SSC CHSL2012Quantitative AptitudePage 4 of 4

SSC CHSL Tier 1 2012 Quantitative Aptitude Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 151–197 of 197, each with the correct answer and a step-by-step explanation.

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151Quantitative Aptitude
An interior angle of a regular polygon is 120°. What is its number of sides?
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Answer: (D) 6

Explanation

The sum of an interior angle and its corresponding exterior angle of a regular polygon is always 180°. Given that the interior angle is 120°, the exterior angle is:

Exterior Angle = 180° - 120° = 60°

Since the sum of all exterior angles of any polygon is always 360°, the number of sides (n) of the regular polygon can be calculated using the formula:

n = 360° / Exterior Angle

Substituting the value of the exterior angle:

n = 360° / 60° = 6

152Quantitative Aptitude
If S is the circumference of triangle ABC and the value of angle BAC is 40°, then the value of angle BSC is
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Answer: (C) 80°

Explanation

In geometry, if S denotes the circumcentre of triangle ABC, then the angle subtended by the arc BC at the circumcentre S is twice the angle subtended by the same arc at any point on the remaining part of the circle, which is the vertex A.

By this theorem: ∠BSC = 2 × ∠BAC

Given that ∠BAC = 40°, we substitute this value into the relation: ∠BSC = 2 × 40° = 80°

153Quantitative Aptitude
Three medians AD, BE and CF of triangle ABC intersect at G. If area of triangle ABC is 36 cm², find the area of quadrilateral BDGF.
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Answer: (D) 12 cm²

Explanation

The medians of a triangle divide the triangle into six smaller triangles of equal area.

When the three medians AD, BE, and CF of triangle ABC intersect at the centroid G, the six smaller triangles formed are ΔAFG, ΔBFG, ΔBDG, ΔCDG, ΔCEG, and ΔAEG. The area of each of these triangles is equal to 1/6 of the total area of triangle ABC.

Area of each small triangle = 36 ÷ 6 = 6 cm²

The quadrilateral BDGF is composed of two of these smaller triangles, which are ΔBFG and ΔBDG.

Area of quadrilateral BDGF = Area of ΔBFG + Area of ΔBDG = 6 + 6 = 12 cm²

154Quantitative Aptitude
The angle of elevation of a cloud from a point h meters above the surface of a lake is 30° and the angle of depression of its reflection is 60°. Then the height of the cloud above the surface of the lake is
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Answer: (D) 2h meters

Explanation

Let H be the height of the cloud above the surface of the lake. Since the observer is at a height h above the lake surface, the height of the cloud above the level of the observer is H - h. Let d be the horizontal distance from the observer to the vertical line of the cloud.

From the right-angled triangle formed by the observer and the cloud: tan 30° = (H - h) / d d = (H - h) / tan 30° d = (H - h)√3

The reflection of the cloud lies at a depth H below the lake surface. Therefore, the depth of the reflection below the level of the observer is H + h.

From the right-angled triangle formed by the observer and the reflection of the cloud: tan 60° = (H + h) / d d = (H + h) / tan 60° d = (H + h) / √3

Equating the two expressions for d: (H - h)√3 = (H + h) / √3

Multiplying both sides by √3: 3(H - h) = H + h 3H - 3h = H + h 2H = 4h H = 2h

155Quantitative Aptitude
If the triangle ABC is right-angled at B, and the sides AB and BC are 15 cm and 20 cm respectively, then the circumradius is
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Answer: (A) 12.5 cm

Explanation

For any right-angled triangle, the circumcentre lies at the midpoint of the hypotenuse. Therefore, the circumradius is exactly half the length of the hypotenuse.

Using the Pythagorean theorem, the length of the hypotenuse AC is: AC = √(AB² + BC²) AC = √(15² + 20²) AC = √(225 + 400) AC = √625 = 25 cm

The circumradius is: Circumradius = AC / 2 = 25 / 2 = 12.5 cm

156Quantitative Aptitude
If sin(x + y) = √3/2 and tan(x - y) = 1/√3 then the value of x is
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Answer: (D) π/4

Explanation

From the given trigonometric equations, we have: sin(x + y) = √3/2 This implies x + y = π/3

Similarly: tan(x - y) = 1/√3 This implies x - y = π/6

Adding these two equations to eliminate y: (x + y) + (x - y) = π/3 + π/6 2x = π/2 x = π/4

157Quantitative Aptitude
If A + B = 90°, then the value of sec²A + sec²B - sec²A.sec²B is
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Answer: (A) 0

Explanation

Given A + B = 90°, we have B = 90° - A. Using the trigonometric co-function identity, we get sec B = sec(90° - A) = cosec A.

Substituting this into the given expression: sec²A + sec²B - sec²A · sec²B = sec²A + cosec²A - sec²A · cosec²A

We can express the sum sec²A + cosec²A in terms of sine and cosine: sec²A + cosec²A = 1/cos²A + 1/sin²A = (sin²A + cos²A) / (sin²A · cos²A) = 1 / (sin²A · cos²A) = sec²A · cosec²A

Substituting this result back into the expression yields: sec²A · cosec²A - sec²A · cosec²A = 0

158Quantitative Aptitude
If P = 999, find the value of P(P + 2).
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Answer: (C) 999999

Explanation

Substituting the value P = 999 into the expression P(P + 2):

P(P + 2) = 999 × (999 + 2) P(P + 2) = 999 × 1001

To simplify the calculation, express 1001 as 1000 + 1:

P(P + 2) = 999 × (1000 + 1) P(P + 2) = 999000 + 999 P(P + 2) = 999999

159Quantitative Aptitude
The marked price of a book is 165 and it is sold for 132. The percentage discount allowed is
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Answer: (A) 20%

Explanation

The discount allowed on the book is the difference between its marked price and its selling price: Discount = Marked Price - Selling Price = 165 - 132 = 33

The percentage discount is calculated on the marked price using the formula: Discount % = (Discount / Marked Price) × 100 Discount % = (33 / 165) × 100 = (1 / 5) × 100 = 20%

160Quantitative Aptitude
In a mixture of 60 litres, the ratio of milk and water is 2:1. If this ratio is to be 1:2, then the quantity of water to be further added is
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Answer: (B) 60 litres

Explanation

The initial mixture has a total volume of 60 litres, with milk and water in the ratio 2:1.

The quantity of milk in the mixture is: (2 / 3) × 60 = 40 litres

The quantity of water in the mixture is: (1 / 3) × 60 = 20 litres

Since only water is added to the mixture, the amount of milk remains unchanged at 40 litres. In the new mixture, the ratio of milk to water is 1:2.

Let x be the amount of water to be added. The new quantity of water becomes 20 + x.

Using the new ratio: 40 / (20 + x) = 1 / 2

Cross-multiplying to solve for x: 80 = 20 + x x = 60

161Quantitative Aptitude
Simplify: ⅔:¾:⅙
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Answer: (C) 28:39:14

Explanation

Convert the mixed numbers to improper fractions: 2 ⅓ = 7/3 3 ¼ = 13/4 1 ⅙ = 7/6

Now, express the ratio of these improper fractions: 7/3 : 13/4 : 7/6

To eliminate the denominators, find the least common multiple (LCM) of the denominators 3, 4, and 6, which is 12.

Multiply each term of the ratio by the LCM: (7/3) × 12 = 28 (13/4) × 12 = 39 (7/6) × 12 = 14

This simplifies the ratio to 28 : 39 : 14.

162Quantitative Aptitude
The number of men, women and boys employed in a factory are in the ratio 5:7:10. If the total number of workers is 660, find the number of men, women and boys.
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Answer: (D) 150,210,300

Explanation

The ratio of men, women, and boys employed in the factory is 5:7:10. Let the common ratio factor be x.

The sum of the ratio terms represents the total number of workers, which is given as 660: 5x + 7x + 10x = 660 22x = 660 x = 660 ÷ 22 x = 30

By multiplying the ratio terms by the common factor of 30, we find the individual counts of each category: Number of men = 5 × 30 = 150 Number of women = 7 × 30 = 210 Number of boys = 10 × 30 = 300

163Quantitative Aptitude
The solution set to the equation |x + 2| = √4 will be
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Answer: (A) {0, -4}

Explanation

The equation says the absolute value of x plus 2 equals the square root of 4, which is 2. So x plus 2 equals 2 or x plus 2 equals negative 2. Solving these gives x equal to 0 or x equal to negative 4, so the solution set is zero and negative four.

164Quantitative Aptitude
A number is added with ⁵⁄₇ and the sum is 1. The number is
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Answer: (D) 40% of ⁵⁄₇

Explanation

Let the required number be x.

According to the problem, the sum of the number and 5/7 is 1: x + 5/7 = 1 x = 1 - 5/7 x = 2/7

To find what percentage of 5/7 this number represents, we calculate: (2/7 ÷ 5/7) × 100% = (2/7 × 7/5) × 100% = 2/5 × 100% = 40%

This confirms the number is 40% of 5/7.

165Quantitative Aptitude
A 250 m long train is running at a speed of 55 km/hr. It crossed a platform of length 520 m in
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Answer: (A) 50-4 sec.

Explanation

The total distance the train needs to cover to cross the platform is the sum of the length of the train and the length of the platform.

Total Distance = Length of Train + Length of Platform Total Distance = 250 + 520 = 770 m

To convert the speed from km/hr to m/s, multiply by 5/18.

Speed = 55 × 5/18 = 275/18 m/s

Using the standard formula for time:

Time = Distance / Speed Time = 770 / (275/18) Time = (770 × 18) / 275 Time = 13860 / 275 Time = 50.4 seconds

166Quantitative Aptitude
If 12 men or 18 women can reap a field in 7 days, then in what time can 4 men and 8 women reap the same field?
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Answer: (B) 9 days

Explanation

Let the daily work capacity of a man be M and a woman be W.

According to the given condition, the work done by 12 men is equal to the work done by 18 women: 12 M = 18 W 2 M = 3 W 1 M = 1.5 W

We need to find the time taken by 4 men and 8 women to reap the same field. Converting men into equivalent women: 4 M + 8 W = 4 × 1.5 W + 8 W = 6 W + 8 W = 14 W

Using the work equivalence formula, if W₁ women complete the work in D₁ days, then W₂ women will complete the same work in D₂ days: W₁ × D₁ = W₂ × D₂ 18 × 7 = 14 × D₂ D₂ = (18 × 7) / 14 = 9 days

167Quantitative Aptitude
A can build a wall in 30 days, while B alone can build it in 40 days. If they build it together and get a payment of ₹ 7,000, then the share of B is
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Answer: (C) ₹ 3,000

Explanation

The share of wages is distributed in proportion to the efficiency of the individuals when they work together for the same duration. Since efficiency is inversely proportional to the time taken to complete the work, the ratio of their work done is calculated as:

Ratio of time taken by A and B = 30 : 40 = 3 : 4

Ratio of efficiency of A and B = 1/30 : 1/40 = 4 : 3

The total payment of ₹ 7,000 is divided in this ratio of 4 : 3.

Share of B = (3 / (4 + 3)) × 7,000 = (3/7) × 7,000 = ₹ 3,000

168Quantitative Aptitude
An edge of a cube is increased by 50%. Then percentage increase in total surface area is
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Answer: (B) 125%

Explanation

The total surface area of a cube is directly proportional to the square of its edge length, as TSA = 6a². When the edge of the cube is increased by 50%, the new edge length becomes 1.5 times the original edge length.

The new total surface area scales by the square of this factor, which is (1.5)² = 2.25 times the original surface area.

The percentage increase in the total surface area is calculated as (2.25 - 1) × 100% = 125%.

169Quantitative Aptitude
The area of the base of a rectangular tank is 6500 sq cm and the volume of water contained in it is 2.6 cubic meters. The depth of water is
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Answer: (D) 4 m

Explanation

Volume of a rectangular tank = Base Area × Depth

The volume of water is given in cubic meters and the base area is given in square centimeters. To perform the calculation in standard units, the base area is first converted into square meters:

Base Area = 6500 cm² Since 1 m² = 10000 cm²: Base Area = 6500 / 10000 = 0.65 m²

Let the depth of water be h meters. Substituting the values into the formula:

2.6 = 0.65 × h h = 2.6 / 0.65 h = 4 m

170Quantitative Aptitude
The true discount on ₹ 1,800 for 3 years is same as the simple interest on ₹ 1,500 for 3 years at the same rate of interest. The rate of interest is
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Answer: (B) 6 2/3%

Explanation

The True Discount (TD) on a sum due (Amount) is equal to the Simple Interest (SI) on its Present Worth (PW) for the same time and rate of interest.

According to the question, the true discount on ₹ 1,800 is equal to the simple interest on ₹ 1,500 for 3 years at the same rate. This directly implies that the Present Worth (PW) is ₹ 1,500.

The relation between Amount, Present Worth, and True Discount is: Amount = Present Worth + True Discount 1,800 = 1,500 + True Discount True Discount = 1,800 - 1,500 = 300

Since True Discount is the Simple Interest on the Present Worth: True Discount = (Present Worth × Rate × Time) / 100 300 = (1,500 × R × 3) / 100 300 = 45R R = 300 / 45 = 20/3 = 6 ⅔ %

171Quantitative Aptitude
The cash down value of an article is ₹ 12,500. It can be bought at credit to ₹ 14,300 payable 1 year hence at 10% per annum. The trader gets a profit of ______ in this transaction.
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Answer: (A) ₹ 500

Explanation

To find the profit of the trader in this transaction, we calculate the present worth of the credit payment.

The present worth (PW) is calculated using the formula: PW = (Amount × 100) / (100 + (Rate × Time))

Given: Amount = ₹ 14,300 Rate = 10% per annum Time = 1 year

Substituting these values into the formula: PW = (14,300 × 100) / (100 + (10 × 1)) PW = 1,430,000 / 110 PW = ₹ 13,000

The profit earned by the trader is the difference between the present worth of the credit payment and the actual cash down value of the article: Profit = Present Worth - Cash Down Value Profit = ₹ 13,000 - ₹ 12,500 Profit = ₹ 500

172Quantitative Aptitude
A sum of money amounts to £500 in 2 years and £540 in 3 years at compound interest per annum; then the rate percent, per annum, is
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Answer: (A) 8

Explanation

Under compound interest, the amount accumulated at the end of a given year acts as the principal for the succeeding year.

Amount after 2 years = £500 Amount after 3 years = £540

The interest earned during the third year is: Interest = Amount after 3 years - Amount after 2 years Interest = 540 - 500 = £40

The rate of interest per annum (R) is given by the relation: R = (Interest / Principal) × 100

Using the second-year amount of £500 as the principal for the third year: R = (40 / 500) × 100 = 8%

173Quantitative Aptitude
A man had £2,000. He lent a part of this at 5% simple interest and the rest at 4%. The total interest he received in one year was £92. The amount of money (in rupees) he lent at 5% was
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Answer: (C) 1,200

Explanation

Let the amount of money lent at 5% simple interest be x. The remaining amount lent at 4% simple interest is 2,000 - x.

The total annual interest received is 92. Using the simple interest formula: (x × 5)/100 + ((2,000 - x) × 4)/100 = 92

Multiply both sides of the equation by 100: 5x + 4(2,000 - x) = 9,200

Expand and simplify: 5x + 8,000 - 4x = 9,200 x + 8,000 = 9,200 x = 1,200

174Quantitative Aptitude
A rectangular circuit board is designed to have width w cm, perimeter p cm and area k sq. cm. Of the following, the equation which must be true is
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Answer: (B) 2w² - pw + 2k = 0

Explanation

For a rectangular board of width w and length l, the perimeter p is given by the formula: p = 2(l + w)

From this, the length l can be expressed as: l = p/2 - w

The area k of the rectangle is given by the formula: k = l × w

Substituting the value of l into the area formula yields: k = (p/2 - w) × w k = (pw)/2 - w²

Multiplying the entire equation by 2 to eliminate the fraction gives: 2k = pw - 2w²

Rearranging the terms to form a standard quadratic equation results in: 2w² - pw + 2k = 0

175Quantitative Aptitude
The average expenditure of a man for the first 5 months is £12,000 and for the next seven months is £13,000. Find his average monthly income if he saves £29,000 during the year.
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Answer: (D) £15,000

Explanation

The relationship between income, expenditure, and savings is given by the formula:

Total Income = Total Expenditure + Savings

First, calculate the total expenditure for the entire year of 12 months: Expenditure for the first 5 months = 5 × £12,000 = £60,000 Expenditure for the next 7 months = 7 × £13,000 = £91,000 Total annual expenditure = £60,000 + £91,000 = £151,000

Since the annual savings are £29,000, the total annual income is: Total annual income = £151,000 + £29,000 = £180,000

The average monthly income is obtained by dividing the total annual income by 12: Average monthly income = £180,000 ÷ 12 = £15,000

176Quantitative Aptitude
If a train maintains an average speed of 40 km/hr, it arrives at its destination punctually. If however the average speed is 35 km/hr, it arrives 15 minutes late. The length of the journey is
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Answer: (B) 70 km

Explanation

The length of the journey can be calculated using the relation:

Distance = (S₁ × S₂ / (S₁ - S₂)) × Δt

where S₁ and S₂ are the two speeds, and Δt is the difference in time.

Given: S₁ = 40 km/hr S₂ = 35 km/hr Δt = 15 minutes = 15/60 hour = ¼ hour

Substituting these values into the formula:

Distance = (40 × 35 / (40 - 35)) × (1/4) Distance = (1400 / 5) × (1/4) Distance = 280 × (1/4) Distance = 70 km

177Quantitative Aptitude
Three years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. What is the age of the baby?
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Answer: (D) 2 years

Explanation

Three years ago, the average age of the 5-member family was 17 years. Therefore, the total age of these 5 members three years ago was 5 × 17 = 85 years.

Since three years have passed, each of the 5 members is now 3 years older. Thus, the total age of these 5 members today is 85 + (5 × 3) = 100 years.

Today, with the addition of the baby, the family has 6 members. The average age of the family remains the same as 17 years. Therefore, the total age of all 6 members today is 6 × 17 = 102 years.

The age of the baby is the difference between the total age of the 6 members today and the total age of the 5 older members today, which is 102 - 100 = 2 years.

178Quantitative Aptitude
The cost of manufacture of an article is made up of materials, labour and overheads in the ratio 4:3:2. If the cost of labour is ₹45, find the total cost of the article. Find the profit percent, if the article is sold for ₹180.
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Answer: (B) 33 ⅓%

Explanation

The ratio of materials, labour, and overheads is 4:3:2. Since the labour component represents 3 parts of the ratio and is given as £45, the value of 1 part is £45 ÷ 3 = £15.

The total cost is the sum of all components, represented by 4 + 3 + 2 = 9 parts. Multiplying 9 parts by £15 per part gives a total cost price of £135.

With a selling price of £180, the profit is computed as £180 - £135 = £45. The profit percentage is calculated by dividing the profit by the cost price and multiplying by 100, which gives (45 ÷ 135) × 100 = 33 ⅓%.

179Quantitative Aptitude
The difference between selling a shirt at profits 4% and 5% is £3. Find the cost price and the two selling prices of the shirt.
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Answer: (B) £300, £312, £315

Explanation

Let the cost price of the shirt be CP.

The difference between selling the shirt at a profit of 5% and 4% is 1% of the cost price.

Given that this difference is £3: 1% of CP = 3 (1/100) × CP = 3 CP = 3 × 100 = 300

Thus, the cost price of the shirt is £300.

The two selling prices are calculated as: First selling price (at 4% profit) = 300 × 1.04 = 312 Second selling price (at 5% profit) = 300 × 1.05 = 315

So, the cost price is £300, and the two selling prices are £312 and £315.

180Quantitative Aptitude
A toy is sold at a profit of 16%. Had it been sold for £10 more, then the profit would have been 20%. Then its cost price is
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Answer: (D) £250

Explanation

Let CP be the cost price of the toy.

The difference between the two profit percentages corresponds to the increase in the selling price: 20% - 16% = 4% of CP

Since this 4% difference is equal to £10: 4/100 × CP = 10 CP = (10 × 100) / 4 = 250

181Quantitative Aptitude
⅔ rd of 30% of 4 times of a is
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Answer: (D) ⁴ᵃ⁄₅

Explanation

To find the value of the given expression, we translate the words directly into a mathematical equation:

(2/3) × 30% × 4a

First, write 30% as a fraction:

30% = 30/100 = 3/10

Now substitute this into the expression:

(2/3) × (3/10) × 4a

Simplify the multiplication by canceling the common factor of 3 in the numerator and denominator:

(2/10) × 4a

This simplifies to:

(1/5) × 4a = 4a/5

182Quantitative Aptitude
65% of a number is 21 less than four-fifth of that number. What is the number?
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Answer: (A) 140

Explanation

Let the number be x.

Four-fifth of the number represents (4/5)x, which is equivalent to 80% of the number.

According to the question, 65% of the number is 21 less than 80% of the number. This relationship can be expressed as:

80% of x - 65% of x = 21

15% of x = 21

0.15 × x = 21

x = 21 / 0.15

x = 140

183Quantitative Aptitude
A man walking at the rate of 6 km/hr crosses a bridge in 20 minutes. What is the length of the bridge in kilometers?
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Answer: (D) 2

Explanation

The length of the bridge is calculated using the distance formula:

Distance = Speed × Time

The speed of the man is given as 6 km/hr, and the time taken to cross the bridge is 20 minutes. First, convert the time from minutes to hours:

Time = 20 minutes = 20/60 hour = 1/3 hour

Now, substitute the speed and time into the distance formula:

Distance = 6 km/hr × 1/3 hour = 2 km

This gives the total length of the bridge as 2 kilometers.

184Quantitative Aptitude
A car is running at a speed of 36 km/hr. The distance covered by it in 32 seconds is
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Answer: (D) 320 meters

Explanation

The relationship between distance, speed, and time is given by the formula: Distance = Speed × Time

First, convert the speed of the car from kilometers per hour (km/hr) to meters per second (m/s) by multiplying by 5/18: Speed = 36 × (5/18) m/s = 10 m/s

Using the converted speed and the given time of 32 seconds, the distance covered is calculated as: Distance = 10 m/s × 32 s = 320 meters

185Quantitative Aptitude
An interior angle of a regular polygon is 120°. What is its number of sides ?
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Answer: (B) 6

Explanation

The interior angle of a regular polygon with n sides is related to its exterior angle by the formula: Exterior angle = 180° - Interior angle

Substituting the given interior angle of 120°: Exterior angle = 180° - 120° = 60°

The number of sides n of a regular polygon is calculated using the formula: n = 360° ÷ Exterior angle

Substituting the calculated exterior angle: n = 360° ÷ 60° = 6

186Quantitative Aptitude
If S is the circumference of Δ ABC and the value of ∠ BAC is 40°, then the value of ∠ BSC is
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Answer: (A) 80°

Explanation

By definition, if S represents the circumcentre of Δ ABC, then the circumcircle passes through the vertices A, B, and C with S as its centre.

According to the central angle theorem, the angle subtended by an arc at the centre of a circle is twice the angle subtended by the same arc at any point on the circumference.

Here, the arc BC subtends the central angle ∠BSC at the circumcentre S, and the angle ∠BAC at the circumference.

Therefore, ∠BSC = 2 × ∠BAC.

Substituting the given value: ∠BSC = 2 × 40° = 80°

187Quantitative Aptitude
Three medians AD, BE and CF of Δ ABC intersect at G. If area of Δ ABC is 36 cm², find the area of quadrilateral BDGF.
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Answer: (B) 12 cm²

Explanation

The three medians AD, BE, and CF of a triangle ABC intersect at the centroid G and divide the triangle into six smaller triangles of equal area: ΔAFG, ΔBFG, ΔBDG, ΔCDG, ΔCEG, and ΔAEG.

Given that the total area of triangle ABC is 36 cm², the area of each of these six smaller triangles is 36 ÷ 6 = 6 cm².

The quadrilateral BDGF is composed of two of these smaller triangles, namely ΔBFG and ΔBDG. Therefore, the area of quadrilateral BDGF is the sum of the areas of ΔBFG and ΔBDG, which is 6 + 6 = 12 cm².

188Quantitative Aptitude
The angle of elevation of a cloud from a point h meters above the surface of a lake is 30° and the angle of depression of its reflection is 60°. Then the height of the cloud above the surface of the lake is
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Answer: (B) 2h meters

Explanation

Let the height of the cloud above the surface of the lake be H and the horizontal distance from the point of observation to the cloud be d. Since the point of observation is at a height h above the lake surface, the vertical height of the cloud above this observation level is H - h.

Using the angle of elevation of 30°: tan(30°) = (H - h) / d d = (H - h) / tan(30°) = (H - h)√3

The reflection of the cloud is at a depth H below the lake surface. Therefore, the vertical depth of the reflection below the horizontal level of the point of observation is H + h.

Using the angle of depression of 60°: tan(60°) = (H + h) / d d = (H + h) / tan(60°) = (H + h) / √3

Equating the two expressions for d: (H - h)√3 = (H + h) / √3

Multiplying both sides by √3: 3(H - h) = H + h 3H - 3h = H + h 2H = 4h H = 2h

189Quantitative Aptitude
If the Δ ABC is right-angled at B, and the sides AB and BC are 15 cm and 20 cm respectively, then the circumradius is
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Answer: (C) 12.5 cm

Explanation

In a right-angled triangle, the circumradius is always equal to half of the length of the hypotenuse.

Using the Pythagorean theorem for the triangle ABC right-angled at B: AC = √(AB² + BC²)

Substitute the given values: AC = √(15² + 20²) AC = √(225 + 400) AC = √625 AC = 25 cm

Therefore, the circumradius is: R = AC / 2 R = 25 / 2 R = 12.5 cm

190Quantitative Aptitude
If sin (x + y) = (√3)/(2) and tan (x - y) = (1)/(√3), then the value of x is
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Answer: (B) π /4

Explanation

From the given trigonometric relations, we can find the values of the angles:

sin(x + y) = √3/2 → x + y = π/3

tan(x - y) = 1/√3 → x - y = π/6

By adding these two linear equations, we get:

(x + y) + (x - y) = π/3 + π/6

2x = π/2

x = π/4

191Quantitative Aptitude
If A + B = 90°, then the value of sec² A + sec² B - sec² A, sec² B is
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Answer: (C) 0

Explanation

Given A + B = 90°, we can write B = 90° - A.

Taking the secant on both sides gives sec B = sec(90° - A) = cosec A. Squaring both sides yields sec² B = cosec² A.

Substituting sec² B = cosec² A into the given expression: sec² A + cosec² A - sec² A cosec² A

Expressing the terms in terms of sine and cosine: 1/cos² A + 1/sin² A - 1/(cos² A sin² A)

Taking the common denominator for the first two terms: (sin² A + cos² A)/(cos² A sin² A) - 1/(cos² A sin² A)

Using the fundamental trigonometric identity sin² A + cos² A = 1: 1/(cos² A sin² A) - 1/(cos² A sin² A) = 0

192Quantitative Aptitude
If the radius of a sphere is increased by 50%, then the percentage increase in its volume is
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Answer: (D) 237.5

Explanation

Volume of a sphere is given by the formula V = (4/3) π r³, which means the volume is directly proportional to the cube of its radius (V ∝ r³).

When the radius of the sphere is increased by 50%, the new radius becomes 1.5 times the original radius (r' = 1.5r).

The new volume is proportional to the cube of the new radius: V' ∝ (1.5r)³ = 3.375r³

This shows that the new volume is 3.375 times the original volume (V' = 3.375V).

The percentage increase in the volume is calculated as: Percentage increase = ((V' - V) / V) × 100 = (3.375 - 1) × 100 = 2.375 × 100 = 237.5%

193Quantitative Aptitude
A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole ice-cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, then the radius of the base of the ice-cream cone is
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Answer: (C) 3 cm

Explanation

The volume of the cylindrical container is calculated using the formula: V = π × R² × H

Substituting the given values of radius R = 6 cm and height H = 15 cm: V = π × 6² × 15 = 540π cm³

Each child receives an ice-cream cone consisting of a conical part and a hemispherical top. Let the radius of the base of the cone be r. The height of the conical portion is given as h = 4r.

The total volume of one ice-cream cone is the sum of the volume of the cone and the volume of the hemisphere: V_cone = (1/3)πr²h + (2/3)πr³ V_cone = (1/3)πr²(4r) + (2/3)πr³ V_cone = (4/3)πr³ + (2/3)πr³ V_cone = 2πr³

Since the ice-cream is distributed equally among 10 children, the volume of 10 ice-cream cones is equal to the volume of the cylindrical container: 10 × 2πr³ = 540π 20πr³ = 540π r³ = 27 r = 3 cm

194Quantitative Aptitude
A hemispherical bowl of internal radius 15 cm contains a liquid. The liquid is to be filled into cylindrical-shaped bottles of diameter 5 cm and height 6 cm. The number of bottles necessary to empty the bowl is
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Answer: (B) 60

Explanation

The volume of a hemisphere is given by V₁ = (2/3) × π × R³, where R is the radius of the hemisphere. Here, R = 15 cm. V₁ = (2/3) × π × 15³ = (2/3) × π × 3375 = 2250π cm³

The volume of a cylinder is given by V₂ = π × r² × h, where r is the radius and h is the height. The diameter of the cylindrical bottle is 5 cm, so its radius r = 5/2 = 2.5 cm, and height h = 6 cm. V₂ = π × (5/2)² × 6 = π × (25/4) × 6 = 37.5π cm³

The number of bottles necessary to empty the bowl is N = V₁ ÷ V₂. N = 2250π ÷ 37.5π = 2250 ÷ 37.5 = 60

195Quantitative Aptitude
Evaluate √(6 + √(6 + √(6 + …)))
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Answer: (D) 3

Explanation

The value of an infinite nested radical of the form √(a + √(a + √(a + ...))) is given by the formula: x = (1 + √(1 + 4a)) / 2

Substituting a = 6 into the formula: x = (1 + √(1 + 4 × 6)) / 2 x = (1 + √(1 + 24)) / 2 x = (1 + √25) / 2 x = (1 + 5) / 2 x = 3

Alternatively, for any expression of this form where a can be factored into two consecutive integers n(n + 1), the value of the positive square root series is always the larger factor, n + 1. Since 6 can be factored as 2 × 3, the larger factor is 3.

196Quantitative Aptitude
If x = (√3 + √2)/(√3 - √2), then the value of (x + ¹⁄ₓ) is
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Answer: (D) 10

Explanation

To find the value of x + 1/x, we first rationalize the expressions.

The given expression for x is: x = (√3 + √2) / (√3 - √2)

Multiplying the numerator and denominator by (√3 + √2): x = (√3 + √2)² / ((√3 - √2)(√3 + √2)) x = (3 + 2 + 2√6) / (3 - 2) x = 5 + 2√6

The reciprocal 1/x is given by: 1/x = (√3 - √2) / (√3 + √2)

Multiplying the numerator and denominator by (√3 - √2): 1/x = (√3 - √2)² / ((√3 + √2)(√3 - √2)) 1/x = (3 + 2 - 2√6) / (3 - 2) 1/x = 5 - 2√6

Adding the values of x and 1/x: x + 1/x = (5 + 2√6) + (5 - 2√6) x + 1/x = 10

197Quantitative Aptitude
If (c - 3)² = c² + kc + 9, then the value of k is
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Answer: (D) -6

Explanation

Applying the algebraic identity for the square of a binomial, (a - b)² = a² - 2ab + b², the left side of the equation is expanded as:

(c - 3)² = c² - 2(c)(3) + 3² = c² - 6c + 9

Equating this expanded form to the right side of the given equation:

c² - 6c + 9 = c² + kc + 9

By comparing the coefficients of the c term on both sides of the equation, we get:

k = -6

Answer key

Tap a number to jump to that question.

  1. 151D
  2. 152C
  3. 153D
  4. 154D
  5. 155A
  6. 156D
  7. 157A
  8. 158C
  9. 159A
  10. 160B
  11. 161C
  12. 162D
  13. 163A
  14. 164D
  15. 165A
  16. 166B
  17. 167C
  18. 168B
  19. 169D
  20. 170B
  21. 171A
  22. 172A
  23. 173C
  24. 174B
  25. 175D
  26. 176B
  27. 177D
  28. 178B
  29. 179B
  30. 180D
  31. 181D
  32. 182A
  33. 183D
  34. 184D
  35. 185B
  36. 186A
  37. 187B
  38. 188B
  39. 189C
  40. 190B
  41. 191C
  42. 192D
  43. 193C
  44. 194B
  45. 195D
  46. 196D
  47. 197D

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