetry, the diagonal connecting the two vertices where the equal sides meet acts as an axis of symmetry. This main diagonal perpendicularly bisects the other diagonal. Consequently, in every kite, at least one diagonal always bisects the other.

Explanation

The effective discount can be calculated using the successive discount formula:

Effective Discount = d₁ + d₂ - (d₁ × d₂)/100

Here, the initial discount d₁ is 25% and the cashback discount d₂ is 4%. Substituting these values into the formula:

Effective Discount = 25 + 4 - (25 × 4)/100 Effective Discount = 29 - 100/100 Effective Discount = 29 - 1 Effective Discount = 28%

Alternatively, if the marked price of the item is 100, a 25% discount reduces the price to 75. Applying a 4% cashback on this reduced price of 75 gives a cashback of 3 (since 4% of 75 is 3). The final price paid by the customer is 72, which represents a total discount of 28% on the original price of 100.

Explanation

To find the highest common factor (HCF) of 133 and 112, we can use the Euclidean division algorithm:

133 = 112 × 1 + 21 112 = 21 × 5 + 7 21 = 7 × 3 + 0

Since the remainder becomes 0, the divisor at this stage, which is 7, is the HCF. Alternatively, expressing both numbers as a product of their prime factors gives:

133 = 7 × 19 112 = 2⁴ × 7

The only common prime factor is 7, which has a lowest power of 1. Hence, the HCF is 7.

Explanation

Applying the algebraic identity (x + y)² = x² + 2xy + y² to the numerator, let x = 2a and y = 3b.

The term x² becomes (2a)² = 4a², the term y² becomes (3b)² = 9b², and the middle term 2xy becomes 2 × 2a × 3b = 12ab.

Therefore, the numerator simplifies to: 4a² + 12ab + 9b² = (2a + 3b)²

Substituting this back into the given expression yields: (2a + 3b)² / (2a + 3b) = 2a + 3b

Explanation

To find the point of intersection of the lines x - y = -1 and 3x - 2y = 0, we can solve them simultaneously.

From the first equation, we get: y = x + 1

Substituting this expression for y into the second equation: 3x - 2(x + 1) = 0 3x - 2x - 2 = 0 x = 2

Using the value of x to find y: y = 2 + 1 = 3

So, the point of intersection is (2, 3).

The equation of a line with slope m passing through a point (x₁, y₁) is given by the formula: y - y₁ = m(x - x₁)

Substituting m = -½ and the point (2, 3) into the formula: y - 3 = -½(x - 2)

Multiplying both sides by 2 to clear the fraction: 2(y - 3) = -(x - 2) 2y - 6 = -x + 2 x + 2y = 8

Explanation

The curved surface area of a cylinder is given by the formula: Curved Surface Area = 2πrh

The circumference of the base of the cylinder is given by: Circumference = 2πr

By substituting the circumference into the curved surface area formula, we get: Curved Surface Area = Circumference × h

Substituting the given values into this relation: 1232 = 154 × h

Solving for height (h): h = 1232 ÷ 154 h = 8 cm

This directly yields the height of the cylinder.

Explanation

Let the number be 30, which is the least common multiple of the denominators 3 and 10.

The correct calculation is: 30 × 10/3 = 100

The incorrect calculation is: 30 × 3/10 = 9

The error in the calculation is: 100 - 9 = 91

The percentage error is calculated as: Percentage Error = (Error / Correct Value) × 100% Percentage Error = (91 / 100) × 100% Percentage Error = 91%

Explanation

The area of a sector of a circle is calculated using the formula:

Area = (θ / 360°) × πr²

where θ is the central angle in degrees and r is the radius of the circle.

Given: Central angle θ = 90° Radius r = 14 cm Value of π ≈ 22/7

Substituting these values into the formula:

Area = (90° / 360°) × (22 / 7) × 14²

Area = (1 / 4) × (22 / 7) × 196

Area = (1 / 4) × 22 × 28

Area = (1 / 4) × 616

Area = 154 sq cm

Explanation

To find the coefficient of x² in the expression (x + 9)(6 - 4x)(4x - 7), we can first multiply the first two binomials:

(x + 9)(6 - 4x) = 6x - 4x² + 54 - 36x = -4x² - 30x + 54

Now, we multiply this resulting quadratic expression by the third binomial:

(-4x² - 30x + 54)(4x - 7)

To find only the coefficient of x², we identify the terms in the expansion that result in x²:

The term from (-4x²) multiplied by (-7) gives 28x². The term from (-30x) multiplied by (4x) gives -120x².

Adding these two terms:

28x² - 120x² = -92x²

Thus, the coefficient of x² is -92.

Explanation

The given system of inequalities consists of two parts:

First inequality: 5x - 3(2x - 7) > 3x - 1 Expanding and simplifying this expression: 5x - 6x + 21 > 3x - 1 -x + 21 > 3x - 1 22 > 4x x < 22/4 x < 5.5

Second inequality: 3x - 1 < 7 + 4x Rearranging the terms: -1 - 7 < 4x - 3x -8 < x x > -8

Combining both inequalities, the value of x must satisfy the range: -8 < x < 5.5

The value -6 lies strictly within this interval, making it a valid solution for x.

Explanation

To convert speed from kilometres per hour (km/h) to metres per second (m/s), multiply the speed by the conversion factor 5/18.

Speed in m/s = Speed in km/h × 5/18

Substituting the given speed:

Speed in m/s = 1422 × 5/18 Speed in m/s = 79 × 5 = 395 m/s

Since the speed of the missile is 395 metres per second, the distance traveled by the missile in one second is 395 metres.

Explanation

Let the original fare be 17x and the new fare be 20x.

The original fare is given as Rs. 425. 17x = 425 x = 425 / 17 x = 25

The increase in the fare is the difference between the new fare and the original fare: Increase = 20x - 17x = 3x

Substituting the value of x: Increase = 3 × 25 = Rs. 75

Explanation

Using the trigonometric identity sec A = 1/cos A, the given expression can be rewritten by substituting sec A in terms of cos A:

(sec A - 1) / (sec A + 1) = (1/cos A - 1) / (1/cos A + 1)

By finding a common denominator in both the numerator and the denominator, we get:

((1 - cos A) / cos A) / ((1 + cos A) / cos A)

Canceling out the common cos A term in the denominators of both the numerator and denominator simplifies the expression to:

(1 - cos A) / (1 + cos A)

Explanation

The triple-angle identity for cosine is derived from the angle sum formula:

cos(3A) = cos(2A + A)

Using the cosine addition formula cos(x + y) = cos(x)cos(y) - sin(x)sin(y):

cos(2A)cos(A) - sin(2A)sin(A)

Substituting the double-angle identities cos(2A) = 2cos²(A) - 1 and sin(2A) = 2sin(A)cos(A):

(2cos²(A) - 1)cos(A) - (2sin(A)cos(A))sin(A) = 2cos³(A) - cos(A) - 2sin²(A)cos(A)

Replacing sin²(A) with 1 - cos²(A):

2cos³(A) - cos(A) - 2(1 - cos²(A))cos(A) = 2cos³(A) - cos(A) - 2cos(A) + 2cos³(A) = 4cos³(A) - 3cos(A)

Explanation

Since the total number of students in the class is 66 and there are 33 girls, the number of boys is also 33. Because the number of girls and boys is equal, the average weight of the entire class is the simple arithmetic mean of the average weight of the girls and the average weight of the boys.

Let A_b be the average weight of the boys.

Average weight of the class = (Average weight of girls + Average weight of boys) / 2

66 = (61 + A_b) / 2

132 = 61 + A_b

A_b = 132 - 61 = 71 kg

Explanation

The amount of work done by A in 1 day is 1/20, and the amount of work done by B in 1 day is 1/10.

When they work together, their combined 1-day work is: 1/20 + 1/10 = 3/20

In 5 days, the fraction of work completed by both together is: 5 × (3/20) = 15/20 = 3/4

The fraction of work that remains left is: 1 - 3/4 = 1/4

Explanation

Let the two-digit number be represented as 10x + y, where x is the tens digit and y is the units digit. The number formed by interchanging the digits is 10y + x.

The difference between a two-digit number and its reversed form is given by the relation: (10y + x) - (10x + y) = 9(y - x)

According to the given condition, adding 18 to the number results in its digits being reversed: (10y + x) - (10x + y) = 18 9(y - x) = 18 y - x = 2

We are also given that the product of the digits is 15: x × y = 15

Substituting y = x + 2 into the product equation: x(x + 2) = 15 x² + 2x - 15 = 0 (x + 5)(x - 3) = 0

Since x represents a digit, it must be a positive integer, giving x = 3. Thus, y = 3 + 2 = 5.

The required two-digit number is 10(3) + 5 = 35.

Explanation

Using the trigonometric identity tan(π + θ) = tan θ, we can write:

tan(7π/6) = tan(π + π/6) = tan(π/6)

Since the value of tan(π/6) is 1/√3, we get:

tan(7π/6) = 1/√3

Explanation

The relationship between Marked Price (MP) and Cost Price (CP) given a profit percentage p and a discount percentage d is: MP/CP = (100 + p) / (100 - d)

Substituting the given values for the first case, where the discount is 20% and the profit is 28%: MP/CP = (100 + 28) / (100 - 20) = 128/80 = 1.6

This gives: MP = 1.6 × CP

In the second case, with a discount of 13%, the new Selling Price (SP) is: SP = MP × (100 - 13) / 100 = 0.87 × MP

Substituting MP in terms of CP into this equation: SP = 0.87 × 1.6 × CP = 1.392 × CP

The profit percentage is calculated as: Profit% = (SP - CP) / CP × 100 = (1.392 × CP - CP) / CP × 100 = 0.392 × 100 = 39.2%

Explanation

We can find the coordinates of R(a, b) by tracing the transformations backward from the final image (-5, 1).

First, let the coordinates of R1 be (x, y). Reflecting a point in the X-axis changes the sign of its y-coordinate while keeping its x-coordinate the same, meaning R1(x, y) reflected in the X-axis is (x, -y). We are given that this image is (-5, 1). Equating the coordinates gives x = -5 and -y = 1, which means y = -1. Thus, R1 is (-5, -1).

Second, R1 is the reflection of R(a, b) in the origin. Reflecting a point in the origin changes the signs of both its coordinates, meaning R(a, b) becomes (-a, -b). Equating (-a, -b) to R1(-5, -1) gives -a = -5 and -b = -1. This yields a = 5 and b = 1. Therefore, the coordinates of point R are (5, 1).

Explanation

The formula for Simple Interest (SI) is: SI = (P × R × T) / 100

where P is the principal, R is the rate of interest per annum, and T is the time in years.

Let the common rate of interest per annum be R%.

The simple interest received from Jairaj is: SI₁ = (8200 × R × 16) / 100 = 1312 R

The simple interest received from Karna is: SI₂ = (4900 × R × 15) / 100 = 735 R

The total interest received from both is the sum of SI₁ and SI₂: Total Interest = 1312 R + 735 R = 2047 R

Given that the total interest received is ₹19446.5: 2047 R = 19446.5 R = 19446.5 / 2047 = 9.5%

Explanation

To find the ratio of boys to girls, the total number of boys and the total number of girls across all divisions must be calculated.

The total number of boys is the sum of boys in all divisions: 30 + 10 + 40 + 30 + 15 + 20 = 145

The total number of girls is the sum of girls in all divisions: 40 + 20 + 10 + 10 + 15 + 20 = 115

The ratio of boys to girls is therefore: 145 : 115

Dividing both terms by 5 to simplify the ratio yields: 29 : 23

Explanation

To find the number of students who scored 20 or more but less than 40, we subtract the number of students who scored 40 and above from the number of students who scored 20 and above.

Number of students scoring 20 or more but less than 40 = (Number of students scoring 20 and above) - (Number of students scoring 40 and above)

Substituting the values from the cumulative frequency table: = 48 - 11 = 37

This directly gives the count of students whose marks lie in the interval from 20 to 39.

Explanation

To find the net average marks, we first calculate the total marks scored across all five subjects: Total marks = 70 + 55 + 30 + 35 + 60 = 250

Since there are 5 subjects, the initial average marks scored by the student is: Average = Total marks / Number of subjects = 250 / 5 = 50

Subtracting 5 points from this average due to poor attendance yields the net average: Net average = 50 - 5 = 45

Explanation

To find the expression that must be added, let the required expression be A. The given equation is:

8(3x - 4y) + A = 18x - 18y

Expanding the first term:

24x - 32y + A = 18x - 18y

Solving for A by subtracting 24x - 32y from both sides:

A = (18x - 18y) - (24x - 32y)

A = 18x - 18y - 24x + 32y

Grouping the like terms together:

A = (18x - 24x) + (32y - 18y)

A = -6x + 14y

A = 14y - 6x

Explanation

The slope-intercept form of a linear equation is y = mx + c, where m is the slope of the line and c is the y-intercept.

The slope m is given by the tangent of the angle θ that the line makes with the positive x-axis: m = tan(45°) = 1

The y-intercept c is given as -3/4.

Substituting the slope m = 1 and the y-intercept c = -3/4 into the slope-intercept equation yields: y = 1x - 3/4

Multiplying the entire equation by 4 to eliminate the fraction gives: 4y = 4x - 3

Rearranging the terms to group the variables on one side: 4x - 4y = 3

Explanation

Let the Marked Price of the goods be MP and the Cost Price be CP.

A discount of 32% is offered on the Marked Price, which means the Selling Price (SP) is: SP = MP × (1 - 0.32) = 0.68 × MP

Since the retailer sells the goods at the Cost Price, we have: SP = CP 0.68 × MP = CP MP = CP / 0.68

If we assume the Cost Price (CP) to be 100: MP = 100 / 0.68 ≈ 147.05

The markup percentage represents the percentage by which the Marked Price exceeds the Cost Price: Markup % = ((MP - CP) / CP) × 100 Markup % = ((147.05 - 100) / 100) × 100 = 47.05%

Explanation

Using the section formula, the ratio k:1 in which T(3,0) divides the line segment joining S(4,-2) and U(1,4) is determined by setting the x-coordinate 3 equal to (k*1 + 4)/(k + 1), which simplifies to k = 1/2, or a ratio of 1:2. This is also confirmed by the y-coordinate equation, which yields the same ratio.

Explanation

We can simplify the given trigonometric expression using standard trigonometric identities.

First, the identity 1 + tan²A = sec²A simplifies the numerator to:

(sec²A × cotA) / cosec²A

Next, expressing each trigonometric function in terms of sine and cosine gives: sec²A = 1/cos²A cotA = cosA/sinA cosec²A = 1/sin²A

Substituting these values into the expression yields:

((1/cos²A) × (cosA/sinA)) / (1/sin²A)

Simplifying the numerator:

(1 / (sinA × cosA)) / (1/sin²A)

Multiplying the numerator by the reciprocal of the denominator:

(1 / (sinA × cosA)) × sin²A

This simplifies to:

sin²A / (sinA × cosA) = sinA / cosA = tanA

Explanation

The total time required to build the wall is 70 hours.

In 7 hours, the fraction of the wall completed by the mason is the ratio of the time worked to the total time required: Completed fraction = 7 / 70 = 1 / 10 = 0.1

The fraction of the wall that is yet to be built is the remaining portion of the total work: Remaining fraction = 1 - 0.1 = 0.9

Explanation

The formula for average speed is Distance divided by Time.

Average speed in km/h = 216 / 3.2 = 67.5 km/h

To convert speed from km/h to m/s, we multiply by 5/18:

Average speed in m/s = 67.5 × 5/18 = 18.75 m/s

Explanation

For a number to be completely divisible by 99, it must be divisible by both 9 and 11.

To test the divisibility of 57717 by 9, we calculate the sum of its digits: 5 + 7 + 7 + 1 + 7 = 27 Since 27 is divisible by 9, the number is divisible by 9.

To test the divisibility of 57717 by 11, we find the difference between the sum of the digits in the odd positions and the sum of the digits in the even positions: Sum of digits at odd positions from the right: 7 + 7 + 5 = 19 Sum of digits at even positions from the right: 1 + 7 = 8 Difference = 19 - 8 = 11 Since the difference is 11, which is divisible by 11, the number is divisible by 11.

As 57717 is divisible by both 9 and 11, it is completely divisible by 99.

Explanation

Simple interest is distributed equally over the two years, meaning the simple interest for the first year is 1400 / 2 = Rs 700.

For the first year, compound interest is equal to simple interest, which is Rs 700. The total compound interest for two years is Rs 1449, which means the interest earned in the second year is 1449 - 700 = Rs 749.

The difference between the second year's compound interest and simple interest is 749 - 700 = Rs 49. This difference is the interest earned on the first year's interest of Rs 700.

Using the interest formula to find the rate (R): 49 = (700 × R × 1) / 100 49 = 7 × R R = 7

This yields a rate of interest of 7% per annum.

Explanation

Let the number of selected candidates be 3x and unselected candidates be x.

The total number of applied candidates is 3x + x = 4x.

According to the problem, if 80 less had applied and 40 less were selected: New total applied candidates = 4x - 80 New selected candidates = 3x - 40

The new number of unselected candidates is the new total applied minus the new selected: New unselected candidates = (4x - 80) - (3x - 40) = x - 40

The new ratio of selected to unselected candidates is 4:1: (3x - 40) / (x - 40) = 4 / 1

Cross-multiplying to solve for x: 3x - 40 = 4(x - 40) 3x - 40 = 4x - 160 x = 120

The original number of candidates who applied is 4x = 4 × 120 = 480.

Explanation

To find the possible values of x, we solve the two given inequalities.

First inequality: 4(2x + 3) > 5 - x 8x + 12 > 5 - x 9x > -7 x > -7/9 (approximately -0.78)

Second inequality: 5x - 3(2x - 7) > 3x - 1 5x - 6x + 21 > 3x - 1 -x + 21 > 3x - 1 22 > 4x x < 22/4 x < 5.5

Combining both inequalities, the value of x must satisfy: -7/9 < x < 5.5

Since 5 lies within this interval, it is a valid value for x.

Explanation

To find the value of the expression 2x - 11, first solve the given equation:

5x - 40 = 3x

Subtracting 3x from both sides and adding 40 to both sides gives:

5x - 3x = 40 2x = 40 x = 20

Substituting the value of 2x into the second expression:

2x - 11 = 40 - 11 = 29

Explanation

A quadratic equation ax² + bx + c = 0 has equal roots when its discriminant, D = b² - 4ac, is equal to zero.

For the quadratic equation 3x² - 6x + 3 = 0, the coefficients are a = 3, b = -6, and c = 3.

Substituting these values into the discriminant formula: D = (-6)² - 4 × 3 × 3 D = 36 - 36 D = 0

Since the discriminant is equal to zero, this equation has equal roots. This is also evident by factoring out 3 to get 3(x² - 2x + 1) = 0, which simplifies to the perfect square 3(x - 1)² = 0, yielding the repeated root x = 1.

Explanation

Let the marks obtained by the two students be x and y, where x is the higher mark.

The higher mark x is 56% of the sum of their marks (x + y). Therefore, the ratio of the higher mark to the sum of their marks is: x / (x + y) = 56/100 = 14/25

This means if the sum of their marks is represented as 25 units, the higher mark is 14 units.

The lower mark is: 25 units - 14 units = 11 units

The difference between their marks in units is: 14 units - 11 units = 3 units

We are given that the actual difference between their marks is 9. 3 units = 9 marks 1 unit = 3 marks

Using this value, the actual marks obtained by the two students are: Higher mark = 14 × 3 = 42 Lower mark = 11 × 3 = 33

Explanation

The tangent subtraction formula is a fundamental trigonometric identity defined as:

tan(A - B) = sin(A - B) / cos(A - B)

By expanding the sine and cosine of the difference of two angles:

sin(A - B) = sinA cosB - cosA sinB cos(A - B) = cosA cosB + sinA sinB

Substituting these expansions into the tangent relation:

tan(A - B) = (sinA cosB - cosA sinB) / (cosA cosB + sinA sinB)

To express this in terms of tangent functions, divide both the numerator and the denominator by cosA cosB:

tan(A - B) = ((sinA cosB / cosA cosB) - (cosA sinB / cosA cosB)) / ((cosA cosB / cosA cosB) + (sinA sinB / cosA cosB))

tan(A - B) = (tanA - tanB) / (1 + tanA tanB)

Thus, if X represents tan(A - B), its value is (tanA - tanB) / (1 + tanA tanB).

Explanation

Correct Answer: D

The trigonometric function sec θ is the reciprocal of cos θ. Therefore, sec 330° is equal to 1 / cos 330°.

The angle 330° lies in the fourth quadrant, where the cosine function is positive. Using the trigonometric reduction formula:

cos(360° - θ) = cos θ

We can express cos 330° as:

cos 330° = cos(360° - 30°) = cos 30°

Since cos 30° is equal to √3/2, we have:

sec 330° = 1 / (√3/2) = 2/√3

Explanation

By the Sine Rule of triangles, the ratio of the length of a side to the sine of its opposite angle is constant:

a/sin(A) = b/sin(B)

Substituting the given values, where a = 8 cm is the side opposite to A = 45°, and b is the side opposite to B = 90°:

8/sin(45°) = b/sin(90°)

Since sin(45°) = 1/√2 and sin(90°) = 1:

8/(1/√2) = b/1

b = 8√2 cm

Explanation

One quintal equals 100 kg, so 22 quintals of wheat is equal to 2200 kg.

Using the rule of alligation to find the ratio of the two parts: First part profit (23%) vs Second part profit (33%) with a mean profit of 27%

Ratio of the quantity sold at 23% profit to the quantity sold at 33% profit is: (33 - 27) : (27 - 23) = 6 : 4 = 3 : 2

The quantity of wheat sold at 33% profit is: (2 / (3 + 2)) × 2200 = (2 / 5) × 2200 = 880 kg

Explanation

The curved surface area of a cylinder is calculated using the formula: CSA = 2πrh

By substituting the given values of CSA = 1386, h = 21, and π = 22/7: 1386 = 2 × (22/7) × r × 21

Simplifying the equation: 1386 = 2 × 22 × r × 3 1386 = 132 × r r = 1386 / 132 r = 10.5 cm

Explanation

Euler's formula for any convex polyhedron relates the number of vertices (V), edges (E), and faces (F) as:

V - E + F = 2

Substituting the given values, V = 12 and E = 30, into the formula:

12 - 30 + F = 2

-18 + F = 2

F = 20

Explanation

To find the percentage of students who chose Engineering who are girls, the formula is:

Percentage of girls in Engineering = (Number of girls in Engineering / Total students in Engineering) × 100

From the table: Number of girls who chose Engineering = 25 Number of boys who chose Engineering = 75

Total students who chose Engineering = 75 + 25 = 100

Substituting these values into the formula:

Percentage = (25 / 100) × 100 = 25%

Explanation

The given table displays the cumulative production of cars at the end of each month.

To find the number of cars manufactured specifically in the months of April and May, we subtract the cumulative production up to the end of March from the cumulative production up to the end of May.

Cumulative production up to May = 3050 Cumulative production up to March = 1940

Cars manufactured in April and May = 3050 - 1940 = 1110