Explanation
Let the starting point be the origin (0, 0) on a Cartesian plane where the positive x-axis is East, the negative x-axis is West, the positive y-axis is North, and the negative y-axis is South.
First, the man travels 10 km West, reaching the position:
P₁ = (-10, 0)
Next, he travels 20 km North-East. A movement in the North-East direction represents an angle of 45° relative to the positive x-axis. The displacement vector for this leg is:
V₂ = (20 cos 45°, 20 sin 45°) = (20 × 1/√2, 20 × 1/ √2) = (10√2, 10√2)
Using √2 ≈ 1.414, this displacement is approximately (14.14, 14.14).
His position after this movement is:
P₂ = (-10 + 10√2, 10√2) ≈ (4.14, 14.14)
Finally, he travels 5 km South-East. A movement in the South-East direction represents an angle of -45° relative to the positive x-axis. The displacement vector for this leg is:
V₃ = (5 cos -45°, 5 sin -45°) = (5 × 1/√2, -5 × 1/√2) = (2.5√2, -2.5√2)
Using √2 ≈ 1.414, this displacement is approximately (3.54, -3.54).
His final position relative to the origin is:
P₃ = P₂ + V₃ = (-10 + 12.5√2, 7.5√2)
Calculating the exact values:
X-coordinate = -10 + 12.5 × 1.414 = 7.68 km
Y-coordinate = 7.5 × 1.414 = 10.61 km
Since both the X-coordinate (East) and Y-coordinate (North) are positive, his final position lies in the first quadrant, which corresponds to the North-East direction from the origin.