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Answer: (D) 25
Explanation
Let d be the original number of days required to finish the work by 150 workers. Total work = 150d worker-days
When workers drop out daily, the number of workers working on consecutive days forms an arithmetic progression with first term a = 150 and common difference d_diff = -4: 150, 146, 142, ...
Let n be the total number of days taken to finish the work. Since it takes 8 more days, n = d + 8, which gives d = n - 8.
The sum of this arithmetic progression for n terms represents the total work done: Total work = (n/2) × [2a + (n - 1)d_diff] Total work = (n/2) × [2 × 150 + (n - 1)(-4)] Total work = (n/2) × [304 - 4n] Total work = n(152 - 2n)
Equating the two expressions for the total work: 150(n - 8) = n(152 - 2n) 150n - 1200 = 152n - 2n² 2n² - 2n - 1200 = 0 n² - n - 600 = 0 (n - 25)(n + 24) = 0
Solving for the positive value of n gives n = 25.