Three students are picked at random from a school having a total of 1000 students. The probability that these three students will have identical data and month of their birth is:
- A3/1000
- B3/365
- C1/(365)2Correct
- D1/(365)2
Explanation
Assuming a standard year of 365 days:
The first student can be born on any day. Probability = 365/365 = 1. The second student must share the same birthday. Probability = 1/365. The third student must also share the same birthday. Probability = 1/365.
Total probability = 1 x (1/365) x (1/365) = 1/(365)².
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