RRB NTPC2020MathematicsPage 3 of 3

RRB NTPC CBT 1 2020 Mathematics Questions with Solutions

Questions from every shift of the year, grouped by section. Questions 101–116 of 116, each with the correct answer and a step-by-step explanation.

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Answers + explanations
101Mathematics
If mean is 40 and standard deviation is 5 then C.V (Coefficient of variation) is
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Answer: (D) 12.5%

Explanation

The Coefficient of Variation (C.V.) measures the relative variability of a dataset and is given by the formula:

C.V. = (Standard Deviation / Mean) × 100%

Substituting the given values:

C.V. = (5 / 40) × 100% = (1 / 8) × 100% = 12.5%

102Mathematics
A shop keeper sold two toys for ₹990 each. On first toy he gained 10% and on the second he lost 10%. Find the total percentage gain or loss.
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Answer: (B) 1% Loss

Explanation

When two items are sold at the same selling price, one at a gain of x% and the other at a loss of x%, there is always an overall net loss given by the formula:

Loss % = (x / 10)²

Substituting x = 10: Loss % = (10 / 10)² = 1² = 1%

Alternatively, calculating individual cost prices: Cost Price of first toy = 990 ÷ 1.10 = ₹900 Cost Price of second toy = 990 ÷ 0.90 = ₹1100 Total Cost Price = 900 + 1100 = ₹2000 Total Selling Price = 990 + 990 = ₹1980 Net Loss = 2000 - 1980 = ₹20 Loss % = (20 ÷ 2000) × 100 = 1%

103Mathematics
Find the length of the longest pole that can be placed in a room of dimensions 30 m × 15 m × 10 m.
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Answer: (D) 35 m

Explanation

The length of the longest pole that can fit inside a rectangular room is equal to the length of the space diagonal of the cuboid.

Diagonal = √(l² + b² + h²)

Substituting l = 30 m, b = 15 m, and h = 10 m:

Diagonal = √(30² + 15² + 10²) = √(900 + 225 + 100) = √1225 = 35 m

104Mathematics
A cuboid having the surface area of 3 adjacent faces as a, b, c has the volume:
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Answer: (D) (abc)²¹

Explanation

If the areas of three adjacent faces of a cuboid are a, b, and c, then a = lw, b = wh, and c = hl. Multiplying these gives abc = (lwh)² = V², which means the volume V = sqrt(abc) = (abc)^(1/2).

105Mathematics
Solve the following. 6202.5 + 620.25 + 62.025 + 6.2025 + 0.62025 =?
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Answer: (B) 6891.59775

Explanation

Aligning the numbers by their decimal points and adding column by column:

6202.50000

  • 620.25000
  • 62.02500
  • 6.20250
  • 0.62025 ─────────────── 6891.59775

Summing the decimals from right to left gives .59775 in the fractional part, and summing the whole numbers with the carry gives 6891, yielding a total of 6891.59775.

106Mathematics
A sum of money amounts to ₹1600 in two years and ₹1700 in three years, at compounded interest, compounded annually. What is the rate of interest?
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Answer: (C) 6.25%

Explanation

In compound interest, the interest earned during any year is calculated on the amount accumulated at the end of the preceding year.

Interest for the 3rd year = Amount after 3 years - Amount after 2 years = ₹1700 - ₹1600 = ₹100

Rate of interest R = (Interest for 3rd year / Amount after 2 years) × 100 R = (100 / 1600) × 100 = 100 / 16 = 6.25%

107Mathematics
If the difference between a number and its 25% is 24, then the number is:
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Answer: (C) 32

Explanation

Let the required number be x.

Since the difference between the number and its 25% is 24: x - 25% of x = 24 x - 0.25x = 24 0.75x = 24 ¾ x = 24 x = 24 × (4/3) = 32

108Mathematics
Find the number of all prime numbers less than 55.
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Answer: (B) 16

Explanation

The prime numbers less than 55 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, and 53. Counting these gives a total of 16 prime numbers.

109Mathematics
Solve the following. (x-y)³ + (y-z)³ + (z-x)³ = ?
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Answer: (A) 3(x-y)(y-z)(z-x)

Explanation

Using the algebraic identity, if a + b + c = 0, then a³ + b³ + c³ = 3abc.

Let a = x - y, b = y - z, and c = z - x.

Adding these three terms gives: a + b + c = (x - y) + (y - z) + (z - x) = 0

Since the sum of the three terms is zero, applying the identity directly gives: (x - y)³ + (y - z)³ + (z - x)³ = 3(x - y)(y - z)(z - x)

110Mathematics
Value of the square root of (36.1)/(102.4) is:
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Answer: (C) 19/32

Explanation

Multiply both the numerator and denominator inside the square root by 10 to remove the decimal points:

√(36.1 / 102.4) = √(361 / 1024)

Taking the square root of the numerator and denominator individually gives:

√361 = 19 √1024 = 32

Therefore, √(361 / 1024) = 19 / 32.

111Mathematics
The given table shows the number of formal learners, informal learners and illiterates, on the basis of gender, in the age group of 18 – 30 years in village X near Delhi. Determine the ratio among the formal learners, informal learners and illiterates. FORMAL LEARNERS BOYS 39 GIRLS 52 INFORMAL LEARNERS BOYS 65 GIRLS 78 ILLITERATES BOYS 143 GIRLS 169
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Answer: (D) 7:11:24

Explanation

Total number of formal learners = 39 + 52 = 91 Total number of informal learners = 65 + 78 = 143 Total number of illiterates = 143 + 169 = 312

Ratio of Formal Learners : Informal Learners : Illiterates = 91 : 143 : 312

Dividing each value by their common factor of 13: 91 ÷ 13 = 7 143 ÷ 13 = 11 312 ÷ 13 = 24

The simplified ratio is 7 : 11 : 24.

112Mathematics
Avinash, Bhuvnesh and Chaman can complete a piece of work in 20, 30 and 60 days respectively. In how many days can Avinash complete the work if he is assisted by Bhuvnesh and Chaman on every third day?
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Answer: (C) 15

Explanation

Total work = LCM(20, 30, 60) = 60 units.

Efficiency of Avinash = 60 / 20 = 3 units/day Efficiency of Bhuvnesh = 60 / 30 = 2 units/day Efficiency of Chaman = 60 / 60 = 1 unit/day

Work done in a 3-day cycle: Day 1: Avinash alone = 3 units Day 2: Avinash alone = 3 units Day 3: Avinash, Bhuvnesh, and Chaman together = 3 + 2 + 1 = 6 units

Total work completed in 3 days = 3 + 3 + 6 = 12 units.

Number of 3-day cycles required to complete 60 units = 60 / 12 = 5 cycles.

Total days taken = 5 × 3 = 15 days.

113Mathematics
In a game Rajesh lost ⅓ of his money in the first round of the game, in the second round he losses ⅗ of his remaining money and in the third round he lost ⁴⁄₇ of the rest. He is left with what part of the original sum of money?
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Answer: (B) 4/35

Explanation

The fraction of money remaining after each round is obtained by multiplying the retention factor of each round:

Fraction remaining = (1 - 1/3) × (1 - 3/5) × (1 - 4/7) = 2/3 × 2/5 × 3/7 = 4/35

114Mathematics
A metallic part of a machine is made from a mixture of copper, zinc and lead mixed in the ratio of 13:6:1 . If the weight of zinc in this part is 90 kg, then the total weight of the part will be:
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Answer: (C) 300 kg

Explanation

The ratio of copper, zinc, and lead in the mixture is 13 : 6 : 1.

Total parts = 13 + 6 + 1 = 20 parts

Given that zinc represents 6 parts of the total weight: Weight of 1 part = 90 ÷ 6 = 15 kg

Total weight of the machine part = 20 × 15 = 300 kg

115Mathematics
The sum of two numbers is 20 and their difference is 2.5. Ratio of these numbers will be:
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Answer: (B) 9 : 7

Explanation

Let the two numbers be x and y (where x > y).

Using the standard formulas for two numbers given their sum (S) and difference (D): x = (S + D) / 2 = (20 + 2.5) / 2 = 11.25 y = (S - D) / 2 = (20 - 2.5) / 2 = 8.75

The required ratio of the two numbers is: x : y = 11.25 : 8.75 = 1125 : 875 = 9 : 7

116Mathematics
Sunila had 9¼ kg of flour to make bread with. If the recipe says that she needs 1⅛ kg to make one loaf of bread, how many loafs can she make? Estimate to the nearest whole number.
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Answer: (C) 8

Explanation

Convert the given mixed fractions into improper fractions: Total flour available = 9 ¼ = 37/4 kg Flour required per loaf = 1 ⅛ = 9/8 kg

Number of loaves = Total flour ÷ Flour per loaf = (37/4) ÷ (9/8) = (37/4) × (8/9) = 74/9 = 8.22...

Rounding 8.22... to the nearest whole number yields 8.

Answer key

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  1. 101D
  2. 102B
  3. 103D
  4. 104D
  5. 105B
  6. 106C
  7. 107C
  8. 108B
  9. 109A
  10. 110C
  11. 111D
  12. 112C
  13. 113B
  14. 114C
  15. 115B
  16. 116C

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